bug_id
stringlengths 1
3
| task_id
stringlengths 64
64
| function_signature
stringlengths 15
364
| prompt_chat
stringlengths 471
20.2k
| code
stringlengths 44
19.8k
| defective
bool 2
classes | project
stringclasses 17
values | prompt_complete
stringlengths 3.07k
22.8k
|
|---|---|---|---|---|---|---|---|
5 | 366305ebc6f7c700952e843c558df2a82701a1df78a2390af8bbc8faee14290e | public Complex reciprocal() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/** {@inheritDoc} */
public Complex reciprocal() {
if (isNaN) {
return NaN;
}
if (real == 0.0 && imaginary == 0.0) {
return NaN;
}
if (isInfinite) {
return ZERO;
}
if (FastMath.abs(real) < FastMath.abs(imaginary)) {
double q = real / imaginary;
double scale = 1. / (real * q + imaginary);
return createComplex(scale * q, -scale);
} else {
double q = imaginary / real;
double scale = 1. / (imaginary * q + real);
return createComplex(scale, -scale * q);
}
}
```
| public Complex reciprocal() {
if (isNaN) {
return NaN;
}
if (real == 0.0 && imaginary == 0.0) {
return NaN;
}
if (isInfinite) {
return ZERO;
}
if (FastMath.abs(real) < FastMath.abs(imaginary)) {
double q = real / imaginary;
double scale = 1. / (real * q + imaginary);
return createComplex(scale * q, -scale);
} else {
double q = imaginary / real;
double scale = 1. / (imaginary * q + real);
return createComplex(scale, -scale * q);
}
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/** {@inheritDoc} */
public Complex reciprocal() {
if (isNaN) {
return NaN;
}
if (real == 0.0 && imaginary == 0.0) {
return NaN;
}
if (isInfinite) {
return ZERO;
}
if (FastMath.abs(real) < FastMath.abs(imaginary)) {
double q = real / imaginary;
double scale = 1. / (real * q + imaginary);
return createComplex(scale * q, -scale);
} else {
double q = imaginary / real;
double scale = 1. / (imaginary * q + real);
return createComplex(scale, -scale * q);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
35 | 366b3a80a16dbfc64e34e3db7f7b814ea842a23a759f594ed3c029be31f89015 | public List<String> getMatchingOptions(String opt)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns the options with a long name starting with the name specified.
*
* @param opt the partial name of the option
* @return the options matching the partial name specified, or an empty list if none matches
* @since 1.3
*/
public List<String> getMatchingOptions(String opt)
{
opt = Util.stripLeadingHyphens(opt);
List<String> matchingOpts = new ArrayList<String>();
// for a perfect match return the single option only
if(longOpts.keySet().contains(opt)) {
return Collections.singletonList(opt);
}
for (String longOpt : longOpts.keySet())
{
if (longOpt.startsWith(opt))
{
matchingOpts.add(longOpt);
}
}
return matchingOpts;
}
```
| public List<String> getMatchingOptions(String opt)
{
opt = Util.stripLeadingHyphens(opt);
List<String> matchingOpts = new ArrayList<String>();
// for a perfect match return the single option only
if(longOpts.keySet().contains(opt)) {
return Collections.singletonList(opt);
}
for (String longOpt : longOpts.keySet())
{
if (longOpt.startsWith(opt))
{
matchingOpts.add(longOpt);
}
}
return matchingOpts;
} | false | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns the options with a long name starting with the name specified.
*
* @param opt the partial name of the option
* @return the options matching the partial name specified, or an empty list if none matches
* @since 1.3
*/
public List<String> getMatchingOptions(String opt)
{
opt = Util.stripLeadingHyphens(opt);
List<String> matchingOpts = new ArrayList<String>();
// for a perfect match return the single option only
if(longOpts.keySet().contains(opt)) {
return Collections.singletonList(opt);
}
for (String longOpt : longOpts.keySet())
{
if (longOpt.startsWith(opt))
{
matchingOpts.add(longOpt);
}
}
return matchingOpts;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
93 | 369e39538cfbe2f832a83534ca69227835032e57069d32862416cc0287badaea | public List<Connection.KeyVal> formData() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Get the data that this form submits. The returned list is a copy of the data, and changes to the contents of the
* list will not be reflected in the DOM.
* @return a list of key vals
*/
public List<Connection.KeyVal> formData() {
ArrayList<Connection.KeyVal> data = new ArrayList<>();
// iterate the form control elements and accumulate their values
for (Element el: elements) {
if (!el.tag().isFormSubmittable()) continue; // contents are form listable, superset of submitable
if (el.hasAttr("disabled")) continue; // skip disabled form inputs
String name = el.attr("name");
if (name.length() == 0) continue;
String type = el.attr("type");
if ("select".equals(el.normalName())) {
Elements options = el.select("option[selected]");
boolean set = false;
for (Element option: options) {
data.add(HttpConnection.KeyVal.create(name, option.val()));
set = true;
}
if (!set) {
Element option = el.select("option").first();
if (option != null)
data.add(HttpConnection.KeyVal.create(name, option.val()));
}
} else if ("checkbox".equalsIgnoreCase(type) || "radio".equalsIgnoreCase(type)) {
// only add checkbox or radio if they have the checked attribute
if (el.hasAttr("checked")) {
final String val = el.val().length() > 0 ? el.val() : "on";
data.add(HttpConnection.KeyVal.create(name, val));
}
} else {
data.add(HttpConnection.KeyVal.create(name, el.val()));
}
}
return data;
}
```
| public List<Connection.KeyVal> formData() {
ArrayList<Connection.KeyVal> data = new ArrayList<>();
// iterate the form control elements and accumulate their values
for (Element el: elements) {
if (!el.tag().isFormSubmittable()) continue; // contents are form listable, superset of submitable
if (el.hasAttr("disabled")) continue; // skip disabled form inputs
String name = el.attr("name");
if (name.length() == 0) continue;
String type = el.attr("type");
if ("select".equals(el.normalName())) {
Elements options = el.select("option[selected]");
boolean set = false;
for (Element option: options) {
data.add(HttpConnection.KeyVal.create(name, option.val()));
set = true;
}
if (!set) {
Element option = el.select("option").first();
if (option != null)
data.add(HttpConnection.KeyVal.create(name, option.val()));
}
} else if ("checkbox".equalsIgnoreCase(type) || "radio".equalsIgnoreCase(type)) {
// only add checkbox or radio if they have the checked attribute
if (el.hasAttr("checked")) {
final String val = el.val().length() > 0 ? el.val() : "on";
data.add(HttpConnection.KeyVal.create(name, val));
}
} else {
data.add(HttpConnection.KeyVal.create(name, el.val()));
}
}
return data;
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Get the data that this form submits. The returned list is a copy of the data, and changes to the contents of the
* list will not be reflected in the DOM.
* @return a list of key vals
*/
public List<Connection.KeyVal> formData() {
ArrayList<Connection.KeyVal> data = new ArrayList<>();
// iterate the form control elements and accumulate their values
for (Element el: elements) {
if (!el.tag().isFormSubmittable()) continue; // contents are form listable, superset of submitable
if (el.hasAttr("disabled")) continue; // skip disabled form inputs
String name = el.attr("name");
if (name.length() == 0) continue;
String type = el.attr("type");
if ("select".equals(el.normalName())) {
Elements options = el.select("option[selected]");
boolean set = false;
for (Element option: options) {
data.add(HttpConnection.KeyVal.create(name, option.val()));
set = true;
}
if (!set) {
Element option = el.select("option").first();
if (option != null)
data.add(HttpConnection.KeyVal.create(name, option.val()));
}
} else if ("checkbox".equalsIgnoreCase(type) || "radio".equalsIgnoreCase(type)) {
// only add checkbox or radio if they have the checked attribute
if (el.hasAttr("checked")) {
final String val = el.val().length() > 0 ? el.val() : "on";
data.add(HttpConnection.KeyVal.create(name, val));
}
} else {
data.add(HttpConnection.KeyVal.create(name, el.val()));
}
}
return data;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
10 | 36cc1745523966b6bb576ffcb5e34014c90a437bfc0bd619a0d4d78766d9ca0d | public String absUrl(String attributeKey) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Get an absolute URL from a URL attribute that may be relative (i.e. an <code><a href></code> or
* <code><img src></code>).
* <p/>
* E.g.: <code>String absUrl = linkEl.absUrl("href");</code>
* <p/>
* If the attribute value is already absolute (i.e. it starts with a protocol, like
* <code>http://</code> or <code>https://</code> etc), and it successfully parses as a URL, the attribute is
* returned directly. Otherwise, it is treated as a URL relative to the element's {@link #baseUri}, and made
* absolute using that.
* <p/>
* As an alternate, you can use the {@link #attr} method with the <code>abs:</code> prefix, e.g.:
* <code>String absUrl = linkEl.attr("abs:href");</code>
*
* @param attributeKey The attribute key
* @return An absolute URL if one could be made, or an empty string (not null) if the attribute was missing or
* could not be made successfully into a URL.
* @see #attr
* @see java.net.URL#URL(java.net.URL, String)
*/
public String absUrl(String attributeKey) {
Validate.notEmpty(attributeKey);
String relUrl = attr(attributeKey);
if (!hasAttr(attributeKey)) {
return ""; // nothing to make absolute with
} else {
URL base;
try {
try {
base = new URL(baseUri);
} catch (MalformedURLException e) {
// the base is unsuitable, but the attribute may be abs on its own, so try that
URL abs = new URL(relUrl);
return abs.toExternalForm();
}
// workaround: java resolves '//path/file + ?foo' to '//path/?foo', not '//path/file?foo' as desired
if (relUrl.startsWith("?"))
relUrl = base.getPath() + relUrl;
URL abs = new URL(base, relUrl);
return abs.toExternalForm();
} catch (MalformedURLException e) {
return "";
}
}
}
```
| public String absUrl(String attributeKey) {
Validate.notEmpty(attributeKey);
String relUrl = attr(attributeKey);
if (!hasAttr(attributeKey)) {
return ""; // nothing to make absolute with
} else {
URL base;
try {
try {
base = new URL(baseUri);
} catch (MalformedURLException e) {
// the base is unsuitable, but the attribute may be abs on its own, so try that
URL abs = new URL(relUrl);
return abs.toExternalForm();
}
// workaround: java resolves '//path/file + ?foo' to '//path/?foo', not '//path/file?foo' as desired
if (relUrl.startsWith("?"))
relUrl = base.getPath() + relUrl;
URL abs = new URL(base, relUrl);
return abs.toExternalForm();
} catch (MalformedURLException e) {
return "";
}
}
} | false | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Get an absolute URL from a URL attribute that may be relative (i.e. an <code><a href></code> or
* <code><img src></code>).
* <p/>
* E.g.: <code>String absUrl = linkEl.absUrl("href");</code>
* <p/>
* If the attribute value is already absolute (i.e. it starts with a protocol, like
* <code>http://</code> or <code>https://</code> etc), and it successfully parses as a URL, the attribute is
* returned directly. Otherwise, it is treated as a URL relative to the element's {@link #baseUri}, and made
* absolute using that.
* <p/>
* As an alternate, you can use the {@link #attr} method with the <code>abs:</code> prefix, e.g.:
* <code>String absUrl = linkEl.attr("abs:href");</code>
*
* @param attributeKey The attribute key
* @return An absolute URL if one could be made, or an empty string (not null) if the attribute was missing or
* could not be made successfully into a URL.
* @see #attr
* @see java.net.URL#URL(java.net.URL, String)
*/
public String absUrl(String attributeKey) {
Validate.notEmpty(attributeKey);
String relUrl = attr(attributeKey);
if (!hasAttr(attributeKey)) {
return ""; // nothing to make absolute with
} else {
URL base;
try {
try {
base = new URL(baseUri);
} catch (MalformedURLException e) {
// the base is unsuitable, but the attribute may be abs on its own, so try that
URL abs = new URL(relUrl);
return abs.toExternalForm();
}
// workaround: java resolves '//path/file + ?foo' to '//path/?foo', not '//path/file?foo' as desired
if (relUrl.startsWith("?"))
relUrl = base.getPath() + relUrl;
URL abs = new URL(base, relUrl);
return abs.toExternalForm();
} catch (MalformedURLException e) {
return "";
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
15 | 36d0b0761e433811c828ab1c0cf3fe6c3d3ac8c5514e8b7e09a2153b8e75b2f2 | private char getMappingCode(final String str, final int index) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Used internally by the Soundex algorithm.
*
* Consonants from the same code group separated by W or H are treated as one.
*
* @param str
* the cleaned working string to encode (in upper case).
* @param index
* the character position to encode
* @return Mapping code for a particular character
* @throws IllegalArgumentException
* if the character is not mapped
*/
private char getMappingCode(final String str, final int index) {
// map() throws IllegalArgumentException
final char mappedChar = this.map(str.charAt(index));
// HW rule check
if (index > 1 && mappedChar != '0') {
final char hwChar = str.charAt(index - 1);
if ('H' == hwChar || 'W' == hwChar) {
final char preHWChar = str.charAt(index - 2);
final char firstCode = this.map(preHWChar);
if (firstCode == mappedChar || 'H' == preHWChar || 'W' == preHWChar) {
return 0;
}
}
}
return mappedChar;
}
```
| private char getMappingCode(final String str, final int index) {
// map() throws IllegalArgumentException
final char mappedChar = this.map(str.charAt(index));
// HW rule check
if (index > 1 && mappedChar != '0') {
final char hwChar = str.charAt(index - 1);
if ('H' == hwChar || 'W' == hwChar) {
final char preHWChar = str.charAt(index - 2);
final char firstCode = this.map(preHWChar);
if (firstCode == mappedChar || 'H' == preHWChar || 'W' == preHWChar) {
return 0;
}
}
}
return mappedChar;
} | true | Codec | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Used internally by the Soundex algorithm.
*
* Consonants from the same code group separated by W or H are treated as one.
*
* @param str
* the cleaned working string to encode (in upper case).
* @param index
* the character position to encode
* @return Mapping code for a particular character
* @throws IllegalArgumentException
* if the character is not mapped
*/
private char getMappingCode(final String str, final int index) {
// map() throws IllegalArgumentException
final char mappedChar = this.map(str.charAt(index));
// HW rule check
if (index > 1 && mappedChar != '0') {
final char hwChar = str.charAt(index - 1);
if ('H' == hwChar || 'W' == hwChar) {
final char preHWChar = str.charAt(index - 2);
final char firstCode = this.map(preHWChar);
if (firstCode == mappedChar || 'H' == preHWChar || 'W' == preHWChar) {
return 0;
}
}
}
return mappedChar;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
11 | 36eac1e29f5262d425a85b3cf67380b660191104c45cecb11a34b6ac4b748081 | private void _verifySharing()
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private void _verifySharing()
{
if (_hashShared) {
_hashArea = Arrays.copyOf(_hashArea, _hashArea.length);
_names = Arrays.copyOf(_names, _names.length);
_hashShared = false;
// 09-Sep-2015, tatu: As per [jackson-core#216], also need to ensure
// we rehash as needed, as need-rehash flag is not copied from parent
}
if (_needRehash) {
rehash();
}
}
```
| private void _verifySharing()
{
if (_hashShared) {
_hashArea = Arrays.copyOf(_hashArea, _hashArea.length);
_names = Arrays.copyOf(_names, _names.length);
_hashShared = false;
// 09-Sep-2015, tatu: As per [jackson-core#216], also need to ensure
// we rehash as needed, as need-rehash flag is not copied from parent
}
if (_needRehash) {
rehash();
}
} | true | JacksonCore | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private void _verifySharing()
{
if (_hashShared) {
_hashArea = Arrays.copyOf(_hashArea, _hashArea.length);
_names = Arrays.copyOf(_names, _names.length);
_hashShared = false;
// 09-Sep-2015, tatu: As per [jackson-core#216], also need to ensure
// we rehash as needed, as need-rehash flag is not copied from parent
}
if (_needRehash) {
rehash();
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
17 | 374b9244cafef1c352d9550e14e933cd2bdd2bc3ce99ab1b79b79dd6381868a8 | public static long parseOctal(final byte[] buffer, final int offset, final int length) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Parse an octal string from a buffer.
*
* <p>Leading spaces are ignored.
* The buffer must contain a trailing space or NUL,
* and may contain an additional trailing space or NUL.</p>
*
* <p>The input buffer is allowed to contain all NULs,
* in which case the method returns 0L
* (this allows for missing fields).</p>
*
* <p>To work-around some tar implementations that insert a
* leading NUL this method returns 0 if it detects a leading NUL
* since Commons Compress 1.4.</p>
*
* @param buffer The buffer from which to parse.
* @param offset The offset into the buffer from which to parse.
* @param length The maximum number of bytes to parse - must be at least 2 bytes.
* @return The long value of the octal string.
* @throws IllegalArgumentException if the trailing space/NUL is missing or if a invalid byte is detected.
*/
public static long parseOctal(final byte[] buffer, final int offset, final int length) {
long result = 0;
int end = offset + length;
int start = offset;
if (length < 2){
throw new IllegalArgumentException("Length "+length+" must be at least 2");
}
if (buffer[start] == 0) {
return 0L;
}
// Skip leading spaces
while (start < end){
if (buffer[start] == ' '){
start++;
} else {
break;
}
}
// Must have trailing NUL or space
byte trailer;
trailer = buffer[end-1];
if (trailer == 0 || trailer == ' '){
end--;
} else {
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, end-1, trailer));
}
// May have additional NULs or spaces
trailer = buffer[end - 1];
if (trailer == 0 || trailer == ' '){
end--;
}
for ( ;start < end; start++) {
final byte currentByte = buffer[start];
// CheckStyle:MagicNumber OFF
if (currentByte < '0' || currentByte > '7'){
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, start, currentByte));
}
result = (result << 3) + (currentByte - '0'); // convert from ASCII
// CheckStyle:MagicNumber ON
}
return result;
}
```
| public static long parseOctal(final byte[] buffer, final int offset, final int length) {
long result = 0;
int end = offset + length;
int start = offset;
if (length < 2){
throw new IllegalArgumentException("Length "+length+" must be at least 2");
}
if (buffer[start] == 0) {
return 0L;
}
// Skip leading spaces
while (start < end){
if (buffer[start] == ' '){
start++;
} else {
break;
}
}
// Must have trailing NUL or space
byte trailer;
trailer = buffer[end-1];
if (trailer == 0 || trailer == ' '){
end--;
} else {
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, end-1, trailer));
}
// May have additional NULs or spaces
trailer = buffer[end - 1];
if (trailer == 0 || trailer == ' '){
end--;
}
for ( ;start < end; start++) {
final byte currentByte = buffer[start];
// CheckStyle:MagicNumber OFF
if (currentByte < '0' || currentByte > '7'){
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, start, currentByte));
}
result = (result << 3) + (currentByte - '0'); // convert from ASCII
// CheckStyle:MagicNumber ON
}
return result;
} | true | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Parse an octal string from a buffer.
*
* <p>Leading spaces are ignored.
* The buffer must contain a trailing space or NUL,
* and may contain an additional trailing space or NUL.</p>
*
* <p>The input buffer is allowed to contain all NULs,
* in which case the method returns 0L
* (this allows for missing fields).</p>
*
* <p>To work-around some tar implementations that insert a
* leading NUL this method returns 0 if it detects a leading NUL
* since Commons Compress 1.4.</p>
*
* @param buffer The buffer from which to parse.
* @param offset The offset into the buffer from which to parse.
* @param length The maximum number of bytes to parse - must be at least 2 bytes.
* @return The long value of the octal string.
* @throws IllegalArgumentException if the trailing space/NUL is missing or if a invalid byte is detected.
*/
public static long parseOctal(final byte[] buffer, final int offset, final int length) {
long result = 0;
int end = offset + length;
int start = offset;
if (length < 2){
throw new IllegalArgumentException("Length "+length+" must be at least 2");
}
if (buffer[start] == 0) {
return 0L;
}
// Skip leading spaces
while (start < end){
if (buffer[start] == ' '){
start++;
} else {
break;
}
}
// Must have trailing NUL or space
byte trailer;
trailer = buffer[end-1];
if (trailer == 0 || trailer == ' '){
end--;
} else {
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, end-1, trailer));
}
// May have additional NULs or spaces
trailer = buffer[end - 1];
if (trailer == 0 || trailer == ' '){
end--;
}
for ( ;start < end; start++) {
final byte currentByte = buffer[start];
// CheckStyle:MagicNumber OFF
if (currentByte < '0' || currentByte > '7'){
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, start, currentByte));
}
result = (result << 3) + (currentByte - '0'); // convert from ASCII
// CheckStyle:MagicNumber ON
}
return result;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
19 | 3755085bc6b324cb77c77a1d3cc2d2b72d54eb790b37fb08a31fb09a0c1390ae | protected void declareNameInScope(FlowScope scope, Node node, JSType type) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Declares a refined type in {@code scope} for the name represented by
* {@code node}. It must be possible to refine the type of the given node in
* the given scope, as determined by {@link #getTypeIfRefinable}.
*/
protected void declareNameInScope(FlowScope scope, Node node, JSType type) {
switch (node.getType()) {
case Token.NAME:
scope.inferSlotType(node.getString(), type);
break;
case Token.GETPROP:
String qualifiedName = node.getQualifiedName();
Preconditions.checkNotNull(qualifiedName);
JSType origType = node.getJSType();
origType = origType == null ? getNativeType(UNKNOWN_TYPE) : origType;
scope.inferQualifiedSlot(node, qualifiedName, origType, type);
break;
case Token.THIS:
// "this" references aren't currently modeled in the CFG.
break;
default:
throw new IllegalArgumentException("Node cannot be refined. \n" +
node.toStringTree());
}
}
```
| protected void declareNameInScope(FlowScope scope, Node node, JSType type) {
switch (node.getType()) {
case Token.NAME:
scope.inferSlotType(node.getString(), type);
break;
case Token.GETPROP:
String qualifiedName = node.getQualifiedName();
Preconditions.checkNotNull(qualifiedName);
JSType origType = node.getJSType();
origType = origType == null ? getNativeType(UNKNOWN_TYPE) : origType;
scope.inferQualifiedSlot(node, qualifiedName, origType, type);
break;
case Token.THIS:
// "this" references aren't currently modeled in the CFG.
break;
default:
throw new IllegalArgumentException("Node cannot be refined. \n" +
node.toStringTree());
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Declares a refined type in {@code scope} for the name represented by
* {@code node}. It must be possible to refine the type of the given node in
* the given scope, as determined by {@link #getTypeIfRefinable}.
*/
protected void declareNameInScope(FlowScope scope, Node node, JSType type) {
switch (node.getType()) {
case Token.NAME:
scope.inferSlotType(node.getString(), type);
break;
case Token.GETPROP:
String qualifiedName = node.getQualifiedName();
Preconditions.checkNotNull(qualifiedName);
JSType origType = node.getJSType();
origType = origType == null ? getNativeType(UNKNOWN_TYPE) : origType;
scope.inferQualifiedSlot(node, qualifiedName, origType, type);
break;
case Token.THIS:
// "this" references aren't currently modeled in the CFG.
break;
default:
throw new IllegalArgumentException("Node cannot be refined. \n" +
node.toStringTree());
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
7 | 380d15991f5eec349a5d89c4a032c87c62e73b84a1accd8db29929db9677f308 | @Override
public JSType caseObjectType(ObjectType type) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public JSType caseObjectType(ObjectType type) {
if (value.equals("function")) {
JSType ctorType = getNativeType(U2U_CONSTRUCTOR_TYPE);
if (resultEqualsValue) {
// Objects are restricted to "Function", subtypes are left
return ctorType.getGreatestSubtype(type);
} else {
// Only filter out subtypes of "function"
return type.isSubtype(ctorType) ? null : type;
}
}
return matchesExpectation("object") ? type : null;
}
```
| @Override
public JSType caseObjectType(ObjectType type) {
if (value.equals("function")) {
JSType ctorType = getNativeType(U2U_CONSTRUCTOR_TYPE);
if (resultEqualsValue) {
// Objects are restricted to "Function", subtypes are left
return ctorType.getGreatestSubtype(type);
} else {
// Only filter out subtypes of "function"
return type.isSubtype(ctorType) ? null : type;
}
}
return matchesExpectation("object") ? type : null;
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public JSType caseObjectType(ObjectType type) {
if (value.equals("function")) {
JSType ctorType = getNativeType(U2U_CONSTRUCTOR_TYPE);
if (resultEqualsValue) {
// Objects are restricted to "Function", subtypes are left
return ctorType.getGreatestSubtype(type);
} else {
// Only filter out subtypes of "function"
return type.isSubtype(ctorType) ? null : type;
}
}
return matchesExpectation("object") ? type : null;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
87 | 38160a0ea22f541b0329a0e38cb4929550bd84441cc5571d287f28753ab51ddf | private boolean isFoldableExpressBlock(Node n) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* @return Whether the node is a block with a single statement that is
* an expression.
*/
private boolean isFoldableExpressBlock(Node n) {
if (n.getType() == Token.BLOCK) {
if (n.hasOneChild()) {
Node maybeExpr = n.getFirstChild();
if (maybeExpr.getType() == Token.EXPR_RESULT) {
// IE has a bug where event handlers behave differently when
// their return value is used vs. when their return value is in
// an EXPR_RESULT. It's pretty freaking weird. See:
// http://code.google.com/p/closure-compiler/issues/detail?id=291
// We try to detect this case, and not fold EXPR_RESULTs
// into other expressions.
if (maybeExpr.getFirstChild().getType() == Token.CALL) {
Node calledFn = maybeExpr.getFirstChild().getFirstChild();
// We only have to worry about methods with an implicit 'this'
// param, or this doesn't happen.
if (calledFn.getType() == Token.GETELEM) {
return false;
} else if (calledFn.getType() == Token.GETPROP &&
calledFn.getLastChild().getString().startsWith("on")) {
return false;
}
}
return true;
}
return false;
}
}
return false;
}
```
| private boolean isFoldableExpressBlock(Node n) {
if (n.getType() == Token.BLOCK) {
if (n.hasOneChild()) {
Node maybeExpr = n.getFirstChild();
if (maybeExpr.getType() == Token.EXPR_RESULT) {
// IE has a bug where event handlers behave differently when
// their return value is used vs. when their return value is in
// an EXPR_RESULT. It's pretty freaking weird. See:
// http://code.google.com/p/closure-compiler/issues/detail?id=291
// We try to detect this case, and not fold EXPR_RESULTs
// into other expressions.
if (maybeExpr.getFirstChild().getType() == Token.CALL) {
Node calledFn = maybeExpr.getFirstChild().getFirstChild();
// We only have to worry about methods with an implicit 'this'
// param, or this doesn't happen.
if (calledFn.getType() == Token.GETELEM) {
return false;
} else if (calledFn.getType() == Token.GETPROP &&
calledFn.getLastChild().getString().startsWith("on")) {
return false;
}
}
return true;
}
return false;
}
}
return false;
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* @return Whether the node is a block with a single statement that is
* an expression.
*/
private boolean isFoldableExpressBlock(Node n) {
if (n.getType() == Token.BLOCK) {
if (n.hasOneChild()) {
Node maybeExpr = n.getFirstChild();
if (maybeExpr.getType() == Token.EXPR_RESULT) {
// IE has a bug where event handlers behave differently when
// their return value is used vs. when their return value is in
// an EXPR_RESULT. It's pretty freaking weird. See:
// http://code.google.com/p/closure-compiler/issues/detail?id=291
// We try to detect this case, and not fold EXPR_RESULTs
// into other expressions.
if (maybeExpr.getFirstChild().getType() == Token.CALL) {
Node calledFn = maybeExpr.getFirstChild().getFirstChild();
// We only have to worry about methods with an implicit 'this'
// param, or this doesn't happen.
if (calledFn.getType() == Token.GETELEM) {
return false;
} else if (calledFn.getType() == Token.GETPROP &&
calledFn.getLastChild().getString().startsWith("on")) {
return false;
}
}
return true;
}
return false;
}
}
return false;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
20 | 382510e3fd009ecda782bad978479f425654f19e0b420e76b52a579e9848a3b8 | public ValueMarker(double value, Paint paint, Stroke stroke,
Paint outlinePaint, Stroke outlineStroke, float alpha) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Creates a new value marker.
*
* @param value the value.
* @param paint the paint (<code>null</code> not permitted).
* @param stroke the stroke (<code>null</code> not permitted).
* @param outlinePaint the outline paint (<code>null</code> permitted).
* @param outlineStroke the outline stroke (<code>null</code> permitted).
* @param alpha the alpha transparency (in the range 0.0f to 1.0f).
*/
public ValueMarker(double value, Paint paint, Stroke stroke,
Paint outlinePaint, Stroke outlineStroke, float alpha) {
super(paint, stroke, outlinePaint, outlineStroke, alpha);
this.value = value;
}
```
| public ValueMarker(double value, Paint paint, Stroke stroke,
Paint outlinePaint, Stroke outlineStroke, float alpha) {
super(paint, stroke, outlinePaint, outlineStroke, alpha);
this.value = value;
} | false | Chart | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Creates a new value marker.
*
* @param value the value.
* @param paint the paint (<code>null</code> not permitted).
* @param stroke the stroke (<code>null</code> not permitted).
* @param outlinePaint the outline paint (<code>null</code> permitted).
* @param outlineStroke the outline stroke (<code>null</code> permitted).
* @param alpha the alpha transparency (in the range 0.0f to 1.0f).
*/
public ValueMarker(double value, Paint paint, Stroke stroke,
Paint outlinePaint, Stroke outlineStroke, float alpha) {
super(paint, stroke, outlinePaint, outlineStroke, alpha);
this.value = value;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
2 | 387f4e487342b5eb59bdb88a22df5ca60da77963f838a41c6ad00a8b365cd5b5 | void encode(byte[] in, int inPos, int inAvail) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>
* Encodes all of the provided data, starting at inPos, for inAvail bytes.
* Must be called at least twice: once with the data to encode, and once
* with inAvail set to "-1" to alert encoder that EOF has been reached,
* so flush last remaining bytes (if not multiple of 3).
* </p><p>
* Thanks to "commons" project in ws.apache.org for the bitwise operations,
* and general approach.
* http://svn.apache.org/repos/asf/webservices/commons/trunk/modules/util/
* </p>
*
* @param in byte[] array of binary data to base64 encode.
* @param inPos Position to start reading data from.
* @param inAvail Amount of bytes available from input for encoding.
*/
void encode(byte[] in, int inPos, int inAvail) {
if (eof) {
return;
}
// inAvail < 0 is how we're informed of EOF in the underlying data we're
// encoding.
if (inAvail < 0) {
eof = true;
if (buf == null || buf.length - pos < encodeSize) {
resizeBuf();
}
switch (modulus) {
case 1:
buf[pos++] = encodeTable[(x >> 2) & MASK_6BITS];
buf[pos++] = encodeTable[(x << 4) & MASK_6BITS];
// URL-SAFE skips the padding to further reduce size.
if (encodeTable == STANDARD_ENCODE_TABLE) {
buf[pos++] = PAD;
buf[pos++] = PAD;
}
break;
case 2:
buf[pos++] = encodeTable[(x >> 10) & MASK_6BITS];
buf[pos++] = encodeTable[(x >> 4) & MASK_6BITS];
buf[pos++] = encodeTable[(x << 2) & MASK_6BITS];
// URL-SAFE skips the padding to further reduce size.
if (encodeTable == STANDARD_ENCODE_TABLE) {
buf[pos++] = PAD;
}
break;
}
if (lineLength > 0 && pos > 0) {
System.arraycopy(lineSeparator, 0, buf, pos, lineSeparator.length);
pos += lineSeparator.length;
}
} else {
for (int i = 0; i < inAvail; i++) {
if (buf == null || buf.length - pos < encodeSize) {
resizeBuf();
}
modulus = (++modulus) % 3;
int b = in[inPos++];
if (b < 0) { b += 256; }
x = (x << 8) + b;
if (0 == modulus) {
buf[pos++] = encodeTable[(x >> 18) & MASK_6BITS];
buf[pos++] = encodeTable[(x >> 12) & MASK_6BITS];
buf[pos++] = encodeTable[(x >> 6) & MASK_6BITS];
buf[pos++] = encodeTable[x & MASK_6BITS];
currentLinePos += 4;
if (lineLength > 0 && lineLength <= currentLinePos) {
System.arraycopy(lineSeparator, 0, buf, pos, lineSeparator.length);
pos += lineSeparator.length;
currentLinePos = 0;
}
}
}
}
}
```
| void encode(byte[] in, int inPos, int inAvail) {
if (eof) {
return;
}
// inAvail < 0 is how we're informed of EOF in the underlying data we're
// encoding.
if (inAvail < 0) {
eof = true;
if (buf == null || buf.length - pos < encodeSize) {
resizeBuf();
}
switch (modulus) {
case 1:
buf[pos++] = encodeTable[(x >> 2) & MASK_6BITS];
buf[pos++] = encodeTable[(x << 4) & MASK_6BITS];
// URL-SAFE skips the padding to further reduce size.
if (encodeTable == STANDARD_ENCODE_TABLE) {
buf[pos++] = PAD;
buf[pos++] = PAD;
}
break;
case 2:
buf[pos++] = encodeTable[(x >> 10) & MASK_6BITS];
buf[pos++] = encodeTable[(x >> 4) & MASK_6BITS];
buf[pos++] = encodeTable[(x << 2) & MASK_6BITS];
// URL-SAFE skips the padding to further reduce size.
if (encodeTable == STANDARD_ENCODE_TABLE) {
buf[pos++] = PAD;
}
break;
}
if (lineLength > 0 && pos > 0) {
System.arraycopy(lineSeparator, 0, buf, pos, lineSeparator.length);
pos += lineSeparator.length;
}
} else {
for (int i = 0; i < inAvail; i++) {
if (buf == null || buf.length - pos < encodeSize) {
resizeBuf();
}
modulus = (++modulus) % 3;
int b = in[inPos++];
if (b < 0) { b += 256; }
x = (x << 8) + b;
if (0 == modulus) {
buf[pos++] = encodeTable[(x >> 18) & MASK_6BITS];
buf[pos++] = encodeTable[(x >> 12) & MASK_6BITS];
buf[pos++] = encodeTable[(x >> 6) & MASK_6BITS];
buf[pos++] = encodeTable[x & MASK_6BITS];
currentLinePos += 4;
if (lineLength > 0 && lineLength <= currentLinePos) {
System.arraycopy(lineSeparator, 0, buf, pos, lineSeparator.length);
pos += lineSeparator.length;
currentLinePos = 0;
}
}
}
}
} | false | Codec | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>
* Encodes all of the provided data, starting at inPos, for inAvail bytes.
* Must be called at least twice: once with the data to encode, and once
* with inAvail set to "-1" to alert encoder that EOF has been reached,
* so flush last remaining bytes (if not multiple of 3).
* </p><p>
* Thanks to "commons" project in ws.apache.org for the bitwise operations,
* and general approach.
* http://svn.apache.org/repos/asf/webservices/commons/trunk/modules/util/
* </p>
*
* @param in byte[] array of binary data to base64 encode.
* @param inPos Position to start reading data from.
* @param inAvail Amount of bytes available from input for encoding.
*/
void encode(byte[] in, int inPos, int inAvail) {
if (eof) {
return;
}
// inAvail < 0 is how we're informed of EOF in the underlying data we're
// encoding.
if (inAvail < 0) {
eof = true;
if (buf == null || buf.length - pos < encodeSize) {
resizeBuf();
}
switch (modulus) {
case 1:
buf[pos++] = encodeTable[(x >> 2) & MASK_6BITS];
buf[pos++] = encodeTable[(x << 4) & MASK_6BITS];
// URL-SAFE skips the padding to further reduce size.
if (encodeTable == STANDARD_ENCODE_TABLE) {
buf[pos++] = PAD;
buf[pos++] = PAD;
}
break;
case 2:
buf[pos++] = encodeTable[(x >> 10) & MASK_6BITS];
buf[pos++] = encodeTable[(x >> 4) & MASK_6BITS];
buf[pos++] = encodeTable[(x << 2) & MASK_6BITS];
// URL-SAFE skips the padding to further reduce size.
if (encodeTable == STANDARD_ENCODE_TABLE) {
buf[pos++] = PAD;
}
break;
}
if (lineLength > 0 && pos > 0) {
System.arraycopy(lineSeparator, 0, buf, pos, lineSeparator.length);
pos += lineSeparator.length;
}
} else {
for (int i = 0; i < inAvail; i++) {
if (buf == null || buf.length - pos < encodeSize) {
resizeBuf();
}
modulus = (++modulus) % 3;
int b = in[inPos++];
if (b < 0) { b += 256; }
x = (x << 8) + b;
if (0 == modulus) {
buf[pos++] = encodeTable[(x >> 18) & MASK_6BITS];
buf[pos++] = encodeTable[(x >> 12) & MASK_6BITS];
buf[pos++] = encodeTable[(x >> 6) & MASK_6BITS];
buf[pos++] = encodeTable[x & MASK_6BITS];
currentLinePos += 4;
if (lineLength > 0 && lineLength <= currentLinePos) {
System.arraycopy(lineSeparator, 0, buf, pos, lineSeparator.length);
pos += lineSeparator.length;
currentLinePos = 0;
}
}
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
37 | 38c2b1273a9eb651fbad88c6ac5359aa7e09826c21a1d891b087e471d80c22f4 | private boolean isShortOption(String token)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Tells if the token looks like a short option.
*
* @param token
*/
private boolean isShortOption(String token)
{
// short options (-S, -SV, -S=V, -SV1=V2, -S1S2)
if (!token.startsWith("-") || token.length() == 1)
{
return false;
}
// remove leading "-" and "=value"
int pos = token.indexOf("=");
String optName = pos == -1 ? token.substring(1) : token.substring(1, pos);
return options.hasShortOption(optName);
}
```
| private boolean isShortOption(String token)
{
// short options (-S, -SV, -S=V, -SV1=V2, -S1S2)
if (!token.startsWith("-") || token.length() == 1)
{
return false;
}
// remove leading "-" and "=value"
int pos = token.indexOf("=");
String optName = pos == -1 ? token.substring(1) : token.substring(1, pos);
return options.hasShortOption(optName);
} | false | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Tells if the token looks like a short option.
*
* @param token
*/
private boolean isShortOption(String token)
{
// short options (-S, -SV, -S=V, -SV1=V2, -S1S2)
if (!token.startsWith("-") || token.length() == 1)
{
return false;
}
// remove leading "-" and "=value"
int pos = token.indexOf("=");
String optName = pos == -1 ? token.substring(1) : token.substring(1, pos);
return options.hasShortOption(optName);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
6 | 38dddbb8cbf1324d0519d304c0d3b366fd71765cdf5ed50bbcf44b808ecc58be | protected boolean equal(
EvalContext context,
Expression left,
Expression right)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Compares two values
*/
protected boolean equal(
EvalContext context,
Expression left,
Expression right)
{
Object l = left.compute(context);
Object r = right.compute(context);
// System.err.println("COMPARING: " +
// (l == null ? "null" : l.getClass().getName()) + " " +
// (r == null ? "null" : r.getClass().getName()));
if (l instanceof InitialContext || l instanceof SelfContext) {
l = ((EvalContext) l).getSingleNodePointer();
}
if (r instanceof InitialContext || r instanceof SelfContext) {
r = ((EvalContext) r).getSingleNodePointer();
}
if (l instanceof Collection) {
l = ((Collection) l).iterator();
}
if (r instanceof Collection) {
r = ((Collection) r).iterator();
}
if ((l instanceof Iterator) && !(r instanceof Iterator)) {
return contains((Iterator) l, r);
}
if (!(l instanceof Iterator) && (r instanceof Iterator)) {
return contains((Iterator) r, l);
}
if (l instanceof Iterator && r instanceof Iterator) {
return findMatch((Iterator) l, (Iterator) r);
}
return equal(l, r);
}
```
| protected boolean equal(
EvalContext context,
Expression left,
Expression right)
{
Object l = left.compute(context);
Object r = right.compute(context);
// System.err.println("COMPARING: " +
// (l == null ? "null" : l.getClass().getName()) + " " +
// (r == null ? "null" : r.getClass().getName()));
if (l instanceof InitialContext || l instanceof SelfContext) {
l = ((EvalContext) l).getSingleNodePointer();
}
if (r instanceof InitialContext || r instanceof SelfContext) {
r = ((EvalContext) r).getSingleNodePointer();
}
if (l instanceof Collection) {
l = ((Collection) l).iterator();
}
if (r instanceof Collection) {
r = ((Collection) r).iterator();
}
if ((l instanceof Iterator) && !(r instanceof Iterator)) {
return contains((Iterator) l, r);
}
if (!(l instanceof Iterator) && (r instanceof Iterator)) {
return contains((Iterator) r, l);
}
if (l instanceof Iterator && r instanceof Iterator) {
return findMatch((Iterator) l, (Iterator) r);
}
return equal(l, r);
} | true | JxPath | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Compares two values
*/
protected boolean equal(
EvalContext context,
Expression left,
Expression right)
{
Object l = left.compute(context);
Object r = right.compute(context);
// System.err.println("COMPARING: " +
// (l == null ? "null" : l.getClass().getName()) + " " +
// (r == null ? "null" : r.getClass().getName()));
if (l instanceof InitialContext || l instanceof SelfContext) {
l = ((EvalContext) l).getSingleNodePointer();
}
if (r instanceof InitialContext || r instanceof SelfContext) {
r = ((EvalContext) r).getSingleNodePointer();
}
if (l instanceof Collection) {
l = ((Collection) l).iterator();
}
if (r instanceof Collection) {
r = ((Collection) r).iterator();
}
if ((l instanceof Iterator) && !(r instanceof Iterator)) {
return contains((Iterator) l, r);
}
if (!(l instanceof Iterator) && (r instanceof Iterator)) {
return contains((Iterator) r, l);
}
if (l instanceof Iterator && r instanceof Iterator) {
return findMatch((Iterator) l, (Iterator) r);
}
return equal(l, r);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
4 | 393ec66314a376228d71cafb9161fa072ea6cc7ff36b001401b23a0c0d14d9f1 | @Override
JSType resolveInternal(ErrorReporter t, StaticScope<JSType> enclosing) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Resolve the referenced type within the enclosing scope.
*/
@Override
JSType resolveInternal(ErrorReporter t, StaticScope<JSType> enclosing) {
// TODO(user): Investigate whether it is really necessary to keep two
// different mechanisms for resolving named types, and if so, which order
// makes more sense. Now, resolution via registry is first in order to
// avoid triggering the warnings built into the resolution via properties.
boolean resolved = resolveViaRegistry(t, enclosing);
if (detectImplicitPrototypeCycle()) {
handleTypeCycle(t);
}
if (resolved) {
super.resolveInternal(t, enclosing);
finishPropertyContinuations();
return registry.isLastGeneration() ?
getReferencedType() : this;
}
resolveViaProperties(t, enclosing);
if (detectImplicitPrototypeCycle()) {
handleTypeCycle(t);
}
super.resolveInternal(t, enclosing);
if (isResolved()) {
finishPropertyContinuations();
}
return registry.isLastGeneration() ?
getReferencedType() : this;
}
```
| @Override
JSType resolveInternal(ErrorReporter t, StaticScope<JSType> enclosing) {
// TODO(user): Investigate whether it is really necessary to keep two
// different mechanisms for resolving named types, and if so, which order
// makes more sense. Now, resolution via registry is first in order to
// avoid triggering the warnings built into the resolution via properties.
boolean resolved = resolveViaRegistry(t, enclosing);
if (detectImplicitPrototypeCycle()) {
handleTypeCycle(t);
}
if (resolved) {
super.resolveInternal(t, enclosing);
finishPropertyContinuations();
return registry.isLastGeneration() ?
getReferencedType() : this;
}
resolveViaProperties(t, enclosing);
if (detectImplicitPrototypeCycle()) {
handleTypeCycle(t);
}
super.resolveInternal(t, enclosing);
if (isResolved()) {
finishPropertyContinuations();
}
return registry.isLastGeneration() ?
getReferencedType() : this;
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Resolve the referenced type within the enclosing scope.
*/
@Override
JSType resolveInternal(ErrorReporter t, StaticScope<JSType> enclosing) {
// TODO(user): Investigate whether it is really necessary to keep two
// different mechanisms for resolving named types, and if so, which order
// makes more sense. Now, resolution via registry is first in order to
// avoid triggering the warnings built into the resolution via properties.
boolean resolved = resolveViaRegistry(t, enclosing);
if (detectImplicitPrototypeCycle()) {
handleTypeCycle(t);
}
if (resolved) {
super.resolveInternal(t, enclosing);
finishPropertyContinuations();
return registry.isLastGeneration() ?
getReferencedType() : this;
}
resolveViaProperties(t, enclosing);
if (detectImplicitPrototypeCycle()) {
handleTypeCycle(t);
}
super.resolveInternal(t, enclosing);
if (isResolved()) {
finishPropertyContinuations();
}
return registry.isLastGeneration() ?
getReferencedType() : this;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
6 | 39c06f3ed16f11344dfa55768a09ab1a4a76f123912b9082277ef481313fcdaa | protected boolean equal(
EvalContext context,
Expression left,
Expression right)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Compares two values
*/
protected boolean equal(
EvalContext context,
Expression left,
Expression right)
{
Object l = left.compute(context);
Object r = right.compute(context);
// System.err.println("COMPARING: " +
// (l == null ? "null" : l.getClass().getName()) + " " +
// (r == null ? "null" : r.getClass().getName()));
if (l instanceof InitialContext) {
((EvalContext) l).reset();
}
if (l instanceof SelfContext) {
l = ((EvalContext) l).getSingleNodePointer();
}
if (r instanceof InitialContext) {
((EvalContext) r).reset();
}
if (r instanceof SelfContext) {
r = ((EvalContext) r).getSingleNodePointer();
}
if (l instanceof Collection) {
l = ((Collection) l).iterator();
}
if (r instanceof Collection) {
r = ((Collection) r).iterator();
}
if ((l instanceof Iterator) && !(r instanceof Iterator)) {
return contains((Iterator) l, r);
}
if (!(l instanceof Iterator) && (r instanceof Iterator)) {
return contains((Iterator) r, l);
}
if (l instanceof Iterator && r instanceof Iterator) {
return findMatch((Iterator) l, (Iterator) r);
}
return equal(l, r);
}
```
| protected boolean equal(
EvalContext context,
Expression left,
Expression right)
{
Object l = left.compute(context);
Object r = right.compute(context);
// System.err.println("COMPARING: " +
// (l == null ? "null" : l.getClass().getName()) + " " +
// (r == null ? "null" : r.getClass().getName()));
if (l instanceof InitialContext) {
((EvalContext) l).reset();
}
if (l instanceof SelfContext) {
l = ((EvalContext) l).getSingleNodePointer();
}
if (r instanceof InitialContext) {
((EvalContext) r).reset();
}
if (r instanceof SelfContext) {
r = ((EvalContext) r).getSingleNodePointer();
}
if (l instanceof Collection) {
l = ((Collection) l).iterator();
}
if (r instanceof Collection) {
r = ((Collection) r).iterator();
}
if ((l instanceof Iterator) && !(r instanceof Iterator)) {
return contains((Iterator) l, r);
}
if (!(l instanceof Iterator) && (r instanceof Iterator)) {
return contains((Iterator) r, l);
}
if (l instanceof Iterator && r instanceof Iterator) {
return findMatch((Iterator) l, (Iterator) r);
}
return equal(l, r);
} | false | JxPath | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Compares two values
*/
protected boolean equal(
EvalContext context,
Expression left,
Expression right)
{
Object l = left.compute(context);
Object r = right.compute(context);
// System.err.println("COMPARING: " +
// (l == null ? "null" : l.getClass().getName()) + " " +
// (r == null ? "null" : r.getClass().getName()));
if (l instanceof InitialContext) {
((EvalContext) l).reset();
}
if (l instanceof SelfContext) {
l = ((EvalContext) l).getSingleNodePointer();
}
if (r instanceof InitialContext) {
((EvalContext) r).reset();
}
if (r instanceof SelfContext) {
r = ((EvalContext) r).getSingleNodePointer();
}
if (l instanceof Collection) {
l = ((Collection) l).iterator();
}
if (r instanceof Collection) {
r = ((Collection) r).iterator();
}
if ((l instanceof Iterator) && !(r instanceof Iterator)) {
return contains((Iterator) l, r);
}
if (!(l instanceof Iterator) && (r instanceof Iterator)) {
return contains((Iterator) r, l);
}
if (l instanceof Iterator && r instanceof Iterator) {
return findMatch((Iterator) l, (Iterator) r);
}
return equal(l, r);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
24 | 3a0af8dd3e4ed3e01d6e0f6ece2f7d1dd9635e8fafe2c4b50255cdc793bd18f7 | public Object answer(InvocationOnMock invocation) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/* (non-Javadoc)
* @see org.mockito.stubbing.Answer#answer(org.mockito.invocation.InvocationOnMock)
*/
public Object answer(InvocationOnMock invocation) {
if (methodsGuru.isToString(invocation.getMethod())) {
Object mock = invocation.getMock();
MockName name = mockUtil.getMockName(mock);
if (name.isDefault()) {
return "Mock for " + mockUtil.getMockSettings(mock).getTypeToMock().getSimpleName() + ", hashCode: " + mock.hashCode();
} else {
return name.toString();
}
} else if (methodsGuru.isCompareToMethod(invocation.getMethod())) {
//see issue 184.
//mocks by default should return 0 if references are the same, otherwise some other value because they are not the same. Hence we return 1 (anything but 0 is good).
//Only for compareTo() method by the Comparable interface
return invocation.getMock() == invocation.getArguments()[0] ? 0 : 1;
}
Class<?> returnType = invocation.getMethod().getReturnType();
return returnValueFor(returnType);
}
```
| public Object answer(InvocationOnMock invocation) {
if (methodsGuru.isToString(invocation.getMethod())) {
Object mock = invocation.getMock();
MockName name = mockUtil.getMockName(mock);
if (name.isDefault()) {
return "Mock for " + mockUtil.getMockSettings(mock).getTypeToMock().getSimpleName() + ", hashCode: " + mock.hashCode();
} else {
return name.toString();
}
} else if (methodsGuru.isCompareToMethod(invocation.getMethod())) {
//see issue 184.
//mocks by default should return 0 if references are the same, otherwise some other value because they are not the same. Hence we return 1 (anything but 0 is good).
//Only for compareTo() method by the Comparable interface
return invocation.getMock() == invocation.getArguments()[0] ? 0 : 1;
}
Class<?> returnType = invocation.getMethod().getReturnType();
return returnValueFor(returnType);
} | false | Mockito | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/* (non-Javadoc)
* @see org.mockito.stubbing.Answer#answer(org.mockito.invocation.InvocationOnMock)
*/
public Object answer(InvocationOnMock invocation) {
if (methodsGuru.isToString(invocation.getMethod())) {
Object mock = invocation.getMock();
MockName name = mockUtil.getMockName(mock);
if (name.isDefault()) {
return "Mock for " + mockUtil.getMockSettings(mock).getTypeToMock().getSimpleName() + ", hashCode: " + mock.hashCode();
} else {
return name.toString();
}
} else if (methodsGuru.isCompareToMethod(invocation.getMethod())) {
//see issue 184.
//mocks by default should return 0 if references are the same, otherwise some other value because they are not the same. Hence we return 1 (anything but 0 is good).
//Only for compareTo() method by the Comparable interface
return invocation.getMock() == invocation.getArguments()[0] ? 0 : 1;
}
Class<?> returnType = invocation.getMethod().getReturnType();
return returnValueFor(returnType);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
42 | 3a4f0cae303a12d71965a02345a4b8ef4bb42dcc70058302b1e9fb4201d30609 | @Override
protected Object _deserializeFromEmptyString() throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
protected Object _deserializeFromEmptyString() throws IOException {
// As per [databind#398], URI requires special handling
if (_kind == STD_URI) {
return URI.create("");
}
// As per [databind#1123], Locale too
return super._deserializeFromEmptyString();
}
```
| @Override
protected Object _deserializeFromEmptyString() throws IOException {
// As per [databind#398], URI requires special handling
if (_kind == STD_URI) {
return URI.create("");
}
// As per [databind#1123], Locale too
return super._deserializeFromEmptyString();
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
protected Object _deserializeFromEmptyString() throws IOException {
// As per [databind#398], URI requires special handling
if (_kind == STD_URI) {
return URI.create("");
}
// As per [databind#1123], Locale too
return super._deserializeFromEmptyString();
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
31 | 3a6466065def69d5a81353a313edac4fb0f48ecf6f494a841eaf9612c799ad7b | public double evaluate(double x, double epsilon, int maxIterations) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>
* Evaluates the continued fraction at the value x.
* </p>
*
* <p>
* The implementation of this method is based on the modified Lentz algorithm as described
* on page 18 ff. in:
* <ul>
* <li>
* I. J. Thompson, A. R. Barnett. "Coulomb and Bessel Functions of Complex Arguments and Order."
* <a target="_blank" href="http://www.fresco.org.uk/papers/Thompson-JCP64p490.pdf">
* http://www.fresco.org.uk/papers/Thompson-JCP64p490.pdf</a>
* </li>
* </ul>
* Note: the implementation uses the terms a<sub>i</sub> and b<sub>i</sub> as defined in
* <a href="http://mathworld.wolfram.com/ContinuedFraction.html">Continued Fraction / MathWorld</a>.
* </p>
*
* @param x the evaluation point.
* @param epsilon maximum error allowed.
* @param maxIterations maximum number of convergents
* @return the value of the continued fraction evaluated at x.
* @throws ConvergenceException if the algorithm fails to converge.
*/
public double evaluate(double x, double epsilon, int maxIterations) {
final double small = 1e-50;
double hPrev = getA(0, x);
// use the value of small as epsilon criteria for zero checks
if (Precision.equals(hPrev, 0.0, small)) {
hPrev = small;
}
int n = 1;
double dPrev = 0.0;
double cPrev = hPrev;
double hN = hPrev;
while (n < maxIterations) {
final double a = getA(n, x);
final double b = getB(n, x);
double dN = a + b * dPrev;
if (Precision.equals(dN, 0.0, small)) {
dN = small;
}
double cN = a + b / cPrev;
if (Precision.equals(cN, 0.0, small)) {
cN = small;
}
dN = 1 / dN;
final double deltaN = cN * dN;
hN = hPrev * deltaN;
if (Double.isInfinite(hN)) {
throw new ConvergenceException(LocalizedFormats.CONTINUED_FRACTION_INFINITY_DIVERGENCE,
x);
}
if (Double.isNaN(hN)) {
throw new ConvergenceException(LocalizedFormats.CONTINUED_FRACTION_NAN_DIVERGENCE,
x);
}
if (FastMath.abs(deltaN - 1.0) < epsilon) {
break;
}
dPrev = dN;
cPrev = cN;
hPrev = hN;
n++;
}
if (n >= maxIterations) {
throw new MaxCountExceededException(LocalizedFormats.NON_CONVERGENT_CONTINUED_FRACTION,
maxIterations, x);
}
return hN;
}
```
| public double evaluate(double x, double epsilon, int maxIterations) {
final double small = 1e-50;
double hPrev = getA(0, x);
// use the value of small as epsilon criteria for zero checks
if (Precision.equals(hPrev, 0.0, small)) {
hPrev = small;
}
int n = 1;
double dPrev = 0.0;
double cPrev = hPrev;
double hN = hPrev;
while (n < maxIterations) {
final double a = getA(n, x);
final double b = getB(n, x);
double dN = a + b * dPrev;
if (Precision.equals(dN, 0.0, small)) {
dN = small;
}
double cN = a + b / cPrev;
if (Precision.equals(cN, 0.0, small)) {
cN = small;
}
dN = 1 / dN;
final double deltaN = cN * dN;
hN = hPrev * deltaN;
if (Double.isInfinite(hN)) {
throw new ConvergenceException(LocalizedFormats.CONTINUED_FRACTION_INFINITY_DIVERGENCE,
x);
}
if (Double.isNaN(hN)) {
throw new ConvergenceException(LocalizedFormats.CONTINUED_FRACTION_NAN_DIVERGENCE,
x);
}
if (FastMath.abs(deltaN - 1.0) < epsilon) {
break;
}
dPrev = dN;
cPrev = cN;
hPrev = hN;
n++;
}
if (n >= maxIterations) {
throw new MaxCountExceededException(LocalizedFormats.NON_CONVERGENT_CONTINUED_FRACTION,
maxIterations, x);
}
return hN;
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>
* Evaluates the continued fraction at the value x.
* </p>
*
* <p>
* The implementation of this method is based on the modified Lentz algorithm as described
* on page 18 ff. in:
* <ul>
* <li>
* I. J. Thompson, A. R. Barnett. "Coulomb and Bessel Functions of Complex Arguments and Order."
