Datasets:

---

math-eval

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TAL-SCQ5K

like 56

[]

[ [ { "aoVal": "A", "content": "Wednesday " } ], [ { "aoVal": "B", "content": "Thursday " } ], [ { "aoVal": "C", "content": "Friday " } ], [ { "aoVal": "D", "content": "Saturday " } ], [ { "aoVal": "E", "content": "Sunday " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time" ]

[ "$$30\\div7=4 \\text{R} 2$$, two days after Thursday, which is Saturday. " ]

[]

[ [ { "aoVal": "A", "content": "$$200$$ g " } ], [ { "aoVal": "B", "content": "$$300$$ g " } ], [ { "aoVal": "C", "content": "$$400$$ g " } ], [ { "aoVal": "D", "content": "$$500$$ g " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Concentration Problems" ]

[ "$$120\\div(1-70\\textbackslash\\%)=400$$ g. " ]

[]

[ [ { "aoVal": "A", "content": "$$7$$ " } ], [ { "aoVal": "B", "content": "$$8$$ " } ], [ { "aoVal": "C", "content": "$$9$$ " } ], [ { "aoVal": "D", "content": "$$10$$ " } ], [ { "aoVal": "E", "content": "$$11$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Average Problems " ]

[ "Total cost: $$10\\times 8+11\\times 20=300$$. There are $$10+20=30$$ bottles, so each bottle of the blended juice should be $$300\\div 30=10$$ dollars. " ]

[]

[ [ { "aoVal": "A", "content": "$$70\\textbackslash\\%$$ " } ], [ { "aoVal": "B", "content": "$$72\\textbackslash\\%$$ " } ], [ { "aoVal": "C", "content": "$$75\\textbackslash\\%$$ " } ], [ { "aoVal": "D", "content": "$$74\\textbackslash\\%$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Concentration Problems->Basic Concentration Problems" ]

[ "$$\\dfrac{100\\times50\\textbackslash\\%+400\\times80\\textbackslash\\%}{100+400}=74\\textbackslash\\%$$. " ]

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$2$$ dollars and $$30$$ cents " } ], [ { "aoVal": "B", "content": "$$4$$ dollars and $$60$$ cents " } ], [ { "aoVal": "C", "content": "$$7$$ dollars and $$60$$ cents " } ], [ { "aoVal": "D", "content": "$$3$$ dollars and $$80$$ cents " } ], [ { "aoVal": "E", "content": "$$6$$ dollars and $$10$$ cents " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Word Problems in Economics->Complex Money Word Problems" ]

[ "$$2$$ dollars and $$30$$ cents + $$3$$ dollars and $$80$$ = $$6$$ dollars and $$10$$ cents " ]

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$90$$ " } ], [ { "aoVal": "B", "content": "$$95$$ " } ], [ { "aoVal": "C", "content": "$$96$$ " } ], [ { "aoVal": "D", "content": "$$97$$ " } ], [ { "aoVal": "E", "content": "$$98$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Percentages Word Problems" ]

[ "The percent decrease is (the amount of decrease)/(original amount) the amount of decrease is $56-2=54$ so the percent decrease is $\\frac{54}{56}$ which is about $ 96 \\textbackslash\\%$ " ]

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$36$$ " } ], [ { "aoVal": "B", "content": "$$39$$ " } ], [ { "aoVal": "C", "content": "$$41$$ " } ], [ { "aoVal": "D", "content": "$$44$$ " } ], [ { "aoVal": "E", "content": "$$48$$ " } ], [ { "aoVal": "F", "content": "None of the above " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Work Word Problems" ]

[ "C " ]

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$12$$ " } ], [ { "aoVal": "B", "content": "$$24$$ " } ], [ { "aoVal": "C", "content": "$$36$$ " } ], [ { "aoVal": "D", "content": "$$48$$ " } ], [ { "aoVal": "E", "content": "$$60$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Interval Problems" ]

[ "$12 \\times (3 - 1) = 24$ " ]

[]

[ [ { "aoVal": "A", "content": "$$24$$ " } ], [ { "aoVal": "B", "content": "$$36$$ " } ], [ { "aoVal": "C", "content": "$$48$$ " } ], [ { "aoVal": "D", "content": "$$60$$ " } ], [ { "aoVal": "E", "content": "$$72$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Proportions->Dividing Quantities Based on Ratio" ]

[ "Assume that $$C$$ borrows $$$20$$. Therefore, $$A:B:C = 4:3:4$$, for a total sum of $$11$$ increments, or $$$220$$. One increment is $$220\\div 11=20$$ dollars. Therefore, $$C$$ has a total of $$4\\times 20-20=60$$ dollars. " ]

[]

[ [ { "aoVal": "A", "content": "Sunday　 " } ], [ { "aoVal": "B", "content": "Monday　 " } ], [ { "aoVal": "C", "content": "Wednesday　 " } ], [ { "aoVal": "D", "content": "Tuesday　 " } ], [ { "aoVal": "E", "content": "Saturday　 " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time" ]

[ "There are 29 days between $$29^{}\\text{th}$$May and~ $$1$$\\textsuperscript{st~}May. Apart from $29$\\textsuperscript{th} May itself, there are 28 days = 4 week. Therefore,~~$$1$$\\textsuperscript{st~}March is Monday. " ]

[]

[ [ { "aoVal": "A", "content": "$$18$$ " } ], [ { "aoVal": "B", "content": "$$20$$ " } ], [ { "aoVal": "C", "content": "$$24$$ " } ], [ { "aoVal": "D", "content": "$$22$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Unitary Method with One Variable" ]

[ "Linda paid ＄$$8$$ for $$4$$ potatoes, $$8\\div4=2$$, so we can know $$1$$ potatoes cost $$2$$ dollars. In total Linda should pay $$2\\times10=20$$ dollars for $$10$$ potatoes. " ]

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$163$$ " } ], [ { "aoVal": "B", "content": "$$165$$ " } ], [ { "aoVal": "C", "content": "$$171$$ " } ], [ { "aoVal": "D", "content": "$$173$$ " } ], [ { "aoVal": "E", "content": "$$178$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Average Problems " ]

[ "$(170-168)-(168-160)-(168-162)+(175-168)=-5$. $168+5=173$. " ]

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$5$$ " } ], [ { "aoVal": "B", "content": "$$4$$ " } ], [ { "aoVal": "C", "content": "$$3$$ " } ], [ { "aoVal": "D", "content": "$$2$$ " } ], [ { "aoVal": "E", "content": "$$1$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Applying Multiplication and Division->Simple Multiplication Applications" ]

[ "There were $8\\times2=16$ slices. $13+1=14$ slices of pizza were ate, so there were $16-14=2$ slices left. " ]

