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Browse files- .gitignore +52 -0
- LICENSE +201 -0
- README.md +38 -12
- main.py +17 -0
- pre-requirements.txt +0 -0
- prompt.txt +71 -0
- reader.py +61 -0
- requirements.txt +38 -0
- utils.py +28 -0
.gitignore
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# Virtual environments
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pyenv
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# Output file
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output.txt
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output.png
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solution.out
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ag.err
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# Gradio
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.gradio
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# Python cache
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__pycache__
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ag4masses/alphageometry/__pycache__/alphageometry.cpython-310.pyc
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ag4masses/alphageometry/__pycache__/ar.cpython-310.pyc
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ag4masses/alphageometry/__pycache__/beam_search.cpython-310.pyc
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ag4masses/alphageometry/__pycache__/dd.cpython-310.pyc
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ag4masses/alphageometry/__pycache__/ddar.cpython-310.pyc
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ag4masses/alphageometry/__pycache__/decoder_stack.cpython-310.pyc
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ag4masses/alphageometry/__pycache__/geometry.cpython-310.pyc
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ag4masses/alphageometry/__pycache__/graph_utils.cpython-310.pyc
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ag4masses/alphageometry/__pycache__/graph.cpython-310.pyc
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ag4masses/alphageometry/__pycache__/lm_inference.cpython-310.pyc
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ag4masses/alphageometry/__pycache__/models.cpython-310.pyc
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ag4masses/alphageometry/__pycache__/numericals.cpython-310.pyc
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ag4masses/alphageometry/__pycache__/pretty.cpython-310.pyc
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ag4masses/alphageometry/__pycache__/problem.cpython-310.pyc
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ag4masses/alphageometry/__pycache__/trace_back.cpython-310.pyc
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ag4masses/alphageometry/__pycache__/transformer_layer.cpython-310.pyc
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ag4mtest/ag.err
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ag4mtest/ag.out
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aglib/meliad/__pycache__/metrics_summary.cpython-310.pyc
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aglib/meliad/__pycache__/optimizer_config.cpython-310.pyc
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aglib/meliad/__pycache__/training_loop.cpython-310.pyc
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aglib/meliad/__pycache__/training_task.cpython-310.pyc
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aglib/meliad/transformer/__pycache__/__init__.cpython-310.pyc
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aglib/meliad/transformer/__pycache__/attention.cpython-310.pyc
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aglib/meliad/transformer/__pycache__/decoder_stack.cpython-310.pyc
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aglib/meliad/transformer/__pycache__/inference_utils.cpython-310.pyc
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aglib/meliad/transformer/__pycache__/memory_factory.cpython-310.pyc
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aglib/meliad/transformer/__pycache__/memory_layer.cpython-310.pyc
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aglib/meliad/transformer/__pycache__/metric_utils.cpython-310.pyc
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aglib/meliad/transformer/__pycache__/models.cpython-310.pyc
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aglib/meliad/transformer/__pycache__/nn_components.cpython-310.pyc
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aglib/meliad/transformer/__pycache__/position_fourier.cpython-310.pyc
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aglib/meliad/transformer/__pycache__/position_t5.cpython-310.pyc
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aglib/meliad/transformer/__pycache__/position.cpython-310.pyc
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aglib/meliad/transformer/__pycache__/synthetic_text_data.cpython-310.pyc
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aglib/meliad/transformer/__pycache__/text_dataset.cpython-310.pyc
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aglib/meliad/transformer/__pycache__/transformer_base.cpython-310.pyc
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aglib/meliad/transformer/__pycache__/transformer_layer.cpython-310.pyc
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LICENSE
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README.md
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# GeoGenSolver: Generative Illustration and Solver for Vietnamese Geometric Problem
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# Requirements
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Linux or Windows WSL with Python 3.10
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# Setup
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## Clone this Repo
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```
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git clone https://github.com/HugoVox/GeoGenSolver.git
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cd GeoGenSolver
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```
|
10 |
+
## Install necessary Linux packages
|
11 |
+
Depending on the exact Linux distribution/version, you may need to install these packages if they are not already installed.