* <a target="_blank" href="http://www.fresco.org.uk/papers/Thompson-JCP64p490.pdf">
* http://www.fresco.org.uk/papers/Thompson-JCP64p490.pdf</a>
* </li>
* </ul>
* Note: the implementation uses the terms a<sub>i</sub> and b<sub>i</sub> as defined in
* <a href="http://mathworld.wolfram.com/ContinuedFraction.html">Continued Fraction / MathWorld</a>.
* </p>
*
* @param x the evaluation point.
* @param epsilon maximum error allowed.
* @param maxIterations maximum number of convergents
* @return the value of the continued fraction evaluated at x.
* @throws ConvergenceException if the algorithm fails to converge.
*/
public double evaluate(double x, double epsilon, int maxIterations) {
final double small = 1e-50;
double hPrev = getA(0, x);
// use the value of small as epsilon criteria for zero checks
if (Precision.equals(hPrev, 0.0, small)) {
hPrev = small;
}
int n = 1;
double dPrev = 0.0;
double cPrev = hPrev;
double hN = hPrev;
while (n < maxIterations) {
final double a = getA(n, x);
final double b = getB(n, x);
double dN = a + b * dPrev;
if (Precision.equals(dN, 0.0, small)) {
dN = small;
}
double cN = a + b / cPrev;
if (Precision.equals(cN, 0.0, small)) {
cN = small;
}
dN = 1 / dN;
final double deltaN = cN * dN;
hN = hPrev * deltaN;
if (Double.isInfinite(hN)) {
throw new ConvergenceException(LocalizedFormats.CONTINUED_FRACTION_INFINITY_DIVERGENCE,
x);
}
if (Double.isNaN(hN)) {
throw new ConvergenceException(LocalizedFormats.CONTINUED_FRACTION_NAN_DIVERGENCE,
x);
}
if (FastMath.abs(deltaN - 1.0) < epsilon) {
break;
}
dPrev = dN;
cPrev = cN;
hPrev = hN;
n++;
}
if (n >= maxIterations) {
throw new MaxCountExceededException(LocalizedFormats.NON_CONVERGENT_CONTINUED_FRACTION,
maxIterations, x);
}
return hN;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
16 | 3abcf5d2198a062d6fe122146e83a43d7cc351fdd351081ef282f7f41510bc59 | public static Number createNumber(String str) throws NumberFormatException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Turns a string value into a java.lang.Number.</p>
*
* <p>First, the value is examined for a type qualifier on the end
* (<code>'f','F','d','D','l','L'</code>). If it is found, it starts
* trying to create successively larger types from the type specified
* until one is found that can represent the value.</p>
*
* <p>If a type specifier is not found, it will check for a decimal point
* and then try successively larger types from <code>Integer</code> to
* <code>BigInteger</code> and from <code>Float</code> to
* <code>BigDecimal</code>.</p>
*
* <p>If the string starts with <code>0x</code> or <code>-0x</code> (lower or upper case), it
* will be interpreted as a hexadecimal integer. Values with leading
* <code>0</code>'s will not be interpreted as octal.</p>
*
* <p>Returns <code>null</code> if the string is <code>null</code>.</p>
*
* <p>This method does not trim the input string, i.e., strings with leading
* or trailing spaces will generate NumberFormatExceptions.</p>
*
* @param str String containing a number, may be null
* @return Number created from the string (or null if the input is null)
* @throws NumberFormatException if the value cannot be converted
*/
// plus minus everything. Prolly more. A lot are not separable.
// 45 45.5 45E7 4.5E7 Hex Oct Binary xxxF xxxD xxxf xxxd
// Possible inputs:
// new BigInteger(String,int radix)
// new BigInteger(String)
// new BigDecimal(String)
// Short.valueOf(String)
// Short.valueOf(String,int)
// Short.decode(String)
// Short.valueOf(String)
// Long.valueOf(String)
// Long.valueOf(String,int)
// Long.getLong(String,Integer)
// Long.getLong(String,int)
// Long.getLong(String)
// Long.valueOf(String)
// new Byte(String)
// Double.valueOf(String)
// Integer.valueOf(String)
// Integer.getInteger(String,Integer val)
// Integer.getInteger(String,int val)
// Integer.getInteger(String)
// Integer.decode(String)
// Integer.valueOf(String)
// Integer.valueOf(String,int radix)
// Float.valueOf(String)
// Float.valueOf(String)
// Double.valueOf(String)
// Byte.valueOf(String)
// Byte.valueOf(String,int radix)
// Byte.decode(String)
// useful methods:
// BigDecimal, BigInteger and Byte
// must handle Long, Float, Integer, Float, Short,
//-----------------------------------------------------------------------
public static Number createNumber(String str) throws NumberFormatException {
if (str == null) {
return null;
}
if (StringUtils.isBlank(str)) {
throw new NumberFormatException("A blank string is not a valid number");
}
if (str.startsWith("--")) {
// this is protection for poorness in java.lang.BigDecimal.
// it accepts this as a legal value, but it does not appear
// to be in specification of class. OS X Java parses it to
// a wrong value.
return null;
}
if (str.startsWith("0x") || str.startsWith("-0x") || str.startsWith("0X") || str.startsWith("-0X")) {
return createInteger(str);
}
char lastChar = str.charAt(str.length() - 1);
String mant;
String dec;
String exp;
int decPos = str.indexOf('.');
int expPos = str.indexOf('e') + str.indexOf('E') + 1;
if (decPos > -1) {
if (expPos > -1) {
if (expPos < decPos || expPos > str.length()) {
throw new NumberFormatException(str + " is not a valid number.");
}
dec = str.substring(decPos + 1, expPos);
} else {
dec = str.substring(decPos + 1);
}
mant = str.substring(0, decPos);
} else {
if (expPos > -1) {
if (expPos > str.length()) {
throw new NumberFormatException(str + " is not a valid number.");
}
mant = str.substring(0, expPos);
} else {
mant = str;
}
dec = null;
}
if (!Character.isDigit(lastChar) && lastChar != '.') {
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length() - 1);
} else {
exp = null;
}
//Requesting a specific type..
String numeric = str.substring(0, str.length() - 1);
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
switch (lastChar) {
case 'l' :
case 'L' :
if (dec == null
&& exp == null
&& (numeric.charAt(0) == '-' && isDigits(numeric.substring(1)) || isDigits(numeric))) {
try {
return createLong(numeric);
} catch (NumberFormatException nfe) { // NOPMD
// Too big for a long
}
return createBigInteger(numeric);
}
throw new NumberFormatException(str + " is not a valid number.");
case 'f' :
case 'F' :
try {
Float f = NumberUtils.createFloat(numeric);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
//If it's too big for a float or the float value = 0 and the string
//has non-zeros in it, then float does not have the precision we want
return f;
}
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
case 'd' :
case 'D' :
try {
Double d = NumberUtils.createDouble(numeric);
if (!(d.isInfinite() || (d.floatValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createBigDecimal(numeric);
} catch (NumberFormatException e) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
default :
throw new NumberFormatException(str + " is not a valid number.");
}
} else {
//User doesn't have a preference on the return type, so let's start
//small and go from there...
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length());
} else {
exp = null;
}
if (dec == null && exp == null) {
//Must be an int,long,bigint
try {
return createInteger(str);
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createLong(str);
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigInteger(str);
} else {
//Must be a float,double,BigDec
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
try {
Float f = createFloat(str);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
return f;
}
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
Double d = createDouble(str);
if (!(d.isInfinite() || (d.doubleValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigDecimal(str);
}
}
}
```
| public static Number createNumber(String str) throws NumberFormatException {
if (str == null) {
return null;
}
if (StringUtils.isBlank(str)) {
throw new NumberFormatException("A blank string is not a valid number");
}
if (str.startsWith("--")) {
// this is protection for poorness in java.lang.BigDecimal.
// it accepts this as a legal value, but it does not appear
// to be in specification of class. OS X Java parses it to
// a wrong value.
return null;
}
if (str.startsWith("0x") || str.startsWith("-0x") || str.startsWith("0X") || str.startsWith("-0X")) {
return createInteger(str);
}
char lastChar = str.charAt(str.length() - 1);
String mant;
String dec;
String exp;
int decPos = str.indexOf('.');
int expPos = str.indexOf('e') + str.indexOf('E') + 1;
if (decPos > -1) {
if (expPos > -1) {
if (expPos < decPos || expPos > str.length()) {
throw new NumberFormatException(str + " is not a valid number.");
}
dec = str.substring(decPos + 1, expPos);
} else {
dec = str.substring(decPos + 1);
}
mant = str.substring(0, decPos);
} else {
if (expPos > -1) {
if (expPos > str.length()) {
throw new NumberFormatException(str + " is not a valid number.");
}
mant = str.substring(0, expPos);
} else {
mant = str;
}
dec = null;
}
if (!Character.isDigit(lastChar) && lastChar != '.') {
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length() - 1);
} else {
exp = null;
}
//Requesting a specific type..
String numeric = str.substring(0, str.length() - 1);
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
switch (lastChar) {
case 'l' :
case 'L' :
if (dec == null
&& exp == null
&& (numeric.charAt(0) == '-' && isDigits(numeric.substring(1)) || isDigits(numeric))) {
try {
return createLong(numeric);
} catch (NumberFormatException nfe) { // NOPMD
// Too big for a long
}
return createBigInteger(numeric);
}
throw new NumberFormatException(str + " is not a valid number.");
case 'f' :
case 'F' :
try {
Float f = NumberUtils.createFloat(numeric);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
//If it's too big for a float or the float value = 0 and the string
//has non-zeros in it, then float does not have the precision we want
return f;
}
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
case 'd' :
case 'D' :
try {
Double d = NumberUtils.createDouble(numeric);
if (!(d.isInfinite() || (d.floatValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createBigDecimal(numeric);
} catch (NumberFormatException e) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
default :
throw new NumberFormatException(str + " is not a valid number.");
}
} else {
//User doesn't have a preference on the return type, so let's start
//small and go from there...
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length());
} else {
exp = null;
}
if (dec == null && exp == null) {
//Must be an int,long,bigint
try {
return createInteger(str);
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createLong(str);
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigInteger(str);
} else {
//Must be a float,double,BigDec
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
try {
Float f = createFloat(str);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
return f;
}
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
Double d = createDouble(str);
if (!(d.isInfinite() || (d.doubleValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigDecimal(str);
}
}
} | false | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Turns a string value into a java.lang.Number.</p>
*
* <p>First, the value is examined for a type qualifier on the end
* (<code>'f','F','d','D','l','L'</code>). If it is found, it starts
* trying to create successively larger types from the type specified
* until one is found that can represent the value.</p>
*
* <p>If a type specifier is not found, it will check for a decimal point
* and then try successively larger types from <code>Integer</code> to
* <code>BigInteger</code> and from <code>Float</code> to
* <code>BigDecimal</code>.</p>
*
* <p>If the string starts with <code>0x</code> or <code>-0x</code> (lower or upper case), it
* will be interpreted as a hexadecimal integer. Values with leading
* <code>0</code>'s will not be interpreted as octal.</p>
*
* <p>Returns <code>null</code> if the string is <code>null</code>.</p>
*
* <p>This method does not trim the input string, i.e., strings with leading
* or trailing spaces will generate NumberFormatExceptions.</p>
*
* @param str String containing a number, may be null
* @return Number created from the string (or null if the input is null)
* @throws NumberFormatException if the value cannot be converted
*/
// plus minus everything. Prolly more. A lot are not separable.
// 45 45.5 45E7 4.5E7 Hex Oct Binary xxxF xxxD xxxf xxxd
// Possible inputs:
// new BigInteger(String,int radix)
// new BigInteger(String)
// new BigDecimal(String)
// Short.valueOf(String)
// Short.valueOf(String,int)
// Short.decode(String)
// Short.valueOf(String)
// Long.valueOf(String)
// Long.valueOf(String,int)
// Long.getLong(String,Integer)
// Long.getLong(String,int)
// Long.getLong(String)
// Long.valueOf(String)
// new Byte(String)
// Double.valueOf(String)
// Integer.valueOf(String)
// Integer.getInteger(String,Integer val)
// Integer.getInteger(String,int val)
// Integer.getInteger(String)
// Integer.decode(String)
// Integer.valueOf(String)
// Integer.valueOf(String,int radix)
// Float.valueOf(String)
// Float.valueOf(String)
// Double.valueOf(String)
// Byte.valueOf(String)
// Byte.valueOf(String,int radix)
// Byte.decode(String)
// useful methods:
// BigDecimal, BigInteger and Byte
// must handle Long, Float, Integer, Float, Short,
//-----------------------------------------------------------------------
public static Number createNumber(String str) throws NumberFormatException {
if (str == null) {
return null;
}
if (StringUtils.isBlank(str)) {
throw new NumberFormatException("A blank string is not a valid number");
}
if (str.startsWith("--")) {
// this is protection for poorness in java.lang.BigDecimal.
// it accepts this as a legal value, but it does not appear
// to be in specification of class. OS X Java parses it to
// a wrong value.
return null;
}
if (str.startsWith("0x") || str.startsWith("-0x") || str.startsWith("0X") || str.startsWith("-0X")) {
return createInteger(str);
}
char lastChar = str.charAt(str.length() - 1);
String mant;
String dec;
String exp;
int decPos = str.indexOf('.');
int expPos = str.indexOf('e') + str.indexOf('E') + 1;
if (decPos > -1) {
if (expPos > -1) {
if (expPos < decPos || expPos > str.length()) {
throw new NumberFormatException(str + " is not a valid number.");
}
dec = str.substring(decPos + 1, expPos);
} else {
dec = str.substring(decPos + 1);
}
mant = str.substring(0, decPos);
} else {
if (expPos > -1) {
if (expPos > str.length()) {
throw new NumberFormatException(str + " is not a valid number.");
}
mant = str.substring(0, expPos);
} else {
mant = str;
}
dec = null;
}
if (!Character.isDigit(lastChar) && lastChar != '.') {
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length() - 1);
} else {
exp = null;
}
//Requesting a specific type..
String numeric = str.substring(0, str.length() - 1);
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
switch (lastChar) {
case 'l' :
case 'L' :
if (dec == null
&& exp == null
&& (numeric.charAt(0) == '-' && isDigits(numeric.substring(1)) || isDigits(numeric))) {
try {
return createLong(numeric);
} catch (NumberFormatException nfe) { // NOPMD
// Too big for a long
}
return createBigInteger(numeric);
}
throw new NumberFormatException(str + " is not a valid number.");
case 'f' :
case 'F' :
try {
Float f = NumberUtils.createFloat(numeric);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
//If it's too big for a float or the float value = 0 and the string
//has non-zeros in it, then float does not have the precision we want
return f;
}
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
case 'd' :
case 'D' :
try {
Double d = NumberUtils.createDouble(numeric);
if (!(d.isInfinite() || (d.floatValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createBigDecimal(numeric);
} catch (NumberFormatException e) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
default :
throw new NumberFormatException(str + " is not a valid number.");
}
} else {
//User doesn't have a preference on the return type, so let's start
//small and go from there...
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length());
} else {
exp = null;
}
if (dec == null && exp == null) {
//Must be an int,long,bigint
try {
return createInteger(str);
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createLong(str);
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigInteger(str);
} else {
//Must be a float,double,BigDec
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
try {
Float f = createFloat(str);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
return f;
}
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
Double d = createDouble(str);
if (!(d.isInfinite() || (d.doubleValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigDecimal(str);
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
2 | 3b00af5bc69529170a647c6cba29923596467a0e1ade648ac742c13d6c799d9c | protected void burstToken(String token, boolean stopAtNonOption)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Breaks <code>token</code> into its constituent parts
* using the following algorithm.
* <ul>
* <li>ignore the first character ("<b>-</b>")</li>
* <li>foreach remaining character check if an {@link Option}
* exists with that id.</li>
* <li>if an {@link Option} does exist then add that character
* prepended with "<b>-</b>" to the list of processed tokens.</li>
* <li>if the {@link Option} can have an argument value and there
* are remaining characters in the token then add the remaining
* characters as a token to the list of processed tokens.</li>
* <li>if an {@link Option} does <b>NOT</b> exist <b>AND</b>
* <code>stopAtNonOption</code> <b>IS</b> set then add the special token
* "<b>--</b>" followed by the remaining characters and also
* the remaining tokens directly to the processed tokens list.</li>
* <li>if an {@link Option} does <b>NOT</b> exist <b>AND</b>
* <code>stopAtNonOption</code> <b>IS NOT</b> set then add that
* character prepended with "<b>-</b>".</li>
* </ul>
* </p>
*
* @param token The current token to be <b>burst</b>
* @param stopAtNonOption Specifies whether to stop processing
* at the first non-Option encountered.
*/
protected void burstToken(String token, boolean stopAtNonOption)
{
int tokenLength = token.length();
for (int i = 1; i < tokenLength; i++)
{
String ch = String.valueOf(token.charAt(i));
boolean hasOption = options.hasOption(ch);
if (hasOption)
{
tokens.add("-" + ch);
currentOption = options.getOption(ch);
if (currentOption.hasArg() && (token.length() != (i + 1)))
{
tokens.add(token.substring(i + 1));
break;
}
}
else if (stopAtNonOption)
{
process(token.substring(i));
}
else
{
tokens.add("-" + ch);
}
}
}
```
| protected void burstToken(String token, boolean stopAtNonOption)
{
int tokenLength = token.length();
for (int i = 1; i < tokenLength; i++)
{
String ch = String.valueOf(token.charAt(i));
boolean hasOption = options.hasOption(ch);
if (hasOption)
{
tokens.add("-" + ch);
currentOption = options.getOption(ch);
if (currentOption.hasArg() && (token.length() != (i + 1)))
{
tokens.add(token.substring(i + 1));
break;
}
}
else if (stopAtNonOption)
{
process(token.substring(i));
}
else
{
tokens.add("-" + ch);
}
}
} | true | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Breaks <code>token</code> into its constituent parts
* using the following algorithm.
* <ul>
* <li>ignore the first character ("<b>-</b>")</li>
* <li>foreach remaining character check if an {@link Option}
* exists with that id.</li>
* <li>if an {@link Option} does exist then add that character
* prepended with "<b>-</b>" to the list of processed tokens.</li>
* <li>if the {@link Option} can have an argument value and there
* are remaining characters in the token then add the remaining
* characters as a token to the list of processed tokens.</li>
* <li>if an {@link Option} does <b>NOT</b> exist <b>AND</b>
* <code>stopAtNonOption</code> <b>IS</b> set then add the special token
* "<b>--</b>" followed by the remaining characters and also
* the remaining tokens directly to the processed tokens list.</li>
* <li>if an {@link Option} does <b>NOT</b> exist <b>AND</b>
* <code>stopAtNonOption</code> <b>IS NOT</b> set then add that
* character prepended with "<b>-</b>".</li>
* </ul>
* </p>
*
* @param token The current token to be <b>burst</b>
* @param stopAtNonOption Specifies whether to stop processing
* at the first non-Option encountered.
*/
protected void burstToken(String token, boolean stopAtNonOption)
{
int tokenLength = token.length();
for (int i = 1; i < tokenLength; i++)
{
String ch = String.valueOf(token.charAt(i));
boolean hasOption = options.hasOption(ch);
if (hasOption)
{
tokens.add("-" + ch);
currentOption = options.getOption(ch);
if (currentOption.hasArg() && (token.length() != (i + 1)))
{
tokens.add(token.substring(i + 1));
break;
}
}
else if (stopAtNonOption)
{
process(token.substring(i));
}
else
{
tokens.add("-" + ch);
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
3 | 3bd6a68c6197351575aeca385fabc17acf4854d8e800e3af25af54e33a221e23 | public static double linearCombination(final double[] a, final double[] b)
throws DimensionMismatchException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Compute a linear combination accurately.
* This method computes the sum of the products
* <code>a<sub>i</sub> b<sub>i</sub></code> to high accuracy.
* It does so by using specific multiplication and addition algorithms to
* preserve accuracy and reduce cancellation effects.
* <br/>
* It is based on the 2005 paper
* <a href="http://citeseerx.ist.psu.edu/viewdoc/summary?doi=10.1.1.2.1547">
* Accurate Sum and Dot Product</a> by Takeshi Ogita, Siegfried M. Rump,
* and Shin'ichi Oishi published in SIAM J. Sci. Comput.
*
* @param a Factors.
* @param b Factors.
* @return <code>Σ<sub>i</sub> a<sub>i</sub> b<sub>i</sub></code>.
* @throws DimensionMismatchException if arrays dimensions don't match
*/
public static double linearCombination(final double[] a, final double[] b)
throws DimensionMismatchException {
final int len = a.length;
if (len != b.length) {
throw new DimensionMismatchException(len, b.length);
}
// Revert to scalar multiplication.
final double[] prodHigh = new double[len];
double prodLowSum = 0;
for (int i = 0; i < len; i++) {
final double ai = a[i];
final double ca = SPLIT_FACTOR * ai;
final double aHigh = ca - (ca - ai);
final double aLow = ai - aHigh;
final double bi = b[i];
final double cb = SPLIT_FACTOR * bi;
final double bHigh = cb - (cb - bi);
final double bLow = bi - bHigh;
prodHigh[i] = ai * bi;
final double prodLow = aLow * bLow - (((prodHigh[i] -
aHigh * bHigh) -
aLow * bHigh) -
aHigh * bLow);
prodLowSum += prodLow;
}
final double prodHighCur = prodHigh[0];
double prodHighNext = prodHigh[1];
double sHighPrev = prodHighCur + prodHighNext;
double sPrime = sHighPrev - prodHighNext;
double sLowSum = (prodHighNext - (sHighPrev - sPrime)) + (prodHighCur - sPrime);
final int lenMinusOne = len - 1;
for (int i = 1; i < lenMinusOne; i++) {
prodHighNext = prodHigh[i + 1];
final double sHighCur = sHighPrev + prodHighNext;
sPrime = sHighCur - prodHighNext;
sLowSum += (prodHighNext - (sHighCur - sPrime)) + (sHighPrev - sPrime);
sHighPrev = sHighCur;
}
double result = sHighPrev + (prodLowSum + sLowSum);
if (Double.isNaN(result)) {
// either we have split infinite numbers or some coefficients were NaNs,
// just rely on the naive implementation and let IEEE754 handle this
result = 0;
for (int i = 0; i < len; ++i) {
result += a[i] * b[i];
}
}
return result;
}
```
| public static double linearCombination(final double[] a, final double[] b)
throws DimensionMismatchException {
final int len = a.length;
if (len != b.length) {
throw new DimensionMismatchException(len, b.length);
}
// Revert to scalar multiplication.
final double[] prodHigh = new double[len];
double prodLowSum = 0;
for (int i = 0; i < len; i++) {
final double ai = a[i];
final double ca = SPLIT_FACTOR * ai;
final double aHigh = ca - (ca - ai);
final double aLow = ai - aHigh;
final double bi = b[i];
final double cb = SPLIT_FACTOR * bi;
final double bHigh = cb - (cb - bi);
final double bLow = bi - bHigh;
prodHigh[i] = ai * bi;
final double prodLow = aLow * bLow - (((prodHigh[i] -
aHigh * bHigh) -
aLow * bHigh) -
aHigh * bLow);
prodLowSum += prodLow;
}
final double prodHighCur = prodHigh[0];
double prodHighNext = prodHigh[1];
double sHighPrev = prodHighCur + prodHighNext;
double sPrime = sHighPrev - prodHighNext;
double sLowSum = (prodHighNext - (sHighPrev - sPrime)) + (prodHighCur - sPrime);
final int lenMinusOne = len - 1;
for (int i = 1; i < lenMinusOne; i++) {
prodHighNext = prodHigh[i + 1];
final double sHighCur = sHighPrev + prodHighNext;
sPrime = sHighCur - prodHighNext;
sLowSum += (prodHighNext - (sHighCur - sPrime)) + (sHighPrev - sPrime);
sHighPrev = sHighCur;
}
double result = sHighPrev + (prodLowSum + sLowSum);
if (Double.isNaN(result)) {
// either we have split infinite numbers or some coefficients were NaNs,
// just rely on the naive implementation and let IEEE754 handle this
result = 0;
for (int i = 0; i < len; ++i) {
result += a[i] * b[i];
}
}
return result;
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Compute a linear combination accurately.
* This method computes the sum of the products
* <code>a<sub>i</sub> b<sub>i</sub></code> to high accuracy.
* It does so by using specific multiplication and addition algorithms to
* preserve accuracy and reduce cancellation effects.
* <br/>
* It is based on the 2005 paper
* <a href="http://citeseerx.ist.psu.edu/viewdoc/summary?doi=10.1.1.2.1547">
* Accurate Sum and Dot Product</a> by Takeshi Ogita, Siegfried M. Rump,
* and Shin'ichi Oishi published in SIAM J. Sci. Comput.
*
* @param a Factors.
* @param b Factors.
* @return <code>Σ<sub>i</sub> a<sub>i</sub> b<sub>i</sub></code>.
* @throws DimensionMismatchException if arrays dimensions don't match
*/
public static double linearCombination(final double[] a, final double[] b)
throws DimensionMismatchException {
final int len = a.length;
if (len != b.length) {
throw new DimensionMismatchException(len, b.length);
}
// Revert to scalar multiplication.
final double[] prodHigh = new double[len];
double prodLowSum = 0;
for (int i = 0; i < len; i++) {
final double ai = a[i];
final double ca = SPLIT_FACTOR * ai;
final double aHigh = ca - (ca - ai);
final double aLow = ai - aHigh;
final double bi = b[i];
final double cb = SPLIT_FACTOR * bi;
final double bHigh = cb - (cb - bi);
final double bLow = bi - bHigh;
prodHigh[i] = ai * bi;
final double prodLow = aLow * bLow - (((prodHigh[i] -
aHigh * bHigh) -
aLow * bHigh) -
aHigh * bLow);
prodLowSum += prodLow;
}
final double prodHighCur = prodHigh[0];
double prodHighNext = prodHigh[1];
double sHighPrev = prodHighCur + prodHighNext;
double sPrime = sHighPrev - prodHighNext;
double sLowSum = (prodHighNext - (sHighPrev - sPrime)) + (prodHighCur - sPrime);
final int lenMinusOne = len - 1;
for (int i = 1; i < lenMinusOne; i++) {
prodHighNext = prodHigh[i + 1];
final double sHighCur = sHighPrev + prodHighNext;
sPrime = sHighCur - prodHighNext;
sLowSum += (prodHighNext - (sHighCur - sPrime)) + (sHighPrev - sPrime);
sHighPrev = sHighCur;
}
double result = sHighPrev + (prodLowSum + sLowSum);
if (Double.isNaN(result)) {
// either we have split infinite numbers or some coefficients were NaNs,
// just rely on the naive implementation and let IEEE754 handle this
result = 0;
for (int i = 0; i < len; ++i) {
result += a[i] * b[i];
}
}
return result;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
5 | 3cb482e2e949e5b891d4cad1465f5d0a53a546f44a830654006bda2bbce63dad | public int read(byte[] buffer, int start, int length) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public int read(byte[] buffer, int start, int length) throws IOException {
if (closed) {
throw new IOException("The stream is closed");
}
if (inf.finished() || current == null) {
return -1;
}
// avoid int overflow, check null buffer
if (start <= buffer.length && length >= 0 && start >= 0
&& buffer.length - start >= length) {
if (current.getMethod() == ZipArchiveOutputStream.STORED) {
int csize = (int) current.getSize();
if (readBytesOfEntry >= csize) {
return -1;
}
if (offsetInBuffer >= lengthOfLastRead) {
offsetInBuffer = 0;
if ((lengthOfLastRead = in.read(buf)) == -1) {
return -1;
}
count(lengthOfLastRead);
bytesReadFromStream += lengthOfLastRead;
}
int toRead = length > lengthOfLastRead
? lengthOfLastRead - offsetInBuffer
: length;
if ((csize - readBytesOfEntry) < toRead) {
toRead = csize - readBytesOfEntry;
}
System.arraycopy(buf, offsetInBuffer, buffer, start, toRead);
offsetInBuffer += toRead;
readBytesOfEntry += toRead;
crc.update(buffer, start, toRead);
return toRead;
}
if (inf.needsInput()) {
fill();
if (lengthOfLastRead > 0) {
bytesReadFromStream += lengthOfLastRead;
}
}
int read = 0;
try {
read = inf.inflate(buffer, start, length);
} catch (DataFormatException e) {
throw new ZipException(e.getMessage());
}
if (read == 0) {
if (inf.finished()) {
return -1;
} else if (lengthOfLastRead == -1) {
throw new IOException("Truncated ZIP file");
}
}
crc.update(buffer, start, read);
return read;
}
throw new ArrayIndexOutOfBoundsException();
}
```
| public int read(byte[] buffer, int start, int length) throws IOException {
if (closed) {
throw new IOException("The stream is closed");
}
if (inf.finished() || current == null) {
return -1;
}
// avoid int overflow, check null buffer
if (start <= buffer.length && length >= 0 && start >= 0
&& buffer.length - start >= length) {
if (current.getMethod() == ZipArchiveOutputStream.STORED) {
int csize = (int) current.getSize();
if (readBytesOfEntry >= csize) {
return -1;
}
if (offsetInBuffer >= lengthOfLastRead) {
offsetInBuffer = 0;
if ((lengthOfLastRead = in.read(buf)) == -1) {
return -1;
}
count(lengthOfLastRead);
bytesReadFromStream += lengthOfLastRead;
}
int toRead = length > lengthOfLastRead
? lengthOfLastRead - offsetInBuffer
: length;
if ((csize - readBytesOfEntry) < toRead) {
toRead = csize - readBytesOfEntry;
}
System.arraycopy(buf, offsetInBuffer, buffer, start, toRead);
offsetInBuffer += toRead;
readBytesOfEntry += toRead;
crc.update(buffer, start, toRead);
return toRead;
}
if (inf.needsInput()) {
fill();
if (lengthOfLastRead > 0) {
bytesReadFromStream += lengthOfLastRead;
}
}
int read = 0;
try {
read = inf.inflate(buffer, start, length);
} catch (DataFormatException e) {
throw new ZipException(e.getMessage());
}
if (read == 0) {
if (inf.finished()) {
return -1;
} else if (lengthOfLastRead == -1) {
throw new IOException("Truncated ZIP file");
}
}
crc.update(buffer, start, read);
return read;
}
throw new ArrayIndexOutOfBoundsException();
} | false | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public int read(byte[] buffer, int start, int length) throws IOException {
if (closed) {
throw new IOException("The stream is closed");
}
if (inf.finished() || current == null) {
return -1;
}
// avoid int overflow, check null buffer
if (start <= buffer.length && length >= 0 && start >= 0
&& buffer.length - start >= length) {
if (current.getMethod() == ZipArchiveOutputStream.STORED) {
int csize = (int) current.getSize();
if (readBytesOfEntry >= csize) {
return -1;
}
if (offsetInBuffer >= lengthOfLastRead) {
offsetInBuffer = 0;
if ((lengthOfLastRead = in.read(buf)) == -1) {
return -1;
}
count(lengthOfLastRead);
bytesReadFromStream += lengthOfLastRead;
}
int toRead = length > lengthOfLastRead
? lengthOfLastRead - offsetInBuffer
: length;
if ((csize - readBytesOfEntry) < toRead) {
toRead = csize - readBytesOfEntry;
}
System.arraycopy(buf, offsetInBuffer, buffer, start, toRead);
offsetInBuffer += toRead;
readBytesOfEntry += toRead;
crc.update(buffer, start, toRead);
return toRead;
}
if (inf.needsInput()) {
fill();
if (lengthOfLastRead > 0) {
bytesReadFromStream += lengthOfLastRead;
}
}
int read = 0;
try {
read = inf.inflate(buffer, start, length);
} catch (DataFormatException e) {
throw new ZipException(e.getMessage());
}
if (read == 0) {
if (inf.finished()) {
return -1;
} else if (lengthOfLastRead == -1) {
throw new IOException("Truncated ZIP file");
}
}
crc.update(buffer, start, read);
return read;
}
throw new ArrayIndexOutOfBoundsException();
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
44 | 3cca9cc9eed361c3eedb533ec701b336efdd24a5a8230a9e385a8d5b4ef4e84b | public ChecksumCalculatingInputStream(final Checksum checksum, final InputStream in) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public ChecksumCalculatingInputStream(final Checksum checksum, final InputStream in) {
if ( checksum == null ){
throw new NullPointerException("Parameter checksum must not be null");
}
if ( in == null ){
throw new NullPointerException("Parameter in must not be null");
}
this.checksum = checksum;
this.in = in;
}
```
| public ChecksumCalculatingInputStream(final Checksum checksum, final InputStream in) {
if ( checksum == null ){
throw new NullPointerException("Parameter checksum must not be null");
}
if ( in == null ){
throw new NullPointerException("Parameter in must not be null");
}
this.checksum = checksum;
this.in = in;
} | false | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public ChecksumCalculatingInputStream(final Checksum checksum, final InputStream in) {
if ( checksum == null ){
throw new NullPointerException("Parameter checksum must not be null");
}
if ( in == null ){
throw new NullPointerException("Parameter in must not be null");
}
this.checksum = checksum;
this.in = in;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
28 | 3cfc569fb3f4bf2e0e351ff7ab9967c7fa8d1beb291d87b3ad78c36f03b238d8 | @Override
public int read(byte[] buf, int offset, int numToRead) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Reads bytes from the current tar archive entry.
*
* This method is aware of the boundaries of the current
* entry in the archive and will deal with them as if they
* were this stream's start and EOF.
*
* @param buf The buffer into which to place bytes read.
* @param offset The offset at which to place bytes read.
* @param numToRead The number of bytes to read.
* @return The number of bytes read, or -1 at EOF.
* @throws IOException on error
*/
@Override
public int read(byte[] buf, int offset, int numToRead) throws IOException {
int totalRead = 0;
if (hasHitEOF || entryOffset >= entrySize) {
return -1;
}
if (currEntry == null) {
throw new IllegalStateException("No current tar entry");
}
numToRead = Math.min(numToRead, available());
totalRead = is.read(buf, offset, numToRead);
if (totalRead == -1) {
if (numToRead > 0) {
throw new IOException("Truncated TAR archive");
}
hasHitEOF = true;
} else {
count(totalRead);
entryOffset += totalRead;
}
return totalRead;
}
```
| @Override
public int read(byte[] buf, int offset, int numToRead) throws IOException {
int totalRead = 0;
if (hasHitEOF || entryOffset >= entrySize) {
return -1;
}
if (currEntry == null) {
throw new IllegalStateException("No current tar entry");
}
numToRead = Math.min(numToRead, available());
totalRead = is.read(buf, offset, numToRead);
if (totalRead == -1) {
if (numToRead > 0) {
throw new IOException("Truncated TAR archive");
}
hasHitEOF = true;
} else {
count(totalRead);
entryOffset += totalRead;
}
return totalRead;
} | false | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Reads bytes from the current tar archive entry.
*
* This method is aware of the boundaries of the current
* entry in the archive and will deal with them as if they
* were this stream's start and EOF.
*
* @param buf The buffer into which to place bytes read.
* @param offset The offset at which to place bytes read.
* @param numToRead The number of bytes to read.
* @return The number of bytes read, or -1 at EOF.
* @throws IOException on error
*/
@Override
public int read(byte[] buf, int offset, int numToRead) throws IOException {
int totalRead = 0;
if (hasHitEOF || entryOffset >= entrySize) {
return -1;
}
if (currEntry == null) {
throw new IllegalStateException("No current tar entry");
}
numToRead = Math.min(numToRead, available());
totalRead = is.read(buf, offset, numToRead);
if (totalRead == -1) {
if (numToRead > 0) {
throw new IOException("Truncated TAR archive");
}
hasHitEOF = true;
} else {
count(totalRead);
entryOffset += totalRead;
}
return totalRead;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
86 | 3e7abd1c402c8e4f86ea5511af24232ba54521501322e4802f5aeeee4ceadb2a | static boolean evaluatesToLocalValue(Node value, Predicate<Node> locals) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* @param locals A predicate to apply to unknown local values.
* @return Whether the node is known to be a value that is not a reference
* outside the expression scope.
*/
static boolean evaluatesToLocalValue(Node value, Predicate<Node> locals) {
switch (value.getType()) {
case Token.ASSIGN:
// A result that is aliased by a non-local name, is the effectively the
// same as returning a non-local name, but this doesn't matter if the
// value is immutable.
return NodeUtil.isImmutableValue(value.getLastChild())
|| (locals.apply(value)
&& evaluatesToLocalValue(value.getLastChild(), locals));
case Token.COMMA:
return evaluatesToLocalValue(value.getLastChild(), locals);
case Token.AND:
case Token.OR:
return evaluatesToLocalValue(value.getFirstChild(), locals)
&& evaluatesToLocalValue(value.getLastChild(), locals);
case Token.HOOK:
return evaluatesToLocalValue(value.getFirstChild().getNext(), locals)
&& evaluatesToLocalValue(value.getLastChild(), locals);
case Token.INC:
case Token.DEC:
if (value.getBooleanProp(Node.INCRDECR_PROP)) {
return evaluatesToLocalValue(value.getFirstChild(), locals);
} else {
return true;
}
case Token.THIS:
return locals.apply(value);
case Token.NAME:
return isImmutableValue(value) || locals.apply(value);
case Token.GETELEM:
case Token.GETPROP:
// There is no information about the locality of object properties.
return locals.apply(value);
case Token.CALL:
return callHasLocalResult(value)
|| isToStringMethodCall(value)
|| locals.apply(value);
case Token.NEW:
// TODO(nicksantos): This needs to be changed so that it
// returns true iff we're sure the value was never aliased from inside
// the constructor (similar to callHasLocalResult)
return false;
case Token.FUNCTION:
case Token.REGEXP:
case Token.ARRAYLIT:
case Token.OBJECTLIT:
// Literals objects with non-literal children are allowed.
return true;
case Token.IN:
// TODO(johnlenz): should IN operator be included in #isSimpleOperator?
return true;
default:
// Other op force a local value:
// x = '' + g (x is now an local string)
// x -= g (x is now an local number)
if (isAssignmentOp(value)
|| isSimpleOperator(value)
|| isImmutableValue(value)) {
return true;
}
throw new IllegalStateException(
"Unexpected expression node" + value +
"\n parent:" + value.getParent());
}
}
```
| static boolean evaluatesToLocalValue(Node value, Predicate<Node> locals) {
switch (value.getType()) {
case Token.ASSIGN:
// A result that is aliased by a non-local name, is the effectively the
// same as returning a non-local name, but this doesn't matter if the
// value is immutable.
return NodeUtil.isImmutableValue(value.getLastChild())
|| (locals.apply(value)
&& evaluatesToLocalValue(value.getLastChild(), locals));
case Token.COMMA:
return evaluatesToLocalValue(value.getLastChild(), locals);
case Token.AND:
case Token.OR:
return evaluatesToLocalValue(value.getFirstChild(), locals)
&& evaluatesToLocalValue(value.getLastChild(), locals);
case Token.HOOK:
return evaluatesToLocalValue(value.getFirstChild().getNext(), locals)
&& evaluatesToLocalValue(value.getLastChild(), locals);
case Token.INC:
case Token.DEC:
if (value.getBooleanProp(Node.INCRDECR_PROP)) {
return evaluatesToLocalValue(value.getFirstChild(), locals);
} else {
return true;
}
case Token.THIS:
return locals.apply(value);
case Token.NAME:
return isImmutableValue(value) || locals.apply(value);
case Token.GETELEM:
case Token.GETPROP:
// There is no information about the locality of object properties.
return locals.apply(value);
case Token.CALL:
return callHasLocalResult(value)
|| isToStringMethodCall(value)
|| locals.apply(value);
case Token.NEW:
// TODO(nicksantos): This needs to be changed so that it
// returns true iff we're sure the value was never aliased from inside
// the constructor (similar to callHasLocalResult)
return false;
case Token.FUNCTION:
case Token.REGEXP:
case Token.ARRAYLIT:
case Token.OBJECTLIT:
// Literals objects with non-literal children are allowed.
return true;
case Token.IN:
// TODO(johnlenz): should IN operator be included in #isSimpleOperator?
return true;
default:
// Other op force a local value:
// x = '' + g (x is now an local string)
// x -= g (x is now an local number)
if (isAssignmentOp(value)
|| isSimpleOperator(value)
|| isImmutableValue(value)) {
return true;
}
throw new IllegalStateException(
"Unexpected expression node" + value +
"\n parent:" + value.getParent());
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* @param locals A predicate to apply to unknown local values.
* @return Whether the node is known to be a value that is not a reference
* outside the expression scope.
*/
static boolean evaluatesToLocalValue(Node value, Predicate<Node> locals) {
switch (value.getType()) {
case Token.ASSIGN:
// A result that is aliased by a non-local name, is the effectively the
// same as returning a non-local name, but this doesn't matter if the
// value is immutable.
return NodeUtil.isImmutableValue(value.getLastChild())
|| (locals.apply(value)
&& evaluatesToLocalValue(value.getLastChild(), locals));
case Token.COMMA:
return evaluatesToLocalValue(value.getLastChild(), locals);
case Token.AND:
case Token.OR:
return evaluatesToLocalValue(value.getFirstChild(), locals)
&& evaluatesToLocalValue(value.getLastChild(), locals);
case Token.HOOK:
return evaluatesToLocalValue(value.getFirstChild().getNext(), locals)
&& evaluatesToLocalValue(value.getLastChild(), locals);
case Token.INC:
case Token.DEC:
if (value.getBooleanProp(Node.INCRDECR_PROP)) {
return evaluatesToLocalValue(value.getFirstChild(), locals);
} else {
return true;
}
case Token.THIS:
return locals.apply(value);
case Token.NAME:
return isImmutableValue(value) || locals.apply(value);
case Token.GETELEM:
case Token.GETPROP:
// There is no information about the locality of object properties.
return locals.apply(value);
case Token.CALL:
return callHasLocalResult(value)
|| isToStringMethodCall(value)
|| locals.apply(value);
case Token.NEW:
// TODO(nicksantos): This needs to be changed so that it
// returns true iff we're sure the value was never aliased from inside
// the constructor (similar to callHasLocalResult)
return false;
case Token.FUNCTION:
case Token.REGEXP:
case Token.ARRAYLIT:
case Token.OBJECTLIT:
// Literals objects with non-literal children are allowed.
return true;
case Token.IN:
// TODO(johnlenz): should IN operator be included in #isSimpleOperator?
return true;
default:
// Other op force a local value:
// x = '' + g (x is now an local string)
// x -= g (x is now an local number)
if (isAssignmentOp(value)
|| isSimpleOperator(value)
|| isImmutableValue(value)) {
return true;
}
throw new IllegalStateException(
"Unexpected expression node" + value +
"\n parent:" + value.getParent());
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
45 | 3effed3d2af2d7069f6ab40db9f60a7ae548990eaca4bf32819b59fc08fa3db5 | public OpenMapRealMatrix(int rowDimension, int columnDimension) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Build a sparse matrix with the supplied row and column dimensions.
*
* @param rowDimension Number of rows of the matrix.
* @param columnDimension Number of columns of the matrix.
*/
public OpenMapRealMatrix(int rowDimension, int columnDimension) {
super(rowDimension, columnDimension);
long lRow = (long) rowDimension;
long lCol = (long) columnDimension;
if (lRow * lCol >= (long) Integer.MAX_VALUE) {
throw new NumberIsTooLargeException(lRow * lCol, Integer.MAX_VALUE, false);
}
this.rows = rowDimension;
this.columns = columnDimension;
this.entries = new OpenIntToDoubleHashMap(0.0);
}
```
| public OpenMapRealMatrix(int rowDimension, int columnDimension) {
super(rowDimension, columnDimension);
long lRow = (long) rowDimension;
long lCol = (long) columnDimension;
if (lRow * lCol >= (long) Integer.MAX_VALUE) {
throw new NumberIsTooLargeException(lRow * lCol, Integer.MAX_VALUE, false);
}
this.rows = rowDimension;
this.columns = columnDimension;
this.entries = new OpenIntToDoubleHashMap(0.0);
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Build a sparse matrix with the supplied row and column dimensions.
*
* @param rowDimension Number of rows of the matrix.
* @param columnDimension Number of columns of the matrix.
*/
public OpenMapRealMatrix(int rowDimension, int columnDimension) {
super(rowDimension, columnDimension);
long lRow = (long) rowDimension;
long lCol = (long) columnDimension;
if (lRow * lCol >= (long) Integer.MAX_VALUE) {
throw new NumberIsTooLargeException(lRow * lCol, Integer.MAX_VALUE, false);
}
this.rows = rowDimension;
this.columns = columnDimension;
this.entries = new OpenIntToDoubleHashMap(0.0);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
40 | 3f42a5ab6a0fdebad780bc3e398e098e938741f7212d784f5308e715fc17f26c | @SuppressWarnings("unchecked") // returned value will have type T because it is fixed by clazz
public static <T> T createValue(final String str, final Class<T> clazz) throws ParseException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns the <code>Object</code> of type <code>clazz</code>
* with the value of <code>str</code>.
*
* @param str the command line value
* @param clazz the type of argument
* @return The instance of <code>clazz</code> initialised with
* the value of <code>str</code>.
* @throws ParseException if the value creation for the given class failed
*/
@SuppressWarnings("unchecked") // returned value will have type T because it is fixed by clazz
public static <T> T createValue(final String str, final Class<T> clazz) throws ParseException
{
if (PatternOptionBuilder.STRING_VALUE == clazz)
{
return (T) str;
}
else if (PatternOptionBuilder.OBJECT_VALUE == clazz)
{
return (T) createObject(str);
}
else if (PatternOptionBuilder.NUMBER_VALUE == clazz)
{
return (T) createNumber(str);
}
else if (PatternOptionBuilder.DATE_VALUE == clazz)
{
return (T) createDate(str);
}
else if (PatternOptionBuilder.CLASS_VALUE == clazz)
{
return (T) createClass(str);
}
else if (PatternOptionBuilder.FILE_VALUE == clazz)
{
return (T) createFile(str);
}
else if (PatternOptionBuilder.EXISTING_FILE_VALUE == clazz)
{
return (T) openFile(str);
}
else if (PatternOptionBuilder.FILES_VALUE == clazz)
{
return (T) createFiles(str);
}
else if (PatternOptionBuilder.URL_VALUE == clazz)
{
return (T) createURL(str);
}
else
{
return null;
}
}
```
| @SuppressWarnings("unchecked") // returned value will have type T because it is fixed by clazz
public static <T> T createValue(final String str, final Class<T> clazz) throws ParseException
{
if (PatternOptionBuilder.STRING_VALUE == clazz)
{
return (T) str;
}
else if (PatternOptionBuilder.OBJECT_VALUE == clazz)
{
return (T) createObject(str);
}
else if (PatternOptionBuilder.NUMBER_VALUE == clazz)
{
return (T) createNumber(str);
}
else if (PatternOptionBuilder.DATE_VALUE == clazz)
{
return (T) createDate(str);
}
else if (PatternOptionBuilder.CLASS_VALUE == clazz)
{
return (T) createClass(str);
}
else if (PatternOptionBuilder.FILE_VALUE == clazz)
{
return (T) createFile(str);
}
else if (PatternOptionBuilder.EXISTING_FILE_VALUE == clazz)
{
return (T) openFile(str);
}
else if (PatternOptionBuilder.FILES_VALUE == clazz)
{
return (T) createFiles(str);
}
else if (PatternOptionBuilder.URL_VALUE == clazz)
{
return (T) createURL(str);
}
else
{
return null;
}
} | true | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns the <code>Object</code> of type <code>clazz</code>
* with the value of <code>str</code>.
*
* @param str the command line value
* @param clazz the type of argument
* @return The instance of <code>clazz</code> initialised with
* the value of <code>str</code>.
* @throws ParseException if the value creation for the given class failed
*/
@SuppressWarnings("unchecked") // returned value will have type T because it is fixed by clazz
public static <T> T createValue(final String str, final Class<T> clazz) throws ParseException
{
if (PatternOptionBuilder.STRING_VALUE == clazz)
{
return (T) str;
}
else if (PatternOptionBuilder.OBJECT_VALUE == clazz)
{
return (T) createObject(str);
}
else if (PatternOptionBuilder.NUMBER_VALUE == clazz)
{
return (T) createNumber(str);
}
else if (PatternOptionBuilder.DATE_VALUE == clazz)
{
return (T) createDate(str);
}
else if (PatternOptionBuilder.CLASS_VALUE == clazz)
{
return (T) createClass(str);
}
else if (PatternOptionBuilder.FILE_VALUE == clazz)
{
return (T) createFile(str);
}
else if (PatternOptionBuilder.EXISTING_FILE_VALUE == clazz)
{
return (T) openFile(str);
}
else if (PatternOptionBuilder.FILES_VALUE == clazz)
{
return (T) createFiles(str);
}
else if (PatternOptionBuilder.URL_VALUE == clazz)
{
return (T) createURL(str);
}
else
{
return null;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
89 | 3f57932c5c681fad8bf50a031cbe00b982f8caaffc8ae001bb0ee51a36b840c1 | @Deprecated
public void addValue(Object v) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Adds 1 to the frequency count for v.
* <p>
* If other objects have already been added to this Frequency, v must
* be comparable to those that have already been added.
* </p>
*
* @param v the value to add.
* @throws IllegalArgumentException if <code>v</code> is not Comparable,
* or is not comparable with previous entries
* @deprecated use {@link #addValue(Comparable)} instead
*/
@Deprecated
public void addValue(Object v) {
if (v instanceof Comparable<?>){
addValue((Comparable<?>) v);
} else {
throw new IllegalArgumentException("Object must implement Comparable");
}
}
```
| @Deprecated
public void addValue(Object v) {
if (v instanceof Comparable<?>){
addValue((Comparable<?>) v);
} else {
throw new IllegalArgumentException("Object must implement Comparable");
}
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Adds 1 to the frequency count for v.
* <p>
* If other objects have already been added to this Frequency, v must
* be comparable to those that have already been added.
* </p>
*
* @param v the value to add.
* @throws IllegalArgumentException if <code>v</code> is not Comparable,
* or is not comparable with previous entries
* @deprecated use {@link #addValue(Comparable)} instead
*/
@Deprecated
public void addValue(Object v) {
if (v instanceof Comparable<?>){
addValue((Comparable<?>) v);
} else {
throw new IllegalArgumentException("Object must implement Comparable");
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
98 | 3f91fd3b2102d4aa26695ba0eb9ef76130cd71abc97e04575036108d926c09d6 | public Object complete(JsonParser p, DeserializationContext ctxt,
PropertyValueBuffer buffer, PropertyBasedCreator creator)
throws IOException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Variant called when creation of the POJO involves buffering of creator properties
* as well as property-based creator.
*/
public Object complete(JsonParser p, DeserializationContext ctxt,
PropertyValueBuffer buffer, PropertyBasedCreator creator)
throws IOException
{
// first things first: deserialize all data buffered:
final int len = _properties.length;
Object[] values = new Object[len];
for (int i = 0; i < len; ++i) {
String typeId = _typeIds[i];
final ExtTypedProperty extProp = _properties[i];
if (typeId == null) {
// let's allow missing both type and property (may already have been set, too)
if (_tokens[i] == null) {
continue;
}
// but not just one
// 26-Oct-2012, tatu: As per [databind#94], must allow use of 'defaultImpl'
if (!extProp.hasDefaultType()) {
ctxt.reportInputMismatch(_beanType,
"Missing external type id property '%s'",
extProp.getTypePropertyName());
} else {
typeId = extProp.getDefaultTypeId();
}
} else if (_tokens[i] == null) {
SettableBeanProperty prop = extProp.getProperty();
ctxt.reportInputMismatch(_beanType,
"Missing property '%s' for external type id '%s'",
prop.getName(), _properties[i].getTypePropertyName());
}
values[i] = _deserialize(p, ctxt, i, typeId);
final SettableBeanProperty prop = extProp.getProperty();
// also: if it's creator prop, fill in
if (prop.getCreatorIndex() >= 0) {
buffer.assignParameter(prop, values[i]);
// [databind#999] And maybe there's creator property for type id too?
SettableBeanProperty typeProp = extProp.getTypeProperty();
// for now, should only be needed for creator properties, too
if ((typeProp != null) && (typeProp.getCreatorIndex() >= 0)) {
// 31-May-2018, tatu: [databind#1328] if id is NOT plain `String`, need to
// apply deserializer... fun fun.
buffer.assignParameter(typeProp, typeId);
}
}
}
Object bean = creator.build(ctxt, buffer);
// third: assign non-creator properties
for (int i = 0; i < len; ++i) {
SettableBeanProperty prop = _properties[i].getProperty();
if (prop.getCreatorIndex() < 0) {
prop.set(bean, values[i]);
}
}
return bean;
}
```
| public Object complete(JsonParser p, DeserializationContext ctxt,
PropertyValueBuffer buffer, PropertyBasedCreator creator)
throws IOException
{
// first things first: deserialize all data buffered:
final int len = _properties.length;
Object[] values = new Object[len];
for (int i = 0; i < len; ++i) {
String typeId = _typeIds[i];
final ExtTypedProperty extProp = _properties[i];
if (typeId == null) {
// let's allow missing both type and property (may already have been set, too)
if (_tokens[i] == null) {
continue;
}
// but not just one
// 26-Oct-2012, tatu: As per [databind#94], must allow use of 'defaultImpl'
if (!extProp.hasDefaultType()) {
ctxt.reportInputMismatch(_beanType,
"Missing external type id property '%s'",
extProp.getTypePropertyName());
} else {
typeId = extProp.getDefaultTypeId();
}
} else if (_tokens[i] == null) {
SettableBeanProperty prop = extProp.getProperty();
ctxt.reportInputMismatch(_beanType,
"Missing property '%s' for external type id '%s'",
prop.getName(), _properties[i].getTypePropertyName());
}
values[i] = _deserialize(p, ctxt, i, typeId);
final SettableBeanProperty prop = extProp.getProperty();
// also: if it's creator prop, fill in
if (prop.getCreatorIndex() >= 0) {
buffer.assignParameter(prop, values[i]);
// [databind#999] And maybe there's creator property for type id too?
SettableBeanProperty typeProp = extProp.getTypeProperty();
// for now, should only be needed for creator properties, too
if ((typeProp != null) && (typeProp.getCreatorIndex() >= 0)) {
// 31-May-2018, tatu: [databind#1328] if id is NOT plain `String`, need to
// apply deserializer... fun fun.
buffer.assignParameter(typeProp, typeId);
}
}
}
Object bean = creator.build(ctxt, buffer);
// third: assign non-creator properties
for (int i = 0; i < len; ++i) {
SettableBeanProperty prop = _properties[i].getProperty();
if (prop.getCreatorIndex() < 0) {
prop.set(bean, values[i]);
}
}
return bean;
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Variant called when creation of the POJO involves buffering of creator properties
* as well as property-based creator.
*/
public Object complete(JsonParser p, DeserializationContext ctxt,
PropertyValueBuffer buffer, PropertyBasedCreator creator)
throws IOException
{
// first things first: deserialize all data buffered:
final int len = _properties.length;
Object[] values = new Object[len];
for (int i = 0; i < len; ++i) {
String typeId = _typeIds[i];
final ExtTypedProperty extProp = _properties[i];
if (typeId == null) {
// let's allow missing both type and property (may already have been set, too)
if (_tokens[i] == null) {
continue;
}
// but not just one
// 26-Oct-2012, tatu: As per [databind#94], must allow use of 'defaultImpl'
if (!extProp.hasDefaultType()) {
ctxt.reportInputMismatch(_beanType,
"Missing external type id property '%s'",
extProp.getTypePropertyName());
} else {
typeId = extProp.getDefaultTypeId();
}
} else if (_tokens[i] == null) {
SettableBeanProperty prop = extProp.getProperty();
ctxt.reportInputMismatch(_beanType,
"Missing property '%s' for external type id '%s'",
prop.getName(), _properties[i].getTypePropertyName());
}
values[i] = _deserialize(p, ctxt, i, typeId);
final SettableBeanProperty prop = extProp.getProperty();
// also: if it's creator prop, fill in
if (prop.getCreatorIndex() >= 0) {
buffer.assignParameter(prop, values[i]);
// [databind#999] And maybe there's creator property for type id too?
