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@@ -57,7 +57,19 @@ print(result)
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  The area of the circle is $\boxed{\frac{27\pi}{4}}$ square cm.
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  </pre>
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- ??? It should have been `9*pi/4`. Am I using this model wrong? Same result with temperature=0.0,top_k=1. With temp=0.0, the Q6_K of the non-interpreter variant of this model produces explanations, and its last lines `A=π(1.5)^2`, `A = π(2.25)`, `A = 6.9887654321` (close to the expected 7.06 which deepseek-math-7b-rl.Q8_0.gguf outputs)
 
 
 
 
 
 
 
 
 
 
 
 
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  # imatrix
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  The area of the circle is $\boxed{\frac{27\pi}{4}}$ square cm.
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  </pre>
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+ ??? It should have been `9*pi/4`. Am I using this model wrong? Same result with temperature=0.0,top_k=1.
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+
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+ In comparison, the Q6_K of the non-interpreter variant of this model with temp=0.0 outputs:
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+ ```
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+ The area of a circle is given by the formula A = πr^2, where r is the radius of the circle. Since the width of the circle is 3cm, the radius is half of that, or 1.5cm. Substituting this value into the formula, we get:
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+
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+ A = π(1.5)^2
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+ A = π(2.25)
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+ A = 6.9887654321
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+
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+ So, the area of the circle is approximately 6.99 cm^2.
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+ ```
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+ (close to the expected 7.06 which `deepseek-math-7b-rl.Q8_0.gguf` outputs)
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  # imatrix
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