Datasets:

maveriq

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spider

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store_1

SELECT first_name , last_name FROM employees ORDER BY birth_date DESC LIMIT 1;

What si the youngest employee's first and last name?

store_1

SELECT first_name , last_name FROM employees ORDER BY hire_date ASC LIMIT 10;

List top 10 employee work longest in the company. List employee's first and last name.

store_1

SELECT first_name , last_name FROM employees ORDER BY hire_date ASC LIMIT 10;

What are the first and last names of the top 10 longest-serving employees?

store_1

SELECT count(*) , city FROM employees WHERE title = 'IT Staff' GROUP BY city

Find the number of employees whose title is IT Staff from each city?

store_1

SELECT count(*) , city FROM employees WHERE title = 'IT Staff' GROUP BY city

How many employees who are IT staff are from each city?

store_1

SELECT T2.first_name , T2.last_name , count(T1.reports_to) FROM employees AS T1 JOIN employees AS T2 ON T1.reports_to = T2.id GROUP BY T1.reports_to ORDER BY count(T1.reports_to) DESC LIMIT 1;

Which employee manage most number of peoples? List employee's first and last name, and number of people report to that employee.

store_1

SELECT T2.first_name , T2.last_name , count(T1.reports_to) FROM employees AS T1 JOIN employees AS T2 ON T1.reports_to = T2.id GROUP BY T1.reports_to ORDER BY count(T1.reports_to) DESC LIMIT 1;

What are the first and last names of all the employees and how many people report to them?

store_1

SELECT count(*) FROM customers AS T1 JOIN invoices AS T2 ON T1.id = T2.customer_id WHERE T1.first_name = "Lucas" AND T1.last_name = "Mancini";

How many orders does Lucas Mancini has?

store_1

SELECT count(*) FROM customers AS T1 JOIN invoices AS T2 ON T1.id = T2.customer_id WHERE T1.first_name = "Lucas" AND T1.last_name = "Mancini";

How many orders does Luca Mancini have in his invoices?

store_1

SELECT sum(T2.total) FROM customers AS T1 JOIN invoices AS T2 ON T1.id = T2.customer_id WHERE T1.first_name = "Lucas" AND T1.last_name = "Mancini";

What is the total amount of money spent by Lucas Mancini?

store_1

SELECT sum(T2.total) FROM customers AS T1 JOIN invoices AS T2 ON T1.id = T2.customer_id WHERE T1.first_name = "Lucas" AND T1.last_name = "Mancini";

How much money did Lucas Mancini spend?

store_1

SELECT name FROM media_types;

List all media types.

store_1

SELECT name FROM media_types;

What are the names of all the media types?

store_1

SELECT DISTINCT name FROM genres;

List all different genre types.

store_1

SELECT DISTINCT name FROM genres;

What are the different names of the genres?

store_1

SELECT name FROM playlists;

List the name of all playlist.

store_1

SELECT name FROM playlists;

What are the names of all the playlists?

store_1

SELECT composer FROM tracks WHERE name = "Fast As a Shark";

Who is the composer of track Fast As a Shark?

store_1

SELECT composer FROM tracks WHERE name = "Fast As a Shark";

What is the composer who created the track "Fast As a Shark"?

store_1

SELECT milliseconds FROM tracks WHERE name = "Fast As a Shark";

How long does track Fast As a Shark has?

store_1

SELECT milliseconds FROM tracks WHERE name = "Fast As a Shark";

How many milliseconds long is Fast As a Shark?

store_1

SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T1.name = "Rock";

What is the name of tracks whose genre is Rock?

store_1

SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T1.name = "Rock";

What is the name of all tracks in the Rock genre?

store_1

SELECT T1.title FROM albums AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T2.name = "Balls to the Wall";

What is title of album which track Balls to the Wall belongs to?

store_1

SELECT T1.title FROM albums AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T2.name = "Balls to the Wall";

What is the name of the album that has the track Ball to the Wall?

store_1

SELECT T2.name FROM albums AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T1.title = "Balls to the Wall";

List name of all tracks in Balls to the Wall.

store_1

SELECT T2.name FROM albums AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T1.title = "Balls to the Wall";

What is the name of all tracks in the album named Balls to the Wall?

store_1

SELECT T1.title FROM albums AS T1 JOIN tracks AS T2 ON T1.id = T2.album_id GROUP BY T1.id HAVING count(T1.id) > 10;

