bug_id
stringlengths 1
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| task_id
stringlengths 64
64
| function_signature
stringlengths 15
364
| prompt_chat
stringlengths 471
20.2k
| code
stringlengths 44
19.8k
| defective
bool 2
classes | project
stringclasses 17
values | prompt_complete
stringlengths 3.07k
22.8k
|
|---|---|---|---|---|---|---|---|
88 | 56414f5d5125fe0e22ce438c0ee435056ea77daeda9e68e56d958d590b9daa48 | protected JavaType _typeFromId(String id, DatabindContext ctxt) throws IOException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
protected JavaType _typeFromId(String id, DatabindContext ctxt) throws IOException
{
/* 30-Jan-2010, tatu: Most ids are basic class names; so let's first
* check if any generics info is added; and only then ask factory
* to do translation when necessary
*/
TypeFactory tf = ctxt.getTypeFactory();
if (id.indexOf('<') > 0) {
// note: may want to try combining with specialization (esp for EnumMap)?
// 17-Aug-2017, tatu: As per [databind#1735] need to ensure assignment
// compatibility -- needed later anyway, and not doing so may open
// security issues.
JavaType t = tf.constructFromCanonical(id);
// Probably cleaner to have a method in `TypeFactory` but can't add in patch
return t;
}
Class<?> cls;
try {
cls = tf.findClass(id);
} catch (ClassNotFoundException e) {
// 24-May-2016, tatu: Ok, this is pretty ugly, but we should always get
// DeserializationContext, just playing it safe
if (ctxt instanceof DeserializationContext) {
DeserializationContext dctxt = (DeserializationContext) ctxt;
// First: we may have problem handlers that can deal with it?
return dctxt.handleUnknownTypeId(_baseType, id, this, "no such class found");
}
// ... meaning that we really should never get here.
return null;
} catch (Exception e) {
throw new IllegalArgumentException("Invalid type id '"+id+"' (for id type 'Id.class'): "+e.getMessage(), e);
}
return tf.constructSpecializedType(_baseType, cls);
}
```
| protected JavaType _typeFromId(String id, DatabindContext ctxt) throws IOException
{
/* 30-Jan-2010, tatu: Most ids are basic class names; so let's first
* check if any generics info is added; and only then ask factory
* to do translation when necessary
*/
TypeFactory tf = ctxt.getTypeFactory();
if (id.indexOf('<') > 0) {
// note: may want to try combining with specialization (esp for EnumMap)?
// 17-Aug-2017, tatu: As per [databind#1735] need to ensure assignment
// compatibility -- needed later anyway, and not doing so may open
// security issues.
JavaType t = tf.constructFromCanonical(id);
// Probably cleaner to have a method in `TypeFactory` but can't add in patch
return t;
}
Class<?> cls;
try {
cls = tf.findClass(id);
} catch (ClassNotFoundException e) {
// 24-May-2016, tatu: Ok, this is pretty ugly, but we should always get
// DeserializationContext, just playing it safe
if (ctxt instanceof DeserializationContext) {
DeserializationContext dctxt = (DeserializationContext) ctxt;
// First: we may have problem handlers that can deal with it?
return dctxt.handleUnknownTypeId(_baseType, id, this, "no such class found");
}
// ... meaning that we really should never get here.
return null;
} catch (Exception e) {
throw new IllegalArgumentException("Invalid type id '"+id+"' (for id type 'Id.class'): "+e.getMessage(), e);
}
return tf.constructSpecializedType(_baseType, cls);
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
protected JavaType _typeFromId(String id, DatabindContext ctxt) throws IOException
{
/* 30-Jan-2010, tatu: Most ids are basic class names; so let's first
* check if any generics info is added; and only then ask factory
* to do translation when necessary
*/
TypeFactory tf = ctxt.getTypeFactory();
if (id.indexOf('<') > 0) {
// note: may want to try combining with specialization (esp for EnumMap)?
// 17-Aug-2017, tatu: As per [databind#1735] need to ensure assignment
// compatibility -- needed later anyway, and not doing so may open
// security issues.
JavaType t = tf.constructFromCanonical(id);
// Probably cleaner to have a method in `TypeFactory` but can't add in patch
return t;
}
Class<?> cls;
try {
cls = tf.findClass(id);
} catch (ClassNotFoundException e) {
// 24-May-2016, tatu: Ok, this is pretty ugly, but we should always get
// DeserializationContext, just playing it safe
if (ctxt instanceof DeserializationContext) {
DeserializationContext dctxt = (DeserializationContext) ctxt;
// First: we may have problem handlers that can deal with it?
return dctxt.handleUnknownTypeId(_baseType, id, this, "no such class found");
}
// ... meaning that we really should never get here.
return null;
} catch (Exception e) {
throw new IllegalArgumentException("Invalid type id '"+id+"' (for id type 'Id.class'): "+e.getMessage(), e);
}
return tf.constructSpecializedType(_baseType, cls);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
168 | 568f99c03233608439dc8e17f6bdd5070ab637815b6b02f6da1f899d5b047b3d | @Override public void visit(NodeTraversal t, Node n, Node parent) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override public void visit(NodeTraversal t, Node n, Node parent) {
if (t.inGlobalScope()) {
return;
}
if (n.isReturn() && n.getFirstChild() != null) {
data.get(t.getScopeRoot()).recordNonEmptyReturn();
}
if (t.getScopeDepth() <= 2) {
// The first-order function analyzer looks at two types of variables:
//
// 1) Local variables that are assigned in inner scopes ("escaped vars")
//
// 2) Local variables that are assigned more than once.
//
// We treat all global variables as escaped by default, so there's
// no reason to do this extra computation for them.
return;
}
if (n.isName() && NodeUtil.isLValue(n) &&
// Be careful of bleeding functions, which create variables
// in the inner scope, not the scope where the name appears.
!NodeUtil.isBleedingFunctionName(n)) {
String name = n.getString();
Scope scope = t.getScope();
Var var = scope.getVar(name);
if (var != null) {
Scope ownerScope = var.getScope();
if (ownerScope.isLocal()) {
data.get(ownerScope.getRootNode()).recordAssignedName(name);
}
if (scope != ownerScope && ownerScope.isLocal()) {
data.get(ownerScope.getRootNode()).recordEscapedVarName(name);
}
}
} else if (n.isGetProp() && n.isUnscopedQualifiedName() &&
NodeUtil.isLValue(n)) {
String name = NodeUtil.getRootOfQualifiedName(n).getString();
Scope scope = t.getScope();
Var var = scope.getVar(name);
if (var != null) {
Scope ownerScope = var.getScope();
if (scope != ownerScope && ownerScope.isLocal()) {
data.get(ownerScope.getRootNode())
.recordEscapedQualifiedName(n.getQualifiedName());
}
}
}
}
```
| @Override public void visit(NodeTraversal t, Node n, Node parent) {
if (t.inGlobalScope()) {
return;
}
if (n.isReturn() && n.getFirstChild() != null) {
data.get(t.getScopeRoot()).recordNonEmptyReturn();
}
if (t.getScopeDepth() <= 2) {
// The first-order function analyzer looks at two types of variables:
//
// 1) Local variables that are assigned in inner scopes ("escaped vars")
//
// 2) Local variables that are assigned more than once.
//
// We treat all global variables as escaped by default, so there's
// no reason to do this extra computation for them.
return;
}
if (n.isName() && NodeUtil.isLValue(n) &&
// Be careful of bleeding functions, which create variables
// in the inner scope, not the scope where the name appears.
!NodeUtil.isBleedingFunctionName(n)) {
String name = n.getString();
Scope scope = t.getScope();
Var var = scope.getVar(name);
if (var != null) {
Scope ownerScope = var.getScope();
if (ownerScope.isLocal()) {
data.get(ownerScope.getRootNode()).recordAssignedName(name);
}
if (scope != ownerScope && ownerScope.isLocal()) {
data.get(ownerScope.getRootNode()).recordEscapedVarName(name);
}
}
} else if (n.isGetProp() && n.isUnscopedQualifiedName() &&
NodeUtil.isLValue(n)) {
String name = NodeUtil.getRootOfQualifiedName(n).getString();
Scope scope = t.getScope();
Var var = scope.getVar(name);
if (var != null) {
Scope ownerScope = var.getScope();
if (scope != ownerScope && ownerScope.isLocal()) {
data.get(ownerScope.getRootNode())
.recordEscapedQualifiedName(n.getQualifiedName());
}
}
}
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override public void visit(NodeTraversal t, Node n, Node parent) {
if (t.inGlobalScope()) {
return;
}
if (n.isReturn() && n.getFirstChild() != null) {
data.get(t.getScopeRoot()).recordNonEmptyReturn();
}
if (t.getScopeDepth() <= 2) {
// The first-order function analyzer looks at two types of variables:
//
// 1) Local variables that are assigned in inner scopes ("escaped vars")
//
// 2) Local variables that are assigned more than once.
//
// We treat all global variables as escaped by default, so there's
// no reason to do this extra computation for them.
return;
}
if (n.isName() && NodeUtil.isLValue(n) &&
// Be careful of bleeding functions, which create variables
// in the inner scope, not the scope where the name appears.
!NodeUtil.isBleedingFunctionName(n)) {
String name = n.getString();
Scope scope = t.getScope();
Var var = scope.getVar(name);
if (var != null) {
Scope ownerScope = var.getScope();
if (ownerScope.isLocal()) {
data.get(ownerScope.getRootNode()).recordAssignedName(name);
}
if (scope != ownerScope && ownerScope.isLocal()) {
data.get(ownerScope.getRootNode()).recordEscapedVarName(name);
}
}
} else if (n.isGetProp() && n.isUnscopedQualifiedName() &&
NodeUtil.isLValue(n)) {
String name = NodeUtil.getRootOfQualifiedName(n).getString();
Scope scope = t.getScope();
Var var = scope.getVar(name);
if (var != null) {
Scope ownerScope = var.getScope();
if (scope != ownerScope && ownerScope.isLocal()) {
data.get(ownerScope.getRootNode())
.recordEscapedQualifiedName(n.getQualifiedName());
}
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
8 | 588fd786cf48fffd44911eadca049dd297c04698b44eacde6b1636433024b2d4 | public T[] sample(int sampleSize) throws NotStrictlyPositiveException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Generate a random sample from the distribution.
*
* @param sampleSize the number of random values to generate.
* @return an array representing the random sample.
* @throws NotStrictlyPositiveException if {@code sampleSize} is not
* positive.
*/
public T[] sample(int sampleSize) throws NotStrictlyPositiveException {
if (sampleSize <= 0) {
throw new NotStrictlyPositiveException(LocalizedFormats.NUMBER_OF_SAMPLES,
sampleSize);
}
final T[]out = (T[]) java.lang.reflect.Array.newInstance(singletons.get(0).getClass(), sampleSize);
for (int i = 0; i < sampleSize; i++) {
out[i] = sample();
}
return out;
}
```
| public T[] sample(int sampleSize) throws NotStrictlyPositiveException {
if (sampleSize <= 0) {
throw new NotStrictlyPositiveException(LocalizedFormats.NUMBER_OF_SAMPLES,
sampleSize);
}
final T[]out = (T[]) java.lang.reflect.Array.newInstance(singletons.get(0).getClass(), sampleSize);
for (int i = 0; i < sampleSize; i++) {
out[i] = sample();
}
return out;
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Generate a random sample from the distribution.
*
* @param sampleSize the number of random values to generate.
* @return an array representing the random sample.
* @throws NotStrictlyPositiveException if {@code sampleSize} is not
* positive.
*/
public T[] sample(int sampleSize) throws NotStrictlyPositiveException {
if (sampleSize <= 0) {
throw new NotStrictlyPositiveException(LocalizedFormats.NUMBER_OF_SAMPLES,
sampleSize);
}
final T[]out = (T[]) java.lang.reflect.Array.newInstance(singletons.get(0).getClass(), sampleSize);
for (int i = 0; i < sampleSize; i++) {
out[i] = sample();
}
return out;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
5 | 58ac90638dc83dda797c44d27aa5da206305b5c30fe3e9df5f7fadb4f79a7f72 | public void println() throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Outputs the record separator.
*
* @throws IOException
* If an I/O error occurs
*/
public void println() throws IOException {
final String recordSeparator = format.getRecordSeparator();
out.append(recordSeparator);
newRecord = true;
}
```
| public void println() throws IOException {
final String recordSeparator = format.getRecordSeparator();
out.append(recordSeparator);
newRecord = true;
} | true | Csv | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Outputs the record separator.
*
* @throws IOException
* If an I/O error occurs
*/
public void println() throws IOException {
final String recordSeparator = format.getRecordSeparator();
out.append(recordSeparator);
newRecord = true;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
3 | 59061baaaedbb47dabf169629dc1b8fb1d47feb398ebec1f9a87b328fd179bdc | public UTF8StreamJsonParser(IOContext ctxt, int features, InputStream in,
ObjectCodec codec, BytesToNameCanonicalizer sym,
byte[] inputBuffer, int start, int end,
boolean bufferRecyclable)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/*
/**********************************************************
/* Life-cycle
/**********************************************************
*/
public UTF8StreamJsonParser(IOContext ctxt, int features, InputStream in,
ObjectCodec codec, BytesToNameCanonicalizer sym,
byte[] inputBuffer, int start, int end,
boolean bufferRecyclable)
{
super(ctxt, features);
_inputStream = in;
_objectCodec = codec;
_symbols = sym;
_inputBuffer = inputBuffer;
_inputPtr = start;
_inputEnd = end;
_currInputRowStart = start;
// If we have offset, need to omit that from byte offset, so:
_currInputProcessed = -start;
_bufferRecyclable = bufferRecyclable;
}
```
| public UTF8StreamJsonParser(IOContext ctxt, int features, InputStream in,
ObjectCodec codec, BytesToNameCanonicalizer sym,
byte[] inputBuffer, int start, int end,
boolean bufferRecyclable)
{
super(ctxt, features);
_inputStream = in;
_objectCodec = codec;
_symbols = sym;
_inputBuffer = inputBuffer;
_inputPtr = start;
_inputEnd = end;
_currInputRowStart = start;
// If we have offset, need to omit that from byte offset, so:
_currInputProcessed = -start;
_bufferRecyclable = bufferRecyclable;
} | false | JacksonCore | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/*
/**********************************************************
/* Life-cycle
/**********************************************************
*/
public UTF8StreamJsonParser(IOContext ctxt, int features, InputStream in,
ObjectCodec codec, BytesToNameCanonicalizer sym,
byte[] inputBuffer, int start, int end,
boolean bufferRecyclable)
{
super(ctxt, features);
_inputStream = in;
_objectCodec = codec;
_symbols = sym;
_inputBuffer = inputBuffer;
_inputPtr = start;
_inputEnd = end;
_currInputRowStart = start;
// If we have offset, need to omit that from byte offset, so:
_currInputProcessed = -start;
_bufferRecyclable = bufferRecyclable;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
46 | 591bb2aac5817c3a863c0bd981052a72b2905d6eebdff06ff078d9fd43bedb0a | static void escape(StringBuilder accum, String string, Document.OutputSettings out,
boolean inAttribute, boolean normaliseWhite, boolean stripLeadingWhite) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
// this method is ugly, and does a lot. but other breakups cause rescanning and stringbuilder generations
static void escape(StringBuilder accum, String string, Document.OutputSettings out,
boolean inAttribute, boolean normaliseWhite, boolean stripLeadingWhite) {
boolean lastWasWhite = false;
boolean reachedNonWhite = false;
final EscapeMode escapeMode = out.escapeMode();
final CharsetEncoder encoder = out.encoder();
final CoreCharset coreCharset = CoreCharset.byName(encoder.charset().name());
final Map<Character, String> map = escapeMode.getMap();
final int length = string.length();
int codePoint;
for (int offset = 0; offset < length; offset += Character.charCount(codePoint)) {
codePoint = string.codePointAt(offset);
if (normaliseWhite) {
if (StringUtil.isWhitespace(codePoint)) {
if ((stripLeadingWhite && !reachedNonWhite) || lastWasWhite)
continue;
accum.append(' ');
lastWasWhite = true;
continue;
} else {
lastWasWhite = false;
reachedNonWhite = true;
}
}
// surrogate pairs, split implementation for efficiency on single char common case (saves creating strings, char[]):
if (codePoint < Character.MIN_SUPPLEMENTARY_CODE_POINT) {
final char c = (char) codePoint;
// html specific and required escapes:
switch (c) {
case '&':
accum.append("&");
break;
case 0xA0:
if (escapeMode != EscapeMode.xhtml)
accum.append(" ");
else
accum.append(c);
break;
case '<':
if (!inAttribute)
accum.append("<");
else
accum.append(c);
break;
case '>':
if (!inAttribute)
accum.append(">");
else
accum.append(c);
break;
case '"':
if (inAttribute)
accum.append(""");
else
accum.append(c);
break;
default:
if (canEncode(coreCharset, c, encoder))
accum.append(c);
else if (map.containsKey(c))
accum.append('&').append(map.get(c)).append(';');
else
accum.append("&#x").append(Integer.toHexString(codePoint)).append(';');
}
} else {
final String c = new String(Character.toChars(codePoint));
if (encoder.canEncode(c)) // uses fallback encoder for simplicity
accum.append(c);
else
accum.append("&#x").append(Integer.toHexString(codePoint)).append(';');
}
}
}
```
| static void escape(StringBuilder accum, String string, Document.OutputSettings out,
boolean inAttribute, boolean normaliseWhite, boolean stripLeadingWhite) {
boolean lastWasWhite = false;
boolean reachedNonWhite = false;
final EscapeMode escapeMode = out.escapeMode();
final CharsetEncoder encoder = out.encoder();
final CoreCharset coreCharset = CoreCharset.byName(encoder.charset().name());
final Map<Character, String> map = escapeMode.getMap();
final int length = string.length();
int codePoint;
for (int offset = 0; offset < length; offset += Character.charCount(codePoint)) {
codePoint = string.codePointAt(offset);
if (normaliseWhite) {
if (StringUtil.isWhitespace(codePoint)) {
if ((stripLeadingWhite && !reachedNonWhite) || lastWasWhite)
continue;
accum.append(' ');
lastWasWhite = true;
continue;
} else {
lastWasWhite = false;
reachedNonWhite = true;
}
}
// surrogate pairs, split implementation for efficiency on single char common case (saves creating strings, char[]):
if (codePoint < Character.MIN_SUPPLEMENTARY_CODE_POINT) {
final char c = (char) codePoint;
// html specific and required escapes:
switch (c) {
case '&':
accum.append("&");
break;
case 0xA0:
if (escapeMode != EscapeMode.xhtml)
accum.append(" ");
else
accum.append(c);
break;
case '<':
if (!inAttribute)
accum.append("<");
else
accum.append(c);
break;
case '>':
if (!inAttribute)
accum.append(">");
else
accum.append(c);
break;
case '"':
if (inAttribute)
accum.append(""");
else
accum.append(c);
break;
default:
if (canEncode(coreCharset, c, encoder))
accum.append(c);
else if (map.containsKey(c))
accum.append('&').append(map.get(c)).append(';');
else
accum.append("&#x").append(Integer.toHexString(codePoint)).append(';');
}
} else {
final String c = new String(Character.toChars(codePoint));
if (encoder.canEncode(c)) // uses fallback encoder for simplicity
accum.append(c);
else
accum.append("&#x").append(Integer.toHexString(codePoint)).append(';');
}
}
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
// this method is ugly, and does a lot. but other breakups cause rescanning and stringbuilder generations
static void escape(StringBuilder accum, String string, Document.OutputSettings out,
boolean inAttribute, boolean normaliseWhite, boolean stripLeadingWhite) {
boolean lastWasWhite = false;
boolean reachedNonWhite = false;
final EscapeMode escapeMode = out.escapeMode();
final CharsetEncoder encoder = out.encoder();
final CoreCharset coreCharset = CoreCharset.byName(encoder.charset().name());
final Map<Character, String> map = escapeMode.getMap();
final int length = string.length();
int codePoint;
for (int offset = 0; offset < length; offset += Character.charCount(codePoint)) {
codePoint = string.codePointAt(offset);
if (normaliseWhite) {
if (StringUtil.isWhitespace(codePoint)) {
if ((stripLeadingWhite && !reachedNonWhite) || lastWasWhite)
continue;
accum.append(' ');
lastWasWhite = true;
continue;
} else {
lastWasWhite = false;
reachedNonWhite = true;
}
}
// surrogate pairs, split implementation for efficiency on single char common case (saves creating strings, char[]):
if (codePoint < Character.MIN_SUPPLEMENTARY_CODE_POINT) {
final char c = (char) codePoint;
// html specific and required escapes:
switch (c) {
case '&':
accum.append("&");
break;
case 0xA0:
if (escapeMode != EscapeMode.xhtml)
accum.append(" ");
else
accum.append(c);
break;
case '<':
if (!inAttribute)
accum.append("<");
else
accum.append(c);
break;
case '>':
if (!inAttribute)
accum.append(">");
else
accum.append(c);
break;
case '"':
if (inAttribute)
accum.append(""");
else
accum.append(c);
break;
default:
if (canEncode(coreCharset, c, encoder))
accum.append(c);
else if (map.containsKey(c))
accum.append('&').append(map.get(c)).append(';');
else
accum.append("&#x").append(Integer.toHexString(codePoint)).append(';');
}
} else {
final String c = new String(Character.toChars(codePoint));
if (encoder.canEncode(c)) // uses fallback encoder for simplicity
accum.append(c);
else
accum.append("&#x").append(Integer.toHexString(codePoint)).append(';');
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
35 | 598376973818196e637c2f3702ab8d772fcaef0b4891b59e19df604b3963aed2 | public List<String> getMatchingOptions(String opt)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns the options with a long name starting with the name specified.
*
* @param opt the partial name of the option
* @return the options matching the partial name specified, or an empty list if none matches
* @since 1.3
*/
public List<String> getMatchingOptions(String opt)
{
opt = Util.stripLeadingHyphens(opt);
List<String> matchingOpts = new ArrayList<String>();
// for a perfect match return the single option only
for (String longOpt : longOpts.keySet())
{
if (longOpt.startsWith(opt))
{
matchingOpts.add(longOpt);
}
}
return matchingOpts;
}
```
| public List<String> getMatchingOptions(String opt)
{
opt = Util.stripLeadingHyphens(opt);
List<String> matchingOpts = new ArrayList<String>();
// for a perfect match return the single option only
for (String longOpt : longOpts.keySet())
{
if (longOpt.startsWith(opt))
{
matchingOpts.add(longOpt);
}
}
return matchingOpts;
} | true | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns the options with a long name starting with the name specified.
