(* Authors: Jose Divasón Sebastiaan Joosten René Thiemann Akihisa Yamada *) subsection \Maximal Degree during Reconstruction\ text \We define a function which computes an upper bound on the degree of a factor for which we have to reconstruct the integer values of the coefficients. This degree will determine how large the second parameter of the factor-bound will be. In essence, if the Berlekamp-factorization will produce $n$ factors with degrees $d_1,\ldots,d_n$, then our bound will be the sum of the $\frac{n}2$ largest degrees. The reason is that we will combine at most $\frac{n}2$ factors before reconstruction. Soundness of the bound is proven, as well as a monotonicity property.\ theory Degree_Bound imports Containers.Set_Impl (* for sort_append_Cons_swap *) "HOL-Library.Multiset" Polynomial_Interpolation.Missing_Polynomial "Efficient-Mergesort.Efficient_Sort" begin definition max_factor_degree :: "nat list \ nat" where "max_factor_degree degs = (let ds = sort degs in sum_list (drop (length ds div 2) ds))" definition degree_bound where "degree_bound vs = max_factor_degree (map degree vs)" lemma insort_middle: "sort (xs @ x # ys) = insort x (sort (xs @ ys))" by (metis append.assoc sort_append_Cons_swap sort_snoc) lemma sum_list_insort[simp]: "sum_list (insort (d :: 'a :: {comm_monoid_add,linorder}) xs) = d + sum_list xs" proof (induct xs) case (Cons x xs) thus ?case by (cases "d \ x", auto simp: ac_simps) qed simp lemma half_largest_elements_mono: "sum_list (drop (length ds div 2) (sort ds)) \ sum_list (drop (Suc (length ds) div 2) (insort (d :: nat) (sort ds)))" proof - define n where "n = length ds div 2" define m where "m = Suc (length ds) div 2" define xs where "xs = sort ds" have xs: "sorted xs" unfolding xs_def by auto have nm: "m \ {n, Suc n}" unfolding n_def m_def by auto show ?thesis unfolding n_def[symmetric] m_def[symmetric] xs_def[symmetric] using nm xs proof (induct xs arbitrary: n m d) case (Cons x xs n m d) show ?case proof (cases n) case 0 with Cons(2) have m: "m = 0 \ m = 1" by auto show ?thesis proof (cases "d \ x") case True hence ins: "insort d (x # xs) = d # x # xs" by auto show ?thesis unfolding ins 0 using True m by auto next case False hence ins: "insort d (x # xs) = x # insort d xs" by auto show ?thesis unfolding ins 0 using False m by auto qed next case (Suc nn) with Cons(2) obtain mm where m: "m = Suc mm" and mm: "mm \ {nn, Suc nn}" by auto from Cons(3) have sort: "sorted xs" by (simp) note IH = Cons(1)[OF mm] show ?thesis proof (cases "d \ x") case True with Cons(3) have ins: "insort d (x # xs) = d # insort x xs" by (cases xs, auto) show ?thesis unfolding ins Suc m using IH[OF sort] by auto next case False hence ins: "insort d (x # xs) = x # insort d xs" by auto show ?thesis unfolding ins Suc m using IH[OF sort] Cons(3) by auto qed qed qed auto qed lemma max_factor_degree_mono: "max_factor_degree (map degree (fold remove1 ws vs)) \ max_factor_degree (map degree vs)" unfolding max_factor_degree_def Let_def length_sort length_map proof (induct ws arbitrary: vs) case (Cons w ws vs) show ?case proof (cases "w \ set vs") case False hence "remove1 w vs = vs" by (rule remove1_idem) thus ?thesis using Cons[of vs] by auto next case True then obtain bef aft where vs: "vs = bef @ w # aft" and rem1: "remove1 w vs = bef @ aft" by (metis remove1.simps(2) remove1_append split_list_first) let ?exp = "\ ws vs. sum_list (drop (length (fold remove1 ws vs) div 2) (sort (map degree (fold remove1 ws vs))))" let ?bnd = "\ vs. sum_list (drop (length vs div 2) (sort (map degree vs)))" let ?bd = "\ vs. sum_list (drop (length vs div 2) (sort vs))" define ba where "ba = bef @ aft" define ds where "ds = map degree ba" define d where "d = degree w" have "?exp (w # ws) vs = ?exp ws (bef @ aft)" by (auto simp: rem1) also have "\ \ ?bnd ba" unfolding ba_def by (rule Cons) also have "\ = ?bd ds" unfolding ds_def by simp also have "\ \ sum_list (drop (Suc (length ds) div 2) (insort d (sort ds)))" by (rule half_largest_elements_mono) also have "\ = ?bnd vs" unfolding vs ds_def d_def by (simp add: ba_def insort_middle) finally show "?exp (w # ws) vs \ ?bnd vs" by simp qed qed auto lemma mset_sub_decompose: "mset ds \# mset bs + as \ length ds < length bs \ \ b1 b b2. bs = b1 @ b # b2 \ mset ds \# mset (b1 @ b2) + as" proof (induct ds arbitrary: bs as) case Nil hence "bs = [] @ hd bs # tl bs" by auto thus ?case by fastforce next case (Cons d ds bs as) have "d \# mset (d # ds)" by auto with Cons(2) have d: "d \# mset bs + as" by (rule mset_subset_eqD) hence "d \ set bs \ d \# as" by auto thus ?case proof assume "d \ set bs" from this[unfolded in_set_conv_decomp] obtain b1 b2 where bs: "bs = b1 @ d # b2" by auto from Cons(2) Cons(3) have "mset ds \# mset (b1 @ b2) + as" "length ds < length (b1 @ b2)" by (auto simp: ac_simps bs) from Cons(1)[OF this] obtain b1' b b2' where split: "b1 @ b2 = b1' @ b # b2'" and sub: "mset ds \# mset (b1' @ b2') + as" by auto from split[unfolded append_eq_append_conv2] obtain us where "b1 = b1' @ us \ us @ b2 = b # b2' \ b1 @ us = b1' \ b2 = us @ b # b2'" .. thus ?thesis proof assume "b1 @ us = b1' \ b2 = us @ b # b2'" hence *: "b1 @ us = b1'" "b2 = us @ b # b2'" by auto hence bs: "bs = (b1 @ d # us) @ b # b2'" unfolding bs by auto show ?thesis by (intro exI conjI, rule bs, insert * sub, auto simp: ac_simps) next assume "b1 = b1' @ us \ us @ b2 = b # b2'" hence *: "b1 = b1' @ us" "us @ b2 = b # b2'" by auto show ?thesis proof (cases us) case Nil with * have *: "b1 = b1'" "b2 = b # b2'" by auto hence bs: "bs = (b1' @ [d]) @ b # b2'" unfolding bs by simp show ?thesis by (intro exI conjI, rule bs, insert * sub, auto simp: ac_simps) next case (Cons u vs) with * have *: "b1 = b1' @ b # vs" "vs @ b2 = b2'" by auto hence bs: "bs = b1' @ b # (vs @ d # b2)" unfolding bs by auto show ?thesis by (intro exI conjI, rule bs, insert * sub, auto simp: ac_simps) qed qed next define as' where "as' = as - {#d#}" assume "d \# as" hence as': "as = {#d#} + as'" unfolding as'_def by auto from Cons(2)[unfolded as'] Cons(3) have "mset ds \# mset bs + as'" "length ds < length bs" by (auto simp: ac_simps) from Cons(1)[OF this] obtain b1 b b2 where bs: "bs = b1 @ b # b2" and sub: "mset ds \# mset (b1 @ b2) + as'" by auto show ?thesis by (intro exI conjI, rule bs, insert sub, auto simp: as' ac_simps) qed qed lemma max_factor_degree_aux: fixes es :: "nat list" assumes sub: "mset ds \# mset es" and len: "length ds + length ds \ length es" and sort: "sorted es" shows "sum_list ds \ sum_list (drop (length es div 2) es)" proof - define bef where "bef = take (length es div 2) es" define aft where "aft = drop (length es div 2) es" have es: "es = bef @ aft" unfolding bef_def aft_def by auto from len have len: "length ds \ length bef" "length ds \ length aft" unfolding bef_def aft_def by auto from sub have sub: "mset ds \# mset bef + mset aft" unfolding es by auto from sort have sort: "sorted (bef @ aft)" unfolding es . show ?thesis unfolding aft_def[symmetric] using sub len sort proof (induct ds arbitrary: bef aft) case (Cons d ds bef aft) have "d \# mset (d # ds)" by auto with Cons(2) have "d \# mset bef + mset aft" by (rule mset_subset_eqD) hence "d \ set bef \ d \ set aft" by auto thus ?case proof assume "d \ set aft" from this[unfolded in_set_conv_decomp] obtain a1 a2 where aft: "aft = a1 @ d # a2" by auto from Cons(4) have len_a: "length ds \ length (a1 @ a2)" unfolding aft by auto from Cons(2)[unfolded aft] Cons(3) have "mset ds \# mset bef + (mset (a1 @ a2))" "length ds < length bef" by auto from mset_sub_decompose[OF this] obtain b b1 b2 where bef: "bef = b1 @ b # b2" and sub: "mset ds \# (mset (b1 @ b2) + mset (a1 @ a2))" by auto from Cons(3) have len_b: "length ds \ length (b1 @ b2)" unfolding bef by auto from Cons(5)[unfolded bef aft] have sort: "sorted ( (b1 @ b2) @ (a1 @ a2))" unfolding sorted_append by auto note IH = Cons(1)[OF sub len_b len_a sort] show ?thesis using IH unfolding aft by simp next assume "d \ set bef" from this[unfolded in_set_conv_decomp] obtain b1 b2 where bef: "bef = b1 @ d # b2" by auto from Cons(3) have len_b: "length ds \ length (b1 @ b2)" unfolding bef by auto from Cons(2)[unfolded bef] Cons(4) have "mset ds \# mset aft + (mset (b1 @ b2))" "length ds < length aft" by (auto simp: ac_simps) from mset_sub_decompose[OF this] obtain a a1 a2 where aft: "aft = a1 @ a # a2" and sub: "mset ds \# (mset (b1 @ b2) + mset (a1 @ a2))" by (auto simp: ac_simps) from Cons(4) have len_a: "length ds \ length (a1 @ a2)" unfolding aft by auto from Cons(5)[unfolded bef aft] have sort: "sorted ( (b1 @ b2) @ (a1 @ a2))" and ad: "d \ a" unfolding sorted_append by auto note IH = Cons(1)[OF sub len_b len_a sort] show ?thesis using IH ad unfolding aft by simp qed qed auto qed lemma max_factor_degree: assumes sub: "mset ws \# mset vs" and len: "length ws + length ws \ length vs" shows "degree (prod_list ws) \ max_factor_degree (map degree vs)" proof - define ds where "ds \ map degree ws" define es where "es \ sort (map degree vs)" from sub len have sub: "mset ds \# mset es" and len: "length ds + length ds \ length es" and es: "sorted es" unfolding ds_def es_def by (auto simp: image_mset_subseteq_mono) have "degree (prod_list ws) \ sum_list (map degree ws)" by (rule degree_prod_list_le) also have "\ \ max_factor_degree (map degree vs)" unfolding max_factor_degree_def Let_def ds_def[symmetric] es_def[symmetric] using sub len es by (rule max_factor_degree_aux) finally show ?thesis . qed lemma degree_bound: assumes sub: "mset ws \# mset vs" and len: "length ws + length ws \ length vs" shows "degree (prod_list ws) \ degree_bound vs" using max_factor_degree[OF sub len] unfolding degree_bound_def by auto end