SettableBeanProperty typeProp = extProp.getTypeProperty();
// for now, should only be needed for creator properties, too
if ((typeProp != null) && (typeProp.getCreatorIndex() >= 0)) {
// 31-May-2018, tatu: [databind#1328] if id is NOT plain `String`, need to
// apply deserializer... fun fun.
buffer.assignParameter(typeProp, typeId);
}
}
}
Object bean = creator.build(ctxt, buffer);
// third: assign non-creator properties
for (int i = 0; i < len; ++i) {
SettableBeanProperty prop = _properties[i].getProperty();
if (prop.getCreatorIndex() < 0) {
prop.set(bean, values[i]);
}
}
return bean;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
75 | 3fc4735b82620958a55c2adfdcc8760bc2081f4417b148a00189d3923a4e04cc | final void html(final Appendable accum, final Document.OutputSettings out) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
final void html(final Appendable accum, final Document.OutputSettings out) throws IOException {
final int sz = size;
for (int i = 0; i < sz; i++) {
// inlined from Attribute.html()
final String key = keys[i];
final String val = vals[i];
accum.append(' ').append(key);
// collapse checked=null, checked="", checked=checked; write out others
if (!Attribute.shouldCollapseAttribute(key, val, out)) {
accum.append("=\"");
Entities.escape(accum, val == null ? EmptyString : val, out, true, false, false);
accum.append('"');
}
}
}
```
| final void html(final Appendable accum, final Document.OutputSettings out) throws IOException {
final int sz = size;
for (int i = 0; i < sz; i++) {
// inlined from Attribute.html()
final String key = keys[i];
final String val = vals[i];
accum.append(' ').append(key);
// collapse checked=null, checked="", checked=checked; write out others
if (!Attribute.shouldCollapseAttribute(key, val, out)) {
accum.append("=\"");
Entities.escape(accum, val == null ? EmptyString : val, out, true, false, false);
accum.append('"');
}
}
} | false | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
final void html(final Appendable accum, final Document.OutputSettings out) throws IOException {
final int sz = size;
for (int i = 0; i < sz; i++) {
// inlined from Attribute.html()
final String key = keys[i];
final String val = vals[i];
accum.append(' ').append(key);
// collapse checked=null, checked="", checked=checked; write out others
if (!Attribute.shouldCollapseAttribute(key, val, out)) {
accum.append("=\"");
Entities.escape(accum, val == null ? EmptyString : val, out, true, false, false);
accum.append('"');
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
97 | 3fe9cb34326a1594b06efacdea1437896108e8141d5030bcaa7b09f8b2a9bf12 | private Node tryFoldShift(Node n, Node left, Node right) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Try to fold shift operations
*/
private Node tryFoldShift(Node n, Node left, Node right) {
if (left.getType() == Token.NUMBER &&
right.getType() == Token.NUMBER) {
double result;
double lval = left.getDouble();
double rval = right.getDouble();
// check ranges. We do not do anything that would clip the double to
// a 32-bit range, since the user likely does not intend that.
if (!(lval >= Integer.MIN_VALUE && lval <= Integer.MAX_VALUE)) {
error(BITWISE_OPERAND_OUT_OF_RANGE, left);
return n;
}
// only the lower 5 bits are used when shifting, so don't do anything
// if the shift amount is outside [0,32)
if (!(rval >= 0 && rval < 32)) {
error(SHIFT_AMOUNT_OUT_OF_BOUNDS, right);
return n;
}
// Convert the numbers to ints
int lvalInt = (int) lval;
if (lvalInt != lval) {
error(FRACTIONAL_BITWISE_OPERAND, left);
return n;
}
int rvalInt = (int) rval;
if (rvalInt != rval) {
error(FRACTIONAL_BITWISE_OPERAND, right);
return n;
}
switch (n.getType()) {
case Token.LSH:
result = lvalInt << rvalInt;
break;
case Token.RSH:
result = lvalInt >> rvalInt;
break;
case Token.URSH:
// JavaScript handles zero shifts on signed numbers differently than
// Java as an Java int can not represent the unsigned 32-bit number
// where JavaScript can so use a long here.
result = lvalInt >>> rvalInt;
break;
default:
throw new AssertionError("Unknown shift operator: " +
Node.tokenToName(n.getType()));
}
Node newNumber = Node.newNumber(result);
n.getParent().replaceChild(n, newNumber);
reportCodeChange();
return newNumber;
}
return n;
}
```
| private Node tryFoldShift(Node n, Node left, Node right) {
if (left.getType() == Token.NUMBER &&
right.getType() == Token.NUMBER) {
double result;
double lval = left.getDouble();
double rval = right.getDouble();
// check ranges. We do not do anything that would clip the double to
// a 32-bit range, since the user likely does not intend that.
if (!(lval >= Integer.MIN_VALUE && lval <= Integer.MAX_VALUE)) {
error(BITWISE_OPERAND_OUT_OF_RANGE, left);
return n;
}
// only the lower 5 bits are used when shifting, so don't do anything
// if the shift amount is outside [0,32)
if (!(rval >= 0 && rval < 32)) {
error(SHIFT_AMOUNT_OUT_OF_BOUNDS, right);
return n;
}
// Convert the numbers to ints
int lvalInt = (int) lval;
if (lvalInt != lval) {
error(FRACTIONAL_BITWISE_OPERAND, left);
return n;
}
int rvalInt = (int) rval;
if (rvalInt != rval) {
error(FRACTIONAL_BITWISE_OPERAND, right);
return n;
}
switch (n.getType()) {
case Token.LSH:
result = lvalInt << rvalInt;
break;
case Token.RSH:
result = lvalInt >> rvalInt;
break;
case Token.URSH:
// JavaScript handles zero shifts on signed numbers differently than
// Java as an Java int can not represent the unsigned 32-bit number
// where JavaScript can so use a long here.
result = lvalInt >>> rvalInt;
break;
default:
throw new AssertionError("Unknown shift operator: " +
Node.tokenToName(n.getType()));
}
Node newNumber = Node.newNumber(result);
n.getParent().replaceChild(n, newNumber);
reportCodeChange();
return newNumber;
}
return n;
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Try to fold shift operations
*/
private Node tryFoldShift(Node n, Node left, Node right) {
if (left.getType() == Token.NUMBER &&
right.getType() == Token.NUMBER) {
double result;
double lval = left.getDouble();
double rval = right.getDouble();
// check ranges. We do not do anything that would clip the double to
// a 32-bit range, since the user likely does not intend that.
if (!(lval >= Integer.MIN_VALUE && lval <= Integer.MAX_VALUE)) {
error(BITWISE_OPERAND_OUT_OF_RANGE, left);
return n;
}
// only the lower 5 bits are used when shifting, so don't do anything
// if the shift amount is outside [0,32)
if (!(rval >= 0 && rval < 32)) {
error(SHIFT_AMOUNT_OUT_OF_BOUNDS, right);
return n;
}
// Convert the numbers to ints
int lvalInt = (int) lval;
if (lvalInt != lval) {
error(FRACTIONAL_BITWISE_OPERAND, left);
return n;
}
int rvalInt = (int) rval;
if (rvalInt != rval) {
error(FRACTIONAL_BITWISE_OPERAND, right);
return n;
}
switch (n.getType()) {
case Token.LSH:
result = lvalInt << rvalInt;
break;
case Token.RSH:
result = lvalInt >> rvalInt;
break;
case Token.URSH:
// JavaScript handles zero shifts on signed numbers differently than
// Java as an Java int can not represent the unsigned 32-bit number
// where JavaScript can so use a long here.
result = lvalInt >>> rvalInt;
break;
default:
throw new AssertionError("Unknown shift operator: " +
Node.tokenToName(n.getType()));
}
Node newNumber = Node.newNumber(result);
n.getParent().replaceChild(n, newNumber);
reportCodeChange();
return newNumber;
}
return n;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
40 | 406c05b04f33e28b8ee3c630b3b640bdec14a66e5482fc528e29ca80e80cb8bd | public DocumentType(String name, String publicId, String systemId, String baseUri) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Create a new doctype element.
* @param name the doctype's name
* @param publicId the doctype's public ID
* @param systemId the doctype's system ID
* @param baseUri the doctype's base URI
*/
// todo: quirk mode from publicId and systemId
public DocumentType(String name, String publicId, String systemId, String baseUri) {
super(baseUri);
attr("name", name);
attr("publicId", publicId);
attr("systemId", systemId);
}
```
| public DocumentType(String name, String publicId, String systemId, String baseUri) {
super(baseUri);
attr("name", name);
attr("publicId", publicId);
attr("systemId", systemId);
} | false | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Create a new doctype element.
* @param name the doctype's name
* @param publicId the doctype's public ID
* @param systemId the doctype's system ID
* @param baseUri the doctype's base URI
*/
// todo: quirk mode from publicId and systemId
public DocumentType(String name, String publicId, String systemId, String baseUri) {
super(baseUri);
attr("name", name);
attr("publicId", publicId);
attr("systemId", systemId);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
94 | 406c15f03dccaedac47ca63490706e88e47cfe2b522c630517c44cf0f7203e1e | public static int gcd(int u, int v) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>
* Gets the greatest common divisor of the absolute value of two numbers,
* using the "binary gcd" method which avoids division and modulo
* operations. See Knuth 4.5.2 algorithm B. This algorithm is due to Josef
* Stein (1961).
* </p>
*
* @param u a non-zero number
* @param v a non-zero number
* @return the greatest common divisor, never zero
* @since 1.1
*/
public static int gcd(int u, int v) {
if ((u == 0) || (v == 0)) {
return (Math.abs(u) + Math.abs(v));
}
// keep u and v negative, as negative integers range down to
// -2^31, while positive numbers can only be as large as 2^31-1
// (i.e. we can't necessarily negate a negative number without
// overflow)
/* assert u!=0 && v!=0; */
if (u > 0) {
u = -u;
} // make u negative
if (v > 0) {
v = -v;
} // make v negative
// B1. [Find power of 2]
int k = 0;
while ((u & 1) == 0 && (v & 1) == 0 && k < 31) { // while u and v are
// both even...
u /= 2;
v /= 2;
k++; // cast out twos.
}
if (k == 31) {
throw new ArithmeticException("overflow: gcd is 2^31");
}
// B2. Initialize: u and v have been divided by 2^k and at least
// one is odd.
int t = ((u & 1) == 1) ? v : -(u / 2)/* B3 */;
// t negative: u was odd, v may be even (t replaces v)
// t positive: u was even, v is odd (t replaces u)
do {
/* assert u<0 && v<0; */
// B4/B3: cast out twos from t.
while ((t & 1) == 0) { // while t is even..
t /= 2; // cast out twos
}
// B5 [reset max(u,v)]
if (t > 0) {
u = -t;
} else {
v = t;
}
// B6/B3. at this point both u and v should be odd.
t = (v - u) / 2;
// |u| larger: t positive (replace u)
// |v| larger: t negative (replace v)
} while (t != 0);
return -u * (1 << k); // gcd is u*2^k
}
```
| public static int gcd(int u, int v) {
if ((u == 0) || (v == 0)) {
return (Math.abs(u) + Math.abs(v));
}
// keep u and v negative, as negative integers range down to
// -2^31, while positive numbers can only be as large as 2^31-1
// (i.e. we can't necessarily negate a negative number without
// overflow)
/* assert u!=0 && v!=0; */
if (u > 0) {
u = -u;
} // make u negative
if (v > 0) {
v = -v;
} // make v negative
// B1. [Find power of 2]
int k = 0;
while ((u & 1) == 0 && (v & 1) == 0 && k < 31) { // while u and v are
// both even...
u /= 2;
v /= 2;
k++; // cast out twos.
}
if (k == 31) {
throw new ArithmeticException("overflow: gcd is 2^31");
}
// B2. Initialize: u and v have been divided by 2^k and at least
// one is odd.
int t = ((u & 1) == 1) ? v : -(u / 2)/* B3 */;
// t negative: u was odd, v may be even (t replaces v)
// t positive: u was even, v is odd (t replaces u)
do {
/* assert u<0 && v<0; */
// B4/B3: cast out twos from t.
while ((t & 1) == 0) { // while t is even..
t /= 2; // cast out twos
}
// B5 [reset max(u,v)]
if (t > 0) {
u = -t;
} else {
v = t;
}
// B6/B3. at this point both u and v should be odd.
t = (v - u) / 2;
// |u| larger: t positive (replace u)
// |v| larger: t negative (replace v)
} while (t != 0);
return -u * (1 << k); // gcd is u*2^k
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>
* Gets the greatest common divisor of the absolute value of two numbers,
* using the "binary gcd" method which avoids division and modulo
* operations. See Knuth 4.5.2 algorithm B. This algorithm is due to Josef
* Stein (1961).
* </p>
*
* @param u a non-zero number
* @param v a non-zero number
* @return the greatest common divisor, never zero
* @since 1.1
*/
public static int gcd(int u, int v) {
if ((u == 0) || (v == 0)) {
return (Math.abs(u) + Math.abs(v));
}
// keep u and v negative, as negative integers range down to
// -2^31, while positive numbers can only be as large as 2^31-1
// (i.e. we can't necessarily negate a negative number without
// overflow)
/* assert u!=0 && v!=0; */
if (u > 0) {
u = -u;
} // make u negative
if (v > 0) {
v = -v;
} // make v negative
// B1. [Find power of 2]
int k = 0;
while ((u & 1) == 0 && (v & 1) == 0 && k < 31) { // while u and v are
// both even...
u /= 2;
v /= 2;
k++; // cast out twos.
}
if (k == 31) {
throw new ArithmeticException("overflow: gcd is 2^31");
}
// B2. Initialize: u and v have been divided by 2^k and at least
// one is odd.
int t = ((u & 1) == 1) ? v : -(u / 2)/* B3 */;
// t negative: u was odd, v may be even (t replaces v)
// t positive: u was even, v is odd (t replaces u)
do {
/* assert u<0 && v<0; */
// B4/B3: cast out twos from t.
while ((t & 1) == 0) { // while t is even..
t /= 2; // cast out twos
}
// B5 [reset max(u,v)]
if (t > 0) {
u = -t;
} else {
v = t;
}
// B6/B3. at this point both u and v should be odd.
t = (v - u) / 2;
// |u| larger: t positive (replace u)
// |v| larger: t negative (replace v)
} while (t != 0);
return -u * (1 << k); // gcd is u*2^k
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
117 | 4074b7be07ba56fb3229ac9e1566b973dfc791c702dd572e1b5a76434d803fa3 | String getReadableJSTypeName(Node n, boolean dereference) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Given a node, get a human-readable name for the type of that node so
* that will be easy for the programmer to find the original declaration.
*
* For example, if SubFoo's property "bar" might have the human-readable
* name "Foo.prototype.bar".
*
* @param n The node.
* @param dereference If true, the type of the node will be dereferenced
* to an Object type, if possible.
*/
String getReadableJSTypeName(Node n, boolean dereference) {
// The best type name is the actual type name.
// If we're analyzing a GETPROP, the property may be inherited by the
// prototype chain. So climb the prototype chain and find out where
// the property was originally defined.
if (n.isGetProp()) {
ObjectType objectType = getJSType(n.getFirstChild()).dereference();
if (objectType != null) {
String propName = n.getLastChild().getString();
if (objectType.getConstructor() != null &&
objectType.getConstructor().isInterface()) {
objectType = FunctionType.getTopDefiningInterface(
objectType, propName);
} else {
// classes
while (objectType != null && !objectType.hasOwnProperty(propName)) {
objectType = objectType.getImplicitPrototype();
}
}
// Don't show complex function names or anonymous types.
// Instead, try to get a human-readable type name.
if (objectType != null &&
(objectType.getConstructor() != null ||
objectType.isFunctionPrototypeType())) {
return objectType.toString() + "." + propName;
}
}
}
JSType type = getJSType(n);
if (dereference) {
ObjectType dereferenced = type.dereference();
if (dereferenced != null) {
type = dereferenced;
}
}
if (type.isFunctionPrototypeType() ||
(type.toObjectType() != null &&
type.toObjectType().getConstructor() != null)) {
return type.toString();
}
String qualifiedName = n.getQualifiedName();
if (qualifiedName != null) {
return qualifiedName;
} else if (type.isFunctionType()) {
// Don't show complex function names.
return "function";
} else {
return type.toString();
}
}
```
| String getReadableJSTypeName(Node n, boolean dereference) {
// The best type name is the actual type name.
// If we're analyzing a GETPROP, the property may be inherited by the
// prototype chain. So climb the prototype chain and find out where
// the property was originally defined.
if (n.isGetProp()) {
ObjectType objectType = getJSType(n.getFirstChild()).dereference();
if (objectType != null) {
String propName = n.getLastChild().getString();
if (objectType.getConstructor() != null &&
objectType.getConstructor().isInterface()) {
objectType = FunctionType.getTopDefiningInterface(
objectType, propName);
} else {
// classes
while (objectType != null && !objectType.hasOwnProperty(propName)) {
objectType = objectType.getImplicitPrototype();
}
}
// Don't show complex function names or anonymous types.
// Instead, try to get a human-readable type name.
if (objectType != null &&
(objectType.getConstructor() != null ||
objectType.isFunctionPrototypeType())) {
return objectType.toString() + "." + propName;
}
}
}
JSType type = getJSType(n);
if (dereference) {
ObjectType dereferenced = type.dereference();
if (dereferenced != null) {
type = dereferenced;
}
}
if (type.isFunctionPrototypeType() ||
(type.toObjectType() != null &&
type.toObjectType().getConstructor() != null)) {
return type.toString();
}
String qualifiedName = n.getQualifiedName();
if (qualifiedName != null) {
return qualifiedName;
} else if (type.isFunctionType()) {
// Don't show complex function names.
return "function";
} else {
return type.toString();
}
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Given a node, get a human-readable name for the type of that node so
* that will be easy for the programmer to find the original declaration.
*
* For example, if SubFoo's property "bar" might have the human-readable
* name "Foo.prototype.bar".
*
* @param n The node.
* @param dereference If true, the type of the node will be dereferenced
* to an Object type, if possible.
*/
String getReadableJSTypeName(Node n, boolean dereference) {
// The best type name is the actual type name.
// If we're analyzing a GETPROP, the property may be inherited by the
// prototype chain. So climb the prototype chain and find out where
// the property was originally defined.
if (n.isGetProp()) {
ObjectType objectType = getJSType(n.getFirstChild()).dereference();
if (objectType != null) {
String propName = n.getLastChild().getString();
if (objectType.getConstructor() != null &&
objectType.getConstructor().isInterface()) {
objectType = FunctionType.getTopDefiningInterface(
objectType, propName);
} else {
// classes
while (objectType != null && !objectType.hasOwnProperty(propName)) {
objectType = objectType.getImplicitPrototype();
}
}
// Don't show complex function names or anonymous types.
// Instead, try to get a human-readable type name.
if (objectType != null &&
(objectType.getConstructor() != null ||
objectType.isFunctionPrototypeType())) {
return objectType.toString() + "." + propName;
}
}
}
JSType type = getJSType(n);
if (dereference) {
ObjectType dereferenced = type.dereference();
if (dereferenced != null) {
type = dereferenced;
}
}
if (type.isFunctionPrototypeType() ||
(type.toObjectType() != null &&
type.toObjectType().getConstructor() != null)) {
return type.toString();
}
String qualifiedName = n.getQualifiedName();
if (qualifiedName != null) {
return qualifiedName;
} else if (type.isFunctionType()) {
// Don't show complex function names.
return "function";
} else {
return type.toString();
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
54 | 40a2f9f34fd784168f28f558314ea7a5fe946eff2887e6f900ee3c4abfa425cf | public static Locale toLocale(String str) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Converts a String to a Locale.</p>
*
* <p>This method takes the string format of a locale and creates the
* locale object from it.</p>
*
* <pre>
* LocaleUtils.toLocale("en") = new Locale("en", "")
* LocaleUtils.toLocale("en_GB") = new Locale("en", "GB")
* LocaleUtils.toLocale("en_GB_xxx") = new Locale("en", "GB", "xxx") (#)
* </pre>
*
* <p>(#) The behaviour of the JDK variant constructor changed between JDK1.3 and JDK1.4.
* In JDK1.3, the constructor upper cases the variant, in JDK1.4, it doesn't.
* Thus, the result from getVariant() may vary depending on your JDK.</p>
*
* <p>This method validates the input strictly.
* The language code must be lowercase.
* The country code must be uppercase.
* The separator must be an underscore.
* The length must be correct.
* </p>
*
* @param str the locale String to convert, null returns null
* @return a Locale, null if null input
* @throws IllegalArgumentException if the string is an invalid format
*/
//-----------------------------------------------------------------------
public static Locale toLocale(String str) {
if (str == null) {
return null;
}
int len = str.length();
if (len != 2 && len != 5 && len < 7) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
char ch0 = str.charAt(0);
char ch1 = str.charAt(1);
if (ch0 < 'a' || ch0 > 'z' || ch1 < 'a' || ch1 > 'z') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (len == 2) {
return new Locale(str, "");
} else {
if (str.charAt(2) != '_') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
char ch3 = str.charAt(3);
char ch4 = str.charAt(4);
if (ch3 < 'A' || ch3 > 'Z' || ch4 < 'A' || ch4 > 'Z') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (len == 5) {
return new Locale(str.substring(0, 2), str.substring(3, 5));
} else {
if (str.charAt(5) != '_') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
return new Locale(str.substring(0, 2), str.substring(3, 5), str.substring(6));
}
}
}
```
| public static Locale toLocale(String str) {
if (str == null) {
return null;
}
int len = str.length();
if (len != 2 && len != 5 && len < 7) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
char ch0 = str.charAt(0);
char ch1 = str.charAt(1);
if (ch0 < 'a' || ch0 > 'z' || ch1 < 'a' || ch1 > 'z') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (len == 2) {
return new Locale(str, "");
} else {
if (str.charAt(2) != '_') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
char ch3 = str.charAt(3);
char ch4 = str.charAt(4);
if (ch3 < 'A' || ch3 > 'Z' || ch4 < 'A' || ch4 > 'Z') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (len == 5) {
return new Locale(str.substring(0, 2), str.substring(3, 5));
} else {
if (str.charAt(5) != '_') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
return new Locale(str.substring(0, 2), str.substring(3, 5), str.substring(6));
}
}
} | true | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Converts a String to a Locale.</p>
*
* <p>This method takes the string format of a locale and creates the
* locale object from it.</p>
*
* <pre>
* LocaleUtils.toLocale("en") = new Locale("en", "")
* LocaleUtils.toLocale("en_GB") = new Locale("en", "GB")
* LocaleUtils.toLocale("en_GB_xxx") = new Locale("en", "GB", "xxx") (#)
* </pre>
*
* <p>(#) The behaviour of the JDK variant constructor changed between JDK1.3 and JDK1.4.
* In JDK1.3, the constructor upper cases the variant, in JDK1.4, it doesn't.
* Thus, the result from getVariant() may vary depending on your JDK.</p>
*
* <p>This method validates the input strictly.
* The language code must be lowercase.
* The country code must be uppercase.
* The separator must be an underscore.
* The length must be correct.
* </p>
*
* @param str the locale String to convert, null returns null
* @return a Locale, null if null input
* @throws IllegalArgumentException if the string is an invalid format
*/
//-----------------------------------------------------------------------
public static Locale toLocale(String str) {
if (str == null) {
return null;
}
int len = str.length();
if (len != 2 && len != 5 && len < 7) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
char ch0 = str.charAt(0);
char ch1 = str.charAt(1);
if (ch0 < 'a' || ch0 > 'z' || ch1 < 'a' || ch1 > 'z') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (len == 2) {
return new Locale(str, "");
} else {
if (str.charAt(2) != '_') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
char ch3 = str.charAt(3);
char ch4 = str.charAt(4);
if (ch3 < 'A' || ch3 > 'Z' || ch4 < 'A' || ch4 > 'Z') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (len == 5) {
return new Locale(str.substring(0, 2), str.substring(3, 5));
} else {
if (str.charAt(5) != '_') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
return new Locale(str.substring(0, 2), str.substring(3, 5), str.substring(6));
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
50 | 418c7d2ef63355c694a4e9b5a5b52ce48aa9ef49b802d315d49c1e3c80ec055e | protected final double doSolve() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/** {@inheritDoc} */
protected final double doSolve() {
// Get initial solution
double x0 = getMin();
double x1 = getMax();
double f0 = computeObjectiveValue(x0);
double f1 = computeObjectiveValue(x1);
// If one of the bounds is the exact root, return it. Since these are
// not under-approximations or over-approximations, we can return them
// regardless of the allowed solutions.
if (f0 == 0.0) {
return x0;
}
if (f1 == 0.0) {
return x1;
}
// Verify bracketing of initial solution.
verifyBracketing(x0, x1);
// Get accuracies.
final double ftol = getFunctionValueAccuracy();
final double atol = getAbsoluteAccuracy();
final double rtol = getRelativeAccuracy();
// Keep track of inverted intervals, meaning that the left bound is
// larger than the right bound.
boolean inverted = false;
// Keep finding better approximations.
while (true) {
// Calculate the next approximation.
final double x = x1 - ((f1 * (x1 - x0)) / (f1 - f0));
final double fx = computeObjectiveValue(x);
// If the new approximation is the exact root, return it. Since
// this is not an under-approximation or an over-approximation,
// we can return it regardless of the allowed solutions.
if (fx == 0.0) {
return x;
}
// Update the bounds with the new approximation.
if (f1 * fx < 0) {
// The value of x1 has switched to the other bound, thus inverting
// the interval.
x0 = x1;
f0 = f1;
inverted = !inverted;
} else {
switch (method) {
case ILLINOIS:
f0 *= 0.5;
break;
case PEGASUS:
f0 *= f1 / (f1 + fx);
break;
case REGULA_FALSI:
// Nothing.
break;
default:
// Should never happen.
throw new MathInternalError();
}
}
// Update from [x0, x1] to [x0, x].
x1 = x;
f1 = fx;
// If the function value of the last approximation is too small,
// given the function value accuracy, then we can't get closer to
// the root than we already are.
if (FastMath.abs(f1) <= ftol) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
if (inverted) {
return x1;
}
break;
case RIGHT_SIDE:
if (!inverted) {
return x1;
}
break;
case BELOW_SIDE:
if (f1 <= 0) {
return x1;
}
break;
case ABOVE_SIDE:
if (f1 >= 0) {
return x1;
}
break;
default:
throw new MathInternalError();
}
}
// If the current interval is within the given accuracies, we
// are satisfied with the current approximation.
if (FastMath.abs(x1 - x0) < FastMath.max(rtol * FastMath.abs(x1),
atol)) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
return inverted ? x1 : x0;
case RIGHT_SIDE:
return inverted ? x0 : x1;
case BELOW_SIDE:
return (f1 <= 0) ? x1 : x0;
case ABOVE_SIDE:
return (f1 >= 0) ? x1 : x0;
default:
throw new MathInternalError();
}
}
}
}
```
| protected final double doSolve() {
// Get initial solution
double x0 = getMin();
double x1 = getMax();
double f0 = computeObjectiveValue(x0);
double f1 = computeObjectiveValue(x1);
// If one of the bounds is the exact root, return it. Since these are
// not under-approximations or over-approximations, we can return them
// regardless of the allowed solutions.
if (f0 == 0.0) {
return x0;
}
if (f1 == 0.0) {
return x1;
}
// Verify bracketing of initial solution.
verifyBracketing(x0, x1);
// Get accuracies.
final double ftol = getFunctionValueAccuracy();
final double atol = getAbsoluteAccuracy();
final double rtol = getRelativeAccuracy();
// Keep track of inverted intervals, meaning that the left bound is
// larger than the right bound.
boolean inverted = false;
// Keep finding better approximations.
while (true) {
// Calculate the next approximation.
final double x = x1 - ((f1 * (x1 - x0)) / (f1 - f0));
final double fx = computeObjectiveValue(x);
// If the new approximation is the exact root, return it. Since
// this is not an under-approximation or an over-approximation,
// we can return it regardless of the allowed solutions.
if (fx == 0.0) {
return x;
}
// Update the bounds with the new approximation.
if (f1 * fx < 0) {
// The value of x1 has switched to the other bound, thus inverting
// the interval.
x0 = x1;
f0 = f1;
inverted = !inverted;
} else {
switch (method) {
case ILLINOIS:
f0 *= 0.5;
break;
case PEGASUS:
f0 *= f1 / (f1 + fx);
break;
case REGULA_FALSI:
// Nothing.
break;
default:
// Should never happen.
throw new MathInternalError();
}
}
// Update from [x0, x1] to [x0, x].
x1 = x;
f1 = fx;
// If the function value of the last approximation is too small,
// given the function value accuracy, then we can't get closer to
// the root than we already are.
if (FastMath.abs(f1) <= ftol) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
if (inverted) {
return x1;
}
break;
case RIGHT_SIDE:
if (!inverted) {
return x1;
}
break;
case BELOW_SIDE:
if (f1 <= 0) {
return x1;
}
break;
case ABOVE_SIDE:
if (f1 >= 0) {
return x1;
}
break;
default:
throw new MathInternalError();
}
}
// If the current interval is within the given accuracies, we
// are satisfied with the current approximation.
if (FastMath.abs(x1 - x0) < FastMath.max(rtol * FastMath.abs(x1),
atol)) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
return inverted ? x1 : x0;
case RIGHT_SIDE:
return inverted ? x0 : x1;
case BELOW_SIDE:
return (f1 <= 0) ? x1 : x0;
case ABOVE_SIDE:
return (f1 >= 0) ? x1 : x0;
default:
throw new MathInternalError();
}
}
}
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/** {@inheritDoc} */
protected final double doSolve() {
// Get initial solution
double x0 = getMin();
double x1 = getMax();
double f0 = computeObjectiveValue(x0);
double f1 = computeObjectiveValue(x1);
// If one of the bounds is the exact root, return it. Since these are
// not under-approximations or over-approximations, we can return them
// regardless of the allowed solutions.
if (f0 == 0.0) {
return x0;
}
if (f1 == 0.0) {
return x1;
}
// Verify bracketing of initial solution.
verifyBracketing(x0, x1);
// Get accuracies.
final double ftol = getFunctionValueAccuracy();
final double atol = getAbsoluteAccuracy();
final double rtol = getRelativeAccuracy();
// Keep track of inverted intervals, meaning that the left bound is
// larger than the right bound.
boolean inverted = false;
// Keep finding better approximations.
while (true) {
// Calculate the next approximation.
final double x = x1 - ((f1 * (x1 - x0)) / (f1 - f0));
final double fx = computeObjectiveValue(x);
// If the new approximation is the exact root, return it. Since
// this is not an under-approximation or an over-approximation,
// we can return it regardless of the allowed solutions.
if (fx == 0.0) {
return x;
}
// Update the bounds with the new approximation.
if (f1 * fx < 0) {
// The value of x1 has switched to the other bound, thus inverting
// the interval.
x0 = x1;
f0 = f1;
inverted = !inverted;
} else {
switch (method) {
case ILLINOIS:
f0 *= 0.5;
break;
case PEGASUS:
f0 *= f1 / (f1 + fx);
break;
case REGULA_FALSI:
// Nothing.
break;
default:
// Should never happen.
throw new MathInternalError();
}
}
// Update from [x0, x1] to [x0, x].
x1 = x;
f1 = fx;
// If the function value of the last approximation is too small,
// given the function value accuracy, then we can't get closer to
// the root than we already are.
if (FastMath.abs(f1) <= ftol) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
if (inverted) {
return x1;
}
break;
case RIGHT_SIDE:
if (!inverted) {
return x1;
}
break;
case BELOW_SIDE:
if (f1 <= 0) {
return x1;
}
break;
case ABOVE_SIDE:
if (f1 >= 0) {
return x1;
}
break;
default:
throw new MathInternalError();
}
}
// If the current interval is within the given accuracies, we
// are satisfied with the current approximation.
if (FastMath.abs(x1 - x0) < FastMath.max(rtol * FastMath.abs(x1),
atol)) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
return inverted ? x1 : x0;
case RIGHT_SIDE:
return inverted ? x0 : x1;
case BELOW_SIDE:
return (f1 <= 0) ? x1 : x0;
case ABOVE_SIDE:
return (f1 >= 0) ? x1 : x0;
default:
throw new MathInternalError();
}
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
40 | 418ef3a199e373b2b12820c00bc89e6fdc421eaaa9d98266d9bb8c5fcbe53bfd | @Override
protected double doSolve() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* {@inheritDoc}
*/
@Override
protected double doSolve() {
// prepare arrays with the first points
final double[] x = new double[maximalOrder + 1];
final double[] y = new double[maximalOrder + 1];
x[0] = getMin();
x[1] = getStartValue();
x[2] = getMax();
verifySequence(x[0], x[1], x[2]);
// evaluate initial guess
y[1] = computeObjectiveValue(x[1]);
if (Precision.equals(y[1], 0.0, 1)) {
// return the initial guess if it is a perfect root.
return x[1];
}
// evaluate first endpoint
y[0] = computeObjectiveValue(x[0]);
if (Precision.equals(y[0], 0.0, 1)) {
// return the first endpoint if it is a perfect root.
return x[0];
}
int nbPoints;
int signChangeIndex;
if (y[0] * y[1] < 0) {
// reduce interval if it brackets the root
nbPoints = 2;
signChangeIndex = 1;
} else {
// evaluate second endpoint
y[2] = computeObjectiveValue(x[2]);
if (Precision.equals(y[2], 0.0, 1)) {
// return the second endpoint if it is a perfect root.
return x[2];
}
if (y[1] * y[2] < 0) {
// use all computed point as a start sampling array for solving
nbPoints = 3;
signChangeIndex = 2;
} else {
throw new NoBracketingException(x[0], x[2], y[0], y[2]);
}
}
// prepare a work array for inverse polynomial interpolation
final double[] tmpX = new double[x.length];
// current tightest bracketing of the root
double xA = x[signChangeIndex - 1];
double yA = y[signChangeIndex - 1];
double absYA = FastMath.abs(yA);
int agingA = 0;
double xB = x[signChangeIndex];
double yB = y[signChangeIndex];
double absYB = FastMath.abs(yB);
int agingB = 0;
// search loop
while (true) {
// check convergence of bracketing interval
final double xTol = getAbsoluteAccuracy() +
getRelativeAccuracy() * FastMath.max(FastMath.abs(xA), FastMath.abs(xB));
if (((xB - xA) <= xTol) || (FastMath.max(absYA, absYB) < getFunctionValueAccuracy())) {
switch (allowed) {
case ANY_SIDE :
return absYA < absYB ? xA : xB;
case LEFT_SIDE :
return xA;
case RIGHT_SIDE :
return xB;
case BELOW_SIDE :
return (yA <= 0) ? xA : xB;
case ABOVE_SIDE :
return (yA < 0) ? xB : xA;
default :
// this should never happen
throw new MathInternalError(null);
}
}
// target for the next evaluation point
double targetY;
if (agingA >= MAXIMAL_AGING) {
// we keep updating the high bracket, try to compensate this
targetY = -REDUCTION_FACTOR * yB;
} else if (agingB >= MAXIMAL_AGING) {
// we keep updating the low bracket, try to compensate this
targetY = -REDUCTION_FACTOR * yA;
} else {
// bracketing is balanced, try to find the root itself
targetY = 0;
}
// make a few attempts to guess a root,
double nextX;
int start = 0;
int end = nbPoints;
do {
// guess a value for current target, using inverse polynomial interpolation
System.arraycopy(x, start, tmpX, start, end - start);
nextX = guessX(targetY, tmpX, y, start, end);
if (!((nextX > xA) && (nextX < xB))) {
// the guessed root is not strictly inside of the tightest bracketing interval
// the guessed root is either not strictly inside the interval or it
// is a NaN (which occurs when some sampling points share the same y)
// we try again with a lower interpolation order
if (signChangeIndex - start >= end - signChangeIndex) {
// we have more points before the sign change, drop the lowest point
++start;
} else {
// we have more points after sign change, drop the highest point
--end;
}
// we need to do one more attempt
nextX = Double.NaN;
}
} while (Double.isNaN(nextX) && (end - start > 1));
if (Double.isNaN(nextX)) {
// fall back to bisection
nextX = xA + 0.5 * (xB - xA);
start = signChangeIndex - 1;
end = signChangeIndex;
}
// evaluate the function at the guessed root
final double nextY = computeObjectiveValue(nextX);
if (Precision.equals(nextY, 0.0, 1)) {
// we have found an exact root, since it is not an approximation
// we don't need to bother about the allowed solutions setting
return nextX;
}
if ((nbPoints > 2) && (end - start != nbPoints)) {
// we have been forced to ignore some points to keep bracketing,
// they are probably too far from the root, drop them from now on
nbPoints = end - start;
System.arraycopy(x, start, x, 0, nbPoints);
System.arraycopy(y, start, y, 0, nbPoints);
signChangeIndex -= start;
} else if (nbPoints == x.length) {
// we have to drop one point in order to insert the new one
nbPoints--;
// keep the tightest bracketing interval as centered as possible
if (signChangeIndex >= (x.length + 1) / 2) {
// we drop the lowest point, we have to shift the arrays and the index
System.arraycopy(x, 1, x, 0, nbPoints);
System.arraycopy(y, 1, y, 0, nbPoints);
--signChangeIndex;
}
}
// insert the last computed point
//(by construction, we know it lies inside the tightest bracketing interval)
System.arraycopy(x, signChangeIndex, x, signChangeIndex + 1, nbPoints - signChangeIndex);
x[signChangeIndex] = nextX;
System.arraycopy(y, signChangeIndex, y, signChangeIndex + 1, nbPoints - signChangeIndex);
y[signChangeIndex] = nextY;
++nbPoints;
// update the bracketing interval
if (nextY * yA <= 0) {
// the sign change occurs before the inserted point
xB = nextX;
yB = nextY;
absYB = FastMath.abs(yB);
++agingA;
agingB = 0;
} else {
// the sign change occurs after the inserted point
xA = nextX;
yA = nextY;
absYA = FastMath.abs(yA);
agingA = 0;
++agingB;
// update the sign change index
signChangeIndex++;
}
}
}
```
| @Override
protected double doSolve() {
// prepare arrays with the first points
final double[] x = new double[maximalOrder + 1];
final double[] y = new double[maximalOrder + 1];
x[0] = getMin();
x[1] = getStartValue();
x[2] = getMax();
verifySequence(x[0], x[1], x[2]);
// evaluate initial guess
y[1] = computeObjectiveValue(x[1]);
if (Precision.equals(y[1], 0.0, 1)) {
// return the initial guess if it is a perfect root.
return x[1];
}
// evaluate first endpoint
y[0] = computeObjectiveValue(x[0]);
if (Precision.equals(y[0], 0.0, 1)) {
// return the first endpoint if it is a perfect root.
return x[0];
}
int nbPoints;
int signChangeIndex;
if (y[0] * y[1] < 0) {
// reduce interval if it brackets the root
nbPoints = 2;
signChangeIndex = 1;
} else {
// evaluate second endpoint
y[2] = computeObjectiveValue(x[2]);
if (Precision.equals(y[2], 0.0, 1)) {
// return the second endpoint if it is a perfect root.
return x[2];
}
if (y[1] * y[2] < 0) {
// use all computed point as a start sampling array for solving
nbPoints = 3;
signChangeIndex = 2;
} else {
throw new NoBracketingException(x[0], x[2], y[0], y[2]);
}
}
// prepare a work array for inverse polynomial interpolation
final double[] tmpX = new double[x.length];
// current tightest bracketing of the root
double xA = x[signChangeIndex - 1];
double yA = y[signChangeIndex - 1];
double absYA = FastMath.abs(yA);
int agingA = 0;
double xB = x[signChangeIndex];
double yB = y[signChangeIndex];
double absYB = FastMath.abs(yB);
int agingB = 0;
// search loop
while (true) {
// check convergence of bracketing interval
final double xTol = getAbsoluteAccuracy() +
getRelativeAccuracy() * FastMath.max(FastMath.abs(xA), FastMath.abs(xB));
if (((xB - xA) <= xTol) || (FastMath.max(absYA, absYB) < getFunctionValueAccuracy())) {
switch (allowed) {
case ANY_SIDE :
return absYA < absYB ? xA : xB;
case LEFT_SIDE :
return xA;
case RIGHT_SIDE :
return xB;
case BELOW_SIDE :
return (yA <= 0) ? xA : xB;
case ABOVE_SIDE :
return (yA < 0) ? xB : xA;
default :
// this should never happen
throw new MathInternalError(null);
}
}
// target for the next evaluation point
double targetY;
if (agingA >= MAXIMAL_AGING) {
// we keep updating the high bracket, try to compensate this
targetY = -REDUCTION_FACTOR * yB;
} else if (agingB >= MAXIMAL_AGING) {
// we keep updating the low bracket, try to compensate this
targetY = -REDUCTION_FACTOR * yA;
} else {
// bracketing is balanced, try to find the root itself
targetY = 0;
}
// make a few attempts to guess a root,
double nextX;
int start = 0;
int end = nbPoints;
do {
// guess a value for current target, using inverse polynomial interpolation
System.arraycopy(x, start, tmpX, start, end - start);
nextX = guessX(targetY, tmpX, y, start, end);
if (!((nextX > xA) && (nextX < xB))) {
// the guessed root is not strictly inside of the tightest bracketing interval
// the guessed root is either not strictly inside the interval or it
// is a NaN (which occurs when some sampling points share the same y)
// we try again with a lower interpolation order
if (signChangeIndex - start >= end - signChangeIndex) {
// we have more points before the sign change, drop the lowest point
++start;
} else {
// we have more points after sign change, drop the highest point
--end;
}
// we need to do one more attempt
nextX = Double.NaN;
}
} while (Double.isNaN(nextX) && (end - start > 1));
if (Double.isNaN(nextX)) {
// fall back to bisection
nextX = xA + 0.5 * (xB - xA);
start = signChangeIndex - 1;
end = signChangeIndex;
}
// evaluate the function at the guessed root
final double nextY = computeObjectiveValue(nextX);
if (Precision.equals(nextY, 0.0, 1)) {
// we have found an exact root, since it is not an approximation
// we don't need to bother about the allowed solutions setting
return nextX;
}
if ((nbPoints > 2) && (end - start != nbPoints)) {
// we have been forced to ignore some points to keep bracketing,
// they are probably too far from the root, drop them from now on
nbPoints = end - start;
System.arraycopy(x, start, x, 0, nbPoints);
System.arraycopy(y, start, y, 0, nbPoints);
signChangeIndex -= start;
} else if (nbPoints == x.length) {
// we have to drop one point in order to insert the new one
nbPoints--;
// keep the tightest bracketing interval as centered as possible
if (signChangeIndex >= (x.length + 1) / 2) {
// we drop the lowest point, we have to shift the arrays and the index
System.arraycopy(x, 1, x, 0, nbPoints);
System.arraycopy(y, 1, y, 0, nbPoints);
--signChangeIndex;
}
}
// insert the last computed point
//(by construction, we know it lies inside the tightest bracketing interval)
System.arraycopy(x, signChangeIndex, x, signChangeIndex + 1, nbPoints - signChangeIndex);
x[signChangeIndex] = nextX;
System.arraycopy(y, signChangeIndex, y, signChangeIndex + 1, nbPoints - signChangeIndex);
y[signChangeIndex] = nextY;
++nbPoints;
// update the bracketing interval
if (nextY * yA <= 0) {
// the sign change occurs before the inserted point
xB = nextX;
yB = nextY;
absYB = FastMath.abs(yB);
++agingA;
agingB = 0;
} else {
// the sign change occurs after the inserted point
xA = nextX;
yA = nextY;
absYA = FastMath.abs(yA);
agingA = 0;
++agingB;
// update the sign change index
signChangeIndex++;
}
}
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* {@inheritDoc}
*/
@Override
protected double doSolve() {
// prepare arrays with the first points
final double[] x = new double[maximalOrder + 1];
final double[] y = new double[maximalOrder + 1];
x[0] = getMin();
x[1] = getStartValue();
x[2] = getMax();
verifySequence(x[0], x[1], x[2]);
// evaluate initial guess
y[1] = computeObjectiveValue(x[1]);
if (Precision.equals(y[1], 0.0, 1)) {
// return the initial guess if it is a perfect root.
return x[1];
}
// evaluate first endpoint
y[0] = computeObjectiveValue(x[0]);
if (Precision.equals(y[0], 0.0, 1)) {
// return the first endpoint if it is a perfect root.
return x[0];
}
int nbPoints;
int signChangeIndex;
if (y[0] * y[1] < 0) {
// reduce interval if it brackets the root
nbPoints = 2;
signChangeIndex = 1;
} else {
// evaluate second endpoint
y[2] = computeObjectiveValue(x[2]);
if (Precision.equals(y[2], 0.0, 1)) {
// return the second endpoint if it is a perfect root.
return x[2];
}
if (y[1] * y[2] < 0) {
// use all computed point as a start sampling array for solving
nbPoints = 3;
signChangeIndex = 2;
} else {
throw new NoBracketingException(x[0], x[2], y[0], y[2]);
}
}
// prepare a work array for inverse polynomial interpolation
final double[] tmpX = new double[x.length];
// current tightest bracketing of the root
double xA = x[signChangeIndex - 1];
double yA = y[signChangeIndex - 1];
double absYA = FastMath.abs(yA);
int agingA = 0;
double xB = x[signChangeIndex];
double yB = y[signChangeIndex];
double absYB = FastMath.abs(yB);
int agingB = 0;
// search loop
while (true) {
// check convergence of bracketing interval
final double xTol = getAbsoluteAccuracy() +
getRelativeAccuracy() * FastMath.max(FastMath.abs(xA), FastMath.abs(xB));
if (((xB - xA) <= xTol) || (FastMath.max(absYA, absYB) < getFunctionValueAccuracy())) {
switch (allowed) {
case ANY_SIDE :
return absYA < absYB ? xA : xB;
case LEFT_SIDE :
return xA;
case RIGHT_SIDE :
return xB;
case BELOW_SIDE :
return (yA <= 0) ? xA : xB;
case ABOVE_SIDE :
return (yA < 0) ? xB : xA;
default :
// this should never happen
throw new MathInternalError(null);
}
}
// target for the next evaluation point
double targetY;
if (agingA >= MAXIMAL_AGING) {
// we keep updating the high bracket, try to compensate this
targetY = -REDUCTION_FACTOR * yB;
} else if (agingB >= MAXIMAL_AGING) {
// we keep updating the low bracket, try to compensate this
targetY = -REDUCTION_FACTOR * yA;
} else {
// bracketing is balanced, try to find the root itself
targetY = 0;
}
// make a few attempts to guess a root,
double nextX;
int start = 0;
int end = nbPoints;
do {
// guess a value for current target, using inverse polynomial interpolation
System.arraycopy(x, start, tmpX, start, end - start);
nextX = guessX(targetY, tmpX, y, start, end);
if (!((nextX > xA) && (nextX < xB))) {
// the guessed root is not strictly inside of the tightest bracketing interval
// the guessed root is either not strictly inside the interval or it
// is a NaN (which occurs when some sampling points share the same y)
// we try again with a lower interpolation order
if (signChangeIndex - start >= end - signChangeIndex) {
// we have more points before the sign change, drop the lowest point
++start;
} else {
// we have more points after sign change, drop the highest point
--end;
}
// we need to do one more attempt
nextX = Double.NaN;
}
} while (Double.isNaN(nextX) && (end - start > 1));
if (Double.isNaN(nextX)) {
// fall back to bisection
nextX = xA + 0.5 * (xB - xA);
start = signChangeIndex - 1;
end = signChangeIndex;
}
// evaluate the function at the guessed root
final double nextY = computeObjectiveValue(nextX);
if (Precision.equals(nextY, 0.0, 1)) {
// we have found an exact root, since it is not an approximation
// we don't need to bother about the allowed solutions setting
return nextX;
}
if ((nbPoints > 2) && (end - start != nbPoints)) {
// we have been forced to ignore some points to keep bracketing,
// they are probably too far from the root, drop them from now on
nbPoints = end - start;
System.arraycopy(x, start, x, 0, nbPoints);
System.arraycopy(y, start, y, 0, nbPoints);
signChangeIndex -= start;
} else if (nbPoints == x.length) {
// we have to drop one point in order to insert the new one
nbPoints--;
// keep the tightest bracketing interval as centered as possible
if (signChangeIndex >= (x.length + 1) / 2) {
// we drop the lowest point, we have to shift the arrays and the index
System.arraycopy(x, 1, x, 0, nbPoints);
System.arraycopy(y, 1, y, 0, nbPoints);
--signChangeIndex;
}
}
// insert the last computed point
//(by construction, we know it lies inside the tightest bracketing interval)
System.arraycopy(x, signChangeIndex, x, signChangeIndex + 1, nbPoints - signChangeIndex);
x[signChangeIndex] = nextX;
System.arraycopy(y, signChangeIndex, y, signChangeIndex + 1, nbPoints - signChangeIndex);
y[signChangeIndex] = nextY;
++nbPoints;
// update the bracketing interval
if (nextY * yA <= 0) {
// the sign change occurs before the inserted point
xB = nextX;
yB = nextY;
absYB = FastMath.abs(yB);
++agingA;
agingB = 0;
} else {
// the sign change occurs after the inserted point
xA = nextX;
yA = nextY;
absYA = FastMath.abs(yA);
agingA = 0;
++agingB;
// update the sign change index
signChangeIndex++;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
4 | 420b3b682e0e313b6c4d9b0e8e0a19186f16ddd84734bd990f28f102c2a6a8df | public Range getDataRange(ValueAxis axis) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns the range for the specified axis.
*
* @param axis the axis.
*
* @return The range.
*/
public Range getDataRange(ValueAxis axis) {
Range result = null;
List mappedDatasets = new ArrayList();
List includedAnnotations = new ArrayList();
boolean isDomainAxis = true;
// is it a domain axis?
int domainIndex = getDomainAxisIndex(axis);
if (domainIndex >= 0) {
isDomainAxis = true;
mappedDatasets.addAll(getDatasetsMappedToDomainAxis(
new Integer(domainIndex)));
if (domainIndex == 0) {
// grab the plot's annotations
Iterator iterator = this.annotations.iterator();
while (iterator.hasNext()) {
XYAnnotation annotation = (XYAnnotation) iterator.next();
if (annotation instanceof XYAnnotationBoundsInfo) {
includedAnnotations.add(annotation);
}
}
}
}
// or is it a range axis?
int rangeIndex = getRangeAxisIndex(axis);
if (rangeIndex >= 0) {
isDomainAxis = false;
mappedDatasets.addAll(getDatasetsMappedToRangeAxis(
new Integer(rangeIndex)));
if (rangeIndex == 0) {
Iterator iterator = this.annotations.iterator();
while (iterator.hasNext()) {
XYAnnotation annotation = (XYAnnotation) iterator.next();
if (annotation instanceof XYAnnotationBoundsInfo) {
includedAnnotations.add(annotation);
}
}
}
}
// iterate through the datasets that map to the axis and get the union
// of the ranges.
Iterator iterator = mappedDatasets.iterator();
while (iterator.hasNext()) {
XYDataset d = (XYDataset) iterator.next();
if (d != null) {
XYItemRenderer r = getRendererForDataset(d);
if (isDomainAxis) {
if (r != null) {
result = Range.combine(result, r.findDomainBounds(d));
}
else {
result = Range.combine(result,
DatasetUtilities.findDomainBounds(d));
}
}
else {
if (r != null) {
result = Range.combine(result, r.findRangeBounds(d));
}
else {
result = Range.combine(result,
DatasetUtilities.findRangeBounds(d));
}
}
if (r != null) {
Collection c = r.getAnnotations();
Iterator i = c.iterator();
while (i.hasNext()) {
XYAnnotation a = (XYAnnotation) i.next();
if (a instanceof XYAnnotationBoundsInfo) {
includedAnnotations.add(a);
}
}
}
}
}
Iterator it = includedAnnotations.iterator();
while (it.hasNext()) {
XYAnnotationBoundsInfo xyabi = (XYAnnotationBoundsInfo) it.next();
if (xyabi.getIncludeInDataBounds()) {
if (isDomainAxis) {
result = Range.combine(result, xyabi.getXRange());
}
else {
result = Range.combine(result, xyabi.getYRange());
}
}
}
return result;
}
```
| public Range getDataRange(ValueAxis axis) {
Range result = null;
List mappedDatasets = new ArrayList();
List includedAnnotations = new ArrayList();
boolean isDomainAxis = true;
// is it a domain axis?
int domainIndex = getDomainAxisIndex(axis);
if (domainIndex >= 0) {
isDomainAxis = true;
mappedDatasets.addAll(getDatasetsMappedToDomainAxis(
new Integer(domainIndex)));
if (domainIndex == 0) {
// grab the plot's annotations
Iterator iterator = this.annotations.iterator();
while (iterator.hasNext()) {
XYAnnotation annotation = (XYAnnotation) iterator.next();
if (annotation instanceof XYAnnotationBoundsInfo) {
includedAnnotations.add(annotation);
}
}
}
}
// or is it a range axis?
int rangeIndex = getRangeAxisIndex(axis);
if (rangeIndex >= 0) {
isDomainAxis = false;
mappedDatasets.addAll(getDatasetsMappedToRangeAxis(
new Integer(rangeIndex)));
if (rangeIndex == 0) {
Iterator iterator = this.annotations.iterator();
while (iterator.hasNext()) {
XYAnnotation annotation = (XYAnnotation) iterator.next();
if (annotation instanceof XYAnnotationBoundsInfo) {
includedAnnotations.add(annotation);
}
}
}
}
// iterate through the datasets that map to the axis and get the union
// of the ranges.
Iterator iterator = mappedDatasets.iterator();
while (iterator.hasNext()) {
XYDataset d = (XYDataset) iterator.next();
if (d != null) {
XYItemRenderer r = getRendererForDataset(d);
if (isDomainAxis) {
if (r != null) {
result = Range.combine(result, r.findDomainBounds(d));
}
else {
result = Range.combine(result,
DatasetUtilities.findDomainBounds(d));
}
}
else {
if (r != null) {
result = Range.combine(result, r.findRangeBounds(d));
}
else {
result = Range.combine(result,
DatasetUtilities.findRangeBounds(d));
}
}
if (r != null) {
Collection c = r.getAnnotations();
Iterator i = c.iterator();
while (i.hasNext()) {
XYAnnotation a = (XYAnnotation) i.next();
if (a instanceof XYAnnotationBoundsInfo) {
includedAnnotations.add(a);
}
}
}
}
}
Iterator it = includedAnnotations.iterator();
while (it.hasNext()) {
XYAnnotationBoundsInfo xyabi = (XYAnnotationBoundsInfo) it.next();
if (xyabi.getIncludeInDataBounds()) {
if (isDomainAxis) {
result = Range.combine(result, xyabi.getXRange());
}
else {
result = Range.combine(result, xyabi.getYRange());
}
}
}
return result;
} | false | Chart | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns the range for the specified axis.
*
* @param axis the axis.
*
* @return The range.
*/
public Range getDataRange(ValueAxis axis) {
Range result = null;
List mappedDatasets = new ArrayList();
List includedAnnotations = new ArrayList();
boolean isDomainAxis = true;
// is it a domain axis?
int domainIndex = getDomainAxisIndex(axis);
if (domainIndex >= 0) {
isDomainAxis = true;
mappedDatasets.addAll(getDatasetsMappedToDomainAxis(
new Integer(domainIndex)));
if (domainIndex == 0) {
// grab the plot's annotations
Iterator iterator = this.annotations.iterator();
while (iterator.hasNext()) {
XYAnnotation annotation = (XYAnnotation) iterator.next();
if (annotation instanceof XYAnnotationBoundsInfo) {
includedAnnotations.add(annotation);
}
}
}
}
// or is it a range axis?
int rangeIndex = getRangeAxisIndex(axis);
if (rangeIndex >= 0) {
isDomainAxis = false;
mappedDatasets.addAll(getDatasetsMappedToRangeAxis(
new Integer(rangeIndex)));
if (rangeIndex == 0) {
Iterator iterator = this.annotations.iterator();
while (iterator.hasNext()) {
XYAnnotation annotation = (XYAnnotation) iterator.next();
if (annotation instanceof XYAnnotationBoundsInfo) {
includedAnnotations.add(annotation);
}
}
}
}
// iterate through the datasets that map to the axis and get the union
// of the ranges.
Iterator iterator = mappedDatasets.iterator();
while (iterator.hasNext()) {
XYDataset d = (XYDataset) iterator.next();
if (d != null) {
XYItemRenderer r = getRendererForDataset(d);
if (isDomainAxis) {
if (r != null) {
result = Range.combine(result, r.findDomainBounds(d));
}
else {
result = Range.combine(result,
DatasetUtilities.findDomainBounds(d));
}
}
else {
if (r != null) {
result = Range.combine(result, r.findRangeBounds(d));
}
else {
result = Range.combine(result,
DatasetUtilities.findRangeBounds(d));
}
}
if (r != null) {
Collection c = r.getAnnotations();
Iterator i = c.iterator();
while (i.hasNext()) {
XYAnnotation a = (XYAnnotation) i.next();
if (a instanceof XYAnnotationBoundsInfo) {
includedAnnotations.add(a);
}
}
}
}
}
Iterator it = includedAnnotations.iterator();
while (it.hasNext()) {
XYAnnotationBoundsInfo xyabi = (XYAnnotationBoundsInfo) it.next();
if (xyabi.getIncludeInDataBounds()) {
if (isDomainAxis) {
result = Range.combine(result, xyabi.getXRange());
}
else {
result = Range.combine(result, xyabi.getYRange());
}
}
}
return result;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
11 | 42967114e16de4c5ef90fc2e0b6dd7b129e5f5386dd515331434afa7938cc377 | public double density(final double[] vals) throws DimensionMismatchException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/** {@inheritDoc} */
public double density(final double[] vals) throws DimensionMismatchException {
final int dim = getDimension();
if (vals.length != dim) {
throw new DimensionMismatchException(vals.length, dim);
}
return FastMath.pow(2 * FastMath.PI, -0.5 * dim) *
FastMath.pow(covarianceMatrixDeterminant, -0.5) *
getExponentTerm(vals);
}
```
| public double density(final double[] vals) throws DimensionMismatchException {
final int dim = getDimension();
if (vals.length != dim) {
throw new DimensionMismatchException(vals.length, dim);
}
return FastMath.pow(2 * FastMath.PI, -0.5 * dim) *
FastMath.pow(covarianceMatrixDeterminant, -0.5) *
getExponentTerm(vals);
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/** {@inheritDoc} */
public double density(final double[] vals) throws DimensionMismatchException {
final int dim = getDimension();
if (vals.length != dim) {
throw new DimensionMismatchException(vals.length, dim);
}
return FastMath.pow(2 * FastMath.PI, -0.5 * dim) *
FastMath.pow(covarianceMatrixDeterminant, -0.5) *
getExponentTerm(vals);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
12 | 42de3726650f3902d60f9d8fb6eabb473d3eb2b9f413d873537bdc5de4635698 | public Class getGenericType(Field field) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Finds the generic type (parametrized type) of the field. If the field is not generic it returns Object.class.