*
* @param opt the partial name of the option
* @return the options matching the partial name specified, or an empty list if none matches
* @since 1.3
*/
public List<String> getMatchingOptions(String opt)
{
opt = Util.stripLeadingHyphens(opt);
List<String> matchingOpts = new ArrayList<String>();
// for a perfect match return the single option only
for (String longOpt : longOpts.keySet())
{
if (longOpt.startsWith(opt))
{
matchingOpts.add(longOpt);
}
}
return matchingOpts;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
7 | 5987e6ef28cdc27350bce1b302d7532427b67cf48a0a41cb32d41b1fcfafe249 | public int writeValue() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public int writeValue() {
// Most likely, object:
if (_type == TYPE_OBJECT) {
if (!_gotName) {
return STATUS_EXPECT_NAME;
}
_gotName = false;
++_index;
return STATUS_OK_AFTER_COLON;
}
// Ok, array?
if (_type == TYPE_ARRAY) {
int ix = _index;
++_index;
return (ix < 0) ? STATUS_OK_AS_IS : STATUS_OK_AFTER_COMMA;
}
// Nope, root context
// No commas within root context, but need space
++_index;
return (_index == 0) ? STATUS_OK_AS_IS : STATUS_OK_AFTER_SPACE;
}
```
| public int writeValue() {
// Most likely, object:
if (_type == TYPE_OBJECT) {
if (!_gotName) {
return STATUS_EXPECT_NAME;
}
_gotName = false;
++_index;
return STATUS_OK_AFTER_COLON;
}
// Ok, array?
if (_type == TYPE_ARRAY) {
int ix = _index;
++_index;
return (ix < 0) ? STATUS_OK_AS_IS : STATUS_OK_AFTER_COMMA;
}
// Nope, root context
// No commas within root context, but need space
++_index;
return (_index == 0) ? STATUS_OK_AS_IS : STATUS_OK_AFTER_SPACE;
} | false | JacksonCore | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public int writeValue() {
// Most likely, object:
if (_type == TYPE_OBJECT) {
if (!_gotName) {
return STATUS_EXPECT_NAME;
}
_gotName = false;
++_index;
return STATUS_OK_AFTER_COLON;
}
// Ok, array?
if (_type == TYPE_ARRAY) {
int ix = _index;
++_index;
return (ix < 0) ? STATUS_OK_AS_IS : STATUS_OK_AFTER_COMMA;
}
// Nope, root context
// No commas within root context, but need space
++_index;
return (_index == 0) ? STATUS_OK_AS_IS : STATUS_OK_AFTER_SPACE;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
14 | 59b0322a5dab66021ca7ad54b8a79d1531cebae3be3bd4022852a67c04be3024 | public static boolean equals(CharSequence cs1, CharSequence cs2) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Compares two CharSequences, returning {@code true} if they represent
* equal sequences of characters.</p>
*
* <p>{@code null}s are handled without exceptions. Two {@code null}
* references are considered to be equal. The comparison is case sensitive.</p>
*
* <pre>
* StringUtils.equals(null, null) = true
* StringUtils.equals(null, "abc") = false
* StringUtils.equals("abc", null) = false
* StringUtils.equals("abc", "abc") = true
* StringUtils.equals("abc", "ABC") = false
* </pre>
*
* @see java.lang.CharSequence#equals(Object)
* @param cs1 the first CharSequence, may be {@code null}
* @param cs2 the second CharSequence, may be {@code null}
* @return {@code true} if the CharSequences are equal (case-sensitive), or both {@code null}
* @since 3.0 Changed signature from equals(String, String) to equals(CharSequence, CharSequence)
*/
//-----------------------------------------------------------------------
// Equals
public static boolean equals(CharSequence cs1, CharSequence cs2) {
if (cs1 == cs2) {
return true;
}
if (cs1 == null || cs2 == null) {
return false;
}
if (cs1 instanceof String && cs2 instanceof String) {
return cs1.equals(cs2);
}
return CharSequenceUtils.regionMatches(cs1, false, 0, cs2, 0, Math.max(cs1.length(), cs2.length()));
}
```
| public static boolean equals(CharSequence cs1, CharSequence cs2) {
if (cs1 == cs2) {
return true;
}
if (cs1 == null || cs2 == null) {
return false;
}
if (cs1 instanceof String && cs2 instanceof String) {
return cs1.equals(cs2);
}
return CharSequenceUtils.regionMatches(cs1, false, 0, cs2, 0, Math.max(cs1.length(), cs2.length()));
} | false | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Compares two CharSequences, returning {@code true} if they represent
* equal sequences of characters.</p>
*
* <p>{@code null}s are handled without exceptions. Two {@code null}
* references are considered to be equal. The comparison is case sensitive.</p>
*
* <pre>
* StringUtils.equals(null, null) = true
* StringUtils.equals(null, "abc") = false
* StringUtils.equals("abc", null) = false
* StringUtils.equals("abc", "abc") = true
* StringUtils.equals("abc", "ABC") = false
* </pre>
*
* @see java.lang.CharSequence#equals(Object)
* @param cs1 the first CharSequence, may be {@code null}
* @param cs2 the second CharSequence, may be {@code null}
* @return {@code true} if the CharSequences are equal (case-sensitive), or both {@code null}
* @since 3.0 Changed signature from equals(String, String) to equals(CharSequence, CharSequence)
*/
//-----------------------------------------------------------------------
// Equals
public static boolean equals(CharSequence cs1, CharSequence cs2) {
if (cs1 == cs2) {
return true;
}
if (cs1 == null || cs2 == null) {
return false;
}
if (cs1 instanceof String && cs2 instanceof String) {
return cs1.equals(cs2);
}
return CharSequenceUtils.regionMatches(cs1, false, 0, cs2, 0, Math.max(cs1.length(), cs2.length()));
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
33 | 5a5f7e32167fe670b0fae8181bd30c1891d0882d84b1d36dfbd34bcab8024b10 | @Override
public PropertyName findNameForSerialization(Annotated a)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/*
/**********************************************************
/* Serialization: property annotations
/**********************************************************
*/
@Override
public PropertyName findNameForSerialization(Annotated a)
{
String name = null;
JsonGetter jg = _findAnnotation(a, JsonGetter.class);
if (jg != null) {
name = jg.value();
} else {
JsonProperty pann = _findAnnotation(a, JsonProperty.class);
if (pann != null) {
name = pann.value();
/* 22-Apr-2014, tatu: Should figure out a better way to do this, but
* it's actually bit tricky to do it more efficiently (meta-annotations
* add more lookups; AnnotationMap costs etc)
*/
} else if (_hasAnnotation(a, JsonSerialize.class)
|| _hasAnnotation(a, JsonView.class)
|| _hasAnnotation(a, JsonRawValue.class)) {
name = "";
} else {
return null;
}
}
return PropertyName.construct(name);
}
```
| @Override
public PropertyName findNameForSerialization(Annotated a)
{
String name = null;
JsonGetter jg = _findAnnotation(a, JsonGetter.class);
if (jg != null) {
name = jg.value();
} else {
JsonProperty pann = _findAnnotation(a, JsonProperty.class);
if (pann != null) {
name = pann.value();
/* 22-Apr-2014, tatu: Should figure out a better way to do this, but
* it's actually bit tricky to do it more efficiently (meta-annotations
* add more lookups; AnnotationMap costs etc)
*/
} else if (_hasAnnotation(a, JsonSerialize.class)
|| _hasAnnotation(a, JsonView.class)
|| _hasAnnotation(a, JsonRawValue.class)) {
name = "";
} else {
return null;
}
}
return PropertyName.construct(name);
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/*
/**********************************************************
/* Serialization: property annotations
/**********************************************************
*/
@Override
public PropertyName findNameForSerialization(Annotated a)
{
String name = null;
JsonGetter jg = _findAnnotation(a, JsonGetter.class);
if (jg != null) {
name = jg.value();
} else {
JsonProperty pann = _findAnnotation(a, JsonProperty.class);
if (pann != null) {
name = pann.value();
/* 22-Apr-2014, tatu: Should figure out a better way to do this, but
* it's actually bit tricky to do it more efficiently (meta-annotations
* add more lookups; AnnotationMap costs etc)
*/
} else if (_hasAnnotation(a, JsonSerialize.class)
|| _hasAnnotation(a, JsonView.class)
|| _hasAnnotation(a, JsonRawValue.class)) {
name = "";
} else {
return null;
}
}
return PropertyName.construct(name);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
27 | 5ab4d4beceb9c38b988d779ad9ea1a90f9b8b8ac6795df76573aaf86d2ea2029 | public <T> void resetMock(T mock) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public <T> void resetMock(T mock) {
MockHandlerInterface<T> oldMockHandler = getMockHandler(mock);
MethodInterceptorFilter newFilter = newMethodInterceptorFilter(oldMockHandler.getMockSettings());
((Factory) mock).setCallback(0, newFilter);
}
```
| public <T> void resetMock(T mock) {
MockHandlerInterface<T> oldMockHandler = getMockHandler(mock);
MethodInterceptorFilter newFilter = newMethodInterceptorFilter(oldMockHandler.getMockSettings());
((Factory) mock).setCallback(0, newFilter);
} | false | Mockito | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public <T> void resetMock(T mock) {
MockHandlerInterface<T> oldMockHandler = getMockHandler(mock);
MethodInterceptorFilter newFilter = newMethodInterceptorFilter(oldMockHandler.getMockSettings());
((Factory) mock).setCallback(0, newFilter);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
8 | 5b9541f70e0b8cfa3a908b4fed71b7b936f56eced2f852f8fd54eedf7c5d1e68 | protected StringBuffer renderWrappedText(StringBuffer sb, int width,
int nextLineTabStop, String text)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Render the specified text and return the rendered Options
* in a StringBuffer.</p>
*
* @param sb The StringBuffer to place the rendered text into.
* @param width The number of characters to display per line
* @param nextLineTabStop The position on the next line for the first tab.
* @param text The text to be rendered.
*
* @return the StringBuffer with the rendered Options contents.
*/
protected StringBuffer renderWrappedText(StringBuffer sb, int width,
int nextLineTabStop, String text)
{
int pos = findWrapPos(text, width, 0);
if (pos == -1)
{
sb.append(rtrim(text));
return sb;
}
sb.append(rtrim(text.substring(0, pos))).append(defaultNewLine);
// all following lines must be padded with nextLineTabStop space
// characters
final String padding = createPadding(nextLineTabStop);
while (true)
{
text = padding + text.substring(pos).trim();
pos = findWrapPos(text, width, nextLineTabStop);
if (pos == -1)
{
sb.append(text);
return sb;
}
sb.append(rtrim(text.substring(0, pos))).append(defaultNewLine);
}
}
```
| protected StringBuffer renderWrappedText(StringBuffer sb, int width,
int nextLineTabStop, String text)
{
int pos = findWrapPos(text, width, 0);
if (pos == -1)
{
sb.append(rtrim(text));
return sb;
}
sb.append(rtrim(text.substring(0, pos))).append(defaultNewLine);
// all following lines must be padded with nextLineTabStop space
// characters
final String padding = createPadding(nextLineTabStop);
while (true)
{
text = padding + text.substring(pos).trim();
pos = findWrapPos(text, width, nextLineTabStop);
if (pos == -1)
{
sb.append(text);
return sb;
}
sb.append(rtrim(text.substring(0, pos))).append(defaultNewLine);
}
} | true | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Render the specified text and return the rendered Options
* in a StringBuffer.</p>
*
* @param sb The StringBuffer to place the rendered text into.
* @param width The number of characters to display per line
* @param nextLineTabStop The position on the next line for the first tab.
* @param text The text to be rendered.
*
* @return the StringBuffer with the rendered Options contents.
*/
protected StringBuffer renderWrappedText(StringBuffer sb, int width,
int nextLineTabStop, String text)
{
int pos = findWrapPos(text, width, 0);
if (pos == -1)
{
sb.append(rtrim(text));
return sb;
}
sb.append(rtrim(text.substring(0, pos))).append(defaultNewLine);
// all following lines must be padded with nextLineTabStop space
// characters
final String padding = createPadding(nextLineTabStop);
while (true)
{
text = padding + text.substring(pos).trim();
pos = findWrapPos(text, width, nextLineTabStop);
if (pos == -1)
{
sb.append(text);
return sb;
}
sb.append(rtrim(text.substring(0, pos))).append(defaultNewLine);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
119 | 5bb81c89167c12fc9d4f70fd5bd05603359d0cdf9781658c707a6975cb62f41d | public void collect(JSModule module, Scope scope, Node n) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public void collect(JSModule module, Scope scope, Node n) {
Node parent = n.getParent();
String name;
boolean isSet = false;
Name.Type type = Name.Type.OTHER;
boolean isPropAssign = false;
switch (n.getType()) {
case Token.GETTER_DEF:
case Token.SETTER_DEF:
case Token.STRING_KEY:
// This may be a key in an object literal declaration.
name = null;
if (parent != null && parent.isObjectLit()) {
name = getNameForObjLitKey(n);
}
if (name == null) {
return;
}
isSet = true;
switch (n.getType()) {
case Token.STRING_KEY:
type = getValueType(n.getFirstChild());
break;
case Token.GETTER_DEF:
type = Name.Type.GET;
break;
case Token.SETTER_DEF:
type = Name.Type.SET;
break;
default:
throw new IllegalStateException("unexpected:" + n);
}
break;
case Token.NAME:
// This may be a variable get or set.
if (parent != null) {
switch (parent.getType()) {
case Token.VAR:
isSet = true;
Node rvalue = n.getFirstChild();
type = rvalue == null ? Name.Type.OTHER : getValueType(rvalue);
break;
case Token.ASSIGN:
if (parent.getFirstChild() == n) {
isSet = true;
type = getValueType(n.getNext());
}
break;
case Token.GETPROP:
return;
case Token.FUNCTION:
Node gramps = parent.getParent();
if (gramps == null || NodeUtil.isFunctionExpression(parent)) {
return;
}
isSet = true;
type = Name.Type.FUNCTION;
break;
case Token.INC:
case Token.DEC:
isSet = true;
type = Name.Type.OTHER;
break;
default:
if (NodeUtil.isAssignmentOp(parent) &&
parent.getFirstChild() == n) {
isSet = true;
type = Name.Type.OTHER;
}
}
}
name = n.getString();
break;
case Token.GETPROP:
// This may be a namespaced name get or set.
if (parent != null) {
switch (parent.getType()) {
case Token.ASSIGN:
if (parent.getFirstChild() == n) {
isSet = true;
type = getValueType(n.getNext());
isPropAssign = true;
}
break;
case Token.INC:
case Token.DEC:
isSet = true;
type = Name.Type.OTHER;
break;
case Token.GETPROP:
return;
default:
if (NodeUtil.isAssignmentOp(parent) &&
parent.getFirstChild() == n) {
isSet = true;
type = Name.Type.OTHER;
}
}
}
name = n.getQualifiedName();
if (name == null) {
return;
}
break;
default:
return;
}
// We are only interested in global names.
if (!isGlobalNameReference(name, scope)) {
return;
}
if (isSet) {
if (isGlobalScope(scope)) {
handleSetFromGlobal(module, scope, n, parent, name, isPropAssign, type);
} else {
handleSetFromLocal(module, scope, n, parent, name);
}
} else {
handleGet(module, scope, n, parent, name);
}
}
```
| public void collect(JSModule module, Scope scope, Node n) {
Node parent = n.getParent();
String name;
boolean isSet = false;
Name.Type type = Name.Type.OTHER;
boolean isPropAssign = false;
switch (n.getType()) {
case Token.GETTER_DEF:
case Token.SETTER_DEF:
case Token.STRING_KEY:
// This may be a key in an object literal declaration.
name = null;
if (parent != null && parent.isObjectLit()) {
name = getNameForObjLitKey(n);
}
if (name == null) {
return;
}
isSet = true;
switch (n.getType()) {
case Token.STRING_KEY:
type = getValueType(n.getFirstChild());
break;
case Token.GETTER_DEF:
type = Name.Type.GET;
break;
case Token.SETTER_DEF:
type = Name.Type.SET;
break;
default:
throw new IllegalStateException("unexpected:" + n);
}
break;
case Token.NAME:
// This may be a variable get or set.
if (parent != null) {
switch (parent.getType()) {
case Token.VAR:
isSet = true;
Node rvalue = n.getFirstChild();
type = rvalue == null ? Name.Type.OTHER : getValueType(rvalue);
break;
case Token.ASSIGN:
if (parent.getFirstChild() == n) {
isSet = true;
type = getValueType(n.getNext());
}
break;
case Token.GETPROP:
return;
case Token.FUNCTION:
Node gramps = parent.getParent();
if (gramps == null || NodeUtil.isFunctionExpression(parent)) {
return;
}
isSet = true;
type = Name.Type.FUNCTION;
break;
case Token.INC:
case Token.DEC:
isSet = true;
type = Name.Type.OTHER;
break;
default:
if (NodeUtil.isAssignmentOp(parent) &&
parent.getFirstChild() == n) {
isSet = true;
type = Name.Type.OTHER;
}
}
}
name = n.getString();
break;
case Token.GETPROP:
// This may be a namespaced name get or set.
if (parent != null) {
switch (parent.getType()) {
case Token.ASSIGN:
if (parent.getFirstChild() == n) {
isSet = true;
type = getValueType(n.getNext());
isPropAssign = true;
}
break;
case Token.INC:
case Token.DEC:
isSet = true;
type = Name.Type.OTHER;
break;
case Token.GETPROP:
return;
default:
if (NodeUtil.isAssignmentOp(parent) &&
parent.getFirstChild() == n) {
isSet = true;
type = Name.Type.OTHER;
}
}
}
name = n.getQualifiedName();
if (name == null) {
return;
}
break;
default:
return;
}
// We are only interested in global names.
if (!isGlobalNameReference(name, scope)) {
return;
}
if (isSet) {
if (isGlobalScope(scope)) {
handleSetFromGlobal(module, scope, n, parent, name, isPropAssign, type);
} else {
handleSetFromLocal(module, scope, n, parent, name);
}
} else {
handleGet(module, scope, n, parent, name);
}
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public void collect(JSModule module, Scope scope, Node n) {
Node parent = n.getParent();
String name;
boolean isSet = false;
Name.Type type = Name.Type.OTHER;
boolean isPropAssign = false;
switch (n.getType()) {
case Token.GETTER_DEF:
case Token.SETTER_DEF:
case Token.STRING_KEY:
// This may be a key in an object literal declaration.
name = null;
if (parent != null && parent.isObjectLit()) {
name = getNameForObjLitKey(n);
}
if (name == null) {
return;
}
isSet = true;
switch (n.getType()) {
case Token.STRING_KEY:
type = getValueType(n.getFirstChild());
break;
case Token.GETTER_DEF:
type = Name.Type.GET;
break;
case Token.SETTER_DEF:
type = Name.Type.SET;
break;
default:
throw new IllegalStateException("unexpected:" + n);
}
break;
case Token.NAME:
// This may be a variable get or set.
if (parent != null) {
switch (parent.getType()) {
case Token.VAR:
isSet = true;
Node rvalue = n.getFirstChild();
type = rvalue == null ? Name.Type.OTHER : getValueType(rvalue);
break;
case Token.ASSIGN:
if (parent.getFirstChild() == n) {
isSet = true;
type = getValueType(n.getNext());
}
break;
case Token.GETPROP:
return;
case Token.FUNCTION:
Node gramps = parent.getParent();
if (gramps == null || NodeUtil.isFunctionExpression(parent)) {
return;
}
isSet = true;
type = Name.Type.FUNCTION;
break;
case Token.INC:
case Token.DEC:
isSet = true;
type = Name.Type.OTHER;
break;
default:
if (NodeUtil.isAssignmentOp(parent) &&
parent.getFirstChild() == n) {
isSet = true;
type = Name.Type.OTHER;
}
}
}
name = n.getString();
break;
case Token.GETPROP:
// This may be a namespaced name get or set.
if (parent != null) {
switch (parent.getType()) {
case Token.ASSIGN:
if (parent.getFirstChild() == n) {
isSet = true;
type = getValueType(n.getNext());
isPropAssign = true;
}
break;
case Token.INC:
case Token.DEC:
isSet = true;
type = Name.Type.OTHER;
break;
case Token.GETPROP:
return;
default:
if (NodeUtil.isAssignmentOp(parent) &&
parent.getFirstChild() == n) {
isSet = true;
type = Name.Type.OTHER;
}
}
}
name = n.getQualifiedName();
if (name == null) {
return;
}
break;
default:
return;
}
// We are only interested in global names.
if (!isGlobalNameReference(name, scope)) {
return;
}
if (isSet) {
if (isGlobalScope(scope)) {
handleSetFromGlobal(module, scope, n, parent, name, isPropAssign, type);
} else {
handleSetFromLocal(module, scope, n, parent, name);
}
} else {
handleGet(module, scope, n, parent, name);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
6 | 5bcfa8046b0f7045f44ea5e306873328b1149bb4d4e702a7568528c3052296dc | <M extends Map<String, String>> M putIn(final M map) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Puts all values of this record into the given Map.
*
* @param map The Map to populate.
* @return the given map.
*/
<M extends Map<String, String>> M putIn(final M map) {
for (final Entry<String, Integer> entry : mapping.entrySet()) {
final int col = entry.getValue().intValue();
if (col < values.length) {
map.put(entry.getKey(), values[col]);
}
}
return map;
}
```
| <M extends Map<String, String>> M putIn(final M map) {
for (final Entry<String, Integer> entry : mapping.entrySet()) {
final int col = entry.getValue().intValue();
if (col < values.length) {
map.put(entry.getKey(), values[col]);
}
}
return map;
} | false | Csv | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Puts all values of this record into the given Map.
*
* @param map The Map to populate.
* @return the given map.
*/
<M extends Map<String, String>> M putIn(final M map) {
for (final Entry<String, Integer> entry : mapping.entrySet()) {
final int col = entry.getValue().intValue();
if (col < values.length) {
map.put(entry.getKey(), values[col]);
}
}
return map;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
9 | 5bcfa8046b0f7045f44ea5e306873328b1149bb4d4e702a7568528c3052296dc | <M extends Map<String, String>> M putIn(final M map) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Puts all values of this record into the given Map.
*
* @param map The Map to populate.
* @return the given map.
*/
<M extends Map<String, String>> M putIn(final M map) {
for (final Entry<String, Integer> entry : mapping.entrySet()) {
final int col = entry.getValue().intValue();
if (col < values.length) {
map.put(entry.getKey(), values[col]);
}
}
return map;
}
```
| <M extends Map<String, String>> M putIn(final M map) {
for (final Entry<String, Integer> entry : mapping.entrySet()) {
final int col = entry.getValue().intValue();
if (col < values.length) {
map.put(entry.getKey(), values[col]);
}
}
return map;
} | true | Csv | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Puts all values of this record into the given Map.
*
* @param map The Map to populate.
* @return the given map.
*/
<M extends Map<String, String>> M putIn(final M map) {
for (final Entry<String, Integer> entry : mapping.entrySet()) {
final int col = entry.getValue().intValue();
if (col < values.length) {
map.put(entry.getKey(), values[col]);
}
}
return map;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
129 | 5bfa22e28ee42d9d4f410e8a8ce53f07fef007a4841089d7b00ac1cf9dd724a2 | private void annotateCalls(Node n) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* There are two types of calls we are interested in calls without explicit
* "this" values (what we are call "free" calls) and direct call to eval.
*/
private void annotateCalls(Node n) {
Preconditions.checkState(n.isCall());
// Keep track of of the "this" context of a call. A call without an
// explicit "this" is a free call.
Node first = n.getFirstChild();
// ignore cast nodes.
if (!NodeUtil.isGet(first)) {
n.putBooleanProp(Node.FREE_CALL, true);
}
// Keep track of the context in which eval is called. It is important
// to distinguish between "(0, eval)()" and "eval()".
if (first.isName() &&
"eval".equals(first.getString())) {
first.putBooleanProp(Node.DIRECT_EVAL, true);
}
}
```
| private void annotateCalls(Node n) {
Preconditions.checkState(n.isCall());
// Keep track of of the "this" context of a call. A call without an
// explicit "this" is a free call.
Node first = n.getFirstChild();
// ignore cast nodes.
if (!NodeUtil.isGet(first)) {
n.putBooleanProp(Node.FREE_CALL, true);
}
// Keep track of the context in which eval is called. It is important
// to distinguish between "(0, eval)()" and "eval()".
if (first.isName() &&
"eval".equals(first.getString())) {
first.putBooleanProp(Node.DIRECT_EVAL, true);
}
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* There are two types of calls we are interested in calls without explicit
* "this" values (what we are call "free" calls) and direct call to eval.
*/
private void annotateCalls(Node n) {
Preconditions.checkState(n.isCall());
// Keep track of of the "this" context of a call. A call without an
// explicit "this" is a free call.
Node first = n.getFirstChild();
// ignore cast nodes.
if (!NodeUtil.isGet(first)) {
n.putBooleanProp(Node.FREE_CALL, true);
}
// Keep track of the context in which eval is called. It is important
// to distinguish between "(0, eval)()" and "eval()".
if (first.isName() &&
"eval".equals(first.getString())) {
first.putBooleanProp(Node.DIRECT_EVAL, true);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
92 | 5c2d63167dd2e683957c0dae1a5816d936d8e5274a48066aefcdac75160324c1 | void replace() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Replace the provide statement.
*
* If we're providing a name with no definition, then create one.
* If we're providing a name with a duplicate definition, then make sure
* that definition becomes a declaration.
*/
void replace() {
if (firstNode == null) {
// Don't touch the base case ('goog').
replacementNode = candidateDefinition;
return;
}
// Handle the case where there is a duplicate definition for an explicitly
// provided symbol.
if (candidateDefinition != null && explicitNode != null) {
explicitNode.detachFromParent();
compiler.reportCodeChange();
// Does this need a VAR keyword?
replacementNode = candidateDefinition;
if (NodeUtil.isExpressionNode(candidateDefinition)) {
candidateDefinition.putBooleanProp(Node.IS_NAMESPACE, true);
Node assignNode = candidateDefinition.getFirstChild();
Node nameNode = assignNode.getFirstChild();
if (nameNode.getType() == Token.NAME) {
// Need to convert this assign to a var declaration.
Node valueNode = nameNode.getNext();
assignNode.removeChild(nameNode);
assignNode.removeChild(valueNode);
nameNode.addChildToFront(valueNode);
Node varNode = new Node(Token.VAR, nameNode);
varNode.copyInformationFrom(candidateDefinition);
candidateDefinition.getParent().replaceChild(
candidateDefinition, varNode);
nameNode.setJSDocInfo(assignNode.getJSDocInfo());
compiler.reportCodeChange();
replacementNode = varNode;
}
}
} else {
// Handle the case where there's not a duplicate definition.
replacementNode = createDeclarationNode();
if (firstModule == minimumModule) {
firstNode.getParent().addChildBefore(replacementNode, firstNode);
} else {
// In this case, the name was implicitly provided by two independent
// modules. We need to move this code up to a common module.
int indexOfDot = namespace.indexOf('.');
if (indexOfDot == -1) {
// Any old place is fine.
compiler.getNodeForCodeInsertion(minimumModule)
.addChildToBack(replacementNode);
} else {
// Add it after the parent namespace.
ProvidedName parentName =
providedNames.get(namespace.substring(0, indexOfDot));
Preconditions.checkNotNull(parentName);
Preconditions.checkNotNull(parentName.replacementNode);
parentName.replacementNode.getParent().addChildAfter(
replacementNode, parentName.replacementNode);
}
}
if (explicitNode != null) {
explicitNode.detachFromParent();
}
compiler.reportCodeChange();
}
}
```
| void replace() {
if (firstNode == null) {
// Don't touch the base case ('goog').
replacementNode = candidateDefinition;
return;
}
// Handle the case where there is a duplicate definition for an explicitly
// provided symbol.
if (candidateDefinition != null && explicitNode != null) {
explicitNode.detachFromParent();
compiler.reportCodeChange();
// Does this need a VAR keyword?
replacementNode = candidateDefinition;
if (NodeUtil.isExpressionNode(candidateDefinition)) {
candidateDefinition.putBooleanProp(Node.IS_NAMESPACE, true);
Node assignNode = candidateDefinition.getFirstChild();
Node nameNode = assignNode.getFirstChild();
if (nameNode.getType() == Token.NAME) {
// Need to convert this assign to a var declaration.
Node valueNode = nameNode.getNext();
assignNode.removeChild(nameNode);
assignNode.removeChild(valueNode);
nameNode.addChildToFront(valueNode);
Node varNode = new Node(Token.VAR, nameNode);
varNode.copyInformationFrom(candidateDefinition);
candidateDefinition.getParent().replaceChild(
candidateDefinition, varNode);
nameNode.setJSDocInfo(assignNode.getJSDocInfo());
compiler.reportCodeChange();
replacementNode = varNode;
}
}
} else {
// Handle the case where there's not a duplicate definition.
replacementNode = createDeclarationNode();
if (firstModule == minimumModule) {
firstNode.getParent().addChildBefore(replacementNode, firstNode);
} else {
// In this case, the name was implicitly provided by two independent
// modules. We need to move this code up to a common module.
int indexOfDot = namespace.indexOf('.');
if (indexOfDot == -1) {
// Any old place is fine.
compiler.getNodeForCodeInsertion(minimumModule)
.addChildToBack(replacementNode);
} else {
// Add it after the parent namespace.
ProvidedName parentName =
providedNames.get(namespace.substring(0, indexOfDot));
Preconditions.checkNotNull(parentName);
Preconditions.checkNotNull(parentName.replacementNode);
parentName.replacementNode.getParent().addChildAfter(
replacementNode, parentName.replacementNode);
}
}
if (explicitNode != null) {
explicitNode.detachFromParent();
}
compiler.reportCodeChange();
}
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Replace the provide statement.