|
12 |
+
```
|
13 |
+
sudo apt update
|
14 |
+
sudo apt install python3-virtualenv
|
15 |
+
sudo apt install python3-tk
|
16 |
+
```
|
17 |
+
## Install Python module dependencies
|
18 |
+
Create a virtual env `pyenv` for GeoGenSolver
|
19 |
+
```
|
20 |
+
virtualenv -p python3 pyenv
|
21 |
+
. pyenv/bin/activate
|
22 |
+
pip install --require-hashes --no-deps -r pre-requirements.txt
|
23 |
+
pip install --no-deps -r requirements.txt
|
24 |
+
```
|
25 |
+
**Note** It is important to install the requirements in the instructed order and templates.
|
26 |
+
## Run
|
27 |
+
For example we have the following geometric problem: `Cho tam giác cân ABC (AB = AC), các đường cao AD, BE, cắt nhau tại H. Gọi O là tâm đường tròn ngoại tiếp tam giác AHE. Chứng minh rằng: Bốn điểm A, E, D, B cùng nằm trên một đường tròn.`, here is how it runs
|
28 |
+
```
|
29 |
+
python main.py --question "Cho tam giác cân ABC (AB = AC), các đường cao AD, BE, cắt nhau tại H. Gọi O là tâm đường tròn ngoại tiếp tam giác AHE. Chứng minh rằng: Bốn điểm A, E, D, B cùng nằm trên một đường tròn."
|
30 |
+
```
|
31 |
+
We implement both Gemma2 and GPT 4o. Default is GPT 4o.
|
32 |
+
```
|
33 |
+
# If you want to use Gemma2
|
34 |
+
python main.py --model "gemma2-9b-it" --question <input question here>
|
35 |
+
```
|
36 |
+
# Issue Log
|
37 |
+
**Error:** Running main.py returns `Permission Denied`
|
38 |
|
39 |
+
**Solution:** Run the following command: `chmod +x ag4masses/utils/run.sh`. Then rerun the executing command above again.
|
main.py
ADDED
@@ -0,0 +1,17 @@
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
1 |
+
from reader import Reader
|
2 |
+
from utils import *
|
3 |
+
import argparse
|
4 |
+
|
5 |
+
if __name__ == '__main__':
|
6 |
+
parser = argparse.ArgumentParser(description='Generate Geometry Answer')
|
7 |
+
parser.add_argument('--model', type=str, default='gpt-4o-mini', help='Model to use for generation', choices=['gpt-4o-mini', 'gemma2-9b-it'])
|
8 |
+
parser.add_argument('--question', type=str, required=True, help='Question to generate answer for')
|
9 |
+
args = parser.parse_args()
|
10 |
+
if args.model == 'gpt-4o-mini':
|
11 |
+
get_github_token()
|
12 |
+
elif args.model == 'gemma2-9b-it':
|
13 |
+
get_grog_api()
|
14 |
+
reader = Reader(model=args.model)
|
15 |
+
input = translate(args.question)
|
16 |
+
reader.main(input)
|
17 |
+
run_ag()
|
pre-requirements.txt
ADDED
The diff for this file is too large to render.
See raw diff
|
|
prompt.txt
ADDED
@@ -0,0 +1,71 @@
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
1 |
+
You are an Artificial General Intelligence. Your task is to provide the problem definition language based on the problem statement.
|
2 |
+
1. Problem Definition Format: Each problem is represented as a sequence of premises followed by a conclusion.
|
3 |
+
- Premises: Define points, lines, and circles. Use clauses to construct points step-by-step as if drawn with a compass and straightedge.
|
4 |
+
- Conclusion: A single statement verifying the final geometry condition.
|
5 |
+
2. Premise Structure:
|
6 |
+
- Clauses: Each clause specifies one or more points using defined actions. Clauses are separated by ';', with no trailing ';' before the '?' that separates premises from the conclusion.
|
7 |
+
- Actions: Each clause uses one or two actions to define points in terms of geometry constraints.
|
8 |
+
######
|
9 |
+
Example:
|
10 |
+
- For constructing the midpoint M of segment AB: m = midpoint m a b
|
11 |
+
- To intersect a line and a circle at P: p = on_circle p o a, on_line p b c
|
12 |
+
######
|
13 |
+
3. Actions: Use only the following actions, each with a specific format and function. Clauses with 2 actions define points by their intersection.