[]

[ [ { "aoVal": "A", "content": "January　 " } ], [ { "aoVal": "B", "content": "February　 " } ], [ { "aoVal": "C", "content": "March　 " } ], [ { "aoVal": "D", "content": "April　 " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time" ]

[ "Since $$12\\times166 +1= 1992 + 1= 1993$$, the month will be April. " ]

[]

[ [ { "aoVal": "A", "content": "$$25000$$ " } ], [ { "aoVal": "B", "content": "$$100000$$ " } ], [ { "aoVal": "C", "content": "$$160000$$ " } ], [ { "aoVal": "D", "content": "$$225000$$ " } ], [ { "aoVal": "E", "content": "$$275000$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Finding the Base" ]

[ "A $$90\\textbackslash\\%$$ decrease means $$10\\textbackslash\\%$$ of $$250000 = 250000 \\div 10 = 25000$$ of the lions remain. " ]

[]

[ [ { "aoVal": "A", "content": "$$0$$ " } ], [ { "aoVal": "B", "content": "$$1$$ " } ], [ { "aoVal": "C", "content": "$$3$$ " } ], [ { "aoVal": "D", "content": "$$4$$ " } ], [ { "aoVal": "E", "content": "$$5$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Work Word Problems->Simple Work Word Problems" ]

[ "When not being used, the cell phone uses up $$\\dfrac{1}{36}$$ of its battery per hour. When being used, the cell phone uses up $$\\dfrac{1}{10}$$ of its battery per hour. Since Annie\\textquotesingle s phone has been on for $$20$$ hours, of those $$18$$ simply on and $2$ being used, $$18\\times\\left(\\dfrac{1}{36}\\right)+2\\times\\left(\\dfrac{1}{10}\\right)=\\dfrac{7}{10}$$ of its battery has been used up. To drain the remaining $$\\dfrac{3}{10}$$, the phone can last for $$(\\frac{3}{10}-3\\times\\frac1{10})\\div \\frac1{36}=0$$ more hours without being used. " ]

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$4$$ " } ], [ { "aoVal": "B", "content": "$$4.8$$ " } ], [ { "aoVal": "C", "content": "$$19.2$$ " } ], [ { "aoVal": "D", "content": "$$20$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Percentages Word Problems" ]

[ "$24 \\times 80$\\%=$19.2$, $24-19.2=4.8$, $4.8$ liters of milk is left with him. " ]

[]

[ [ { "aoVal": "A", "content": "$$3^{rd}$$ " } ], [ { "aoVal": "B", "content": "$$4^{th}$$ " } ], [ { "aoVal": "C", "content": "$$10^{th}$$ " } ], [ { "aoVal": "D", "content": "$$11^{th}$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Inverse Operation Problems->Inverse Operations" ]

[ "$3+8-7+6=10$ " ]

[]

[ [ { "aoVal": "A", "content": "$$60\\text{kg}$$ " } ], [ { "aoVal": "B", "content": "$$66\\text{kg}$$ " } ], [ { "aoVal": "C", "content": "$$69\\text{kg}$$ " } ], [ { "aoVal": "D", "content": "$$70\\text{kg}$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Sum, Difference and Multiples->Problems Involving Sum and Difference->Sum and Differences Problems with multiple Variables" ]

[ "Nil " ]

[]

[ [ { "aoVal": "A", "content": "$$3$$ " } ], [ { "aoVal": "B", "content": "$$6$$ " } ], [ { "aoVal": "C", "content": "$$8$$ " } ], [ { "aoVal": "D", "content": "$$12$$ " } ], [ { "aoVal": "E", "content": "$$15$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Sum, Difference and Multiples->Problems of Difference and Multiple->Differences and Multiples of Two Variables->Differences and Integer Multiples" ]

[ "Difference: $4+4=8$ " ]

[]

[ [ { "aoVal": "A", "content": "$$20$$ ounces " } ], [ { "aoVal": "B", "content": "$$30$$ ounces " } ], [ { "aoVal": "C", "content": "$$40$$ ounces " } ], [ { "aoVal": "D", "content": "$$50$$ ounces " } ], [ { "aoVal": "E", "content": "$$60$$ ounces " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Proportions->Dividing Quantities Based on Ratio" ]

[ "The ratio of flour to milk is $$2:10$$ or $$1:5$$. With $$10$$ ounces of flour, you could make as many as $$5$$ puddings. At the same time, you need $$50$$ more ounces of milk. The ratio of flour to milk is $$10:50$$, or $$1:5$$. " ]

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$1991$$ " } ], [ { "aoVal": "B", "content": "$$1992$$ " } ], [ { "aoVal": "C", "content": "$$1994$$ " } ], [ { "aoVal": "D", "content": "$$1996$$ " } ], [ { "aoVal": "E", "content": "$$1998$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Interval Problems" ]

[ "$62-58=4$ $2008-4-10=1994$ " ]

[]

[ [ { "aoVal": "A", "content": "$$33$$ " } ], [ { "aoVal": "B", "content": "$$34$$ " } ], [ { "aoVal": "C", "content": "$$35$$ " } ], [ { "aoVal": "D", "content": "$$36$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Problems Involving Queuing->Finding the Total Number According to the Position of one Character in a Line" ]

[ "If there are a total of $$110$$ people in line, subtract those behind Frank and Frank himself: $$110-76-1=33$$, the number in front of Frank. " ]

[]

[ [ { "aoVal": "A", "content": "$$4$$ " } ], [ { "aoVal": "B", "content": "$$6$$ " } ], [ { "aoVal": "C", "content": "$$10$$ " } ], [ { "aoVal": "D", "content": "$$12$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Distribution Problems->Basic Distribution Problems" ]

[ "If $2-1=1$ less card is given to students, the situation would transfer from \\textquotesingle a shortage of $12$ cards\\textquotesingle~ to \\textquotesingle all cards are just divided\\textquotesingle{} . Therefore. the shortage of $12$ cards is equal to the number of cards that everyone gets $1$ less card. So, there are in total $12\\div1=12$ students. " ]

[]

[ [ { "aoVal": "A", "content": "February $$14$$ " } ], [ { "aoVal": "B", "content": "February $$15$$ " } ], [ { "aoVal": "C", "content": "February $$16$$ " } ], [ { "aoVal": "D", "content": "February $$17$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time" ]

[ "It\\textquotesingle s $$92$$ days $$\\left( 30+31+31 \\right)$$ from Nov. $$6$$ to Feb. $$6$$;~$$8$$ days later is $$100$$ days. " ]

[]

