DDL_schema
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CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT flno FROM Flight ORDER BY distance ASC LIMIT 3
What are the numbers of the shortest flights?
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT avg(distance) , avg(price) FROM Flight WHERE origin = "Los Angeles"
What is the average distance and average price for flights from Los Angeles.
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT avg(distance) , avg(price) FROM Flight WHERE origin = "Los Angeles"
What is the average distance and price for all flights from LA?
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT origin , count(*) FROM Flight GROUP BY origin
Show all origins and the number of flights from each origin.
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT origin , count(*) FROM Flight GROUP BY origin
For each origin, how many flights came from there?
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT destination , count(*) FROM Flight GROUP BY destination
Show all destinations and the number of flights to each destination.
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT destination , count(*) FROM Flight GROUP BY destination
What are the destinations and number of flights to each one?
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT origin FROM Flight GROUP BY origin ORDER BY count(*) DESC LIMIT 1
Which origin has most number of flights?
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT origin FROM Flight GROUP BY origin ORDER BY count(*) DESC LIMIT 1
What place has the most flights coming from there?
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT destination FROM Flight GROUP BY destination ORDER BY count(*) LIMIT 1
Which destination has least number of flights?
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT destination FROM Flight GROUP BY destination ORDER BY count(*) LIMIT 1
What destination has the fewest number of flights?
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT T2.name FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid WHERE T1.flno = 99
What is the aircraft name for the flight with number 99
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT T2.name FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid WHERE T1.flno = 99
What is the name of the aircraft that was on flight number 99?
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT T1.flno FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid WHERE T2.name = "Airbus A340-300"
Show all flight numbers with aircraft Airbus A340-300.
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT T1.flno FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid WHERE T2.name = "Airbus A340-300"
What are the flight numbers for the aircraft Airbus A340-300?
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT T2.name , count(*) FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid GROUP BY T1.aid
Show aircraft names and number of flights for each aircraft.
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT T2.name , count(*) FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid GROUP BY T1.aid
What is the name of each aircraft and how many flights does each one complete?
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT T2.name FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid GROUP BY T1.aid HAVING count(*) >= 2
Show names for all aircraft with at least two flights.
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT T2.name FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid GROUP BY T1.aid HAVING count(*) >= 2
What are the names for all aircrafts with at least 2 flights?
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT count(DISTINCT eid) FROM Certificate
How many employees have certificate.
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT count(DISTINCT eid) FROM Certificate
What is the count of distinct employees with certificates?
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT eid FROM Employee EXCEPT SELECT eid FROM Certificate
Show ids for all employees who don't have a certificate.
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT eid FROM Employee EXCEPT SELECT eid FROM Certificate
What are the ids of all employees that don't have certificates?
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT T3.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T1.name = "John Williams"
Show names for all aircrafts of which John Williams has certificates.
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT T3.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T1.name = "John Williams"
What are the names of all aircrafts that John Williams have certificates to be able to fly?
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800"
Show names for all employees who have certificate of Boeing 737-800.
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800"
What are the names of all employees who have a certificate to fly Boeing 737-800?
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800" INTERSECT SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Airbus A340-300"
Show names for all employees who have certificates on both Boeing 737-800 and Airbus A340-300.
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800" INTERSECT SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Airbus A340-300"
What are the names of all employees who can fly both the Boeing 737-800 and the Airbus A340-300?
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT name FROM Employee EXCEPT SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800"
Show names for all employees who do not have certificate of Boeing 737-800.
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT name FROM Employee EXCEPT SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800"
What are the names of all employees who are not certified to fly Boeing 737-800s?
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT T2.name FROM Certificate AS T1 JOIN Aircraft AS T2 ON T2.aid = T1.aid GROUP BY T1.aid ORDER BY count(*) DESC LIMIT 1
Show the name of aircraft which fewest people have its certificate.
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT T2.name FROM Certificate AS T1 JOIN Aircraft AS T2 ON T2.aid = T1.aid GROUP BY T1.aid ORDER BY count(*) DESC LIMIT 1
What are the names of the aircraft that the least people are certified to fly?