|
14 |
+
3.1. Basic Point Constructions:
|
15 |
+
- x = angle_bisector x a b c : Construct a point X on the angle bisector of angle ABC
|
16 |
+
- x = circle x a b c : Construct point X as the circumcenter of ABC, or ABC inscribed in (X)
|
17 |
+
- x = foot x a b c : Construct X as the foot of A on BC
|
18 |
+
- x = incenter x a b c : Construct X as the incenter of ABC
|
19 |
+
- x y z i = incenter2 x y z i a b c : Construct I as the incenter of ABC with touchpoints X, Y, Z
|
20 |
+
- x y = segment x y : Construct two distinct points X, Y
|
21 |
+
- x = excenter x a b c : Construct X as the excenter of ABC
|
22 |
+
- x = lc_tangent x a o : Construct E on the tangent of circle (O, A) with touchpoint A
|
23 |
+
- x = tangent x o a : Construct X such that OA is perpendicular to AX
|
24 |
+
- x = midpoint x a b : Construct X as the midpoint of AB'
|
25 |
+
- x = mirror x a b : Construct X such that B is the midpoint of AX
|
26 |
+
- x = on_bline x a b : Construct X on the perpendicular bisector of AB
|
27 |
+
- x = on_circle x o a : Construct X such that OA = OX
|
28 |
+
- x = on_line x a b : Construct X on line AB
|
29 |
+
- x = on_pline x a b c : Construct X such that XA is parallel to BC
|
30 |
+
- x = on_tline x a b c : Construct X such that XA is perpendicular to BC
|
31 |
+
- x = orthocenter x a b c : Construct X as the orthocenter of ABC
|
32 |
+
- x = parallelogram x a b c : Construct X such that ABCX is a parallelogram
|
33 |
+
- a b c = r_triangle a b c : Construct right triangle ABC
|
34 |
+
- a b c = triangle a b c : Construct triangle ABC
|
35 |
+
- a b c = iso_triangle a b c : Construct isosceles triangle ABC such that AB = AC
|
36 |
+
- a b c d = isquare a b c d : Construct square ABCD
|
37 |
+
- x y = tangent x y a o b : Construct points X, Y as the tangent touch points from A to circle (O, B)
|
38 |
+
3.2. Intersection Actions:
|
39 |
+
- x = on_line x a b, on_line x c d : Construct point X as the intersection of line AB and line CD
|
40 |
+
- x = on_circle x o a, on_line x b c : Construct point X as the intersection of line BC and circle (O, A)
|
41 |
+
- x = lc_tangent x a o, on_line x b c : Construct point X as the intersection of the tangent of circle (O, A) with touchpoint A and line BC
|
42 |
+
- x = on_line x a b, angle_bisector x c d e : Construct point X as the intersection of line AB and the angle bisector of angle CDE
|
43 |
+
- x = on_tline x a b c, on_circle x o d : Construct point X as the intersection of the line perpendicular to BC from A and circle (O, D)
|
44 |
+
- x = on_circle x o a, angle_bisector x c d e : Construct point X as the intersection of circle (O, A) and the angle bisector of angle CDE
|
45 |
+
- x = on_pline x a b c, on_circle x o d : Construct point X as the intersection of the line parallel to BC from A and circle (O, D)
|
46 |
+
- x = on_tline x a b c, on_tline x d e f : Construct point X as the intersection of the line perpendicular to BC from A and the line perpendicular to EF from D
|
47 |
+
4. Conclusion Types: After ?, state a single goal from the list below:
|
48 |
+
- coll a b c : points a b c are collinear
|
49 |
+
- cong a b c e : segments ab and cd are congruent (length equal)
|
50 |
+
- contri a b c p q r : triangles abc and pqr are congruent
|
51 |
+
- cyclic a b c d : 4 points a b c d are cocyclic, or quadrilateral abcd is inscribed, or quadrilateral abcd is cyclic
|
52 |
+
- eqangle a b c d p q r s : the angles between lines ab-cd and pq-rs are equal. Note that angles have directions (signs) so the order between a b and c d matters. eqangle a b c d c d a b is false. The way to think about it is, angle ab-cd is the angle to turn line ab clockwise so it is parallel with the line cd. You can use counter-clockwise as the convention too, as long as for all angles the same convention is used
|
53 |
+
- eqratio a b c d p q r s : segment length ab/cd = pq/rs, or ab.rs = cd.pq
|
54 |
+
- midp m a b : point m is the midpoint of a and b
|
55 |
+
- para a b c d : segments ab and cd are parallel
|
56 |
+
- perp a b c d : segments ab and cd are perpendicular to each other
|
57 |
+
- simtri a b c p q r : triangles abc and pqr are similar
|
58 |
+
######
|
59 |
+
Example Problem Transformation:
|
60 |
+
user: Given a triangle ABC with three acute angles connected to the circle (O). The altitudes AD, BE, CF intersect at H and intersect the circle (O) at M, N, P respectively. Prove that: Quadrilateral CEHD is inscribed
|
61 |
+
assistant: a b c = triangle a b c; o = circle o a b c; d = foot d a b c; e = foot e b a c; f = foot f c a b; h = orthocenter h a b c; m = on_line m a d, on_circle m o a; n = on_line n b e, on_circle n o a; p = on_line p c f, on_circle p o a ? cyclic c e h d
|
62 |
+
|
63 |
+
user: Given a right triangle ABC at A. On side AC, take point M, construct a circle (O) with diameter MC. Line BM intersects circle (O) at D. Line AD intersects circle (O) at S. Prove that ABCD is an inscribed quadrilateral.