List title of albums have the number of tracks greater than 10.

store_1

SELECT T1.title FROM albums AS T1 JOIN tracks AS T2 ON T1.id = T2.album_id GROUP BY T1.id HAVING count(T1.id) > 10;

What are the names of the albums that have more than 10 tracks?

store_1

SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id JOIN media_types AS T3 ON T3.id = T2.media_type_id WHERE T1.name = "Rock" AND T3.name = "MPEG audio file";

List the name of tracks belongs to genre Rock and whose media type is MPEG audio file.

store_1

SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id JOIN media_types AS T3 ON T3.id = T2.media_type_id WHERE T1.name = "Rock" AND T3.name = "MPEG audio file";

What are the names of all Rock tracks that are stored on MPEG audio files?

store_1

SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id JOIN media_types AS T3 ON T3.id = T2.media_type_id WHERE T1.name = "Rock" OR T3.name = "MPEG audio file";

List the name of tracks belongs to genre Rock or media type is MPEG audio file.

store_1

SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id JOIN media_types AS T3 ON T3.id = T2.media_type_id WHERE T1.name = "Rock" OR T3.name = "MPEG audio file";

What are the names of all tracks that belong to the Rock genre and whose media type is MPEG?

store_1

SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T1.name = "Rock" OR T1.name = "Jazz"

List the name of tracks belongs to genre Rock or genre Jazz.

store_1

SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T1.name = "Rock" OR T1.name = "Jazz"

What are the names of the tracks that are Rock or Jazz songs?

store_1

SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T3.id = T2.playlist_id WHERE T3.name = "Movies";

List the name of all tracks in the playlists of Movies.

store_1

SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T3.id = T2.playlist_id WHERE T3.name = "Movies";

What are the names of all tracks that are on playlists titled Movies?

store_1

SELECT T2.name FROM playlist_tracks AS T1 JOIN playlists AS T2 ON T2.id = T1.playlist_id GROUP BY T1.playlist_id HAVING count(T1.track_id) > 100;

List the name of playlist which has number of tracks greater than 100.

store_1

SELECT T2.name FROM playlist_tracks AS T1 JOIN playlists AS T2 ON T2.id = T1.playlist_id GROUP BY T1.playlist_id HAVING count(T1.track_id) > 100;

What are the names of all playlists that have more than 100 tracks?

store_1

SELECT T1.name FROM tracks AS T1 JOIN invoice_lines AS T2 ON T1.id = T2.track_id JOIN invoices AS T3 ON T3.id = T2.invoice_id JOIN customers AS T4 ON T4.id = T3.customer_id WHERE T4.first_name = "Daan" AND T4.last_name = "Peeters";

List all tracks bought by customer Daan Peeters.

store_1

SELECT T1.name FROM tracks AS T1 JOIN invoice_lines AS T2 ON T1.id = T2.track_id JOIN invoices AS T3 ON T3.id = T2.invoice_id JOIN customers AS T4 ON T4.id = T3.customer_id WHERE T4.first_name = "Daan" AND T4.last_name = "Peeters";

What are the tracks that Dean Peeters bought?

store_1

SELECT unit_price FROM tracks WHERE name = "Fast As a Shark";

How much is the track Fast As a Shark?

store_1

SELECT unit_price FROM tracks WHERE name = "Fast As a Shark";

What is the unit price of the tune "Fast As a Shark"?

store_1

SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Movies' EXCEPT SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Music'

Find the name of tracks which are in Movies playlist but not in music playlist.

store_1

SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Movies' EXCEPT SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Music'

What are the names of all tracks that are on the Movies playlist but not in the music playlist?

store_1

SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Movies' INTERSECT SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Music'

Find the name of tracks which are in both Movies and music playlists.

store_1

SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Movies' INTERSECT SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Music'

What are the names of all the tracks that are in both the Movies and music playlists?

store_1

SELECT count(*) , T1.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id GROUP BY T1.name;

Find number of tracks in each genre?

store_1

SELECT count(*) , T1.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id GROUP BY T1.name;

How many tracks are in each genre?

journal_committee

SELECT count(*) FROM editor

How many editors are there?

journal_committee

SELECT Name FROM editor ORDER BY Age ASC

List the names of editors in ascending order of age.

journal_committee

SELECT Name , Age FROM editor

What are the names and ages of editors?

journal_committee

SELECT Name FROM editor WHERE Age > 25

List the names of editors who are older than 25.

journal_committee

SELECT Name FROM editor WHERE Age = 24 OR Age = 25

Show the names of editors of age either 24 or 25.

journal_committee

SELECT Name FROM editor ORDER BY Age ASC LIMIT 1

What is the name of the youngest editor?

journal_committee

SELECT Age , COUNT(*) FROM editor GROUP BY Age

What are the different ages of editors? Show each age along with the number of editors of that age.

journal_committee

SELECT Age FROM editor GROUP BY Age ORDER BY COUNT(*) DESC LIMIT 1

Please show the most common age of editors.

journal_committee

SELECT DISTINCT Theme FROM journal

Show the distinct themes of journals.

journal_committee

SELECT T2.Name , T3.Theme FROM journal_committee AS T1 JOIN editor AS T2 ON T1.Editor_ID = T2.Editor_ID JOIN journal AS T3 ON T1.Journal_ID = T3.Journal_ID

Show the names of editors and the theme of journals for which they serve on committees.

journal_committee

SELECT T2.Name , T3.Theme FROM journal_committee AS T1 JOIN editor AS T2 ON T1.Editor_ID = T2.Editor_ID JOIN journal AS T3 ON T1.Journal_ID = T3.Journal_ID

For each journal_committee, find the editor name and the journal theme.

journal_committee

SELECT T2.Name , T2.age , T3.Theme FROM journal_committee AS T1 JOIN editor AS T2 ON T1.Editor_ID = T2.Editor_ID JOIN journal AS T3 ON T1.Journal_ID = T3.Journal_ID ORDER BY T3.Theme ASC

Show the names and ages of editors and the theme of journals for which they serve on committees, in ascending alphabetical order of theme.

journal_committee

SELECT T2.Name FROM journal_committee AS T1 JOIN editor AS T2 ON T1.Editor_ID = T2.Editor_ID JOIN journal AS T3 ON T1.Journal_ID = T3.Journal_ID WHERE T3.Sales > 3000

Show the names of editors that are on the committee of journals with sales bigger than 3000.

journal_committee

SELECT T1.editor_id , T1.Name , COUNT(*) FROM editor AS T1 JOIN journal_committee AS T2 ON T1.Editor_ID = T2.Editor_ID GROUP BY T1.editor_id

Show the id, name of each editor and the number of journal committees they are on.

journal_committee

SELECT T1.Name FROM editor AS T1 JOIN journal_committee AS T2 ON T1.Editor_ID = T2.Editor_ID GROUP BY T1.Name HAVING COUNT(*) >= 2

Show the names of editors that are on at least two journal committees.

journal_committee

SELECT Name FROM editor WHERE editor_id NOT IN (SELECT editor_id FROM journal_committee)

List the names of editors that are not on any journal committee.

journal_committee

SELECT date , theme , sales FROM journal EXCEPT SELECT T1.date , T1.theme , T1.sales FROM journal AS T1 JOIN journal_committee AS T2 ON T1.journal_ID = T2.journal_ID

List the date, theme and sales of the journal which did not have any of the listed editors serving on committee.

journal_committee

SELECT avg(T1.sales) FROM journal AS T1 JOIN journal_committee AS T2 ON T1.journal_ID = T2.journal_ID WHERE T2.work_type = 'Photo'

What is the average sales of the journals that have an editor whose work type is 'Photo'?

customers_card_transactions

SELECT count(*) FROM Accounts

How many accounts do we have?

customers_card_transactions

SELECT count(*) FROM Accounts

Count the number of accounts.

customers_card_transactions

SELECT account_id , customer_id , account_name FROM Accounts

Show ids, customer ids, names for all accounts.

customers_card_transactions

SELECT account_id , customer_id , account_name FROM Accounts

What are the account ids, customer ids, and account names for all the accounts?

customers_card_transactions

SELECT other_account_details FROM Accounts WHERE account_name = "338"

Show other account details for account with name 338.

customers_card_transactions

SELECT other_account_details FROM Accounts WHERE account_name = "338"

What are the other account details for the account with the name 338?

customers_card_transactions

SELECT T2.customer_first_name , T2.customer_last_name , T2.customer_phone FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T1.account_name = "162"

What is the first name, last name, and phone of the customer with account name 162?

customers_card_transactions

SELECT T2.customer_first_name , T2.customer_last_name , T2.customer_phone FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T1.account_name = "162"

Give the full name and phone of the customer who has the account name 162.