*
* @param field
* @return
*/
public Class getGenericType(Field field) {
Type generic = field.getGenericType();
if (generic != null && generic instanceof ParameterizedType) {
Type actual = ((ParameterizedType) generic).getActualTypeArguments()[0];
if (actual instanceof Class) {
return (Class) actual;
} else if (actual instanceof ParameterizedType) {
//in case of nested generics we don't go deep
return (Class) ((ParameterizedType) actual).getRawType();
}
}
return Object.class;
}
```
| public Class getGenericType(Field field) {
Type generic = field.getGenericType();
if (generic != null && generic instanceof ParameterizedType) {
Type actual = ((ParameterizedType) generic).getActualTypeArguments()[0];
if (actual instanceof Class) {
return (Class) actual;
} else if (actual instanceof ParameterizedType) {
//in case of nested generics we don't go deep
return (Class) ((ParameterizedType) actual).getRawType();
}
}
return Object.class;
} | false | Mockito | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Finds the generic type (parametrized type) of the field. If the field is not generic it returns Object.class.
*
* @param field
* @return
*/
public Class getGenericType(Field field) {
Type generic = field.getGenericType();
if (generic != null && generic instanceof ParameterizedType) {
Type actual = ((ParameterizedType) generic).getActualTypeArguments()[0];
if (actual instanceof Class) {
return (Class) actual;
} else if (actual instanceof ParameterizedType) {
//in case of nested generics we don't go deep
return (Class) ((ParameterizedType) actual).getRawType();
}
}
return Object.class;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
11 | 43750fac284be2062ba176fa6ff49659167479594eea9d71ed04a83545b401c8 | public ArchiveInputStream createArchiveInputStream(final InputStream in)
throws ArchiveException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Create an archive input stream from an input stream, autodetecting
* the archive type from the first few bytes of the stream. The InputStream
* must support marks, like BufferedInputStream.
*
* @param in the input stream
* @return the archive input stream
* @throws ArchiveException if the archiver name is not known
* @throws IllegalArgumentException if the stream is null or does not support mark
*/
public ArchiveInputStream createArchiveInputStream(final InputStream in)
throws ArchiveException {
if (in == null) {
throw new IllegalArgumentException("Stream must not be null.");
}
if (!in.markSupported()) {
throw new IllegalArgumentException("Mark is not supported.");
}
final byte[] signature = new byte[12];
in.mark(signature.length);
try {
int signatureLength = in.read(signature);
in.reset();
if (ZipArchiveInputStream.matches(signature, signatureLength)) {
return new ZipArchiveInputStream(in);
} else if (JarArchiveInputStream.matches(signature, signatureLength)) {
return new JarArchiveInputStream(in);
} else if (ArArchiveInputStream.matches(signature, signatureLength)) {
return new ArArchiveInputStream(in);
} else if (CpioArchiveInputStream.matches(signature, signatureLength)) {
return new CpioArchiveInputStream(in);
}
// Dump needs a bigger buffer to check the signature;
final byte[] dumpsig = new byte[32];
in.mark(dumpsig.length);
signatureLength = in.read(dumpsig);
in.reset();
if (DumpArchiveInputStream.matches(dumpsig, signatureLength)) {
return new DumpArchiveInputStream(in);
}
// Tar needs an even bigger buffer to check the signature; read the first block
final byte[] tarheader = new byte[512];
in.mark(tarheader.length);
signatureLength = in.read(tarheader);
in.reset();
if (TarArchiveInputStream.matches(tarheader, signatureLength)) {
return new TarArchiveInputStream(in);
}
// COMPRESS-117 - improve auto-recognition
if (signatureLength >= 512) {
try {
TarArchiveInputStream tais = new TarArchiveInputStream(new ByteArrayInputStream(tarheader));
tais.getNextEntry();
return new TarArchiveInputStream(in);
} catch (Exception e) { // NOPMD
// can generate IllegalArgumentException as well as IOException
// autodetection, simply not a TAR
// ignored
}
}
} catch (IOException e) {
throw new ArchiveException("Could not use reset and mark operations.", e);
}
throw new ArchiveException("No Archiver found for the stream signature");
}
```
| public ArchiveInputStream createArchiveInputStream(final InputStream in)
throws ArchiveException {
if (in == null) {
throw new IllegalArgumentException("Stream must not be null.");
}
if (!in.markSupported()) {
throw new IllegalArgumentException("Mark is not supported.");
}
final byte[] signature = new byte[12];
in.mark(signature.length);
try {
int signatureLength = in.read(signature);
in.reset();
if (ZipArchiveInputStream.matches(signature, signatureLength)) {
return new ZipArchiveInputStream(in);
} else if (JarArchiveInputStream.matches(signature, signatureLength)) {
return new JarArchiveInputStream(in);
} else if (ArArchiveInputStream.matches(signature, signatureLength)) {
return new ArArchiveInputStream(in);
} else if (CpioArchiveInputStream.matches(signature, signatureLength)) {
return new CpioArchiveInputStream(in);
}
// Dump needs a bigger buffer to check the signature;
final byte[] dumpsig = new byte[32];
in.mark(dumpsig.length);
signatureLength = in.read(dumpsig);
in.reset();
if (DumpArchiveInputStream.matches(dumpsig, signatureLength)) {
return new DumpArchiveInputStream(in);
}
// Tar needs an even bigger buffer to check the signature; read the first block
final byte[] tarheader = new byte[512];
in.mark(tarheader.length);
signatureLength = in.read(tarheader);
in.reset();
if (TarArchiveInputStream.matches(tarheader, signatureLength)) {
return new TarArchiveInputStream(in);
}
// COMPRESS-117 - improve auto-recognition
if (signatureLength >= 512) {
try {
TarArchiveInputStream tais = new TarArchiveInputStream(new ByteArrayInputStream(tarheader));
tais.getNextEntry();
return new TarArchiveInputStream(in);
} catch (Exception e) { // NOPMD
// can generate IllegalArgumentException as well as IOException
// autodetection, simply not a TAR
// ignored
}
}
} catch (IOException e) {
throw new ArchiveException("Could not use reset and mark operations.", e);
}
throw new ArchiveException("No Archiver found for the stream signature");
} | false | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Create an archive input stream from an input stream, autodetecting
* the archive type from the first few bytes of the stream. The InputStream
* must support marks, like BufferedInputStream.
*
* @param in the input stream
* @return the archive input stream
* @throws ArchiveException if the archiver name is not known
* @throws IllegalArgumentException if the stream is null or does not support mark
*/
public ArchiveInputStream createArchiveInputStream(final InputStream in)
throws ArchiveException {
if (in == null) {
throw new IllegalArgumentException("Stream must not be null.");
}
if (!in.markSupported()) {
throw new IllegalArgumentException("Mark is not supported.");
}
final byte[] signature = new byte[12];
in.mark(signature.length);
try {
int signatureLength = in.read(signature);
in.reset();
if (ZipArchiveInputStream.matches(signature, signatureLength)) {
return new ZipArchiveInputStream(in);
} else if (JarArchiveInputStream.matches(signature, signatureLength)) {
return new JarArchiveInputStream(in);
} else if (ArArchiveInputStream.matches(signature, signatureLength)) {
return new ArArchiveInputStream(in);
} else if (CpioArchiveInputStream.matches(signature, signatureLength)) {
return new CpioArchiveInputStream(in);
}
// Dump needs a bigger buffer to check the signature;
final byte[] dumpsig = new byte[32];
in.mark(dumpsig.length);
signatureLength = in.read(dumpsig);
in.reset();
if (DumpArchiveInputStream.matches(dumpsig, signatureLength)) {
return new DumpArchiveInputStream(in);
}
// Tar needs an even bigger buffer to check the signature; read the first block
final byte[] tarheader = new byte[512];
in.mark(tarheader.length);
signatureLength = in.read(tarheader);
in.reset();
if (TarArchiveInputStream.matches(tarheader, signatureLength)) {
return new TarArchiveInputStream(in);
}
// COMPRESS-117 - improve auto-recognition
if (signatureLength >= 512) {
try {
TarArchiveInputStream tais = new TarArchiveInputStream(new ByteArrayInputStream(tarheader));
tais.getNextEntry();
return new TarArchiveInputStream(in);
} catch (Exception e) { // NOPMD
// can generate IllegalArgumentException as well as IOException
// autodetection, simply not a TAR
// ignored
}
}
} catch (IOException e) {
throw new ArchiveException("Could not use reset and mark operations.", e);
}
throw new ArchiveException("No Archiver found for the stream signature");
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
58 | 43e8e0af17887e3066429466d09ecc3fea42dd7b69faed5455c1bbe2b7a226ae | private void computeGenKill(Node n, BitSet gen, BitSet kill,
boolean conditional) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Computes the GEN and KILL set.
*
* @param n Root node.
* @param gen Local variables that are live because of the instruction at
* {@code n} will be added to this set.
* @param kill Local variables that are killed because of the instruction at
* {@code n} will be added to this set.
* @param conditional {@code true} if any assignments encountered are
* conditionally executed. These assignments might not kill a variable.
*/
private void computeGenKill(Node n, BitSet gen, BitSet kill,
boolean conditional) {
switch (n.getType()) {
case Token.SCRIPT:
case Token.BLOCK:
case Token.FUNCTION:
return;
case Token.WHILE:
case Token.DO:
case Token.IF:
computeGenKill(NodeUtil.getConditionExpression(n), gen, kill,
conditional);
return;
case Token.FOR:
if (!NodeUtil.isForIn(n)) {
computeGenKill(NodeUtil.getConditionExpression(n), gen, kill,
conditional);
} else {
// for(x in y) {...}
Node lhs = n.getFirstChild();
Node rhs = lhs.getNext();
if (NodeUtil.isVar(lhs)) {
// for(var x in y) {...}
lhs = lhs.getLastChild();
}
addToSetIfLocal(lhs, kill);
addToSetIfLocal(lhs, gen);
computeGenKill(rhs, gen, kill, conditional);
}
return;
case Token.VAR:
for (Node c = n.getFirstChild(); c != null; c = c.getNext()) {
if (c.hasChildren()) {
computeGenKill(c.getFirstChild(), gen, kill, conditional);
if (!conditional) {
addToSetIfLocal(c, kill);
}
}
}
return;
case Token.AND:
case Token.OR:
computeGenKill(n.getFirstChild(), gen, kill, conditional);
// May short circuit.
computeGenKill(n.getLastChild(), gen, kill, true);
return;
case Token.HOOK:
computeGenKill(n.getFirstChild(), gen, kill, conditional);
// Assume both sides are conditional.
computeGenKill(n.getFirstChild().getNext(), gen, kill, true);
computeGenKill(n.getLastChild(), gen, kill, true);
return;
case Token.NAME:
if (isArgumentsName(n)) {
markAllParametersEscaped();
} else {
addToSetIfLocal(n, gen);
}
return;
default:
if (NodeUtil.isAssignmentOp(n) && NodeUtil.isName(n.getFirstChild())) {
Node lhs = n.getFirstChild();
if (!conditional) {
addToSetIfLocal(lhs, kill);
}
if (!NodeUtil.isAssign(n)) {
// assignments such as a += 1 reads a.
addToSetIfLocal(lhs, gen);
}
computeGenKill(lhs.getNext(), gen, kill, conditional);
} else {
for (Node c = n.getFirstChild(); c != null; c = c.getNext()) {
computeGenKill(c, gen, kill, conditional);
}
}
return;
}
}
```
| private void computeGenKill(Node n, BitSet gen, BitSet kill,
boolean conditional) {
switch (n.getType()) {
case Token.SCRIPT:
case Token.BLOCK:
case Token.FUNCTION:
return;
case Token.WHILE:
case Token.DO:
case Token.IF:
computeGenKill(NodeUtil.getConditionExpression(n), gen, kill,
conditional);
return;
case Token.FOR:
if (!NodeUtil.isForIn(n)) {
computeGenKill(NodeUtil.getConditionExpression(n), gen, kill,
conditional);
} else {
// for(x in y) {...}
Node lhs = n.getFirstChild();
Node rhs = lhs.getNext();
if (NodeUtil.isVar(lhs)) {
// for(var x in y) {...}
lhs = lhs.getLastChild();
}
addToSetIfLocal(lhs, kill);
addToSetIfLocal(lhs, gen);
computeGenKill(rhs, gen, kill, conditional);
}
return;
case Token.VAR:
for (Node c = n.getFirstChild(); c != null; c = c.getNext()) {
if (c.hasChildren()) {
computeGenKill(c.getFirstChild(), gen, kill, conditional);
if (!conditional) {
addToSetIfLocal(c, kill);
}
}
}
return;
case Token.AND:
case Token.OR:
computeGenKill(n.getFirstChild(), gen, kill, conditional);
// May short circuit.
computeGenKill(n.getLastChild(), gen, kill, true);
return;
case Token.HOOK:
computeGenKill(n.getFirstChild(), gen, kill, conditional);
// Assume both sides are conditional.
computeGenKill(n.getFirstChild().getNext(), gen, kill, true);
computeGenKill(n.getLastChild(), gen, kill, true);
return;
case Token.NAME:
if (isArgumentsName(n)) {
markAllParametersEscaped();
} else {
addToSetIfLocal(n, gen);
}
return;
default:
if (NodeUtil.isAssignmentOp(n) && NodeUtil.isName(n.getFirstChild())) {
Node lhs = n.getFirstChild();
if (!conditional) {
addToSetIfLocal(lhs, kill);
}
if (!NodeUtil.isAssign(n)) {
// assignments such as a += 1 reads a.
addToSetIfLocal(lhs, gen);
}
computeGenKill(lhs.getNext(), gen, kill, conditional);
} else {
for (Node c = n.getFirstChild(); c != null; c = c.getNext()) {
computeGenKill(c, gen, kill, conditional);
}
}
return;
}
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Computes the GEN and KILL set.
*
* @param n Root node.
* @param gen Local variables that are live because of the instruction at
* {@code n} will be added to this set.
* @param kill Local variables that are killed because of the instruction at
* {@code n} will be added to this set.
* @param conditional {@code true} if any assignments encountered are
* conditionally executed. These assignments might not kill a variable.
*/
private void computeGenKill(Node n, BitSet gen, BitSet kill,
boolean conditional) {
switch (n.getType()) {
case Token.SCRIPT:
case Token.BLOCK:
case Token.FUNCTION:
return;
case Token.WHILE:
case Token.DO:
case Token.IF:
computeGenKill(NodeUtil.getConditionExpression(n), gen, kill,
conditional);
return;
case Token.FOR:
if (!NodeUtil.isForIn(n)) {
computeGenKill(NodeUtil.getConditionExpression(n), gen, kill,
conditional);
} else {
// for(x in y) {...}
Node lhs = n.getFirstChild();
Node rhs = lhs.getNext();
if (NodeUtil.isVar(lhs)) {
// for(var x in y) {...}
lhs = lhs.getLastChild();
}
addToSetIfLocal(lhs, kill);
addToSetIfLocal(lhs, gen);
computeGenKill(rhs, gen, kill, conditional);
}
return;
case Token.VAR:
for (Node c = n.getFirstChild(); c != null; c = c.getNext()) {
if (c.hasChildren()) {
computeGenKill(c.getFirstChild(), gen, kill, conditional);
if (!conditional) {
addToSetIfLocal(c, kill);
}
}
}
return;
case Token.AND:
case Token.OR:
computeGenKill(n.getFirstChild(), gen, kill, conditional);
// May short circuit.
computeGenKill(n.getLastChild(), gen, kill, true);
return;
case Token.HOOK:
computeGenKill(n.getFirstChild(), gen, kill, conditional);
// Assume both sides are conditional.
computeGenKill(n.getFirstChild().getNext(), gen, kill, true);
computeGenKill(n.getLastChild(), gen, kill, true);
return;
case Token.NAME:
if (isArgumentsName(n)) {
markAllParametersEscaped();
} else {
addToSetIfLocal(n, gen);
}
return;
default:
if (NodeUtil.isAssignmentOp(n) && NodeUtil.isName(n.getFirstChild())) {
Node lhs = n.getFirstChild();
if (!conditional) {
addToSetIfLocal(lhs, kill);
}
if (!NodeUtil.isAssign(n)) {
// assignments such as a += 1 reads a.
addToSetIfLocal(lhs, gen);
}
computeGenKill(lhs.getNext(), gen, kill, conditional);
} else {
for (Node c = n.getFirstChild(); c != null; c = c.getNext()) {
computeGenKill(c, gen, kill, conditional);
}
}
return;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
15 | 44666cd937affcc578e6f40a060cd270c19c8f750b249f2fda27a6f09dc9707d | @Override
public boolean equals(Object obj) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/* (non-Javadoc)
* @see java.lang.Object#equals(java.lang.Object)
*/
@Override
public boolean equals(Object obj) {
if (this == obj) {
return true;
}
if (obj == null || getClass() != obj.getClass()) {
return false;
}
ZipArchiveEntry other = (ZipArchiveEntry) obj;
String myName = getName();
String otherName = other.getName();
if (myName == null) {
if (otherName != null) {
return false;
}
} else if (!myName.equals(otherName)) {
return false;
}
String myComment = getComment();
String otherComment = other.getComment();
if (myComment == null) {
myComment = "";
}
if (otherComment == null) {
otherComment = "";
}
return getTime() == other.getTime()
&& myComment.equals(otherComment)
&& getInternalAttributes() == other.getInternalAttributes()
&& getPlatform() == other.getPlatform()
&& getExternalAttributes() == other.getExternalAttributes()
&& getMethod() == other.getMethod()
&& getSize() == other.getSize()
&& getCrc() == other.getCrc()
&& getCompressedSize() == other.getCompressedSize()
&& Arrays.equals(getCentralDirectoryExtra(),
other.getCentralDirectoryExtra())
&& Arrays.equals(getLocalFileDataExtra(),
other.getLocalFileDataExtra())
&& gpb.equals(other.gpb);
}
```
| @Override
public boolean equals(Object obj) {
if (this == obj) {
return true;
}
if (obj == null || getClass() != obj.getClass()) {
return false;
}
ZipArchiveEntry other = (ZipArchiveEntry) obj;
String myName = getName();
String otherName = other.getName();
if (myName == null) {
if (otherName != null) {
return false;
}
} else if (!myName.equals(otherName)) {
return false;
}
String myComment = getComment();
String otherComment = other.getComment();
if (myComment == null) {
myComment = "";
}
if (otherComment == null) {
otherComment = "";
}
return getTime() == other.getTime()
&& myComment.equals(otherComment)
&& getInternalAttributes() == other.getInternalAttributes()
&& getPlatform() == other.getPlatform()
&& getExternalAttributes() == other.getExternalAttributes()
&& getMethod() == other.getMethod()
&& getSize() == other.getSize()
&& getCrc() == other.getCrc()
&& getCompressedSize() == other.getCompressedSize()
&& Arrays.equals(getCentralDirectoryExtra(),
other.getCentralDirectoryExtra())
&& Arrays.equals(getLocalFileDataExtra(),
other.getLocalFileDataExtra())
&& gpb.equals(other.gpb);
} | false | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/* (non-Javadoc)
* @see java.lang.Object#equals(java.lang.Object)
*/
@Override
public boolean equals(Object obj) {
if (this == obj) {
return true;
}
if (obj == null || getClass() != obj.getClass()) {
return false;
}
ZipArchiveEntry other = (ZipArchiveEntry) obj;
String myName = getName();
String otherName = other.getName();
if (myName == null) {
if (otherName != null) {
return false;
}
} else if (!myName.equals(otherName)) {
return false;
}
String myComment = getComment();
String otherComment = other.getComment();
if (myComment == null) {
myComment = "";
}
if (otherComment == null) {
otherComment = "";
}
return getTime() == other.getTime()
&& myComment.equals(otherComment)
&& getInternalAttributes() == other.getInternalAttributes()
&& getPlatform() == other.getPlatform()
&& getExternalAttributes() == other.getExternalAttributes()
&& getMethod() == other.getMethod()
&& getSize() == other.getSize()
&& getCrc() == other.getCrc()
&& getCompressedSize() == other.getCompressedSize()
&& Arrays.equals(getCentralDirectoryExtra(),
other.getCentralDirectoryExtra())
&& Arrays.equals(getLocalFileDataExtra(),
other.getLocalFileDataExtra())
&& gpb.equals(other.gpb);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
4 | 4479e7e62b9e84d7d843806b8ac568891db6449153aa81bb4c845185eca274b9 | public Partial with(DateTimeFieldType fieldType, int value) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Gets a copy of this date with the specified field set to a new value.
* <p>
* If this partial did not previously support the field, the new one will.
* Contrast this behaviour with {@link #withField(DateTimeFieldType, int)}.
* <p>
* For example, if the field type is <code>dayOfMonth</code> then the day
* would be changed/added in the returned instance.
*
* @param fieldType the field type to set, not null
* @param value the value to set
* @return a copy of this instance with the field set
* @throws IllegalArgumentException if the value is null or invalid
*/
//-----------------------------------------------------------------------
public Partial with(DateTimeFieldType fieldType, int value) {
if (fieldType == null) {
throw new IllegalArgumentException("The field type must not be null");
}
int index = indexOf(fieldType);
if (index == -1) {
DateTimeFieldType[] newTypes = new DateTimeFieldType[iTypes.length + 1];
int[] newValues = new int[newTypes.length];
// find correct insertion point to keep largest-smallest order
int i = 0;
DurationField unitField = fieldType.getDurationType().getField(iChronology);
if (unitField.isSupported()) {
for (; i < iTypes.length; i++) {
DateTimeFieldType loopType = iTypes[i];
DurationField loopUnitField = loopType.getDurationType().getField(iChronology);
if (loopUnitField.isSupported()) {
int compare = unitField.compareTo(loopUnitField);
if (compare > 0) {
break;
} else if (compare == 0) {
DurationField rangeField = fieldType.getRangeDurationType().getField(iChronology);
DurationField loopRangeField = loopType.getRangeDurationType().getField(iChronology);
if (rangeField.compareTo(loopRangeField) > 0) {
break;
}
}
}
}
}
System.arraycopy(iTypes, 0, newTypes, 0, i);
System.arraycopy(iValues, 0, newValues, 0, i);
newTypes[i] = fieldType;
newValues[i] = value;
System.arraycopy(iTypes, i, newTypes, i + 1, newTypes.length - i - 1);
System.arraycopy(iValues, i, newValues, i + 1, newValues.length - i - 1);
// use public constructor to ensure full validation
// this isn't overly efficient, but is safe
Partial newPartial = new Partial(newTypes, newValues, iChronology);
iChronology.validate(newPartial, newValues);
return newPartial;
}
if (value == getValue(index)) {
return this;
}
int[] newValues = getValues();
newValues = getField(index).set(this, index, newValues, value);
return new Partial(this, newValues);
}
```
| public Partial with(DateTimeFieldType fieldType, int value) {
if (fieldType == null) {
throw new IllegalArgumentException("The field type must not be null");
}
int index = indexOf(fieldType);
if (index == -1) {
DateTimeFieldType[] newTypes = new DateTimeFieldType[iTypes.length + 1];
int[] newValues = new int[newTypes.length];
// find correct insertion point to keep largest-smallest order
int i = 0;
DurationField unitField = fieldType.getDurationType().getField(iChronology);
if (unitField.isSupported()) {
for (; i < iTypes.length; i++) {
DateTimeFieldType loopType = iTypes[i];
DurationField loopUnitField = loopType.getDurationType().getField(iChronology);
if (loopUnitField.isSupported()) {
int compare = unitField.compareTo(loopUnitField);
if (compare > 0) {
break;
} else if (compare == 0) {
DurationField rangeField = fieldType.getRangeDurationType().getField(iChronology);
DurationField loopRangeField = loopType.getRangeDurationType().getField(iChronology);
if (rangeField.compareTo(loopRangeField) > 0) {
break;
}
}
}
}
}
System.arraycopy(iTypes, 0, newTypes, 0, i);
System.arraycopy(iValues, 0, newValues, 0, i);
newTypes[i] = fieldType;
newValues[i] = value;
System.arraycopy(iTypes, i, newTypes, i + 1, newTypes.length - i - 1);
System.arraycopy(iValues, i, newValues, i + 1, newValues.length - i - 1);
// use public constructor to ensure full validation
// this isn't overly efficient, but is safe
Partial newPartial = new Partial(newTypes, newValues, iChronology);
iChronology.validate(newPartial, newValues);
return newPartial;
}
if (value == getValue(index)) {
return this;
}
int[] newValues = getValues();
newValues = getField(index).set(this, index, newValues, value);
return new Partial(this, newValues);
} | false | Time | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Gets a copy of this date with the specified field set to a new value.
* <p>
* If this partial did not previously support the field, the new one will.
* Contrast this behaviour with {@link #withField(DateTimeFieldType, int)}.
* <p>
* For example, if the field type is <code>dayOfMonth</code> then the day
* would be changed/added in the returned instance.
*
* @param fieldType the field type to set, not null
* @param value the value to set
* @return a copy of this instance with the field set
* @throws IllegalArgumentException if the value is null or invalid
*/
//-----------------------------------------------------------------------
public Partial with(DateTimeFieldType fieldType, int value) {
if (fieldType == null) {
throw new IllegalArgumentException("The field type must not be null");
}
int index = indexOf(fieldType);
if (index == -1) {
DateTimeFieldType[] newTypes = new DateTimeFieldType[iTypes.length + 1];
int[] newValues = new int[newTypes.length];
// find correct insertion point to keep largest-smallest order
int i = 0;
DurationField unitField = fieldType.getDurationType().getField(iChronology);
if (unitField.isSupported()) {
for (; i < iTypes.length; i++) {
DateTimeFieldType loopType = iTypes[i];
DurationField loopUnitField = loopType.getDurationType().getField(iChronology);
if (loopUnitField.isSupported()) {
int compare = unitField.compareTo(loopUnitField);
if (compare > 0) {
break;
} else if (compare == 0) {
DurationField rangeField = fieldType.getRangeDurationType().getField(iChronology);
DurationField loopRangeField = loopType.getRangeDurationType().getField(iChronology);
if (rangeField.compareTo(loopRangeField) > 0) {
break;
}
}
}
}
}
System.arraycopy(iTypes, 0, newTypes, 0, i);
System.arraycopy(iValues, 0, newValues, 0, i);
newTypes[i] = fieldType;
newValues[i] = value;
System.arraycopy(iTypes, i, newTypes, i + 1, newTypes.length - i - 1);
System.arraycopy(iValues, i, newValues, i + 1, newValues.length - i - 1);
// use public constructor to ensure full validation
// this isn't overly efficient, but is safe
Partial newPartial = new Partial(newTypes, newValues, iChronology);
iChronology.validate(newPartial, newValues);
return newPartial;
}
if (value == getValue(index)) {
return this;
}
int[] newValues = getValues();
newValues = getField(index).set(this, index, newValues, value);
return new Partial(this, newValues);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
159 | 4494195d42d2aba283669952b7fd3d272c25d30facbd4003fc712d41add34280 | private void findCalledFunctions(
Node node, Set<String> changed) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* @see #findCalledFunctions(Node)
*/
private void findCalledFunctions(
Node node, Set<String> changed) {
Preconditions.checkArgument(changed != null);
// For each referenced function, add a new reference
if (node.getType() == Token.NAME) {
if (isCandidateUsage(node)) {
changed.add(node.getString());
}
}
for (Node c = node.getFirstChild(); c != null; c = c.getNext()) {
findCalledFunctions(c, changed);
}
}
```
| private void findCalledFunctions(
Node node, Set<String> changed) {
Preconditions.checkArgument(changed != null);
// For each referenced function, add a new reference
if (node.getType() == Token.NAME) {
if (isCandidateUsage(node)) {
changed.add(node.getString());
}
}
for (Node c = node.getFirstChild(); c != null; c = c.getNext()) {
findCalledFunctions(c, changed);
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* @see #findCalledFunctions(Node)
*/
private void findCalledFunctions(
Node node, Set<String> changed) {
Preconditions.checkArgument(changed != null);
// For each referenced function, add a new reference
if (node.getType() == Token.NAME) {
if (isCandidateUsage(node)) {
changed.add(node.getString());
}
}
for (Node c = node.getFirstChild(); c != null; c = c.getNext()) {
findCalledFunctions(c, changed);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
130 | 4514c57fa6501281e244503bd510c769ed4bd1d85a965aa605d8e7aa76c586a1 | private void inlineAliases(GlobalNamespace namespace) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* For each qualified name N in the global scope, we check if:
* (a) No ancestor of N is ever aliased or assigned an unknown value type.
* (If N = "a.b.c", "a" and "a.b" are never aliased).
* (b) N has exactly one write, and it lives in the global scope.
* (c) N is aliased in a local scope.
*
* If (a) is true, then GlobalNamespace must know all the writes to N.
* If (a) and (b) are true, then N cannot change during the execution of
* a local scope.
* If (a) and (b) and (c) are true, then the alias can be inlined if the
* alias obeys the usual rules for how we decide whether a variable is
* inlineable.
* @see InlineVariables
*/
private void inlineAliases(GlobalNamespace namespace) {
// Invariant: All the names in the worklist meet condition (a).
Deque<Name> workList = new ArrayDeque<Name>(namespace.getNameForest());
while (!workList.isEmpty()) {
Name name = workList.pop();
// Don't attempt to inline a getter or setter property as a variable.
if (name.type == Name.Type.GET || name.type == Name.Type.SET) {
continue;
}
if (name.globalSets == 1 && name.localSets == 0 &&
name.aliasingGets > 0) {
// {@code name} meets condition (b). Find all of its local aliases
// and try to inline them.
List<Ref> refs = Lists.newArrayList(name.getRefs());
for (Ref ref : refs) {
if (ref.type == Type.ALIASING_GET && ref.scope.isLocal()) {
// {@code name} meets condition (c). Try to inline it.
if (inlineAliasIfPossible(ref, namespace)) {
name.removeRef(ref);
}
}
}
}
// Check if {@code name} has any aliases left after the
// local-alias-inlining above.
if ((name.type == Name.Type.OBJECTLIT ||
name.type == Name.Type.FUNCTION) &&
name.aliasingGets == 0 && name.props != null) {
// All of {@code name}'s children meet condition (a), so they can be
// added to the worklist.
workList.addAll(name.props);
}
}
}
```
| private void inlineAliases(GlobalNamespace namespace) {
// Invariant: All the names in the worklist meet condition (a).
Deque<Name> workList = new ArrayDeque<Name>(namespace.getNameForest());
while (!workList.isEmpty()) {
Name name = workList.pop();
// Don't attempt to inline a getter or setter property as a variable.
if (name.type == Name.Type.GET || name.type == Name.Type.SET) {
continue;
}
if (name.globalSets == 1 && name.localSets == 0 &&
name.aliasingGets > 0) {
// {@code name} meets condition (b). Find all of its local aliases
// and try to inline them.
List<Ref> refs = Lists.newArrayList(name.getRefs());
for (Ref ref : refs) {
if (ref.type == Type.ALIASING_GET && ref.scope.isLocal()) {
// {@code name} meets condition (c). Try to inline it.
if (inlineAliasIfPossible(ref, namespace)) {
name.removeRef(ref);
}
}
}
}
// Check if {@code name} has any aliases left after the
// local-alias-inlining above.
if ((name.type == Name.Type.OBJECTLIT ||
name.type == Name.Type.FUNCTION) &&
name.aliasingGets == 0 && name.props != null) {
// All of {@code name}'s children meet condition (a), so they can be
// added to the worklist.
workList.addAll(name.props);
}
}
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* For each qualified name N in the global scope, we check if:
* (a) No ancestor of N is ever aliased or assigned an unknown value type.
* (If N = "a.b.c", "a" and "a.b" are never aliased).
* (b) N has exactly one write, and it lives in the global scope.
* (c) N is aliased in a local scope.
*
* If (a) is true, then GlobalNamespace must know all the writes to N.
* If (a) and (b) are true, then N cannot change during the execution of
* a local scope.
* If (a) and (b) and (c) are true, then the alias can be inlined if the
* alias obeys the usual rules for how we decide whether a variable is
* inlineable.
* @see InlineVariables
*/
private void inlineAliases(GlobalNamespace namespace) {
// Invariant: All the names in the worklist meet condition (a).
Deque<Name> workList = new ArrayDeque<Name>(namespace.getNameForest());
while (!workList.isEmpty()) {
Name name = workList.pop();
// Don't attempt to inline a getter or setter property as a variable.
if (name.type == Name.Type.GET || name.type == Name.Type.SET) {
continue;
}
if (name.globalSets == 1 && name.localSets == 0 &&
name.aliasingGets > 0) {
// {@code name} meets condition (b). Find all of its local aliases
// and try to inline them.
List<Ref> refs = Lists.newArrayList(name.getRefs());
for (Ref ref : refs) {
if (ref.type == Type.ALIASING_GET && ref.scope.isLocal()) {
// {@code name} meets condition (c). Try to inline it.
if (inlineAliasIfPossible(ref, namespace)) {
name.removeRef(ref);
}
}
}
}
// Check if {@code name} has any aliases left after the
// local-alias-inlining above.
if ((name.type == Name.Type.OBJECTLIT ||
name.type == Name.Type.FUNCTION) &&
name.aliasingGets == 0 && name.props != null) {
// All of {@code name}'s children meet condition (a), so they can be
// added to the worklist.
workList.addAll(name.props);
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
13 | 45848e3ed0b67244942179c7ec710a6d5f8eaf9b68c628abfa7d4edb4efcd2ff | public Object handle(Invocation invocation) throws Throwable | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public Object handle(Invocation invocation) throws Throwable {
if (invocationContainerImpl.hasAnswersForStubbing()) {
// stubbing voids with stubVoid() or doAnswer() style
InvocationMatcher invocationMatcher = matchersBinder.bindMatchers(mockingProgress
.getArgumentMatcherStorage(), invocation);
invocationContainerImpl.setMethodForStubbing(invocationMatcher);
return null;
}
VerificationMode verificationMode = mockingProgress.pullVerificationMode();
InvocationMatcher invocationMatcher = matchersBinder.bindMatchers(mockingProgress.getArgumentMatcherStorage(),
invocation);
mockingProgress.validateState();
//if verificationMode is not null then someone is doing verify()
if (verificationMode != null) {
//We need to check if verification was started on the correct mock
// - see VerifyingWithAnExtraCallToADifferentMockTest (bug 138)
if (verificationMode instanceof MockAwareVerificationMode && ((MockAwareVerificationMode) verificationMode).getMock() == invocation.getMock()) {
VerificationDataImpl data = new VerificationDataImpl(invocationContainerImpl, invocationMatcher);
verificationMode.verify(data);
return null;
// this means there is an invocation on a different mock. Re-adding verification mode
// - see VerifyingWithAnExtraCallToADifferentMockTest (bug 138)
}
}
invocationContainerImpl.setInvocationForPotentialStubbing(invocationMatcher);
OngoingStubbingImpl<T> ongoingStubbing = new OngoingStubbingImpl<T>(invocationContainerImpl);
mockingProgress.reportOngoingStubbing(ongoingStubbing);
StubbedInvocationMatcher stubbedInvocation = invocationContainerImpl.findAnswerFor(invocation);
if (stubbedInvocation != null) {
stubbedInvocation.captureArgumentsFrom(invocation);
return stubbedInvocation.answer(invocation);
} else {
Object ret = mockSettings.getDefaultAnswer().answer(invocation);
// redo setting invocation for potential stubbing in case of partial
// mocks / spies.
// Without it, the real method inside 'when' might have delegated
// to other self method and overwrite the intended stubbed method
// with a different one. The reset is required to avoid runtime exception that validates return type with stubbed method signature.
invocationContainerImpl.resetInvocationForPotentialStubbing(invocationMatcher);
return ret;
}
}
```
| public Object handle(Invocation invocation) throws Throwable {
if (invocationContainerImpl.hasAnswersForStubbing()) {
// stubbing voids with stubVoid() or doAnswer() style
InvocationMatcher invocationMatcher = matchersBinder.bindMatchers(mockingProgress
.getArgumentMatcherStorage(), invocation);
invocationContainerImpl.setMethodForStubbing(invocationMatcher);
return null;
}
VerificationMode verificationMode = mockingProgress.pullVerificationMode();
InvocationMatcher invocationMatcher = matchersBinder.bindMatchers(mockingProgress.getArgumentMatcherStorage(),
invocation);
mockingProgress.validateState();
//if verificationMode is not null then someone is doing verify()
if (verificationMode != null) {
//We need to check if verification was started on the correct mock
// - see VerifyingWithAnExtraCallToADifferentMockTest (bug 138)
if (verificationMode instanceof MockAwareVerificationMode && ((MockAwareVerificationMode) verificationMode).getMock() == invocation.getMock()) {
VerificationDataImpl data = new VerificationDataImpl(invocationContainerImpl, invocationMatcher);
verificationMode.verify(data);
return null;
// this means there is an invocation on a different mock. Re-adding verification mode
// - see VerifyingWithAnExtraCallToADifferentMockTest (bug 138)
}
}
invocationContainerImpl.setInvocationForPotentialStubbing(invocationMatcher);
OngoingStubbingImpl<T> ongoingStubbing = new OngoingStubbingImpl<T>(invocationContainerImpl);
mockingProgress.reportOngoingStubbing(ongoingStubbing);
StubbedInvocationMatcher stubbedInvocation = invocationContainerImpl.findAnswerFor(invocation);
if (stubbedInvocation != null) {
stubbedInvocation.captureArgumentsFrom(invocation);
return stubbedInvocation.answer(invocation);
} else {
Object ret = mockSettings.getDefaultAnswer().answer(invocation);
// redo setting invocation for potential stubbing in case of partial
// mocks / spies.
// Without it, the real method inside 'when' might have delegated
// to other self method and overwrite the intended stubbed method
// with a different one. The reset is required to avoid runtime exception that validates return type with stubbed method signature.
invocationContainerImpl.resetInvocationForPotentialStubbing(invocationMatcher);
return ret;
}
} | true | Mockito | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public Object handle(Invocation invocation) throws Throwable {
if (invocationContainerImpl.hasAnswersForStubbing()) {
// stubbing voids with stubVoid() or doAnswer() style
InvocationMatcher invocationMatcher = matchersBinder.bindMatchers(mockingProgress
.getArgumentMatcherStorage(), invocation);
invocationContainerImpl.setMethodForStubbing(invocationMatcher);
return null;
}
VerificationMode verificationMode = mockingProgress.pullVerificationMode();
InvocationMatcher invocationMatcher = matchersBinder.bindMatchers(mockingProgress.getArgumentMatcherStorage(),
invocation);
mockingProgress.validateState();
//if verificationMode is not null then someone is doing verify()
if (verificationMode != null) {
//We need to check if verification was started on the correct mock
// - see VerifyingWithAnExtraCallToADifferentMockTest (bug 138)
if (verificationMode instanceof MockAwareVerificationMode && ((MockAwareVerificationMode) verificationMode).getMock() == invocation.getMock()) {
VerificationDataImpl data = new VerificationDataImpl(invocationContainerImpl, invocationMatcher);
verificationMode.verify(data);
return null;
// this means there is an invocation on a different mock. Re-adding verification mode
// - see VerifyingWithAnExtraCallToADifferentMockTest (bug 138)
}
}
invocationContainerImpl.setInvocationForPotentialStubbing(invocationMatcher);
OngoingStubbingImpl<T> ongoingStubbing = new OngoingStubbingImpl<T>(invocationContainerImpl);
mockingProgress.reportOngoingStubbing(ongoingStubbing);
StubbedInvocationMatcher stubbedInvocation = invocationContainerImpl.findAnswerFor(invocation);
if (stubbedInvocation != null) {
stubbedInvocation.captureArgumentsFrom(invocation);
return stubbedInvocation.answer(invocation);
} else {
Object ret = mockSettings.getDefaultAnswer().answer(invocation);
// redo setting invocation for potential stubbing in case of partial
// mocks / spies.
// Without it, the real method inside 'when' might have delegated
// to other self method and overwrite the intended stubbed method
// with a different one. The reset is required to avoid runtime exception that validates return type with stubbed method signature.
invocationContainerImpl.resetInvocationForPotentialStubbing(invocationMatcher);
return ret;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
4 | 4596e77a36c5dcad96c03b8b136d3be4c812f9def987e425b5954913b7f771e1 | public Map<String, Integer> getHeaderMap() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns a copy of the header map that iterates in column order.
* <p>
* The map keys are column names. The map values are 0-based indices.
* </p>
* @return a copy of the header map that iterates in column order.
*/
public Map<String, Integer> getHeaderMap() {
return new LinkedHashMap<String, Integer>(this.headerMap);
}
```
| public Map<String, Integer> getHeaderMap() {
return new LinkedHashMap<String, Integer>(this.headerMap);
} | true | Csv | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns a copy of the header map that iterates in column order.
* <p>
* The map keys are column names. The map values are 0-based indices.
* </p>
* @return a copy of the header map that iterates in column order.
*/
public Map<String, Integer> getHeaderMap() {
return new LinkedHashMap<String, Integer>(this.headerMap);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
12 | 45e127ad8d9349a25c4fc91351f5bdc54866efa52fbfa33ff911cd8921b7a6de | protected String[] flatten(Options options, String[] arguments, boolean stopAtNonOption)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>This flatten method does so using the following rules:
* <ol>
* <li>If an {@link Option} exists for the first character of
* the <code>arguments</code> entry <b>AND</b> an {@link Option}
* does not exist for the whole <code>argument</code> then
* add the first character as an option to the processed tokens
* list e.g. "-D" and add the rest of the entry to the also.</li>
* <li>Otherwise just add the token to the processed tokens list.
* </li>
* </ol>
* </p>
*
* @param options The Options to parse the arguments by.
* @param arguments The arguments that have to be flattened.
* @param stopAtNonOption specifies whether to stop
* flattening when a non option has been encountered
* @return a String array of the flattened arguments
*/
protected String[] flatten(Options options, String[] arguments, boolean stopAtNonOption)
{
List tokens = new ArrayList();
boolean eatTheRest = false;
for (int i = 0; i < arguments.length; i++)
{
String arg = arguments[i];
if ("--".equals(arg))
{
eatTheRest = true;
tokens.add("--");
}
else if ("-".equals(arg))
{
tokens.add("-");
}
else if (arg.startsWith("-"))
{
String opt = Util.stripLeadingHyphens(arg);
if (options.hasOption(opt))
{
tokens.add(arg);
}
else
{
if (options.hasOption(arg.substring(0, 2)))
{
// the format is --foo=value or -foo=value
// the format is a special properties option (-Dproperty=value)
tokens.add(arg.substring(0, 2)); // -D
tokens.add(arg.substring(2)); // property=value
}
else
{
eatTheRest = stopAtNonOption;
tokens.add(arg);
}
}
}
else
{
tokens.add(arg);
}
if (eatTheRest)
{
for (i++; i < arguments.length; i++)
{
tokens.add(arguments[i]);
}
}
}
return (String[]) tokens.toArray(new String[tokens.size()]);
}
```
| protected String[] flatten(Options options, String[] arguments, boolean stopAtNonOption)
{
List tokens = new ArrayList();
boolean eatTheRest = false;
for (int i = 0; i < arguments.length; i++)
{
String arg = arguments[i];
if ("--".equals(arg))
{
eatTheRest = true;
tokens.add("--");
}
else if ("-".equals(arg))
{
tokens.add("-");
}
else if (arg.startsWith("-"))
{
String opt = Util.stripLeadingHyphens(arg);
if (options.hasOption(opt))
{
tokens.add(arg);
}
else
{
if (options.hasOption(arg.substring(0, 2)))
{
// the format is --foo=value or -foo=value
// the format is a special properties option (-Dproperty=value)
tokens.add(arg.substring(0, 2)); // -D
tokens.add(arg.substring(2)); // property=value
}
else
{
eatTheRest = stopAtNonOption;
tokens.add(arg);
}
}
}
else
{
tokens.add(arg);
}
if (eatTheRest)
{
for (i++; i < arguments.length; i++)
{
tokens.add(arguments[i]);
}
}
}
return (String[]) tokens.toArray(new String[tokens.size()]);
} | true | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>This flatten method does so using the following rules:
* <ol>
* <li>If an {@link Option} exists for the first character of
* the <code>arguments</code> entry <b>AND</b> an {@link Option}
* does not exist for the whole <code>argument</code> then
* add the first character as an option to the processed tokens
* list e.g. "-D" and add the rest of the entry to the also.</li>
* <li>Otherwise just add the token to the processed tokens list.
* </li>
* </ol>
* </p>
*
* @param options The Options to parse the arguments by.
* @param arguments The arguments that have to be flattened.
* @param stopAtNonOption specifies whether to stop
* flattening when a non option has been encountered
* @return a String array of the flattened arguments
*/
protected String[] flatten(Options options, String[] arguments, boolean stopAtNonOption)
{
List tokens = new ArrayList();
boolean eatTheRest = false;
for (int i = 0; i < arguments.length; i++)
{
String arg = arguments[i];
if ("--".equals(arg))
{
eatTheRest = true;
tokens.add("--");
}
else if ("-".equals(arg))
{
tokens.add("-");
}
else if (arg.startsWith("-"))
{
String opt = Util.stripLeadingHyphens(arg);
if (options.hasOption(opt))
{
tokens.add(arg);
}
else
{
if (options.hasOption(arg.substring(0, 2)))
{
// the format is --foo=value or -foo=value
// the format is a special properties option (-Dproperty=value)
tokens.add(arg.substring(0, 2)); // -D
tokens.add(arg.substring(2)); // property=value
}
else
{
eatTheRest = stopAtNonOption;
tokens.add(arg);
}
}
}
else
{
tokens.add(arg);
}
if (eatTheRest)
{
for (i++; i < arguments.length; i++)
{
tokens.add(arguments[i]);
}
}
}
return (String[]) tokens.toArray(new String[tokens.size()]);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
97 | 468532214507917118d685ce70b2f9706b1d35d3e44a23cab2ad5f369088bd77 | @Override
public final void serialize(JsonGenerator gen, SerializerProvider ctxt) throws IOException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/*
/**********************************************************
/* Public API, serialization
/**********************************************************
*/
@Override
public final void serialize(JsonGenerator gen, SerializerProvider ctxt) throws IOException
{
if (_value == null) {
ctxt.defaultSerializeNull(gen);
} else if (_value instanceof JsonSerializable) {
((JsonSerializable) _value).serialize(gen, ctxt);
} else {
// 25-May-2018, tatu: [databind#1991] do not call via generator but through context;
// this to preserve contextual information
gen.writeObject(_value);
}
}
```
| @Override
public final void serialize(JsonGenerator gen, SerializerProvider ctxt) throws IOException
{
if (_value == null) {
ctxt.defaultSerializeNull(gen);
} else if (_value instanceof JsonSerializable) {
((JsonSerializable) _value).serialize(gen, ctxt);
} else {
// 25-May-2018, tatu: [databind#1991] do not call via generator but through context;
// this to preserve contextual information
gen.writeObject(_value);
}
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/*
/**********************************************************
/* Public API, serialization
/**********************************************************
*/
@Override
public final void serialize(JsonGenerator gen, SerializerProvider ctxt) throws IOException
{
if (_value == null) {
ctxt.defaultSerializeNull(gen);
} else if (_value instanceof JsonSerializable) {
((JsonSerializable) _value).serialize(gen, ctxt);
} else {
// 25-May-2018, tatu: [databind#1991] do not call via generator but through context;
// this to preserve contextual information
gen.writeObject(_value);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
2 | 46c61cf81ab186dfd075eaa67dd0353f5f30998c39714c5788f82daad183c3a2 | public String get(final String name) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns a value by name.
*
* @param name
* the name of the column to be retrieved.
* @return the column value, or {@code null} if the column name is not found
* @throws IllegalStateException
* if no header mapping was provided
* @throws IllegalArgumentException
* if the record is inconsistent
* @see #isConsistent()
*/
public String get(final String name) {
if (mapping == null) {
throw new IllegalStateException(
"No header mapping was specified, the record values can't be accessed by name");
}
final Integer index = mapping.get(name);
try {
return index != null ? values[index.intValue()] : null;
} catch (ArrayIndexOutOfBoundsException e) {
throw new IllegalArgumentException(
String.format(
"Index for header '%s' is %d but CSVRecord only has %d values!",
name, index.intValue(), values.length));
}
}
```
| public String get(final String name) {
if (mapping == null) {
throw new IllegalStateException(
"No header mapping was specified, the record values can't be accessed by name");
}
final Integer index = mapping.get(name);
try {
return index != null ? values[index.intValue()] : null;
} catch (ArrayIndexOutOfBoundsException e) {
throw new IllegalArgumentException(
String.format(
"Index for header '%s' is %d but CSVRecord only has %d values!",
name, index.intValue(), values.length));
}
} | false | Csv | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns a value by name.
*
* @param name
* the name of the column to be retrieved.
* @return the column value, or {@code null} if the column name is not found
* @throws IllegalStateException
* if no header mapping was provided
* @throws IllegalArgumentException
* if the record is inconsistent
* @see #isConsistent()
*/
public String get(final String name) {
if (mapping == null) {
throw new IllegalStateException(
"No header mapping was specified, the record values can't be accessed by name");
}
final Integer index = mapping.get(name);
try {
return index != null ? values[index.intValue()] : null;
} catch (ArrayIndexOutOfBoundsException e) {
throw new IllegalArgumentException(
String.format(
"Index for header '%s' is %d but CSVRecord only has %d values!",
name, index.intValue(), values.length));
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
20 | 46cdac5c57e04ceba2712e0c3e363b98b633e388673cf84d5bb9a90ee36dd0ac | public int parseInto(DateTimeParserBucket bucket, String text, int position) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public int parseInto(DateTimeParserBucket bucket, String text, int position) {
String str = text.substring(position);
String best = null;
for (String id : ALL_IDS) {
if (str.startsWith(id)) {
if (best == null || id.length() > best.length()) {
best = id;
}
}
}
if (best != null) {
bucket.setZone(DateTimeZone.forID(best));
return position + best.length();
}
return ~position;
}
```
| public int parseInto(DateTimeParserBucket bucket, String text, int position) {
String str = text.substring(position);
String best = null;
for (String id : ALL_IDS) {
if (str.startsWith(id)) {
if (best == null || id.length() > best.length()) {
best = id;
}
}
}
if (best != null) {
bucket.setZone(DateTimeZone.forID(best));
return position + best.length();
}
return ~position;
} | false | Time | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public int parseInto(DateTimeParserBucket bucket, String text, int position) {
String str = text.substring(position);
String best = null;
for (String id : ALL_IDS) {
if (str.startsWith(id)) {
if (best == null || id.length() > best.length()) {
best = id;
}
}
}
if (best != null) {
bucket.setZone(DateTimeZone.forID(best));
return position + best.length();
}
return ~position;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
6 | 46e3ca19e3121bcd59cf1e95689312186fa4227b241aac1af323ecfa2c25e0db | public final void translate(CharSequence input, Writer out) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Translate an input onto a Writer. This is intentionally final as its algorithm is
* tightly coupled with the abstract method of this class.
*
* @param input CharSequence that is being translated
* @param out Writer to translate the text to
* @throws IOException if and only if the Writer produces an IOException
*/
public final void translate(CharSequence input, Writer out) throws IOException {
if (out == null) {
throw new IllegalArgumentException("The Writer must not be null");
}
if (input == null) {
return;
}
int pos = 0;
int len = input.length();
while (pos < len) {
int consumed = translate(input, pos, out);
if (consumed == 0) {
char[] c = Character.toChars(Character.codePointAt(input, pos));
out.write(c);
pos+= c.length;
continue;
}
// // contract with translators is that they have to understand codepoints
// // and they just took care of a surrogate pair
for (int pt = 0; pt < consumed; pt++) {
pos += Character.charCount(Character.codePointAt(input, pt));
}
}
}
```
| public final void translate(CharSequence input, Writer out) throws IOException {
if (out == null) {
throw new IllegalArgumentException("The Writer must not be null");
}
if (input == null) {
return;
}
int pos = 0;
int len = input.length();
while (pos < len) {
int consumed = translate(input, pos, out);
if (consumed == 0) {
char[] c = Character.toChars(Character.codePointAt(input, pos));
out.write(c);
pos+= c.length;
continue;
}
// // contract with translators is that they have to understand codepoints
// // and they just took care of a surrogate pair
for (int pt = 0; pt < consumed; pt++) {
pos += Character.charCount(Character.codePointAt(input, pt));
}
}
} | false | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Translate an input onto a Writer. This is intentionally final as its algorithm is
* tightly coupled with the abstract method of this class.
*
* @param input CharSequence that is being translated
* @param out Writer to translate the text to
* @throws IOException if and only if the Writer produces an IOException
*/
public final void translate(CharSequence input, Writer out) throws IOException {
if (out == null) {
throw new IllegalArgumentException("The Writer must not be null");
}
if (input == null) {
return;
}
int pos = 0;
int len = input.length();
while (pos < len) {
int consumed = translate(input, pos, out);
if (consumed == 0) {
char[] c = Character.toChars(Character.codePointAt(input, pos));
out.write(c);
pos+= c.length;
continue;
}
// // contract with translators is that they have to understand codepoints
// // and they just took care of a surrogate pair
for (int pt = 0; pt < consumed; pt++) {
pos += Character.charCount(Character.codePointAt(input, pt));
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
74 | 4782684d7c42a7d52ef57ce8fafa8f64774d9fe95d1860b14803c286e24c1607 | @SuppressWarnings("resource")
protected Object _deserializeTypedUsingDefaultImpl(JsonParser p, DeserializationContext ctxt,
TokenBuffer tb) throws IOException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
// off-lined to keep main method lean and mean...
@SuppressWarnings("resource")
protected Object _deserializeTypedUsingDefaultImpl(JsonParser p, DeserializationContext ctxt,
TokenBuffer tb) throws IOException
{
// As per [JACKSON-614], may have default implementation to use
JsonDeserializer<Object> deser = _findDefaultImplDeserializer(ctxt);
if (deser != null) {
if (tb != null) {
tb.writeEndObject();
p = tb.asParser(p);
// must move to point to the first token:
p.nextToken();
}
return deser.deserialize(p, ctxt);
}
// or, perhaps we just bumped into a "natural" value (boolean/int/double/String)?
Object result = TypeDeserializer.deserializeIfNatural(p, ctxt, _baseType);
if (result != null) {
return result;
}
// or, something for which "as-property" won't work, changed into "wrapper-array" type:
if (p.getCurrentToken() == JsonToken.START_ARRAY) {
return super.deserializeTypedFromAny(p, ctxt);
}
ctxt.reportWrongTokenException(p, JsonToken.FIELD_NAME,
"missing property '"+_typePropertyName+"' that is to contain type id (for class "+baseTypeName()+")");
return null;
}
```
| @SuppressWarnings("resource")
protected Object _deserializeTypedUsingDefaultImpl(JsonParser p, DeserializationContext ctxt,
TokenBuffer tb) throws IOException
{
// As per [JACKSON-614], may have default implementation to use
JsonDeserializer<Object> deser = _findDefaultImplDeserializer(ctxt);
if (deser != null) {
if (tb != null) {
tb.writeEndObject();
p = tb.asParser(p);
// must move to point to the first token:
p.nextToken();
}
return deser.deserialize(p, ctxt);
}
// or, perhaps we just bumped into a "natural" value (boolean/int/double/String)?
Object result = TypeDeserializer.deserializeIfNatural(p, ctxt, _baseType);
if (result != null) {
return result;
}
// or, something for which "as-property" won't work, changed into "wrapper-array" type:
if (p.getCurrentToken() == JsonToken.START_ARRAY) {
return super.deserializeTypedFromAny(p, ctxt);
}
ctxt.reportWrongTokenException(p, JsonToken.FIELD_NAME,
"missing property '"+_typePropertyName+"' that is to contain type id (for class "+baseTypeName()+")");
return null;
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
// off-lined to keep main method lean and mean...