|
64 |
+
assistant: a b c = r_triangle a b c; m = on_line m a c; o = midpoint o m c; d = on_line d b m, on_circle d o m; s = on_line s a d, on_circle s o m ? cyclic a b c d
|
65 |
+
|
66 |
+
user: Given triangle ABC, bisector AD, median AM. The line perpendicular to AD at D intersects AB, AM at X, Y respectively. The line perpendicular to AB at X intersects AD at Z. Prove that YZ is perpendicular to BC.
|
67 |
+
assistant: a b c = triangle a b c; d = angle_bisector d b a c, on_line d b c; m = midpoint m b c; x = on_tline x d a d, on_line x a b; y = on_tline y d a d, on_line y a m; z = on_tline z x a b, on_line z a d ? perp y z b c
|
68 |
+
|
69 |
+
user: Given acute triangle ABC, Draw altitudes AD, BE, CF. Let H be the orthocenter of the triangle. Let M, N, P, Q be the perpendicular projections of D onto AB, BE, CF, AC, respectively. Prove: quadrilateral BMND is inscribed.
|
70 |
+
assistant: a b c = triangle a b c; d = foot d a b c; e = foot e b a c; f = foot f c a b; h = orthocenter h a b c; m = foot m d a b; n = foot n d b e; p = foot p d c f; q = foot q d a c ? cyclic b m n d
|
71 |
+
######
|
reader.py
ADDED
@@ -0,0 +1,61 @@
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
1 |
+
from groq import Groq
|
2 |
+
from openai import OpenAI
|
3 |
+
import os
|
4 |
+
import regex as re
|
5 |
+
class Reader:
|
6 |
+
def __init__(self, model:str):
|
7 |
+
self.model_name = model
|
8 |
+
if model == 'gemma2-9b-it':
|
9 |
+
self.client = Groq()
|
10 |
+
elif model == 'gpt-4o-mini':
|
11 |
+
token = os.environ["GITHUB_TOKEN"]
|
12 |
+
endpoint = "https://models.inference.ai.azure.com"
|
13 |
+
self.client = OpenAI(base_url=endpoint,api_key=token)
|
14 |
+
self.prompt = None
|
15 |
+
def get_prompt(self) -> str:
|
16 |
+
"""
|
17 |
+
Get the prompt from the prompt.txt file
|
18 |
+
"""
|
19 |
+
with open('prompt.txt', 'r', encoding='utf-8') as f:
|
20 |
+
self.prompt = f.read()
|
21 |
+
def refine(self, input:str) -> str:
|
22 |
+
"""
|
23 |
+
Refine the input
|
24 |
+
"""
|
25 |
+
fix = re.sub(r'[;]\s*[?]\s*', ' ? ', input)
|
26 |
+
clean = re.sub(r'\s+', ' ', fix)
|
27 |
+
return clean
|
28 |
+
def reader(self, input: str) -> str:
|
29 |
+
"""
|
30 |
+
Generate a response from the input
|
31 |
+
Args:
|
32 |
+
input (str): Math question from the user
|
33 |
+
|
34 |
+
Returns:
|
35 |
+
str: The generated response
|
36 |
+
"""
|
37 |
+
|
38 |
+
chat_completion = self.client.chat.completions.create(
|
39 |
+
messages=[
|
40 |
+
{ "role": "system", "content": self.prompt},
|
41 |
+
{ "role": "user", "content": input,}
|
42 |
+
],
|
43 |
+
model=self.model_name,
|
44 |
+
temperature=0.5,
|
45 |
+
max_tokens=2048,
|
46 |
+
top_p=1.0,
|
47 |
+
stop=None,
|
48 |
+
stream=False,
|
49 |
+
)
|
50 |
+
return self.refine(chat_completion.choices[0].message.content)
|
51 |
+
def write_output(self, output:str):
|
52 |
+
"""
|
53 |
+
Write the output to the output.txt file
|
54 |
+
"""
|
55 |
+