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT T2.name FROM Certificate AS T1 JOIN Aircraft AS T2 ON T2.aid = T1.aid WHERE T2.distance > 5000 GROUP BY T1.aid ORDER BY count(*) >= 5
Show the name and distance of the aircrafts with more than 5000 distance and which at least 5 people have its certificate.
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT T2.name FROM Certificate AS T1 JOIN Aircraft AS T2 ON T2.aid = T1.aid WHERE T2.distance > 5000 GROUP BY T1.aid ORDER BY count(*) >= 5
What is the name and distance of every aircraft that can cover a distance of more than 5000 and which at least 5 people can fly?
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT T1.name , T1.salary FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid GROUP BY T1.eid ORDER BY count(*) DESC LIMIT 1
what is the salary and name of the employee who has the most number of aircraft certificates?
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT T1.name , T1.salary FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid GROUP BY T1.eid ORDER BY count(*) DESC LIMIT 1
What is the salaray and name of the employee that is certified to fly the most planes?
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.distance > 5000 GROUP BY T1.eid ORDER BY count(*) DESC LIMIT 1
What is the salary and name of the employee who has the most number of certificates on aircrafts with distance more than 5000?
flight_1
CREATE TABLE flight( flno number(4,0) primary key, origin varchar2(20), destination varchar2(20), distance number(6,0), departure_date date, arrival_date date, price number(7,2), aid number(9,0), foreign key("aid") references `aircraft`("aid")) CREATE TABLE aircraft( aid number(9,0) primary key, name varchar2(30), distance number(6,0)) CREATE TABLE employee( eid number(9,0) primary key, name varchar2(30), salary number(10,2)) CREATE TABLE certificate( eid number(9,0), aid number(9,0), primary key(eid,aid), foreign key("eid") references `employee`("eid"), foreign key("aid") references `aircraft`("aid"))
SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.distance > 5000 GROUP BY T1.eid ORDER BY count(*) DESC LIMIT 1
What is the salaray and name of the employee with the most certificates to fly planes more than 5000?
flight_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT count(DISTINCT allergy) FROM Allergy_type
How many allergies are there?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT count(DISTINCT allergy) FROM Allergy_type
How many allergy entries are there?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT count(DISTINCT allergytype) FROM Allergy_type
How many different allergy types exist?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT count(DISTINCT allergytype) FROM Allergy_type
How many distinct allergies are there?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT DISTINCT allergytype FROM Allergy_type
Show all allergy types.
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT DISTINCT allergytype FROM Allergy_type
What are the different allergy types?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT allergy , allergytype FROM Allergy_type
Show all allergies and their types.
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT allergy , allergytype FROM Allergy_type
What are the allergies and their types?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT DISTINCT allergy FROM Allergy_type WHERE allergytype = "food"
Show all allergies with type food.
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT DISTINCT allergy FROM Allergy_type WHERE allergytype = "food"
What are all the different food allergies?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT allergytype FROM Allergy_type WHERE allergy = "Cat"
What is the type of allergy Cat?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT allergytype FROM Allergy_type WHERE allergy = "Cat"
What is allergy type of a cat allergy?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT count(*) FROM Allergy_type WHERE allergytype = "animal"
How many allergies have type animal?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT count(*) FROM Allergy_type WHERE allergytype = "animal"
How many animal type allergies exist?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT allergytype , count(*) FROM Allergy_type GROUP BY allergytype
Show all allergy types and the number of allergies in each type.
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT allergytype , count(*) FROM Allergy_type GROUP BY allergytype
What are the allergy types and how many allergies correspond to each one?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT allergytype FROM Allergy_type GROUP BY allergytype ORDER BY count(*) DESC LIMIT 1
Which allergy type has most number of allergies?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT allergytype FROM Allergy_type GROUP BY allergytype ORDER BY count(*) DESC LIMIT 1
Which allergy type is most common?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT allergytype FROM Allergy_type GROUP BY allergytype ORDER BY count(*) ASC LIMIT 1
Which allergy type has least number of allergies?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT allergytype FROM Allergy_type GROUP BY allergytype ORDER BY count(*) ASC LIMIT 1
Which allergy type is the least common?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT count(*) FROM Student
How many students are there?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT count(*) FROM Student
What is the total number of students?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT Fname , Lname FROM Student
Show first name and last name for all students.