@SuppressWarnings("resource")
protected Object _deserializeTypedUsingDefaultImpl(JsonParser p, DeserializationContext ctxt,
TokenBuffer tb) throws IOException
{
// As per [JACKSON-614], may have default implementation to use
JsonDeserializer<Object> deser = _findDefaultImplDeserializer(ctxt);
if (deser != null) {
if (tb != null) {
tb.writeEndObject();
p = tb.asParser(p);
// must move to point to the first token:
p.nextToken();
}
return deser.deserialize(p, ctxt);
}
// or, perhaps we just bumped into a "natural" value (boolean/int/double/String)?
Object result = TypeDeserializer.deserializeIfNatural(p, ctxt, _baseType);
if (result != null) {
return result;
}
// or, something for which "as-property" won't work, changed into "wrapper-array" type:
if (p.getCurrentToken() == JsonToken.START_ARRAY) {
return super.deserializeTypedFromAny(p, ctxt);
}
ctxt.reportWrongTokenException(p, JsonToken.FIELD_NAME,
"missing property '"+_typePropertyName+"' that is to contain type id (for class "+baseTypeName()+")");
return null;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
30 | 479fb1427cbe58db4e173b0cc02d8b1b907653e0220690d4997d3ddb060767bc | private double calculateAsymptoticPValue(final double Umin,
final int n1,
final int n2)
throws ConvergenceException, MaxCountExceededException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* @param Umin smallest Mann-Whitney U value
* @param n1 number of subjects in first sample
* @param n2 number of subjects in second sample
* @return two-sided asymptotic p-value
* @throws ConvergenceException if the p-value can not be computed
* due to a convergence error
* @throws MaxCountExceededException if the maximum number of
* iterations is exceeded
*/
private double calculateAsymptoticPValue(final double Umin,
final int n1,
final int n2)
throws ConvergenceException, MaxCountExceededException {
final int n1n2prod = n1 * n2;
// http://en.wikipedia.org/wiki/Mann%E2%80%93Whitney_U#Normal_approximation
final double EU = n1n2prod / 2.0;
final double VarU = n1n2prod * (n1 + n2 + 1) / 12.0;
final double z = (Umin - EU) / FastMath.sqrt(VarU);
final NormalDistribution standardNormal = new NormalDistribution(0, 1);
return 2 * standardNormal.cumulativeProbability(z);
}
```
| private double calculateAsymptoticPValue(final double Umin,
final int n1,
final int n2)
throws ConvergenceException, MaxCountExceededException {
final int n1n2prod = n1 * n2;
// http://en.wikipedia.org/wiki/Mann%E2%80%93Whitney_U#Normal_approximation
final double EU = n1n2prod / 2.0;
final double VarU = n1n2prod * (n1 + n2 + 1) / 12.0;
final double z = (Umin - EU) / FastMath.sqrt(VarU);
final NormalDistribution standardNormal = new NormalDistribution(0, 1);
return 2 * standardNormal.cumulativeProbability(z);
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* @param Umin smallest Mann-Whitney U value
* @param n1 number of subjects in first sample
* @param n2 number of subjects in second sample
* @return two-sided asymptotic p-value
* @throws ConvergenceException if the p-value can not be computed
* due to a convergence error
* @throws MaxCountExceededException if the maximum number of
* iterations is exceeded
*/
private double calculateAsymptoticPValue(final double Umin,
final int n1,
final int n2)
throws ConvergenceException, MaxCountExceededException {
final int n1n2prod = n1 * n2;
// http://en.wikipedia.org/wiki/Mann%E2%80%93Whitney_U#Normal_approximation
final double EU = n1n2prod / 2.0;
final double VarU = n1n2prod * (n1 + n2 + 1) / 12.0;
final double z = (Umin - EU) / FastMath.sqrt(VarU);
final NormalDistribution standardNormal = new NormalDistribution(0, 1);
return 2 * standardNormal.cumulativeProbability(z);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
17 | 47bca00d947a8c6e455dd089e895ceed780f1e04c78a1d9d640884abdf256539 | private JSType getDeclaredType(String sourceName, JSDocInfo info,
Node lValue, @Nullable Node rValue) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Look for a type declaration on a property assignment
* (in an ASSIGN or an object literal key).
*
* @param info The doc info for this property.
* @param lValue The l-value node.
* @param rValue The node that {@code n} is being initialized to,
* or {@code null} if this is a stub declaration.
*/
private JSType getDeclaredType(String sourceName, JSDocInfo info,
Node lValue, @Nullable Node rValue) {
if (info != null && info.hasType()) {
return getDeclaredTypeInAnnotation(sourceName, lValue, info);
} else if (rValue != null && rValue.isFunction() &&
shouldUseFunctionLiteralType(
JSType.toMaybeFunctionType(rValue.getJSType()), info, lValue)) {
return rValue.getJSType();
} else if (info != null) {
if (info.hasEnumParameterType()) {
if (rValue != null && rValue.isObjectLit()) {
return rValue.getJSType();
} else {
return createEnumTypeFromNodes(
rValue, lValue.getQualifiedName(), info, lValue);
}
} else if (info.isConstructor() || info.isInterface()) {
return createFunctionTypeFromNodes(
rValue, lValue.getQualifiedName(), info, lValue);
} else {
// Check if this is constant, and if it has a known type.
if (info.isConstant()) {
JSType knownType = null;
if (rValue != null) {
JSDocInfo rValueInfo = rValue.getJSDocInfo();
if (rValueInfo != null && rValueInfo.hasType()) {
// If rValue has a type-cast, we use the type in the type-cast.
return rValueInfo.getType().evaluate(scope, typeRegistry);
} else if (rValue.getJSType() != null
&& !rValue.getJSType().isUnknownType()) {
// If rValue's type was already computed during scope creation,
// then we can safely use that.
return rValue.getJSType();
} else if (rValue.isOr()) {
// Check for a very specific JS idiom:
// var x = x || TYPE;
// This is used by Closure's base namespace for esoteric
// reasons.
Node firstClause = rValue.getFirstChild();
Node secondClause = firstClause.getNext();
boolean namesMatch = firstClause.isName()
&& lValue.isName()
&& firstClause.getString().equals(lValue.getString());
if (namesMatch && secondClause.getJSType() != null
&& !secondClause.getJSType().isUnknownType()) {
return secondClause.getJSType();
}
}
}
}
}
}
return getDeclaredTypeInAnnotation(sourceName, lValue, info);
}
```
| private JSType getDeclaredType(String sourceName, JSDocInfo info,
Node lValue, @Nullable Node rValue) {
if (info != null && info.hasType()) {
return getDeclaredTypeInAnnotation(sourceName, lValue, info);
} else if (rValue != null && rValue.isFunction() &&
shouldUseFunctionLiteralType(
JSType.toMaybeFunctionType(rValue.getJSType()), info, lValue)) {
return rValue.getJSType();
} else if (info != null) {
if (info.hasEnumParameterType()) {
if (rValue != null && rValue.isObjectLit()) {
return rValue.getJSType();
} else {
return createEnumTypeFromNodes(
rValue, lValue.getQualifiedName(), info, lValue);
}
} else if (info.isConstructor() || info.isInterface()) {
return createFunctionTypeFromNodes(
rValue, lValue.getQualifiedName(), info, lValue);
} else {
// Check if this is constant, and if it has a known type.
if (info.isConstant()) {
JSType knownType = null;
if (rValue != null) {
JSDocInfo rValueInfo = rValue.getJSDocInfo();
if (rValueInfo != null && rValueInfo.hasType()) {
// If rValue has a type-cast, we use the type in the type-cast.
return rValueInfo.getType().evaluate(scope, typeRegistry);
} else if (rValue.getJSType() != null
&& !rValue.getJSType().isUnknownType()) {
// If rValue's type was already computed during scope creation,
// then we can safely use that.
return rValue.getJSType();
} else if (rValue.isOr()) {
// Check for a very specific JS idiom:
// var x = x || TYPE;
// This is used by Closure's base namespace for esoteric
// reasons.
Node firstClause = rValue.getFirstChild();
Node secondClause = firstClause.getNext();
boolean namesMatch = firstClause.isName()
&& lValue.isName()
&& firstClause.getString().equals(lValue.getString());
if (namesMatch && secondClause.getJSType() != null
&& !secondClause.getJSType().isUnknownType()) {
return secondClause.getJSType();
}
}
}
}
}
}
return getDeclaredTypeInAnnotation(sourceName, lValue, info);
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Look for a type declaration on a property assignment
* (in an ASSIGN or an object literal key).
*
* @param info The doc info for this property.
* @param lValue The l-value node.
* @param rValue The node that {@code n} is being initialized to,
* or {@code null} if this is a stub declaration.
*/
private JSType getDeclaredType(String sourceName, JSDocInfo info,
Node lValue, @Nullable Node rValue) {
if (info != null && info.hasType()) {
return getDeclaredTypeInAnnotation(sourceName, lValue, info);
} else if (rValue != null && rValue.isFunction() &&
shouldUseFunctionLiteralType(
JSType.toMaybeFunctionType(rValue.getJSType()), info, lValue)) {
return rValue.getJSType();
} else if (info != null) {
if (info.hasEnumParameterType()) {
if (rValue != null && rValue.isObjectLit()) {
return rValue.getJSType();
} else {
return createEnumTypeFromNodes(
rValue, lValue.getQualifiedName(), info, lValue);
}
} else if (info.isConstructor() || info.isInterface()) {
return createFunctionTypeFromNodes(
rValue, lValue.getQualifiedName(), info, lValue);
} else {
// Check if this is constant, and if it has a known type.
if (info.isConstant()) {
JSType knownType = null;
if (rValue != null) {
JSDocInfo rValueInfo = rValue.getJSDocInfo();
if (rValueInfo != null && rValueInfo.hasType()) {
// If rValue has a type-cast, we use the type in the type-cast.
return rValueInfo.getType().evaluate(scope, typeRegistry);
} else if (rValue.getJSType() != null
&& !rValue.getJSType().isUnknownType()) {
// If rValue's type was already computed during scope creation,
// then we can safely use that.
return rValue.getJSType();
} else if (rValue.isOr()) {
// Check for a very specific JS idiom:
// var x = x || TYPE;
// This is used by Closure's base namespace for esoteric
// reasons.
Node firstClause = rValue.getFirstChild();
Node secondClause = firstClause.getNext();
boolean namesMatch = firstClause.isName()
&& lValue.isName()
&& firstClause.getString().equals(lValue.getString());
if (namesMatch && secondClause.getJSType() != null
&& !secondClause.getJSType().isUnknownType()) {
return secondClause.getJSType();
}
}
}
}
}
}
return getDeclaredTypeInAnnotation(sourceName, lValue, info);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
14 | 4841ee0ed4be8b1a8658e79e686722bb9efe4d8700446004b9ae3af2a9c128d5 | public int[] add(ReadablePartial partial, int fieldIndex, int[] values, int valueToAdd) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
//-----------------------------------------------------------------------
public int[] add(ReadablePartial partial, int fieldIndex, int[] values, int valueToAdd) {
// overridden as superclass algorithm can't handle
// 2004-02-29 + 48 months -> 2008-02-29 type dates
if (valueToAdd == 0) {
return values;
}
// month is largest field and being added to, such as month-day
if (DateTimeUtils.isContiguous(partial)) {
long instant = 0L;
for (int i = 0, isize = partial.size(); i < isize; i++) {
instant = partial.getFieldType(i).getField(iChronology).set(instant, values[i]);
}
instant = add(instant, valueToAdd);
return iChronology.get(partial, instant);
} else {
return super.add(partial, fieldIndex, values, valueToAdd);
}
}
```
| public int[] add(ReadablePartial partial, int fieldIndex, int[] values, int valueToAdd) {
// overridden as superclass algorithm can't handle
// 2004-02-29 + 48 months -> 2008-02-29 type dates
if (valueToAdd == 0) {
return values;
}
// month is largest field and being added to, such as month-day
if (DateTimeUtils.isContiguous(partial)) {
long instant = 0L;
for (int i = 0, isize = partial.size(); i < isize; i++) {
instant = partial.getFieldType(i).getField(iChronology).set(instant, values[i]);
}
instant = add(instant, valueToAdd);
return iChronology.get(partial, instant);
} else {
return super.add(partial, fieldIndex, values, valueToAdd);
}
} | true | Time | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
//-----------------------------------------------------------------------
public int[] add(ReadablePartial partial, int fieldIndex, int[] values, int valueToAdd) {
// overridden as superclass algorithm can't handle
// 2004-02-29 + 48 months -> 2008-02-29 type dates
if (valueToAdd == 0) {
return values;
}
// month is largest field and being added to, such as month-day
if (DateTimeUtils.isContiguous(partial)) {
long instant = 0L;
for (int i = 0, isize = partial.size(); i < isize; i++) {
instant = partial.getFieldType(i).getField(iChronology).set(instant, values[i]);
}
instant = add(instant, valueToAdd);
return iChronology.get(partial, instant);
} else {
return super.add(partial, fieldIndex, values, valueToAdd);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
84 | 488f995e5f16497f45faba5a06a993325d32815a4e7e920ccec8c27e3027fecd | public void head(org.jsoup.nodes.Node source, int depth) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public void head(org.jsoup.nodes.Node source, int depth) {
namespacesStack.push(new HashMap<>(namespacesStack.peek())); // inherit from above on the stack
if (source instanceof org.jsoup.nodes.Element) {
org.jsoup.nodes.Element sourceEl = (org.jsoup.nodes.Element) source;
String prefix = updateNamespaces(sourceEl);
String namespace = namespacesStack.peek().get(prefix);
String tagName = sourceEl.tagName();
Element el =
doc.createElementNS(namespace, tagName);
copyAttributes(sourceEl, el);
if (dest == null) { // sets up the root
doc.appendChild(el);
} else {
dest.appendChild(el);
}
dest = el; // descend
} else if (source instanceof org.jsoup.nodes.TextNode) {
org.jsoup.nodes.TextNode sourceText = (org.jsoup.nodes.TextNode) source;
Text text = doc.createTextNode(sourceText.getWholeText());
dest.appendChild(text);
} else if (source instanceof org.jsoup.nodes.Comment) {
org.jsoup.nodes.Comment sourceComment = (org.jsoup.nodes.Comment) source;
Comment comment = doc.createComment(sourceComment.getData());
dest.appendChild(comment);
} else if (source instanceof org.jsoup.nodes.DataNode) {
org.jsoup.nodes.DataNode sourceData = (org.jsoup.nodes.DataNode) source;
Text node = doc.createTextNode(sourceData.getWholeData());
dest.appendChild(node);
} else {
// unhandled
}
}
```
| public void head(org.jsoup.nodes.Node source, int depth) {
namespacesStack.push(new HashMap<>(namespacesStack.peek())); // inherit from above on the stack
if (source instanceof org.jsoup.nodes.Element) {
org.jsoup.nodes.Element sourceEl = (org.jsoup.nodes.Element) source;
String prefix = updateNamespaces(sourceEl);
String namespace = namespacesStack.peek().get(prefix);
String tagName = sourceEl.tagName();
Element el =
doc.createElementNS(namespace, tagName);
copyAttributes(sourceEl, el);
if (dest == null) { // sets up the root
doc.appendChild(el);
} else {
dest.appendChild(el);
}
dest = el; // descend
} else if (source instanceof org.jsoup.nodes.TextNode) {
org.jsoup.nodes.TextNode sourceText = (org.jsoup.nodes.TextNode) source;
Text text = doc.createTextNode(sourceText.getWholeText());
dest.appendChild(text);
} else if (source instanceof org.jsoup.nodes.Comment) {
org.jsoup.nodes.Comment sourceComment = (org.jsoup.nodes.Comment) source;
Comment comment = doc.createComment(sourceComment.getData());
dest.appendChild(comment);
} else if (source instanceof org.jsoup.nodes.DataNode) {
org.jsoup.nodes.DataNode sourceData = (org.jsoup.nodes.DataNode) source;
Text node = doc.createTextNode(sourceData.getWholeData());
dest.appendChild(node);
} else {
// unhandled
}
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public void head(org.jsoup.nodes.Node source, int depth) {
namespacesStack.push(new HashMap<>(namespacesStack.peek())); // inherit from above on the stack
if (source instanceof org.jsoup.nodes.Element) {
org.jsoup.nodes.Element sourceEl = (org.jsoup.nodes.Element) source;
String prefix = updateNamespaces(sourceEl);
String namespace = namespacesStack.peek().get(prefix);
String tagName = sourceEl.tagName();
Element el =
doc.createElementNS(namespace, tagName);
copyAttributes(sourceEl, el);
if (dest == null) { // sets up the root
doc.appendChild(el);
} else {
dest.appendChild(el);
}
dest = el; // descend
} else if (source instanceof org.jsoup.nodes.TextNode) {
org.jsoup.nodes.TextNode sourceText = (org.jsoup.nodes.TextNode) source;
Text text = doc.createTextNode(sourceText.getWholeText());
dest.appendChild(text);
} else if (source instanceof org.jsoup.nodes.Comment) {
org.jsoup.nodes.Comment sourceComment = (org.jsoup.nodes.Comment) source;
Comment comment = doc.createComment(sourceComment.getData());
dest.appendChild(comment);
} else if (source instanceof org.jsoup.nodes.DataNode) {
org.jsoup.nodes.DataNode sourceData = (org.jsoup.nodes.DataNode) source;
Text node = doc.createTextNode(sourceData.getWholeData());
dest.appendChild(node);
} else {
// unhandled
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
3 | 48d00d82b8b334c8be4493bd96ccacf7eedf86b4bf21fadb3d0abbc38b6dcbfd | @Override
public String nextTextValue() throws IOException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Method overridden to support more reliable deserialization of
* String collections.
*/
/*
/**********************************************************
/* Overrides of specialized nextXxx() methods
/**********************************************************
*/
@Override
public String nextTextValue() throws IOException
{
_binaryValue = null;
if (_nextToken != null) {
JsonToken t = _nextToken;
_currToken = t;
_nextToken = null;
// expected case; yes, got a String
if (t == JsonToken.VALUE_STRING) {
return _currText;
}
_updateState(t);
return null;
}
int token = _xmlTokens.next();
// mostly copied from 'nextToken()'
while (token == XmlTokenStream.XML_START_ELEMENT) {
if (_mayBeLeaf) {
_nextToken = JsonToken.FIELD_NAME;
_parsingContext = _parsingContext.createChildObjectContext(-1, -1);
_currToken = JsonToken.START_OBJECT;
return null;
}
if (_parsingContext.inArray()) {
token = _xmlTokens.next();
_mayBeLeaf = true;
continue;
}
String name = _xmlTokens.getLocalName();
_parsingContext.setCurrentName(name);
if (_namesToWrap != null && _namesToWrap.contains(name)) {
_xmlTokens.repeatStartElement();
}
_mayBeLeaf = true;
_currToken = JsonToken.FIELD_NAME;
return null;
}
// Ok; beyond start element, what do we get?
switch (token) {
case XmlTokenStream.XML_END_ELEMENT:
if (_mayBeLeaf) {
// NOTE: this is different from nextToken() -- produce "", NOT null
_mayBeLeaf = false;
_currToken = JsonToken.VALUE_STRING;
return (_currText = "");
}
_currToken = _parsingContext.inArray() ? JsonToken.END_ARRAY : JsonToken.END_OBJECT;
_parsingContext = _parsingContext.getParent();
_namesToWrap = _parsingContext.getNamesToWrap();
break;
case XmlTokenStream.XML_ATTRIBUTE_NAME:
// If there was a chance of leaf node, no more...
if (_mayBeLeaf) {
_mayBeLeaf = false;
_nextToken = JsonToken.FIELD_NAME;
_currText = _xmlTokens.getText();
_parsingContext = _parsingContext.createChildObjectContext(-1, -1);
_currToken = JsonToken.START_OBJECT;
} else {
_parsingContext.setCurrentName(_xmlTokens.getLocalName());
_currToken = JsonToken.FIELD_NAME;
}
break;
case XmlTokenStream.XML_ATTRIBUTE_VALUE:
_currText = _xmlTokens.getText();
_currToken = JsonToken.VALUE_STRING;
break;
case XmlTokenStream.XML_TEXT:
_currText = _xmlTokens.getText();
if (_mayBeLeaf) {
_mayBeLeaf = false;
// Also: must skip following END_ELEMENT
_xmlTokens.skipEndElement();
// NOTE: this is different from nextToken() -- NO work-around
// for otherwise empty List/array
_currToken = JsonToken.VALUE_STRING;
return _currText;
}
// If not a leaf, need to transform into property...
_parsingContext.setCurrentName(_cfgNameForTextElement);
_nextToken = JsonToken.VALUE_STRING;
_currToken = JsonToken.FIELD_NAME;
break;
case XmlTokenStream.XML_END:
_currToken = null;
}
return null;
}
```
| @Override
public String nextTextValue() throws IOException
{
_binaryValue = null;
if (_nextToken != null) {
JsonToken t = _nextToken;
_currToken = t;
_nextToken = null;
// expected case; yes, got a String
if (t == JsonToken.VALUE_STRING) {
return _currText;
}
_updateState(t);
return null;
}
int token = _xmlTokens.next();
// mostly copied from 'nextToken()'
while (token == XmlTokenStream.XML_START_ELEMENT) {
if (_mayBeLeaf) {
_nextToken = JsonToken.FIELD_NAME;
_parsingContext = _parsingContext.createChildObjectContext(-1, -1);
_currToken = JsonToken.START_OBJECT;
return null;
}
if (_parsingContext.inArray()) {
token = _xmlTokens.next();
_mayBeLeaf = true;
continue;
}
String name = _xmlTokens.getLocalName();
_parsingContext.setCurrentName(name);
if (_namesToWrap != null && _namesToWrap.contains(name)) {
_xmlTokens.repeatStartElement();
}
_mayBeLeaf = true;
_currToken = JsonToken.FIELD_NAME;
return null;
}
// Ok; beyond start element, what do we get?
switch (token) {
case XmlTokenStream.XML_END_ELEMENT:
if (_mayBeLeaf) {
// NOTE: this is different from nextToken() -- produce "", NOT null
_mayBeLeaf = false;
_currToken = JsonToken.VALUE_STRING;
return (_currText = "");
}
_currToken = _parsingContext.inArray() ? JsonToken.END_ARRAY : JsonToken.END_OBJECT;
_parsingContext = _parsingContext.getParent();
_namesToWrap = _parsingContext.getNamesToWrap();
break;
case XmlTokenStream.XML_ATTRIBUTE_NAME:
// If there was a chance of leaf node, no more...
if (_mayBeLeaf) {
_mayBeLeaf = false;
_nextToken = JsonToken.FIELD_NAME;
_currText = _xmlTokens.getText();
_parsingContext = _parsingContext.createChildObjectContext(-1, -1);
_currToken = JsonToken.START_OBJECT;
} else {
_parsingContext.setCurrentName(_xmlTokens.getLocalName());
_currToken = JsonToken.FIELD_NAME;
}
break;
case XmlTokenStream.XML_ATTRIBUTE_VALUE:
_currText = _xmlTokens.getText();
_currToken = JsonToken.VALUE_STRING;
break;
case XmlTokenStream.XML_TEXT:
_currText = _xmlTokens.getText();
if (_mayBeLeaf) {
_mayBeLeaf = false;
// Also: must skip following END_ELEMENT
_xmlTokens.skipEndElement();
// NOTE: this is different from nextToken() -- NO work-around
// for otherwise empty List/array
_currToken = JsonToken.VALUE_STRING;
return _currText;
}
// If not a leaf, need to transform into property...
_parsingContext.setCurrentName(_cfgNameForTextElement);
_nextToken = JsonToken.VALUE_STRING;
_currToken = JsonToken.FIELD_NAME;
break;
case XmlTokenStream.XML_END:
_currToken = null;
}
return null;
} | true | JacksonXml | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Method overridden to support more reliable deserialization of
* String collections.
*/
/*
/**********************************************************
/* Overrides of specialized nextXxx() methods
/**********************************************************
*/
@Override
public String nextTextValue() throws IOException
{
_binaryValue = null;
if (_nextToken != null) {
JsonToken t = _nextToken;
_currToken = t;
_nextToken = null;
// expected case; yes, got a String
if (t == JsonToken.VALUE_STRING) {
return _currText;
}
_updateState(t);
return null;
}
int token = _xmlTokens.next();
// mostly copied from 'nextToken()'
while (token == XmlTokenStream.XML_START_ELEMENT) {
if (_mayBeLeaf) {
_nextToken = JsonToken.FIELD_NAME;
_parsingContext = _parsingContext.createChildObjectContext(-1, -1);
_currToken = JsonToken.START_OBJECT;
return null;
}
if (_parsingContext.inArray()) {
token = _xmlTokens.next();
_mayBeLeaf = true;
continue;
}
String name = _xmlTokens.getLocalName();
_parsingContext.setCurrentName(name);
if (_namesToWrap != null && _namesToWrap.contains(name)) {
_xmlTokens.repeatStartElement();
}
_mayBeLeaf = true;
_currToken = JsonToken.FIELD_NAME;
return null;
}
// Ok; beyond start element, what do we get?
switch (token) {
case XmlTokenStream.XML_END_ELEMENT:
if (_mayBeLeaf) {
// NOTE: this is different from nextToken() -- produce "", NOT null
_mayBeLeaf = false;
_currToken = JsonToken.VALUE_STRING;
return (_currText = "");
}
_currToken = _parsingContext.inArray() ? JsonToken.END_ARRAY : JsonToken.END_OBJECT;
_parsingContext = _parsingContext.getParent();
_namesToWrap = _parsingContext.getNamesToWrap();
break;
case XmlTokenStream.XML_ATTRIBUTE_NAME:
// If there was a chance of leaf node, no more...
if (_mayBeLeaf) {
_mayBeLeaf = false;
_nextToken = JsonToken.FIELD_NAME;
_currText = _xmlTokens.getText();
_parsingContext = _parsingContext.createChildObjectContext(-1, -1);
_currToken = JsonToken.START_OBJECT;
} else {
_parsingContext.setCurrentName(_xmlTokens.getLocalName());
_currToken = JsonToken.FIELD_NAME;
}
break;
case XmlTokenStream.XML_ATTRIBUTE_VALUE:
_currText = _xmlTokens.getText();
_currToken = JsonToken.VALUE_STRING;
break;
case XmlTokenStream.XML_TEXT:
_currText = _xmlTokens.getText();
if (_mayBeLeaf) {
_mayBeLeaf = false;
// Also: must skip following END_ELEMENT
_xmlTokens.skipEndElement();
// NOTE: this is different from nextToken() -- NO work-around
// for otherwise empty List/array
_currToken = JsonToken.VALUE_STRING;
return _currText;
}
// If not a leaf, need to transform into property...
_parsingContext.setCurrentName(_cfgNameForTextElement);
_nextToken = JsonToken.VALUE_STRING;
_currToken = JsonToken.FIELD_NAME;
break;
case XmlTokenStream.XML_END:
_currToken = null;
}
return null;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
112 | 491aa043b8f794f713af19ab83fc53b29d13123a0c75fc81088acf87bc0dcead | @Override
public JsonDeserializer<?> createContextual(DeserializationContext ctxt,
BeanProperty property) throws JsonMappingException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/*
/**********************************************************
/* Validation, post-processing
/**********************************************************
*/
@Override
public JsonDeserializer<?> createContextual(DeserializationContext ctxt,
BeanProperty property) throws JsonMappingException
{
// May need to resolve types for delegate-based creators:
JsonDeserializer<Object> delegate = null;
if (_valueInstantiator != null) {
// [databind#2324]: check both array-delegating and delegating
AnnotatedWithParams delegateCreator = _valueInstantiator.getDelegateCreator();
if (delegateCreator != null) {
JavaType delegateType = _valueInstantiator.getDelegateType(ctxt.getConfig());
delegate = findDeserializer(ctxt, delegateType, property);
}
}
JsonDeserializer<?> valueDeser = _valueDeserializer;
final JavaType valueType = _containerType.getContentType();
if (valueDeser == null) {
// [databind#125]: May have a content converter
valueDeser = findConvertingContentDeserializer(ctxt, property, valueDeser);
if (valueDeser == null) {
// And we may also need to get deserializer for String
valueDeser = ctxt.findContextualValueDeserializer(valueType, property);
}
} else { // if directly assigned, probably not yet contextual, so:
valueDeser = ctxt.handleSecondaryContextualization(valueDeser, property, valueType);
}
// 11-Dec-2015, tatu: Should we pass basic `Collection.class`, or more refined? Mostly
// comes down to "List vs Collection" I suppose... for now, pass Collection
Boolean unwrapSingle = findFormatFeature(ctxt, property, Collection.class,
JsonFormat.Feature.ACCEPT_SINGLE_VALUE_AS_ARRAY);
NullValueProvider nuller = findContentNullProvider(ctxt, property, valueDeser);
if (isDefaultDeserializer(valueDeser)) {
valueDeser = null;
}
return withResolved(delegate, valueDeser, nuller, unwrapSingle);
}
```
| @Override
public JsonDeserializer<?> createContextual(DeserializationContext ctxt,
BeanProperty property) throws JsonMappingException
{
// May need to resolve types for delegate-based creators:
JsonDeserializer<Object> delegate = null;
if (_valueInstantiator != null) {
// [databind#2324]: check both array-delegating and delegating
AnnotatedWithParams delegateCreator = _valueInstantiator.getDelegateCreator();
if (delegateCreator != null) {
JavaType delegateType = _valueInstantiator.getDelegateType(ctxt.getConfig());
delegate = findDeserializer(ctxt, delegateType, property);
}
}
JsonDeserializer<?> valueDeser = _valueDeserializer;
final JavaType valueType = _containerType.getContentType();
if (valueDeser == null) {
// [databind#125]: May have a content converter
valueDeser = findConvertingContentDeserializer(ctxt, property, valueDeser);
if (valueDeser == null) {
// And we may also need to get deserializer for String
valueDeser = ctxt.findContextualValueDeserializer(valueType, property);
}
} else { // if directly assigned, probably not yet contextual, so:
valueDeser = ctxt.handleSecondaryContextualization(valueDeser, property, valueType);
}
// 11-Dec-2015, tatu: Should we pass basic `Collection.class`, or more refined? Mostly
// comes down to "List vs Collection" I suppose... for now, pass Collection
Boolean unwrapSingle = findFormatFeature(ctxt, property, Collection.class,
JsonFormat.Feature.ACCEPT_SINGLE_VALUE_AS_ARRAY);
NullValueProvider nuller = findContentNullProvider(ctxt, property, valueDeser);
if (isDefaultDeserializer(valueDeser)) {
valueDeser = null;
}
return withResolved(delegate, valueDeser, nuller, unwrapSingle);
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/*
/**********************************************************
/* Validation, post-processing
/**********************************************************
*/
@Override
public JsonDeserializer<?> createContextual(DeserializationContext ctxt,
BeanProperty property) throws JsonMappingException
{
// May need to resolve types for delegate-based creators:
JsonDeserializer<Object> delegate = null;
if (_valueInstantiator != null) {
// [databind#2324]: check both array-delegating and delegating
AnnotatedWithParams delegateCreator = _valueInstantiator.getDelegateCreator();
if (delegateCreator != null) {
JavaType delegateType = _valueInstantiator.getDelegateType(ctxt.getConfig());
delegate = findDeserializer(ctxt, delegateType, property);
}
}
JsonDeserializer<?> valueDeser = _valueDeserializer;
final JavaType valueType = _containerType.getContentType();
if (valueDeser == null) {
// [databind#125]: May have a content converter
valueDeser = findConvertingContentDeserializer(ctxt, property, valueDeser);
if (valueDeser == null) {
// And we may also need to get deserializer for String
valueDeser = ctxt.findContextualValueDeserializer(valueType, property);
}
} else { // if directly assigned, probably not yet contextual, so:
valueDeser = ctxt.handleSecondaryContextualization(valueDeser, property, valueType);
}
// 11-Dec-2015, tatu: Should we pass basic `Collection.class`, or more refined? Mostly
// comes down to "List vs Collection" I suppose... for now, pass Collection
Boolean unwrapSingle = findFormatFeature(ctxt, property, Collection.class,
JsonFormat.Feature.ACCEPT_SINGLE_VALUE_AS_ARRAY);
NullValueProvider nuller = findContentNullProvider(ctxt, property, valueDeser);
if (isDefaultDeserializer(valueDeser)) {
valueDeser = null;
}
return withResolved(delegate, valueDeser, nuller, unwrapSingle);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
27 | 499465725cfeeea6d8fa1be0c091c8d20133663cb1a16495da87ef72a0ab3f1d | static String getCharsetFromContentType(String contentType) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Parse out a charset from a content type header. If the charset is not supported, returns null (so the default
* will kick in.)
* @param contentType e.g. "text/html; charset=EUC-JP"
* @return "EUC-JP", or null if not found. Charset is trimmed and uppercased.
*/
static String getCharsetFromContentType(String contentType) {
if (contentType == null) return null;
Matcher m = charsetPattern.matcher(contentType);
if (m.find()) {
String charset = m.group(1).trim();
charset = charset.toUpperCase(Locale.ENGLISH);
return charset;
}
return null;
}
```
| static String getCharsetFromContentType(String contentType) {
if (contentType == null) return null;
Matcher m = charsetPattern.matcher(contentType);
if (m.find()) {
String charset = m.group(1).trim();
charset = charset.toUpperCase(Locale.ENGLISH);
return charset;
}
return null;
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Parse out a charset from a content type header. If the charset is not supported, returns null (so the default
* will kick in.)
* @param contentType e.g. "text/html; charset=EUC-JP"
* @return "EUC-JP", or null if not found. Charset is trimmed and uppercased.
*/
static String getCharsetFromContentType(String contentType) {
if (contentType == null) return null;
Matcher m = charsetPattern.matcher(contentType);
if (m.find()) {
String charset = m.group(1).trim();
charset = charset.toUpperCase(Locale.ENGLISH);
return charset;
}
return null;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
131 | 4a2a1450f5078cb75b1aac3a1484093b3a28dab55ceed894e4d330a479cf6e1e | public static boolean isJSIdentifier(String s) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public static boolean isJSIdentifier(String s) {
int length = s.length();
if (length == 0 ||
Character.isIdentifierIgnorable(s.charAt(0)) ||
!Character.isJavaIdentifierStart(s.charAt(0))) {
return false;
}
for (int i = 1; i < length; i++) {
if (Character.isIdentifierIgnorable(s.charAt(i)) ||
!Character.isJavaIdentifierPart(s.charAt(i))) {
return false;
}
}
return true;
}
```
| public static boolean isJSIdentifier(String s) {
int length = s.length();
if (length == 0 ||
Character.isIdentifierIgnorable(s.charAt(0)) ||
!Character.isJavaIdentifierStart(s.charAt(0))) {
return false;
}
for (int i = 1; i < length; i++) {
if (Character.isIdentifierIgnorable(s.charAt(i)) ||
!Character.isJavaIdentifierPart(s.charAt(i))) {
return false;
}
}
return true;
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public static boolean isJSIdentifier(String s) {
int length = s.length();
if (length == 0 ||
Character.isIdentifierIgnorable(s.charAt(0)) ||
!Character.isJavaIdentifierStart(s.charAt(0))) {
return false;
}
for (int i = 1; i < length; i++) {
if (Character.isIdentifierIgnorable(s.charAt(i)) ||
!Character.isJavaIdentifierPart(s.charAt(i))) {
return false;
}
}
return true;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
11 | 4ae750cfadb8cf9890cf6d7cc0c7ef400f34c36b52feeb78c911a5926b4e5ac0 | private Map<String, Integer> initializeHeader() throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Initializes the name to index mapping if the format defines a header.
*
* @return null if the format has no header.
* @throws IOException if there is a problem reading the header or skipping the first record
*/
private Map<String, Integer> initializeHeader() throws IOException {
Map<String, Integer> hdrMap = null;
final String[] formatHeader = this.format.getHeader();
if (formatHeader != null) {
hdrMap = new LinkedHashMap<String, Integer>();
String[] headerRecord = null;
if (formatHeader.length == 0) {
// read the header from the first line of the file
final CSVRecord nextRecord = this.nextRecord();
if (nextRecord != null) {
headerRecord = nextRecord.values();
}
} else {
if (this.format.getSkipHeaderRecord()) {
this.nextRecord();
}
headerRecord = formatHeader;
}
// build the name to index mappings
if (headerRecord != null) {
for (int i = 0; i < headerRecord.length; i++) {
final String header = headerRecord[i];
final boolean containsHeader = hdrMap.containsKey(header);
final boolean emptyHeader = header == null || header.trim().isEmpty();
if (containsHeader && (!emptyHeader || (emptyHeader && !this.format.getIgnoreEmptyHeaders()))) {
throw new IllegalArgumentException("The header contains a duplicate name: \"" + header +
"\" in " + Arrays.toString(headerRecord));
}
hdrMap.put(header, Integer.valueOf(i));
}
}
}
return hdrMap;
}
```
| private Map<String, Integer> initializeHeader() throws IOException {
Map<String, Integer> hdrMap = null;
final String[] formatHeader = this.format.getHeader();
if (formatHeader != null) {
hdrMap = new LinkedHashMap<String, Integer>();
String[] headerRecord = null;
if (formatHeader.length == 0) {
// read the header from the first line of the file
final CSVRecord nextRecord = this.nextRecord();
if (nextRecord != null) {
headerRecord = nextRecord.values();
}
} else {
if (this.format.getSkipHeaderRecord()) {
this.nextRecord();
}
headerRecord = formatHeader;
}
// build the name to index mappings
if (headerRecord != null) {
for (int i = 0; i < headerRecord.length; i++) {
final String header = headerRecord[i];
final boolean containsHeader = hdrMap.containsKey(header);
final boolean emptyHeader = header == null || header.trim().isEmpty();
if (containsHeader && (!emptyHeader || (emptyHeader && !this.format.getIgnoreEmptyHeaders()))) {
throw new IllegalArgumentException("The header contains a duplicate name: \"" + header +
"\" in " + Arrays.toString(headerRecord));
}
hdrMap.put(header, Integer.valueOf(i));
}
}
}
return hdrMap;
} | false | Csv | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Initializes the name to index mapping if the format defines a header.
*
* @return null if the format has no header.
* @throws IOException if there is a problem reading the header or skipping the first record
*/
private Map<String, Integer> initializeHeader() throws IOException {
Map<String, Integer> hdrMap = null;
final String[] formatHeader = this.format.getHeader();
if (formatHeader != null) {
hdrMap = new LinkedHashMap<String, Integer>();
String[] headerRecord = null;
if (formatHeader.length == 0) {
// read the header from the first line of the file
final CSVRecord nextRecord = this.nextRecord();
if (nextRecord != null) {
headerRecord = nextRecord.values();
}
} else {
if (this.format.getSkipHeaderRecord()) {
this.nextRecord();
}
headerRecord = formatHeader;
}
// build the name to index mappings
if (headerRecord != null) {
for (int i = 0; i < headerRecord.length; i++) {
final String header = headerRecord[i];
final boolean containsHeader = hdrMap.containsKey(header);
final boolean emptyHeader = header == null || header.trim().isEmpty();
if (containsHeader && (!emptyHeader || (emptyHeader && !this.format.getIgnoreEmptyHeaders()))) {
throw new IllegalArgumentException("The header contains a duplicate name: \"" + header +
"\" in " + Arrays.toString(headerRecord));
}
hdrMap.put(header, Integer.valueOf(i));
}
}
}
return hdrMap;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
21 | 4bd974ea0ace3b7700c19aa2cc6514631c9f2ebe2cdf21f23259a48e33d519c5 | @Override
public void visit(NodeTraversal t, Node n, Node parent) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public void visit(NodeTraversal t, Node n, Node parent) {
// VOID nodes appear when there are extra semicolons at the BLOCK level.
// I've been unable to think of any cases where this indicates a bug,
// and apparently some people like keeping these semicolons around,
// so we'll allow it.
if (n.isEmpty() ||
n.isComma()) {
return;
}
if (parent == null) {
return;
}
// Do not try to remove a block or an expr result. We already handle
// these cases when we visit the child, and the peephole passes will
// fix up the tree in more clever ways when these are removed.
if (n.isExprResult()) {
return;
}
// This no-op statement was there so that JSDoc information could
// be attached to the name. This check should not complain about it.
if (n.isQualifiedName() && n.getJSDocInfo() != null) {
return;
}
boolean isResultUsed = NodeUtil.isExpressionResultUsed(n);
boolean isSimpleOp = NodeUtil.isSimpleOperatorType(n.getType());
if (parent.getType() == Token.COMMA) {
if (isResultUsed) {
return;
}
if (n == parent.getLastChild()) {
for (Node an : parent.getAncestors()) {
int ancestorType = an.getType();
if (ancestorType == Token.COMMA) continue;
if (ancestorType != Token.EXPR_RESULT && ancestorType != Token.BLOCK) return;
else break;
}
}
} else if (parent.getType() != Token.EXPR_RESULT && parent.getType() != Token.BLOCK) {
if (! (parent.getType() == Token.FOR && parent.getChildCount() == 4 && (n == parent.getFirstChild() || n == parent.getFirstChild().getNext().getNext()))) {
return;
}
}
if (
(isSimpleOp || !NodeUtil.mayHaveSideEffects(n, t.getCompiler()))) {
String msg = "This code lacks side-effects. Is there a bug?";
if (n.isString()) {
msg = "Is there a missing '+' on the previous line?";
} else if (isSimpleOp) {
msg = "The result of the '" + Token.name(n.getType()).toLowerCase() +
"' operator is not being used.";
}
t.getCompiler().report(
t.makeError(n, level, USELESS_CODE_ERROR, msg));
// TODO(johnlenz): determine if it is necessary to
// try to protect side-effect free statements as well.
if (!NodeUtil.isStatement(n)) {
problemNodes.add(n);
}
}
}
```
| @Override
public void visit(NodeTraversal t, Node n, Node parent) {
// VOID nodes appear when there are extra semicolons at the BLOCK level.
// I've been unable to think of any cases where this indicates a bug,
// and apparently some people like keeping these semicolons around,
// so we'll allow it.
if (n.isEmpty() ||
n.isComma()) {
return;
}
if (parent == null) {
return;
}
// Do not try to remove a block or an expr result. We already handle
// these cases when we visit the child, and the peephole passes will
// fix up the tree in more clever ways when these are removed.
if (n.isExprResult()) {
return;
}
// This no-op statement was there so that JSDoc information could
// be attached to the name. This check should not complain about it.
if (n.isQualifiedName() && n.getJSDocInfo() != null) {
return;
}
boolean isResultUsed = NodeUtil.isExpressionResultUsed(n);
boolean isSimpleOp = NodeUtil.isSimpleOperatorType(n.getType());
if (parent.getType() == Token.COMMA) {
if (isResultUsed) {
return;
}
if (n == parent.getLastChild()) {
for (Node an : parent.getAncestors()) {
int ancestorType = an.getType();
if (ancestorType == Token.COMMA) continue;
if (ancestorType != Token.EXPR_RESULT && ancestorType != Token.BLOCK) return;
else break;
}
}
} else if (parent.getType() != Token.EXPR_RESULT && parent.getType() != Token.BLOCK) {
if (! (parent.getType() == Token.FOR && parent.getChildCount() == 4 && (n == parent.getFirstChild() || n == parent.getFirstChild().getNext().getNext()))) {
return;
}
}
if (
(isSimpleOp || !NodeUtil.mayHaveSideEffects(n, t.getCompiler()))) {
String msg = "This code lacks side-effects. Is there a bug?";
if (n.isString()) {
msg = "Is there a missing '+' on the previous line?";
} else if (isSimpleOp) {
msg = "The result of the '" + Token.name(n.getType()).toLowerCase() +
"' operator is not being used.";
}
t.getCompiler().report(
t.makeError(n, level, USELESS_CODE_ERROR, msg));
// TODO(johnlenz): determine if it is necessary to
// try to protect side-effect free statements as well.
if (!NodeUtil.isStatement(n)) {
problemNodes.add(n);
}
}
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public void visit(NodeTraversal t, Node n, Node parent) {
// VOID nodes appear when there are extra semicolons at the BLOCK level.
// I've been unable to think of any cases where this indicates a bug,
// and apparently some people like keeping these semicolons around,
// so we'll allow it.
if (n.isEmpty() ||
n.isComma()) {
return;
}
if (parent == null) {
return;
}
// Do not try to remove a block or an expr result. We already handle
// these cases when we visit the child, and the peephole passes will
// fix up the tree in more clever ways when these are removed.
if (n.isExprResult()) {
return;
}
// This no-op statement was there so that JSDoc information could
// be attached to the name. This check should not complain about it.
if (n.isQualifiedName() && n.getJSDocInfo() != null) {
return;
}
boolean isResultUsed = NodeUtil.isExpressionResultUsed(n);
boolean isSimpleOp = NodeUtil.isSimpleOperatorType(n.getType());
if (parent.getType() == Token.COMMA) {
if (isResultUsed) {
return;
}
if (n == parent.getLastChild()) {
for (Node an : parent.getAncestors()) {
int ancestorType = an.getType();
if (ancestorType == Token.COMMA) continue;
if (ancestorType != Token.EXPR_RESULT && ancestorType != Token.BLOCK) return;
else break;
}
}
} else if (parent.getType() != Token.EXPR_RESULT && parent.getType() != Token.BLOCK) {
if (! (parent.getType() == Token.FOR && parent.getChildCount() == 4 && (n == parent.getFirstChild() || n == parent.getFirstChild().getNext().getNext()))) {
return;
}
}
if (
(isSimpleOp || !NodeUtil.mayHaveSideEffects(n, t.getCompiler()))) {
String msg = "This code lacks side-effects. Is there a bug?";
if (n.isString()) {
msg = "Is there a missing '+' on the previous line?";
} else if (isSimpleOp) {
msg = "The result of the '" + Token.name(n.getType()).toLowerCase() +
"' operator is not being used.";
}
t.getCompiler().report(
t.makeError(n, level, USELESS_CODE_ERROR, msg));
// TODO(johnlenz): determine if it is necessary to
// try to protect side-effect free statements as well.
if (!NodeUtil.isStatement(n)) {
problemNodes.add(n);
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
16 | 4c3e8b99f1a9e6c99d29cd96a667f5c32933a78bfaa924e395db7c93b42766e1 | protected final boolean _add(Annotation ann) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/*
/**********************************************************
/* Helper methods
/**********************************************************
*/
protected final boolean _add(Annotation ann) {
if (_annotations == null) {
_annotations = new HashMap<Class<? extends Annotation>,Annotation>();
}
Annotation previous = _annotations.put(ann.annotationType(), ann);
return (previous != null) && previous.equals(ann);
}
```
| protected final boolean _add(Annotation ann) {
if (_annotations == null) {
_annotations = new HashMap<Class<? extends Annotation>,Annotation>();
}
Annotation previous = _annotations.put(ann.annotationType(), ann);
return (previous != null) && previous.equals(ann);
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/*
/**********************************************************
/* Helper methods
/**********************************************************
*/
protected final boolean _add(Annotation ann) {
if (_annotations == null) {
_annotations = new HashMap<Class<? extends Annotation>,Annotation>();
}
Annotation previous = _annotations.put(ann.annotationType(), ann);
return (previous != null) && previous.equals(ann);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
48 | 4d255105cdde2e31f3a58bae739422ca78e5848de1f0b93fd5833b06407a6d5d | void maybeDeclareQualifiedName(NodeTraversal t, JSDocInfo info,
Node n, Node parent, Node rhsValue) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Declare the symbol for a qualified name in the global scope.
*
* @param info The doc info for this property.
* @param n A top-level GETPROP node (it should not be contained inside
* another GETPROP).
* @param parent The parent of {@code n}.
* @param rhsValue The node that {@code n} is being initialized to,
* or {@code null} if this is a stub declaration.
*/
void maybeDeclareQualifiedName(NodeTraversal t, JSDocInfo info,
Node n, Node parent, Node rhsValue) {
Node ownerNode = n.getFirstChild();
String ownerName = ownerNode.getQualifiedName();
String qName = n.getQualifiedName();
String propName = n.getLastChild().getString();
Preconditions.checkArgument(qName != null && ownerName != null);
// Precedence of type information on GETPROPs:
// 1) @type annnotation / @enum annotation
// 2) ASSIGN to FUNCTION literal
// 3) @param/@return annotation (with no function literal)
// 4) ASSIGN to something marked @const
// 5) ASSIGN to anything else
//
// 1, 3, and 4 are declarations, 5 is inferred, and 2 is a declaration iff
// the function has jsdoc or has not been declared before.
//
// FUNCTION literals are special because TypedScopeCreator is very smart
// about getting as much type information as possible for them.
// Determining type for #1 + #2 + #3 + #4
JSType valueType = getDeclaredType(t.getSourceName(), info, n, rhsValue);
if (valueType == null && rhsValue != null) {
// Determining type for #5
valueType = rhsValue.getJSType();
}
// Function prototypes are special.
// It's a common JS idiom to do:
// F.prototype = { ... };
// So if F does not have an explicitly declared super type,
// allow F.prototype to be redefined arbitrarily.
if ("prototype".equals(propName)) {
Var qVar = scope.getVar(qName);
if (qVar != null) {
// If the programmer has declared that F inherits from Super,
// and they assign F.prototype to an object literal,
// then they are responsible for making sure that the object literal's
// implicit prototype is set up appropriately. We just obey
// the @extends tag.
ObjectType qVarType = ObjectType.cast(qVar.getType());
if (qVarType != null &&
rhsValue != null &&
rhsValue.isObjectLit()) {
typeRegistry.resetImplicitPrototype(
rhsValue.getJSType(), qVarType.getImplicitPrototype());
} else if (!qVar.isTypeInferred()) {
// If the programmer has declared that F inherits from Super,
// and they assign F.prototype to some arbitrary expression,
// there's not much we can do. We just ignore the expression,
// and hope they've annotated their code in a way to tell us
// what props are going to be on that prototype.
return;
}
if (qVar.getScope() == scope) {
scope.undeclare(qVar);
}
}
}
if (valueType == null) {
if (parent.isExprResult()) {
stubDeclarations.add(new StubDeclaration(
n,
t.getInput() != null && t.getInput().isExtern(),
ownerName));
}
return;
}
// NOTE(nicksantos): Determining whether a property is declared or not
// is really really obnoxious.
//
// The problem is that there are two (equally valid) coding styles:
//
// (function() {
// /* The authoritative definition of goog.bar. */
// goog.bar = function() {};
// })();
//
// function f() {
// goog.bar();
// /* Reset goog.bar to a no-op. */
// goog.bar = function() {};
// }
//
// In a dynamic language with first-class functions, it's very difficult
// to know which one the user intended without looking at lots of
// contextual information (the second example demonstrates a small case
// of this, but there are some really pathological cases as well).
//
// The current algorithm checks if either the declaration has
// jsdoc type information, or @const with a known type,
// or a function literal with a name we haven't seen before.
boolean inferred = true;
if (info != null) {
// Determining declaration for #1 + #3 + #4
inferred = !(info.hasType()
|| info.hasEnumParameterType()
|| (info.isConstant() && valueType != null
&& !valueType.isUnknownType())
|| FunctionTypeBuilder.isFunctionTypeDeclaration(info));
}
if (inferred && rhsValue != null && rhsValue.isFunction()) {
// Determining declaration for #2
if (info != null) {
inferred = false;
} else if (!scope.isDeclared(qName, false) &&
n.isUnscopedQualifiedName()) {
inferred = false;
}
}
if (!inferred) {
ObjectType ownerType = getObjectSlot(ownerName);
if (ownerType != null) {
// Only declare this as an official property if it has not been
// declared yet.
boolean isExtern = t.getInput() != null && t.getInput().isExtern();
if ((!ownerType.hasOwnProperty(propName) ||
ownerType.isPropertyTypeInferred(propName)) &&
((isExtern && !ownerType.isNativeObjectType()) ||
!ownerType.isInstanceType())) {
// If the property is undeclared or inferred, declare it now.
ownerType.defineDeclaredProperty(propName, valueType, n);
}
}
// If the property is already declared, the error will be
// caught when we try to declare it in the current scope.
defineSlot(n, parent, valueType, inferred);
} else if (rhsValue != null && rhsValue.isTrue()) {
// We declare these for delegate proxy method properties.
FunctionType ownerType =
JSType.toMaybeFunctionType(getObjectSlot(ownerName));
if (ownerType != null) {
JSType ownerTypeOfThis = ownerType.getTypeOfThis();
String delegateName = codingConvention.getDelegateSuperclassName();
JSType delegateType = delegateName == null ?
null : typeRegistry.getType(delegateName);
if (delegateType != null &&
ownerTypeOfThis.isSubtype(delegateType)) {
defineSlot(n, parent, getNativeType(BOOLEAN_TYPE), true);
}
}
}
}
```
| void maybeDeclareQualifiedName(NodeTraversal t, JSDocInfo info,
Node n, Node parent, Node rhsValue) {
Node ownerNode = n.getFirstChild();
String ownerName = ownerNode.getQualifiedName();
String qName = n.getQualifiedName();
String propName = n.getLastChild().getString();
Preconditions.checkArgument(qName != null && ownerName != null);
// Precedence of type information on GETPROPs:
// 1) @type annnotation / @enum annotation
// 2) ASSIGN to FUNCTION literal
// 3) @param/@return annotation (with no function literal)
// 4) ASSIGN to something marked @const
// 5) ASSIGN to anything else
//
// 1, 3, and 4 are declarations, 5 is inferred, and 2 is a declaration iff
// the function has jsdoc or has not been declared before.
//
// FUNCTION literals are special because TypedScopeCreator is very smart
// about getting as much type information as possible for them.
// Determining type for #1 + #2 + #3 + #4
JSType valueType = getDeclaredType(t.getSourceName(), info, n, rhsValue);
if (valueType == null && rhsValue != null) {
// Determining type for #5
valueType = rhsValue.getJSType();
}
// Function prototypes are special.
// It's a common JS idiom to do:
// F.prototype = { ... };
// So if F does not have an explicitly declared super type,
// allow F.prototype to be redefined arbitrarily.
if ("prototype".equals(propName)) {
Var qVar = scope.getVar(qName);
if (qVar != null) {
// If the programmer has declared that F inherits from Super,
// and they assign F.prototype to an object literal,
// then they are responsible for making sure that the object literal's
// implicit prototype is set up appropriately. We just obey
// the @extends tag.
ObjectType qVarType = ObjectType.cast(qVar.getType());
if (qVarType != null &&
rhsValue != null &&
rhsValue.isObjectLit()) {
typeRegistry.resetImplicitPrototype(
rhsValue.getJSType(), qVarType.getImplicitPrototype());
} else if (!qVar.isTypeInferred()) {
// If the programmer has declared that F inherits from Super,
// and they assign F.prototype to some arbitrary expression,
// there's not much we can do. We just ignore the expression,
// and hope they've annotated their code in a way to tell us
// what props are going to be on that prototype.
return;
}
if (qVar.getScope() == scope) {
scope.undeclare(qVar);
}
}
}
if (valueType == null) {
if (parent.isExprResult()) {
stubDeclarations.add(new StubDeclaration(
n,
t.getInput() != null && t.getInput().isExtern(),
ownerName));
}
return;
}
// NOTE(nicksantos): Determining whether a property is declared or not
// is really really obnoxious.
//
// The problem is that there are two (equally valid) coding styles:
//
// (function() {
// /* The authoritative definition of goog.bar. */
// goog.bar = function() {};
// })();
//
// function f() {
// goog.bar();
// /* Reset goog.bar to a no-op. */
// goog.bar = function() {};
// }
//
// In a dynamic language with first-class functions, it's very difficult
// to know which one the user intended without looking at lots of
// contextual information (the second example demonstrates a small case
// of this, but there are some really pathological cases as well).
//
// The current algorithm checks if either the declaration has
// jsdoc type information, or @const with a known type,
// or a function literal with a name we haven't seen before.
boolean inferred = true;
if (info != null) {
// Determining declaration for #1 + #3 + #4
inferred = !(info.hasType()
|| info.hasEnumParameterType()
|| (info.isConstant() && valueType != null
&& !valueType.isUnknownType())
|| FunctionTypeBuilder.isFunctionTypeDeclaration(info));
}
if (inferred && rhsValue != null && rhsValue.isFunction()) {
// Determining declaration for #2
if (info != null) {
inferred = false;
} else if (!scope.isDeclared(qName, false) &&
n.isUnscopedQualifiedName()) {
inferred = false;
}
}
if (!inferred) {
ObjectType ownerType = getObjectSlot(ownerName);
if (ownerType != null) {
// Only declare this as an official property if it has not been
// declared yet.
boolean isExtern = t.getInput() != null && t.getInput().isExtern();
if ((!ownerType.hasOwnProperty(propName) ||
ownerType.isPropertyTypeInferred(propName)) &&
((isExtern && !ownerType.isNativeObjectType()) ||
!ownerType.isInstanceType())) {
// If the property is undeclared or inferred, declare it now.
ownerType.defineDeclaredProperty(propName, valueType, n);
}
}
// If the property is already declared, the error will be
// caught when we try to declare it in the current scope.
defineSlot(n, parent, valueType, inferred);
} else if (rhsValue != null && rhsValue.isTrue()) {
// We declare these for delegate proxy method properties.