with open('ag4mout/output.txt', 'w', encoding='utf-8') as f:
|
56 |
+
f.write("Output\n")
|
57 |
+
f.write(output.strip())
|
58 |
+
def main(self, input:str) -> str:
|
59 |
+
self.get_prompt()
|
60 |
+
result = self.reader(input)
|
61 |
+
self.write_output(result)
|
requirements.txt
ADDED
@@ -0,0 +1,38 @@
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
1 |
+
aiofiles==23.2.1
|
2 |
+
annotated-types==0.7.0
|
3 |
+
anyio==4.6.0
|
4 |
+
certifi==2024.8.30
|
5 |
+
colorama==0.4.6
|
6 |
+
deep-translator==1.11.4
|
7 |
+
distro==1.9.0
|
8 |
+
exceptiongroup==1.2.2
|
9 |
+
fastapi==0.115.4
|
10 |
+
ffmpy==0.4.0
|
11 |
+
gradio==5.5.0
|
12 |
+
gradio-client==1.4.2
|
13 |
+
groq==0.11.0
|
14 |
+
h11==0.14.0
|
15 |
+
httpcore==1.0.6
|
16 |
+
httpx==0.27.2
|
17 |
+
huggingface-hub==0.25.1
|
18 |
+
idna==3.10
|
19 |
+
jinja2==3.1.4
|
20 |
+
jiter==0.7.0
|
21 |
+
openai==1.54.3
|
22 |
+
orjson==3.10.11
|
23 |
+
pydantic==2.9.2
|
24 |
+
pydantic-core==2.23.4
|
25 |
+
python-multipart==0.0.12
|
26 |
+
pydub==0.25.1
|
27 |
+
ruff==0.7.3
|
28 |
+
safehttpx==0.1.1
|
29 |
+
semantic-version==2.10.0
|
30 |
+
shellingham==1.5.4
|
31 |
+
sniffio==1.3.1
|
32 |
+
starlette==0.41.2
|
33 |
+
tomlkit==0.12.0
|
34 |
+
tqdm==4.67.0
|
35 |
+
typer==0.13.0
|
36 |
+
typing-extensions==4.12.2
|
37 |
+
uvicorn==0.32.0
|
38 |
+
websockets==12.0
|
utils.py
ADDED
@@ -0,0 +1,28 @@
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
1 |
+
import subprocess, os
|
2 |
+
import regex as re
|
3 |
+
from deep_translator import GoogleTranslator
|
4 |
+
def get_grog_api():
|
5 |
+
os.environ["GROQ_API_KEY"]="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"
|
6 |
+
def get_github_token():
|
7 |
+
os.environ['GITHUB_TOKEN'] ="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"
|
8 |
+
def translate(input:str) -> str:
|
9 |
+
translated = GoogleTranslator(source='vi', target='en').translate(text=input)
|
10 |
+
return translated
|
11 |
+
def run_ag():
|
12 |
+
subprocess.run(["ag4masses/utils/run.sh"])
|
13 |
+
def read_solution():
|
14 |
+
with open('ag4mout/solution.out', 'r', encoding='utf-8') as f:
|
15 |
+
lines = f.readlines()
|
16 |
+
paragraphs = ''.join(lines).split('\n\n')
|
17 |
+
theorem_premises = paragraphs[0].strip()
|
18 |
+
auxiliary_constructions = paragraphs[1].strip()
|
19 |
+
proof_steps = paragraphs[2].strip()
|
20 |
+
proof_steps = re.sub(r'\d+\. ', '- Ta có:\n', proof_steps)
|
21 |
+
proof_steps = re.sub(r' & ', '\n', proof_steps)
|
22 |
+
proof_steps = re.sub(r' ⇒ ', '\n⇒ ', proof_steps)
|
23 |
+
result = {
|
24 |
+
theorem_premises.split('\n')[0]: GoogleTranslator(target='vi').translate(text='\n'.join(theorem_premises.split('\n')[1:])),
|
25 |
+
auxiliary_constructions.split('\n')[0]: GoogleTranslator(target='vi').translate(text='\n'.join(auxiliary_constructions.split('\n')[1:])),
|
26 |
+
proof_steps.split('\n')[0]: GoogleTranslator(target='vi').translate(text='\n'.join(proof_steps.split('\n')[1:]))
|
27 |
+
}
|
28 |
+
return result
|