[ [ { "aoVal": "A", "content": "$$8\\text{p}$$ " } ], [ { "aoVal": "B", "content": "$$10\\text{p}$$ " } ], [ { "aoVal": "C", "content": "$$25\\text{p}$$ " } ], [ { "aoVal": "D", "content": "$$40\\text{p}$$ " } ], [ { "aoVal": "E", "content": "$$80\\text{p}$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Finding the Total Value using Unitary Method" ]

[ "All but $$10$$ of the coins are $$1\\text{p}$$ coins, which tells us that the number of $$2\\text{p}$$ and $$5\\text{p}$$ coins adds up to $$10$$. Similarly, the total of the $$1\\text{p}$$ and $$5\\text{p}$$ coins is $$10$$ and the total of the $$1\\text{p}$$ and $$2\\text{p}$$ coins is $$10$$. He therefore has $$5$$ of each coin, giving a total of $$(5 \\times1)+ (5 \\times2)+(5\\times5)=40\\text{p}$$. " ]

[]

[ [ { "aoVal": "A", "content": "$$12$$ " } ], [ { "aoVal": "B", "content": "$$13$$ " } ], [ { "aoVal": "C", "content": "$$14$$ " } ], [ { "aoVal": "D", "content": "$$15$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Applying Addition and Subtraction->Simple Addition and Subtraction" ]

[ "Quadrilaterals, trapezoids, and parallelograms each have $$4$$ sides each, so the total number of sides is $$4+4+4=12$$. " ]

[]

[ [ { "aoVal": "A", "content": "$$7$$ " } ], [ { "aoVal": "B", "content": "$$8$$ " } ], [ { "aoVal": "C", "content": "$$12$$ " } ], [ { "aoVal": "D", "content": "$$15$$ " } ], [ { "aoVal": "E", "content": "$$16$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Problems Involving Queuing->Finding the Total Number According to the Position of one Character in a Line" ]

[ "The pirate captain was the $$8$$\\textsuperscript{th}~pirate and there were as many pirates in front of him as behind him, which means there were $$7$$ pirates in front of him and there were also $$7$$ pirates behind him. The total number of pirates is~~$$7+7+1=15$$. " ]

[]

[ [ { "aoVal": "A", "content": "Thursday " } ], [ { "aoVal": "B", "content": "Friday " } ], [ { "aoVal": "C", "content": "Saturday " } ], [ { "aoVal": "D", "content": "Sunday " } ], [ { "aoVal": "E", "content": "Monday " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time" ]

[ "$2000$ is a leap year and the period includes $29$ Feb, so there are $366$ days. $366\\div7=52$ R $2$ Friday $+$ $2$ days $\\rightarrow$ Sunday " ]

[]

[ [ { "aoVal": "A", "content": "$$1$$ m " } ], [ { "aoVal": "B", "content": "$$2$$ m " } ], [ { "aoVal": "C", "content": "$$3$$ m " } ], [ { "aoVal": "D", "content": "$$4$$ m " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Interval Problems->Straight Line Type with Objects on Both Sides" ]

[ "The $$9-1=8$$ intervals are $$7\\times8=56$$ meters in total. So, the sum of length of all the benches is $$74-56=18$$ meters and each of them is $$18\\div9=2$$ meters. " ]

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$12$$ " } ], [ { "aoVal": "B", "content": "$$24$$ " } ], [ { "aoVal": "C", "content": "$$28$$ " } ], [ { "aoVal": "D", "content": "$$30$$ " } ], [ { "aoVal": "E", "content": "$$36$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules" ]

[ "The black parts of the straw was $$12+12=24$$ cm, so the part not colored was $$24\\div2=12$$ cm. Thus, the length of the straw was $$24+12=36$$ cm. " ]

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$21$$ " } ], [ { "aoVal": "B", "content": "$$19$$ " } ], [ { "aoVal": "C", "content": "$$18$$ " } ], [ { "aoVal": "D", "content": "$$16$$ " } ], [ { "aoVal": "E", "content": "$$15$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Newton's Problem of Cows and Fields->Basic Newton's Problem of Cows and Fields->Finding the Number of Cows" ]

[ "B " ]

[]

[ [ { "aoVal": "A", "content": "$$5$$ " } ], [ { "aoVal": "B", "content": "$$6$$ " } ], [ { "aoVal": "C", "content": "$$7$$ " } ], [ { "aoVal": "D", "content": "$$8$$ " } ], [ { "aoVal": "E", "content": "$$9$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Equation Word Problems->Indefinite Equation Word Problems" ]

[ "Let Billy have $$b$$ lambs and $$3b$$ llamas. Let Milly have $$m$$ llamas and $$2m$$ lambs. Therefore, as they have $$17$$ animals in total, $$4b + 3m= 17$$. The only positive integer solution of this equation is $$b= 2$$, $$m= 3$$. So the number of llamas is $$3b + m = 3 \\times 2 + 3 = 6 + 3 = 9$$. " ]

[]

[ [ { "aoVal": "A", "content": "$$100$$ g " } ], [ { "aoVal": "B", "content": "$$25.5$$ g " } ], [ { "aoVal": "C", "content": "$$25$$ g " } ], [ { "aoVal": "D", "content": "$$102$$ g " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Concentration Problems->Basic Concentration Problems" ]

[ "$$75\\div(1-25\\textbackslash\\%) = 100$$ g. " ]

[]

[ [ { "aoVal": "A", "content": "$$35$$ m " } ], [ { "aoVal": "B", "content": "$$49$$ m " } ], [ { "aoVal": "C", "content": "$$47$$ m " } ], [ { "aoVal": "D", "content": "$$54$$ m " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Interval Problems->Straight Line Type with Objects on Both Sides" ]

[ "Among the $$7$$ buses, there are $$7-1=6$$ intervals. So the answer is $$7\\times5+2\\times6=47$$ meters. " ]

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$24$$ " } ], [ { "aoVal": "B", "content": "$$25$$ " } ], [ { "aoVal": "C", "content": "$$144$$ " } ], [ { "aoVal": "D", "content": "$$18$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Interval Problems" ]

[ "Number of sakura intervals = $$37-1 = 36$$ Length of road = $$36 \\times 4 = 144m$$ Number of pineapple intervals = $$144m \\div 6m = 24$$ Number of pineapple trees = $$24 + 1 = 25$$ " ]

[]

[ [ { "aoVal": "A", "content": "$$20$$ " } ], [ { "aoVal": "B", "content": "$$30$$ " } ], [ { "aoVal": "C", "content": "$$40$$ " } ], [ { "aoVal": "D", "content": "$$60$$ " } ], [ { "aoVal": "E", "content": "$$90$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Sum, Difference and Multiples->Problems of Sum and Multiple" ]