*
* If we're providing a name with no definition, then create one.
* If we're providing a name with a duplicate definition, then make sure
* that definition becomes a declaration.
*/
void replace() {
if (firstNode == null) {
// Don't touch the base case ('goog').
replacementNode = candidateDefinition;
return;
}
// Handle the case where there is a duplicate definition for an explicitly
// provided symbol.
if (candidateDefinition != null && explicitNode != null) {
explicitNode.detachFromParent();
compiler.reportCodeChange();
// Does this need a VAR keyword?
replacementNode = candidateDefinition;
if (NodeUtil.isExpressionNode(candidateDefinition)) {
candidateDefinition.putBooleanProp(Node.IS_NAMESPACE, true);
Node assignNode = candidateDefinition.getFirstChild();
Node nameNode = assignNode.getFirstChild();
if (nameNode.getType() == Token.NAME) {
// Need to convert this assign to a var declaration.
Node valueNode = nameNode.getNext();
assignNode.removeChild(nameNode);
assignNode.removeChild(valueNode);
nameNode.addChildToFront(valueNode);
Node varNode = new Node(Token.VAR, nameNode);
varNode.copyInformationFrom(candidateDefinition);
candidateDefinition.getParent().replaceChild(
candidateDefinition, varNode);
nameNode.setJSDocInfo(assignNode.getJSDocInfo());
compiler.reportCodeChange();
replacementNode = varNode;
}
}
} else {
// Handle the case where there's not a duplicate definition.
replacementNode = createDeclarationNode();
if (firstModule == minimumModule) {
firstNode.getParent().addChildBefore(replacementNode, firstNode);
} else {
// In this case, the name was implicitly provided by two independent
// modules. We need to move this code up to a common module.
int indexOfDot = namespace.indexOf('.');
if (indexOfDot == -1) {
// Any old place is fine.
compiler.getNodeForCodeInsertion(minimumModule)
.addChildToBack(replacementNode);
} else {
// Add it after the parent namespace.
ProvidedName parentName =
providedNames.get(namespace.substring(0, indexOfDot));
Preconditions.checkNotNull(parentName);
Preconditions.checkNotNull(parentName.replacementNode);
parentName.replacementNode.getParent().addChildAfter(
replacementNode, parentName.replacementNode);
}
}
if (explicitNode != null) {
explicitNode.detachFromParent();
}
compiler.reportCodeChange();
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
22 | 5cebdb6c015b313757e222428f46f5833059f31cbfe1fbab56da07abf5d6d560 | public static String getNamespaceURI(Node node) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Get the ns uri of the specified node.
* @param node Node to check
* @return String ns uri
*/
public static String getNamespaceURI(Node node) {
if (node instanceof Document) {
node = ((Document) node).getDocumentElement();
}
Element element = (Element) node;
String uri = element.getNamespaceURI();
if (uri == null) {
String prefix = getPrefix(node);
String qname = prefix == null ? "xmlns" : "xmlns:" + prefix;
Node aNode = node;
while (aNode != null) {
if (aNode.getNodeType() == Node.ELEMENT_NODE) {
Attr attr = ((Element) aNode).getAttributeNode(qname);
if (attr != null) {
uri = attr.getValue();
break;
}
}
aNode = aNode.getParentNode();
}
}
return "".equals(uri) ? null : uri;
}
```
| public static String getNamespaceURI(Node node) {
if (node instanceof Document) {
node = ((Document) node).getDocumentElement();
}
Element element = (Element) node;
String uri = element.getNamespaceURI();
if (uri == null) {
String prefix = getPrefix(node);
String qname = prefix == null ? "xmlns" : "xmlns:" + prefix;
Node aNode = node;
while (aNode != null) {
if (aNode.getNodeType() == Node.ELEMENT_NODE) {
Attr attr = ((Element) aNode).getAttributeNode(qname);
if (attr != null) {
uri = attr.getValue();
break;
}
}
aNode = aNode.getParentNode();
}
}
return "".equals(uri) ? null : uri;
} | false | JxPath | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Get the ns uri of the specified node.
* @param node Node to check
* @return String ns uri
*/
public static String getNamespaceURI(Node node) {
if (node instanceof Document) {
node = ((Document) node).getDocumentElement();
}
Element element = (Element) node;
String uri = element.getNamespaceURI();
if (uri == null) {
String prefix = getPrefix(node);
String qname = prefix == null ? "xmlns" : "xmlns:" + prefix;
Node aNode = node;
while (aNode != null) {
if (aNode.getNodeType() == Node.ELEMENT_NODE) {
Attr attr = ((Element) aNode).getAttributeNode(qname);
if (attr != null) {
uri = attr.getValue();
break;
}
}
aNode = aNode.getParentNode();
}
}
return "".equals(uri) ? null : uri;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
48 | 5da8ab3f005dddcb5f271d5bd41d9735b35f041f72dfea44edec7cf06c2af82d | void processResponseHeaders(Map<String, List<String>> resHeaders) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
void processResponseHeaders(Map<String, List<String>> resHeaders) {
for (Map.Entry<String, List<String>> entry : resHeaders.entrySet()) {
String name = entry.getKey();
if (name == null)
continue; // http/1.1 line
List<String> values = entry.getValue();
if (name.equalsIgnoreCase("Set-Cookie")) {
for (String value : values) {
if (value == null)
continue;
TokenQueue cd = new TokenQueue(value);
String cookieName = cd.chompTo("=").trim();
String cookieVal = cd.consumeTo(";").trim();
// ignores path, date, domain, validateTLSCertificates et al. req'd?
// name not blank, value not null
if (cookieName.length() > 0)
cookie(cookieName, cookieVal);
}
} else { // combine same header names with comma: http://www.w3.org/Protocols/rfc2616/rfc2616-sec4.html#sec4.2
if (!values.isEmpty())
header(name, values.get(0));
}
}
}
```
| void processResponseHeaders(Map<String, List<String>> resHeaders) {
for (Map.Entry<String, List<String>> entry : resHeaders.entrySet()) {
String name = entry.getKey();
if (name == null)
continue; // http/1.1 line
List<String> values = entry.getValue();
if (name.equalsIgnoreCase("Set-Cookie")) {
for (String value : values) {
if (value == null)
continue;
TokenQueue cd = new TokenQueue(value);
String cookieName = cd.chompTo("=").trim();
String cookieVal = cd.consumeTo(";").trim();
// ignores path, date, domain, validateTLSCertificates et al. req'd?
// name not blank, value not null
if (cookieName.length() > 0)
cookie(cookieName, cookieVal);
}
} else { // combine same header names with comma: http://www.w3.org/Protocols/rfc2616/rfc2616-sec4.html#sec4.2
if (!values.isEmpty())
header(name, values.get(0));
}
}
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
void processResponseHeaders(Map<String, List<String>> resHeaders) {
for (Map.Entry<String, List<String>> entry : resHeaders.entrySet()) {
String name = entry.getKey();
if (name == null)
continue; // http/1.1 line
List<String> values = entry.getValue();
if (name.equalsIgnoreCase("Set-Cookie")) {
for (String value : values) {
if (value == null)
continue;
TokenQueue cd = new TokenQueue(value);
String cookieName = cd.chompTo("=").trim();
String cookieVal = cd.consumeTo(";").trim();
// ignores path, date, domain, validateTLSCertificates et al. req'd?
// name not blank, value not null
if (cookieName.length() > 0)
cookie(cookieName, cookieVal);
}
} else { // combine same header names with comma: http://www.w3.org/Protocols/rfc2616/rfc2616-sec4.html#sec4.2
if (!values.isEmpty())
header(name, values.get(0));
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
120 | 5ded3cd8794e39baf3dc969862eb1dcdb28bcb5b90a83a962058c2f9d7cf4afd | boolean isAssignedOnceInLifetime() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* @return Whether the variable is only assigned a value once for its
* lifetime.
*/
boolean isAssignedOnceInLifetime() {
Reference ref = getOneAndOnlyAssignment();
if (ref == null) {
return false;
}
// Make sure this assignment is not in a loop.
for (BasicBlock block = ref.getBasicBlock();
block != null; block = block.getParent()) {
if (block.isFunction) {
if (ref.getSymbol().getScope() != ref.scope) {
return false;
}
break;
} else if (block.isLoop) {
return false;
}
}
return true;
}
```
| boolean isAssignedOnceInLifetime() {
Reference ref = getOneAndOnlyAssignment();
if (ref == null) {
return false;
}
// Make sure this assignment is not in a loop.
for (BasicBlock block = ref.getBasicBlock();
block != null; block = block.getParent()) {
if (block.isFunction) {
if (ref.getSymbol().getScope() != ref.scope) {
return false;
}
break;
} else if (block.isLoop) {
return false;
}
}
return true;
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* @return Whether the variable is only assigned a value once for its
* lifetime.
*/
boolean isAssignedOnceInLifetime() {
Reference ref = getOneAndOnlyAssignment();
if (ref == null) {
return false;
}
// Make sure this assignment is not in a loop.
for (BasicBlock block = ref.getBasicBlock();
block != null; block = block.getParent()) {
if (block.isFunction) {
if (ref.getSymbol().getScope() != ref.scope) {
return false;
}
break;
} else if (block.isLoop) {
return false;
}
}
return true;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
39 | 5e594f85d4eb7af44459315fb8f22e97705d40491663ec2aa37e75594a5fab8d | @Override
public void integrate(final ExpandableStatefulODE equations, final double t)
throws MathIllegalStateException, MathIllegalArgumentException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/** {@inheritDoc} */
@Override
public void integrate(final ExpandableStatefulODE equations, final double t)
throws MathIllegalStateException, MathIllegalArgumentException {
sanityChecks(equations, t);
setEquations(equations);
final boolean forward = t > equations.getTime();
// create some internal working arrays
final double[] y0 = equations.getCompleteState();
final double[] y = y0.clone();
final int stages = c.length + 1;
final double[][] yDotK = new double[stages][y.length];
final double[] yTmp = y0.clone();
final double[] yDotTmp = new double[y.length];
// set up an interpolator sharing the integrator arrays
final RungeKuttaStepInterpolator interpolator = (RungeKuttaStepInterpolator) prototype.copy();
interpolator.reinitialize(this, yTmp, yDotK, forward,
equations.getPrimaryMapper(), equations.getSecondaryMappers());
interpolator.storeTime(equations.getTime());
// set up integration control objects
stepStart = equations.getTime();
double hNew = 0;
boolean firstTime = true;
initIntegration(equations.getTime(), y0, t);
// main integration loop
isLastStep = false;
do {
interpolator.shift();
// iterate over step size, ensuring local normalized error is smaller than 1
double error = 10;
while (error >= 1.0) {
if (firstTime || !fsal) {
// first stage
computeDerivatives(stepStart, y, yDotK[0]);
}
if (firstTime) {
final double[] scale = new double[mainSetDimension];
if (vecAbsoluteTolerance == null) {
for (int i = 0; i < scale.length; ++i) {
scale[i] = scalAbsoluteTolerance + scalRelativeTolerance * FastMath.abs(y[i]);
}
} else {
for (int i = 0; i < scale.length; ++i) {
scale[i] = vecAbsoluteTolerance[i] + vecRelativeTolerance[i] * FastMath.abs(y[i]);
}
}
hNew = initializeStep(forward, getOrder(), scale,
stepStart, y, yDotK[0], yTmp, yDotK[1]);
firstTime = false;
}
stepSize = hNew;
if (forward) {
if (stepStart + stepSize >= t) {
stepSize = t - stepStart;
}
} else {
if (stepStart + stepSize <= t) {
stepSize = t - stepStart;
}
}
// next stages
for (int k = 1; k < stages; ++k) {
for (int j = 0; j < y0.length; ++j) {
double sum = a[k-1][0] * yDotK[0][j];
for (int l = 1; l < k; ++l) {
sum += a[k-1][l] * yDotK[l][j];
}
yTmp[j] = y[j] + stepSize * sum;
}
computeDerivatives(stepStart + c[k-1] * stepSize, yTmp, yDotK[k]);
}
// estimate the state at the end of the step
for (int j = 0; j < y0.length; ++j) {
double sum = b[0] * yDotK[0][j];
for (int l = 1; l < stages; ++l) {
sum += b[l] * yDotK[l][j];
}
yTmp[j] = y[j] + stepSize * sum;
}
// estimate the error at the end of the step
error = estimateError(yDotK, y, yTmp, stepSize);
if (error >= 1.0) {
// reject the step and attempt to reduce error by stepsize control
final double factor =
FastMath.min(maxGrowth,
FastMath.max(minReduction, safety * FastMath.pow(error, exp)));
hNew = filterStep(stepSize * factor, forward, false);
}
}
// local error is small enough: accept the step, trigger events and step handlers
interpolator.storeTime(stepStart + stepSize);
System.arraycopy(yTmp, 0, y, 0, y0.length);
System.arraycopy(yDotK[stages - 1], 0, yDotTmp, 0, y0.length);
stepStart = acceptStep(interpolator, y, yDotTmp, t);
System.arraycopy(y, 0, yTmp, 0, y.length);
if (!isLastStep) {
// prepare next step
interpolator.storeTime(stepStart);
if (fsal) {
// save the last evaluation for the next step
System.arraycopy(yDotTmp, 0, yDotK[0], 0, y0.length);
}
// stepsize control for next step
final double factor =
FastMath.min(maxGrowth, FastMath.max(minReduction, safety * FastMath.pow(error, exp)));
final double scaledH = stepSize * factor;
final double nextT = stepStart + scaledH;
final boolean nextIsLast = forward ? (nextT >= t) : (nextT <= t);
hNew = filterStep(scaledH, forward, nextIsLast);
final double filteredNextT = stepStart + hNew;
final boolean filteredNextIsLast = forward ? (filteredNextT >= t) : (filteredNextT <= t);
if (filteredNextIsLast) {
hNew = t - stepStart;
}
}
} while (!isLastStep);
// dispatch results
equations.setTime(stepStart);
equations.setCompleteState(y);
resetInternalState();
}
```
| @Override
public void integrate(final ExpandableStatefulODE equations, final double t)
throws MathIllegalStateException, MathIllegalArgumentException {
sanityChecks(equations, t);
setEquations(equations);
final boolean forward = t > equations.getTime();
// create some internal working arrays
final double[] y0 = equations.getCompleteState();
final double[] y = y0.clone();
final int stages = c.length + 1;
final double[][] yDotK = new double[stages][y.length];
final double[] yTmp = y0.clone();
final double[] yDotTmp = new double[y.length];
// set up an interpolator sharing the integrator arrays
final RungeKuttaStepInterpolator interpolator = (RungeKuttaStepInterpolator) prototype.copy();
interpolator.reinitialize(this, yTmp, yDotK, forward,
equations.getPrimaryMapper(), equations.getSecondaryMappers());
interpolator.storeTime(equations.getTime());
// set up integration control objects
stepStart = equations.getTime();
double hNew = 0;
boolean firstTime = true;
initIntegration(equations.getTime(), y0, t);
// main integration loop
isLastStep = false;
do {
interpolator.shift();
// iterate over step size, ensuring local normalized error is smaller than 1
double error = 10;
while (error >= 1.0) {
if (firstTime || !fsal) {
// first stage
computeDerivatives(stepStart, y, yDotK[0]);
}
if (firstTime) {
final double[] scale = new double[mainSetDimension];
if (vecAbsoluteTolerance == null) {
for (int i = 0; i < scale.length; ++i) {
scale[i] = scalAbsoluteTolerance + scalRelativeTolerance * FastMath.abs(y[i]);
}
} else {
for (int i = 0; i < scale.length; ++i) {
scale[i] = vecAbsoluteTolerance[i] + vecRelativeTolerance[i] * FastMath.abs(y[i]);
}
}
hNew = initializeStep(forward, getOrder(), scale,
stepStart, y, yDotK[0], yTmp, yDotK[1]);
firstTime = false;
}
stepSize = hNew;
if (forward) {
if (stepStart + stepSize >= t) {
stepSize = t - stepStart;
}
} else {
if (stepStart + stepSize <= t) {
stepSize = t - stepStart;
}
}
// next stages
for (int k = 1; k < stages; ++k) {
for (int j = 0; j < y0.length; ++j) {
double sum = a[k-1][0] * yDotK[0][j];
for (int l = 1; l < k; ++l) {
sum += a[k-1][l] * yDotK[l][j];
}
yTmp[j] = y[j] + stepSize * sum;
}
computeDerivatives(stepStart + c[k-1] * stepSize, yTmp, yDotK[k]);
}
// estimate the state at the end of the step
for (int j = 0; j < y0.length; ++j) {
double sum = b[0] * yDotK[0][j];
for (int l = 1; l < stages; ++l) {
sum += b[l] * yDotK[l][j];
}
yTmp[j] = y[j] + stepSize * sum;
}
// estimate the error at the end of the step
error = estimateError(yDotK, y, yTmp, stepSize);
if (error >= 1.0) {
// reject the step and attempt to reduce error by stepsize control
final double factor =
FastMath.min(maxGrowth,
FastMath.max(minReduction, safety * FastMath.pow(error, exp)));
hNew = filterStep(stepSize * factor, forward, false);
}
}
// local error is small enough: accept the step, trigger events and step handlers
interpolator.storeTime(stepStart + stepSize);
System.arraycopy(yTmp, 0, y, 0, y0.length);
System.arraycopy(yDotK[stages - 1], 0, yDotTmp, 0, y0.length);
stepStart = acceptStep(interpolator, y, yDotTmp, t);
System.arraycopy(y, 0, yTmp, 0, y.length);
if (!isLastStep) {
// prepare next step
interpolator.storeTime(stepStart);
if (fsal) {
// save the last evaluation for the next step
System.arraycopy(yDotTmp, 0, yDotK[0], 0, y0.length);
}
// stepsize control for next step
final double factor =
FastMath.min(maxGrowth, FastMath.max(minReduction, safety * FastMath.pow(error, exp)));
final double scaledH = stepSize * factor;
final double nextT = stepStart + scaledH;
final boolean nextIsLast = forward ? (nextT >= t) : (nextT <= t);
hNew = filterStep(scaledH, forward, nextIsLast);
final double filteredNextT = stepStart + hNew;
final boolean filteredNextIsLast = forward ? (filteredNextT >= t) : (filteredNextT <= t);
if (filteredNextIsLast) {
hNew = t - stepStart;
}
}
} while (!isLastStep);
// dispatch results
equations.setTime(stepStart);
equations.setCompleteState(y);
resetInternalState();
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/** {@inheritDoc} */
@Override
public void integrate(final ExpandableStatefulODE equations, final double t)
throws MathIllegalStateException, MathIllegalArgumentException {
sanityChecks(equations, t);
setEquations(equations);
final boolean forward = t > equations.getTime();
// create some internal working arrays
final double[] y0 = equations.getCompleteState();
final double[] y = y0.clone();
final int stages = c.length + 1;
final double[][] yDotK = new double[stages][y.length];
final double[] yTmp = y0.clone();
final double[] yDotTmp = new double[y.length];
// set up an interpolator sharing the integrator arrays
final RungeKuttaStepInterpolator interpolator = (RungeKuttaStepInterpolator) prototype.copy();
interpolator.reinitialize(this, yTmp, yDotK, forward,
equations.getPrimaryMapper(), equations.getSecondaryMappers());
interpolator.storeTime(equations.getTime());
// set up integration control objects
stepStart = equations.getTime();
double hNew = 0;
boolean firstTime = true;
initIntegration(equations.getTime(), y0, t);
// main integration loop
isLastStep = false;
do {
interpolator.shift();
// iterate over step size, ensuring local normalized error is smaller than 1
double error = 10;
while (error >= 1.0) {
if (firstTime || !fsal) {
// first stage
computeDerivatives(stepStart, y, yDotK[0]);
}
if (firstTime) {
final double[] scale = new double[mainSetDimension];
if (vecAbsoluteTolerance == null) {
for (int i = 0; i < scale.length; ++i) {
scale[i] = scalAbsoluteTolerance + scalRelativeTolerance * FastMath.abs(y[i]);
}
} else {
for (int i = 0; i < scale.length; ++i) {
scale[i] = vecAbsoluteTolerance[i] + vecRelativeTolerance[i] * FastMath.abs(y[i]);
}
}
hNew = initializeStep(forward, getOrder(), scale,
stepStart, y, yDotK[0], yTmp, yDotK[1]);
firstTime = false;
}
stepSize = hNew;
if (forward) {
if (stepStart + stepSize >= t) {
stepSize = t - stepStart;
}
} else {
if (stepStart + stepSize <= t) {
stepSize = t - stepStart;
}
}
// next stages
for (int k = 1; k < stages; ++k) {
for (int j = 0; j < y0.length; ++j) {
double sum = a[k-1][0] * yDotK[0][j];
for (int l = 1; l < k; ++l) {
sum += a[k-1][l] * yDotK[l][j];
}
yTmp[j] = y[j] + stepSize * sum;
}
computeDerivatives(stepStart + c[k-1] * stepSize, yTmp, yDotK[k]);
}
// estimate the state at the end of the step
for (int j = 0; j < y0.length; ++j) {
double sum = b[0] * yDotK[0][j];
for (int l = 1; l < stages; ++l) {
sum += b[l] * yDotK[l][j];
}
yTmp[j] = y[j] + stepSize * sum;
}
// estimate the error at the end of the step
error = estimateError(yDotK, y, yTmp, stepSize);
if (error >= 1.0) {
// reject the step and attempt to reduce error by stepsize control
final double factor =
FastMath.min(maxGrowth,
FastMath.max(minReduction, safety * FastMath.pow(error, exp)));
hNew = filterStep(stepSize * factor, forward, false);
}
}
// local error is small enough: accept the step, trigger events and step handlers
interpolator.storeTime(stepStart + stepSize);
System.arraycopy(yTmp, 0, y, 0, y0.length);
System.arraycopy(yDotK[stages - 1], 0, yDotTmp, 0, y0.length);
stepStart = acceptStep(interpolator, y, yDotTmp, t);
System.arraycopy(y, 0, yTmp, 0, y.length);
if (!isLastStep) {
// prepare next step
interpolator.storeTime(stepStart);
if (fsal) {
// save the last evaluation for the next step
System.arraycopy(yDotTmp, 0, yDotK[0], 0, y0.length);
}
// stepsize control for next step
final double factor =
FastMath.min(maxGrowth, FastMath.max(minReduction, safety * FastMath.pow(error, exp)));
final double scaledH = stepSize * factor;
final double nextT = stepStart + scaledH;
final boolean nextIsLast = forward ? (nextT >= t) : (nextT <= t);
hNew = filterStep(scaledH, forward, nextIsLast);
final double filteredNextT = stepStart + hNew;
final boolean filteredNextIsLast = forward ? (filteredNextT >= t) : (filteredNextT <= t);
if (filteredNextIsLast) {
hNew = t - stepStart;
}
}
} while (!isLastStep);
// dispatch results
equations.setTime(stepStart);
equations.setCompleteState(y);
resetInternalState();
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
91 | 5ede8b554f416ab7e23729be8fa30ef0564985c4d4bff1f9c4589bc99b641bd6 | public int compareTo(Fraction object) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Compares this object to another based on size.
* @param object the object to compare to
* @return -1 if this is less than <tt>object</tt>, +1 if this is greater
* than <tt>object</tt>, 0 if they are equal.
*/
public int compareTo(Fraction object) {
double nOd = doubleValue();
double dOn = object.doubleValue();
return (nOd < dOn) ? -1 : ((nOd > dOn) ? +1 : 0);
}
```
| public int compareTo(Fraction object) {
double nOd = doubleValue();
double dOn = object.doubleValue();
return (nOd < dOn) ? -1 : ((nOd > dOn) ? +1 : 0);
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Compares this object to another based on size.
* @param object the object to compare to
* @return -1 if this is less than <tt>object</tt>, +1 if this is greater
* than <tt>object</tt>, 0 if they are equal.
*/
public int compareTo(Fraction object) {
double nOd = doubleValue();
double dOn = object.doubleValue();
return (nOd < dOn) ? -1 : ((nOd > dOn) ? +1 : 0);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
25 | 5f0c4e6828c04378e0c542261cb9ad8b5ed0e80ee3b83a1a861043b52df58d5f | private void guessAOmega() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Estimate a first guess of the amplitude and angular frequency.
* This method assumes that the {@link #sortObservations()} method
* has been called previously.
*
* @throws ZeroException if the abscissa range is zero.
* @throws MathIllegalStateException when the guessing procedure cannot
* produce sensible results.