FunctionType ownerType =
JSType.toMaybeFunctionType(getObjectSlot(ownerName));
if (ownerType != null) {
JSType ownerTypeOfThis = ownerType.getTypeOfThis();
String delegateName = codingConvention.getDelegateSuperclassName();
JSType delegateType = delegateName == null ?
null : typeRegistry.getType(delegateName);
if (delegateType != null &&
ownerTypeOfThis.isSubtype(delegateType)) {
defineSlot(n, parent, getNativeType(BOOLEAN_TYPE), true);
}
}
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Declare the symbol for a qualified name in the global scope.
*
* @param info The doc info for this property.
* @param n A top-level GETPROP node (it should not be contained inside
* another GETPROP).
* @param parent The parent of {@code n}.
* @param rhsValue The node that {@code n} is being initialized to,
* or {@code null} if this is a stub declaration.
*/
void maybeDeclareQualifiedName(NodeTraversal t, JSDocInfo info,
Node n, Node parent, Node rhsValue) {
Node ownerNode = n.getFirstChild();
String ownerName = ownerNode.getQualifiedName();
String qName = n.getQualifiedName();
String propName = n.getLastChild().getString();
Preconditions.checkArgument(qName != null && ownerName != null);
// Precedence of type information on GETPROPs:
// 1) @type annnotation / @enum annotation
// 2) ASSIGN to FUNCTION literal
// 3) @param/@return annotation (with no function literal)
// 4) ASSIGN to something marked @const
// 5) ASSIGN to anything else
//
// 1, 3, and 4 are declarations, 5 is inferred, and 2 is a declaration iff
// the function has jsdoc or has not been declared before.
//
// FUNCTION literals are special because TypedScopeCreator is very smart
// about getting as much type information as possible for them.
// Determining type for #1 + #2 + #3 + #4
JSType valueType = getDeclaredType(t.getSourceName(), info, n, rhsValue);
if (valueType == null && rhsValue != null) {
// Determining type for #5
valueType = rhsValue.getJSType();
}
// Function prototypes are special.
// It's a common JS idiom to do:
// F.prototype = { ... };
// So if F does not have an explicitly declared super type,
// allow F.prototype to be redefined arbitrarily.
if ("prototype".equals(propName)) {
Var qVar = scope.getVar(qName);
if (qVar != null) {
// If the programmer has declared that F inherits from Super,
// and they assign F.prototype to an object literal,
// then they are responsible for making sure that the object literal's
// implicit prototype is set up appropriately. We just obey
// the @extends tag.
ObjectType qVarType = ObjectType.cast(qVar.getType());
if (qVarType != null &&
rhsValue != null &&
rhsValue.isObjectLit()) {
typeRegistry.resetImplicitPrototype(
rhsValue.getJSType(), qVarType.getImplicitPrototype());
} else if (!qVar.isTypeInferred()) {
// If the programmer has declared that F inherits from Super,
// and they assign F.prototype to some arbitrary expression,
// there's not much we can do. We just ignore the expression,
// and hope they've annotated their code in a way to tell us
// what props are going to be on that prototype.
return;
}
if (qVar.getScope() == scope) {
scope.undeclare(qVar);
}
}
}
if (valueType == null) {
if (parent.isExprResult()) {
stubDeclarations.add(new StubDeclaration(
n,
t.getInput() != null && t.getInput().isExtern(),
ownerName));
}
return;
}
// NOTE(nicksantos): Determining whether a property is declared or not
// is really really obnoxious.
//
// The problem is that there are two (equally valid) coding styles:
//
// (function() {
// /* The authoritative definition of goog.bar. */
// goog.bar = function() {};
// })();
//
// function f() {
// goog.bar();
// /* Reset goog.bar to a no-op. */
// goog.bar = function() {};
// }
//
// In a dynamic language with first-class functions, it's very difficult
// to know which one the user intended without looking at lots of
// contextual information (the second example demonstrates a small case
// of this, but there are some really pathological cases as well).
//
// The current algorithm checks if either the declaration has
// jsdoc type information, or @const with a known type,
// or a function literal with a name we haven't seen before.
boolean inferred = true;
if (info != null) {
// Determining declaration for #1 + #3 + #4
inferred = !(info.hasType()
|| info.hasEnumParameterType()
|| (info.isConstant() && valueType != null
&& !valueType.isUnknownType())
|| FunctionTypeBuilder.isFunctionTypeDeclaration(info));
}
if (inferred && rhsValue != null && rhsValue.isFunction()) {
// Determining declaration for #2
if (info != null) {
inferred = false;
} else if (!scope.isDeclared(qName, false) &&
n.isUnscopedQualifiedName()) {
inferred = false;
}
}
if (!inferred) {
ObjectType ownerType = getObjectSlot(ownerName);
if (ownerType != null) {
// Only declare this as an official property if it has not been
// declared yet.
boolean isExtern = t.getInput() != null && t.getInput().isExtern();
if ((!ownerType.hasOwnProperty(propName) ||
ownerType.isPropertyTypeInferred(propName)) &&
((isExtern && !ownerType.isNativeObjectType()) ||
!ownerType.isInstanceType())) {
// If the property is undeclared or inferred, declare it now.
ownerType.defineDeclaredProperty(propName, valueType, n);
}
}
// If the property is already declared, the error will be
// caught when we try to declare it in the current scope.
defineSlot(n, parent, valueType, inferred);
} else if (rhsValue != null && rhsValue.isTrue()) {
// We declare these for delegate proxy method properties.
FunctionType ownerType =
JSType.toMaybeFunctionType(getObjectSlot(ownerName));
if (ownerType != null) {
JSType ownerTypeOfThis = ownerType.getTypeOfThis();
String delegateName = codingConvention.getDelegateSuperclassName();
JSType delegateType = delegateName == null ?
null : typeRegistry.getType(delegateName);
if (delegateType != null &&
ownerTypeOfThis.isSubtype(delegateType)) {
defineSlot(n, parent, getNativeType(BOOLEAN_TYPE), true);
}
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
5 | 4d6ac2c2107113f5373474ae57ad8723a7fbc29307589e420d93436531f4b4f9 | private final static int _parseIndex(String str) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/*
/**********************************************************
/* Internal methods
/**********************************************************
*/
private final static int _parseIndex(String str) {
final int len = str.length();
// [Issue#133]: beware of super long indexes; assume we never
// have arrays over 2 billion entries so ints are fine.
if (len == 0 || len > 10) {
return -1;
}
for (int i = 0; i < len; ++i) {
char c = str.charAt(i++);
if (c > '9' || c < '0') {
return -1;
}
}
if (len == 10) {
long l = NumberInput.parseLong(str);
if (l > Integer.MAX_VALUE) {
return -1;
}
}
return NumberInput.parseInt(str);
}
```
| private final static int _parseIndex(String str) {
final int len = str.length();
// [Issue#133]: beware of super long indexes; assume we never
// have arrays over 2 billion entries so ints are fine.
if (len == 0 || len > 10) {
return -1;
}
for (int i = 0; i < len; ++i) {
char c = str.charAt(i++);
if (c > '9' || c < '0') {
return -1;
}
}
if (len == 10) {
long l = NumberInput.parseLong(str);
if (l > Integer.MAX_VALUE) {
return -1;
}
}
return NumberInput.parseInt(str);
} | true | JacksonCore | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/*
/**********************************************************
/* Internal methods
/**********************************************************
*/
private final static int _parseIndex(String str) {
final int len = str.length();
// [Issue#133]: beware of super long indexes; assume we never
// have arrays over 2 billion entries so ints are fine.
if (len == 0 || len > 10) {
return -1;
}
for (int i = 0; i < len; ++i) {
char c = str.charAt(i++);
if (c > '9' || c < '0') {
return -1;
}
}
if (len == 10) {
long l = NumberInput.parseLong(str);
if (l > Integer.MAX_VALUE) {
return -1;
}
}
return NumberInput.parseInt(str);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
34 | 4f53638ec6e69fa85a1ec279f87931bf9438237025de439b0dde12e5fff80b6b | public Iterator<Chromosome> iterator() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns an iterator over the unmodifiable list of chromosomes.
* <p>Any call to {@link Iterator#remove()} will result in a {@link UnsupportedOperationException}.</p>
*
* @return chromosome iterator
*/
public Iterator<Chromosome> iterator() {
return getChromosomes().iterator();
}
```
| public Iterator<Chromosome> iterator() {
return getChromosomes().iterator();
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns an iterator over the unmodifiable list of chromosomes.
* <p>Any call to {@link Iterator#remove()} will result in a {@link UnsupportedOperationException}.</p>
*
* @return chromosome iterator
*/
public Iterator<Chromosome> iterator() {
return getChromosomes().iterator();
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
15 | 4fa7e1fd6cdef41c8943d60b824f24d52d4fe12576bb043206cd4538c3477f82 | public static long safeMultiply(long val1, int val2) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Multiply two values throwing an exception if overflow occurs.
*
* @param val1 the first value
* @param val2 the second value
* @return the new total
* @throws ArithmeticException if the value is too big or too small
* @since 1.2
*/
public static long safeMultiply(long val1, int val2) {
switch (val2) {
case -1:
if (val1 == Long.MIN_VALUE) {
throw new ArithmeticException("Multiplication overflows a long: " + val1 + " * " + val2);
}
return -val1;
case 0:
return 0L;
case 1:
return val1;
}
long total = val1 * val2;
if (total / val2 != val1) {
throw new ArithmeticException("Multiplication overflows a long: " + val1 + " * " + val2);
}
return total;
}
```
| public static long safeMultiply(long val1, int val2) {
switch (val2) {
case -1:
if (val1 == Long.MIN_VALUE) {
throw new ArithmeticException("Multiplication overflows a long: " + val1 + " * " + val2);
}
return -val1;
case 0:
return 0L;
case 1:
return val1;
}
long total = val1 * val2;
if (total / val2 != val1) {
throw new ArithmeticException("Multiplication overflows a long: " + val1 + " * " + val2);
}
return total;
} | false | Time | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Multiply two values throwing an exception if overflow occurs.
*
* @param val1 the first value
* @param val2 the second value
* @return the new total
* @throws ArithmeticException if the value is too big or too small
* @since 1.2
*/
public static long safeMultiply(long val1, int val2) {
switch (val2) {
case -1:
if (val1 == Long.MIN_VALUE) {
throw new ArithmeticException("Multiplication overflows a long: " + val1 + " * " + val2);
}
return -val1;
case 0:
return 0L;
case 1:
return val1;
}
long total = val1 * val2;
if (total / val2 != val1) {
throw new ArithmeticException("Multiplication overflows a long: " + val1 + " * " + val2);
}
return total;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
7 | 4fdda0a543bc8df8b9425ec1a8db87f548f2c5749085bd61b59300cd079f83ea | public int parseInto(ReadWritableInstant instant, String text, int position) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Parses a datetime from the given text, at the given position, saving the
* result into the fields of the given ReadWritableInstant. If the parse
* succeeds, the return value is the new text position. Note that the parse
* may succeed without fully reading the text and in this case those fields
* that were read will be set.
* <p>
* Only those fields present in the string will be changed in the specified
* instant. All other fields will remain unaltered. Thus if the string only
* contains a year and a month, then the day and time will be retained from
* the input instant. If this is not the behaviour you want, then reset the
* fields before calling this method, or use {@link #parseDateTime(String)}
* or {@link #parseMutableDateTime(String)}.
* <p>
* If it fails, the return value is negative, but the instant may still be
* modified. To determine the position where the parse failed, apply the
* one's complement operator (~) on the return value.
* <p>
* This parse method ignores the {@link #getDefaultYear() default year} and
* parses using the year from the supplied instant based on the chronology
* and time-zone of the supplied instant.
* <p>
* The parse will use the chronology of the instant.
*
* @param instant an instant that will be modified, not null
* @param text the text to parse
* @param position position to start parsing from
* @return new position, negative value means parse failed -
* apply complement operator (~) to get position of failure
* @throws UnsupportedOperationException if parsing is not supported
* @throws IllegalArgumentException if the instant is null
* @throws IllegalArgumentException if any field is out of range
*/
//-----------------------------------------------------------------------
public int parseInto(ReadWritableInstant instant, String text, int position) {
DateTimeParser parser = requireParser();
if (instant == null) {
throw new IllegalArgumentException("Instant must not be null");
}
long instantMillis = instant.getMillis();
Chronology chrono = instant.getChronology();
long instantLocal = instantMillis + chrono.getZone().getOffset(instantMillis);
chrono = selectChronology(chrono);
int defaultYear = chrono.year().get(instantLocal);
DateTimeParserBucket bucket = new DateTimeParserBucket(
instantLocal, chrono, iLocale, iPivotYear, defaultYear);
int newPos = parser.parseInto(bucket, text, position);
instant.setMillis(bucket.computeMillis(false, text));
if (iOffsetParsed && bucket.getOffsetInteger() != null) {
int parsedOffset = bucket.getOffsetInteger();
DateTimeZone parsedZone = DateTimeZone.forOffsetMillis(parsedOffset);
chrono = chrono.withZone(parsedZone);
} else if (bucket.getZone() != null) {
chrono = chrono.withZone(bucket.getZone());
}
instant.setChronology(chrono);
if (iZone != null) {
instant.setZone(iZone);
}
return newPos;
}
```
| public int parseInto(ReadWritableInstant instant, String text, int position) {
DateTimeParser parser = requireParser();
if (instant == null) {
throw new IllegalArgumentException("Instant must not be null");
}
long instantMillis = instant.getMillis();
Chronology chrono = instant.getChronology();
long instantLocal = instantMillis + chrono.getZone().getOffset(instantMillis);
chrono = selectChronology(chrono);
int defaultYear = chrono.year().get(instantLocal);
DateTimeParserBucket bucket = new DateTimeParserBucket(
instantLocal, chrono, iLocale, iPivotYear, defaultYear);
int newPos = parser.parseInto(bucket, text, position);
instant.setMillis(bucket.computeMillis(false, text));
if (iOffsetParsed && bucket.getOffsetInteger() != null) {
int parsedOffset = bucket.getOffsetInteger();
DateTimeZone parsedZone = DateTimeZone.forOffsetMillis(parsedOffset);
chrono = chrono.withZone(parsedZone);
} else if (bucket.getZone() != null) {
chrono = chrono.withZone(bucket.getZone());
}
instant.setChronology(chrono);
if (iZone != null) {
instant.setZone(iZone);
}
return newPos;
} | true | Time | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Parses a datetime from the given text, at the given position, saving the
* result into the fields of the given ReadWritableInstant. If the parse
* succeeds, the return value is the new text position. Note that the parse
* may succeed without fully reading the text and in this case those fields
* that were read will be set.
* <p>
* Only those fields present in the string will be changed in the specified
* instant. All other fields will remain unaltered. Thus if the string only
* contains a year and a month, then the day and time will be retained from
* the input instant. If this is not the behaviour you want, then reset the
* fields before calling this method, or use {@link #parseDateTime(String)}
* or {@link #parseMutableDateTime(String)}.
* <p>
* If it fails, the return value is negative, but the instant may still be
* modified. To determine the position where the parse failed, apply the
* one's complement operator (~) on the return value.
* <p>
* This parse method ignores the {@link #getDefaultYear() default year} and
* parses using the year from the supplied instant based on the chronology
* and time-zone of the supplied instant.
* <p>
* The parse will use the chronology of the instant.
*
* @param instant an instant that will be modified, not null
* @param text the text to parse
* @param position position to start parsing from
* @return new position, negative value means parse failed -
* apply complement operator (~) to get position of failure
* @throws UnsupportedOperationException if parsing is not supported
* @throws IllegalArgumentException if the instant is null
* @throws IllegalArgumentException if any field is out of range
*/
//-----------------------------------------------------------------------
public int parseInto(ReadWritableInstant instant, String text, int position) {
DateTimeParser parser = requireParser();
if (instant == null) {
throw new IllegalArgumentException("Instant must not be null");
}
long instantMillis = instant.getMillis();
Chronology chrono = instant.getChronology();
long instantLocal = instantMillis + chrono.getZone().getOffset(instantMillis);
chrono = selectChronology(chrono);
int defaultYear = chrono.year().get(instantLocal);
DateTimeParserBucket bucket = new DateTimeParserBucket(
instantLocal, chrono, iLocale, iPivotYear, defaultYear);
int newPos = parser.parseInto(bucket, text, position);
instant.setMillis(bucket.computeMillis(false, text));
if (iOffsetParsed && bucket.getOffsetInteger() != null) {
int parsedOffset = bucket.getOffsetInteger();
DateTimeZone parsedZone = DateTimeZone.forOffsetMillis(parsedOffset);
chrono = chrono.withZone(parsedZone);
} else if (bucket.getZone() != null) {
chrono = chrono.withZone(bucket.getZone());
}
instant.setChronology(chrono);
if (iZone != null) {
instant.setZone(iZone);
}
return newPos;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
26 | 4fdde7aee8168c872ced01fa31f4f07547a62d8d1ccda7015a927c782fe19f57 | protected AxisState drawLabel(String label, Graphics2D g2,
Rectangle2D plotArea, Rectangle2D dataArea, RectangleEdge edge,
AxisState state, PlotRenderingInfo plotState) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Draws the axis label.
*
* @param label the label text.
* @param g2 the graphics device.
* @param plotArea the plot area.
* @param dataArea the area inside the axes.
* @param edge the location of the axis.
* @param state the axis state (<code>null</code> not permitted).
* @param plotState the plot state (<code>null</code> permitted).
*
* @return Information about the axis.
*/
protected AxisState drawLabel(String label, Graphics2D g2,
Rectangle2D plotArea, Rectangle2D dataArea, RectangleEdge edge,
AxisState state, PlotRenderingInfo plotState) {
// it is unlikely that 'state' will be null, but check anyway...
if (state == null) {
throw new IllegalArgumentException("Null 'state' argument.");
}
if ((label == null) || (label.equals(""))) {
return state;
}
Font font = getLabelFont();
RectangleInsets insets = getLabelInsets();
g2.setFont(font);
g2.setPaint(getLabelPaint());
FontMetrics fm = g2.getFontMetrics();
Rectangle2D labelBounds = TextUtilities.getTextBounds(label, g2, fm);
Shape hotspot = null;
if (edge == RectangleEdge.TOP) {
AffineTransform t = AffineTransform.getRotateInstance(
getLabelAngle(), labelBounds.getCenterX(),
labelBounds.getCenterY());
Shape rotatedLabelBounds = t.createTransformedShape(labelBounds);
labelBounds = rotatedLabelBounds.getBounds2D();
float w = (float) labelBounds.getWidth();
float h = (float) labelBounds.getHeight();
float labelx = (float) dataArea.getCenterX();
float labely = (float) (state.getCursor() - insets.getBottom()
- h / 2.0);
TextUtilities.drawRotatedString(label, g2, labelx, labely,
TextAnchor.CENTER, getLabelAngle(), TextAnchor.CENTER);
hotspot = new Rectangle2D.Float(labelx - w / 2.0f,
labely - h / 2.0f, w, h);
state.cursorUp(insets.getTop() + labelBounds.getHeight()
+ insets.getBottom());
}
else if (edge == RectangleEdge.BOTTOM) {
AffineTransform t = AffineTransform.getRotateInstance(
getLabelAngle(), labelBounds.getCenterX(),
labelBounds.getCenterY());
Shape rotatedLabelBounds = t.createTransformedShape(labelBounds);
labelBounds = rotatedLabelBounds.getBounds2D();
float w = (float) labelBounds.getWidth();
float h = (float) labelBounds.getHeight();
float labelx = (float) dataArea.getCenterX();
float labely = (float) (state.getCursor() + insets.getTop()
+ h / 2.0);
TextUtilities.drawRotatedString(label, g2, labelx, labely,
TextAnchor.CENTER, getLabelAngle(), TextAnchor.CENTER);
hotspot = new Rectangle2D.Float(labelx - w / 2.0f,
labely - h / 2.0f, w, h);
state.cursorDown(insets.getTop() + labelBounds.getHeight()
+ insets.getBottom());
}
else if (edge == RectangleEdge.LEFT) {
AffineTransform t = AffineTransform.getRotateInstance(
getLabelAngle() - Math.PI / 2.0, labelBounds.getCenterX(),
labelBounds.getCenterY());
Shape rotatedLabelBounds = t.createTransformedShape(labelBounds);
labelBounds = rotatedLabelBounds.getBounds2D();
float w = (float) labelBounds.getWidth();
float h = (float) labelBounds.getHeight();
float labelx = (float) (state.getCursor() - insets.getRight()
- w / 2.0);
float labely = (float) dataArea.getCenterY();
TextUtilities.drawRotatedString(label, g2, labelx, labely,
TextAnchor.CENTER, getLabelAngle() - Math.PI / 2.0,
TextAnchor.CENTER);
hotspot = new Rectangle2D.Float(labelx - w / 2.0f,
labely - h / 2.0f, w, h);
state.cursorLeft(insets.getLeft() + labelBounds.getWidth()
+ insets.getRight());
}
else if (edge == RectangleEdge.RIGHT) {
AffineTransform t = AffineTransform.getRotateInstance(
getLabelAngle() + Math.PI / 2.0,
labelBounds.getCenterX(), labelBounds.getCenterY());
Shape rotatedLabelBounds = t.createTransformedShape(labelBounds);
labelBounds = rotatedLabelBounds.getBounds2D();
float w = (float) labelBounds.getWidth();
float h = (float) labelBounds.getHeight();
float labelx = (float) (state.getCursor()
+ insets.getLeft() + w / 2.0);
float labely = (float) (dataArea.getY() + dataArea.getHeight()
/ 2.0);
TextUtilities.drawRotatedString(label, g2, labelx, labely,
TextAnchor.CENTER, getLabelAngle() + Math.PI / 2.0,
TextAnchor.CENTER);
hotspot = new Rectangle2D.Float(labelx - w / 2.0f,
labely - h / 2.0f, w, h);
state.cursorRight(insets.getLeft() + labelBounds.getWidth()
+ insets.getRight());
}
if (plotState != null && hotspot != null) {
ChartRenderingInfo owner = plotState.getOwner();
if (owner != null) {
EntityCollection entities = owner.getEntityCollection();
if (entities != null) {
entities.add(new AxisLabelEntity(this, hotspot,
this.labelToolTip, this.labelURL));
}
}
}
return state;
}
```
| protected AxisState drawLabel(String label, Graphics2D g2,
Rectangle2D plotArea, Rectangle2D dataArea, RectangleEdge edge,
AxisState state, PlotRenderingInfo plotState) {
// it is unlikely that 'state' will be null, but check anyway...
if (state == null) {
throw new IllegalArgumentException("Null 'state' argument.");
}
if ((label == null) || (label.equals(""))) {
return state;
}
Font font = getLabelFont();
RectangleInsets insets = getLabelInsets();
g2.setFont(font);
g2.setPaint(getLabelPaint());
FontMetrics fm = g2.getFontMetrics();
Rectangle2D labelBounds = TextUtilities.getTextBounds(label, g2, fm);
Shape hotspot = null;
if (edge == RectangleEdge.TOP) {
AffineTransform t = AffineTransform.getRotateInstance(
getLabelAngle(), labelBounds.getCenterX(),
labelBounds.getCenterY());
Shape rotatedLabelBounds = t.createTransformedShape(labelBounds);
labelBounds = rotatedLabelBounds.getBounds2D();
float w = (float) labelBounds.getWidth();
float h = (float) labelBounds.getHeight();
float labelx = (float) dataArea.getCenterX();
float labely = (float) (state.getCursor() - insets.getBottom()
- h / 2.0);
TextUtilities.drawRotatedString(label, g2, labelx, labely,
TextAnchor.CENTER, getLabelAngle(), TextAnchor.CENTER);
hotspot = new Rectangle2D.Float(labelx - w / 2.0f,
labely - h / 2.0f, w, h);
state.cursorUp(insets.getTop() + labelBounds.getHeight()
+ insets.getBottom());
}
else if (edge == RectangleEdge.BOTTOM) {
AffineTransform t = AffineTransform.getRotateInstance(
getLabelAngle(), labelBounds.getCenterX(),
labelBounds.getCenterY());
Shape rotatedLabelBounds = t.createTransformedShape(labelBounds);
labelBounds = rotatedLabelBounds.getBounds2D();
float w = (float) labelBounds.getWidth();
float h = (float) labelBounds.getHeight();
float labelx = (float) dataArea.getCenterX();
float labely = (float) (state.getCursor() + insets.getTop()
+ h / 2.0);
TextUtilities.drawRotatedString(label, g2, labelx, labely,
TextAnchor.CENTER, getLabelAngle(), TextAnchor.CENTER);
hotspot = new Rectangle2D.Float(labelx - w / 2.0f,
labely - h / 2.0f, w, h);
state.cursorDown(insets.getTop() + labelBounds.getHeight()
+ insets.getBottom());
}
else if (edge == RectangleEdge.LEFT) {
AffineTransform t = AffineTransform.getRotateInstance(
getLabelAngle() - Math.PI / 2.0, labelBounds.getCenterX(),
labelBounds.getCenterY());
Shape rotatedLabelBounds = t.createTransformedShape(labelBounds);
labelBounds = rotatedLabelBounds.getBounds2D();
float w = (float) labelBounds.getWidth();
float h = (float) labelBounds.getHeight();
float labelx = (float) (state.getCursor() - insets.getRight()
- w / 2.0);
float labely = (float) dataArea.getCenterY();
TextUtilities.drawRotatedString(label, g2, labelx, labely,
TextAnchor.CENTER, getLabelAngle() - Math.PI / 2.0,
TextAnchor.CENTER);
hotspot = new Rectangle2D.Float(labelx - w / 2.0f,
labely - h / 2.0f, w, h);
state.cursorLeft(insets.getLeft() + labelBounds.getWidth()
+ insets.getRight());
}
else if (edge == RectangleEdge.RIGHT) {
AffineTransform t = AffineTransform.getRotateInstance(
getLabelAngle() + Math.PI / 2.0,
labelBounds.getCenterX(), labelBounds.getCenterY());
Shape rotatedLabelBounds = t.createTransformedShape(labelBounds);
labelBounds = rotatedLabelBounds.getBounds2D();
float w = (float) labelBounds.getWidth();
float h = (float) labelBounds.getHeight();
float labelx = (float) (state.getCursor()
+ insets.getLeft() + w / 2.0);
float labely = (float) (dataArea.getY() + dataArea.getHeight()
/ 2.0);
TextUtilities.drawRotatedString(label, g2, labelx, labely,
TextAnchor.CENTER, getLabelAngle() + Math.PI / 2.0,
TextAnchor.CENTER);
hotspot = new Rectangle2D.Float(labelx - w / 2.0f,
labely - h / 2.0f, w, h);
state.cursorRight(insets.getLeft() + labelBounds.getWidth()
+ insets.getRight());
}
if (plotState != null && hotspot != null) {
ChartRenderingInfo owner = plotState.getOwner();
if (owner != null) {
EntityCollection entities = owner.getEntityCollection();
if (entities != null) {
entities.add(new AxisLabelEntity(this, hotspot,
this.labelToolTip, this.labelURL));
}
}
}
return state;
} | false | Chart | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Draws the axis label.
*
* @param label the label text.
* @param g2 the graphics device.
* @param plotArea the plot area.
* @param dataArea the area inside the axes.
* @param edge the location of the axis.
* @param state the axis state (<code>null</code> not permitted).
* @param plotState the plot state (<code>null</code> permitted).
*
* @return Information about the axis.
*/
protected AxisState drawLabel(String label, Graphics2D g2,
Rectangle2D plotArea, Rectangle2D dataArea, RectangleEdge edge,
AxisState state, PlotRenderingInfo plotState) {
// it is unlikely that 'state' will be null, but check anyway...
if (state == null) {
throw new IllegalArgumentException("Null 'state' argument.");
}
if ((label == null) || (label.equals(""))) {
return state;
}
Font font = getLabelFont();
RectangleInsets insets = getLabelInsets();
g2.setFont(font);
g2.setPaint(getLabelPaint());
FontMetrics fm = g2.getFontMetrics();
Rectangle2D labelBounds = TextUtilities.getTextBounds(label, g2, fm);
Shape hotspot = null;
if (edge == RectangleEdge.TOP) {
AffineTransform t = AffineTransform.getRotateInstance(
getLabelAngle(), labelBounds.getCenterX(),
labelBounds.getCenterY());
Shape rotatedLabelBounds = t.createTransformedShape(labelBounds);
labelBounds = rotatedLabelBounds.getBounds2D();
float w = (float) labelBounds.getWidth();
float h = (float) labelBounds.getHeight();
float labelx = (float) dataArea.getCenterX();
float labely = (float) (state.getCursor() - insets.getBottom()
- h / 2.0);
TextUtilities.drawRotatedString(label, g2, labelx, labely,
TextAnchor.CENTER, getLabelAngle(), TextAnchor.CENTER);
hotspot = new Rectangle2D.Float(labelx - w / 2.0f,
labely - h / 2.0f, w, h);
state.cursorUp(insets.getTop() + labelBounds.getHeight()
+ insets.getBottom());
}
else if (edge == RectangleEdge.BOTTOM) {
AffineTransform t = AffineTransform.getRotateInstance(
getLabelAngle(), labelBounds.getCenterX(),
labelBounds.getCenterY());
Shape rotatedLabelBounds = t.createTransformedShape(labelBounds);
labelBounds = rotatedLabelBounds.getBounds2D();
float w = (float) labelBounds.getWidth();
float h = (float) labelBounds.getHeight();
float labelx = (float) dataArea.getCenterX();
float labely = (float) (state.getCursor() + insets.getTop()
+ h / 2.0);
TextUtilities.drawRotatedString(label, g2, labelx, labely,
TextAnchor.CENTER, getLabelAngle(), TextAnchor.CENTER);
hotspot = new Rectangle2D.Float(labelx - w / 2.0f,
labely - h / 2.0f, w, h);
state.cursorDown(insets.getTop() + labelBounds.getHeight()
+ insets.getBottom());
}
else if (edge == RectangleEdge.LEFT) {
AffineTransform t = AffineTransform.getRotateInstance(
getLabelAngle() - Math.PI / 2.0, labelBounds.getCenterX(),
labelBounds.getCenterY());
Shape rotatedLabelBounds = t.createTransformedShape(labelBounds);
labelBounds = rotatedLabelBounds.getBounds2D();
float w = (float) labelBounds.getWidth();
float h = (float) labelBounds.getHeight();
float labelx = (float) (state.getCursor() - insets.getRight()
- w / 2.0);
float labely = (float) dataArea.getCenterY();
TextUtilities.drawRotatedString(label, g2, labelx, labely,
TextAnchor.CENTER, getLabelAngle() - Math.PI / 2.0,
TextAnchor.CENTER);
hotspot = new Rectangle2D.Float(labelx - w / 2.0f,
labely - h / 2.0f, w, h);
state.cursorLeft(insets.getLeft() + labelBounds.getWidth()
+ insets.getRight());
}
else if (edge == RectangleEdge.RIGHT) {
AffineTransform t = AffineTransform.getRotateInstance(
getLabelAngle() + Math.PI / 2.0,
labelBounds.getCenterX(), labelBounds.getCenterY());
Shape rotatedLabelBounds = t.createTransformedShape(labelBounds);
labelBounds = rotatedLabelBounds.getBounds2D();
float w = (float) labelBounds.getWidth();
float h = (float) labelBounds.getHeight();
float labelx = (float) (state.getCursor()
+ insets.getLeft() + w / 2.0);
float labely = (float) (dataArea.getY() + dataArea.getHeight()
/ 2.0);
TextUtilities.drawRotatedString(label, g2, labelx, labely,
TextAnchor.CENTER, getLabelAngle() + Math.PI / 2.0,
TextAnchor.CENTER);
hotspot = new Rectangle2D.Float(labelx - w / 2.0f,
labely - h / 2.0f, w, h);
state.cursorRight(insets.getLeft() + labelBounds.getWidth()
+ insets.getRight());
}
if (plotState != null && hotspot != null) {
ChartRenderingInfo owner = plotState.getOwner();
if (owner != null) {
EntityCollection entities = owner.getEntityCollection();
if (entities != null) {
entities.add(new AxisLabelEntity(this, hotspot,
this.labelToolTip, this.labelURL));
}
}
}
return state;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
1 | 507620c195343cf0854da676972de386ee51452761e9c98e6e77123589a1c989 | @Override
public JsonToken nextToken() throws IOException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/*
@Override
public JsonToken nextToken() throws IOException
{
JsonToken t = nextToken0();
if (t != null) {
switch (t) {
case FIELD_NAME:
System.out.println("JsonToken: FIELD_NAME '"+_parsingContext.getCurrentName()+"'");
break;
case VALUE_STRING:
System.out.println("JsonToken: VALUE_STRING '"+getText()+"'");
break;
default:
System.out.println("JsonToken: "+t);
}
}
return t;
}
*/
// DEBUGGING
@Override
public JsonToken nextToken() throws IOException
{
_binaryValue = null;
if (_nextToken != null) {
JsonToken t = _nextToken;
_currToken = t;
_nextToken = null;
switch (t) {
case START_OBJECT:
_parsingContext = _parsingContext.createChildObjectContext(-1, -1);
break;
case START_ARRAY:
_parsingContext = _parsingContext.createChildArrayContext(-1, -1);
break;
case END_OBJECT:
case END_ARRAY:
_parsingContext = _parsingContext.getParent();
_namesToWrap = _parsingContext.getNamesToWrap();
break;
case FIELD_NAME:
_parsingContext.setCurrentName(_xmlTokens.getLocalName());
break;
default: // VALUE_STRING, VALUE_NULL
// should be fine as is?
}
return t;
}
int token = _xmlTokens.next();
// Need to have a loop just because we may have to eat/convert
// a start-element that indicates an array element.
while (token == XmlTokenStream.XML_START_ELEMENT) {
// If we thought we might get leaf, no such luck
if (_mayBeLeaf) {
// leave _mayBeLeaf set, as we start a new context
_nextToken = JsonToken.FIELD_NAME;
_parsingContext = _parsingContext.createChildObjectContext(-1, -1);
return (_currToken = JsonToken.START_OBJECT);
}
if (_parsingContext.inArray()) {
// Yup: in array, so this element could be verified; but it won't be
// reported anyway, and we need to process following event.
token = _xmlTokens.next();
_mayBeLeaf = true;
continue;
}
String name = _xmlTokens.getLocalName();
_parsingContext.setCurrentName(name);
// Ok: virtual wrapping can be done by simply repeating current START_ELEMENT.
// Couple of ways to do it; but start by making _xmlTokens replay the thing...
if (_namesToWrap != null && _namesToWrap.contains(name)) {
_xmlTokens.repeatStartElement();
}
_mayBeLeaf = true;
// Ok: in array context we need to skip reporting field names.
// But what's the best way to find next token?
return (_currToken = JsonToken.FIELD_NAME);
}
// Ok; beyond start element, what do we get?
switch (token) {
case XmlTokenStream.XML_END_ELEMENT:
// Simple, except that if this is a leaf, need to suppress end:
if (_mayBeLeaf) {
_mayBeLeaf = false;
if (_parsingContext.inArray()) {
// 06-Jan-2015, tatu: as per [dataformat-xml#180], need to
// expose as empty Object, not null
_nextToken = JsonToken.END_OBJECT;
_parsingContext = _parsingContext.createChildObjectContext(-1, -1);
return (_currToken = JsonToken.START_OBJECT);
}
return (_currToken = JsonToken.VALUE_NULL);
}
_currToken = _parsingContext.inArray() ? JsonToken.END_ARRAY : JsonToken.END_OBJECT;
_parsingContext = _parsingContext.getParent();
_namesToWrap = _parsingContext.getNamesToWrap();
return _currToken;
case XmlTokenStream.XML_ATTRIBUTE_NAME:
// If there was a chance of leaf node, no more...
if (_mayBeLeaf) {
_mayBeLeaf = false;
_nextToken = JsonToken.FIELD_NAME;
_currText = _xmlTokens.getText();
_parsingContext = _parsingContext.createChildObjectContext(-1, -1);
return (_currToken = JsonToken.START_OBJECT);
}
_parsingContext.setCurrentName(_xmlTokens.getLocalName());
return (_currToken = JsonToken.FIELD_NAME);
case XmlTokenStream.XML_ATTRIBUTE_VALUE:
_currText = _xmlTokens.getText();
return (_currToken = JsonToken.VALUE_STRING);
case XmlTokenStream.XML_TEXT:
_currText = _xmlTokens.getText();
if (_mayBeLeaf) {
_mayBeLeaf = false;
/* One more refinement (pronunced like "hack") is that if
* we had an empty String (or all white space), and we are
* deserializing an array, we better hide the empty text.
*/
// Also: must skip following END_ELEMENT
_xmlTokens.skipEndElement();
if (_parsingContext.inArray()) {
if (_isEmpty(_currText)) {
// 06-Jan-2015, tatu: as per [dataformat-xml#180], need to
// expose as empty Object, not null (or, worse, as used to
// be done, by swallowing the token)
_nextToken = JsonToken.END_OBJECT;
_parsingContext = _parsingContext.createChildObjectContext(-1, -1);
return (_currToken = JsonToken.START_OBJECT);
}
}
return (_currToken = JsonToken.VALUE_STRING);
} else {
// [dataformat-xml#177]: empty text may also need to be skipped
if (_parsingContext.inObject()
&& (_currToken != JsonToken.FIELD_NAME) && _isEmpty(_currText)) {
_currToken = JsonToken.END_OBJECT;
_parsingContext = _parsingContext.getParent();
_namesToWrap = _parsingContext.getNamesToWrap();
return _currToken;
}
}
// If not a leaf (or otherwise ignorable), need to transform into property...
_parsingContext.setCurrentName(_cfgNameForTextElement);
_nextToken = JsonToken.VALUE_STRING;
return (_currToken = JsonToken.FIELD_NAME);
case XmlTokenStream.XML_END:
return (_currToken = null);
}
// should never get here
_throwInternal();
return null;
}
```
| @Override
public JsonToken nextToken() throws IOException
{
_binaryValue = null;
if (_nextToken != null) {
JsonToken t = _nextToken;
_currToken = t;
_nextToken = null;
switch (t) {
case START_OBJECT:
_parsingContext = _parsingContext.createChildObjectContext(-1, -1);
break;
case START_ARRAY:
_parsingContext = _parsingContext.createChildArrayContext(-1, -1);
break;
case END_OBJECT:
case END_ARRAY:
_parsingContext = _parsingContext.getParent();
_namesToWrap = _parsingContext.getNamesToWrap();
break;
case FIELD_NAME:
_parsingContext.setCurrentName(_xmlTokens.getLocalName());
break;
default: // VALUE_STRING, VALUE_NULL
// should be fine as is?
}
return t;
}
int token = _xmlTokens.next();
// Need to have a loop just because we may have to eat/convert
// a start-element that indicates an array element.
while (token == XmlTokenStream.XML_START_ELEMENT) {
// If we thought we might get leaf, no such luck
if (_mayBeLeaf) {
// leave _mayBeLeaf set, as we start a new context
_nextToken = JsonToken.FIELD_NAME;
_parsingContext = _parsingContext.createChildObjectContext(-1, -1);
return (_currToken = JsonToken.START_OBJECT);
}
if (_parsingContext.inArray()) {
// Yup: in array, so this element could be verified; but it won't be
// reported anyway, and we need to process following event.
token = _xmlTokens.next();
_mayBeLeaf = true;
continue;
}
String name = _xmlTokens.getLocalName();
_parsingContext.setCurrentName(name);
// Ok: virtual wrapping can be done by simply repeating current START_ELEMENT.
// Couple of ways to do it; but start by making _xmlTokens replay the thing...
if (_namesToWrap != null && _namesToWrap.contains(name)) {
_xmlTokens.repeatStartElement();
}
_mayBeLeaf = true;
// Ok: in array context we need to skip reporting field names.
// But what's the best way to find next token?
return (_currToken = JsonToken.FIELD_NAME);
}
// Ok; beyond start element, what do we get?
switch (token) {
case XmlTokenStream.XML_END_ELEMENT:
// Simple, except that if this is a leaf, need to suppress end:
if (_mayBeLeaf) {
_mayBeLeaf = false;
if (_parsingContext.inArray()) {
// 06-Jan-2015, tatu: as per [dataformat-xml#180], need to
// expose as empty Object, not null
_nextToken = JsonToken.END_OBJECT;
_parsingContext = _parsingContext.createChildObjectContext(-1, -1);
return (_currToken = JsonToken.START_OBJECT);
}
return (_currToken = JsonToken.VALUE_NULL);
}
_currToken = _parsingContext.inArray() ? JsonToken.END_ARRAY : JsonToken.END_OBJECT;
_parsingContext = _parsingContext.getParent();
_namesToWrap = _parsingContext.getNamesToWrap();
return _currToken;
case XmlTokenStream.XML_ATTRIBUTE_NAME:
// If there was a chance of leaf node, no more...
if (_mayBeLeaf) {
_mayBeLeaf = false;
_nextToken = JsonToken.FIELD_NAME;
_currText = _xmlTokens.getText();
_parsingContext = _parsingContext.createChildObjectContext(-1, -1);
return (_currToken = JsonToken.START_OBJECT);
}
_parsingContext.setCurrentName(_xmlTokens.getLocalName());
return (_currToken = JsonToken.FIELD_NAME);
case XmlTokenStream.XML_ATTRIBUTE_VALUE:
_currText = _xmlTokens.getText();
return (_currToken = JsonToken.VALUE_STRING);
case XmlTokenStream.XML_TEXT:
_currText = _xmlTokens.getText();
if (_mayBeLeaf) {
_mayBeLeaf = false;
/* One more refinement (pronunced like "hack") is that if
* we had an empty String (or all white space), and we are
* deserializing an array, we better hide the empty text.
*/
// Also: must skip following END_ELEMENT
_xmlTokens.skipEndElement();
if (_parsingContext.inArray()) {
if (_isEmpty(_currText)) {
// 06-Jan-2015, tatu: as per [dataformat-xml#180], need to
// expose as empty Object, not null (or, worse, as used to
// be done, by swallowing the token)
_nextToken = JsonToken.END_OBJECT;
_parsingContext = _parsingContext.createChildObjectContext(-1, -1);
return (_currToken = JsonToken.START_OBJECT);
}
}
return (_currToken = JsonToken.VALUE_STRING);
} else {
// [dataformat-xml#177]: empty text may also need to be skipped
if (_parsingContext.inObject()
&& (_currToken != JsonToken.FIELD_NAME) && _isEmpty(_currText)) {
_currToken = JsonToken.END_OBJECT;
_parsingContext = _parsingContext.getParent();
_namesToWrap = _parsingContext.getNamesToWrap();
return _currToken;
}
}
// If not a leaf (or otherwise ignorable), need to transform into property...
_parsingContext.setCurrentName(_cfgNameForTextElement);
_nextToken = JsonToken.VALUE_STRING;
return (_currToken = JsonToken.FIELD_NAME);
case XmlTokenStream.XML_END:
return (_currToken = null);
}
// should never get here
_throwInternal();
return null;
} | false | JacksonXml | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/*
@Override
public JsonToken nextToken() throws IOException
{
JsonToken t = nextToken0();
if (t != null) {
switch (t) {
case FIELD_NAME:
System.out.println("JsonToken: FIELD_NAME '"+_parsingContext.getCurrentName()+"'");
break;
case VALUE_STRING:
System.out.println("JsonToken: VALUE_STRING '"+getText()+"'");
break;
default:
System.out.println("JsonToken: "+t);
}
}
return t;
}
*/
// DEBUGGING
@Override
public JsonToken nextToken() throws IOException
{
_binaryValue = null;
if (_nextToken != null) {
JsonToken t = _nextToken;
_currToken = t;
_nextToken = null;
switch (t) {
case START_OBJECT:
_parsingContext = _parsingContext.createChildObjectContext(-1, -1);
break;
case START_ARRAY:
_parsingContext = _parsingContext.createChildArrayContext(-1, -1);
break;
case END_OBJECT:
case END_ARRAY:
_parsingContext = _parsingContext.getParent();
_namesToWrap = _parsingContext.getNamesToWrap();
break;
case FIELD_NAME:
_parsingContext.setCurrentName(_xmlTokens.getLocalName());
break;
default: // VALUE_STRING, VALUE_NULL
// should be fine as is?
}
return t;
}
int token = _xmlTokens.next();
// Need to have a loop just because we may have to eat/convert
// a start-element that indicates an array element.
while (token == XmlTokenStream.XML_START_ELEMENT) {
// If we thought we might get leaf, no such luck
if (_mayBeLeaf) {
// leave _mayBeLeaf set, as we start a new context
_nextToken = JsonToken.FIELD_NAME;
_parsingContext = _parsingContext.createChildObjectContext(-1, -1);
return (_currToken = JsonToken.START_OBJECT);
}
if (_parsingContext.inArray()) {
// Yup: in array, so this element could be verified; but it won't be
// reported anyway, and we need to process following event.
token = _xmlTokens.next();
_mayBeLeaf = true;
continue;
}
String name = _xmlTokens.getLocalName();
_parsingContext.setCurrentName(name);
// Ok: virtual wrapping can be done by simply repeating current START_ELEMENT.
// Couple of ways to do it; but start by making _xmlTokens replay the thing...
if (_namesToWrap != null && _namesToWrap.contains(name)) {
_xmlTokens.repeatStartElement();
}
_mayBeLeaf = true;
// Ok: in array context we need to skip reporting field names.
// But what's the best way to find next token?
return (_currToken = JsonToken.FIELD_NAME);
}
// Ok; beyond start element, what do we get?
switch (token) {
case XmlTokenStream.XML_END_ELEMENT:
// Simple, except that if this is a leaf, need to suppress end:
if (_mayBeLeaf) {
_mayBeLeaf = false;
if (_parsingContext.inArray()) {
// 06-Jan-2015, tatu: as per [dataformat-xml#180], need to
// expose as empty Object, not null
_nextToken = JsonToken.END_OBJECT;
_parsingContext = _parsingContext.createChildObjectContext(-1, -1);
return (_currToken = JsonToken.START_OBJECT);
}
return (_currToken = JsonToken.VALUE_NULL);
}
_currToken = _parsingContext.inArray() ? JsonToken.END_ARRAY : JsonToken.END_OBJECT;
_parsingContext = _parsingContext.getParent();
_namesToWrap = _parsingContext.getNamesToWrap();
return _currToken;
case XmlTokenStream.XML_ATTRIBUTE_NAME:
// If there was a chance of leaf node, no more...
if (_mayBeLeaf) {
_mayBeLeaf = false;
_nextToken = JsonToken.FIELD_NAME;
_currText = _xmlTokens.getText();
_parsingContext = _parsingContext.createChildObjectContext(-1, -1);
return (_currToken = JsonToken.START_OBJECT);
}
_parsingContext.setCurrentName(_xmlTokens.getLocalName());
return (_currToken = JsonToken.FIELD_NAME);
case XmlTokenStream.XML_ATTRIBUTE_VALUE:
_currText = _xmlTokens.getText();
return (_currToken = JsonToken.VALUE_STRING);
case XmlTokenStream.XML_TEXT:
_currText = _xmlTokens.getText();
if (_mayBeLeaf) {
_mayBeLeaf = false;
/* One more refinement (pronunced like "hack") is that if
* we had an empty String (or all white space), and we are
* deserializing an array, we better hide the empty text.
*/
// Also: must skip following END_ELEMENT
_xmlTokens.skipEndElement();
if (_parsingContext.inArray()) {
if (_isEmpty(_currText)) {
// 06-Jan-2015, tatu: as per [dataformat-xml#180], need to
// expose as empty Object, not null (or, worse, as used to
// be done, by swallowing the token)
_nextToken = JsonToken.END_OBJECT;
_parsingContext = _parsingContext.createChildObjectContext(-1, -1);
return (_currToken = JsonToken.START_OBJECT);
}
}
return (_currToken = JsonToken.VALUE_STRING);
} else {
// [dataformat-xml#177]: empty text may also need to be skipped
if (_parsingContext.inObject()
&& (_currToken != JsonToken.FIELD_NAME) && _isEmpty(_currText)) {
_currToken = JsonToken.END_OBJECT;
_parsingContext = _parsingContext.getParent();
_namesToWrap = _parsingContext.getNamesToWrap();
return _currToken;
}
}
// If not a leaf (or otherwise ignorable), need to transform into property...
_parsingContext.setCurrentName(_cfgNameForTextElement);
_nextToken = JsonToken.VALUE_STRING;
return (_currToken = JsonToken.FIELD_NAME);
case XmlTokenStream.XML_END:
return (_currToken = null);
}
// should never get here
_throwInternal();
return null;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
81 | 508f64458d4bc7dbeb9393861588d31e789708cb7531b90303b3ff30044eed39 | @Override
Node processFunctionNode(FunctionNode functionNode) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
Node processFunctionNode(FunctionNode functionNode) {
Name name = functionNode.getFunctionName();
Boolean isUnnamedFunction = false;
if (name == null) {
int functionType = functionNode.getFunctionType();
if (functionType != FunctionNode.FUNCTION_EXPRESSION) {
errorReporter.error(
"unnamed function statement",
sourceName,
functionNode.getLineno(), "", 0);
}
name = new Name();
name.setIdentifier("");
isUnnamedFunction = true;
}
Node node = newNode(Token.FUNCTION);
Node newName = transform(name);
if (isUnnamedFunction) {
// Old Rhino tagged the empty name node with the line number of the
// declaration.
newName.setLineno(functionNode.getLineno());
// TODO(bowdidge) Mark line number of paren correctly.
// Same problem as below - the left paren might not be on the
// same line as the function keyword.
int lpColumn = functionNode.getAbsolutePosition() +
functionNode.getLp();
newName.setCharno(position2charno(lpColumn));
}
node.addChildToBack(newName);
Node lp = newNode(Token.LP);
// The left paren's complicated because it's not represented by an
// AstNode, so there's nothing that has the actual line number that it
// appeared on. We know the paren has to appear on the same line as the
// function name (or else a semicolon will be inserted.) If there's no
// function name, assume the paren was on the same line as the function.
// TODO(bowdidge): Mark line number of paren correctly.
Name fnName = functionNode.getFunctionName();
if (fnName != null) {
lp.setLineno(fnName.getLineno());
} else {
lp.setLineno(functionNode.getLineno());
}
int lparenCharno = functionNode.getLp() +
functionNode.getAbsolutePosition();
lp.setCharno(position2charno(lparenCharno));
for (AstNode param : functionNode.getParams()) {
lp.addChildToBack(transform(param));
}
node.addChildToBack(lp);
Node bodyNode = transform(functionNode.getBody());
parseDirectives(bodyNode);
node.addChildToBack(bodyNode);
return node;
}
```
| @Override
Node processFunctionNode(FunctionNode functionNode) {
Name name = functionNode.getFunctionName();
Boolean isUnnamedFunction = false;
if (name == null) {
int functionType = functionNode.getFunctionType();
if (functionType != FunctionNode.FUNCTION_EXPRESSION) {
errorReporter.error(
"unnamed function statement",
sourceName,
functionNode.getLineno(), "", 0);
}
name = new Name();
name.setIdentifier("");
isUnnamedFunction = true;
}
Node node = newNode(Token.FUNCTION);
Node newName = transform(name);
if (isUnnamedFunction) {
// Old Rhino tagged the empty name node with the line number of the
// declaration.
newName.setLineno(functionNode.getLineno());
// TODO(bowdidge) Mark line number of paren correctly.
// Same problem as below - the left paren might not be on the
// same line as the function keyword.
int lpColumn = functionNode.getAbsolutePosition() +
functionNode.getLp();
newName.setCharno(position2charno(lpColumn));
}
node.addChildToBack(newName);
Node lp = newNode(Token.LP);
// The left paren's complicated because it's not represented by an
// AstNode, so there's nothing that has the actual line number that it
// appeared on. We know the paren has to appear on the same line as the
// function name (or else a semicolon will be inserted.) If there's no
// function name, assume the paren was on the same line as the function.
// TODO(bowdidge): Mark line number of paren correctly.
Name fnName = functionNode.getFunctionName();
if (fnName != null) {
lp.setLineno(fnName.getLineno());
} else {
lp.setLineno(functionNode.getLineno());
}
int lparenCharno = functionNode.getLp() +
functionNode.getAbsolutePosition();
lp.setCharno(position2charno(lparenCharno));
for (AstNode param : functionNode.getParams()) {
lp.addChildToBack(transform(param));
}
node.addChildToBack(lp);
Node bodyNode = transform(functionNode.getBody());
parseDirectives(bodyNode);
node.addChildToBack(bodyNode);
return node;
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
Node processFunctionNode(FunctionNode functionNode) {
Name name = functionNode.getFunctionName();
Boolean isUnnamedFunction = false;
if (name == null) {
int functionType = functionNode.getFunctionType();
if (functionType != FunctionNode.FUNCTION_EXPRESSION) {
errorReporter.error(
"unnamed function statement",
sourceName,
functionNode.getLineno(), "", 0);
}
name = new Name();
name.setIdentifier("");
isUnnamedFunction = true;
}
Node node = newNode(Token.FUNCTION);
Node newName = transform(name);
if (isUnnamedFunction) {
// Old Rhino tagged the empty name node with the line number of the
// declaration.
newName.setLineno(functionNode.getLineno());
// TODO(bowdidge) Mark line number of paren correctly.
// Same problem as below - the left paren might not be on the
// same line as the function keyword.
int lpColumn = functionNode.getAbsolutePosition() +
functionNode.getLp();
newName.setCharno(position2charno(lpColumn));
}
node.addChildToBack(newName);
Node lp = newNode(Token.LP);
// The left paren's complicated because it's not represented by an
// AstNode, so there's nothing that has the actual line number that it
// appeared on. We know the paren has to appear on the same line as the
// function name (or else a semicolon will be inserted.) If there's no
// function name, assume the paren was on the same line as the function.
// TODO(bowdidge): Mark line number of paren correctly.