[ "Let Agnijo have $$n$$ apps. Now Sam has $$2n$$, and Naomi $$6n$$. Therefore $$n+2n+6n = 9n = 180$$, and so $$n = 180\\div9 = 20$$. Hence Sam has $$2\\times20 = 40$$ apps. " ]

[]

[ [ { "aoVal": "A", "content": "$$6$$ " } ], [ { "aoVal": "B", "content": "$$8$$ " } ], [ { "aoVal": "C", "content": "$$10$$ " } ], [ { "aoVal": "D", "content": "$$5$$ " } ], [ { "aoVal": "E", "content": "$$4$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Unitary Method with One Variable" ]

[ "$(23-3)\\div2=10$ " ]

[]

[ [ { "aoVal": "A", "content": "Sunday " } ], [ { "aoVal": "B", "content": "Monday " } ], [ { "aoVal": "C", "content": "Tuesday " } ], [ { "aoVal": "D", "content": "Wednesday " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time->Period of Dates" ]

[ "$26-10=16$, $16\\div7=2\\textbackslash{} \\rm R\\textasciitilde2$,~ it\\textquotesingle s Tuesday. " ]

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$126$$ " } ], [ { "aoVal": "B", "content": "$$124$$ " } ], [ { "aoVal": "C", "content": "$$534$$ " } ], [ { "aoVal": "D", "content": "$$634$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules" ]

[ "$$380-254=126$$ " ]

[]

[ [ { "aoVal": "A", "content": "$$45$$ " } ], [ { "aoVal": "B", "content": "$$50$$ " } ], [ { "aoVal": "C", "content": "$$55$$ " } ], [ { "aoVal": "D", "content": "$$65$$ " } ], [ { "aoVal": "E", "content": "$$75$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Interval Problems->Straight Line Type with Objects on Both Sides->Planting Trees on Both Sides" ]

[ "$(11-1)\\times5=50$ " ]

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$5600$$ " } ], [ { "aoVal": "B", "content": "$$5700$$ " } ], [ { "aoVal": "C", "content": "$$5800$$ " } ], [ { "aoVal": "D", "content": "$$6000$$ " } ], [ { "aoVal": "E", "content": "$$6100$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Practical Application of Arithmetic Progression" ]

[ "$1000 + 1100 + 1200 + 1300 + 1400 = 6000$ " ]

[]

[ [ { "aoVal": "A", "content": "$$5$$ " } ], [ { "aoVal": "B", "content": "$$6$$ " } ], [ { "aoVal": "C", "content": "$$7$$ " } ], [ { "aoVal": "D", "content": "$$8$$ " } ], [ { "aoVal": "E", "content": "$$9$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Equation Word Problems->Word Problems for Linear Equations with One Variable" ]

[ "Suppose Olivia has $$x$$ correct answers. $$5x-2(10-x)=29$$, $$x=7$$. " ]

[]

[ [ { "aoVal": "A", "content": "$$120$$ " } ], [ { "aoVal": "B", "content": "$$90$$ " } ], [ { "aoVal": "C", "content": "$$85$$ " } ], [ { "aoVal": "D", "content": "$$60$$ " } ], [ { "aoVal": "E", "content": "$$55$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Inverse Operation Problems" ]

[ "Now, Wendy had $30-3-7=20$ stickers. Then, all of them had $20\\times3=60$ stickers, which was equal to the total number of stickers they had at beginning. " ]

[]

[ [ { "aoVal": "A", "content": "＄$$3.50$$ " } ], [ { "aoVal": "B", "content": "＄$$4.00$$ " } ], [ { "aoVal": "C", "content": "＄$$5.00$$ " } ], [ { "aoVal": "D", "content": "＄$$5.50$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Finding the Total Value using Unitary Method" ]

[ "If $$60$$ beans cost ＄$$3.00$$, then $$1$$ bean costs $$5$$￠and $$100$$ beans cost ＄$$5$$. " ]

[]

[ [ { "aoVal": "A", "content": "$$790$$ " } ], [ { "aoVal": "B", "content": "$$810$$ " } ], [ { "aoVal": "C", "content": "$$910$$ " } ], [ { "aoVal": "D", "content": "$$990$$ " } ], [ { "aoVal": "E", "content": "$$1010$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Applying Addition and Subtraction->Simple Addition and Subtraction" ]

[ "The number of years from William\\textquotesingle s birth is $$2018 - 1028 = 990$$. " ]

[ "其它" ]

[ [ { "aoVal": "A", "content": "-0.5 and the two goods are substitutes. " } ], [ { "aoVal": "B", "content": "-0.5 and the two goods are complements. " } ], [ { "aoVal": "C", "content": "0.5 and the two goods are complements. " } ], [ { "aoVal": "D", "content": "-2 and the two goods are substitutes. " } ], [ { "aoVal": "E", "content": "2 and the two goods are complements. " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules" ]

[ "This is an application of the cross-price elasticity equation: \\% change in QDx/\\% change in Py. -0.10/0.2 = -0.5. A negative number means the goods are complements. " ]

[]

[ [ { "aoVal": "A", "content": "$$$0.25$$ " } ], [ { "aoVal": "B", "content": "$$$1.50$$ " } ], [ { "aoVal": "C", "content": "$$$2.25$$ " } ], [ { "aoVal": "D", "content": "$$$3.00$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Finding the Total Value using Unitary Method" ]

[ "One bag costs $$75$$￠. Three such bags cost $$3\\times $0.75=$2.25$$. " ]

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$1$$ " } ], [ { "aoVal": "B", "content": "$$2$$ " } ], [ { "aoVal": "C", "content": "$$3$$ " } ], [ { "aoVal": "D", "content": "$$4$$ " } ], [ { "aoVal": "E", "content": "$$5$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Percentages Word Problems" ]

[ "Sally made $0.4 * 20=8$ shots originally. Letting $x$ be the number of shots she made, we have $\\frac{8+x}{25}=0.52$. Solving for $x$ gives us $x=5$ " ]

[]

[ [ { "aoVal": "A", "content": "Sunday " } ], [ { "aoVal": "B", "content": "Monday " } ], [ { "aoVal": "C", "content": "Tuesday " } ], [ { "aoVal": "D", "content": "Wednesday " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time" ]

[ "Number of days from $$1$$ August to $$12$$ September $$=31+12-1$$ $$=42$$ $$42\\div 7=6$$ weeks Therefore, $$12$$ September will fall on \\textbf{Monday}. " ]

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$8$$ " } ], [ { "aoVal": "B", "content": "$$10$$ " } ], [ { "aoVal": "C", "content": "$$12$$ " } ], [ { "aoVal": "D", "content": "$$14$$ " } ], [ { "aoVal": "E", "content": "$$16$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Equation Word Problems" ]

[ "$50\\div 2=25$ let $x$ be the number of bicycles, $y$ be the number of tricycles $2x+3y=64$ $x+y=25$ " ]

[]

[ [ { "aoVal": "A", "content": "$$37\\text{m}$$ " } ], [ { "aoVal": "B", "content": "$$41\\text{m}$$ " } ], [ { "aoVal": "C", "content": "$$50\\text{m}$$ " } ], [ { "aoVal": "D", "content": "$$55\\text{m}$$ " } ], [ { "aoVal": "E", "content": "$$60\\text{m}$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Distance Word Problems->Distance Word Problems on Straight Road" ]

[ "Carol finishes $$25$$ metres behind Bridgit, so she travels $$75$$ metres while Bridgit runs $$100$$ metres. Therefore she runs $$3$$ metres for every $$4$$ metres Bridgit runs. When Anna finishes, Bridgit has run $$84$$ metres, so that at that time Carol has run $$\\frac{3}{4}\\times 84$$ metres $$=63$$ metres. Hence Carol finishes $$\\left( 100-63 \\right)$$ metres $$= 37$$ metres behind Anna. " ]

[]

[ [ { "aoVal": "A", "content": "$$192$$ " } ], [ { "aoVal": "B", "content": "$$208$$ " } ], [ { "aoVal": "C", "content": "$$240$$ " } ], [ { "aoVal": "D", "content": "$$288$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Finding the Unit Rate and then the Total Value" ]

[ "If $$6$$ cans contain $$96$$ teaspoons of sugar, $$1$$ can contains $$96\\div6 = 16$$ teaspoons of sugar. Thus $$15$$ cans contain $$16\\times15 =240$$ teaspoons of sugar. " ]

[]

[ [ { "aoVal": "A", "content": "Tuesday " } ], [ { "aoVal": "B", "content": "Monday " } ], [ { "aoVal": "C", "content": "Sunday " } ], [ { "aoVal": "D", "content": "Wednesday " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time" ]

[ "$2018$ was a common year which had $365$ days. Thus, January $$1$$st, $$2019$$ fell on one day after Monday, which was Tuesday. " ]

[]

[ [ { "aoVal": "A", "content": "$$16$$ " } ], [ { "aoVal": "B", "content": "$$18$$ " } ], [ { "aoVal": "C", "content": "$$20$$ " } ], [ { "aoVal": "D", "content": "$$21$$ " } ], [ { "aoVal": "E", "content": "$$23$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules" ]

[ "NA " ]

[]

[ [ { "aoVal": "A", "content": "$$18$$ " } ], [ { "aoVal": "B", "content": "$$21$$ " } ], [ { "aoVal": "C", "content": "$$35$$ " } ], [ { "aoVal": "D", "content": "$$42$$ " } ], [ { "aoVal": "E", "content": "$$43$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Equation Word Problems->Word Problems for Linear Equations with One Variable" ]

[ "Suppose there are $$x$$ ducks in the yard. Since there is an equal number of pigs, ducks and chickens, $$2x+4x+2x=144$$, $$x=18$$. " ]

[]

[ [ { "aoVal": "A", "content": "$$70$$ cents " } ], [ { "aoVal": "B", "content": "$$80$$ cents " } ], [ { "aoVal": "C", "content": "$$90$$ cents " } ], [ { "aoVal": "D", "content": "$$1$$ dollar " } ], [ { "aoVal": "E", "content": "$$1$$ dollar $$10$$ cents " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Distribution Problems->Basic Distribution Problems" ]

[ "$$(80+30)\\div (4-3)=110$$ cents $$=1$$ dollar and $$10$$ cents. " ]

[]

[ [ { "aoVal": "A", "content": "$15\\textbackslash\\%$ " } ], [ { "aoVal": "B", "content": "$20\\textbackslash\\%$ " } ], [ { "aoVal": "C", "content": "$25\\textbackslash\\%$ " } ], [ { "aoVal": "D", "content": "$30\\textbackslash\\%$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Word Problems in Economics->Basic Profit and Loss Concepts->Calculating Price from Cost and Profit" ]

[ "$$100\\div \\left( 100+400\\right) \\times 100\\textbackslash\\% =20\\textbackslash\\%$$. ~~ " ]

[]

[ [ { "aoVal": "A", "content": "$$1$$ " } ], [ { "aoVal": "B", "content": "$$2$$ " } ], [ { "aoVal": "C", "content": "$$3$$ " } ], [ { "aoVal": "D", "content": "$$4$$ " } ], [ { "aoVal": "E", "content": "$$5$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Concentration Problems" ]

[ "Use the cross method $$\\begin{matrix}30\\textbackslash\\%10\\textbackslash\\% \\textbackslash\\textbackslash{} \\searrow \\swarrow \\textbackslash\\textbackslash{} 26 \\textbackslash\\% \\textbackslash\\textbackslash{} \\swarrow \\searrow \\textbackslash\\textbackslash{} 16 \\textbackslash\\%4\\textbackslash\\% \\textbackslash\\textbackslash\\end{matrix}$$ to see that the ratio of $$30\\textbackslash\\%$$ solution to $$10\\textbackslash\\%$$ solution is $$4:1$$. Therefore, $$1\\text{kg}$$ of $$10\\textbackslash\\%$$ solution is needed. " ]

[]

[ [ { "aoVal": "A", "content": "$$4$$ " } ], [ { "aoVal": "B", "content": "$$6$$ " } ], [ { "aoVal": "C", "content": "$$10$$ " } ], [ { "aoVal": "D", "content": "$$12$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Distribution Problems->Basic Distribution Problems" ]

[ "$50+10=60$ $60\\div6=10$ " ]

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$25$$ " } ], [ { "aoVal": "B", "content": "$$35$$ " } ], [ { "aoVal": "C", "content": "$$40$$ " } ], [ { "aoVal": "D", "content": "$$45$$ " } ], [ { "aoVal": "E", "content": "$$50$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Percentages Word Problems" ]

[ "Since $30 \\textbackslash\\%$ of the original 30 liters of paint was yellow, and 5 liters of yellow paint were added to make the new mixture, there are $9+5=14$ liters of yellow tint in the new mixture. Since only 5 liters of paint were added to the original 30 , there are a total of 35 liters of paint in the new mixture. This gives $40 \\textbackslash\\%$ of yellow tint in the new mixture, which is (C) 40 . " ]

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$72$$ " } ], [ { "aoVal": "B", "content": "$$60$$ " } ], [ { "aoVal": "C", "content": "$$48$$ " } ], [ { "aoVal": "D", "content": "$$36$$ " } ], [ { "aoVal": "E", "content": "$$32$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Interval Problems" ]

[ "$24 \\div 2 \\times (6 - 1) = 60$ " ]

[]