*/
private void guessAOmega() {
// initialize the sums for the linear model between the two integrals
double sx2 = 0;
double sy2 = 0;
double sxy = 0;
double sxz = 0;
double syz = 0;
double currentX = observations[0].getX();
double currentY = observations[0].getY();
double f2Integral = 0;
double fPrime2Integral = 0;
final double startX = currentX;
for (int i = 1; i < observations.length; ++i) {
// one step forward
final double previousX = currentX;
final double previousY = currentY;
currentX = observations[i].getX();
currentY = observations[i].getY();
// update the integrals of f<sup>2</sup> and f'<sup>2</sup>
// considering a linear model for f (and therefore constant f')
final double dx = currentX - previousX;
final double dy = currentY - previousY;
final double f2StepIntegral =
dx * (previousY * previousY + previousY * currentY + currentY * currentY) / 3;
final double fPrime2StepIntegral = dy * dy / dx;
final double x = currentX - startX;
f2Integral += f2StepIntegral;
fPrime2Integral += fPrime2StepIntegral;
sx2 += x * x;
sy2 += f2Integral * f2Integral;
sxy += x * f2Integral;
sxz += x * fPrime2Integral;
syz += f2Integral * fPrime2Integral;
}
// compute the amplitude and pulsation coefficients
double c1 = sy2 * sxz - sxy * syz;
double c2 = sxy * sxz - sx2 * syz;
double c3 = sx2 * sy2 - sxy * sxy;
if ((c1 / c2 < 0) || (c2 / c3 < 0)) {
final int last = observations.length - 1;
// Range of the observations, assuming that the
// observations are sorted.
final double xRange = observations[last].getX() - observations[0].getX();
if (xRange == 0) {
throw new ZeroException();
}
omega = 2 * Math.PI / xRange;
double yMin = Double.POSITIVE_INFINITY;
double yMax = Double.NEGATIVE_INFINITY;
for (int i = 1; i < observations.length; ++i) {
final double y = observations[i].getY();
if (y < yMin) {
yMin = y;
}
if (y > yMax) {
yMax = y;
}
}
a = 0.5 * (yMax - yMin);
} else {
if (c2 == 0) {
// In some ill-conditioned cases (cf. MATH-844), the guesser
// procedure cannot produce sensible results.
throw new MathIllegalStateException(LocalizedFormats.ZERO_DENOMINATOR);
}
a = FastMath.sqrt(c1 / c2);
omega = FastMath.sqrt(c2 / c3);
}
}
```
| private void guessAOmega() {
// initialize the sums for the linear model between the two integrals
double sx2 = 0;
double sy2 = 0;
double sxy = 0;
double sxz = 0;
double syz = 0;
double currentX = observations[0].getX();
double currentY = observations[0].getY();
double f2Integral = 0;
double fPrime2Integral = 0;
final double startX = currentX;
for (int i = 1; i < observations.length; ++i) {
// one step forward
final double previousX = currentX;
final double previousY = currentY;
currentX = observations[i].getX();
currentY = observations[i].getY();
// update the integrals of f<sup>2</sup> and f'<sup>2</sup>
// considering a linear model for f (and therefore constant f')
final double dx = currentX - previousX;
final double dy = currentY - previousY;
final double f2StepIntegral =
dx * (previousY * previousY + previousY * currentY + currentY * currentY) / 3;
final double fPrime2StepIntegral = dy * dy / dx;
final double x = currentX - startX;
f2Integral += f2StepIntegral;
fPrime2Integral += fPrime2StepIntegral;
sx2 += x * x;
sy2 += f2Integral * f2Integral;
sxy += x * f2Integral;
sxz += x * fPrime2Integral;
syz += f2Integral * fPrime2Integral;
}
// compute the amplitude and pulsation coefficients
double c1 = sy2 * sxz - sxy * syz;
double c2 = sxy * sxz - sx2 * syz;
double c3 = sx2 * sy2 - sxy * sxy;
if ((c1 / c2 < 0) || (c2 / c3 < 0)) {
final int last = observations.length - 1;
// Range of the observations, assuming that the
// observations are sorted.
final double xRange = observations[last].getX() - observations[0].getX();
if (xRange == 0) {
throw new ZeroException();
}
omega = 2 * Math.PI / xRange;
double yMin = Double.POSITIVE_INFINITY;
double yMax = Double.NEGATIVE_INFINITY;
for (int i = 1; i < observations.length; ++i) {
final double y = observations[i].getY();
if (y < yMin) {
yMin = y;
}
if (y > yMax) {
yMax = y;
}
}
a = 0.5 * (yMax - yMin);
} else {
if (c2 == 0) {
// In some ill-conditioned cases (cf. MATH-844), the guesser
// procedure cannot produce sensible results.
throw new MathIllegalStateException(LocalizedFormats.ZERO_DENOMINATOR);
}
a = FastMath.sqrt(c1 / c2);
omega = FastMath.sqrt(c2 / c3);
}
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Estimate a first guess of the amplitude and angular frequency.
* This method assumes that the {@link #sortObservations()} method
* has been called previously.
*
* @throws ZeroException if the abscissa range is zero.
* @throws MathIllegalStateException when the guessing procedure cannot
* produce sensible results.
*/
private void guessAOmega() {
// initialize the sums for the linear model between the two integrals
double sx2 = 0;
double sy2 = 0;
double sxy = 0;
double sxz = 0;
double syz = 0;
double currentX = observations[0].getX();
double currentY = observations[0].getY();
double f2Integral = 0;
double fPrime2Integral = 0;
final double startX = currentX;
for (int i = 1; i < observations.length; ++i) {
// one step forward
final double previousX = currentX;
final double previousY = currentY;
currentX = observations[i].getX();
currentY = observations[i].getY();
// update the integrals of f<sup>2</sup> and f'<sup>2</sup>
// considering a linear model for f (and therefore constant f')
final double dx = currentX - previousX;
final double dy = currentY - previousY;
final double f2StepIntegral =
dx * (previousY * previousY + previousY * currentY + currentY * currentY) / 3;
final double fPrime2StepIntegral = dy * dy / dx;
final double x = currentX - startX;
f2Integral += f2StepIntegral;
fPrime2Integral += fPrime2StepIntegral;
sx2 += x * x;
sy2 += f2Integral * f2Integral;
sxy += x * f2Integral;
sxz += x * fPrime2Integral;
syz += f2Integral * fPrime2Integral;
}
// compute the amplitude and pulsation coefficients
double c1 = sy2 * sxz - sxy * syz;
double c2 = sxy * sxz - sx2 * syz;
double c3 = sx2 * sy2 - sxy * sxy;
if ((c1 / c2 < 0) || (c2 / c3 < 0)) {
final int last = observations.length - 1;
// Range of the observations, assuming that the
// observations are sorted.
final double xRange = observations[last].getX() - observations[0].getX();
if (xRange == 0) {
throw new ZeroException();
}
omega = 2 * Math.PI / xRange;
double yMin = Double.POSITIVE_INFINITY;
double yMax = Double.NEGATIVE_INFINITY;
for (int i = 1; i < observations.length; ++i) {
final double y = observations[i].getY();
if (y < yMin) {
yMin = y;
}
if (y > yMax) {
yMax = y;
}
}
a = 0.5 * (yMax - yMin);
} else {
if (c2 == 0) {
// In some ill-conditioned cases (cf. MATH-844), the guesser
// procedure cannot produce sensible results.
throw new MathIllegalStateException(LocalizedFormats.ZERO_DENOMINATOR);
}
a = FastMath.sqrt(c1 / c2);
omega = FastMath.sqrt(c2 / c3);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
5 | 5fc37335db2dcd69da0859e57345d23abf4397f96923da91e23208d92ea77b7d | void decode(byte[] in, int inPos, int inAvail) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>
* Decodes all of the provided data, starting at inPos, for inAvail bytes. Should be called at least twice: once
* with the data to decode, and once with inAvail set to "-1" to alert decoder that EOF has been reached. The "-1"
* call is not necessary when decoding, but it doesn't hurt, either.
* </p>
* <p>
* Ignores all non-base64 characters. This is how chunked (e.g. 76 character) data is handled, since CR and LF are
* silently ignored, but has implications for other bytes, too. This method subscribes to the garbage-in,
* garbage-out philosophy: it will not check the provided data for validity.
* </p>
* <p>
* Thanks to "commons" project in ws.apache.org for the bitwise operations, and general approach.
* http://svn.apache.org/repos/asf/webservices/commons/trunk/modules/util/
* </p>
*
* @param in
* byte[] array of ascii data to base64 decode.
* @param inPos
* Position to start reading data from.
* @param inAvail
* Amount of bytes available from input for encoding.
*/
void decode(byte[] in, int inPos, int inAvail) {
if (eof) {
return;
}
if (inAvail < 0) {
eof = true;
}
for (int i = 0; i < inAvail; i++) {
if (buffer == null || buffer.length - pos < decodeSize) {
resizeBuffer();
}
byte b = in[inPos++];
if (b == PAD) {
// We're done.
eof = true;
break;
} else {
if (b >= 0 && b < DECODE_TABLE.length) {
int result = DECODE_TABLE[b];
if (result >= 0) {
modulus = (++modulus) % 4;
x = (x << 6) + result;
if (modulus == 0) {
buffer[pos++] = (byte) ((x >> 16) & MASK_8BITS);
buffer[pos++] = (byte) ((x >> 8) & MASK_8BITS);
buffer[pos++] = (byte) (x & MASK_8BITS);
}
}
}
}
}
// Two forms of EOF as far as base64 decoder is concerned: actual
// EOF (-1) and first time '=' character is encountered in stream.
// This approach makes the '=' padding characters completely optional.
if (eof && modulus != 0) {
if (buffer == null || buffer.length - pos < decodeSize) {
resizeBuffer();
}
x = x << 6;
switch (modulus) {
case 2 :
x = x << 6;
buffer[pos++] = (byte) ((x >> 16) & MASK_8BITS);
break;
case 3 :
buffer[pos++] = (byte) ((x >> 16) & MASK_8BITS);
buffer[pos++] = (byte) ((x >> 8) & MASK_8BITS);
break;
}
}
}
```
| void decode(byte[] in, int inPos, int inAvail) {
if (eof) {
return;
}
if (inAvail < 0) {
eof = true;
}
for (int i = 0; i < inAvail; i++) {
if (buffer == null || buffer.length - pos < decodeSize) {
resizeBuffer();
}
byte b = in[inPos++];
if (b == PAD) {
// We're done.
eof = true;
break;
} else {
if (b >= 0 && b < DECODE_TABLE.length) {
int result = DECODE_TABLE[b];
if (result >= 0) {
modulus = (++modulus) % 4;
x = (x << 6) + result;
if (modulus == 0) {
buffer[pos++] = (byte) ((x >> 16) & MASK_8BITS);
buffer[pos++] = (byte) ((x >> 8) & MASK_8BITS);
buffer[pos++] = (byte) (x & MASK_8BITS);
}
}
}
}
}
// Two forms of EOF as far as base64 decoder is concerned: actual
// EOF (-1) and first time '=' character is encountered in stream.
// This approach makes the '=' padding characters completely optional.
if (eof && modulus != 0) {
if (buffer == null || buffer.length - pos < decodeSize) {
resizeBuffer();
}
x = x << 6;
switch (modulus) {
case 2 :
x = x << 6;
buffer[pos++] = (byte) ((x >> 16) & MASK_8BITS);
break;
case 3 :
buffer[pos++] = (byte) ((x >> 16) & MASK_8BITS);
buffer[pos++] = (byte) ((x >> 8) & MASK_8BITS);
break;
}
}
} | false | Codec | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>
* Decodes all of the provided data, starting at inPos, for inAvail bytes. Should be called at least twice: once
* with the data to decode, and once with inAvail set to "-1" to alert decoder that EOF has been reached. The "-1"
* call is not necessary when decoding, but it doesn't hurt, either.
* </p>
* <p>
* Ignores all non-base64 characters. This is how chunked (e.g. 76 character) data is handled, since CR and LF are
* silently ignored, but has implications for other bytes, too. This method subscribes to the garbage-in,
* garbage-out philosophy: it will not check the provided data for validity.
* </p>
* <p>
* Thanks to "commons" project in ws.apache.org for the bitwise operations, and general approach.
* http://svn.apache.org/repos/asf/webservices/commons/trunk/modules/util/
* </p>
*
* @param in
* byte[] array of ascii data to base64 decode.
* @param inPos
* Position to start reading data from.
* @param inAvail
* Amount of bytes available from input for encoding.
*/
void decode(byte[] in, int inPos, int inAvail) {
if (eof) {
return;
}
if (inAvail < 0) {
eof = true;
}
for (int i = 0; i < inAvail; i++) {
if (buffer == null || buffer.length - pos < decodeSize) {
resizeBuffer();
}
byte b = in[inPos++];
if (b == PAD) {
// We're done.
eof = true;
break;
} else {
if (b >= 0 && b < DECODE_TABLE.length) {
int result = DECODE_TABLE[b];
if (result >= 0) {
modulus = (++modulus) % 4;
x = (x << 6) + result;
if (modulus == 0) {
buffer[pos++] = (byte) ((x >> 16) & MASK_8BITS);
buffer[pos++] = (byte) ((x >> 8) & MASK_8BITS);
buffer[pos++] = (byte) (x & MASK_8BITS);
}
}
}
}
}
// Two forms of EOF as far as base64 decoder is concerned: actual
// EOF (-1) and first time '=' character is encountered in stream.
// This approach makes the '=' padding characters completely optional.
if (eof && modulus != 0) {
if (buffer == null || buffer.length - pos < decodeSize) {
resizeBuffer();
}
x = x << 6;
switch (modulus) {
case 2 :
x = x << 6;
buffer[pos++] = (byte) ((x >> 16) & MASK_8BITS);
break;
case 3 :
buffer[pos++] = (byte) ((x >> 16) & MASK_8BITS);
buffer[pos++] = (byte) ((x >> 8) & MASK_8BITS);
break;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
25 | 600c37843e7185ce6b208590231a5821555ef433dc230aee1a40db9fe8a00708 | private FlowScope traverseNew(Node n, FlowScope scope) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private FlowScope traverseNew(Node n, FlowScope scope) {
Node constructor = n.getFirstChild();
scope = traverse(constructor, scope);
JSType constructorType = constructor.getJSType();
JSType type = null;
if (constructorType != null) {
constructorType = constructorType.restrictByNotNullOrUndefined();
if (constructorType.isUnknownType()) {
type = getNativeType(UNKNOWN_TYPE);
} else {
FunctionType ct = constructorType.toMaybeFunctionType();
if (ct == null && constructorType instanceof FunctionType) {
// If constructorType is a NoObjectType, then toMaybeFunctionType will
// return null. But NoObjectType implements the FunctionType
// interface, precisely because it can validly construct objects.
ct = (FunctionType) constructorType;
}
if (ct != null && ct.isConstructor()) {
type = ct.getInstanceType();
}
}
}
n.setJSType(type);
for (Node arg = constructor.getNext(); arg != null; arg = arg.getNext()) {
scope = traverse(arg, scope);
}
return scope;
}
```
| private FlowScope traverseNew(Node n, FlowScope scope) {
Node constructor = n.getFirstChild();
scope = traverse(constructor, scope);
JSType constructorType = constructor.getJSType();
JSType type = null;
if (constructorType != null) {
constructorType = constructorType.restrictByNotNullOrUndefined();
if (constructorType.isUnknownType()) {
type = getNativeType(UNKNOWN_TYPE);
} else {
FunctionType ct = constructorType.toMaybeFunctionType();
if (ct == null && constructorType instanceof FunctionType) {
// If constructorType is a NoObjectType, then toMaybeFunctionType will
// return null. But NoObjectType implements the FunctionType
// interface, precisely because it can validly construct objects.
ct = (FunctionType) constructorType;
}
if (ct != null && ct.isConstructor()) {
type = ct.getInstanceType();
}
}
}
n.setJSType(type);
for (Node arg = constructor.getNext(); arg != null; arg = arg.getNext()) {
scope = traverse(arg, scope);
}
return scope;
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private FlowScope traverseNew(Node n, FlowScope scope) {
Node constructor = n.getFirstChild();
scope = traverse(constructor, scope);
JSType constructorType = constructor.getJSType();
JSType type = null;
if (constructorType != null) {
constructorType = constructorType.restrictByNotNullOrUndefined();
if (constructorType.isUnknownType()) {
type = getNativeType(UNKNOWN_TYPE);
} else {
FunctionType ct = constructorType.toMaybeFunctionType();
if (ct == null && constructorType instanceof FunctionType) {
// If constructorType is a NoObjectType, then toMaybeFunctionType will
// return null. But NoObjectType implements the FunctionType
// interface, precisely because it can validly construct objects.
ct = (FunctionType) constructorType;
}
if (ct != null && ct.isConstructor()) {
type = ct.getInstanceType();
}
}
}
n.setJSType(type);
for (Node arg = constructor.getNext(); arg != null; arg = arg.getNext()) {
scope = traverse(arg, scope);
}
return scope;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
125 | 602c4a2c367133e0d06f2344ac495a87916b942f50574ed1406282b17176f772 | private void visitNew(NodeTraversal t, Node n) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Visits a NEW node.
*/
private void visitNew(NodeTraversal t, Node n) {
Node constructor = n.getFirstChild();
JSType type = getJSType(constructor).restrictByNotNullOrUndefined();
if (type.isConstructor() || type.isEmptyType() || type.isUnknownType()) {
FunctionType fnType = type.toMaybeFunctionType();
if (fnType != null) {
visitParameterList(t, n, fnType);
ensureTyped(t, n, fnType.getInstanceType());
} else {
ensureTyped(t, n);
}
} else {
report(t, n, NOT_A_CONSTRUCTOR);
ensureTyped(t, n);
}
}
```
| private void visitNew(NodeTraversal t, Node n) {
Node constructor = n.getFirstChild();
JSType type = getJSType(constructor).restrictByNotNullOrUndefined();
if (type.isConstructor() || type.isEmptyType() || type.isUnknownType()) {
FunctionType fnType = type.toMaybeFunctionType();
if (fnType != null) {
visitParameterList(t, n, fnType);
ensureTyped(t, n, fnType.getInstanceType());
} else {
ensureTyped(t, n);
}
} else {
report(t, n, NOT_A_CONSTRUCTOR);
ensureTyped(t, n);
}
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Visits a NEW node.
*/
private void visitNew(NodeTraversal t, Node n) {
Node constructor = n.getFirstChild();
JSType type = getJSType(constructor).restrictByNotNullOrUndefined();
if (type.isConstructor() || type.isEmptyType() || type.isUnknownType()) {
FunctionType fnType = type.toMaybeFunctionType();
if (fnType != null) {
visitParameterList(t, n, fnType);
ensureTyped(t, n, fnType.getInstanceType());
} else {
ensureTyped(t, n);
}
} else {
report(t, n, NOT_A_CONSTRUCTOR);
ensureTyped(t, n);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
101 | 6042db12e247f278f75268601339fc9c84a07cf52a8f766e53c694bbb3ececb4 | public Complex parse(String source, ParsePosition pos) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Parses a string to produce a {@link Complex} object.
*
* @param source the string to parse
* @param pos input/ouput parsing parameter.
* @return the parsed {@link Complex} object.
*/
public Complex parse(String source, ParsePosition pos) {
int initialIndex = pos.getIndex();
// parse whitespace
parseAndIgnoreWhitespace(source, pos);
// parse real
Number re = parseNumber(source, getRealFormat(), pos);
if (re == null) {
// invalid real number
// set index back to initial, error index should already be set
// character examined.
pos.setIndex(initialIndex);
return null;
}
// parse sign
int startIndex = pos.getIndex();
char c = parseNextCharacter(source, pos);
int sign = 0;
switch (c) {
case 0 :
// no sign
// return real only complex number
return new Complex(re.doubleValue(), 0.0);
case '-' :
sign = -1;
break;
case '+' :
sign = 1;
break;
default :
// invalid sign
// set index back to initial, error index should be the last
// character examined.
pos.setIndex(initialIndex);
pos.setErrorIndex(startIndex);
return null;
}
// parse whitespace
parseAndIgnoreWhitespace(source, pos);
// parse imaginary
Number im = parseNumber(source, getRealFormat(), pos);
if (im == null) {
// invalid imaginary number
// set index back to initial, error index should already be set
// character examined.
pos.setIndex(initialIndex);
return null;
}
// parse imaginary character
int n = getImaginaryCharacter().length();
startIndex = pos.getIndex();
int endIndex = startIndex + n;
if ((startIndex >= source.length()) ||
(endIndex > source.length()) ||
source.substring(startIndex, endIndex).compareTo(
getImaginaryCharacter()) != 0) {
// set index back to initial, error index should be the start index
// character examined.
pos.setIndex(initialIndex);
pos.setErrorIndex(startIndex);
return null;
}
pos.setIndex(endIndex);
return new Complex(re.doubleValue(), im.doubleValue() * sign);
}
```
| public Complex parse(String source, ParsePosition pos) {
int initialIndex = pos.getIndex();
// parse whitespace
parseAndIgnoreWhitespace(source, pos);
// parse real
Number re = parseNumber(source, getRealFormat(), pos);
if (re == null) {
// invalid real number
// set index back to initial, error index should already be set
// character examined.
pos.setIndex(initialIndex);
return null;
}
// parse sign
int startIndex = pos.getIndex();
char c = parseNextCharacter(source, pos);
int sign = 0;
switch (c) {
case 0 :
// no sign
// return real only complex number
return new Complex(re.doubleValue(), 0.0);
case '-' :
sign = -1;
break;
case '+' :
sign = 1;
break;
default :
// invalid sign
// set index back to initial, error index should be the last
// character examined.
pos.setIndex(initialIndex);
pos.setErrorIndex(startIndex);
return null;
}
// parse whitespace
parseAndIgnoreWhitespace(source, pos);
// parse imaginary
Number im = parseNumber(source, getRealFormat(), pos);
if (im == null) {
// invalid imaginary number
// set index back to initial, error index should already be set
// character examined.
pos.setIndex(initialIndex);
return null;
}
// parse imaginary character
int n = getImaginaryCharacter().length();
startIndex = pos.getIndex();
int endIndex = startIndex + n;
if ((startIndex >= source.length()) ||
(endIndex > source.length()) ||
source.substring(startIndex, endIndex).compareTo(
getImaginaryCharacter()) != 0) {
// set index back to initial, error index should be the start index
// character examined.
pos.setIndex(initialIndex);
pos.setErrorIndex(startIndex);
return null;
}
pos.setIndex(endIndex);
return new Complex(re.doubleValue(), im.doubleValue() * sign);
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Parses a string to produce a {@link Complex} object.
*
* @param source the string to parse
* @param pos input/ouput parsing parameter.
* @return the parsed {@link Complex} object.
*/
public Complex parse(String source, ParsePosition pos) {
int initialIndex = pos.getIndex();
// parse whitespace
parseAndIgnoreWhitespace(source, pos);
// parse real
Number re = parseNumber(source, getRealFormat(), pos);
if (re == null) {
// invalid real number
// set index back to initial, error index should already be set
// character examined.
pos.setIndex(initialIndex);
return null;
}
// parse sign
int startIndex = pos.getIndex();
char c = parseNextCharacter(source, pos);
int sign = 0;
switch (c) {
case 0 :
// no sign
// return real only complex number
return new Complex(re.doubleValue(), 0.0);
case '-' :
sign = -1;
break;
case '+' :
sign = 1;
break;
default :
// invalid sign
// set index back to initial, error index should be the last
// character examined.
pos.setIndex(initialIndex);
pos.setErrorIndex(startIndex);
return null;
}
// parse whitespace
parseAndIgnoreWhitespace(source, pos);
// parse imaginary
Number im = parseNumber(source, getRealFormat(), pos);
if (im == null) {
// invalid imaginary number
// set index back to initial, error index should already be set
// character examined.
pos.setIndex(initialIndex);
return null;
}
// parse imaginary character
int n = getImaginaryCharacter().length();
startIndex = pos.getIndex();
int endIndex = startIndex + n;
if ((startIndex >= source.length()) ||
(endIndex > source.length()) ||
source.substring(startIndex, endIndex).compareTo(
getImaginaryCharacter()) != 0) {
// set index back to initial, error index should be the start index
// character examined.
pos.setIndex(initialIndex);
pos.setErrorIndex(startIndex);
return null;
}
pos.setIndex(endIndex);
return new Complex(re.doubleValue(), im.doubleValue() * sign);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
59 | 6060f86c5a2d0196255ddad05dc5787e9bc4f29134440b1509ef081ec32e40da | final void newAttribute() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
final void newAttribute() {
if (attributes == null)
attributes = new Attributes();
if (pendingAttributeName != null) {
// the tokeniser has skipped whitespace control chars, but trimming could collapse to empty for other control codes, so verify here
pendingAttributeName = pendingAttributeName.trim();
Attribute attribute;
if (hasPendingAttributeValue)
attribute = new Attribute(pendingAttributeName,
pendingAttributeValue.length() > 0 ? pendingAttributeValue.toString() : pendingAttributeValueS);
else if (hasEmptyAttributeValue)
attribute = new Attribute(pendingAttributeName, "");
else
attribute = new BooleanAttribute(pendingAttributeName);
attributes.put(attribute);
}
pendingAttributeName = null;
hasEmptyAttributeValue = false;
hasPendingAttributeValue = false;
reset(pendingAttributeValue);
pendingAttributeValueS = null;
}
```
| final void newAttribute() {
if (attributes == null)
attributes = new Attributes();
if (pendingAttributeName != null) {
// the tokeniser has skipped whitespace control chars, but trimming could collapse to empty for other control codes, so verify here
pendingAttributeName = pendingAttributeName.trim();
Attribute attribute;
if (hasPendingAttributeValue)
attribute = new Attribute(pendingAttributeName,
pendingAttributeValue.length() > 0 ? pendingAttributeValue.toString() : pendingAttributeValueS);
else if (hasEmptyAttributeValue)
attribute = new Attribute(pendingAttributeName, "");
else
attribute = new BooleanAttribute(pendingAttributeName);
attributes.put(attribute);
}
pendingAttributeName = null;
hasEmptyAttributeValue = false;
hasPendingAttributeValue = false;
reset(pendingAttributeValue);
pendingAttributeValueS = null;
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
final void newAttribute() {
if (attributes == null)
attributes = new Attributes();
if (pendingAttributeName != null) {
// the tokeniser has skipped whitespace control chars, but trimming could collapse to empty for other control codes, so verify here
pendingAttributeName = pendingAttributeName.trim();
Attribute attribute;
if (hasPendingAttributeValue)
attribute = new Attribute(pendingAttributeName,
pendingAttributeValue.length() > 0 ? pendingAttributeValue.toString() : pendingAttributeValueS);
else if (hasEmptyAttributeValue)
attribute = new Attribute(pendingAttributeName, "");
else
attribute = new BooleanAttribute(pendingAttributeName);
attributes.put(attribute);
}
pendingAttributeName = null;
hasEmptyAttributeValue = false;
hasPendingAttributeValue = false;
reset(pendingAttributeValue);
pendingAttributeValueS = null;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
5 | 608ff873170a33f4f1aae8235d95949feb125cd4b90e4fb558f693dabf70d6fe | private final static int _parseIndex(String str) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/*
/**********************************************************
/* Internal methods
/**********************************************************
*/
private final static int _parseIndex(String str) {
final int len = str.length();
// [Issue#133]: beware of super long indexes; assume we never
// have arrays over 2 billion entries so ints are fine.
if (len == 0 || len > 10) {
return -1;
}
for (int i = 0; i < len; ++i) {
char c = str.charAt(i);
if (c > '9' || c < '0') {
return -1;
}
}
if (len == 10) {
long l = NumberInput.parseLong(str);
if (l > Integer.MAX_VALUE) {
return -1;
}
}
return NumberInput.parseInt(str);
}
```
| private final static int _parseIndex(String str) {
final int len = str.length();
// [Issue#133]: beware of super long indexes; assume we never
// have arrays over 2 billion entries so ints are fine.
if (len == 0 || len > 10) {
return -1;
}
for (int i = 0; i < len; ++i) {
char c = str.charAt(i);
if (c > '9' || c < '0') {
return -1;
}
}
if (len == 10) {
long l = NumberInput.parseLong(str);
if (l > Integer.MAX_VALUE) {
return -1;
}
}
return NumberInput.parseInt(str);
} | false | JacksonCore | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/*
/**********************************************************
/* Internal methods
/**********************************************************
*/
private final static int _parseIndex(String str) {
final int len = str.length();
// [Issue#133]: beware of super long indexes; assume we never
// have arrays over 2 billion entries so ints are fine.
if (len == 0 || len > 10) {
return -1;
}
for (int i = 0; i < len; ++i) {
char c = str.charAt(i);
if (c > '9' || c < '0') {
return -1;
}
}
if (len == 10) {
long l = NumberInput.parseLong(str);
if (l > Integer.MAX_VALUE) {
return -1;
}
}
return NumberInput.parseInt(str);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
51 | 60d37b8cf9b8f1dcacd85d0a6aa362ab948cdf0c450d245e0babec8a0e596530 | boolean matchesLetter() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
boolean matchesLetter() {
if (isEmpty())
return false;
char c = input[pos];
return (c >= 'A' && c <= 'Z') || (c >= 'a' && c <= 'z');
}
```
| boolean matchesLetter() {
if (isEmpty())
return false;
char c = input[pos];
return (c >= 'A' && c <= 'Z') || (c >= 'a' && c <= 'z');
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
boolean matchesLetter() {
if (isEmpty())
return false;
char c = input[pos];
return (c >= 'A' && c <= 'Z') || (c >= 'a' && c <= 'z');
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
53 | 61012afa47b8d0f36162e44ca34389489132a1e6f4801a5653e401e735d1806e | public String chompBalanced(char open, char close) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Pulls a balanced string off the queue. E.g. if queue is "(one (two) three) four", (,) will return "one (two) three",
* and leave " four" on the queue. Unbalanced openers and closers can quoted (with ' or ") or escaped (with \). Those escapes will be left
* in the returned string, which is suitable for regexes (where we need to preserve the escape), but unsuitable for
* contains text strings; use unescape for that.