Name fnName = functionNode.getFunctionName();
if (fnName != null) {
lp.setLineno(fnName.getLineno());
} else {
lp.setLineno(functionNode.getLineno());
}
int lparenCharno = functionNode.getLp() +
functionNode.getAbsolutePosition();
lp.setCharno(position2charno(lparenCharno));
for (AstNode param : functionNode.getParams()) {
lp.addChildToBack(transform(param));
}
node.addChildToBack(lp);
Node bodyNode = transform(functionNode.getBody());
parseDirectives(bodyNode);
node.addChildToBack(bodyNode);
return node;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
37 | 50cd2926ee9064f53ddc9371c4c3db24ce91af2c6598a0df69d9f5cca2dce44a | Map<String, String> parsePaxHeaders(final InputStream i)
throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
// https://www.gnu.org/software/tar/manual/html_section/tar_92.html#SEC188
// sparse files using the PAX Format 0.0, see
// NOTE, using a Map here makes it impossible to ever support GNU
Map<String, String> parsePaxHeaders(final InputStream i)
throws IOException {
final Map<String, String> headers = new HashMap<String, String>(globalPaxHeaders);
// Format is "length keyword=value\n";
while(true){ // get length
int ch;
int len = 0;
int read = 0;
while((ch = i.read()) != -1) {
read++;
if (ch == ' '){
// Get keyword
final ByteArrayOutputStream coll = new ByteArrayOutputStream();
while((ch = i.read()) != -1) {
read++;
if (ch == '='){ // end of keyword
final String keyword = coll.toString(CharsetNames.UTF_8);
// Get rest of entry
final int restLen = len - read;
if (restLen == 1) { // only NL
headers.remove(keyword);
} else {
final byte[] rest = new byte[restLen];
final int got = IOUtils.readFully(i, rest);
if (got != restLen) {
throw new IOException("Failed to read "
+ "Paxheader. Expected "
+ restLen
+ " bytes, read "
+ got);
}
// Drop trailing NL
final String value = new String(rest, 0,
restLen - 1, CharsetNames.UTF_8);
headers.put(keyword, value);
}
break;
}
coll.write((byte) ch);
}
break; // Processed single header
}
len *= 10;
len += ch - '0';
}
if (ch == -1){ // EOF
break;
}
}
return headers;
}
```
| Map<String, String> parsePaxHeaders(final InputStream i)
throws IOException {
final Map<String, String> headers = new HashMap<String, String>(globalPaxHeaders);
// Format is "length keyword=value\n";
while(true){ // get length
int ch;
int len = 0;
int read = 0;
while((ch = i.read()) != -1) {
read++;
if (ch == ' '){
// Get keyword
final ByteArrayOutputStream coll = new ByteArrayOutputStream();
while((ch = i.read()) != -1) {
read++;
if (ch == '='){ // end of keyword
final String keyword = coll.toString(CharsetNames.UTF_8);
// Get rest of entry
final int restLen = len - read;
if (restLen == 1) { // only NL
headers.remove(keyword);
} else {
final byte[] rest = new byte[restLen];
final int got = IOUtils.readFully(i, rest);
if (got != restLen) {
throw new IOException("Failed to read "
+ "Paxheader. Expected "
+ restLen
+ " bytes, read "
+ got);
}
// Drop trailing NL
final String value = new String(rest, 0,
restLen - 1, CharsetNames.UTF_8);
headers.put(keyword, value);
}
break;
}
coll.write((byte) ch);
}
break; // Processed single header
}
len *= 10;
len += ch - '0';
}
if (ch == -1){ // EOF
break;
}
}
return headers;
} | true | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
// https://www.gnu.org/software/tar/manual/html_section/tar_92.html#SEC188
// sparse files using the PAX Format 0.0, see
// NOTE, using a Map here makes it impossible to ever support GNU
Map<String, String> parsePaxHeaders(final InputStream i)
throws IOException {
final Map<String, String> headers = new HashMap<String, String>(globalPaxHeaders);
// Format is "length keyword=value\n";
while(true){ // get length
int ch;
int len = 0;
int read = 0;
while((ch = i.read()) != -1) {
read++;
if (ch == ' '){
// Get keyword
final ByteArrayOutputStream coll = new ByteArrayOutputStream();
while((ch = i.read()) != -1) {
read++;
if (ch == '='){ // end of keyword
final String keyword = coll.toString(CharsetNames.UTF_8);
// Get rest of entry
final int restLen = len - read;
if (restLen == 1) { // only NL
headers.remove(keyword);
} else {
final byte[] rest = new byte[restLen];
final int got = IOUtils.readFully(i, rest);
if (got != restLen) {
throw new IOException("Failed to read "
+ "Paxheader. Expected "
+ restLen
+ " bytes, read "
+ got);
}
// Drop trailing NL
final String value = new String(rest, 0,
restLen - 1, CharsetNames.UTF_8);
headers.put(keyword, value);
}
break;
}
coll.write((byte) ch);
}
break; // Processed single header
}
len *= 10;
len += ch - '0';
}
if (ch == -1){ // EOF
break;
}
}
return headers;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
21 | 517ab964151a4bec4a20e1b983ef0e10ba210a6430a1b864ecdd3e4919980f77 | public int getLength() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* If the property contains a collection, then the length of that
* collection, otherwise - 1.
* @return int length
*/
public int getLength() {
return ValueUtils.getLength(getBaseValue());
}
```
| public int getLength() {
return ValueUtils.getLength(getBaseValue());
} | true | JxPath | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* If the property contains a collection, then the length of that
* collection, otherwise - 1.
* @return int length
*/
public int getLength() {
return ValueUtils.getLength(getBaseValue());
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
29 | 51bf02a991fb3cf4699d3a5fddc2b2efe84e2d8ead2b96d513913ff84e584621 | static String stripLeadingAndTrailingQuotes(String str)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Remove the leading and trailing quotes from <code>str</code>.
* E.g. if str is '"one two"', then 'one two' is returned.
*
* @param str The string from which the leading and trailing quotes
* should be removed.
*
* @return The string without the leading and trailing quotes.
*/
static String stripLeadingAndTrailingQuotes(String str)
{
if (str.startsWith("\""))
{
str = str.substring(1, str.length());
}
int length = str.length();
if (str.endsWith("\""))
{
str = str.substring(0, length - 1);
}
return str;
}
```
| static String stripLeadingAndTrailingQuotes(String str)
{
if (str.startsWith("\""))
{
str = str.substring(1, str.length());
}
int length = str.length();
if (str.endsWith("\""))
{
str = str.substring(0, length - 1);
}
return str;
} | true | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Remove the leading and trailing quotes from <code>str</code>.
* E.g. if str is '"one two"', then 'one two' is returned.
*
* @param str The string from which the leading and trailing quotes
* should be removed.
*
* @return The string without the leading and trailing quotes.
*/
static String stripLeadingAndTrailingQuotes(String str)
{
if (str.startsWith("\""))
{
str = str.substring(1, str.length());
}
int length = str.length();
if (str.endsWith("\""))
{
str = str.substring(0, length - 1);
}
return str;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
105 | 523d2cbadafadd929bdee35bf9b4a7505fcbe78370ca962294533099099d7ec0 | void tryFoldStringJoin(NodeTraversal t, Node n, Node left, Node right,
Node parent) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Try to fold an array join: ['a', 'b', 'c'].join('') -> 'abc';
*/
void tryFoldStringJoin(NodeTraversal t, Node n, Node left, Node right,
Node parent) {
if (!NodeUtil.isGetProp(left) || !NodeUtil.isImmutableValue(right)) {
return;
}
Node arrayNode = left.getFirstChild();
Node functionName = arrayNode.getNext();
if ((arrayNode.getType() != Token.ARRAYLIT) ||
!functionName.getString().equals("join")) {
return;
}
String joinString = NodeUtil.getStringValue(right);
List<Node> arrayFoldedChildren = Lists.newLinkedList();
StringBuilder sb = new StringBuilder();
int foldedSize = 0;
Node elem = arrayNode.getFirstChild();
// Merges adjacent String nodes.
while (elem != null) {
if (NodeUtil.isImmutableValue(elem)) {
if (sb.length() > 0) {
sb.append(joinString);
}
sb.append(NodeUtil.getStringValue(elem));
} else {
if (sb.length() > 0) {
// + 2 for the quotes.
foldedSize += sb.length() + 2;
arrayFoldedChildren.add(Node.newString(sb.toString()));
sb = new StringBuilder();
}
foldedSize += InlineCostEstimator.getCost(elem);
arrayFoldedChildren.add(elem);
}
elem = elem.getNext();
}
if (sb.length() > 0) {
// + 2 for the quotes.
foldedSize += sb.length() + 2;
arrayFoldedChildren.add(Node.newString(sb.toString()));
}
// one for each comma.
foldedSize += arrayFoldedChildren.size() - 1;
int originalSize = InlineCostEstimator.getCost(n);
switch (arrayFoldedChildren.size()) {
case 0:
Node emptyStringNode = Node.newString("");
parent.replaceChild(n, emptyStringNode);
break;
case 1:
Node foldedStringNode = arrayFoldedChildren.remove(0);
if (foldedSize > originalSize) {
return;
}
arrayNode.detachChildren();
if (foldedStringNode.getType() != Token.STRING) {
// If the Node is not a string literal, ensure that
// it is coerced to a string.
Node replacement = new Node(Token.ADD,
Node.newString(""), foldedStringNode);
foldedStringNode = replacement;
}
parent.replaceChild(n, foldedStringNode);
break;
default:
// No folding could actually be performed.
if (arrayFoldedChildren.size() == arrayNode.getChildCount()) {
return;
}
int kJoinOverhead = "[].join()".length();
foldedSize += kJoinOverhead;
foldedSize += InlineCostEstimator.getCost(right);
if (foldedSize > originalSize) {
return;
}
arrayNode.detachChildren();
for (Node node : arrayFoldedChildren) {
arrayNode.addChildToBack(node);
}
break;
}
t.getCompiler().reportCodeChange();
}
```
| void tryFoldStringJoin(NodeTraversal t, Node n, Node left, Node right,
Node parent) {
if (!NodeUtil.isGetProp(left) || !NodeUtil.isImmutableValue(right)) {
return;
}
Node arrayNode = left.getFirstChild();
Node functionName = arrayNode.getNext();
if ((arrayNode.getType() != Token.ARRAYLIT) ||
!functionName.getString().equals("join")) {
return;
}
String joinString = NodeUtil.getStringValue(right);
List<Node> arrayFoldedChildren = Lists.newLinkedList();
StringBuilder sb = new StringBuilder();
int foldedSize = 0;
Node elem = arrayNode.getFirstChild();
// Merges adjacent String nodes.
while (elem != null) {
if (NodeUtil.isImmutableValue(elem)) {
if (sb.length() > 0) {
sb.append(joinString);
}
sb.append(NodeUtil.getStringValue(elem));
} else {
if (sb.length() > 0) {
// + 2 for the quotes.
foldedSize += sb.length() + 2;
arrayFoldedChildren.add(Node.newString(sb.toString()));
sb = new StringBuilder();
}
foldedSize += InlineCostEstimator.getCost(elem);
arrayFoldedChildren.add(elem);
}
elem = elem.getNext();
}
if (sb.length() > 0) {
// + 2 for the quotes.
foldedSize += sb.length() + 2;
arrayFoldedChildren.add(Node.newString(sb.toString()));
}
// one for each comma.
foldedSize += arrayFoldedChildren.size() - 1;
int originalSize = InlineCostEstimator.getCost(n);
switch (arrayFoldedChildren.size()) {
case 0:
Node emptyStringNode = Node.newString("");
parent.replaceChild(n, emptyStringNode);
break;
case 1:
Node foldedStringNode = arrayFoldedChildren.remove(0);
if (foldedSize > originalSize) {
return;
}
arrayNode.detachChildren();
if (foldedStringNode.getType() != Token.STRING) {
// If the Node is not a string literal, ensure that
// it is coerced to a string.
Node replacement = new Node(Token.ADD,
Node.newString(""), foldedStringNode);
foldedStringNode = replacement;
}
parent.replaceChild(n, foldedStringNode);
break;
default:
// No folding could actually be performed.
if (arrayFoldedChildren.size() == arrayNode.getChildCount()) {
return;
}
int kJoinOverhead = "[].join()".length();
foldedSize += kJoinOverhead;
foldedSize += InlineCostEstimator.getCost(right);
if (foldedSize > originalSize) {
return;
}
arrayNode.detachChildren();
for (Node node : arrayFoldedChildren) {
arrayNode.addChildToBack(node);
}
break;
}
t.getCompiler().reportCodeChange();
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Try to fold an array join: ['a', 'b', 'c'].join('') -> 'abc';
*/
void tryFoldStringJoin(NodeTraversal t, Node n, Node left, Node right,
Node parent) {
if (!NodeUtil.isGetProp(left) || !NodeUtil.isImmutableValue(right)) {
return;
}
Node arrayNode = left.getFirstChild();
Node functionName = arrayNode.getNext();
if ((arrayNode.getType() != Token.ARRAYLIT) ||
!functionName.getString().equals("join")) {
return;
}
String joinString = NodeUtil.getStringValue(right);
List<Node> arrayFoldedChildren = Lists.newLinkedList();
StringBuilder sb = new StringBuilder();
int foldedSize = 0;
Node elem = arrayNode.getFirstChild();
// Merges adjacent String nodes.
while (elem != null) {
if (NodeUtil.isImmutableValue(elem)) {
if (sb.length() > 0) {
sb.append(joinString);
}
sb.append(NodeUtil.getStringValue(elem));
} else {
if (sb.length() > 0) {
// + 2 for the quotes.
foldedSize += sb.length() + 2;
arrayFoldedChildren.add(Node.newString(sb.toString()));
sb = new StringBuilder();
}
foldedSize += InlineCostEstimator.getCost(elem);
arrayFoldedChildren.add(elem);
}
elem = elem.getNext();
}
if (sb.length() > 0) {
// + 2 for the quotes.
foldedSize += sb.length() + 2;
arrayFoldedChildren.add(Node.newString(sb.toString()));
}
// one for each comma.
foldedSize += arrayFoldedChildren.size() - 1;
int originalSize = InlineCostEstimator.getCost(n);
switch (arrayFoldedChildren.size()) {
case 0:
Node emptyStringNode = Node.newString("");
parent.replaceChild(n, emptyStringNode);
break;
case 1:
Node foldedStringNode = arrayFoldedChildren.remove(0);
if (foldedSize > originalSize) {
return;
}
arrayNode.detachChildren();
if (foldedStringNode.getType() != Token.STRING) {
// If the Node is not a string literal, ensure that
// it is coerced to a string.
Node replacement = new Node(Token.ADD,
Node.newString(""), foldedStringNode);
foldedStringNode = replacement;
}
parent.replaceChild(n, foldedStringNode);
break;
default:
// No folding could actually be performed.
if (arrayFoldedChildren.size() == arrayNode.getChildCount()) {
return;
}
int kJoinOverhead = "[].join()".length();
foldedSize += kJoinOverhead;
foldedSize += InlineCostEstimator.getCost(right);
if (foldedSize > originalSize) {
return;
}
arrayNode.detachChildren();
for (Node node : arrayFoldedChildren) {
arrayNode.addChildToBack(node);
}
break;
}
t.getCompiler().reportCodeChange();
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
87 | 529c8020b475481ef2a438f7384c56d25fa617fabc5a24a71c62fff5f7b1eda0 | private Integer getBasicRow(final int col) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Checks whether the given column is basic.
* @param col index of the column to check
* @return the row that the variable is basic in. null if the column is not basic
*/
private Integer getBasicRow(final int col) {
Integer row = null;
for (int i = getNumObjectiveFunctions(); i < getHeight(); i++) {
if (!MathUtils.equals(getEntry(i, col), 0.0, epsilon)) {
if (row == null) {
row = i;
} else {
return null;
}
}
}
return row;
}
```
| private Integer getBasicRow(final int col) {
Integer row = null;
for (int i = getNumObjectiveFunctions(); i < getHeight(); i++) {
if (!MathUtils.equals(getEntry(i, col), 0.0, epsilon)) {
if (row == null) {
row = i;
} else {
return null;
}
}
}
return row;
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Checks whether the given column is basic.
* @param col index of the column to check
* @return the row that the variable is basic in. null if the column is not basic
*/
private Integer getBasicRow(final int col) {
Integer row = null;
for (int i = getNumObjectiveFunctions(); i < getHeight(); i++) {
if (!MathUtils.equals(getEntry(i, col), 0.0, epsilon)) {
if (row == null) {
row = i;
} else {
return null;
}
}
}
return row;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
66 | 52a3ebc9d8ed2080a334007c017faa3bdfd1b32dd26f25e005c4ba9dd0ca45a1 | public void visit(NodeTraversal t, Node n, Node parent) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* This is the meat of the type checking. It is basically one big switch,
* with each case representing one type of parse tree node. The individual
* cases are usually pretty straightforward.
*
* @param t The node traversal object that supplies context, such as the
* scope chain to use in name lookups as well as error reporting.
* @param n The node being visited.
* @param parent The parent of the node n.
*/
public void visit(NodeTraversal t, Node n, Node parent) {
JSType childType;
JSType leftType, rightType;
Node left, right;
// To be explicitly set to false if the node is not typeable.
boolean typeable = true;
switch (n.getType()) {
case Token.NAME:
typeable = visitName(t, n, parent);
break;
case Token.LP:
// If this is under a FUNCTION node, it is a parameter list and can be
// ignored here.
if (parent.getType() != Token.FUNCTION) {
ensureTyped(t, n, getJSType(n.getFirstChild()));
} else {
typeable = false;
}
break;
case Token.COMMA:
ensureTyped(t, n, getJSType(n.getLastChild()));
break;
case Token.TRUE:
case Token.FALSE:
ensureTyped(t, n, BOOLEAN_TYPE);
break;
case Token.THIS:
ensureTyped(t, n, t.getScope().getTypeOfThis());
break;
case Token.REF_SPECIAL:
ensureTyped(t, n);
break;
case Token.GET_REF:
ensureTyped(t, n, getJSType(n.getFirstChild()));
break;
case Token.NULL:
ensureTyped(t, n, NULL_TYPE);
break;
case Token.NUMBER:
ensureTyped(t, n, NUMBER_TYPE);
break;
case Token.STRING:
// Object literal keys are handled with OBJECTLIT
if (!NodeUtil.isObjectLitKey(n, n.getParent())) {
ensureTyped(t, n, STRING_TYPE);
} else {
// Object literal keys are not typeable
typeable = false;
}
break;
case Token.GET:
case Token.SET:
// Object literal keys are handled with OBJECTLIT
break;
case Token.ARRAYLIT:
ensureTyped(t, n, ARRAY_TYPE);
break;
case Token.REGEXP:
ensureTyped(t, n, REGEXP_TYPE);
break;
case Token.GETPROP:
visitGetProp(t, n, parent);
typeable = !(parent.getType() == Token.ASSIGN &&
parent.getFirstChild() == n);
break;
case Token.GETELEM:
visitGetElem(t, n);
// The type of GETELEM is always unknown, so no point counting that.
// If that unknown leaks elsewhere (say by an assignment to another
// variable), then it will be counted.
typeable = false;
break;
case Token.VAR:
visitVar(t, n);
typeable = false;
break;
case Token.NEW:
visitNew(t, n);
typeable = true;
break;
case Token.CALL:
visitCall(t, n);
typeable = !NodeUtil.isExpressionNode(parent);
break;
case Token.RETURN:
visitReturn(t, n);
typeable = false;
break;
case Token.DEC:
case Token.INC:
left = n.getFirstChild();
validator.expectNumber(
t, left, getJSType(left), "increment/decrement");
ensureTyped(t, n, NUMBER_TYPE);
break;
case Token.NOT:
ensureTyped(t, n, BOOLEAN_TYPE);
break;
case Token.VOID:
ensureTyped(t, n, VOID_TYPE);
break;
case Token.TYPEOF:
ensureTyped(t, n, STRING_TYPE);
break;
case Token.BITNOT:
childType = getJSType(n.getFirstChild());
if (!childType.matchesInt32Context()) {
report(t, n, BIT_OPERATION, NodeUtil.opToStr(n.getType()),
childType.toString());
}
ensureTyped(t, n, NUMBER_TYPE);
break;
case Token.POS:
case Token.NEG:
left = n.getFirstChild();
validator.expectNumber(t, left, getJSType(left), "sign operator");
ensureTyped(t, n, NUMBER_TYPE);
break;
case Token.EQ:
case Token.NE: {
leftType = getJSType(n.getFirstChild());
rightType = getJSType(n.getLastChild());
JSType leftTypeRestricted = leftType.restrictByNotNullOrUndefined();
JSType rightTypeRestricted = rightType.restrictByNotNullOrUndefined();
TernaryValue result =
leftTypeRestricted.testForEquality(rightTypeRestricted);
if (result != TernaryValue.UNKNOWN) {
if (n.getType() == Token.NE) {
result = result.not();
}
report(t, n, DETERMINISTIC_TEST, leftType.toString(),
rightType.toString(), result.toString());
}
ensureTyped(t, n, BOOLEAN_TYPE);
break;
}
case Token.SHEQ:
case Token.SHNE: {
leftType = getJSType(n.getFirstChild());
rightType = getJSType(n.getLastChild());
JSType leftTypeRestricted = leftType.restrictByNotNullOrUndefined();
JSType rightTypeRestricted = rightType.restrictByNotNullOrUndefined();
if (!leftTypeRestricted.canTestForShallowEqualityWith(
rightTypeRestricted)) {
report(t, n, DETERMINISTIC_TEST_NO_RESULT, leftType.toString(),
rightType.toString());
}
ensureTyped(t, n, BOOLEAN_TYPE);
break;
}
case Token.LT:
case Token.LE:
case Token.GT:
case Token.GE:
leftType = getJSType(n.getFirstChild());
rightType = getJSType(n.getLastChild());
if (rightType.isNumber()) {
validator.expectNumber(
t, n, leftType, "left side of numeric comparison");
} else if (leftType.isNumber()) {
validator.expectNumber(
t, n, rightType, "right side of numeric comparison");
} else if (leftType.matchesNumberContext() &&
rightType.matchesNumberContext()) {
// OK.
} else {
// Whether the comparison is numeric will be determined at runtime
// each time the expression is evaluated. Regardless, both operands
// should match a string context.
String message = "left side of comparison";
validator.expectString(t, n, leftType, message);
validator.expectNotNullOrUndefined(
t, n, leftType, message, getNativeType(STRING_TYPE));
message = "right side of comparison";
validator.expectString(t, n, rightType, message);
validator.expectNotNullOrUndefined(
t, n, rightType, message, getNativeType(STRING_TYPE));
}
ensureTyped(t, n, BOOLEAN_TYPE);
break;
case Token.IN:
left = n.getFirstChild();
right = n.getLastChild();
leftType = getJSType(left);
rightType = getJSType(right);
validator.expectObject(t, n, rightType, "'in' requires an object");
validator.expectString(t, left, leftType, "left side of 'in'");
ensureTyped(t, n, BOOLEAN_TYPE);
break;
case Token.INSTANCEOF:
left = n.getFirstChild();
right = n.getLastChild();
leftType = getJSType(left);
rightType = getJSType(right).restrictByNotNullOrUndefined();
validator.expectAnyObject(
t, left, leftType, "deterministic instanceof yields false");
validator.expectActualObject(
t, right, rightType, "instanceof requires an object");
ensureTyped(t, n, BOOLEAN_TYPE);
break;
case Token.ASSIGN:
visitAssign(t, n);
typeable = false;
break;
case Token.ASSIGN_LSH:
case Token.ASSIGN_RSH:
case Token.ASSIGN_URSH:
case Token.ASSIGN_DIV:
case Token.ASSIGN_MOD:
case Token.ASSIGN_BITOR:
case Token.ASSIGN_BITXOR:
case Token.ASSIGN_BITAND:
case Token.ASSIGN_SUB:
case Token.ASSIGN_ADD:
case Token.ASSIGN_MUL:
case Token.LSH:
case Token.RSH:
case Token.URSH:
case Token.DIV:
case Token.MOD:
case Token.BITOR:
case Token.BITXOR:
case Token.BITAND:
case Token.SUB:
case Token.ADD:
case Token.MUL:
visitBinaryOperator(n.getType(), t, n);
break;
case Token.DELPROP:
if (!isReference(n.getFirstChild())) {
report(t, n, BAD_DELETE);
}
ensureTyped(t, n, BOOLEAN_TYPE);
break;
case Token.CASE:
JSType switchType = getJSType(parent.getFirstChild());
JSType caseType = getJSType(n.getFirstChild());
validator.expectSwitchMatchesCase(t, n, switchType, caseType);
typeable = false;
break;
case Token.WITH: {
Node child = n.getFirstChild();
childType = getJSType(child);
validator.expectObject(
t, child, childType, "with requires an object");
typeable = false;
break;
}
case Token.FUNCTION:
visitFunction(t, n);
break;
// These nodes have no interesting type behavior.
case Token.LABEL:
case Token.LABEL_NAME:
case Token.SWITCH:
case Token.BREAK:
case Token.CATCH:
case Token.TRY:
case Token.SCRIPT:
case Token.EXPR_RESULT:
case Token.BLOCK:
case Token.EMPTY:
case Token.DEFAULT:
case Token.CONTINUE:
case Token.DEBUGGER:
case Token.THROW:
typeable = false;
break;
// These nodes require data flow analysis.
case Token.DO:
case Token.FOR:
case Token.IF:
case Token.WHILE:
typeable = false;
break;
// These nodes are typed during the type inference.
case Token.AND:
case Token.HOOK:
case Token.OBJECTLIT:
case Token.OR:
if (n.getJSType() != null) { // If we didn't run type inference.
ensureTyped(t, n);
} else {
// If this is an enum, then give that type to the objectlit as well.
if ((n.getType() == Token.OBJECTLIT)
&& (parent.getJSType() instanceof EnumType)) {
ensureTyped(t, n, parent.getJSType());
} else {
ensureTyped(t, n);
}
}
if (n.getType() == Token.OBJECTLIT) {
for (Node key : n.children()) {
visitObjLitKey(t, key, n);
}
}
break;
default:
report(t, n, UNEXPECTED_TOKEN, Token.name(n.getType()));
ensureTyped(t, n);
break;
}
// Don't count externs since the user's code may not even use that part.
typeable = typeable && !inExterns;
if (typeable) {
doPercentTypedAccounting(t, n);
}
checkNoTypeCheckSection(n, false);
}
```
| public void visit(NodeTraversal t, Node n, Node parent) {
JSType childType;
JSType leftType, rightType;
Node left, right;
// To be explicitly set to false if the node is not typeable.
boolean typeable = true;
switch (n.getType()) {
case Token.NAME:
typeable = visitName(t, n, parent);
break;
case Token.LP:
// If this is under a FUNCTION node, it is a parameter list and can be
// ignored here.
if (parent.getType() != Token.FUNCTION) {
ensureTyped(t, n, getJSType(n.getFirstChild()));
} else {
typeable = false;
}
break;
case Token.COMMA:
ensureTyped(t, n, getJSType(n.getLastChild()));
break;
case Token.TRUE:
case Token.FALSE:
ensureTyped(t, n, BOOLEAN_TYPE);
break;
case Token.THIS:
ensureTyped(t, n, t.getScope().getTypeOfThis());
break;
case Token.REF_SPECIAL:
ensureTyped(t, n);
break;
case Token.GET_REF:
ensureTyped(t, n, getJSType(n.getFirstChild()));
break;
case Token.NULL:
ensureTyped(t, n, NULL_TYPE);
break;
case Token.NUMBER:
ensureTyped(t, n, NUMBER_TYPE);
break;
case Token.STRING:
// Object literal keys are handled with OBJECTLIT
if (!NodeUtil.isObjectLitKey(n, n.getParent())) {
ensureTyped(t, n, STRING_TYPE);
} else {
// Object literal keys are not typeable
typeable = false;
}
break;
case Token.GET:
case Token.SET:
// Object literal keys are handled with OBJECTLIT
break;
case Token.ARRAYLIT:
ensureTyped(t, n, ARRAY_TYPE);
break;
case Token.REGEXP:
ensureTyped(t, n, REGEXP_TYPE);
break;
case Token.GETPROP:
visitGetProp(t, n, parent);
typeable = !(parent.getType() == Token.ASSIGN &&
parent.getFirstChild() == n);
break;
case Token.GETELEM:
visitGetElem(t, n);
// The type of GETELEM is always unknown, so no point counting that.
// If that unknown leaks elsewhere (say by an assignment to another
// variable), then it will be counted.
typeable = false;
break;
case Token.VAR:
visitVar(t, n);
typeable = false;
break;
case Token.NEW:
visitNew(t, n);
typeable = true;
break;
case Token.CALL:
visitCall(t, n);
typeable = !NodeUtil.isExpressionNode(parent);
break;
case Token.RETURN:
visitReturn(t, n);
typeable = false;
break;
case Token.DEC:
case Token.INC:
left = n.getFirstChild();
validator.expectNumber(
t, left, getJSType(left), "increment/decrement");
ensureTyped(t, n, NUMBER_TYPE);
break;
case Token.NOT:
ensureTyped(t, n, BOOLEAN_TYPE);
break;
case Token.VOID:
ensureTyped(t, n, VOID_TYPE);
break;
case Token.TYPEOF:
ensureTyped(t, n, STRING_TYPE);
break;
case Token.BITNOT:
childType = getJSType(n.getFirstChild());
if (!childType.matchesInt32Context()) {
report(t, n, BIT_OPERATION, NodeUtil.opToStr(n.getType()),
childType.toString());
}
ensureTyped(t, n, NUMBER_TYPE);
break;
case Token.POS:
case Token.NEG:
left = n.getFirstChild();
validator.expectNumber(t, left, getJSType(left), "sign operator");
ensureTyped(t, n, NUMBER_TYPE);
break;
case Token.EQ:
case Token.NE: {
leftType = getJSType(n.getFirstChild());
rightType = getJSType(n.getLastChild());
JSType leftTypeRestricted = leftType.restrictByNotNullOrUndefined();
JSType rightTypeRestricted = rightType.restrictByNotNullOrUndefined();
TernaryValue result =
leftTypeRestricted.testForEquality(rightTypeRestricted);
if (result != TernaryValue.UNKNOWN) {
if (n.getType() == Token.NE) {
result = result.not();
}
report(t, n, DETERMINISTIC_TEST, leftType.toString(),
rightType.toString(), result.toString());
}
ensureTyped(t, n, BOOLEAN_TYPE);
break;
}
case Token.SHEQ:
case Token.SHNE: {
leftType = getJSType(n.getFirstChild());
rightType = getJSType(n.getLastChild());
JSType leftTypeRestricted = leftType.restrictByNotNullOrUndefined();
JSType rightTypeRestricted = rightType.restrictByNotNullOrUndefined();
if (!leftTypeRestricted.canTestForShallowEqualityWith(
rightTypeRestricted)) {
report(t, n, DETERMINISTIC_TEST_NO_RESULT, leftType.toString(),
rightType.toString());
}
ensureTyped(t, n, BOOLEAN_TYPE);
break;
}
case Token.LT:
case Token.LE:
case Token.GT:
case Token.GE:
leftType = getJSType(n.getFirstChild());
rightType = getJSType(n.getLastChild());
if (rightType.isNumber()) {
validator.expectNumber(
t, n, leftType, "left side of numeric comparison");
} else if (leftType.isNumber()) {
validator.expectNumber(
t, n, rightType, "right side of numeric comparison");
} else if (leftType.matchesNumberContext() &&
rightType.matchesNumberContext()) {
// OK.
} else {
// Whether the comparison is numeric will be determined at runtime
// each time the expression is evaluated. Regardless, both operands
// should match a string context.
String message = "left side of comparison";
validator.expectString(t, n, leftType, message);
validator.expectNotNullOrUndefined(
t, n, leftType, message, getNativeType(STRING_TYPE));
message = "right side of comparison";
validator.expectString(t, n, rightType, message);
validator.expectNotNullOrUndefined(
t, n, rightType, message, getNativeType(STRING_TYPE));
}
ensureTyped(t, n, BOOLEAN_TYPE);
break;
case Token.IN:
left = n.getFirstChild();
right = n.getLastChild();
leftType = getJSType(left);
rightType = getJSType(right);
validator.expectObject(t, n, rightType, "'in' requires an object");
validator.expectString(t, left, leftType, "left side of 'in'");
ensureTyped(t, n, BOOLEAN_TYPE);
break;
case Token.INSTANCEOF:
left = n.getFirstChild();
right = n.getLastChild();
leftType = getJSType(left);
rightType = getJSType(right).restrictByNotNullOrUndefined();
validator.expectAnyObject(
t, left, leftType, "deterministic instanceof yields false");
validator.expectActualObject(
t, right, rightType, "instanceof requires an object");
ensureTyped(t, n, BOOLEAN_TYPE);
break;
case Token.ASSIGN:
visitAssign(t, n);
typeable = false;
break;
case Token.ASSIGN_LSH:
case Token.ASSIGN_RSH:
case Token.ASSIGN_URSH:
case Token.ASSIGN_DIV:
case Token.ASSIGN_MOD:
case Token.ASSIGN_BITOR:
case Token.ASSIGN_BITXOR:
case Token.ASSIGN_BITAND:
case Token.ASSIGN_SUB:
case Token.ASSIGN_ADD:
case Token.ASSIGN_MUL:
case Token.LSH:
case Token.RSH:
case Token.URSH:
case Token.DIV:
case Token.MOD:
case Token.BITOR:
case Token.BITXOR:
case Token.BITAND:
case Token.SUB:
case Token.ADD:
case Token.MUL:
visitBinaryOperator(n.getType(), t, n);
break;
case Token.DELPROP:
if (!isReference(n.getFirstChild())) {
report(t, n, BAD_DELETE);
}
ensureTyped(t, n, BOOLEAN_TYPE);
break;
case Token.CASE:
JSType switchType = getJSType(parent.getFirstChild());
JSType caseType = getJSType(n.getFirstChild());
validator.expectSwitchMatchesCase(t, n, switchType, caseType);
typeable = false;
break;
case Token.WITH: {
Node child = n.getFirstChild();
childType = getJSType(child);
validator.expectObject(
t, child, childType, "with requires an object");
typeable = false;
break;
}
case Token.FUNCTION:
visitFunction(t, n);
break;
// These nodes have no interesting type behavior.
case Token.LABEL:
case Token.LABEL_NAME:
case Token.SWITCH:
case Token.BREAK:
case Token.CATCH:
case Token.TRY:
case Token.SCRIPT:
case Token.EXPR_RESULT:
case Token.BLOCK:
case Token.EMPTY:
case Token.DEFAULT:
case Token.CONTINUE:
case Token.DEBUGGER:
case Token.THROW:
typeable = false;
break;
// These nodes require data flow analysis.
case Token.DO:
case Token.FOR:
case Token.IF:
case Token.WHILE:
typeable = false;
break;
// These nodes are typed during the type inference.
case Token.AND:
case Token.HOOK:
case Token.OBJECTLIT:
case Token.OR:
if (n.getJSType() != null) { // If we didn't run type inference.
ensureTyped(t, n);
} else {
// If this is an enum, then give that type to the objectlit as well.
if ((n.getType() == Token.OBJECTLIT)
&& (parent.getJSType() instanceof EnumType)) {
ensureTyped(t, n, parent.getJSType());
} else {
ensureTyped(t, n);
}
}
if (n.getType() == Token.OBJECTLIT) {
for (Node key : n.children()) {
visitObjLitKey(t, key, n);
}
}
break;
default:
report(t, n, UNEXPECTED_TOKEN, Token.name(n.getType()));
ensureTyped(t, n);
break;
}
// Don't count externs since the user's code may not even use that part.
typeable = typeable && !inExterns;
if (typeable) {
doPercentTypedAccounting(t, n);
}
checkNoTypeCheckSection(n, false);
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* This is the meat of the type checking. It is basically one big switch,
* with each case representing one type of parse tree node. The individual
* cases are usually pretty straightforward.
*
* @param t The node traversal object that supplies context, such as the
* scope chain to use in name lookups as well as error reporting.
* @param n The node being visited.
* @param parent The parent of the node n.
*/
public void visit(NodeTraversal t, Node n, Node parent) {
JSType childType;
JSType leftType, rightType;
Node left, right;
// To be explicitly set to false if the node is not typeable.
boolean typeable = true;
switch (n.getType()) {
case Token.NAME:
typeable = visitName(t, n, parent);
break;
case Token.LP:
// If this is under a FUNCTION node, it is a parameter list and can be
// ignored here.
if (parent.getType() != Token.FUNCTION) {
ensureTyped(t, n, getJSType(n.getFirstChild()));
} else {
typeable = false;
}
break;
case Token.COMMA:
ensureTyped(t, n, getJSType(n.getLastChild()));
break;
case Token.TRUE:
case Token.FALSE:
ensureTyped(t, n, BOOLEAN_TYPE);
break;
case Token.THIS:
ensureTyped(t, n, t.getScope().getTypeOfThis());
break;
case Token.REF_SPECIAL:
ensureTyped(t, n);
break;
case Token.GET_REF:
ensureTyped(t, n, getJSType(n.getFirstChild()));
break;
case Token.NULL:
ensureTyped(t, n, NULL_TYPE);
break;
case Token.NUMBER:
ensureTyped(t, n, NUMBER_TYPE);
break;
case Token.STRING:
// Object literal keys are handled with OBJECTLIT
if (!NodeUtil.isObjectLitKey(n, n.getParent())) {
ensureTyped(t, n, STRING_TYPE);
} else {
// Object literal keys are not typeable
typeable = false;
}
break;
case Token.GET:
case Token.SET:
// Object literal keys are handled with OBJECTLIT
break;
case Token.ARRAYLIT:
ensureTyped(t, n, ARRAY_TYPE);
break;
case Token.REGEXP:
ensureTyped(t, n, REGEXP_TYPE);
break;
case Token.GETPROP:
visitGetProp(t, n, parent);
typeable = !(parent.getType() == Token.ASSIGN &&
parent.getFirstChild() == n);
break;
case Token.GETELEM:
visitGetElem(t, n);
// The type of GETELEM is always unknown, so no point counting that.
// If that unknown leaks elsewhere (say by an assignment to another
// variable), then it will be counted.
typeable = false;
break;
case Token.VAR:
visitVar(t, n);
typeable = false;
break;
case Token.NEW:
visitNew(t, n);
typeable = true;
break;
case Token.CALL:
visitCall(t, n);
typeable = !NodeUtil.isExpressionNode(parent);
break;
case Token.RETURN:
visitReturn(t, n);
typeable = false;
break;
case Token.DEC:
case Token.INC:
left = n.getFirstChild();
validator.expectNumber(
t, left, getJSType(left), "increment/decrement");
ensureTyped(t, n, NUMBER_TYPE);
break;
case Token.NOT:
ensureTyped(t, n, BOOLEAN_TYPE);
break;
case Token.VOID:
ensureTyped(t, n, VOID_TYPE);
break;
case Token.TYPEOF:
ensureTyped(t, n, STRING_TYPE);
break;
case Token.BITNOT:
childType = getJSType(n.getFirstChild());
if (!childType.matchesInt32Context()) {
report(t, n, BIT_OPERATION, NodeUtil.opToStr(n.getType()),
childType.toString());
}
ensureTyped(t, n, NUMBER_TYPE);
break;
case Token.POS:
case Token.NEG:
left = n.getFirstChild();
validator.expectNumber(t, left, getJSType(left), "sign operator");
ensureTyped(t, n, NUMBER_TYPE);
break;
case Token.EQ:
case Token.NE: {
leftType = getJSType(n.getFirstChild());
rightType = getJSType(n.getLastChild());
JSType leftTypeRestricted = leftType.restrictByNotNullOrUndefined();
JSType rightTypeRestricted = rightType.restrictByNotNullOrUndefined();
TernaryValue result =
leftTypeRestricted.testForEquality(rightTypeRestricted);
if (result != TernaryValue.UNKNOWN) {
if (n.getType() == Token.NE) {
result = result.not();
}
report(t, n, DETERMINISTIC_TEST, leftType.toString(),
rightType.toString(), result.toString());
}
ensureTyped(t, n, BOOLEAN_TYPE);
break;
}
case Token.SHEQ:
case Token.SHNE: {
leftType = getJSType(n.getFirstChild());
rightType = getJSType(n.getLastChild());
JSType leftTypeRestricted = leftType.restrictByNotNullOrUndefined();
JSType rightTypeRestricted = rightType.restrictByNotNullOrUndefined();
if (!leftTypeRestricted.canTestForShallowEqualityWith(
rightTypeRestricted)) {
report(t, n, DETERMINISTIC_TEST_NO_RESULT, leftType.toString(),
rightType.toString());
}
ensureTyped(t, n, BOOLEAN_TYPE);
break;
}
case Token.LT:
case Token.LE:
case Token.GT:
case Token.GE:
leftType = getJSType(n.getFirstChild());
rightType = getJSType(n.getLastChild());
if (rightType.isNumber()) {
validator.expectNumber(
t, n, leftType, "left side of numeric comparison");
} else if (leftType.isNumber()) {
validator.expectNumber(
t, n, rightType, "right side of numeric comparison");
} else if (leftType.matchesNumberContext() &&
rightType.matchesNumberContext()) {
// OK.
} else {
// Whether the comparison is numeric will be determined at runtime
// each time the expression is evaluated. Regardless, both operands
// should match a string context.
String message = "left side of comparison";
validator.expectString(t, n, leftType, message);
validator.expectNotNullOrUndefined(
t, n, leftType, message, getNativeType(STRING_TYPE));
message = "right side of comparison";
validator.expectString(t, n, rightType, message);
validator.expectNotNullOrUndefined(
t, n, rightType, message, getNativeType(STRING_TYPE));
}
ensureTyped(t, n, BOOLEAN_TYPE);
break;
case Token.IN:
left = n.getFirstChild();
right = n.getLastChild();
leftType = getJSType(left);
rightType = getJSType(right);
validator.expectObject(t, n, rightType, "'in' requires an object");
validator.expectString(t, left, leftType, "left side of 'in'");
ensureTyped(t, n, BOOLEAN_TYPE);
break;
case Token.INSTANCEOF:
left = n.getFirstChild();
right = n.getLastChild();
leftType = getJSType(left);
rightType = getJSType(right).restrictByNotNullOrUndefined();
validator.expectAnyObject(
t, left, leftType, "deterministic instanceof yields false");
validator.expectActualObject(
t, right, rightType, "instanceof requires an object");
ensureTyped(t, n, BOOLEAN_TYPE);
break;
case Token.ASSIGN:
visitAssign(t, n);
typeable = false;
break;
case Token.ASSIGN_LSH:
case Token.ASSIGN_RSH:
case Token.ASSIGN_URSH:
case Token.ASSIGN_DIV:
case Token.ASSIGN_MOD:
case Token.ASSIGN_BITOR:
case Token.ASSIGN_BITXOR:
case Token.ASSIGN_BITAND:
case Token.ASSIGN_SUB:
case Token.ASSIGN_ADD:
case Token.ASSIGN_MUL:
case Token.LSH:
case Token.RSH:
case Token.URSH:
case Token.DIV:
case Token.MOD:
case Token.BITOR:
case Token.BITXOR:
case Token.BITAND:
case Token.SUB:
case Token.ADD:
case Token.MUL:
visitBinaryOperator(n.getType(), t, n);
break;
case Token.DELPROP:
if (!isReference(n.getFirstChild())) {
report(t, n, BAD_DELETE);
}
ensureTyped(t, n, BOOLEAN_TYPE);
break;
case Token.CASE:
JSType switchType = getJSType(parent.getFirstChild());
JSType caseType = getJSType(n.getFirstChild());
validator.expectSwitchMatchesCase(t, n, switchType, caseType);
typeable = false;
break;
case Token.WITH: {
Node child = n.getFirstChild();
childType = getJSType(child);
validator.expectObject(
t, child, childType, "with requires an object");
typeable = false;
break;
}
case Token.FUNCTION:
visitFunction(t, n);
break;
// These nodes have no interesting type behavior.
case Token.LABEL:
case Token.LABEL_NAME:
case Token.SWITCH:
case Token.BREAK:
case Token.CATCH:
case Token.TRY:
case Token.SCRIPT:
case Token.EXPR_RESULT:
case Token.BLOCK:
case Token.EMPTY:
case Token.DEFAULT:
case Token.CONTINUE:
case Token.DEBUGGER:
case Token.THROW:
typeable = false;
break;
// These nodes require data flow analysis.
case Token.DO:
case Token.FOR:
case Token.IF:
case Token.WHILE:
typeable = false;
break;
// These nodes are typed during the type inference.
case Token.AND:
case Token.HOOK:
case Token.OBJECTLIT:
case Token.OR:
if (n.getJSType() != null) { // If we didn't run type inference.
ensureTyped(t, n);
} else {
// If this is an enum, then give that type to the objectlit as well.
if ((n.getType() == Token.OBJECTLIT)
&& (parent.getJSType() instanceof EnumType)) {
ensureTyped(t, n, parent.getJSType());
} else {
ensureTyped(t, n);
}
}
if (n.getType() == Token.OBJECTLIT) {
for (Node key : n.children()) {
visitObjLitKey(t, key, n);
}
}
break;
default:
report(t, n, UNEXPECTED_TOKEN, Token.name(n.getType()));
ensureTyped(t, n);
break;
}
// Don't count externs since the user's code may not even use that part.
typeable = typeable && !inExterns;
if (typeable) {
doPercentTypedAccounting(t, n);
}
checkNoTypeCheckSection(n, false);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
10 | 52d6dba4eb93e002b6aea28654383abb9fd6b3bb8593838175f87be328d5b7da | private static StringBuilder escapeRegex(StringBuilder regex, String value, boolean unquote) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Escape constant fields into regular expression
* @param regex The destination regex
* @param value The source field
* @param unquote If true, replace two success quotes ('') with single quote (')
* @return The <code>StringBuilder</code>
*/
//-----------------------------------------------------------------------
// Support for strategies
private static StringBuilder escapeRegex(StringBuilder regex, String value, boolean unquote) {
for(int i= 0; i<value.length(); ++i) {
char c= value.charAt(i);
switch(c) {
case '\'':
if(unquote) {
if(++i==value.length()) {
return regex;
}
c= value.charAt(i);
}
break;
case '?':
case '[':
case ']':
case '(':
case ')':
case '{':
case '}':
case '\\':
case '|':
case '*':
case '+':
case '^':
case '$':
case '.':
regex.append('\\');
}
regex.append(c);
}
return regex;
}
```
| private static StringBuilder escapeRegex(StringBuilder regex, String value, boolean unquote) {
for(int i= 0; i<value.length(); ++i) {
char c= value.charAt(i);
switch(c) {
case '\'':
if(unquote) {
if(++i==value.length()) {
return regex;
}
c= value.charAt(i);
}
break;
case '?':
case '[':
case ']':
case '(':
case ')':
case '{':
case '}':
case '\\':
case '|':
case '*':
case '+':
case '^':
case '$':
case '.':
regex.append('\\');
}
regex.append(c);
}
return regex;
} | false | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Escape constant fields into regular expression
* @param regex The destination regex
* @param value The source field
* @param unquote If true, replace two success quotes ('') with single quote (')
* @return The <code>StringBuilder</code>
*/
//-----------------------------------------------------------------------
// Support for strategies
private static StringBuilder escapeRegex(StringBuilder regex, String value, boolean unquote) {
for(int i= 0; i<value.length(); ++i) {
char c= value.charAt(i);
switch(c) {
case '\'':
if(unquote) {
if(++i==value.length()) {
return regex;
}
c= value.charAt(i);
}
break;
case '?':
case '[':
case ']':
case '(':
case ')':
case '{':
case '}':
case '\\':
case '|':
case '*':
case '+':
case '^':
case '$':
case '.':
regex.append('\\');
}
regex.append(c);
}
return regex;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
17 | 52e44e642530af8eb7c4489de0a13f1bac9f410a1c15ebaf7ded8137e3ccf9fe | public final void translate(CharSequence input, Writer out) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Translate an input onto a Writer. This is intentionally final as its algorithm is
* tightly coupled with the abstract method of this class.
*
* @param input CharSequence that is being translated
* @param out Writer to translate the text to
* @throws IOException if and only if the Writer produces an IOException
*/
public final void translate(CharSequence input, Writer out) throws IOException {
if (out == null) {
throw new IllegalArgumentException("The Writer must not be null");
}
if (input == null) {
return;
}
int pos = 0;
int len = Character.codePointCount(input, 0, input.length());
while (pos < len) {
int consumed = translate(input, pos, out);
if (consumed == 0) {
char[] c = Character.toChars(Character.codePointAt(input, pos));
out.write(c);
}
else {
// // contract with translators is that they have to understand codepoints
// // and they just took care of a surrogate pair
for (int pt = 0; pt < consumed; pt++) {
if (pos < len - 2) {
pos += Character.charCount(Character.codePointAt(input, pos));
} else {
pos++;
}
}
pos--;
}
pos++;
}
}
```
| public final void translate(CharSequence input, Writer out) throws IOException {
if (out == null) {
throw new IllegalArgumentException("The Writer must not be null");
}
if (input == null) {
return;
}
int pos = 0;
int len = Character.codePointCount(input, 0, input.length());
while (pos < len) {
int consumed = translate(input, pos, out);
if (consumed == 0) {
char[] c = Character.toChars(Character.codePointAt(input, pos));
out.write(c);
}
else {
// // contract with translators is that they have to understand codepoints
// // and they just took care of a surrogate pair
for (int pt = 0; pt < consumed; pt++) {
if (pos < len - 2) {
pos += Character.charCount(Character.codePointAt(input, pos));
} else {
pos++;
}
}
pos--;
}
pos++;
}
} | true | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Translate an input onto a Writer. This is intentionally final as its algorithm is
* tightly coupled with the abstract method of this class.
*
* @param input CharSequence that is being translated
* @param out Writer to translate the text to
* @throws IOException if and only if the Writer produces an IOException
*/
public final void translate(CharSequence input, Writer out) throws IOException {
if (out == null) {
throw new IllegalArgumentException("The Writer must not be null");
}
if (input == null) {
return;
}
int pos = 0;
int len = Character.codePointCount(input, 0, input.length());
while (pos < len) {
int consumed = translate(input, pos, out);
if (consumed == 0) {
char[] c = Character.toChars(Character.codePointAt(input, pos));
out.write(c);
}
else {
// // contract with translators is that they have to understand codepoints
// // and they just took care of a surrogate pair
for (int pt = 0; pt < consumed; pt++) {
if (pos < len - 2) {
pos += Character.charCount(Character.codePointAt(input, pos));
} else {
pos++;
}
}
pos--;
}
pos++;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
2 | 52f815fdf61f3d0723d7758da87917d2826d324d35062e3dd955420f1bcbd32e | private void checkInterfaceConflictProperties(NodeTraversal t, Node n,
String functionName, HashMap<String, ObjectType> properties,
HashMap<String, ObjectType> currentProperties,
ObjectType interfaceType) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Check whether there's any property conflict for for a particular super
* interface
* @param t The node traversal object that supplies context
* @param n The node being visited
* @param functionName The function name being checked
* @param properties The property names in the super interfaces that have
* been visited
* @param currentProperties The property names in the super interface
* that have been visited
* @param interfaceType The super interface that is being visited
*/
private void checkInterfaceConflictProperties(NodeTraversal t, Node n,
String functionName, HashMap<String, ObjectType> properties,
HashMap<String, ObjectType> currentProperties,
ObjectType interfaceType) {
ObjectType implicitProto = interfaceType.getImplicitPrototype();
Set<String> currentPropertyNames;
// This can be the case if interfaceType is proxy to a non-existent
// object (which is a bad type annotation, but shouldn't crash).
currentPropertyNames = implicitProto.getOwnPropertyNames();
for (String name : currentPropertyNames) {
ObjectType oType = properties.get(name);
if (oType != null) {
if (!interfaceType.getPropertyType(name).isEquivalentTo(
oType.getPropertyType(name))) {
compiler.report(
t.makeError(n, INCOMPATIBLE_EXTENDED_PROPERTY_TYPE,
functionName, name, oType.toString(),
interfaceType.toString()));
}
}
currentProperties.put(name, interfaceType);
}
for (ObjectType iType : interfaceType.getCtorExtendedInterfaces()) {
checkInterfaceConflictProperties(t, n, functionName, properties,
currentProperties, iType);
}
}
```
| private void checkInterfaceConflictProperties(NodeTraversal t, Node n,
String functionName, HashMap<String, ObjectType> properties,
HashMap<String, ObjectType> currentProperties,
ObjectType interfaceType) {
ObjectType implicitProto = interfaceType.getImplicitPrototype();
Set<String> currentPropertyNames;
// This can be the case if interfaceType is proxy to a non-existent
// object (which is a bad type annotation, but shouldn't crash).
currentPropertyNames = implicitProto.getOwnPropertyNames();
for (String name : currentPropertyNames) {
ObjectType oType = properties.get(name);
if (oType != null) {
if (!interfaceType.getPropertyType(name).isEquivalentTo(
oType.getPropertyType(name))) {
compiler.report(
t.makeError(n, INCOMPATIBLE_EXTENDED_PROPERTY_TYPE,
functionName, name, oType.toString(),
interfaceType.toString()));
}
}
currentProperties.put(name, interfaceType);
}
for (ObjectType iType : interfaceType.getCtorExtendedInterfaces()) {
checkInterfaceConflictProperties(t, n, functionName, properties,
currentProperties, iType);
}
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Check whether there's any property conflict for for a particular super
* interface
* @param t The node traversal object that supplies context
* @param n The node being visited
* @param functionName The function name being checked
* @param properties The property names in the super interfaces that have
* been visited
* @param currentProperties The property names in the super interface
* that have been visited
* @param interfaceType The super interface that is being visited
*/
private void checkInterfaceConflictProperties(NodeTraversal t, Node n,
String functionName, HashMap<String, ObjectType> properties,
HashMap<String, ObjectType> currentProperties,
ObjectType interfaceType) {
ObjectType implicitProto = interfaceType.getImplicitPrototype();
Set<String> currentPropertyNames;
// This can be the case if interfaceType is proxy to a non-existent
// object (which is a bad type annotation, but shouldn't crash).
currentPropertyNames = implicitProto.getOwnPropertyNames();
for (String name : currentPropertyNames) {
ObjectType oType = properties.get(name);
if (oType != null) {
if (!interfaceType.getPropertyType(name).isEquivalentTo(
oType.getPropertyType(name))) {
compiler.report(
t.makeError(n, INCOMPATIBLE_EXTENDED_PROPERTY_TYPE,
functionName, name, oType.toString(),
interfaceType.toString()));
}
}
currentProperties.put(name, interfaceType);
}
for (ObjectType iType : interfaceType.getCtorExtendedInterfaces()) {
checkInterfaceConflictProperties(t, n, functionName, properties,
currentProperties, iType);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
100 | 53287b475ce1abe3ebc623a33c3b3444974bd89f4082d583d81fbbdd036801f1 | @Override
public byte[] getBinaryValue(Base64Variant b64variant)
throws IOException, JsonParseException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/*
/**********************************************************
/* Public API, typed binary (base64) access
/**********************************************************
*/
@Override
public byte[] getBinaryValue(Base64Variant b64variant)
throws IOException, JsonParseException
{
// Multiple possibilities...
JsonNode n = currentNode();
if (n != null) {
// [databind#2096]: although `binaryValue()` works for real binary node
// and embedded "POJO" node, coercion from TextNode may require variant, so:
byte[] data = n.binaryValue();
if (data != null) {
return data;
}
if (n.isPojo()) {
Object ob = ((POJONode) n).getPojo();
if (ob instanceof byte[]) {
return (byte[]) ob;
}
}
}
// otherwise return null to mark we have no binary content
return null;
}
```
| @Override
public byte[] getBinaryValue(Base64Variant b64variant)
throws IOException, JsonParseException
{
// Multiple possibilities...
JsonNode n = currentNode();
if (n != null) {
// [databind#2096]: although `binaryValue()` works for real binary node
// and embedded "POJO" node, coercion from TextNode may require variant, so:
byte[] data = n.binaryValue();
if (data != null) {
return data;
}
if (n.isPojo()) {
Object ob = ((POJONode) n).getPojo();
if (ob instanceof byte[]) {
return (byte[]) ob;
}
}
}
// otherwise return null to mark we have no binary content
return null;
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/*
/**********************************************************
/* Public API, typed binary (base64) access
/**********************************************************
*/
@Override
public byte[] getBinaryValue(Base64Variant b64variant)
throws IOException, JsonParseException
{
// Multiple possibilities...
JsonNode n = currentNode();
if (n != null) {
// [databind#2096]: although `binaryValue()` works for real binary node
// and embedded "POJO" node, coercion from TextNode may require variant, so:
byte[] data = n.binaryValue();
if (data != null) {
return data;
}
if (n.isPojo()) {
Object ob = ((POJONode) n).getPojo();
if (ob instanceof byte[]) {
return (byte[]) ob;
}
}
}
// otherwise return null to mark we have no binary content
return null;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
48 | 532f621b243f0cce62fc8483290f863041732782e81bff0e925e942687b625dc | public EqualsBuilder append(Object lhs, Object rhs) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Test if two <code>Object</code>s are equal using their
* <code>equals</code> method.</p>
*
* @param lhs the left hand object
* @param rhs the right hand object
* @return EqualsBuilder - used to chain calls.
*/
//-------------------------------------------------------------------------
public EqualsBuilder append(Object lhs, Object rhs) {
if (isEquals == false) {
return this;
}
if (lhs == rhs) {
return this;
}
if (lhs == null || rhs == null) {
this.setEquals(false);
return this;
}
Class lhsClass = lhs.getClass();
if (!lhsClass.isArray()) {
// The simple case, not an array, just test the element
isEquals = lhs.equals(rhs);
} else if (lhs.getClass() != rhs.getClass()) {
// Here when we compare different dimensions, for example: a boolean[][] to a boolean[]
this.setEquals(false);
}
// 'Switch' on type of array, to dispatch to the correct handler
// This handles multi dimensional arrays of the same depth
else if (lhs instanceof long[]) {
append((long[]) lhs, (long[]) rhs);
} else if (lhs instanceof int[]) {
append((int[]) lhs, (int[]) rhs);
} else if (lhs instanceof short[]) {
append((short[]) lhs, (short[]) rhs);
} else if (lhs instanceof char[]) {
append((char[]) lhs, (char[]) rhs);
} else if (lhs instanceof byte[]) {
append((byte[]) lhs, (byte[]) rhs);
} else if (lhs instanceof double[]) {
append((double[]) lhs, (double[]) rhs);
} else if (lhs instanceof float[]) {
append((float[]) lhs, (float[]) rhs);
} else if (lhs instanceof boolean[]) {
append((boolean[]) lhs, (boolean[]) rhs);
} else {
// Not an array of primitives
append((Object[]) lhs, (Object[]) rhs);
}
return this;
}
```
| public EqualsBuilder append(Object lhs, Object rhs) {
if (isEquals == false) {
return this;
}
if (lhs == rhs) {
return this;
}
if (lhs == null || rhs == null) {
this.setEquals(false);
return this;
}
Class lhsClass = lhs.getClass();
if (!lhsClass.isArray()) {
// The simple case, not an array, just test the element
isEquals = lhs.equals(rhs);
} else if (lhs.getClass() != rhs.getClass()) {
// Here when we compare different dimensions, for example: a boolean[][] to a boolean[]
this.setEquals(false);
}
// 'Switch' on type of array, to dispatch to the correct handler
// This handles multi dimensional arrays of the same depth
else if (lhs instanceof long[]) {
append((long[]) lhs, (long[]) rhs);
} else if (lhs instanceof int[]) {
append((int[]) lhs, (int[]) rhs);
} else if (lhs instanceof short[]) {
append((short[]) lhs, (short[]) rhs);
} else if (lhs instanceof char[]) {
append((char[]) lhs, (char[]) rhs);
} else if (lhs instanceof byte[]) {
append((byte[]) lhs, (byte[]) rhs);
} else if (lhs instanceof double[]) {
append((double[]) lhs, (double[]) rhs);
} else if (lhs instanceof float[]) {
append((float[]) lhs, (float[]) rhs);
} else if (lhs instanceof boolean[]) {
append((boolean[]) lhs, (boolean[]) rhs);
} else {
// Not an array of primitives
append((Object[]) lhs, (Object[]) rhs);
}
return this;
} | true | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Test if two <code>Object</code>s are equal using their
* <code>equals</code> method.</p>
*
* @param lhs the left hand object
* @param rhs the right hand object
* @return EqualsBuilder - used to chain calls.