[ [ { "aoVal": "A", "content": "$$31 \\frac{2}{11}$$ " } ], [ { "aoVal": "B", "content": "$$31 \\frac{3}{11}$$ " } ], [ { "aoVal": "C", "content": "$$32 \\frac{8}{11}$$ " } ], [ { "aoVal": "D", "content": "$$33 \\frac{3}{11}$$ " } ], [ { "aoVal": "E", "content": "None of the above " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules" ]

[ "The minute hand rotates $6^{\\circ}$ per minute. The hour hand rotates $\\dfrac{1}{60}\\times30^{\\circ}=\\left (\\dfrac{1}{2}\\right )^{\\circ}$ per mimte. Starting at $3$ O\\textquotesingle clock, when the minute and hour hands are next perpendicular: $$(90+90)\\div(6-0.5)=\\frac{360}{11}=32 \\frac{8}{11}$$ " ]

[]

[ [ { "aoVal": "A", "content": "$$12$$ " } ], [ { "aoVal": "B", "content": "$$13$$ " } ], [ { "aoVal": "C", "content": "$$14$$ " } ], [ { "aoVal": "D", "content": "$$15$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Practical Application of Arithmetic Progression" ]

[ "$$\\left( 1+62 \\right)\\times 62\\div 2=1953$$ $$1953-1940=13$$. " ]

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$40$$ " } ], [ { "aoVal": "B", "content": "$$60$$ " } ], [ { "aoVal": "C", "content": "$$80$$ " } ], [ { "aoVal": "D", "content": "$120$ " } ], [ { "aoVal": "E", "content": "$$200$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Percentages Word Problems" ]

[ "$50\\textbackslash\\% \\cdot x = 30\\textbackslash\\% \\cdot y$ $ x = 0.6\\cdot y$ " ]

[]

[ [ { "aoVal": "A", "content": "$$10$$ " } ], [ { "aoVal": "B", "content": "$$21$$ " } ], [ { "aoVal": "C", "content": "$$20$$ " } ], [ { "aoVal": "D", "content": "$$15$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Sum, Difference and Multiples->Problems Involving Sum and Difference" ]

[ "$$(31-11)\\div2=10.$$ " ]

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$2.5$$ " } ], [ { "aoVal": "B", "content": "$$3.5$$ " } ], [ { "aoVal": "C", "content": "$$4$$ " } ], [ { "aoVal": "D", "content": "$$4.5$$ " } ], [ { "aoVal": "E", "content": "$$5$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Percentages Word Problems" ]

[ "Since $30 \\textbackslash\\%$ of the original 30 liters of paint was yellow, and 5 liters of yellow paint were added to make the new mixture, there are $9+5=14$ liters of yellow tint in the new mixture. Since only 5 liters of paint were added to the original 30 , there are a total of 35 liters of paint in the new mixture. This gives $40 \\textbackslash\\%$ of yellow tint in the new mixture, which is (C) 40 . " ]

[]

[ [ { "aoVal": "A", "content": "$$10$$ " } ], [ { "aoVal": "B", "content": "$$21$$ " } ], [ { "aoVal": "C", "content": "$$20$$ " } ], [ { "aoVal": "D", "content": "$$15$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Sum, Difference and Multiples->Problems Involving Sum and Difference" ]

[ "$$(31-11)\\div2=10.$$ " ]

[]

[ [ { "aoVal": "A", "content": "$$31 \\frac{2}{11}$$ " } ], [ { "aoVal": "B", "content": "$$31 \\frac{3}{11}$$ " } ], [ { "aoVal": "C", "content": "$$32 \\frac{8}{11}$$ " } ], [ { "aoVal": "D", "content": "$$33 \\frac{3}{11}$$ " } ], [ { "aoVal": "E", "content": "None of the above " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules" ]

[ "The minute hand rotates $6^{\\circ}$ per minute. The hour hand rotates $\\dfrac{1}{60}\\times30^{\\circ}=\\left (\\dfrac{1}{2}\\right )^{\\circ}$ per mimte. Starting at $3$ O\\textquotesingle clock, the minute hand rotates $\\left (6t\\right )^{\\circ}$ and the hour hand rotates ~$$(90+ \\frac{1}{2}t)^{ \\circ }$$. When the minute and hour hands are next perpendicular: $$6t-\\left (90+ \\frac{1}{2}t\\right )=90$$, $$\\frac{11}{2}t=180$$, $$t= \\frac{360}{11}=32 \\frac{8}{11}$$. " ]

[]

[ [ { "aoVal": "A", "content": "Thursday " } ], [ { "aoVal": "B", "content": "Saturday " } ], [ { "aoVal": "C", "content": "Sunday " } ], [ { "aoVal": "D", "content": "Tuesday " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time" ]

[ "It passed $$31-10 + 21 = 42$$ days in total. Since $$42 \\div 7 = 6$$, it was Sunday. " ]

[]

[ [ { "aoVal": "A", "content": "$$16$$ " } ], [ { "aoVal": "B", "content": "$$18$$ " } ], [ { "aoVal": "C", "content": "$$20$$ " } ], [ { "aoVal": "D", "content": "$$21$$ " } ], [ { "aoVal": "E", "content": "$$23$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules" ]

[ "NA " ]

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$16$$ " } ], [ { "aoVal": "B", "content": "$$20$$ " } ], [ { "aoVal": "C", "content": "$$24$$ " } ], [ { "aoVal": "D", "content": "$$28$$ " } ], [ { "aoVal": "E", "content": "$$30$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules" ]

[ "Their difference in age: $$9-5=4$$ When Mike is $$20$$, Sara is $$20-4=16$$ " ]

[]

[ [ { "aoVal": "A", "content": "$$90$$ grams " } ], [ { "aoVal": "B", "content": "$$100$$ grams " } ], [ { "aoVal": "C", "content": "$$120$$ grams " } ], [ { "aoVal": "D", "content": "$$150$$ grams " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Concentration Problems->Basic Concentration Problems" ]

[ "$$18\\div15\\textbackslash\\% = 120$$ ounces. " ]

[]

[ [ { "aoVal": "A", "content": "$$99$$ " } ], [ { "aoVal": "B", "content": "$$100$$ " } ], [ { "aoVal": "C", "content": "$$101$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Interval Problems->Circular Paths" ]

[ "In the case of circular tracks, number of intervals $$=$$ number of trees, $$600\\div 6=100$$, $$100$$ trees are planted round the lake. " ]

[]

[ [ { "aoVal": "A", "content": "Tuesday " } ], [ { "aoVal": "B", "content": "Monday " } ], [ { "aoVal": "C", "content": "Sunday " } ], [ { "aoVal": "D", "content": "Wednesday " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time" ]

[ "$2018$ was a common year which had $365$ days. Thus, January $$1$$, $$2019$$ fell on one day after Monday, which was Tuesday. " ]

[]

[ [ { "aoVal": "A", "content": "$$20000$$ " } ], [ { "aoVal": "B", "content": "$$22000$$ " } ], [ { "aoVal": "C", "content": "$$23000$$ " } ], [ { "aoVal": "D", "content": "$$26000$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Finding the Total Value using Unitary Method" ]

[ "NA " ]

[]

[ [ { "aoVal": "A", "content": "＄$$190$$ " } ], [ { "aoVal": "B", "content": "＄$$200$$ " } ], [ { "aoVal": "C", "content": "＄$$210$$ " } ], [ { "aoVal": "D", "content": "＄$$215$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Finding the Total Value using Unitary Method" ]

[ "$$(168-125)\\times 5 = 215$$. " ]

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$34$$ " } ], [ { "aoVal": "B", "content": "$$37$$ " } ], [ { "aoVal": "C", "content": "$$40$$ " } ], [ { "aoVal": "D", "content": "$$42$$ " } ], [ { "aoVal": "E", "content": "$$44$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules" ]

[ "$$15=3\\times5$$, so $5$ dollars for each book $$3+5=8$$, $8\\times5=40$ " ]

[]

[ [ { "aoVal": "A", "content": "$$180$$ " } ], [ { "aoVal": "B", "content": "$$200$$ " } ], [ { "aoVal": "C", "content": "$$100$$ " } ], [ { "aoVal": "D", "content": "$$225$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Knowing the Base" ]

[ "Hens $=$ baby chickens $\\times\\dfrac{8}{9}$, Roosters $=$ hens $\\times\\dfrac{1}{16}$, We can write the formula as:~$3600\\times\\dfrac{8}{9}\\times\\dfrac{1}{16}=3200\\times\\dfrac{1}{16}=200$. " ]

[]

[ [ { "aoVal": "A", "content": "$$148$$ " } ], [ { "aoVal": "B", "content": "$$152$$ " } ], [ { "aoVal": "C", "content": "$$144$$ " } ], [ { "aoVal": "D", "content": "$$140$$ " } ], [ { "aoVal": "E", "content": "$$156$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Squares->Solid Squares" ]

[ "$$36\\times 4=144$$, or $$37\\times 4-4=144$$ students. " ]

[]

[ [ { "aoVal": "A", "content": "$$1$$ " } ], [ { "aoVal": "B", "content": "$$2$$ " } ], [ { "aoVal": "C", "content": "$$3$$ " } ], [ { "aoVal": "D", "content": "$$4$$ " } ], [ { "aoVal": "E", "content": "$$6$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules" ]

[ "The mushrooms picked by $2$ white rabbits in $3$ days will be eaten by $3$ gray rabbits in $4$ days, so the mushrooms picked by $1$ white rabbits in $1$ days will be eaten by $1$ gray rabbits in $2$ days. Thus, the mushrooms picked by $5$ white rabbits in $6$ days will be eaten by $15$ gray rabbits in $4$ days. " ]

[]

[ [ { "aoVal": "A", "content": "$$1$$ " } ], [ { "aoVal": "B", "content": "$$3$$ " } ], [ { "aoVal": "C", "content": "$$4$$ " } ], [ { "aoVal": "D", "content": "$$2$$ " } ], [ { "aoVal": "E", "content": "$$0$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Knowing the Base" ]

[ "$3-1=2$ " ]

[]

[ [ { "aoVal": "A", "content": "$$20$$ " } ], [ { "aoVal": "B", "content": "$$59$$ " } ], [ { "aoVal": "C", "content": "$$74$$ " } ], [ { "aoVal": "D", "content": "$$91$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Proportions->Complex Ratio Problems" ]

[ "The ratio of red cars to black cars is $$8:5=24:15$$; the ratio of black cars to white cars is $$3:4 = 15:20$$. The minimum number of cars is $$24+15+20 =59$$. " ]

[]

[ [ { "aoVal": "A", "content": "$$19$$ " } ], [ { "aoVal": "B", "content": "$$23$$ " } ], [ { "aoVal": "C", "content": "$$24$$ " } ], [ { "aoVal": "D", "content": "$$25$$ " } ], [ { "aoVal": "E", "content": "$$20$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Applying Addition and Subtraction->Simple Addition and Subtraction" ]

[ "There are $25$ superheroes in total. After subtracting $6$, there are $25-6=19$ left. " ]

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$11$$ " } ], [ { "aoVal": "B", "content": "$$10$$ " } ], [ { "aoVal": "C", "content": "$$9$$ " } ], [ { "aoVal": "D", "content": "$$8$$ " } ], [ { "aoVal": "E", "content": "$$7$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Average Problems " ]

[ "Total points: $$40\\times 25=1000$$. To have as many $100$ points as possible, we should consider there are only two groups of students: everyone gets $5$ points in a group and everyone gets $100$ in the other group. $$10\\times 100=1000$$, so there must be less than $10$ people getting $100$ points. If there are nine $100$s: $$9\\times 100+31\\times 5=1055\\textgreater1000$$, which is impossible. If there are eight $100$s:$$8\\times 100+32\\times 5=960\\textless{}1000$$. Thus, the answer is $$8$$. " ]

[]

[ [ { "aoVal": "A", "content": "$$A$$ " } ], [ { "aoVal": "B", "content": "$$E$$ " } ], [ { "aoVal": "C", "content": "$$V$$ " } ], [ { "aoVal": "D", "content": "$$Z$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Basic Permutation" ]

[ "Since $$806\\div 26=31$$, the $$806$$th letter Iwrite will be the last letter of the $$31$$st time I write the full alphabet; it will be a $$Z$$. " ]

[]

[ [ { "aoVal": "A", "content": "$$15$$ g " } ], [ { "aoVal": "B", "content": "$$18$$ g " } ], [ { "aoVal": "C", "content": "$$20$$ g " } ], [ { "aoVal": "D", "content": "$$25$$ g " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Concentration Problems->Finding and Making Use of Invariants" ]

[ "$$10\\times20\\textbackslash\\%+40\\times 25\\textbackslash\\%=12$$ g. $$(10+40)-12\\div40\\textbackslash\\%=20$$ g. " ]

[]

[ [ { "aoVal": "A", "content": "$$5$$ " } ], [ { "aoVal": "B", "content": "$$6$$ " } ], [ { "aoVal": "C", "content": "$$7$$ " } ], [ { "aoVal": "D", "content": "$$8$$ " } ], [ { "aoVal": "E", "content": "$$9$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Snail Climbing out of Well Problems" ]

[ "It climbs up $$3-1=2$$ meters actually everyday. It takes $$12\\div 2 +1=7$$ days in total, and in the last day, it climbs up $3$ meters. " ]

[]

[ [ { "aoVal": "A", "content": "$$15$$ " } ], [ { "aoVal": "B", "content": "$$45$$ " } ], [ { "aoVal": "C", "content": "$$60$$ " } ], [ { "aoVal": "D", "content": "$$75$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Sum, Difference and Multiples->Questions Involving Varying Multiples" ]

[ "Let the number of Annie\\textquotesingle s and Beth\\textquotesingle s be 2n and n. 2n=4(n-15), so n=30, 2n=30 " ]

[]

[ [ { "aoVal": "A", "content": "$$45$$ " } ], [ { "aoVal": "B", "content": "$$65$$ " } ], [ { "aoVal": "C", "content": "$$80$$ " } ], [ { "aoVal": "D", "content": "$$96$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Finding the Total Value using Unitary Method" ]

[ "It takes $$144$$ workers $$60$$ hours to paint a bridge. That\\textquotesingle s $$144\\times60=8640$$ worker-hours. For $$108$$ workers, the job takes $$8640\\div108=80$$ hours. " ]

[]

[ [ { "aoVal": "A", "content": "$$2 $$ " } ], [ { "aoVal": "B", "content": "$$20 $$ " } ], [ { "aoVal": "C", "content": "$$70 $$ " } ], [ { "aoVal": "D", "content": "$$200 $$ " } ], [ { "aoVal": "E", "content": "$$700$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Sum, Difference and Multiples->Basic Computation of the Multiples" ]

[ "The speed of high-speed train is approximately $$350$$ kilometers per hour, which is approximately $$100$$ meters per second. So its speed is roughly $$20$$ times faster than $$5$$ meters per second. " ]

[]

[ [ { "aoVal": "A", "content": "$$160$$ dollars " } ], [ { "aoVal": "B", "content": "$$180$$ dollars " } ], [ { "aoVal": "C", "content": "$$190$$ dollars " } ], [ { "aoVal": "D", "content": "$$200$$ dollars " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Word Problems in Economics->Basic Profit and Loss Concepts" ]

[ "$$\\left( 125+25 \\right)\\div \\left( 1-25 \\textbackslash\\% \\right)=200$$ dollars. " ]

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[ [ { "aoVal": "A", "content": "$$50$$ " } ], [ { "aoVal": "B", "content": "$$51 \\frac{2}{3}$$ " } ], [ { "aoVal": "C", "content": "$$52 \\frac{1}{2}$$ " } ], [ { "aoVal": "D", "content": "$$53 \\frac{1}{3}$$ " } ], [ { "aoVal": "E", "content": "None of the above " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Equation Word Problems->Word Problems for Linear Equations with One Variable" ]

[ "NA " ]

[ "其它" ]

[ [ { "aoVal": "A", "content": "1~\\textbf{year} " } ], [ { "aoVal": "B", "content": "2~\\textbf{years} " } ], [ { "aoVal": "C", "content": "\\textbf{4 years} " } ], [ { "aoVal": "D", "content": "\\textbf{8 years} " } ], [ { "aoVal": "E", "content": "\\textbf{13 years} " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules" ]

[ "\\textbf{Daniel is learning conservation of number, a skill that Piaget believed children learn in the concrete operational stage} " ]

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[ [ { "aoVal": "A", "content": "$$70$$ " } ], [ { "aoVal": "B", "content": "$$72$$ " } ], [ { "aoVal": "C", "content": "$$75$$ " } ], [ { "aoVal": "D", "content": "$$80$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Concentration Problems->Finding and Making Use of Invariants" ]

[ "$$30\\times30\\textbackslash\\%+20\\times 20\\textbackslash\\%=9+4=13$$ g. $$13\\div10\\textbackslash\\%-(30+20)=80$$ g. ~~ " ]

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[ [ { "aoVal": "A", "content": "$$5$$ " } ], [ { "aoVal": "B", "content": "$$6$$ " } ], [ { "aoVal": "C", "content": "$$7$$ " } ], [ { "aoVal": "D", "content": "$$8$$ " } ], [ { "aoVal": "E", "content": "$$9$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Squares->Hallow Squares" ]

[ "Put $$1$$ ball in each corner ($$4$$ balls in total). Remaining balls: $$28-4=24$$ $$24\\div4=6$$ So, each side has $$1$$ ball at each corner and $$6$$ balls in the middle, giving a total of $$8$$ balls. " ]

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$36$$ " } ], [ { "aoVal": "B", "content": "$$28$$ " } ], [ { "aoVal": "C", "content": "$$69$$ " } ], [ { "aoVal": "D", "content": "$$85$$ " } ], [ { "aoVal": "E", "content": "$$89$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Average Problems " ]

[ "More than average: $$(92.5-91)\\times24=36$$. Each boy should have $$36\\div18=2$$ dollars less than the average, so each of them has $91-2=89$ dollars. " ]

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[ [ { "aoVal": "A", "content": "$$42$$ " } ], [ { "aoVal": "B", "content": "$$30$$ " } ], [ { "aoVal": "C", "content": "$$18$$ " } ], [ { "aoVal": "D", "content": "$$15$$ " } ], [ { "aoVal": "E", "content": "$$10$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Finding the Base" ]

[ "$$1- \\frac{3}{7}= \\frac{4}{7}$$ $24\\div \\frac47=42$ $42-24=18$. " ]

[]

[ [ { "aoVal": "A", "content": "$$6$$ " } ], [ { "aoVal": "B", "content": "$$9$$ " } ], [ { "aoVal": "C", "content": "$$11$$ " } ], [ { "aoVal": "D", "content": "$$12$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Age Problems->When..., When... Type Age Problems" ]

[ "$$7\\times5=35$$, His father was $$35$$ years old when Teddy was $$5$$ years old. Age difference $=35-5=30$ $42-30=12$ years old $\\textasciitilde$ or $\\textasciitilde$ $$7\\times5=35$$, His father was $$35$$ years old when Teddy was $$5$$ years old. $$42-35=7$$ years later $$5+7=12$$ years old $\\textasciitilde$ Teddy will be $$12$$ years old when his father is $$42$$ years old. " ]

[]

[ [ { "aoVal": "A", "content": "$$5$$ " } ], [ { "aoVal": "B", "content": "$$9$$ " } ], [ { "aoVal": "C", "content": "$$10$$ " } ], [ { "aoVal": "D", "content": "$$18$$ " } ], [ { "aoVal": "E", "content": "$$21$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Average Problems " ]

[ "Total height less than the average: $(180-168)\\times5=60$. Thus, there are $60\\div(168-162)=10$ female teachers. " ]