customers_card_transactions

SELECT count(*) FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = "Art" AND T2.customer_last_name = "Turcotte"

How many accounts does the customer with first name Art and last name Turcotte have?

customers_card_transactions

SELECT count(*) FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = "Art" AND T2.customer_last_name = "Turcotte"

Return the number of accounts that the customer with the first name Art and last name Turcotte has.

customers_card_transactions

SELECT customer_id , count(*) FROM Accounts GROUP BY customer_id

Show all customer ids and the number of accounts for each customer.

customers_card_transactions

SELECT customer_id , count(*) FROM Accounts GROUP BY customer_id

How many accounts are there for each customer id?

customers_card_transactions

SELECT customer_id , count(*) FROM Accounts GROUP BY customer_id ORDER BY count(*) DESC LIMIT 1

Show the customer id and number of accounts with most accounts.

customers_card_transactions

SELECT customer_id , count(*) FROM Accounts GROUP BY customer_id ORDER BY count(*) DESC LIMIT 1

What is the customer id of the customer with the most accounts, and how many accounts does this person have?

customers_card_transactions

SELECT T2.customer_first_name , T2.customer_last_name , T1.customer_id FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY count(*) ASC LIMIT 1

What is the customer first, last name and id with least number of accounts.

customers_card_transactions

SELECT T2.customer_first_name , T2.customer_last_name , T1.customer_id FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY count(*) ASC LIMIT 1

Give the full name and customer id of the customer with the fewest accounts.

customers_card_transactions

SELECT count(*) FROM Customers WHERE customer_id NOT IN (SELECT customer_id FROM Accounts)

Show the number of all customers without an account.

customers_card_transactions

SELECT count(*) FROM Customers WHERE customer_id NOT IN (SELECT customer_id FROM Accounts)

How many customers do not have an account?

customers_card_transactions

SELECT customer_first_name , customer_last_name FROM Customers EXCEPT SELECT T1.customer_first_name , T1.customer_last_name FROM Customers AS T1 JOIN Accounts AS T2 ON T1.customer_id = T2.customer_id

Show the first names and last names of customers without any account.

customers_card_transactions

SELECT customer_first_name , customer_last_name FROM Customers EXCEPT SELECT T1.customer_first_name , T1.customer_last_name FROM Customers AS T1 JOIN Accounts AS T2 ON T1.customer_id = T2.customer_id

What are the full names of customers who do not have any accounts?

customers_card_transactions

SELECT DISTINCT T1.customer_first_name , T1.customer_last_name FROM Customers AS T1 JOIN Accounts AS T2 ON T1.customer_id = T2.customer_id

Show distinct first and last names for all customers with an account.

customers_card_transactions

SELECT DISTINCT T1.customer_first_name , T1.customer_last_name FROM Customers AS T1 JOIN Accounts AS T2 ON T1.customer_id = T2.customer_id

What are the full names of customers who have accounts?

customers_card_transactions

SELECT count(DISTINCT customer_id) FROM Accounts

How many customers have an account?

customers_card_transactions

SELECT count(DISTINCT customer_id) FROM Accounts

Count the number of customers who hold an account.

customers_card_transactions

SELECT count(*) FROM Customers

How many customers do we have?

customers_card_transactions

SELECT count(*) FROM Customers

Count the number of customers.

customers_card_transactions

SELECT customer_id , customer_first_name , customer_last_name , customer_phone FROM Customers

Show ids, first names, last names, and phones for all customers.

customers_card_transactions

SELECT customer_id , customer_first_name , customer_last_name , customer_phone FROM Customers

What are the ids, full names, and phones of each customer?

customers_card_transactions

SELECT customer_phone , customer_email FROM Customers WHERE customer_first_name = "Aniyah" AND customer_last_name = "Feest"

What is the phone and email for customer with first name Aniyah and last name Feest?

customers_card_transactions

SELECT customer_phone , customer_email FROM Customers WHERE customer_first_name = "Aniyah" AND customer_last_name = "Feest"

Return the phone and email of the customer with the first name Aniyah and last name Feest.

customers_card_transactions

SELECT count(*) FROM Customers_cards

Show the number of customer cards.

customers_card_transactions

SELECT count(*) FROM Customers_cards

How many customer cards are there?

customers_card_transactions

SELECT card_id , customer_id , card_type_code , card_number FROM Customers_cards

Show ids, customer ids, card type codes, card numbers for all cards.