*/
//-------------------------------------------------------------------------
public EqualsBuilder append(Object lhs, Object rhs) {
if (isEquals == false) {
return this;
}
if (lhs == rhs) {
return this;
}
if (lhs == null || rhs == null) {
this.setEquals(false);
return this;
}
Class lhsClass = lhs.getClass();
if (!lhsClass.isArray()) {
// The simple case, not an array, just test the element
isEquals = lhs.equals(rhs);
} else if (lhs.getClass() != rhs.getClass()) {
// Here when we compare different dimensions, for example: a boolean[][] to a boolean[]
this.setEquals(false);
}
// 'Switch' on type of array, to dispatch to the correct handler
// This handles multi dimensional arrays of the same depth
else if (lhs instanceof long[]) {
append((long[]) lhs, (long[]) rhs);
} else if (lhs instanceof int[]) {
append((int[]) lhs, (int[]) rhs);
} else if (lhs instanceof short[]) {
append((short[]) lhs, (short[]) rhs);
} else if (lhs instanceof char[]) {
append((char[]) lhs, (char[]) rhs);
} else if (lhs instanceof byte[]) {
append((byte[]) lhs, (byte[]) rhs);
} else if (lhs instanceof double[]) {
append((double[]) lhs, (double[]) rhs);
} else if (lhs instanceof float[]) {
append((float[]) lhs, (float[]) rhs);
} else if (lhs instanceof boolean[]) {
append((boolean[]) lhs, (boolean[]) rhs);
} else {
// Not an array of primitives
append((Object[]) lhs, (Object[]) rhs);
}
return this;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
20 | 53a51820959f94f6548aa8f8d61946d84d0fe0496c36cd3a95711b93e0307b4e | private Node tryFoldSimpleFunctionCall(Node n) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private Node tryFoldSimpleFunctionCall(Node n) {
Preconditions.checkState(n.isCall());
Node callTarget = n.getFirstChild();
if (callTarget != null && callTarget.isName() &&
callTarget.getString().equals("String")) {
// Fold String(a) to '' + (a) on immutable literals,
// which allows further optimizations
//
// We can't do this in the general case, because String(a) has
// slightly different semantics than '' + (a). See
// http://code.google.com/p/closure-compiler/issues/detail?id=759
Node value = callTarget.getNext();
if (value != null && value.getNext() == null &&
NodeUtil.isImmutableValue(value)) {
Node addition = IR.add(
IR.string("").srcref(callTarget),
value.detachFromParent());
n.getParent().replaceChild(n, addition);
reportCodeChange();
return addition;
}
}
return n;
}
```
| private Node tryFoldSimpleFunctionCall(Node n) {
Preconditions.checkState(n.isCall());
Node callTarget = n.getFirstChild();
if (callTarget != null && callTarget.isName() &&
callTarget.getString().equals("String")) {
// Fold String(a) to '' + (a) on immutable literals,
// which allows further optimizations
//
// We can't do this in the general case, because String(a) has
// slightly different semantics than '' + (a). See
// http://code.google.com/p/closure-compiler/issues/detail?id=759
Node value = callTarget.getNext();
if (value != null && value.getNext() == null &&
NodeUtil.isImmutableValue(value)) {
Node addition = IR.add(
IR.string("").srcref(callTarget),
value.detachFromParent());
n.getParent().replaceChild(n, addition);
reportCodeChange();
return addition;
}
}
return n;
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private Node tryFoldSimpleFunctionCall(Node n) {
Preconditions.checkState(n.isCall());
Node callTarget = n.getFirstChild();
if (callTarget != null && callTarget.isName() &&
callTarget.getString().equals("String")) {
// Fold String(a) to '' + (a) on immutable literals,
// which allows further optimizations
//
// We can't do this in the general case, because String(a) has
// slightly different semantics than '' + (a). See
// http://code.google.com/p/closure-compiler/issues/detail?id=759
Node value = callTarget.getNext();
if (value != null && value.getNext() == null &&
NodeUtil.isImmutableValue(value)) {
Node addition = IR.add(
IR.string("").srcref(callTarget),
value.detachFromParent());
n.getParent().replaceChild(n, addition);
reportCodeChange();
return addition;
}
}
return n;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
15 | 53b491b9dec5cfef045c63e73c26dd1f5c295239eae2ba880215dd65e76cf8c2 | public JsonWriter value(double value) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Encodes {@code value}.
*
* @param value a finite value. May not be {@link Double#isNaN() NaNs} or
* {@link Double#isInfinite() infinities}.
* @return this writer.
*/
public JsonWriter value(double value) throws IOException {
writeDeferredName();
if (Double.isNaN(value) || Double.isInfinite(value)) {
throw new IllegalArgumentException("Numeric values must be finite, but was " + value);
}
beforeValue();
out.append(Double.toString(value));
return this;
}
```
| public JsonWriter value(double value) throws IOException {
writeDeferredName();
if (Double.isNaN(value) || Double.isInfinite(value)) {
throw new IllegalArgumentException("Numeric values must be finite, but was " + value);
}
beforeValue();
out.append(Double.toString(value));
return this;
} | true | Gson | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Encodes {@code value}.
*
* @param value a finite value. May not be {@link Double#isNaN() NaNs} or
* {@link Double#isInfinite() infinities}.
* @return this writer.
*/
public JsonWriter value(double value) throws IOException {
writeDeferredName();
if (Double.isNaN(value) || Double.isInfinite(value)) {
throw new IllegalArgumentException("Numeric values must be finite, but was " + value);
}
beforeValue();
out.append(Double.toString(value));
return this;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
101 | 53ccfdbab19593cacf8f65263e6a99f0286a3dcce06abb7d6d0f71d3ab22eda9 | @Override
protected CompilerOptions createOptions() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
protected CompilerOptions createOptions() {
CompilerOptions options = new CompilerOptions();
options.setCodingConvention(new ClosureCodingConvention());
CompilationLevel level = flags.compilation_level;
level.setOptionsForCompilationLevel(options);
if (flags.debug) {
level.setDebugOptionsForCompilationLevel(options);
}
WarningLevel wLevel = flags.warning_level;
wLevel.setOptionsForWarningLevel(options);
for (FormattingOption formattingOption : flags.formatting) {
formattingOption.applyToOptions(options);
}
options.closurePass = flags.process_closure_primitives;
initOptionsFromFlags(options);
return options;
}
```
| @Override
protected CompilerOptions createOptions() {
CompilerOptions options = new CompilerOptions();
options.setCodingConvention(new ClosureCodingConvention());
CompilationLevel level = flags.compilation_level;
level.setOptionsForCompilationLevel(options);
if (flags.debug) {
level.setDebugOptionsForCompilationLevel(options);
}
WarningLevel wLevel = flags.warning_level;
wLevel.setOptionsForWarningLevel(options);
for (FormattingOption formattingOption : flags.formatting) {
formattingOption.applyToOptions(options);
}
options.closurePass = flags.process_closure_primitives;
initOptionsFromFlags(options);
return options;
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
protected CompilerOptions createOptions() {
CompilerOptions options = new CompilerOptions();
options.setCodingConvention(new ClosureCodingConvention());
CompilationLevel level = flags.compilation_level;
level.setOptionsForCompilationLevel(options);
if (flags.debug) {
level.setDebugOptionsForCompilationLevel(options);
}
WarningLevel wLevel = flags.warning_level;
wLevel.setOptionsForWarningLevel(options);
for (FormattingOption formattingOption : flags.formatting) {
formattingOption.applyToOptions(options);
}
options.closurePass = flags.process_closure_primitives;
initOptionsFromFlags(options);
return options;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
10 | 5436c79807ff2a5531d11d47c1e227108a47b7ff3c504a1e9738e8e364df3c52 | public void atan2(final double[] y, final int yOffset,
final double[] x, final int xOffset,
final double[] result, final int resultOffset) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/** Compute two arguments arc tangent of a derivative structure.
* @param y array holding the first operand
* @param yOffset offset of the first operand in its array
* @param x array holding the second operand
* @param xOffset offset of the second operand in its array
* @param result array where result must be stored (for
* two arguments arc tangent the result array <em>cannot</em>
* be the input array)
* @param resultOffset offset of the result in its array
*/
public void atan2(final double[] y, final int yOffset,
final double[] x, final int xOffset,
final double[] result, final int resultOffset) {
// compute r = sqrt(x^2+y^2)
double[] tmp1 = new double[getSize()];
multiply(x, xOffset, x, xOffset, tmp1, 0); // x^2
double[] tmp2 = new double[getSize()];
multiply(y, yOffset, y, yOffset, tmp2, 0); // y^2
add(tmp1, 0, tmp2, 0, tmp2, 0); // x^2 + y^2
rootN(tmp2, 0, 2, tmp1, 0); // r = sqrt(x^2 + y^2)
if (x[xOffset] >= 0) {
// compute atan2(y, x) = 2 atan(y / (r + x))
add(tmp1, 0, x, xOffset, tmp2, 0); // r + x
divide(y, yOffset, tmp2, 0, tmp1, 0); // y /(r + x)
atan(tmp1, 0, tmp2, 0); // atan(y / (r + x))
for (int i = 0; i < tmp2.length; ++i) {
result[resultOffset + i] = 2 * tmp2[i]; // 2 * atan(y / (r + x))
}
} else {
// compute atan2(y, x) = +/- pi - 2 atan(y / (r - x))
subtract(tmp1, 0, x, xOffset, tmp2, 0); // r - x
divide(y, yOffset, tmp2, 0, tmp1, 0); // y /(r - x)
atan(tmp1, 0, tmp2, 0); // atan(y / (r - x))
result[resultOffset] =
((tmp2[0] <= 0) ? -FastMath.PI : FastMath.PI) - 2 * tmp2[0]; // +/-pi - 2 * atan(y / (r - x))
for (int i = 1; i < tmp2.length; ++i) {
result[resultOffset + i] = -2 * tmp2[i]; // +/-pi - 2 * atan(y / (r - x))
}
}
// fix value to take special cases (+0/+0, +0/-0, -0/+0, -0/-0, +/-infinity) correctly
result[resultOffset] = FastMath.atan2(y[yOffset], x[xOffset]);
}
```
| public void atan2(final double[] y, final int yOffset,
final double[] x, final int xOffset,
final double[] result, final int resultOffset) {
// compute r = sqrt(x^2+y^2)
double[] tmp1 = new double[getSize()];
multiply(x, xOffset, x, xOffset, tmp1, 0); // x^2
double[] tmp2 = new double[getSize()];
multiply(y, yOffset, y, yOffset, tmp2, 0); // y^2
add(tmp1, 0, tmp2, 0, tmp2, 0); // x^2 + y^2
rootN(tmp2, 0, 2, tmp1, 0); // r = sqrt(x^2 + y^2)
if (x[xOffset] >= 0) {
// compute atan2(y, x) = 2 atan(y / (r + x))
add(tmp1, 0, x, xOffset, tmp2, 0); // r + x
divide(y, yOffset, tmp2, 0, tmp1, 0); // y /(r + x)
atan(tmp1, 0, tmp2, 0); // atan(y / (r + x))
for (int i = 0; i < tmp2.length; ++i) {
result[resultOffset + i] = 2 * tmp2[i]; // 2 * atan(y / (r + x))
}
} else {
// compute atan2(y, x) = +/- pi - 2 atan(y / (r - x))
subtract(tmp1, 0, x, xOffset, tmp2, 0); // r - x
divide(y, yOffset, tmp2, 0, tmp1, 0); // y /(r - x)
atan(tmp1, 0, tmp2, 0); // atan(y / (r - x))
result[resultOffset] =
((tmp2[0] <= 0) ? -FastMath.PI : FastMath.PI) - 2 * tmp2[0]; // +/-pi - 2 * atan(y / (r - x))
for (int i = 1; i < tmp2.length; ++i) {
result[resultOffset + i] = -2 * tmp2[i]; // +/-pi - 2 * atan(y / (r - x))
}
}
// fix value to take special cases (+0/+0, +0/-0, -0/+0, -0/-0, +/-infinity) correctly
result[resultOffset] = FastMath.atan2(y[yOffset], x[xOffset]);
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/** Compute two arguments arc tangent of a derivative structure.
* @param y array holding the first operand
* @param yOffset offset of the first operand in its array
* @param x array holding the second operand
* @param xOffset offset of the second operand in its array
* @param result array where result must be stored (for
* two arguments arc tangent the result array <em>cannot</em>
* be the input array)
* @param resultOffset offset of the result in its array
*/
public void atan2(final double[] y, final int yOffset,
final double[] x, final int xOffset,
final double[] result, final int resultOffset) {
// compute r = sqrt(x^2+y^2)
double[] tmp1 = new double[getSize()];
multiply(x, xOffset, x, xOffset, tmp1, 0); // x^2
double[] tmp2 = new double[getSize()];
multiply(y, yOffset, y, yOffset, tmp2, 0); // y^2
add(tmp1, 0, tmp2, 0, tmp2, 0); // x^2 + y^2
rootN(tmp2, 0, 2, tmp1, 0); // r = sqrt(x^2 + y^2)
if (x[xOffset] >= 0) {
// compute atan2(y, x) = 2 atan(y / (r + x))
add(tmp1, 0, x, xOffset, tmp2, 0); // r + x
divide(y, yOffset, tmp2, 0, tmp1, 0); // y /(r + x)
atan(tmp1, 0, tmp2, 0); // atan(y / (r + x))
for (int i = 0; i < tmp2.length; ++i) {
result[resultOffset + i] = 2 * tmp2[i]; // 2 * atan(y / (r + x))
}
} else {
// compute atan2(y, x) = +/- pi - 2 atan(y / (r - x))
subtract(tmp1, 0, x, xOffset, tmp2, 0); // r - x
divide(y, yOffset, tmp2, 0, tmp1, 0); // y /(r - x)
atan(tmp1, 0, tmp2, 0); // atan(y / (r - x))
result[resultOffset] =
((tmp2[0] <= 0) ? -FastMath.PI : FastMath.PI) - 2 * tmp2[0]; // +/-pi - 2 * atan(y / (r - x))
for (int i = 1; i < tmp2.length; ++i) {
result[resultOffset + i] = -2 * tmp2[i]; // +/-pi - 2 * atan(y / (r - x))
}
}
// fix value to take special cases (+0/+0, +0/-0, -0/+0, -0/-0, +/-infinity) correctly
result[resultOffset] = FastMath.atan2(y[yOffset], x[xOffset]);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
87 | 544d051a743b828f2d9b529becbaa89eed908f1f02e2a7898577be397405fb57 | private Integer getBasicRow(final int col) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Checks whether the given column is basic.
* @param col index of the column to check
* @return the row that the variable is basic in. null if the column is not basic
*/
private Integer getBasicRow(final int col) {
Integer row = null;
for (int i = getNumObjectiveFunctions(); i < getHeight(); i++) {
if (MathUtils.equals(getEntry(i, col), 1.0, epsilon) && (row == null)) {
row = i;
} else if (!MathUtils.equals(getEntry(i, col), 0.0, epsilon)) {
return null;
}
}
return row;
}
```
| private Integer getBasicRow(final int col) {
Integer row = null;
for (int i = getNumObjectiveFunctions(); i < getHeight(); i++) {
if (MathUtils.equals(getEntry(i, col), 1.0, epsilon) && (row == null)) {
row = i;
} else if (!MathUtils.equals(getEntry(i, col), 0.0, epsilon)) {
return null;
}
}
return row;
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Checks whether the given column is basic.
* @param col index of the column to check
* @return the row that the variable is basic in. null if the column is not basic
*/
private Integer getBasicRow(final int col) {
Integer row = null;
for (int i = getNumObjectiveFunctions(); i < getHeight(); i++) {
if (MathUtils.equals(getEntry(i, col), 1.0, epsilon) && (row == null)) {
row = i;
} else if (!MathUtils.equals(getEntry(i, col), 0.0, epsilon)) {
return null;
}
}
return row;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
9 | 544fb103a2eee802a556e9000f13b6d21e1c7bb7c8fba3e2f7201d5ca7cc8f62 | private void init() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Initialize derived fields from defining fields.
* This is called from constructor and from readObject (de-serialization)
*/
private void init() {
thisYear= Calendar.getInstance(timeZone, locale).get(Calendar.YEAR);
nameValues= new ConcurrentHashMap<Integer, KeyValue[]>();
StringBuilder regex= new StringBuilder();
List<Strategy> collector = new ArrayList<Strategy>();
Matcher patternMatcher= formatPattern.matcher(pattern);
if(!patternMatcher.lookingAt()) {
throw new IllegalArgumentException("Invalid pattern");
}
currentFormatField= patternMatcher.group();
Strategy currentStrategy= getStrategy(currentFormatField);
for(;;) {
patternMatcher.region(patternMatcher.end(), patternMatcher.regionEnd());
if(!patternMatcher.lookingAt()) {
nextStrategy = null;
break;
}
String nextFormatField= patternMatcher.group();
nextStrategy = getStrategy(nextFormatField);
if(currentStrategy.addRegex(this, regex)) {
collector.add(currentStrategy);
}
currentFormatField= nextFormatField;
currentStrategy= nextStrategy;
}
if (patternMatcher.regionStart() != patternMatcher.regionEnd()) {
throw new IllegalArgumentException("Failed to parse \""+pattern+"\" ; gave up at index "+patternMatcher.regionStart());
}
if(currentStrategy.addRegex(this, regex)) {
collector.add(currentStrategy);
}
currentFormatField= null;
strategies= collector.toArray(new Strategy[collector.size()]);
parsePattern= Pattern.compile(regex.toString());
}
```
| private void init() {
thisYear= Calendar.getInstance(timeZone, locale).get(Calendar.YEAR);
nameValues= new ConcurrentHashMap<Integer, KeyValue[]>();
StringBuilder regex= new StringBuilder();
List<Strategy> collector = new ArrayList<Strategy>();
Matcher patternMatcher= formatPattern.matcher(pattern);
if(!patternMatcher.lookingAt()) {
throw new IllegalArgumentException("Invalid pattern");
}
currentFormatField= patternMatcher.group();
Strategy currentStrategy= getStrategy(currentFormatField);
for(;;) {
patternMatcher.region(patternMatcher.end(), patternMatcher.regionEnd());
if(!patternMatcher.lookingAt()) {
nextStrategy = null;
break;
}
String nextFormatField= patternMatcher.group();
nextStrategy = getStrategy(nextFormatField);
if(currentStrategy.addRegex(this, regex)) {
collector.add(currentStrategy);
}
currentFormatField= nextFormatField;
currentStrategy= nextStrategy;
}
if (patternMatcher.regionStart() != patternMatcher.regionEnd()) {
throw new IllegalArgumentException("Failed to parse \""+pattern+"\" ; gave up at index "+patternMatcher.regionStart());
}
if(currentStrategy.addRegex(this, regex)) {
collector.add(currentStrategy);
}
currentFormatField= null;
strategies= collector.toArray(new Strategy[collector.size()]);
parsePattern= Pattern.compile(regex.toString());
} | false | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Initialize derived fields from defining fields.
* This is called from constructor and from readObject (de-serialization)
*/
private void init() {
thisYear= Calendar.getInstance(timeZone, locale).get(Calendar.YEAR);
nameValues= new ConcurrentHashMap<Integer, KeyValue[]>();
StringBuilder regex= new StringBuilder();
List<Strategy> collector = new ArrayList<Strategy>();
Matcher patternMatcher= formatPattern.matcher(pattern);
if(!patternMatcher.lookingAt()) {
throw new IllegalArgumentException("Invalid pattern");
}
currentFormatField= patternMatcher.group();
Strategy currentStrategy= getStrategy(currentFormatField);
for(;;) {
patternMatcher.region(patternMatcher.end(), patternMatcher.regionEnd());
if(!patternMatcher.lookingAt()) {
nextStrategy = null;
break;
}
String nextFormatField= patternMatcher.group();
nextStrategy = getStrategy(nextFormatField);
if(currentStrategy.addRegex(this, regex)) {
collector.add(currentStrategy);
}
currentFormatField= nextFormatField;
currentStrategy= nextStrategy;
}
if (patternMatcher.regionStart() != patternMatcher.regionEnd()) {
throw new IllegalArgumentException("Failed to parse \""+pattern+"\" ; gave up at index "+patternMatcher.regionStart());
}
if(currentStrategy.addRegex(this, regex)) {
collector.add(currentStrategy);
}
currentFormatField= null;
strategies= collector.toArray(new Strategy[collector.size()]);
parsePattern= Pattern.compile(regex.toString());
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
40 | 5485528aefc8eb8ffd2343e7a565e2389b89f890fc6fa7f87324b53e684f7cdc | public DocumentType(String name, String publicId, String systemId, String baseUri) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Create a new doctype element.
* @param name the doctype's name
* @param publicId the doctype's public ID
* @param systemId the doctype's system ID
* @param baseUri the doctype's base URI
*/
// todo: quirk mode from publicId and systemId
public DocumentType(String name, String publicId, String systemId, String baseUri) {
super(baseUri);
Validate.notEmpty(name);
attr("name", name);
attr("publicId", publicId);
attr("systemId", systemId);
}
```
| public DocumentType(String name, String publicId, String systemId, String baseUri) {
super(baseUri);
Validate.notEmpty(name);
attr("name", name);
attr("publicId", publicId);
attr("systemId", systemId);
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Create a new doctype element.
* @param name the doctype's name
* @param publicId the doctype's public ID
* @param systemId the doctype's system ID
* @param baseUri the doctype's base URI
*/
// todo: quirk mode from publicId and systemId
public DocumentType(String name, String publicId, String systemId, String baseUri) {
super(baseUri);
Validate.notEmpty(name);
attr("name", name);
attr("publicId", publicId);
attr("systemId", systemId);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
15 | 54efb0a2e3fbe21d18f15d8bef9e494ad2c53defd4669db3f1977e24b599d59e | public List getValues(final Option option,
List defaultValues) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public List getValues(final Option option,
List defaultValues) {
// initialize the return list
List valueList = (List) values.get(option);
// grab the correct default values
if (defaultValues == null || defaultValues.isEmpty()) {
defaultValues = (List) this.defaultValues.get(option);
}
// augment the list with the default values
if (defaultValues != null && !defaultValues.isEmpty()) {
if (valueList == null || valueList.isEmpty()) {
valueList = defaultValues;
} else {
// if there are more default values as specified, add them to
// the list.
if (defaultValues.size() > valueList.size()) {
// copy the list first
valueList = new ArrayList(valueList);
for (int i=valueList.size(); i<defaultValues.size(); i++) {
valueList.add(defaultValues.get(i));
}
}
}
}
return valueList == null ? Collections.EMPTY_LIST : valueList;
}
```
| public List getValues(final Option option,
List defaultValues) {
// initialize the return list
List valueList = (List) values.get(option);
// grab the correct default values
if (defaultValues == null || defaultValues.isEmpty()) {
defaultValues = (List) this.defaultValues.get(option);
}
// augment the list with the default values
if (defaultValues != null && !defaultValues.isEmpty()) {
if (valueList == null || valueList.isEmpty()) {
valueList = defaultValues;
} else {
// if there are more default values as specified, add them to
// the list.
if (defaultValues.size() > valueList.size()) {
// copy the list first
valueList = new ArrayList(valueList);
for (int i=valueList.size(); i<defaultValues.size(); i++) {
valueList.add(defaultValues.get(i));
}
}
}
}
return valueList == null ? Collections.EMPTY_LIST : valueList;
} | false | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public List getValues(final Option option,
List defaultValues) {
// initialize the return list
List valueList = (List) values.get(option);
// grab the correct default values
if (defaultValues == null || defaultValues.isEmpty()) {
defaultValues = (List) this.defaultValues.get(option);
}
// augment the list with the default values
if (defaultValues != null && !defaultValues.isEmpty()) {
if (valueList == null || valueList.isEmpty()) {
valueList = defaultValues;
} else {
// if there are more default values as specified, add them to
// the list.
if (defaultValues.size() > valueList.size()) {
// copy the list first
valueList = new ArrayList(valueList);
for (int i=valueList.size(); i<defaultValues.size(); i++) {
valueList.add(defaultValues.get(i));
}
}
}
}
return valueList == null ? Collections.EMPTY_LIST : valueList;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
78 | 552b0f172cdd3c84d6d5de1a98aba717f6c7b8f0ef6ecac386d0a1831acf7b00 | private Node performArithmeticOp(int opType, Node left, Node right) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Try to fold arithmetic binary operators
*/
private Node performArithmeticOp(int opType, Node left, Node right) {
// Unlike other operations, ADD operands are not always converted
// to Number.
if (opType == Token.ADD
&& (NodeUtil.mayBeString(left, false)
|| NodeUtil.mayBeString(right, false))) {
return null;
}
double result;
// TODO(johnlenz): Handle NaN with unknown value. BIT ops convert NaN
// to zero so this is a little akward here.
Double lValObj = NodeUtil.getNumberValue(left);
if (lValObj == null) {
return null;
}
Double rValObj = NodeUtil.getNumberValue(right);
if (rValObj == null) {
return null;
}
double lval = lValObj;
double rval = rValObj;
switch (opType) {
case Token.BITAND:
result = ScriptRuntime.toInt32(lval) & ScriptRuntime.toInt32(rval);
break;
case Token.BITOR:
result = ScriptRuntime.toInt32(lval) | ScriptRuntime.toInt32(rval);
break;
case Token.BITXOR:
result = ScriptRuntime.toInt32(lval) ^ ScriptRuntime.toInt32(rval);
break;
case Token.ADD:
result = lval + rval;
break;
case Token.SUB:
result = lval - rval;
break;
case Token.MUL:
result = lval * rval;
break;
case Token.MOD:
if (rval == 0) {
error(DiagnosticType.error("JSC_DIVIDE_BY_0_ERROR", "Divide by 0"), right);
return null;
}
result = lval % rval;
break;
case Token.DIV:
if (rval == 0) {
error(DiagnosticType.error("JSC_DIVIDE_BY_0_ERROR", "Divide by 0"), right);
return null;
}
result = lval / rval;
break;
default:
throw new Error("Unexpected arithmetic operator");
}
// TODO(johnlenz): consider removing the result length check.
// length of the left and right value plus 1 byte for the operator.
if (String.valueOf(result).length() <=
String.valueOf(lval).length() + String.valueOf(rval).length() + 1 &&
// Do not try to fold arithmetic for numbers > 2^53. After that
// point, fixed-point math starts to break down and become inaccurate.
Math.abs(result) <= MAX_FOLD_NUMBER) {
Node newNumber = Node.newNumber(result);
return newNumber;
} else if (Double.isNaN(result)) {
return Node.newString(Token.NAME, "NaN");
} else if (result == Double.POSITIVE_INFINITY) {
return Node.newString(Token.NAME, "Infinity");
} else if (result == Double.NEGATIVE_INFINITY) {
return new Node(Token.NEG, Node.newString(Token.NAME, "Infinity"));
}
return null;
}
```
| private Node performArithmeticOp(int opType, Node left, Node right) {
// Unlike other operations, ADD operands are not always converted
// to Number.
if (opType == Token.ADD
&& (NodeUtil.mayBeString(left, false)
|| NodeUtil.mayBeString(right, false))) {
return null;
}
double result;
// TODO(johnlenz): Handle NaN with unknown value. BIT ops convert NaN
// to zero so this is a little akward here.
Double lValObj = NodeUtil.getNumberValue(left);
if (lValObj == null) {
return null;
}
Double rValObj = NodeUtil.getNumberValue(right);
if (rValObj == null) {
return null;
}
double lval = lValObj;
double rval = rValObj;
switch (opType) {
case Token.BITAND:
result = ScriptRuntime.toInt32(lval) & ScriptRuntime.toInt32(rval);
break;
case Token.BITOR:
result = ScriptRuntime.toInt32(lval) | ScriptRuntime.toInt32(rval);
break;
case Token.BITXOR:
result = ScriptRuntime.toInt32(lval) ^ ScriptRuntime.toInt32(rval);
break;
case Token.ADD:
result = lval + rval;
break;
case Token.SUB:
result = lval - rval;
break;
case Token.MUL:
result = lval * rval;
break;
case Token.MOD:
if (rval == 0) {
error(DiagnosticType.error("JSC_DIVIDE_BY_0_ERROR", "Divide by 0"), right);
return null;
}
result = lval % rval;
break;
case Token.DIV:
if (rval == 0) {
error(DiagnosticType.error("JSC_DIVIDE_BY_0_ERROR", "Divide by 0"), right);
return null;
}
result = lval / rval;
break;
default:
throw new Error("Unexpected arithmetic operator");
}
// TODO(johnlenz): consider removing the result length check.
// length of the left and right value plus 1 byte for the operator.
if (String.valueOf(result).length() <=
String.valueOf(lval).length() + String.valueOf(rval).length() + 1 &&
// Do not try to fold arithmetic for numbers > 2^53. After that
// point, fixed-point math starts to break down and become inaccurate.
Math.abs(result) <= MAX_FOLD_NUMBER) {
Node newNumber = Node.newNumber(result);
return newNumber;
} else if (Double.isNaN(result)) {
return Node.newString(Token.NAME, "NaN");
} else if (result == Double.POSITIVE_INFINITY) {
return Node.newString(Token.NAME, "Infinity");
} else if (result == Double.NEGATIVE_INFINITY) {
return new Node(Token.NEG, Node.newString(Token.NAME, "Infinity"));
}
return null;
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Try to fold arithmetic binary operators
*/
private Node performArithmeticOp(int opType, Node left, Node right) {
// Unlike other operations, ADD operands are not always converted
// to Number.
if (opType == Token.ADD
&& (NodeUtil.mayBeString(left, false)
|| NodeUtil.mayBeString(right, false))) {
return null;
}
double result;
// TODO(johnlenz): Handle NaN with unknown value. BIT ops convert NaN
// to zero so this is a little akward here.
Double lValObj = NodeUtil.getNumberValue(left);
if (lValObj == null) {
return null;
}
Double rValObj = NodeUtil.getNumberValue(right);
if (rValObj == null) {
return null;
}
double lval = lValObj;
double rval = rValObj;
switch (opType) {
case Token.BITAND:
result = ScriptRuntime.toInt32(lval) & ScriptRuntime.toInt32(rval);
break;
case Token.BITOR:
result = ScriptRuntime.toInt32(lval) | ScriptRuntime.toInt32(rval);
break;
case Token.BITXOR:
result = ScriptRuntime.toInt32(lval) ^ ScriptRuntime.toInt32(rval);
break;
case Token.ADD:
result = lval + rval;
break;
case Token.SUB:
result = lval - rval;
break;
case Token.MUL:
result = lval * rval;
break;
case Token.MOD:
if (rval == 0) {
error(DiagnosticType.error("JSC_DIVIDE_BY_0_ERROR", "Divide by 0"), right);
return null;
}
result = lval % rval;
break;
case Token.DIV:
if (rval == 0) {
error(DiagnosticType.error("JSC_DIVIDE_BY_0_ERROR", "Divide by 0"), right);
return null;
}
result = lval / rval;
break;
default:
throw new Error("Unexpected arithmetic operator");
}
// TODO(johnlenz): consider removing the result length check.
// length of the left and right value plus 1 byte for the operator.
if (String.valueOf(result).length() <=
String.valueOf(lval).length() + String.valueOf(rval).length() + 1 &&
// Do not try to fold arithmetic for numbers > 2^53. After that
// point, fixed-point math starts to break down and become inaccurate.
Math.abs(result) <= MAX_FOLD_NUMBER) {
Node newNumber = Node.newNumber(result);
return newNumber;
} else if (Double.isNaN(result)) {
return Node.newString(Token.NAME, "NaN");
} else if (result == Double.POSITIVE_INFINITY) {
return Node.newString(Token.NAME, "Infinity");
} else if (result == Double.NEGATIVE_INFINITY) {
return new Node(Token.NEG, Node.newString(Token.NAME, "Infinity"));
}
return null;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
11 | 55574722fe8ea96342e3f18aa4bd95b72fb7f8a779827881c15595bbd35fece9 | @Override
public Number read(JsonReader in) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public Number read(JsonReader in) throws IOException {
JsonToken jsonToken = in.peek();
switch (jsonToken) {
case NULL:
in.nextNull();
return null;
case NUMBER:
return new LazilyParsedNumber(in.nextString());
default:
throw new JsonSyntaxException("Expecting number, got: " + jsonToken);
}
}
```
| @Override
public Number read(JsonReader in) throws IOException {
JsonToken jsonToken = in.peek();
switch (jsonToken) {
case NULL:
in.nextNull();
return null;
case NUMBER:
return new LazilyParsedNumber(in.nextString());
default:
throw new JsonSyntaxException("Expecting number, got: " + jsonToken);
}
} | true | Gson | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public Number read(JsonReader in) throws IOException {
JsonToken jsonToken = in.peek();
switch (jsonToken) {
case NULL:
in.nextNull();
return null;
case NUMBER:
return new LazilyParsedNumber(in.nextString());
default:
throw new JsonSyntaxException("Expecting number, got: " + jsonToken);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
40 | 555e40e9b26bed999658586184f57e6d4f3f2a1e93d76815059a9c50e8ef80b7 | @Override
public void visit(NodeTraversal t, Node n, Node parent) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public void visit(NodeTraversal t, Node n, Node parent) {
// Record global variable and function declarations
if (t.inGlobalScope()) {
if (NodeUtil.isVarDeclaration(n)) {
NameInformation ns = createNameInformation(t, n, parent);
Preconditions.checkNotNull(ns);
recordSet(ns.name, n);
} else if (NodeUtil.isFunctionDeclaration(n)) {
Node nameNode = n.getFirstChild();
NameInformation ns = createNameInformation(t, nameNode, n);
if (ns != null) {
JsName nameInfo = getName(nameNode.getString(), true);
recordSet(nameInfo.name, nameNode);
}
} else if (NodeUtil.isObjectLitKey(n, parent)) {
NameInformation ns = createNameInformation(t, n, parent);
if (ns != null) {
recordSet(ns.name, n);
}
}
}
// Record assignments and call sites
if (n.isAssign()) {
Node nameNode = n.getFirstChild();
NameInformation ns = createNameInformation(t, nameNode, n);
if (ns != null) {
if (ns.isPrototype) {
recordPrototypeSet(ns.prototypeClass, ns.prototypeProperty, n);
} else {
recordSet(ns.name, nameNode);
}
}
} else if (n.isCall()) {
Node nameNode = n.getFirstChild();
NameInformation ns = createNameInformation(t, nameNode, n);
if (ns != null && ns.onlyAffectsClassDef) {
JsName name = getName(ns.name, true);
refNodes.add(new ClassDefiningFunctionNode(
name, n, parent, parent.getParent()));
}
}
}
```
| @Override
public void visit(NodeTraversal t, Node n, Node parent) {
// Record global variable and function declarations
if (t.inGlobalScope()) {
if (NodeUtil.isVarDeclaration(n)) {
NameInformation ns = createNameInformation(t, n, parent);
Preconditions.checkNotNull(ns);
recordSet(ns.name, n);
} else if (NodeUtil.isFunctionDeclaration(n)) {
Node nameNode = n.getFirstChild();
NameInformation ns = createNameInformation(t, nameNode, n);
if (ns != null) {
JsName nameInfo = getName(nameNode.getString(), true);
recordSet(nameInfo.name, nameNode);
}
} else if (NodeUtil.isObjectLitKey(n, parent)) {
NameInformation ns = createNameInformation(t, n, parent);
if (ns != null) {
recordSet(ns.name, n);
}
}
}
// Record assignments and call sites
if (n.isAssign()) {
Node nameNode = n.getFirstChild();
NameInformation ns = createNameInformation(t, nameNode, n);
if (ns != null) {
if (ns.isPrototype) {
recordPrototypeSet(ns.prototypeClass, ns.prototypeProperty, n);
} else {
recordSet(ns.name, nameNode);
}
}
} else if (n.isCall()) {
Node nameNode = n.getFirstChild();
NameInformation ns = createNameInformation(t, nameNode, n);
if (ns != null && ns.onlyAffectsClassDef) {
JsName name = getName(ns.name, true);
refNodes.add(new ClassDefiningFunctionNode(
name, n, parent, parent.getParent()));
}
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public void visit(NodeTraversal t, Node n, Node parent) {
// Record global variable and function declarations
if (t.inGlobalScope()) {
if (NodeUtil.isVarDeclaration(n)) {
NameInformation ns = createNameInformation(t, n, parent);
Preconditions.checkNotNull(ns);
recordSet(ns.name, n);
} else if (NodeUtil.isFunctionDeclaration(n)) {
Node nameNode = n.getFirstChild();
NameInformation ns = createNameInformation(t, nameNode, n);
if (ns != null) {
JsName nameInfo = getName(nameNode.getString(), true);
recordSet(nameInfo.name, nameNode);
}
} else if (NodeUtil.isObjectLitKey(n, parent)) {
NameInformation ns = createNameInformation(t, n, parent);
if (ns != null) {
recordSet(ns.name, n);
}
}
}
// Record assignments and call sites
if (n.isAssign()) {
Node nameNode = n.getFirstChild();
NameInformation ns = createNameInformation(t, nameNode, n);
if (ns != null) {
if (ns.isPrototype) {
recordPrototypeSet(ns.prototypeClass, ns.prototypeProperty, n);
} else {
recordSet(ns.name, nameNode);
}
}
} else if (n.isCall()) {
Node nameNode = n.getFirstChild();
NameInformation ns = createNameInformation(t, nameNode, n);
if (ns != null && ns.onlyAffectsClassDef) {
JsName name = getName(ns.name, true);
refNodes.add(new ClassDefiningFunctionNode(
name, n, parent, parent.getParent()));
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
102 | 55f7790b1b7e19068e7928781d3e01f148d6818819c54f7aa85f6586b297bdfe | @Override
public JsonSerializer<?> createContextual(SerializerProvider serializers,
BeanProperty property) throws JsonMappingException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public JsonSerializer<?> createContextual(SerializerProvider serializers,
BeanProperty property) throws JsonMappingException
{
// Note! Should not skip if `property` null since that'd skip check
// for config overrides, in case of root value
JsonFormat.Value format = findFormatOverrides(serializers, property, handledType());
if (format == null) {
return this;
}
// Simple case first: serialize as numeric timestamp?
JsonFormat.Shape shape = format.getShape();
if (shape.isNumeric()) {
return withFormat(Boolean.TRUE, null);
}
// 08-Jun-2017, tatu: With [databind#1648], this gets bit tricky..
// First: custom pattern will override things
if (format.hasPattern()) {
final Locale loc = format.hasLocale()
? format.getLocale()
: serializers.getLocale();
SimpleDateFormat df = new SimpleDateFormat(format.getPattern(), loc);
TimeZone tz = format.hasTimeZone() ? format.getTimeZone()
: serializers.getTimeZone();
df.setTimeZone(tz);
return withFormat(Boolean.FALSE, df);
}
// Otherwise, need one of these changes:
final boolean hasLocale = format.hasLocale();
final boolean hasTZ = format.hasTimeZone();
final boolean asString = (shape == JsonFormat.Shape.STRING);
if (!hasLocale && !hasTZ && !asString) {
return this;
}
DateFormat df0 = serializers.getConfig().getDateFormat();
// Jackson's own `StdDateFormat` is quite easy to deal with...
if (df0 instanceof StdDateFormat) {
StdDateFormat std = (StdDateFormat) df0;
if (format.hasLocale()) {
std = std.withLocale(format.getLocale());
}
if (format.hasTimeZone()) {
std = std.withTimeZone(format.getTimeZone());
}
return withFormat(Boolean.FALSE, std);
}
// 08-Jun-2017, tatu: Unfortunately there's no generally usable
// mechanism for changing `DateFormat` instances (or even clone()ing)
// So: require it be `SimpleDateFormat`; can't config other types
if (!(df0 instanceof SimpleDateFormat)) {
serializers.reportBadDefinition(handledType(), String.format(
"Configured `DateFormat` (%s) not a `SimpleDateFormat`; cannot configure `Locale` or `TimeZone`",
df0.getClass().getName()));
}
SimpleDateFormat df = (SimpleDateFormat) df0;
if (hasLocale) {
// Ugh. No way to change `Locale`, create copy; must re-crete completely:
df = new SimpleDateFormat(df.toPattern(), format.getLocale());
} else {
df = (SimpleDateFormat) df.clone();
}
TimeZone newTz = format.getTimeZone();
boolean changeTZ = (newTz != null) && !newTz.equals(df.getTimeZone());
if (changeTZ) {
df.setTimeZone(newTz);
}
return withFormat(Boolean.FALSE, df);
}
```
| @Override
public JsonSerializer<?> createContextual(SerializerProvider serializers,
BeanProperty property) throws JsonMappingException
{
// Note! Should not skip if `property` null since that'd skip check
// for config overrides, in case of root value
JsonFormat.Value format = findFormatOverrides(serializers, property, handledType());
if (format == null) {
return this;
}
// Simple case first: serialize as numeric timestamp?
JsonFormat.Shape shape = format.getShape();
if (shape.isNumeric()) {
return withFormat(Boolean.TRUE, null);
}
// 08-Jun-2017, tatu: With [databind#1648], this gets bit tricky..
// First: custom pattern will override things
if (format.hasPattern()) {
final Locale loc = format.hasLocale()
? format.getLocale()
: serializers.getLocale();
SimpleDateFormat df = new SimpleDateFormat(format.getPattern(), loc);
TimeZone tz = format.hasTimeZone() ? format.getTimeZone()
: serializers.getTimeZone();
df.setTimeZone(tz);
return withFormat(Boolean.FALSE, df);
}
// Otherwise, need one of these changes:
final boolean hasLocale = format.hasLocale();
final boolean hasTZ = format.hasTimeZone();
final boolean asString = (shape == JsonFormat.Shape.STRING);
if (!hasLocale && !hasTZ && !asString) {
return this;
}
DateFormat df0 = serializers.getConfig().getDateFormat();
// Jackson's own `StdDateFormat` is quite easy to deal with...
if (df0 instanceof StdDateFormat) {
StdDateFormat std = (StdDateFormat) df0;
if (format.hasLocale()) {
std = std.withLocale(format.getLocale());
}
if (format.hasTimeZone()) {
std = std.withTimeZone(format.getTimeZone());
}
return withFormat(Boolean.FALSE, std);
}
// 08-Jun-2017, tatu: Unfortunately there's no generally usable
// mechanism for changing `DateFormat` instances (or even clone()ing)
// So: require it be `SimpleDateFormat`; can't config other types
if (!(df0 instanceof SimpleDateFormat)) {
serializers.reportBadDefinition(handledType(), String.format(
"Configured `DateFormat` (%s) not a `SimpleDateFormat`; cannot configure `Locale` or `TimeZone`",
df0.getClass().getName()));
}
SimpleDateFormat df = (SimpleDateFormat) df0;
if (hasLocale) {
// Ugh. No way to change `Locale`, create copy; must re-crete completely:
df = new SimpleDateFormat(df.toPattern(), format.getLocale());
} else {
df = (SimpleDateFormat) df.clone();
}
TimeZone newTz = format.getTimeZone();
boolean changeTZ = (newTz != null) && !newTz.equals(df.getTimeZone());
if (changeTZ) {
df.setTimeZone(newTz);
}
return withFormat(Boolean.FALSE, df);
} | false | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public JsonSerializer<?> createContextual(SerializerProvider serializers,
BeanProperty property) throws JsonMappingException
{
// Note! Should not skip if `property` null since that'd skip check
// for config overrides, in case of root value
JsonFormat.Value format = findFormatOverrides(serializers, property, handledType());
if (format == null) {
return this;
}
// Simple case first: serialize as numeric timestamp?
JsonFormat.Shape shape = format.getShape();
if (shape.isNumeric()) {
return withFormat(Boolean.TRUE, null);
}
// 08-Jun-2017, tatu: With [databind#1648], this gets bit tricky..
// First: custom pattern will override things
if (format.hasPattern()) {
final Locale loc = format.hasLocale()
? format.getLocale()
: serializers.getLocale();
SimpleDateFormat df = new SimpleDateFormat(format.getPattern(), loc);
TimeZone tz = format.hasTimeZone() ? format.getTimeZone()
: serializers.getTimeZone();
df.setTimeZone(tz);
return withFormat(Boolean.FALSE, df);
}
// Otherwise, need one of these changes:
final boolean hasLocale = format.hasLocale();
final boolean hasTZ = format.hasTimeZone();
final boolean asString = (shape == JsonFormat.Shape.STRING);
if (!hasLocale && !hasTZ && !asString) {
return this;
}
DateFormat df0 = serializers.getConfig().getDateFormat();
// Jackson's own `StdDateFormat` is quite easy to deal with...
if (df0 instanceof StdDateFormat) {
StdDateFormat std = (StdDateFormat) df0;
if (format.hasLocale()) {
std = std.withLocale(format.getLocale());
}
if (format.hasTimeZone()) {
std = std.withTimeZone(format.getTimeZone());
}
return withFormat(Boolean.FALSE, std);
}
// 08-Jun-2017, tatu: Unfortunately there's no generally usable
// mechanism for changing `DateFormat` instances (or even clone()ing)
// So: require it be `SimpleDateFormat`; can't config other types
if (!(df0 instanceof SimpleDateFormat)) {
serializers.reportBadDefinition(handledType(), String.format(
"Configured `DateFormat` (%s) not a `SimpleDateFormat`; cannot configure `Locale` or `TimeZone`",
df0.getClass().getName()));
}
SimpleDateFormat df = (SimpleDateFormat) df0;
if (hasLocale) {
// Ugh. No way to change `Locale`, create copy; must re-crete completely:
df = new SimpleDateFormat(df.toPattern(), format.getLocale());
} else {
df = (SimpleDateFormat) df.clone();
}
TimeZone newTz = format.getTimeZone();
boolean changeTZ = (newTz != null) && !newTz.equals(df.getTimeZone());
if (changeTZ) {
df.setTimeZone(newTz);
}
return withFormat(Boolean.FALSE, df);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
25 | 560f0eb193d7a404946d0d198f1aae4ed386958179bef6ea9415a5e952749e7d | private String _handleOddName2(int startPtr, int hash, int[] codes) throws IOException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private String _handleOddName2(int startPtr, int hash, int[] codes) throws IOException
{
_textBuffer.resetWithShared(_inputBuffer, startPtr, (_inputPtr - startPtr));
char[] outBuf = _textBuffer.getCurrentSegment();
int outPtr = _textBuffer.getCurrentSegmentSize();
final int maxCode = codes.length;
while (true) {
if (_inputPtr >= _inputEnd) {
if (!_loadMore()) { // acceptable for now (will error out later)
break;
}
}
char c = _inputBuffer[_inputPtr];
int i = (int) c;
if (i <= maxCode) {
if (codes[i] != 0) {
break;
}
} else if (!Character.isJavaIdentifierPart(c)) {
break;
}
++_inputPtr;
hash = (hash * CharsToNameCanonicalizer.HASH_MULT) + i;
// Ok, let's add char to output:
outBuf[outPtr++] = c;
// Need more room?
if (outPtr >= outBuf.length) {
outBuf = _textBuffer.finishCurrentSegment();
outPtr = 0;
}
}
_textBuffer.setCurrentLength(outPtr);
{
TextBuffer tb = _textBuffer;
char[] buf = tb.getTextBuffer();
int start = tb.getTextOffset();
int len = tb.size();
return _symbols.findSymbol(buf, start, len, hash);
}
}
```
| private String _handleOddName2(int startPtr, int hash, int[] codes) throws IOException
{
_textBuffer.resetWithShared(_inputBuffer, startPtr, (_inputPtr - startPtr));
char[] outBuf = _textBuffer.getCurrentSegment();
int outPtr = _textBuffer.getCurrentSegmentSize();
final int maxCode = codes.length;
while (true) {
if (_inputPtr >= _inputEnd) {
if (!_loadMore()) { // acceptable for now (will error out later)
break;
}
}
char c = _inputBuffer[_inputPtr];
int i = (int) c;
if (i <= maxCode) {
if (codes[i] != 0) {
break;
}
} else if (!Character.isJavaIdentifierPart(c)) {
break;
}
++_inputPtr;
hash = (hash * CharsToNameCanonicalizer.HASH_MULT) + i;
// Ok, let's add char to output:
outBuf[outPtr++] = c;
// Need more room?
if (outPtr >= outBuf.length) {
outBuf = _textBuffer.finishCurrentSegment();
outPtr = 0;
}
}
_textBuffer.setCurrentLength(outPtr);
{
TextBuffer tb = _textBuffer;
char[] buf = tb.getTextBuffer();
int start = tb.getTextOffset();
int len = tb.size();
return _symbols.findSymbol(buf, start, len, hash);
}
} | true | JacksonCore | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private String _handleOddName2(int startPtr, int hash, int[] codes) throws IOException
{
_textBuffer.resetWithShared(_inputBuffer, startPtr, (_inputPtr - startPtr));
char[] outBuf = _textBuffer.getCurrentSegment();
int outPtr = _textBuffer.getCurrentSegmentSize();
final int maxCode = codes.length;
while (true) {
if (_inputPtr >= _inputEnd) {
if (!_loadMore()) { // acceptable for now (will error out later)
break;
}
}
char c = _inputBuffer[_inputPtr];
int i = (int) c;
if (i <= maxCode) {
if (codes[i] != 0) {
break;
}
} else if (!Character.isJavaIdentifierPart(c)) {
break;
}
++_inputPtr;
hash = (hash * CharsToNameCanonicalizer.HASH_MULT) + i;
// Ok, let's add char to output:
outBuf[outPtr++] = c;
// Need more room?
if (outPtr >= outBuf.length) {
outBuf = _textBuffer.finishCurrentSegment();
outPtr = 0;
}
}
_textBuffer.setCurrentLength(outPtr);
{
TextBuffer tb = _textBuffer;
char[] buf = tb.getTextBuffer();
int start = tb.getTextOffset();
int len = tb.size();
return _symbols.findSymbol(buf, start, len, hash);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
49 | 561763ac4839034f2aa73b571ed68ce340d46ef63e8c8dc04e734e9fd7d2465c | public Fraction reduce() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Reduce the fraction to the smallest values for the numerator and
* denominator, returning the result.</p>
*
* <p>For example, if this fraction represents 2/4, then the result
* will be 1/2.</p>
*
* @return a new reduced fraction instance, or this if no simplification possible
*/
//-------------------------------------------------------------------
// Calculations
public Fraction reduce() {
if (numerator == 0) {
return equals(ZERO) ? this : ZERO;
}
int gcd = greatestCommonDivisor(Math.abs(numerator), denominator);
if (gcd == 1) {
return this;
}
return Fraction.getFraction(numerator / gcd, denominator / gcd);
}
```
| public Fraction reduce() {
if (numerator == 0) {
return equals(ZERO) ? this : ZERO;
}
int gcd = greatestCommonDivisor(Math.abs(numerator), denominator);
if (gcd == 1) {
return this;
}
return Fraction.getFraction(numerator / gcd, denominator / gcd);
} | false | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Reduce the fraction to the smallest values for the numerator and
* denominator, returning the result.</p>
*
* <p>For example, if this fraction represents 2/4, then the result
* will be 1/2.</p>
*
* @return a new reduced fraction instance, or this if no simplification possible
*/
//-------------------------------------------------------------------
// Calculations
public Fraction reduce() {
if (numerator == 0) {
return equals(ZERO) ? this : ZERO;
}
int gcd = greatestCommonDivisor(Math.abs(numerator), denominator);
if (gcd == 1) {
return this;
}
return Fraction.getFraction(numerator / gcd, denominator / gcd);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
102 | 563a34773e563ab84bd4d3f758d3e789a64c5e631d3e02f6bb20c16cad09ba7a | public double chiSquare(double[] expected, long[] observed)
throws IllegalArgumentException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* {@inheritDoc}
* <p><strong>Note: </strong>This implementation rescales the
* <code>expected</code> array if necessary to ensure that the sum of the
* expected and observed counts are equal.</p>
*
* @param observed array of observed frequency counts
* @param expected array of expected frequency counts
* @return chi-square test statistic
* @throws IllegalArgumentException if preconditions are not met
* or length is less than 2
*/
public double chiSquare(double[] expected, long[] observed)
throws IllegalArgumentException {
if ((expected.length < 2) || (expected.length != observed.length)) {
throw new IllegalArgumentException(
"observed, expected array lengths incorrect");
}
if (!isPositive(expected) || !isNonNegative(observed)) {
throw new IllegalArgumentException(
"observed counts must be non-negative and expected counts must be postive");
}
double sumExpected = 0d;
double sumObserved = 0d;
for (int i = 0; i < observed.length; i++) {
sumExpected += expected[i];
sumObserved += observed[i];
}
double ratio = 1.0d;
boolean rescale = false;
if (Math.abs(sumExpected - sumObserved) > 10E-6) {
ratio = sumObserved / sumExpected;
rescale = true;
}
double sumSq = 0.0d;
double dev = 0.0d;
for (int i = 0; i < observed.length; i++) {
if (rescale) {
dev = ((double) observed[i] - ratio * expected[i]);
sumSq += dev * dev / (ratio * expected[i]);
} else {
dev = ((double) observed[i] - expected[i]);
sumSq += dev * dev / expected[i];
}
}
return sumSq;
}
```
| public double chiSquare(double[] expected, long[] observed)
throws IllegalArgumentException {
if ((expected.length < 2) || (expected.length != observed.length)) {
throw new IllegalArgumentException(
"observed, expected array lengths incorrect");
}
if (!isPositive(expected) || !isNonNegative(observed)) {
throw new IllegalArgumentException(
"observed counts must be non-negative and expected counts must be postive");
}
double sumExpected = 0d;
double sumObserved = 0d;
for (int i = 0; i < observed.length; i++) {
sumExpected += expected[i];
sumObserved += observed[i];
}
double ratio = 1.0d;
boolean rescale = false;
if (Math.abs(sumExpected - sumObserved) > 10E-6) {
ratio = sumObserved / sumExpected;
rescale = true;
}
double sumSq = 0.0d;
double dev = 0.0d;
for (int i = 0; i < observed.length; i++) {
if (rescale) {
dev = ((double) observed[i] - ratio * expected[i]);
sumSq += dev * dev / (ratio * expected[i]);
} else {
dev = ((double) observed[i] - expected[i]);
sumSq += dev * dev / expected[i];
}
}
return sumSq;
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* {@inheritDoc}
* <p><strong>Note: </strong>This implementation rescales the
* <code>expected</code> array if necessary to ensure that the sum of the
* expected and observed counts are equal.</p>
*
* @param observed array of observed frequency counts
* @param expected array of expected frequency counts
* @return chi-square test statistic
* @throws IllegalArgumentException if preconditions are not met
* or length is less than 2
*/
public double chiSquare(double[] expected, long[] observed)
throws IllegalArgumentException {
if ((expected.length < 2) || (expected.length != observed.length)) {
throw new IllegalArgumentException(
"observed, expected array lengths incorrect");
}
if (!isPositive(expected) || !isNonNegative(observed)) {
throw new IllegalArgumentException(
"observed counts must be non-negative and expected counts must be postive");
}
double sumExpected = 0d;
double sumObserved = 0d;
for (int i = 0; i < observed.length; i++) {
sumExpected += expected[i];
sumObserved += observed[i];
}
double ratio = 1.0d;
boolean rescale = false;
if (Math.abs(sumExpected - sumObserved) > 10E-6) {
ratio = sumObserved / sumExpected;
rescale = true;
}
double sumSq = 0.0d;
double dev = 0.0d;
for (int i = 0; i < observed.length; i++) {
if (rescale) {
dev = ((double) observed[i] - ratio * expected[i]);
sumSq += dev * dev / (ratio * expected[i]);
} else {
dev = ((double) observed[i] - expected[i]);
sumSq += dev * dev / expected[i];
}
}
return sumSq;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |