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Zhangir Azerbayev
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let EXAMPLE = prove
(`!n. nsum(0..n) (\i. i) = (n*(n + 1)) DIV 2`,
INDUCT_TAC THEN ASM_REWRITE_TAC[NSUM_CLAUSES_NUMSEG] THEN ARITH_TAC);;
let EXAMPLE_IN_MIZAR_LIGHT = thm `;
!n. nsum (0..n) (\i. i) = (n * (n + 1)) DIV 2 [1]
proof
nsum (0..0) (\i. i) = 0 [2] by NSUM_CLAUSES_NUMSEG;
... = (0 * (0 + 1)) DIV 2 [3] by ARITH_TAC;
!n. nsum (0..n) (\i. i) = (n * (n + 1)) DIV 2
==> nsum (0..SUC n) (\i. i) = (SUC n * (SUC n + 1)) DIV 2 [4]
proof
let n be num;
assume nsum (0..n) (\i. i) = (n * (n + 1)) DIV 2 [5];
qed by #;
qed by INDUCT_TAC from 3,4`;;