Reformat with black

parse.py

@@ -2,18 +2,20 @@ import re
 import os
 import xml.etree.ElementTree as ET
 
+
 def get_refs(root):
     refs = []
 
     for child in root:
-        if child.tag == 'scripRef':
-            if 'osisRef' in child.attrib:
-                refs.append(child.attrib['osisRef'])
+        if child.tag == "scripRef":
+            if "osisRef" in child.attrib:
+                refs.append(child.attrib["osisRef"])
 
     return refs
 
+
 def get_text_content(root, strip_ref=False):
-    """ Return the plain text content of a node
+    """Return the plain text content of a node
 
     This will:
 
@@ -26,7 +28,7 @@ def get_text_content(root, strip_ref=False):
 
     for child in root:
         if child.text:
-            if child.tag != 'scripRef' or not strip_ref:
+            if child.tag != "scripRef" or not strip_ref:
                 text += child.text
         if child.tail:
             # Add the root node text between this child and the next child
@@ -41,10 +43,12 @@ def get_text_content(root, strip_ref=False):
 
     return text
 
+
 def get_paras():
     paras = []
 
     from pathlib import Path
+
     for filename in list(Path(".").rglob("*.xml")):
         filename = str(filename)
         if "authInfo." in filename:
@@ -55,16 +59,16 @@ def get_paras():
         except:
             print("ERROR: Unable to parse:", filename)
             continue
-            
+
         root = tree.getroot()
 
-        #for i, p in enumerate(root.findall(".//p[scripRef]")):
+        # for i, p in enumerate(root.findall(".//p[scripRef]")):
         for i, p in enumerate(root.findall(".//p")):
             text = get_text_content(p)
 
             if False:
-                text = re.sub(r'".*?"', '...', text, flags=re.M|re.DOTALL)
-                text = re.sub(r'“.*?”', '...', text, flags=re.M|re.DOTALL)
+                text = re.sub(r'".*?"', "...", text, flags=re.M | re.DOTALL)
+                text = re.sub(r"“.*?”", "...", text, flags=re.M | re.DOTALL)
 
                 # Remove spaces before punctuation
                 text = re.sub(r"[\t\n ]\.", ".", text)
@@ -75,14 +79,15 @@ def get_paras():
 
             refs = get_refs(p)
 
-            if len(text) > 160 and 'id' in p.attrib:
+            if len(text) > 160 and "id" in p.attrib:
                 yield {
-                    "id": filename + ":" + p.attrib['id'],
+                    "id": filename + ":" + p.attrib["id"],
                     "refs": refs,
                     "text": text,
-                    "text-noref": get_text_content(p, strip_ref=True)
+                    "text-noref": get_text_content(p, strip_ref=True),
                 }
 
+
 from datasets import Dataset
 
 ds = Dataset.from_generator(get_paras)