/* Determine alignment of types. | |
Copyright (C) 2003-2004, 2006, 2009-2023 Free Software Foundation, Inc. | |
This file is free software: you can redistribute it and/or modify | |
it under the terms of the GNU Lesser General Public License as | |
published by the Free Software Foundation; either version 2.1 of the | |
License, or (at your option) any later version. | |
This file is distributed in the hope that it will be useful, | |
but WITHOUT ANY WARRANTY; without even the implied warranty of | |
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the | |
GNU Lesser General Public License for more details. | |
You should have received a copy of the GNU Lesser General Public License | |
along with this program. If not, see <https://www.gnu.org/licenses/>. */ | |
/* alignof_slot (TYPE) | |
Determine the alignment of a structure slot (field) of a given type, | |
at compile time. Note that the result depends on the ABI. | |
This is the same as alignof (TYPE). | |
Note: The result cannot be used as a value for an 'enum' constant, | |
due to bugs in HP-UX 10.20 cc and AIX 3.2.5 xlc. */ | |
template <class type> struct alignof_helper { char __slot1; type __slot2; }; | |
/* alignof_type (TYPE) | |
Determine the good alignment of an object of the given type at compile time. | |
Note that this is not necessarily the same as alignof_slot(type). | |
For example, with GNU C on x86 platforms and with clang on Linux/x86: | |
alignof_type(long long) = 8, but alignof_slot(long long) = 4. | |
And alignof_type(double) = 8, but | |
- when -malign-double is not specified: alignof_slot(double) = 4, | |
- when -malign-double is specified: alignof_slot(double) = 8. | |
Note: The result cannot be used as a value for an 'enum' constant, | |
due to bugs in HP-UX 10.20 cc and AIX 3.2.5 xlc. */ | |