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT Fname , Lname FROM Student
What are the full names of all students
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT count(DISTINCT advisor) FROM Student
How many different advisors are listed?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT count(DISTINCT advisor) FROM Student
How many advisors are there?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT DISTINCT Major FROM Student
Show all majors.
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT DISTINCT Major FROM Student
What are the different majors?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT DISTINCT city_code FROM Student
Show all cities where students live.
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT DISTINCT city_code FROM Student
What cities do students live in?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT Fname , Lname , Age FROM Student WHERE Sex = 'F'
Show first name, last name, age for all female students. Their sex is F.
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT Fname , Lname , Age FROM Student WHERE Sex = 'F'
What are the full names and ages for all female students whose sex is F?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT StuID FROM Student WHERE Sex = 'M'
Show student ids for all male students.
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT StuID FROM Student WHERE Sex = 'M'
What are the student ids for all male students?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT count(*) FROM Student WHERE age = 18
How many students are age 18?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT count(*) FROM Student WHERE age = 18
How many students are 18 years old?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT StuID FROM Student WHERE age > 20
Show all student ids who are older than 20.
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT StuID FROM Student WHERE age > 20
What are the student ids for students over 20 years old?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT city_code FROM Student WHERE LName = "Kim"
Which city does the student whose last name is "Kim" live in?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT city_code FROM Student WHERE LName = "Kim"
Give the city that the student whose family name is Kim lives in.
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT Advisor FROM Student WHERE StuID = 1004
Who is the advisor of student with ID 1004?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT Advisor FROM Student WHERE StuID = 1004
Who advises student 1004?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT count(*) FROM Student WHERE city_code = "HKG" OR city_code = "CHI"
How many students live in HKG or CHI?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT count(*) FROM Student WHERE city_code = "HKG" OR city_code = "CHI"
Give the number of students living in either HKG or CHI.
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT min(age) , avg(age) , max(age) FROM Student
Show the minimum, average, and maximum age of all students.
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT min(age) , avg(age) , max(age) FROM Student
What is the minimum, mean, and maximum age across all students?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT LName FROM Student WHERE age = (SELECT min(age) FROM Student)
What is the last name of the youngest student?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT LName FROM Student WHERE age = (SELECT min(age) FROM Student)
Provide the last name of the youngest student.
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT StuID FROM Student WHERE age = (SELECT max(age) FROM Student)
Show the student id of the oldest student.
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT StuID FROM Student WHERE age = (SELECT max(age) FROM Student)
What student id corresponds to the oldest student?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT major , count(*) FROM Student GROUP BY major
Show all majors and corresponding number of students.
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT major , count(*) FROM Student GROUP BY major
How many students are there for each major?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT major FROM Student GROUP BY major ORDER BY count(*) DESC LIMIT 1
Which major has most number of students?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT major FROM Student GROUP BY major ORDER BY count(*) DESC LIMIT 1
What is the largest major?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT age , count(*) FROM Student GROUP BY age
Show all ages and corresponding number of students.
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT age , count(*) FROM Student GROUP BY age
How old is each student and how many students are each age?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT avg(age) , sex FROM Student GROUP BY sex
Show the average age for male and female students.
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT avg(age) , sex FROM Student GROUP BY sex
What are the average ages for male and female students?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT city_code , count(*) FROM Student GROUP BY city_code
Show all cities and corresponding number of students.
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT city_code , count(*) FROM Student GROUP BY city_code
How many students live in each city?
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR(20) PRIMARY KEY, AllergyType VARCHAR(20) ) CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR(20), FOREIGN KEY(StuID) REFERENCES Student(StuID), FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy) ) CREATE TABLE Student ( StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3) )
SELECT advisor , count(*) FROM Student GROUP BY advisor
Show all advisors and corresponding number of students.
allergy_1