* @param open opener
* @param close closer
* @return data matched from the queue
*/
public String chompBalanced(char open, char close) {
int start = -1;
int end = -1;
int depth = 0;
char last = 0;
do {
if (isEmpty()) break;
Character c = consume();
if (last == 0 || last != ESC) {
if (c.equals(open)) {
depth++;
if (start == -1)
start = pos;
}
else if (c.equals(close))
depth--;
}
if (depth > 0 && last != 0)
end = pos; // don't include the outer match pair in the return
last = c;
} while (depth > 0);
return (end >= 0) ? queue.substring(start, end) : "";
}
```
| public String chompBalanced(char open, char close) {
int start = -1;
int end = -1;
int depth = 0;
char last = 0;
do {
if (isEmpty()) break;
Character c = consume();
if (last == 0 || last != ESC) {
if (c.equals(open)) {
depth++;
if (start == -1)
start = pos;
}
else if (c.equals(close))
depth--;
}
if (depth > 0 && last != 0)
end = pos; // don't include the outer match pair in the return
last = c;
} while (depth > 0);
return (end >= 0) ? queue.substring(start, end) : "";
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Pulls a balanced string off the queue. E.g. if queue is "(one (two) three) four", (,) will return "one (two) three",
* and leave " four" on the queue. Unbalanced openers and closers can quoted (with ' or ") or escaped (with \). Those escapes will be left
* in the returned string, which is suitable for regexes (where we need to preserve the escape), but unsuitable for
* contains text strings; use unescape for that.
* @param open opener
* @param close closer
* @return data matched from the queue
*/
public String chompBalanced(char open, char close) {
int start = -1;
int end = -1;
int depth = 0;
char last = 0;
do {
if (isEmpty()) break;
Character c = consume();
if (last == 0 || last != ESC) {
if (c.equals(open)) {
depth++;
if (start == -1)
start = pos;
}
else if (c.equals(close))
depth--;
}
if (depth > 0 && last != 0)
end = pos; // don't include the outer match pair in the return
last = c;
} while (depth > 0);
return (end >= 0) ? queue.substring(start, end) : "";
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
11 | 611c8807e92f3a3ff47625d14cce81b6cedfaf702dee2c3627489a559e4e95ad | private static void appendOption(final StringBuffer buff,
final Option option,
final boolean required)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Appends the usage clause for an Option to a StringBuffer.
*
* @param buff the StringBuffer to append to
* @param option the Option to append
* @param required whether the Option is required or not
*/
private static void appendOption(final StringBuffer buff,
final Option option,
final boolean required)
{
if (!required)
{
buff.append("[");
}
if (option.getOpt() != null)
{
buff.append("-").append(option.getOpt());
}
else
{
buff.append("--").append(option.getLongOpt());
}
// if the Option has a value
if (option.hasArg() && option.hasArgName())
{
buff.append(" <").append(option.getArgName()).append(">");
}
// if the Option is not a required option
if (!required)
{
buff.append("]");
}
}
```
| private static void appendOption(final StringBuffer buff,
final Option option,
final boolean required)
{
if (!required)
{
buff.append("[");
}
if (option.getOpt() != null)
{
buff.append("-").append(option.getOpt());
}
else
{
buff.append("--").append(option.getLongOpt());
}
// if the Option has a value
if (option.hasArg() && option.hasArgName())
{
buff.append(" <").append(option.getArgName()).append(">");
}
// if the Option is not a required option
if (!required)
{
buff.append("]");
}
} | false | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Appends the usage clause for an Option to a StringBuffer.
*
* @param buff the StringBuffer to append to
* @param option the Option to append
* @param required whether the Option is required or not
*/
private static void appendOption(final StringBuffer buff,
final Option option,
final boolean required)
{
if (!required)
{
buff.append("[");
}
if (option.getOpt() != null)
{
buff.append("-").append(option.getOpt());
}
else
{
buff.append("--").append(option.getLongOpt());
}
// if the Option has a value
if (option.hasArg() && option.hasArgName())
{
buff.append(" <").append(option.getArgName()).append(">");
}
// if the Option is not a required option
if (!required)
{
buff.append("]");
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
23 | 611d6b303bed94b64d2a1401709b5b26bbf3d05c3c2cfbedd6be3778e010d849 | protected StringBuffer renderWrappedText(StringBuffer sb, int width,
int nextLineTabStop, String text)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Render the specified text and return the rendered Options
* in a StringBuffer.
*
* @param sb The StringBuffer to place the rendered text into.
* @param width The number of characters to display per line
* @param nextLineTabStop The position on the next line for the first tab.
* @param text The text to be rendered.
*
* @return the StringBuffer with the rendered Options contents.
*/
protected StringBuffer renderWrappedText(StringBuffer sb, int width,
int nextLineTabStop, String text)
{
int pos = findWrapPos(text, width, 0);
if (pos == -1)
{
sb.append(rtrim(text));
return sb;
}
sb.append(rtrim(text.substring(0, pos))).append(defaultNewLine);
// all following lines must be padded with nextLineTabStop space
// characters
final String padding = createPadding(nextLineTabStop);
while (true)
{
int lastPos = pos;
text = padding + text.substring(pos).trim();
pos = findWrapPos(text, width, 0);
if (pos == -1)
{
sb.append(text);
return sb;
} else
if (pos == lastPos)
{
throw new RuntimeException("Text too long for line - throwing exception to avoid infinite loop [CLI-162]: " + text);
}
sb.append(rtrim(text.substring(0, pos))).append(defaultNewLine);
}
}
```
| protected StringBuffer renderWrappedText(StringBuffer sb, int width,
int nextLineTabStop, String text)
{
int pos = findWrapPos(text, width, 0);
if (pos == -1)
{
sb.append(rtrim(text));
return sb;
}
sb.append(rtrim(text.substring(0, pos))).append(defaultNewLine);
// all following lines must be padded with nextLineTabStop space
// characters
final String padding = createPadding(nextLineTabStop);
while (true)
{
int lastPos = pos;
text = padding + text.substring(pos).trim();
pos = findWrapPos(text, width, 0);
if (pos == -1)
{
sb.append(text);
return sb;
} else
if (pos == lastPos)
{
throw new RuntimeException("Text too long for line - throwing exception to avoid infinite loop [CLI-162]: " + text);
}
sb.append(rtrim(text.substring(0, pos))).append(defaultNewLine);
}
} | true | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Render the specified text and return the rendered Options
* in a StringBuffer.
*
* @param sb The StringBuffer to place the rendered text into.
* @param width The number of characters to display per line
* @param nextLineTabStop The position on the next line for the first tab.
* @param text The text to be rendered.
*
* @return the StringBuffer with the rendered Options contents.
*/
protected StringBuffer renderWrappedText(StringBuffer sb, int width,
int nextLineTabStop, String text)
{
int pos = findWrapPos(text, width, 0);
if (pos == -1)
{
sb.append(rtrim(text));
return sb;
}
sb.append(rtrim(text.substring(0, pos))).append(defaultNewLine);
// all following lines must be padded with nextLineTabStop space
// characters
final String padding = createPadding(nextLineTabStop);
while (true)
{
int lastPos = pos;
text = padding + text.substring(pos).trim();
pos = findWrapPos(text, width, 0);
if (pos == -1)
{
sb.append(text);
return sb;
} else
if (pos == lastPos)
{
throw new RuntimeException("Text too long for line - throwing exception to avoid infinite loop [CLI-162]: " + text);
}
sb.append(rtrim(text.substring(0, pos))).append(defaultNewLine);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
7 | 6155e294d88f1109758e8134b95e4f84bf9adfd9462f7641ffc0df4b46bf397c | public static String parseName(byte[] buffer, final int offset, final int length) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Parse an entry name from a buffer.
* Parsing stops when a NUL is found
* or the buffer length is reached.
*
* @param buffer The buffer from which to parse.
* @param offset The offset into the buffer from which to parse.
* @param length The maximum number of bytes to parse.
* @return The entry name.
*/
public static String parseName(byte[] buffer, final int offset, final int length) {
StringBuffer result = new StringBuffer(length);
int end = offset + length;
for (int i = offset; i < end; ++i) {
if (buffer[i] == 0) {
break;
}
result.append((char) buffer[i]);
}
return result.toString();
}
```
| public static String parseName(byte[] buffer, final int offset, final int length) {
StringBuffer result = new StringBuffer(length);
int end = offset + length;
for (int i = offset; i < end; ++i) {
if (buffer[i] == 0) {
break;
}
result.append((char) buffer[i]);
}
return result.toString();
} | true | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Parse an entry name from a buffer.
* Parsing stops when a NUL is found
* or the buffer length is reached.
*
* @param buffer The buffer from which to parse.
* @param offset The offset into the buffer from which to parse.
* @param length The maximum number of bytes to parse.
* @return The entry name.
*/
public static String parseName(byte[] buffer, final int offset, final int length) {
StringBuffer result = new StringBuffer(length);
int end = offset + length;
for (int i = offset; i < end; ++i) {
if (buffer[i] == 0) {
break;
}
result.append((char) buffer[i]);
}
return result.toString();
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
52 | 61ab0ecee24ca1302a7f81d63813f8992f745b3accdf476f29ed19d9e65f7f21 | private static void escapeJavaStyleString(Writer out, String str, boolean escapeSingleQuote) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Worker method for the {@link #escapeJavaScript(String)} method.</p>
*
* @param out write to receieve the escaped string
* @param str String to escape values in, may be null
* @param escapeSingleQuote escapes single quotes if <code>true</code>
* @throws IOException if an IOException occurs
*/
private static void escapeJavaStyleString(Writer out, String str, boolean escapeSingleQuote) throws IOException {
if (out == null) {
throw new IllegalArgumentException("The Writer must not be null");
}
if (str == null) {
return;
}
int sz;
sz = str.length();
for (int i = 0; i < sz; i++) {
char ch = str.charAt(i);
// handle unicode
if (ch > 0xfff) {
out.write("\\u" + hex(ch));
} else if (ch > 0xff) {
out.write("\\u0" + hex(ch));
} else if (ch > 0x7f) {
out.write("\\u00" + hex(ch));
} else if (ch < 32) {
switch (ch) {
case '\b':
out.write('\\');
out.write('b');
break;
case '\n':
out.write('\\');
out.write('n');
break;
case '\t':
out.write('\\');
out.write('t');
break;
case '\f':
out.write('\\');
out.write('f');
break;
case '\r':
out.write('\\');
out.write('r');
break;
default :
if (ch > 0xf) {
out.write("\\u00" + hex(ch));
} else {
out.write("\\u000" + hex(ch));
}
break;
}
} else {
switch (ch) {
case '\'':
if (escapeSingleQuote) {
out.write('\\');
}
out.write('\'');
break;
case '"':
out.write('\\');
out.write('"');
break;
case '\\':
out.write('\\');
out.write('\\');
break;
default :
out.write(ch);
break;
}
}
}
}
```
| private static void escapeJavaStyleString(Writer out, String str, boolean escapeSingleQuote) throws IOException {
if (out == null) {
throw new IllegalArgumentException("The Writer must not be null");
}
if (str == null) {
return;
}
int sz;
sz = str.length();
for (int i = 0; i < sz; i++) {
char ch = str.charAt(i);
// handle unicode
if (ch > 0xfff) {
out.write("\\u" + hex(ch));
} else if (ch > 0xff) {
out.write("\\u0" + hex(ch));
} else if (ch > 0x7f) {
out.write("\\u00" + hex(ch));
} else if (ch < 32) {
switch (ch) {
case '\b':
out.write('\\');
out.write('b');
break;
case '\n':
out.write('\\');
out.write('n');
break;
case '\t':
out.write('\\');
out.write('t');
break;
case '\f':
out.write('\\');
out.write('f');
break;
case '\r':
out.write('\\');
out.write('r');
break;
default :
if (ch > 0xf) {
out.write("\\u00" + hex(ch));
} else {
out.write("\\u000" + hex(ch));
}
break;
}
} else {
switch (ch) {
case '\'':
if (escapeSingleQuote) {
out.write('\\');
}
out.write('\'');
break;
case '"':
out.write('\\');
out.write('"');
break;
case '\\':
out.write('\\');
out.write('\\');
break;
default :
out.write(ch);
break;
}
}
}
} | true | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Worker method for the {@link #escapeJavaScript(String)} method.</p>
*
* @param out write to receieve the escaped string
* @param str String to escape values in, may be null
* @param escapeSingleQuote escapes single quotes if <code>true</code>
* @throws IOException if an IOException occurs
*/
private static void escapeJavaStyleString(Writer out, String str, boolean escapeSingleQuote) throws IOException {
if (out == null) {
throw new IllegalArgumentException("The Writer must not be null");
}
if (str == null) {
return;
}
int sz;
sz = str.length();
for (int i = 0; i < sz; i++) {
char ch = str.charAt(i);
// handle unicode
if (ch > 0xfff) {
out.write("\\u" + hex(ch));
} else if (ch > 0xff) {
out.write("\\u0" + hex(ch));
} else if (ch > 0x7f) {
out.write("\\u00" + hex(ch));
} else if (ch < 32) {
switch (ch) {
case '\b':
out.write('\\');
out.write('b');
break;
case '\n':
out.write('\\');
out.write('n');
break;
case '\t':
out.write('\\');
out.write('t');
break;
case '\f':
out.write('\\');
out.write('f');
break;
case '\r':
out.write('\\');
out.write('r');
break;
default :
if (ch > 0xf) {
out.write("\\u00" + hex(ch));
} else {
out.write("\\u000" + hex(ch));
}
break;
}
} else {
switch (ch) {
case '\'':
if (escapeSingleQuote) {
out.write('\\');
}
out.write('\'');
break;
case '"':
out.write('\\');
out.write('"');
break;
case '\\':
out.write('\\');
out.write('\\');
break;
default :
out.write(ch);
break;
}
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
8 | 61ec5277bc8af5c781f0e2816282575b4add305c22984e06ba4412856cb9e997 | private boolean compute(Object left, Object right) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private boolean compute(Object left, Object right) {
left = reduce(left);
right = reduce(right);
if (left instanceof InitialContext) {
((InitialContext) left).reset();
}
if (right instanceof InitialContext) {
((InitialContext) right).reset();
}
if (left instanceof Iterator && right instanceof Iterator) {
return findMatch((Iterator) left, (Iterator) right);
}
if (left instanceof Iterator) {
return containsMatch((Iterator) left, right);
}
if (right instanceof Iterator) {
return containsMatch((Iterator) right, left);
}
double ld = InfoSetUtil.doubleValue(left);
if (Double.isNaN(ld)) {
return false;
}
double rd = InfoSetUtil.doubleValue(right);
if (Double.isNaN(rd)) {
return false;
}
return evaluateCompare(ld == rd ? 0 : ld < rd ? -1 : 1);
}
```
| private boolean compute(Object left, Object right) {
left = reduce(left);
right = reduce(right);
if (left instanceof InitialContext) {
((InitialContext) left).reset();
}
if (right instanceof InitialContext) {
((InitialContext) right).reset();
}
if (left instanceof Iterator && right instanceof Iterator) {
return findMatch((Iterator) left, (Iterator) right);
}
if (left instanceof Iterator) {
return containsMatch((Iterator) left, right);
}
if (right instanceof Iterator) {
return containsMatch((Iterator) right, left);
}
double ld = InfoSetUtil.doubleValue(left);
if (Double.isNaN(ld)) {
return false;
}
double rd = InfoSetUtil.doubleValue(right);
if (Double.isNaN(rd)) {
return false;
}
return evaluateCompare(ld == rd ? 0 : ld < rd ? -1 : 1);
} | false | JxPath | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private boolean compute(Object left, Object right) {
left = reduce(left);
right = reduce(right);
if (left instanceof InitialContext) {
((InitialContext) left).reset();
}
if (right instanceof InitialContext) {
((InitialContext) right).reset();
}
if (left instanceof Iterator && right instanceof Iterator) {
return findMatch((Iterator) left, (Iterator) right);
}
if (left instanceof Iterator) {
return containsMatch((Iterator) left, right);
}
if (right instanceof Iterator) {
return containsMatch((Iterator) right, left);
}
double ld = InfoSetUtil.doubleValue(left);
if (Double.isNaN(ld)) {
return false;
}
double rd = InfoSetUtil.doubleValue(right);
if (Double.isNaN(rd)) {
return false;
}
return evaluateCompare(ld == rd ? 0 : ld < rd ? -1 : 1);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
16 | 626d2197d1ff9c1afb990f2847f5305559009cf781d55fece90c5b59125fae35 | private static Type resolve(Type context, Class<?> contextRawType, Type toResolve,
Collection<TypeVariable> visitedTypeVariables) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private static Type resolve(Type context, Class<?> contextRawType, Type toResolve,
Collection<TypeVariable> visitedTypeVariables) {
// this implementation is made a little more complicated in an attempt to avoid object-creation
while (true) {
if (toResolve instanceof TypeVariable) {
TypeVariable<?> typeVariable = (TypeVariable<?>) toResolve;
// cannot reduce due to infinite recursion
toResolve = resolveTypeVariable(context, contextRawType, typeVariable);
if (toResolve == typeVariable) {
return toResolve;
}
} else if (toResolve instanceof Class && ((Class<?>) toResolve).isArray()) {
Class<?> original = (Class<?>) toResolve;
Type componentType = original.getComponentType();
Type newComponentType = resolve(context, contextRawType, componentType, visitedTypeVariables);
return componentType == newComponentType
? original
: arrayOf(newComponentType);
} else if (toResolve instanceof GenericArrayType) {
GenericArrayType original = (GenericArrayType) toResolve;
Type componentType = original.getGenericComponentType();
Type newComponentType = resolve(context, contextRawType, componentType, visitedTypeVariables);
return componentType == newComponentType
? original
: arrayOf(newComponentType);
} else if (toResolve instanceof ParameterizedType) {
ParameterizedType original = (ParameterizedType) toResolve;
Type ownerType = original.getOwnerType();
Type newOwnerType = resolve(context, contextRawType, ownerType, visitedTypeVariables);
boolean changed = newOwnerType != ownerType;
Type[] args = original.getActualTypeArguments();
for (int t = 0, length = args.length; t < length; t++) {
Type resolvedTypeArgument = resolve(context, contextRawType, args[t], visitedTypeVariables);
if (resolvedTypeArgument != args[t]) {
if (!changed) {
args = args.clone();
changed = true;
}
args[t] = resolvedTypeArgument;
}
}
return changed
? newParameterizedTypeWithOwner(newOwnerType, original.getRawType(), args)
: original;
} else if (toResolve instanceof WildcardType) {
WildcardType original = (WildcardType) toResolve;
Type[] originalLowerBound = original.getLowerBounds();
Type[] originalUpperBound = original.getUpperBounds();
if (originalLowerBound.length == 1) {
Type lowerBound = resolve(context, contextRawType, originalLowerBound[0], visitedTypeVariables);
if (lowerBound != originalLowerBound[0]) {
return supertypeOf(lowerBound);
}
} else if (originalUpperBound.length == 1) {
Type upperBound = resolve(context, contextRawType, originalUpperBound[0], visitedTypeVariables);
if (upperBound != originalUpperBound[0]) {
return subtypeOf(upperBound);
}
}
return original;
} else {
return toResolve;
}
}
}
```
| private static Type resolve(Type context, Class<?> contextRawType, Type toResolve,
Collection<TypeVariable> visitedTypeVariables) {
// this implementation is made a little more complicated in an attempt to avoid object-creation
while (true) {
if (toResolve instanceof TypeVariable) {
TypeVariable<?> typeVariable = (TypeVariable<?>) toResolve;
// cannot reduce due to infinite recursion
toResolve = resolveTypeVariable(context, contextRawType, typeVariable);
if (toResolve == typeVariable) {
return toResolve;
}
} else if (toResolve instanceof Class && ((Class<?>) toResolve).isArray()) {
Class<?> original = (Class<?>) toResolve;
Type componentType = original.getComponentType();
Type newComponentType = resolve(context, contextRawType, componentType, visitedTypeVariables);
return componentType == newComponentType
? original
: arrayOf(newComponentType);
} else if (toResolve instanceof GenericArrayType) {
GenericArrayType original = (GenericArrayType) toResolve;
Type componentType = original.getGenericComponentType();
Type newComponentType = resolve(context, contextRawType, componentType, visitedTypeVariables);
return componentType == newComponentType
? original
: arrayOf(newComponentType);
} else if (toResolve instanceof ParameterizedType) {
ParameterizedType original = (ParameterizedType) toResolve;
Type ownerType = original.getOwnerType();
Type newOwnerType = resolve(context, contextRawType, ownerType, visitedTypeVariables);
boolean changed = newOwnerType != ownerType;
Type[] args = original.getActualTypeArguments();
for (int t = 0, length = args.length; t < length; t++) {
Type resolvedTypeArgument = resolve(context, contextRawType, args[t], visitedTypeVariables);
if (resolvedTypeArgument != args[t]) {
if (!changed) {
args = args.clone();
changed = true;
}
args[t] = resolvedTypeArgument;
}
}
return changed
? newParameterizedTypeWithOwner(newOwnerType, original.getRawType(), args)
: original;
} else if (toResolve instanceof WildcardType) {
WildcardType original = (WildcardType) toResolve;
Type[] originalLowerBound = original.getLowerBounds();
Type[] originalUpperBound = original.getUpperBounds();
if (originalLowerBound.length == 1) {
Type lowerBound = resolve(context, contextRawType, originalLowerBound[0], visitedTypeVariables);
if (lowerBound != originalLowerBound[0]) {
return supertypeOf(lowerBound);
}
} else if (originalUpperBound.length == 1) {
Type upperBound = resolve(context, contextRawType, originalUpperBound[0], visitedTypeVariables);
if (upperBound != originalUpperBound[0]) {
return subtypeOf(upperBound);
}
}
return original;
} else {
return toResolve;
}
}
} | true | Gson | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private static Type resolve(Type context, Class<?> contextRawType, Type toResolve,
Collection<TypeVariable> visitedTypeVariables) {
// this implementation is made a little more complicated in an attempt to avoid object-creation
while (true) {
if (toResolve instanceof TypeVariable) {
TypeVariable<?> typeVariable = (TypeVariable<?>) toResolve;
// cannot reduce due to infinite recursion
toResolve = resolveTypeVariable(context, contextRawType, typeVariable);
if (toResolve == typeVariable) {
return toResolve;
}
} else if (toResolve instanceof Class && ((Class<?>) toResolve).isArray()) {
Class<?> original = (Class<?>) toResolve;
Type componentType = original.getComponentType();
Type newComponentType = resolve(context, contextRawType, componentType, visitedTypeVariables);
return componentType == newComponentType
? original
: arrayOf(newComponentType);
} else if (toResolve instanceof GenericArrayType) {
GenericArrayType original = (GenericArrayType) toResolve;
Type componentType = original.getGenericComponentType();
Type newComponentType = resolve(context, contextRawType, componentType, visitedTypeVariables);
return componentType == newComponentType
? original
: arrayOf(newComponentType);
} else if (toResolve instanceof ParameterizedType) {
ParameterizedType original = (ParameterizedType) toResolve;
Type ownerType = original.getOwnerType();
Type newOwnerType = resolve(context, contextRawType, ownerType, visitedTypeVariables);
boolean changed = newOwnerType != ownerType;
Type[] args = original.getActualTypeArguments();
for (int t = 0, length = args.length; t < length; t++) {
Type resolvedTypeArgument = resolve(context, contextRawType, args[t], visitedTypeVariables);
if (resolvedTypeArgument != args[t]) {
if (!changed) {
args = args.clone();
changed = true;
}
args[t] = resolvedTypeArgument;
}
}
return changed
? newParameterizedTypeWithOwner(newOwnerType, original.getRawType(), args)
: original;
} else if (toResolve instanceof WildcardType) {
WildcardType original = (WildcardType) toResolve;
Type[] originalLowerBound = original.getLowerBounds();
Type[] originalUpperBound = original.getUpperBounds();
if (originalLowerBound.length == 1) {
Type lowerBound = resolve(context, contextRawType, originalLowerBound[0], visitedTypeVariables);
if (lowerBound != originalLowerBound[0]) {
return supertypeOf(lowerBound);
}
} else if (originalUpperBound.length == 1) {
Type upperBound = resolve(context, contextRawType, originalUpperBound[0], visitedTypeVariables);
if (upperBound != originalUpperBound[0]) {
return subtypeOf(upperBound);
}
}
return original;
} else {
return toResolve;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
5 | 628ac3e0b4c6afdfb9ee9811dd59d43d3e58b1752d0727722e16a317658d058f | public Complex reciprocal() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/** {@inheritDoc} */
public Complex reciprocal() {
if (isNaN) {
return NaN;
}
if (real == 0.0 && imaginary == 0.0) {
return INF;
}
if (isInfinite) {
return ZERO;
}
if (FastMath.abs(real) < FastMath.abs(imaginary)) {
double q = real / imaginary;
double scale = 1. / (real * q + imaginary);
return createComplex(scale * q, -scale);
} else {
double q = imaginary / real;
double scale = 1. / (imaginary * q + real);
return createComplex(scale, -scale * q);
}
}
```
| public Complex reciprocal() {
if (isNaN) {
return NaN;
}
if (real == 0.0 && imaginary == 0.0) {
return INF;
}
if (isInfinite) {
return ZERO;
}
if (FastMath.abs(real) < FastMath.abs(imaginary)) {
double q = real / imaginary;
double scale = 1. / (real * q + imaginary);
return createComplex(scale * q, -scale);
} else {
double q = imaginary / real;
double scale = 1. / (imaginary * q + real);
return createComplex(scale, -scale * q);
}
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/** {@inheritDoc} */
public Complex reciprocal() {
if (isNaN) {
return NaN;
}
if (real == 0.0 && imaginary == 0.0) {
return INF;
}
if (isInfinite) {
return ZERO;
}
if (FastMath.abs(real) < FastMath.abs(imaginary)) {
double q = real / imaginary;
double scale = 1. / (real * q + imaginary);
return createComplex(scale * q, -scale);
} else {
double q = imaginary / real;
double scale = 1. / (imaginary * q + real);
return createComplex(scale, -scale * q);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
5 | 62b35683549259ff608e5d2375392bb0b5482ce0df2b4658def6feb90d2efac9 | private boolean isInlinableObject(List<Reference> refs) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Counts the number of direct (full) references to an object.
* Specifically, we check for references of the following type:
* <pre>
* x;
* x.fn();
* </pre>
*/
private boolean isInlinableObject(List<Reference> refs) {
boolean ret = false;
Set<String> validProperties = Sets.newHashSet();
for (Reference ref : refs) {
Node name = ref.getNode();
Node parent = ref.getParent();
Node gramps = ref.getGrandparent();
// Ignore most indirect references, like x.y (but not x.y(),
// since the function referenced by y might reference 'this').
//
if (parent.isGetProp()) {
Preconditions.checkState(parent.getFirstChild() == name);
// A call target may be using the object as a 'this' value.
if (gramps.isCall()
&& gramps.getFirstChild() == parent) {
return false;
}
// Deleting a property has different semantics from deleting
// a variable, so deleted properties should not be inlined.
// NOTE(nicksantos): This pass's object-splitting algorithm has
// a blind spot. It assumes that if a property isn't defined on an
// object, then the value is undefined. This is not true, because
// Object.prototype can have arbitrary properties on it.
//
// We short-circuit this problem by bailing out if we see a reference
// to a property that isn't defined on the object literal. This
// isn't a perfect algorithm, but it should catch most cases.
String propName = parent.getLastChild().getString();
if (!validProperties.contains(propName)) {
if (NodeUtil.isVarOrSimpleAssignLhs(parent, gramps)) {
validProperties.add(propName);
} else {
return false;
}
}
continue;
}
// Only rewrite VAR declarations or simple assignment statements
if (!isVarOrAssignExprLhs(name)) {
return false;
}
Node val = ref.getAssignedValue();
if (val == null) {
// A var with no assignment.
continue;
}
// We're looking for object literal assignments only.
if (!val.isObjectLit()) {
return false;
}
// Make sure that the value is not self-referential. IOW,
// disallow things like x = {b: x.a}.
//
// TODO: Only exclude unorderable self-referential
// assignments. i.e. x = {a: x.b, b: x.a} is not orderable,
// but x = {a: 1, b: x.a} is.
//
// Also, ES5 getters/setters aren't handled by this pass.
for (Node child = val.getFirstChild(); child != null;
child = child.getNext()) {
if (child.isGetterDef() ||
child.isSetterDef()) {
// ES5 get/set not supported.
return false;
}
validProperties.add(child.getString());
Node childVal = child.getFirstChild();
// Check if childVal is the parent of any of the passed in
// references, as that is how self-referential assignments
// will happen.
for (Reference t : refs) {
Node refNode = t.getParent();
while (!NodeUtil.isStatementBlock(refNode)) {
if (refNode == childVal) {
// There's a self-referential assignment
return false;
}
refNode = refNode.getParent();
}
}
}
// We have found an acceptable object literal assignment. As
// long as there are no other assignments that mess things up,
// we can inline.
ret = true;
}
return ret;
}
```
| private boolean isInlinableObject(List<Reference> refs) {
boolean ret = false;
Set<String> validProperties = Sets.newHashSet();
for (Reference ref : refs) {
Node name = ref.getNode();
Node parent = ref.getParent();
Node gramps = ref.getGrandparent();
// Ignore most indirect references, like x.y (but not x.y(),
// since the function referenced by y might reference 'this').
//
if (parent.isGetProp()) {
Preconditions.checkState(parent.getFirstChild() == name);
// A call target may be using the object as a 'this' value.
if (gramps.isCall()
&& gramps.getFirstChild() == parent) {
return false;
}
// Deleting a property has different semantics from deleting
// a variable, so deleted properties should not be inlined.
// NOTE(nicksantos): This pass's object-splitting algorithm has
// a blind spot. It assumes that if a property isn't defined on an
// object, then the value is undefined. This is not true, because
// Object.prototype can have arbitrary properties on it.
//
// We short-circuit this problem by bailing out if we see a reference
// to a property that isn't defined on the object literal. This
// isn't a perfect algorithm, but it should catch most cases.
String propName = parent.getLastChild().getString();
if (!validProperties.contains(propName)) {
if (NodeUtil.isVarOrSimpleAssignLhs(parent, gramps)) {
validProperties.add(propName);
} else {
return false;
}
}
continue;
}
// Only rewrite VAR declarations or simple assignment statements
if (!isVarOrAssignExprLhs(name)) {
return false;
}
Node val = ref.getAssignedValue();
if (val == null) {
// A var with no assignment.
continue;
}
// We're looking for object literal assignments only.
if (!val.isObjectLit()) {
return false;
}
// Make sure that the value is not self-referential. IOW,
// disallow things like x = {b: x.a}.
//
// TODO: Only exclude unorderable self-referential
// assignments. i.e. x = {a: x.b, b: x.a} is not orderable,
// but x = {a: 1, b: x.a} is.
//
// Also, ES5 getters/setters aren't handled by this pass.
for (Node child = val.getFirstChild(); child != null;
child = child.getNext()) {
if (child.isGetterDef() ||
child.isSetterDef()) {
// ES5 get/set not supported.
return false;
}
validProperties.add(child.getString());
Node childVal = child.getFirstChild();
// Check if childVal is the parent of any of the passed in
// references, as that is how self-referential assignments
// will happen.
for (Reference t : refs) {
Node refNode = t.getParent();
while (!NodeUtil.isStatementBlock(refNode)) {
if (refNode == childVal) {
// There's a self-referential assignment
return false;
}
refNode = refNode.getParent();
}
}
}
// We have found an acceptable object literal assignment. As
// long as there are no other assignments that mess things up,
// we can inline.
ret = true;
}
return ret;
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of direct (full) references to an object.
* Specifically, we check for references of the following type:
* <pre>
* x;
* x.fn();
* </pre>
*/
private boolean isInlinableObject(List<Reference> refs) {
boolean ret = false;
Set<String> validProperties = Sets.newHashSet();
for (Reference ref : refs) {
Node name = ref.getNode();
Node parent = ref.getParent();
Node gramps = ref.getGrandparent();
// Ignore most indirect references, like x.y (but not x.y(),
// since the function referenced by y might reference 'this').
//
if (parent.isGetProp()) {
Preconditions.checkState(parent.getFirstChild() == name);
// A call target may be using the object as a 'this' value.
if (gramps.isCall()
&& gramps.getFirstChild() == parent) {
return false;
}
// Deleting a property has different semantics from deleting
// a variable, so deleted properties should not be inlined.
// NOTE(nicksantos): This pass's object-splitting algorithm has
// a blind spot. It assumes that if a property isn't defined on an
// object, then the value is undefined. This is not true, because
// Object.prototype can have arbitrary properties on it.
//
// We short-circuit this problem by bailing out if we see a reference
// to a property that isn't defined on the object literal. This
// isn't a perfect algorithm, but it should catch most cases.
String propName = parent.getLastChild().getString();
if (!validProperties.contains(propName)) {
if (NodeUtil.isVarOrSimpleAssignLhs(parent, gramps)) {
validProperties.add(propName);
} else {
return false;
}
}
continue;
}
// Only rewrite VAR declarations or simple assignment statements
if (!isVarOrAssignExprLhs(name)) {
return false;
}
Node val = ref.getAssignedValue();
if (val == null) {
// A var with no assignment.
continue;
}
// We're looking for object literal assignments only.
if (!val.isObjectLit()) {
return false;
}
// Make sure that the value is not self-referential. IOW,
// disallow things like x = {b: x.a}.
//
// TODO: Only exclude unorderable self-referential
// assignments. i.e. x = {a: x.b, b: x.a} is not orderable,
// but x = {a: 1, b: x.a} is.
//
// Also, ES5 getters/setters aren't handled by this pass.
for (Node child = val.getFirstChild(); child != null;
child = child.getNext()) {
if (child.isGetterDef() ||
child.isSetterDef()) {
// ES5 get/set not supported.
return false;
}
validProperties.add(child.getString());
Node childVal = child.getFirstChild();
// Check if childVal is the parent of any of the passed in
// references, as that is how self-referential assignments
// will happen.
for (Reference t : refs) {
Node refNode = t.getParent();
while (!NodeUtil.isStatementBlock(refNode)) {
if (refNode == childVal) {
// There's a self-referential assignment
return false;
}
refNode = refNode.getParent();
}
}
}
// We have found an acceptable object literal assignment. As
// long as there are no other assignments that mess things up,
// we can inline.
ret = true;
}
return ret;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
42 | 62cc965f84f10f89b3921042390d9645e37f15eb9a3e76ed5b8009d097ec31e8 | public List<Connection.KeyVal> formData() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Get the data that this form submits. The returned list is a copy of the data, and changes to the contents of the
* list will not be reflected in the DOM.
* @return a list of key vals
*/
public List<Connection.KeyVal> formData() {
ArrayList<Connection.KeyVal> data = new ArrayList<Connection.KeyVal>();
// iterate the form control elements and accumulate their values
for (Element el: elements) {
if (!el.tag().isFormSubmittable()) continue; // contents are form listable, superset of submitable
String name = el.attr("name");
if (name.length() == 0) continue;
String type = el.attr("type");
if ("select".equals(el.tagName())) {
Elements options = el.select("option[selected]");
boolean set = false;
for (Element option: options) {
data.add(HttpConnection.KeyVal.create(name, option.val()));
set = true;
}
if (!set) {
Element option = el.select("option").first();
if (option != null)
data.add(HttpConnection.KeyVal.create(name, option.val()));
}
} else if ("checkbox".equalsIgnoreCase(type) || "radio".equalsIgnoreCase(type)) {
// only add checkbox or radio if they have the checked attribute
if (el.hasAttr("checked")) {
final String val = el.val();
data.add(HttpConnection.KeyVal.create(name, val));
}
} else {
data.add(HttpConnection.KeyVal.create(name, el.val()));
}
}
return data;
}
```
| public List<Connection.KeyVal> formData() {
ArrayList<Connection.KeyVal> data = new ArrayList<Connection.KeyVal>();
// iterate the form control elements and accumulate their values
for (Element el: elements) {
if (!el.tag().isFormSubmittable()) continue; // contents are form listable, superset of submitable
String name = el.attr("name");
if (name.length() == 0) continue;
String type = el.attr("type");
if ("select".equals(el.tagName())) {
Elements options = el.select("option[selected]");
boolean set = false;
for (Element option: options) {
data.add(HttpConnection.KeyVal.create(name, option.val()));
set = true;
}
if (!set) {
Element option = el.select("option").first();
if (option != null)
data.add(HttpConnection.KeyVal.create(name, option.val()));
}
} else if ("checkbox".equalsIgnoreCase(type) || "radio".equalsIgnoreCase(type)) {
// only add checkbox or radio if they have the checked attribute
if (el.hasAttr("checked")) {
final String val = el.val();
data.add(HttpConnection.KeyVal.create(name, val));
}
} else {
data.add(HttpConnection.KeyVal.create(name, el.val()));
}
}
return data;
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Get the data that this form submits. The returned list is a copy of the data, and changes to the contents of the
* list will not be reflected in the DOM.
* @return a list of key vals
*/
public List<Connection.KeyVal> formData() {
ArrayList<Connection.KeyVal> data = new ArrayList<Connection.KeyVal>();
// iterate the form control elements and accumulate their values
for (Element el: elements) {
if (!el.tag().isFormSubmittable()) continue; // contents are form listable, superset of submitable
String name = el.attr("name");
if (name.length() == 0) continue;
String type = el.attr("type");
if ("select".equals(el.tagName())) {
Elements options = el.select("option[selected]");
boolean set = false;
for (Element option: options) {
data.add(HttpConnection.KeyVal.create(name, option.val()));
set = true;
}
if (!set) {
Element option = el.select("option").first();
if (option != null)
data.add(HttpConnection.KeyVal.create(name, option.val()));
}
} else if ("checkbox".equalsIgnoreCase(type) || "radio".equalsIgnoreCase(type)) {
// only add checkbox or radio if they have the checked attribute
if (el.hasAttr("checked")) {
final String val = el.val();
data.add(HttpConnection.KeyVal.create(name, val));
}
} else {
data.add(HttpConnection.KeyVal.create(name, el.val()));
}
}
return data;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
10 | 62dc8a6f82d808a59699c6dc9c9a6eeb2d018a6f1457bfad10014e0c7babfaca | public final Object computeValue(EvalContext context) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public final Object computeValue(EvalContext context) {
return compute(args[0].compute(context), args[1].compute(context))
? Boolean.TRUE : Boolean.FALSE;
}
```
| public final Object computeValue(EvalContext context) {
return compute(args[0].compute(context), args[1].compute(context))
? Boolean.TRUE : Boolean.FALSE;
} | false | JxPath | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public final Object computeValue(EvalContext context) {
return compute(args[0].compute(context), args[1].compute(context))
? Boolean.TRUE : Boolean.FALSE;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
36 | 62ee68d2b13a79bc4ed49ee98d2b9fad07714ece1c55125264ea2c5c188d98a1 | private InputStream getCurrentStream() throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private InputStream getCurrentStream() throws IOException {
if (deferredBlockStreams.isEmpty()) {
throw new IllegalStateException("No current 7z entry (call getNextEntry() first).");
}
while (deferredBlockStreams.size() > 1) {
// In solid compression mode we need to decompress all leading folder'
// streams to get access to an entry. We defer this until really needed
// so that entire blocks can be skipped without wasting time for decompression.
final InputStream stream = deferredBlockStreams.remove(0);
IOUtils.skip(stream, Long.MAX_VALUE);
stream.close();
}
return deferredBlockStreams.get(0);
}
```
| private InputStream getCurrentStream() throws IOException {
if (deferredBlockStreams.isEmpty()) {
throw new IllegalStateException("No current 7z entry (call getNextEntry() first).");
}
while (deferredBlockStreams.size() > 1) {
// In solid compression mode we need to decompress all leading folder'
// streams to get access to an entry. We defer this until really needed
// so that entire blocks can be skipped without wasting time for decompression.
final InputStream stream = deferredBlockStreams.remove(0);
IOUtils.skip(stream, Long.MAX_VALUE);
stream.close();
}
return deferredBlockStreams.get(0);
} | true | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private InputStream getCurrentStream() throws IOException {
if (deferredBlockStreams.isEmpty()) {
throw new IllegalStateException("No current 7z entry (call getNextEntry() first).");
}
while (deferredBlockStreams.size() > 1) {
// In solid compression mode we need to decompress all leading folder'
// streams to get access to an entry. We defer this until really needed
// so that entire blocks can be skipped without wasting time for decompression.
final InputStream stream = deferredBlockStreams.remove(0);
IOUtils.skip(stream, Long.MAX_VALUE);
stream.close();
}
return deferredBlockStreams.get(0);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
17 | 63752fb12433643a33c8335c571f1046e88a2f7ce6fcb8e1451f677bd5dd5bf8 | public Object clone() throws CloneNotSupportedException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns a clone of the time series.
* <P>
* Notes:
* <ul>
* <li>no need to clone the domain and range descriptions, since String
* object is immutable;</li>
* <li>we pass over to the more general method clone(start, end).</li>
* </ul>
*
* @return A clone of the time series.
*
* @throws CloneNotSupportedException not thrown by this class, but
* subclasses may differ.
*/
public Object clone() throws CloneNotSupportedException {
Object clone = createCopy(0, getItemCount() - 1);
return clone;
}
```
| public Object clone() throws CloneNotSupportedException {
Object clone = createCopy(0, getItemCount() - 1);
return clone;
} | true | Chart | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns a clone of the time series.
* <P>
* Notes:
* <ul>
* <li>no need to clone the domain and range descriptions, since String
* object is immutable;</li>
* <li>we pass over to the more general method clone(start, end).</li>
* </ul>
*
* @return A clone of the time series.
*
* @throws CloneNotSupportedException not thrown by this class, but
* subclasses may differ.
*/
public Object clone() throws CloneNotSupportedException {
Object clone = createCopy(0, getItemCount() - 1);
return clone;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
103 | 63ee1d69547c5f7e6310853f41887dda6d2a6f36afd9bac3aea729e502879a14 | public double cumulativeProbability(double x) throws MathException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* For this disbution, X, this method returns P(X < <code>x</code>).
* @param x the value at which the CDF is evaluated.
* @return CDF evaluted at <code>x</code>.
* @throws MathException if the algorithm fails to converge; unless
* x is more than 20 standard deviations from the mean, in which case the
* convergence exception is caught and 0 or 1 is returned.
*/
public double cumulativeProbability(double x) throws MathException {
return 0.5 * (1.0 + Erf.erf((x - mean) /
(standardDeviation * Math.sqrt(2.0))));
}
```
| public double cumulativeProbability(double x) throws MathException {
return 0.5 * (1.0 + Erf.erf((x - mean) /
(standardDeviation * Math.sqrt(2.0))));
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* For this disbution, X, this method returns P(X < <code>x</code>).
* @param x the value at which the CDF is evaluated.
* @return CDF evaluted at <code>x</code>.
* @throws MathException if the algorithm fails to converge; unless
* x is more than 20 standard deviations from the mean, in which case the
* convergence exception is caught and 0 or 1 is returned.
*/
public double cumulativeProbability(double x) throws MathException {
return 0.5 * (1.0 + Erf.erf((x - mean) /
(standardDeviation * Math.sqrt(2.0))));
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
12 | 63ee9a7bd435bd2b3fd095d55cf9ac6e10629e53cacd4a356cded8ce2c9ddae9 | public Class getGenericType(Field field) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Finds the generic type (parametrized type) of the field. If the field is not generic it returns Object.class.
*
* @param field
* @return
*/
public Class getGenericType(Field field) {
Type generic = field.getGenericType();
if (generic != null && generic instanceof ParameterizedType) {
Type actual = ((ParameterizedType) generic).getActualTypeArguments()[0];
return (Class) actual;
//in case of nested generics we don't go deep
}
return Object.class;
}
```
| public Class getGenericType(Field field) {
Type generic = field.getGenericType();
if (generic != null && generic instanceof ParameterizedType) {
Type actual = ((ParameterizedType) generic).getActualTypeArguments()[0];
return (Class) actual;
//in case of nested generics we don't go deep
}
return Object.class;
} | true | Mockito | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Finds the generic type (parametrized type) of the field. If the field is not generic it returns Object.class.
*
* @param field
* @return
*/
public Class getGenericType(Field field) {
Type generic = field.getGenericType();
if (generic != null && generic instanceof ParameterizedType) {
Type actual = ((ParameterizedType) generic).getActualTypeArguments()[0];
return (Class) actual;
//in case of nested generics we don't go deep
}
return Object.class;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
63 | 6488a2a0df6fa3b6508b4775009679a2cad6249bc4e3d952bef94f8c3c3a0470 | public static boolean equals(double x, double y) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns true iff they are equal as defined by
* {@link #equals(double,double,int) equals(x, y, 1)}.
*
* @param x first value
* @param y second value
* @return {@code true} if the values are equal.
*/
public static boolean equals(double x, double y) {
return equals(x, y, 1);
}
```
| public static boolean equals(double x, double y) {
return equals(x, y, 1);
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns true iff they are equal as defined by
* {@link #equals(double,double,int) equals(x, y, 1)}.
*
* @param x first value
* @param y second value
* @return {@code true} if the values are equal.
*/
public static boolean equals(double x, double y) {
return equals(x, y, 1);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
4 | 64eb032a2a3291c6afbe24351a0779c56e67ddc7e6c8d5c801dddad54486b02c | private void checkRequiredOptions()
throws MissingOptionException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Throws a {@link MissingOptionException} if all of the
* required options are no present.</p>
*
* @throws MissingOptionException if any of the required Options
* are not present.
*/
private void checkRequiredOptions()
throws MissingOptionException
{
// if there are required options that have not been
// processsed
if (requiredOptions.size() > 0)
{
Iterator iter = requiredOptions.iterator();
StringBuffer buff = new StringBuffer();
// loop through the required options
while (iter.hasNext())
{
buff.append(iter.next());
}
throw new MissingOptionException(buff.toString());
}
}
```
| private void checkRequiredOptions()
throws MissingOptionException
{
// if there are required options that have not been
// processsed
if (requiredOptions.size() > 0)
{
Iterator iter = requiredOptions.iterator();
StringBuffer buff = new StringBuffer();
// loop through the required options
while (iter.hasNext())
{
buff.append(iter.next());
}
throw new MissingOptionException(buff.toString());
}
} | true | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Throws a {@link MissingOptionException} if all of the
* required options are no present.</p>
*
* @throws MissingOptionException if any of the required Options
* are not present.
*/
private void checkRequiredOptions()
throws MissingOptionException
{
// if there are required options that have not been
// processsed
if (requiredOptions.size() > 0)
{
Iterator iter = requiredOptions.iterator();
StringBuffer buff = new StringBuffer();
// loop through the required options
while (iter.hasNext())
{
buff.append(iter.next());
}
throw new MissingOptionException(buff.toString());
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
7 | 650e1b6d7f7ddab93bdee0a6e769a653949625f398fc31f1fcf0494620577a3b | public TokenBuffer deserialize(JsonParser jp, DeserializationContext ctxt) throws IOException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Helper method used by standard deserializer.
*
* @since 2.3
*/
public TokenBuffer deserialize(JsonParser jp, DeserializationContext ctxt) throws IOException
{
copyCurrentStructure(jp);
/* 28-Oct-2014, tatu: As per #592, need to support a special case of starting from
* FIELD_NAME, which is taken to mean that we are missing START_OBJECT, but need
* to assume one did exist.
*/
return this;
}
```
| public TokenBuffer deserialize(JsonParser jp, DeserializationContext ctxt) throws IOException
{
copyCurrentStructure(jp);
/* 28-Oct-2014, tatu: As per #592, need to support a special case of starting from
* FIELD_NAME, which is taken to mean that we are missing START_OBJECT, but need
* to assume one did exist.
*/
return this;
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Helper method used by standard deserializer.
*
* @since 2.3
*/
public TokenBuffer deserialize(JsonParser jp, DeserializationContext ctxt) throws IOException
{
copyCurrentStructure(jp);
/* 28-Oct-2014, tatu: As per #592, need to support a special case of starting from
* FIELD_NAME, which is taken to mean that we are missing START_OBJECT, but need
* to assume one did exist.
*/
return this;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
18 | 65624a4a0260931cb091a97e7a1f2db6ab46cf6e3c09e2069912a7dbe22a72df | public long getDateTimeMillis(int year, int monthOfYear, int dayOfMonth,
int hourOfDay, int minuteOfHour,
int secondOfMinute, int millisOfSecond)
throws IllegalArgumentException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public long getDateTimeMillis(int year, int monthOfYear, int dayOfMonth,
int hourOfDay, int minuteOfHour,
int secondOfMinute, int millisOfSecond)
throws IllegalArgumentException
{
Chronology base;
if ((base = getBase()) != null) {
return base.getDateTimeMillis
(year, monthOfYear, dayOfMonth,
hourOfDay, minuteOfHour, secondOfMinute, millisOfSecond);
}
// Assume date is Gregorian.
long instant;
try {
instant = iGregorianChronology.getDateTimeMillis
(year, monthOfYear, dayOfMonth,
hourOfDay, minuteOfHour, secondOfMinute, millisOfSecond);
} catch (IllegalFieldValueException ex) {
if (monthOfYear != 2 || dayOfMonth != 29) {
throw ex;
}
instant = iGregorianChronology.getDateTimeMillis
(year, monthOfYear, 28,
hourOfDay, minuteOfHour, secondOfMinute, millisOfSecond);
if (instant >= iCutoverMillis) {
throw ex;
}
}
if (instant < iCutoverMillis) {
// Maybe it's Julian.
instant = iJulianChronology.getDateTimeMillis
(year, monthOfYear, dayOfMonth,
hourOfDay, minuteOfHour, secondOfMinute, millisOfSecond);
if (instant >= iCutoverMillis) {
// Okay, it's in the illegal cutover gap.
throw new IllegalArgumentException("Specified date does not exist");
}
}
return instant;
}
```
| public long getDateTimeMillis(int year, int monthOfYear, int dayOfMonth,
int hourOfDay, int minuteOfHour,
int secondOfMinute, int millisOfSecond)
throws IllegalArgumentException
{
Chronology base;
if ((base = getBase()) != null) {
return base.getDateTimeMillis
(year, monthOfYear, dayOfMonth,
hourOfDay, minuteOfHour, secondOfMinute, millisOfSecond);
}
// Assume date is Gregorian.
long instant;
try {
instant = iGregorianChronology.getDateTimeMillis
(year, monthOfYear, dayOfMonth,
hourOfDay, minuteOfHour, secondOfMinute, millisOfSecond);
} catch (IllegalFieldValueException ex) {
if (monthOfYear != 2 || dayOfMonth != 29) {
throw ex;
}
instant = iGregorianChronology.getDateTimeMillis
(year, monthOfYear, 28,
hourOfDay, minuteOfHour, secondOfMinute, millisOfSecond);
if (instant >= iCutoverMillis) {
throw ex;
}
}
if (instant < iCutoverMillis) {
// Maybe it's Julian.
instant = iJulianChronology.getDateTimeMillis
(year, monthOfYear, dayOfMonth,
hourOfDay, minuteOfHour, secondOfMinute, millisOfSecond);
if (instant >= iCutoverMillis) {
// Okay, it's in the illegal cutover gap.
throw new IllegalArgumentException("Specified date does not exist");
}
}
return instant;
} | false | Time | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public long getDateTimeMillis(int year, int monthOfYear, int dayOfMonth,
int hourOfDay, int minuteOfHour,
int secondOfMinute, int millisOfSecond)
throws IllegalArgumentException
{
Chronology base;
if ((base = getBase()) != null) {
return base.getDateTimeMillis
(year, monthOfYear, dayOfMonth,
hourOfDay, minuteOfHour, secondOfMinute, millisOfSecond);
}
// Assume date is Gregorian.
long instant;
try {
instant = iGregorianChronology.getDateTimeMillis
(year, monthOfYear, dayOfMonth,
hourOfDay, minuteOfHour, secondOfMinute, millisOfSecond);
} catch (IllegalFieldValueException ex) {
if (monthOfYear != 2 || dayOfMonth != 29) {
throw ex;
}
instant = iGregorianChronology.getDateTimeMillis
(year, monthOfYear, 28,
hourOfDay, minuteOfHour, secondOfMinute, millisOfSecond);
if (instant >= iCutoverMillis) {
throw ex;
}
}
if (instant < iCutoverMillis) {
// Maybe it's Julian.
instant = iJulianChronology.getDateTimeMillis
(year, monthOfYear, dayOfMonth,
hourOfDay, minuteOfHour, secondOfMinute, millisOfSecond);
if (instant >= iCutoverMillis) {
// Okay, it's in the illegal cutover gap.
throw new IllegalArgumentException("Specified date does not exist");
}
}
return instant;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
7 | 657019c7c20d72a349404c60b21fd844abadbf30472e9c8d53f1d1d2f415929b | public int parseInto(ReadWritableInstant instant, String text, int position) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Parses a datetime from the given text, at the given position, saving the
* result into the fields of the given ReadWritableInstant. If the parse
* succeeds, the return value is the new text position. Note that the parse
* may succeed without fully reading the text and in this case those fields
* that were read will be set.
* <p>
* Only those fields present in the string will be changed in the specified
* instant. All other fields will remain unaltered. Thus if the string only
* contains a year and a month, then the day and time will be retained from
* the input instant. If this is not the behaviour you want, then reset the
* fields before calling this method, or use {@link #parseDateTime(String)}
* or {@link #parseMutableDateTime(String)}.
* <p>
* If it fails, the return value is negative, but the instant may still be
* modified. To determine the position where the parse failed, apply the
* one's complement operator (~) on the return value.
* <p>
* This parse method ignores the {@link #getDefaultYear() default year} and
* parses using the year from the supplied instant based on the chronology
* and time-zone of the supplied instant.
* <p>
* The parse will use the chronology of the instant.
*
* @param instant an instant that will be modified, not null
* @param text the text to parse
* @param position position to start parsing from
* @return new position, negative value means parse failed -
* apply complement operator (~) to get position of failure
* @throws UnsupportedOperationException if parsing is not supported
* @throws IllegalArgumentException if the instant is null
* @throws IllegalArgumentException if any field is out of range
*/
//-----------------------------------------------------------------------
public int parseInto(ReadWritableInstant instant, String text, int position) {
DateTimeParser parser = requireParser();
if (instant == null) {
throw new IllegalArgumentException("Instant must not be null");
}
long instantMillis = instant.getMillis();
Chronology chrono = instant.getChronology();
int defaultYear = DateTimeUtils.getChronology(chrono).year().get(instantMillis);
long instantLocal = instantMillis + chrono.getZone().getOffset(instantMillis);
chrono = selectChronology(chrono);
DateTimeParserBucket bucket = new DateTimeParserBucket(
instantLocal, chrono, iLocale, iPivotYear, defaultYear);
int newPos = parser.parseInto(bucket, text, position);
instant.setMillis(bucket.computeMillis(false, text));
if (iOffsetParsed && bucket.getOffsetInteger() != null) {
int parsedOffset = bucket.getOffsetInteger();
DateTimeZone parsedZone = DateTimeZone.forOffsetMillis(parsedOffset);
chrono = chrono.withZone(parsedZone);
} else if (bucket.getZone() != null) {
chrono = chrono.withZone(bucket.getZone());
}
instant.setChronology(chrono);
if (iZone != null) {
instant.setZone(iZone);
}
return newPos;
}
```
| public int parseInto(ReadWritableInstant instant, String text, int position) {
DateTimeParser parser = requireParser();
if (instant == null) {
throw new IllegalArgumentException("Instant must not be null");
}
long instantMillis = instant.getMillis();
Chronology chrono = instant.getChronology();
int defaultYear = DateTimeUtils.getChronology(chrono).year().get(instantMillis);
long instantLocal = instantMillis + chrono.getZone().getOffset(instantMillis);
chrono = selectChronology(chrono);
DateTimeParserBucket bucket = new DateTimeParserBucket(
instantLocal, chrono, iLocale, iPivotYear, defaultYear);
int newPos = parser.parseInto(bucket, text, position);
instant.setMillis(bucket.computeMillis(false, text));
if (iOffsetParsed && bucket.getOffsetInteger() != null) {
int parsedOffset = bucket.getOffsetInteger();
DateTimeZone parsedZone = DateTimeZone.forOffsetMillis(parsedOffset);
chrono = chrono.withZone(parsedZone);
} else if (bucket.getZone() != null) {
chrono = chrono.withZone(bucket.getZone());
}
instant.setChronology(chrono);
if (iZone != null) {
instant.setZone(iZone);
}
return newPos;
} | false | Time | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Parses a datetime from the given text, at the given position, saving the
* result into the fields of the given ReadWritableInstant. If the parse
* succeeds, the return value is the new text position. Note that the parse
* may succeed without fully reading the text and in this case those fields
* that were read will be set.
* <p>
* Only those fields present in the string will be changed in the specified
* instant. All other fields will remain unaltered. Thus if the string only
* contains a year and a month, then the day and time will be retained from
* the input instant. If this is not the behaviour you want, then reset the
* fields before calling this method, or use {@link #parseDateTime(String)}
* or {@link #parseMutableDateTime(String)}.
* <p>
* If it fails, the return value is negative, but the instant may still be
* modified. To determine the position where the parse failed, apply the
* one's complement operator (~) on the return value.
* <p>
* This parse method ignores the {@link #getDefaultYear() default year} and
* parses using the year from the supplied instant based on the chronology
* and time-zone of the supplied instant.
* <p>
* The parse will use the chronology of the instant.
*
* @param instant an instant that will be modified, not null
* @param text the text to parse
* @param position position to start parsing from
* @return new position, negative value means parse failed -
* apply complement operator (~) to get position of failure
* @throws UnsupportedOperationException if parsing is not supported
* @throws IllegalArgumentException if the instant is null
* @throws IllegalArgumentException if any field is out of range
*/
//-----------------------------------------------------------------------
public int parseInto(ReadWritableInstant instant, String text, int position) {
DateTimeParser parser = requireParser();
if (instant == null) {
throw new IllegalArgumentException("Instant must not be null");
}
long instantMillis = instant.getMillis();
Chronology chrono = instant.getChronology();
int defaultYear = DateTimeUtils.getChronology(chrono).year().get(instantMillis);
long instantLocal = instantMillis + chrono.getZone().getOffset(instantMillis);
chrono = selectChronology(chrono);
DateTimeParserBucket bucket = new DateTimeParserBucket(
instantLocal, chrono, iLocale, iPivotYear, defaultYear);
int newPos = parser.parseInto(bucket, text, position);
instant.setMillis(bucket.computeMillis(false, text));
if (iOffsetParsed && bucket.getOffsetInteger() != null) {
int parsedOffset = bucket.getOffsetInteger();
DateTimeZone parsedZone = DateTimeZone.forOffsetMillis(parsedOffset);
chrono = chrono.withZone(parsedZone);
} else if (bucket.getZone() != null) {
chrono = chrono.withZone(bucket.getZone());
}
instant.setChronology(chrono);
if (iZone != null) {
instant.setZone(iZone);
}
return newPos;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
18 | 658f5867b9708075c5cc8a7f3e6dfd9e50476c82ef6b7a8fbd48f8fc036b0a25 | public long getDateTimeMillis(int year, int monthOfYear, int dayOfMonth,
int hourOfDay, int minuteOfHour,
int secondOfMinute, int millisOfSecond)
throws IllegalArgumentException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public long getDateTimeMillis(int year, int monthOfYear, int dayOfMonth,
int hourOfDay, int minuteOfHour,
int secondOfMinute, int millisOfSecond)
throws IllegalArgumentException
{
Chronology base;
if ((base = getBase()) != null) {
return base.getDateTimeMillis
(year, monthOfYear, dayOfMonth,
hourOfDay, minuteOfHour, secondOfMinute, millisOfSecond);
}
// Assume date is Gregorian.
long instant;
instant = iGregorianChronology.getDateTimeMillis
(year, monthOfYear, dayOfMonth,
hourOfDay, minuteOfHour, secondOfMinute, millisOfSecond);
if (instant < iCutoverMillis) {
// Maybe it's Julian.
instant = iJulianChronology.getDateTimeMillis
(year, monthOfYear, dayOfMonth,
hourOfDay, minuteOfHour, secondOfMinute, millisOfSecond);
if (instant >= iCutoverMillis) {
// Okay, it's in the illegal cutover gap.
throw new IllegalArgumentException("Specified date does not exist");
}
}
return instant;
}
```
| public long getDateTimeMillis(int year, int monthOfYear, int dayOfMonth,
int hourOfDay, int minuteOfHour,
int secondOfMinute, int millisOfSecond)
throws IllegalArgumentException
{
Chronology base;
if ((base = getBase()) != null) {
return base.getDateTimeMillis
(year, monthOfYear, dayOfMonth,
hourOfDay, minuteOfHour, secondOfMinute, millisOfSecond);
}
// Assume date is Gregorian.
long instant;
instant = iGregorianChronology.getDateTimeMillis
(year, monthOfYear, dayOfMonth,
hourOfDay, minuteOfHour, secondOfMinute, millisOfSecond);
if (instant < iCutoverMillis) {
// Maybe it's Julian.
instant = iJulianChronology.getDateTimeMillis
(year, monthOfYear, dayOfMonth,
hourOfDay, minuteOfHour, secondOfMinute, millisOfSecond);
if (instant >= iCutoverMillis) {
// Okay, it's in the illegal cutover gap.
throw new IllegalArgumentException("Specified date does not exist");
}
}
return instant;
} | true | Time | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public long getDateTimeMillis(int year, int monthOfYear, int dayOfMonth,
int hourOfDay, int minuteOfHour,
int secondOfMinute, int millisOfSecond)
throws IllegalArgumentException
{
Chronology base;
if ((base = getBase()) != null) {
return base.getDateTimeMillis
(year, monthOfYear, dayOfMonth,
hourOfDay, minuteOfHour, secondOfMinute, millisOfSecond);
}
// Assume date is Gregorian.
long instant;
instant = iGregorianChronology.getDateTimeMillis
(year, monthOfYear, dayOfMonth,
hourOfDay, minuteOfHour, secondOfMinute, millisOfSecond);
if (instant < iCutoverMillis) {
// Maybe it's Julian.
instant = iJulianChronology.getDateTimeMillis
(year, monthOfYear, dayOfMonth,
hourOfDay, minuteOfHour, secondOfMinute, millisOfSecond);
if (instant >= iCutoverMillis) {
// Okay, it's in the illegal cutover gap.
throw new IllegalArgumentException("Specified date does not exist");
}
}
return instant;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
11 | 65fd36a052de259bba7996bbe80da58d084b409eb923dfe994bb6f02fcc59234 | private void visitGetProp(NodeTraversal t, Node n, Node parent) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Visits a GETPROP node.
*
* @param t The node traversal object that supplies context, such as the
* scope chain to use in name lookups as well as error reporting.
* @param n The node being visited.
* @param parent The parent of <code>n</code>
*/
private void visitGetProp(NodeTraversal t, Node n, Node parent) {
// obj.prop or obj.method()
// Lots of types can appear on the left, a call to a void function can
// never be on the left. getPropertyType will decide what is acceptable
// and what isn't.
Node property = n.getLastChild();
Node objNode = n.getFirstChild();
JSType childType = getJSType(objNode);
if (childType.isDict()) {
report(t, property, TypeValidator.ILLEGAL_PROPERTY_ACCESS, "'.'", "dict");
} else if (validator.expectNotNullOrUndefined(t, n, childType,
"No properties on this expression", getNativeType(OBJECT_TYPE))) {
checkPropertyAccess(childType, property.getString(), t, n);
}
ensureTyped(t, n);
}
```
| private void visitGetProp(NodeTraversal t, Node n, Node parent) {
// obj.prop or obj.method()
// Lots of types can appear on the left, a call to a void function can
// never be on the left. getPropertyType will decide what is acceptable
// and what isn't.
Node property = n.getLastChild();
Node objNode = n.getFirstChild();
JSType childType = getJSType(objNode);
if (childType.isDict()) {
report(t, property, TypeValidator.ILLEGAL_PROPERTY_ACCESS, "'.'", "dict");
} else if (validator.expectNotNullOrUndefined(t, n, childType,
"No properties on this expression", getNativeType(OBJECT_TYPE))) {
checkPropertyAccess(childType, property.getString(), t, n);
}
ensureTyped(t, n);
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Visits a GETPROP node.
*
* @param t The node traversal object that supplies context, such as the
* scope chain to use in name lookups as well as error reporting.
* @param n The node being visited.
* @param parent The parent of <code>n</code>
*/
private void visitGetProp(NodeTraversal t, Node n, Node parent) {
// obj.prop or obj.method()
// Lots of types can appear on the left, a call to a void function can
// never be on the left. getPropertyType will decide what is acceptable
// and what isn't.
Node property = n.getLastChild();
Node objNode = n.getFirstChild();
JSType childType = getJSType(objNode);
if (childType.isDict()) {
report(t, property, TypeValidator.ILLEGAL_PROPERTY_ACCESS, "'.'", "dict");
} else if (validator.expectNotNullOrUndefined(t, n, childType,
"No properties on this expression", getNativeType(OBJECT_TYPE))) {
checkPropertyAccess(childType, property.getString(), t, n);
}
ensureTyped(t, n);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
8 | 6667d5177aef6505a149a75ca96c1646e63edbfe45099eac8d072f21cf118ed0 | public static long parseOctal(final byte[] buffer, final int offset, final int length) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Parse an octal string from a buffer.
* Leading spaces are ignored.
* The buffer must contain a trailing space or NUL,
* and may contain an additional trailing space or NUL.
*
* The input buffer is allowed to contain all NULs,
* in which case the method returns 0L
* (this allows for missing fields).
*
* @param buffer The buffer from which to parse.
* @param offset The offset into the buffer from which to parse.
* @param length The maximum number of bytes to parse - must be at least 2 bytes.
* @return The long value of the octal string.
* @throws IllegalArgumentException if the trailing space/NUL is missing or if a invalid byte is detected.
*/
public static long parseOctal(final byte[] buffer, final int offset, final int length) {
long result = 0;
int end = offset + length;
int start = offset;
if (length < 2){
throw new IllegalArgumentException("Length "+length+" must be at least 2");
}
boolean allNUL = true;
for (int i = start; i < end; i++){
if (buffer[i] != 0){
allNUL = false;
break;
}
}
if (allNUL) {
return 0L;
}
// Skip leading spaces
while (start < end){
if (buffer[start] == ' '){
start++;
} else {
break;
}
}
// Must have trailing NUL or space
byte trailer;
trailer = buffer[end-1];
if (trailer == 0 || trailer == ' '){
end--;
} else {
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, end-1, trailer));
}
// May have additional NUL or space
trailer = buffer[end-1];
if (trailer == 0 || trailer == ' '){
end--;
}
for ( ;start < end; start++) {
final byte currentByte = buffer[start];
// CheckStyle:MagicNumber OFF
if (currentByte < '0' || currentByte > '7'){
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, start, currentByte));
}
result = (result << 3) + (currentByte - '0'); // convert from ASCII
// CheckStyle:MagicNumber ON
}
return result;
}
```
| public static long parseOctal(final byte[] buffer, final int offset, final int length) {
long result = 0;
int end = offset + length;
int start = offset;
if (length < 2){
throw new IllegalArgumentException("Length "+length+" must be at least 2");
}
boolean allNUL = true;
for (int i = start; i < end; i++){
if (buffer[i] != 0){
allNUL = false;
break;
}
}
if (allNUL) {
return 0L;
}
// Skip leading spaces
while (start < end){
if (buffer[start] == ' '){
start++;
} else {
break;
}
}
// Must have trailing NUL or space
byte trailer;
trailer = buffer[end-1];
if (trailer == 0 || trailer == ' '){
end--;
} else {
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, end-1, trailer));
}
// May have additional NUL or space
trailer = buffer[end-1];
if (trailer == 0 || trailer == ' '){
end--;
}
for ( ;start < end; start++) {
final byte currentByte = buffer[start];
// CheckStyle:MagicNumber OFF
if (currentByte < '0' || currentByte > '7'){
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, start, currentByte));
}
result = (result << 3) + (currentByte - '0'); // convert from ASCII
// CheckStyle:MagicNumber ON
}
return result;
} | false | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Parse an octal string from a buffer.
* Leading spaces are ignored.
* The buffer must contain a trailing space or NUL,
* and may contain an additional trailing space or NUL.
*
* The input buffer is allowed to contain all NULs,
* in which case the method returns 0L
* (this allows for missing fields).
*
* @param buffer The buffer from which to parse.
* @param offset The offset into the buffer from which to parse.
* @param length The maximum number of bytes to parse - must be at least 2 bytes.
* @return The long value of the octal string.
* @throws IllegalArgumentException if the trailing space/NUL is missing or if a invalid byte is detected.
*/
public static long parseOctal(final byte[] buffer, final int offset, final int length) {
long result = 0;
int end = offset + length;
int start = offset;
if (length < 2){
throw new IllegalArgumentException("Length "+length+" must be at least 2");
}
boolean allNUL = true;
for (int i = start; i < end; i++){
if (buffer[i] != 0){
allNUL = false;
break;
}
}
if (allNUL) {
return 0L;
}
// Skip leading spaces
while (start < end){
if (buffer[start] == ' '){
start++;
} else {
break;
}
}
// Must have trailing NUL or space
byte trailer;
trailer = buffer[end-1];
if (trailer == 0 || trailer == ' '){
end--;
} else {
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, end-1, trailer));
}
// May have additional NUL or space
trailer = buffer[end-1];
if (trailer == 0 || trailer == ' '){
end--;
}
for ( ;start < end; start++) {
final byte currentByte = buffer[start];
// CheckStyle:MagicNumber OFF
if (currentByte < '0' || currentByte > '7'){
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, start, currentByte));
}
result = (result << 3) + (currentByte - '0'); // convert from ASCII
// CheckStyle:MagicNumber ON
}
return result;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
14 | 6667d5177aef6505a149a75ca96c1646e63edbfe45099eac8d072f21cf118ed0 | public static long parseOctal(final byte[] buffer, final int offset, final int length) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Parse an octal string from a buffer.
*
* <p>Leading spaces are ignored.
* The buffer must contain a trailing space or NUL,
* and may contain an additional trailing space or NUL.</p>
*
* <p>The input buffer is allowed to contain all NULs,
* in which case the method returns 0L
* (this allows for missing fields).</p>
*
* <p>To work-around some tar implementations that insert a
* leading NUL this method returns 0 if it detects a leading NUL
* since Commons Compress 1.4.</p>
*
* @param buffer The buffer from which to parse.
* @param offset The offset into the buffer from which to parse.
* @param length The maximum number of bytes to parse - must be at least 2 bytes.
* @return The long value of the octal string.
* @throws IllegalArgumentException if the trailing space/NUL is missing or if a invalid byte is detected.
*/
public static long parseOctal(final byte[] buffer, final int offset, final int length) {
long result = 0;
int end = offset + length;
int start = offset;
if (length < 2){
throw new IllegalArgumentException("Length "+length+" must be at least 2");
}
boolean allNUL = true;
for (int i = start; i < end; i++){
if (buffer[i] != 0){
allNUL = false;
break;
}
}
if (allNUL) {
return 0L;
}
// Skip leading spaces
while (start < end){
if (buffer[start] == ' '){
start++;
} else {
break;
}
}
// Must have trailing NUL or space
byte trailer;
trailer = buffer[end-1];
if (trailer == 0 || trailer == ' '){
end--;
} else {
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, end-1, trailer));
}
// May have additional NUL or space
trailer = buffer[end-1];
if (trailer == 0 || trailer == ' '){
end--;
}
for ( ;start < end; start++) {
final byte currentByte = buffer[start];
// CheckStyle:MagicNumber OFF
if (currentByte < '0' || currentByte > '7'){
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, start, currentByte));
}
result = (result << 3) + (currentByte - '0'); // convert from ASCII
// CheckStyle:MagicNumber ON
}
return result;
}
```
| public static long parseOctal(final byte[] buffer, final int offset, final int length) {
long result = 0;
int end = offset + length;
int start = offset;
if (length < 2){
throw new IllegalArgumentException("Length "+length+" must be at least 2");
}
boolean allNUL = true;
for (int i = start; i < end; i++){
if (buffer[i] != 0){
allNUL = false;
break;
}
}
if (allNUL) {
return 0L;
}
// Skip leading spaces
while (start < end){
if (buffer[start] == ' '){
start++;
} else {
break;
}
}
// Must have trailing NUL or space
byte trailer;
trailer = buffer[end-1];
if (trailer == 0 || trailer == ' '){
end--;
} else {
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, end-1, trailer));
}
// May have additional NUL or space
trailer = buffer[end-1];
if (trailer == 0 || trailer == ' '){
end--;
}
for ( ;start < end; start++) {
final byte currentByte = buffer[start];
// CheckStyle:MagicNumber OFF
if (currentByte < '0' || currentByte > '7'){
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, start, currentByte));
}
result = (result << 3) + (currentByte - '0'); // convert from ASCII
// CheckStyle:MagicNumber ON
}
return result;
} | true | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Parse an octal string from a buffer.
*
* <p>Leading spaces are ignored.
* The buffer must contain a trailing space or NUL,
* and may contain an additional trailing space or NUL.</p>
*
* <p>The input buffer is allowed to contain all NULs,
* in which case the method returns 0L
* (this allows for missing fields).</p>
*
* <p>To work-around some tar implementations that insert a
* leading NUL this method returns 0 if it detects a leading NUL
* since Commons Compress 1.4.</p>
*
* @param buffer The buffer from which to parse.
* @param offset The offset into the buffer from which to parse.
* @param length The maximum number of bytes to parse - must be at least 2 bytes.
* @return The long value of the octal string.
* @throws IllegalArgumentException if the trailing space/NUL is missing or if a invalid byte is detected.
*/
public static long parseOctal(final byte[] buffer, final int offset, final int length) {
long result = 0;
int end = offset + length;
int start = offset;
if (length < 2){
throw new IllegalArgumentException("Length "+length+" must be at least 2");
}
boolean allNUL = true;
for (int i = start; i < end; i++){
if (buffer[i] != 0){
allNUL = false;
break;
}
}
if (allNUL) {
return 0L;
}
// Skip leading spaces
while (start < end){
if (buffer[start] == ' '){
start++;
} else {
break;
}
}
// Must have trailing NUL or space
byte trailer;
trailer = buffer[end-1];
if (trailer == 0 || trailer == ' '){
end--;
} else {
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, end-1, trailer));
}
// May have additional NUL or space
trailer = buffer[end-1];
if (trailer == 0 || trailer == ' '){
end--;
}
for ( ;start < end; start++) {
final byte currentByte = buffer[start];
// CheckStyle:MagicNumber OFF
if (currentByte < '0' || currentByte > '7'){
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, start, currentByte));
}
result = (result << 3) + (currentByte - '0'); // convert from ASCII
// CheckStyle:MagicNumber ON
}
return result;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
34 | 66ababb77236f6df9ba50a3a5b0c615efbdf0bab4ae8ef0196ea92f180c4a68c | int nextIndexOf(CharSequence seq) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns the number of characters between the current position and the next instance of the input sequence
*
* @param seq scan target
* @return offset between current position and next instance of target. -1 if not found.
*/
int nextIndexOf(CharSequence seq) {
// doesn't handle scanning for surrogates
char startChar = seq.charAt(0);
for (int offset = pos; offset < length; offset++) {
// scan to first instance of startchar:
if (startChar != input[offset])
while(++offset < length && startChar != input[offset]);
int i = offset + 1;
int last = i + seq.length()-1;
if (offset < length) {
for (int j = 1; i < last && seq.charAt(j) == input[i]; i++, j++);
if (i == last) // found full sequence
return offset - pos;
}
}
return -1;
}
```
| int nextIndexOf(CharSequence seq) {
// doesn't handle scanning for surrogates
char startChar = seq.charAt(0);
for (int offset = pos; offset < length; offset++) {
// scan to first instance of startchar:
if (startChar != input[offset])
while(++offset < length && startChar != input[offset]);
int i = offset + 1;
int last = i + seq.length()-1;
if (offset < length) {
for (int j = 1; i < last && seq.charAt(j) == input[i]; i++, j++);
if (i == last) // found full sequence
return offset - pos;
}
}
return -1;
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns the number of characters between the current position and the next instance of the input sequence
*
* @param seq scan target
* @return offset between current position and next instance of target. -1 if not found.
*/
int nextIndexOf(CharSequence seq) {
// doesn't handle scanning for surrogates
char startChar = seq.charAt(0);
for (int offset = pos; offset < length; offset++) {
// scan to first instance of startchar:
if (startChar != input[offset])
while(++offset < length && startChar != input[offset]);
int i = offset + 1;
int last = i + seq.length()-1;
if (offset < length) {
for (int j = 1; i < last && seq.charAt(j) == input[i]; i++, j++);
if (i == last) // found full sequence
return offset - pos;
}
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
33 | 66f24deeae9cb99ce86011bd56a66d86189bd8a51d5e0238d75956098ac13b47 | public static Class<?>[] toClass(Object[] array) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Converts an array of <code>Object</code> in to an array of <code>Class</code> objects.
* If any of these objects is null, a null element will be inserted into the array.</p>
*
* <p>This method returns <code>null</code> for a <code>null</code> input array.</p>
*
* @param array an <code>Object</code> array
* @return a <code>Class</code> array, <code>null</code> if null array input
* @since 2.4
*/
public static Class<?>[] toClass(Object[] array) {
if (array == null) {
return null;
} else if (array.length == 0) {
return ArrayUtils.EMPTY_CLASS_ARRAY;
}
Class<?>[] classes = new Class[array.length];
for (int i = 0; i < array.length; i++) {
classes[i] = array[i].getClass();
}
return classes;
}
```
| public static Class<?>[] toClass(Object[] array) {
if (array == null) {
return null;
} else if (array.length == 0) {
return ArrayUtils.EMPTY_CLASS_ARRAY;
}
Class<?>[] classes = new Class[array.length];
for (int i = 0; i < array.length; i++) {
classes[i] = array[i].getClass();
}
return classes;
} | true | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Converts an array of <code>Object</code> in to an array of <code>Class</code> objects.
* If any of these objects is null, a null element will be inserted into the array.</p>
*
* <p>This method returns <code>null</code> for a <code>null</code> input array.</p>
*
* @param array an <code>Object</code> array
* @return a <code>Class</code> array, <code>null</code> if null array input
* @since 2.4
*/
public static Class<?>[] toClass(Object[] array) {
if (array == null) {
return null;
} else if (array.length == 0) {
return ArrayUtils.EMPTY_CLASS_ARRAY;
}
Class<?>[] classes = new Class[array.length];
for (int i = 0; i < array.length; i++) {
classes[i] = array[i].getClass();
}
return classes;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
10 | 672a66176d765c230cd662b21340159061af6eb72555d71ec8c29bc14db6e6a7 | static boolean mayBeString(Node n, boolean recurse) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
static boolean mayBeString(Node n, boolean recurse) {
if (recurse) {
return anyResultsMatch(n, MAY_BE_STRING_PREDICATE);
} else {
return mayBeStringHelper(n);
}
}
```
| static boolean mayBeString(Node n, boolean recurse) {
if (recurse) {
return anyResultsMatch(n, MAY_BE_STRING_PREDICATE);
} else {
return mayBeStringHelper(n);
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
static boolean mayBeString(Node n, boolean recurse) {
if (recurse) {
return anyResultsMatch(n, MAY_BE_STRING_PREDICATE);
} else {
return mayBeStringHelper(n);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
59 | 68420d5f3d5773f9c3eaaefdbae34c8ea7f2d6f71154a5907e4b912cc566b22a | public static float max(final float a, final float b) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/** Compute the maximum of two values
* @param a first value
* @param b second value
* @return b if a is lesser or equal to b, a otherwise
*/
public static float max(final float a, final float b) {
return (a <= b) ? b : (Float.isNaN(a + b) ? Float.NaN : a);
}
```
| public static float max(final float a, final float b) {
return (a <= b) ? b : (Float.isNaN(a + b) ? Float.NaN : a);
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/** Compute the maximum of two values
* @param a first value
* @param b second value
* @return b if a is lesser or equal to b, a otherwise
*/
public static float max(final float a, final float b) {
return (a <= b) ? b : (Float.isNaN(a + b) ? Float.NaN : a);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
60 | 687352afd4a8453dd137321c43d7c47ed8e72fdafe623957cbe731da06f8d5f1 | public double cumulativeProbability(double x) throws MathException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* For this distribution, {@code X}, this method returns {@code P(X < x)}.
* If {@code x}is more than 40 standard deviations from the mean, 0 or 1 is returned,
* as in these cases the actual value is within {@code Double.MIN_VALUE} of 0 or 1.
*
* @param x Value at which the CDF is evaluated.
* @return CDF evaluated at {@code x}.
* @throws MathException if the algorithm fails to converge
*/
public double cumulativeProbability(double x) throws MathException {
final double dev = x - mean;
try {
return 0.5 * (1.0 + Erf.erf((dev) /
(standardDeviation * FastMath.sqrt(2.0))));
} catch (MaxIterationsExceededException ex) {
if (x < (mean - 20 * standardDeviation)) { // JDK 1.5 blows at 38
return 0;
} else if (x > (mean + 20 * standardDeviation)) {
return 1;
} else {
throw ex;
}
}
}
```
| public double cumulativeProbability(double x) throws MathException {
final double dev = x - mean;
try {
return 0.5 * (1.0 + Erf.erf((dev) /
(standardDeviation * FastMath.sqrt(2.0))));
} catch (MaxIterationsExceededException ex) {
if (x < (mean - 20 * standardDeviation)) { // JDK 1.5 blows at 38
return 0;
} else if (x > (mean + 20 * standardDeviation)) {
return 1;
} else {
throw ex;
}
}
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* For this distribution, {@code X}, this method returns {@code P(X < x)}.
* If {@code x}is more than 40 standard deviations from the mean, 0 or 1 is returned,
* as in these cases the actual value is within {@code Double.MIN_VALUE} of 0 or 1.
*
* @param x Value at which the CDF is evaluated.
* @return CDF evaluated at {@code x}.
* @throws MathException if the algorithm fails to converge
*/
public double cumulativeProbability(double x) throws MathException {
final double dev = x - mean;
try {
return 0.5 * (1.0 + Erf.erf((dev) /
(standardDeviation * FastMath.sqrt(2.0))));
} catch (MaxIterationsExceededException ex) {
if (x < (mean - 20 * standardDeviation)) { // JDK 1.5 blows at 38
return 0;
} else if (x > (mean + 20 * standardDeviation)) {
return 1;
} else {
throw ex;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
115 | 688ae47f4a9486f8378a54c9ad2b17c4b8b021d062c0433ecae02d1a4993c082 | private CanInlineResult canInlineReferenceDirectly(
Node callNode, Node fnNode) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Determines whether a function can be inlined at a particular call site.
* There are several criteria that the function and reference must hold in
* order for the functions to be inlined:
* 1) If a call's arguments have side effects,
* the corresponding argument in the function must only be referenced once.
* For instance, this will not be inlined:
* <pre>
* function foo(a) { return a + a }
* x = foo(i++);
* </pre>
*/
private CanInlineResult canInlineReferenceDirectly(
Node callNode, Node fnNode) {
if (!isDirectCallNodeReplacementPossible(fnNode)) {
return CanInlineResult.NO;
}
Node block = fnNode.getLastChild();
boolean hasSideEffects = false;
if (block.hasChildren()) {
Preconditions.checkState(block.hasOneChild());
Node stmt = block.getFirstChild();
if (stmt.isReturn()) {
hasSideEffects = NodeUtil.mayHaveSideEffects(stmt.getFirstChild(), compiler);
}
}
// CALL NODE: [ NAME, ARG1, ARG2, ... ]
Node cArg = callNode.getFirstChild().getNext();
// Functions called via 'call' and 'apply' have a this-object as
// the first parameter, but this is not part of the called function's
// parameter list.
if (!callNode.getFirstChild().isName()) {
if (NodeUtil.isFunctionObjectCall(callNode)) {
// TODO(johnlenz): Support replace this with a value.
if (cArg == null || !cArg.isThis()) {
return CanInlineResult.NO;
}
cArg = cArg.getNext();
} else {
// ".apply" call should be filtered before this.
Preconditions.checkState(!NodeUtil.isFunctionObjectApply(callNode));
}
}
// FUNCTION NODE -> LP NODE: [ ARG1, ARG2, ... ]
Node fnParam = NodeUtil.getFunctionParameters(fnNode).getFirstChild();
while (cArg != null || fnParam != null) {
// For each named parameter check if a mutable argument use more than one.
if (fnParam != null) {
if (cArg != null) {
if (hasSideEffects && NodeUtil.canBeSideEffected(cArg)) {
return CanInlineResult.NO;
}
// Check for arguments that are evaluated more than once.
// Note: Unlike block inlining, there it is not possible that a
// parameter reference will be in a loop.
if (NodeUtil.mayEffectMutableState(cArg, compiler)
&& NodeUtil.getNameReferenceCount(
block, fnParam.getString()) > 1) {
return CanInlineResult.NO;
}
}
// Move to the next name.
fnParam = fnParam.getNext();
}
// For every call argument check for side-effects, even if there
// isn't a named parameter to match.
if (cArg != null) {
if (NodeUtil.mayHaveSideEffects(cArg, compiler)) {
return CanInlineResult.NO;
}
cArg = cArg.getNext();
}
}
return CanInlineResult.YES;
}
```
| private CanInlineResult canInlineReferenceDirectly(
Node callNode, Node fnNode) {
if (!isDirectCallNodeReplacementPossible(fnNode)) {
return CanInlineResult.NO;
}
Node block = fnNode.getLastChild();
boolean hasSideEffects = false;
if (block.hasChildren()) {
Preconditions.checkState(block.hasOneChild());
Node stmt = block.getFirstChild();
if (stmt.isReturn()) {
hasSideEffects = NodeUtil.mayHaveSideEffects(stmt.getFirstChild(), compiler);
}
}
// CALL NODE: [ NAME, ARG1, ARG2, ... ]
Node cArg = callNode.getFirstChild().getNext();
// Functions called via 'call' and 'apply' have a this-object as
// the first parameter, but this is not part of the called function's
// parameter list.
if (!callNode.getFirstChild().isName()) {
if (NodeUtil.isFunctionObjectCall(callNode)) {
// TODO(johnlenz): Support replace this with a value.
if (cArg == null || !cArg.isThis()) {
return CanInlineResult.NO;
}
cArg = cArg.getNext();
} else {
// ".apply" call should be filtered before this.
Preconditions.checkState(!NodeUtil.isFunctionObjectApply(callNode));
}
}
// FUNCTION NODE -> LP NODE: [ ARG1, ARG2, ... ]
Node fnParam = NodeUtil.getFunctionParameters(fnNode).getFirstChild();
while (cArg != null || fnParam != null) {
// For each named parameter check if a mutable argument use more than one.
if (fnParam != null) {
if (cArg != null) {
if (hasSideEffects && NodeUtil.canBeSideEffected(cArg)) {
return CanInlineResult.NO;
}
// Check for arguments that are evaluated more than once.
// Note: Unlike block inlining, there it is not possible that a
// parameter reference will be in a loop.
if (NodeUtil.mayEffectMutableState(cArg, compiler)
&& NodeUtil.getNameReferenceCount(
block, fnParam.getString()) > 1) {
return CanInlineResult.NO;
}
}
// Move to the next name.
fnParam = fnParam.getNext();
}
// For every call argument check for side-effects, even if there
// isn't a named parameter to match.
if (cArg != null) {
if (NodeUtil.mayHaveSideEffects(cArg, compiler)) {
return CanInlineResult.NO;
}
cArg = cArg.getNext();
}
}
return CanInlineResult.YES;
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Determines whether a function can be inlined at a particular call site.
* There are several criteria that the function and reference must hold in
* order for the functions to be inlined:
* 1) If a call's arguments have side effects,
* the corresponding argument in the function must only be referenced once.
* For instance, this will not be inlined:
* <pre>
* function foo(a) { return a + a }
* x = foo(i++);
* </pre>
*/
private CanInlineResult canInlineReferenceDirectly(
Node callNode, Node fnNode) {
if (!isDirectCallNodeReplacementPossible(fnNode)) {
return CanInlineResult.NO;
}
Node block = fnNode.getLastChild();
boolean hasSideEffects = false;
if (block.hasChildren()) {
Preconditions.checkState(block.hasOneChild());
Node stmt = block.getFirstChild();
if (stmt.isReturn()) {
hasSideEffects = NodeUtil.mayHaveSideEffects(stmt.getFirstChild(), compiler);
}
}
// CALL NODE: [ NAME, ARG1, ARG2, ... ]
Node cArg = callNode.getFirstChild().getNext();
// Functions called via 'call' and 'apply' have a this-object as
// the first parameter, but this is not part of the called function's
// parameter list.
if (!callNode.getFirstChild().isName()) {
if (NodeUtil.isFunctionObjectCall(callNode)) {
// TODO(johnlenz): Support replace this with a value.
if (cArg == null || !cArg.isThis()) {
return CanInlineResult.NO;
}
cArg = cArg.getNext();
} else {
// ".apply" call should be filtered before this.
Preconditions.checkState(!NodeUtil.isFunctionObjectApply(callNode));
}
}
// FUNCTION NODE -> LP NODE: [ ARG1, ARG2, ... ]
Node fnParam = NodeUtil.getFunctionParameters(fnNode).getFirstChild();
while (cArg != null || fnParam != null) {
// For each named parameter check if a mutable argument use more than one.
if (fnParam != null) {
if (cArg != null) {
if (hasSideEffects && NodeUtil.canBeSideEffected(cArg)) {
return CanInlineResult.NO;
}
// Check for arguments that are evaluated more than once.
// Note: Unlike block inlining, there it is not possible that a
// parameter reference will be in a loop.
if (NodeUtil.mayEffectMutableState(cArg, compiler)
&& NodeUtil.getNameReferenceCount(
block, fnParam.getString()) > 1) {
return CanInlineResult.NO;
}
}
// Move to the next name.
fnParam = fnParam.getNext();
}
// For every call argument check for side-effects, even if there
// isn't a named parameter to match.
if (cArg != null) {
if (NodeUtil.mayHaveSideEffects(cArg, compiler)) {
return CanInlineResult.NO;
}
cArg = cArg.getNext();
}
}
return CanInlineResult.YES;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
3 | 696a9ae3441e5b7ac55b7296922d2027479d6a48d14f55301798b35e544aa263 | public TimeSeries createCopy(int start, int end)
throws CloneNotSupportedException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Creates a new timeseries by copying a subset of the data in this time
* series.
*
* @param start the index of the first time period to copy.
* @param end the index of the last time period to copy.
*
* @return A series containing a copy of this times series from start until
* end.
*
* @throws CloneNotSupportedException if there is a cloning problem.
*/
public TimeSeries createCopy(int start, int end)
throws CloneNotSupportedException {
if (start < 0) {
throw new IllegalArgumentException("Requires start >= 0.");
}
if (end < start) {
throw new IllegalArgumentException("Requires start <= end.");
}
TimeSeries copy = (TimeSeries) super.clone();
copy.minY = Double.NaN;
copy.maxY = Double.NaN;
copy.data = new java.util.ArrayList();
if (this.data.size() > 0) {
for (int index = start; index <= end; index++) {
TimeSeriesDataItem item
= (TimeSeriesDataItem) this.data.get(index);
TimeSeriesDataItem clone = (TimeSeriesDataItem) item.clone();
try {
copy.add(clone);
}
catch (SeriesException e) {
e.printStackTrace();
}
}
}
return copy;
}
```
| public TimeSeries createCopy(int start, int end)
throws CloneNotSupportedException {
if (start < 0) {
throw new IllegalArgumentException("Requires start >= 0.");
}
if (end < start) {
throw new IllegalArgumentException("Requires start <= end.");
}
TimeSeries copy = (TimeSeries) super.clone();
copy.minY = Double.NaN;
copy.maxY = Double.NaN;
copy.data = new java.util.ArrayList();
if (this.data.size() > 0) {
for (int index = start; index <= end; index++) {
TimeSeriesDataItem item
= (TimeSeriesDataItem) this.data.get(index);
TimeSeriesDataItem clone = (TimeSeriesDataItem) item.clone();
try {
copy.add(clone);
}
catch (SeriesException e) {
e.printStackTrace();
}
}
}
return copy;
} | false | Chart | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Creates a new timeseries by copying a subset of the data in this time
* series.
*
* @param start the index of the first time period to copy.
* @param end the index of the last time period to copy.
*
* @return A series containing a copy of this times series from start until
* end.
*
* @throws CloneNotSupportedException if there is a cloning problem.
*/
public TimeSeries createCopy(int start, int end)
throws CloneNotSupportedException {
if (start < 0) {
throw new IllegalArgumentException("Requires start >= 0.");
}
if (end < start) {
throw new IllegalArgumentException("Requires start <= end.");
}
TimeSeries copy = (TimeSeries) super.clone();
copy.minY = Double.NaN;
copy.maxY = Double.NaN;
copy.data = new java.util.ArrayList();
if (this.data.size() > 0) {
for (int index = start; index <= end; index++) {
TimeSeriesDataItem item
= (TimeSeriesDataItem) this.data.get(index);
TimeSeriesDataItem clone = (TimeSeriesDataItem) item.clone();
try {
copy.add(clone);
}
catch (SeriesException e) {
e.printStackTrace();
}
}
}
return copy;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
91 | 6987ce6ec6d07f46e036c7f167f0e44fe5616384e0252b2c121df7470612a3c0 | public int compareTo(Fraction object) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Compares this object to another based on size.
* @param object the object to compare to
* @return -1 if this is less than <tt>object</tt>, +1 if this is greater
* than <tt>object</tt>, 0 if they are equal.
*/
public int compareTo(Fraction object) {
long nOd = ((long) numerator) * object.denominator;
long dOn = ((long) denominator) * object.numerator;
return (nOd < dOn) ? -1 : ((nOd > dOn) ? +1 : 0);
}
```
| public int compareTo(Fraction object) {
long nOd = ((long) numerator) * object.denominator;
long dOn = ((long) denominator) * object.numerator;
return (nOd < dOn) ? -1 : ((nOd > dOn) ? +1 : 0);
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Compares this object to another based on size.
* @param object the object to compare to
* @return -1 if this is less than <tt>object</tt>, +1 if this is greater
* than <tt>object</tt>, 0 if they are equal.
*/
public int compareTo(Fraction object) {
long nOd = ((long) numerator) * object.denominator;
long dOn = ((long) denominator) * object.numerator;
return (nOd < dOn) ? -1 : ((nOd > dOn) ? +1 : 0);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
10 | 6a413abff7b5e20f816be43bf3aae9aed2f57d738cef2ba045dd51f22893e023 | public void atan2(final double[] y, final int yOffset,
final double[] x, final int xOffset,
final double[] result, final int resultOffset) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/** Compute two arguments arc tangent of a derivative structure.
* @param y array holding the first operand
* @param yOffset offset of the first operand in its array
* @param x array holding the second operand
* @param xOffset offset of the second operand in its array
* @param result array where result must be stored (for
* two arguments arc tangent the result array <em>cannot</em>
* be the input array)
* @param resultOffset offset of the result in its array
*/
public void atan2(final double[] y, final int yOffset,
final double[] x, final int xOffset,
final double[] result, final int resultOffset) {
// compute r = sqrt(x^2+y^2)
double[] tmp1 = new double[getSize()];
multiply(x, xOffset, x, xOffset, tmp1, 0); // x^2
double[] tmp2 = new double[getSize()];
multiply(y, yOffset, y, yOffset, tmp2, 0); // y^2
add(tmp1, 0, tmp2, 0, tmp2, 0); // x^2 + y^2
rootN(tmp2, 0, 2, tmp1, 0); // r = sqrt(x^2 + y^2)
if (x[xOffset] >= 0) {
// compute atan2(y, x) = 2 atan(y / (r + x))
add(tmp1, 0, x, xOffset, tmp2, 0); // r + x
divide(y, yOffset, tmp2, 0, tmp1, 0); // y /(r + x)
atan(tmp1, 0, tmp2, 0); // atan(y / (r + x))
for (int i = 0; i < tmp2.length; ++i) {
result[resultOffset + i] = 2 * tmp2[i]; // 2 * atan(y / (r + x))
}
} else {
// compute atan2(y, x) = +/- pi - 2 atan(y / (r - x))
subtract(tmp1, 0, x, xOffset, tmp2, 0); // r - x
divide(y, yOffset, tmp2, 0, tmp1, 0); // y /(r - x)
atan(tmp1, 0, tmp2, 0); // atan(y / (r - x))
result[resultOffset] =
((tmp2[0] <= 0) ? -FastMath.PI : FastMath.PI) - 2 * tmp2[0]; // +/-pi - 2 * atan(y / (r - x))
for (int i = 1; i < tmp2.length; ++i) {
result[resultOffset + i] = -2 * tmp2[i]; // +/-pi - 2 * atan(y / (r - x))
}
}
// fix value to take special cases (+0/+0, +0/-0, -0/+0, -0/-0, +/-infinity) correctly
}
```
| public void atan2(final double[] y, final int yOffset,
final double[] x, final int xOffset,
final double[] result, final int resultOffset) {
// compute r = sqrt(x^2+y^2)
double[] tmp1 = new double[getSize()];
multiply(x, xOffset, x, xOffset, tmp1, 0); // x^2
double[] tmp2 = new double[getSize()];
multiply(y, yOffset, y, yOffset, tmp2, 0); // y^2
add(tmp1, 0, tmp2, 0, tmp2, 0); // x^2 + y^2
rootN(tmp2, 0, 2, tmp1, 0); // r = sqrt(x^2 + y^2)
if (x[xOffset] >= 0) {
// compute atan2(y, x) = 2 atan(y / (r + x))
add(tmp1, 0, x, xOffset, tmp2, 0); // r + x
divide(y, yOffset, tmp2, 0, tmp1, 0); // y /(r + x)
atan(tmp1, 0, tmp2, 0); // atan(y / (r + x))
for (int i = 0; i < tmp2.length; ++i) {
result[resultOffset + i] = 2 * tmp2[i]; // 2 * atan(y / (r + x))
}
} else {
// compute atan2(y, x) = +/- pi - 2 atan(y / (r - x))
subtract(tmp1, 0, x, xOffset, tmp2, 0); // r - x
divide(y, yOffset, tmp2, 0, tmp1, 0); // y /(r - x)
atan(tmp1, 0, tmp2, 0); // atan(y / (r - x))
result[resultOffset] =
((tmp2[0] <= 0) ? -FastMath.PI : FastMath.PI) - 2 * tmp2[0]; // +/-pi - 2 * atan(y / (r - x))
for (int i = 1; i < tmp2.length; ++i) {
result[resultOffset + i] = -2 * tmp2[i]; // +/-pi - 2 * atan(y / (r - x))
}
}
// fix value to take special cases (+0/+0, +0/-0, -0/+0, -0/-0, +/-infinity) correctly
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/** Compute two arguments arc tangent of a derivative structure.
* @param y array holding the first operand
* @param yOffset offset of the first operand in its array
* @param x array holding the second operand
* @param xOffset offset of the second operand in its array
* @param result array where result must be stored (for
* two arguments arc tangent the result array <em>cannot</em>
* be the input array)
* @param resultOffset offset of the result in its array
*/
public void atan2(final double[] y, final int yOffset,
final double[] x, final int xOffset,
final double[] result, final int resultOffset) {
// compute r = sqrt(x^2+y^2)
double[] tmp1 = new double[getSize()];
multiply(x, xOffset, x, xOffset, tmp1, 0); // x^2
double[] tmp2 = new double[getSize()];
multiply(y, yOffset, y, yOffset, tmp2, 0); // y^2
add(tmp1, 0, tmp2, 0, tmp2, 0); // x^2 + y^2
rootN(tmp2, 0, 2, tmp1, 0); // r = sqrt(x^2 + y^2)
if (x[xOffset] >= 0) {
// compute atan2(y, x) = 2 atan(y / (r + x))
add(tmp1, 0, x, xOffset, tmp2, 0); // r + x
divide(y, yOffset, tmp2, 0, tmp1, 0); // y /(r + x)
atan(tmp1, 0, tmp2, 0); // atan(y / (r + x))
for (int i = 0; i < tmp2.length; ++i) {
result[resultOffset + i] = 2 * tmp2[i]; // 2 * atan(y / (r + x))
}
} else {
// compute atan2(y, x) = +/- pi - 2 atan(y / (r - x))
subtract(tmp1, 0, x, xOffset, tmp2, 0); // r - x
divide(y, yOffset, tmp2, 0, tmp1, 0); // y /(r - x)
atan(tmp1, 0, tmp2, 0); // atan(y / (r - x))
result[resultOffset] =
((tmp2[0] <= 0) ? -FastMath.PI : FastMath.PI) - 2 * tmp2[0]; // +/-pi - 2 * atan(y / (r - x))
for (int i = 1; i < tmp2.length; ++i) {
result[resultOffset + i] = -2 * tmp2[i]; // +/-pi - 2 * atan(y / (r - x))
}
}
// fix value to take special cases (+0/+0, +0/-0, -0/+0, -0/-0, +/-infinity) correctly
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
56 | 6ae0e36482369556f7542ad71e7f7c4fe63cf2017651d8d9e36d2e0c28074c77 | public int[] getCounts(int index) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Convert to multidimensional counter.
*
* @param index Index in unidimensional counter.
* @return the multidimensional counts.
* @throws OutOfRangeException if {@code index} is not between
* {@code 0} and the value returned by {@link #getSize()} (excluded).
*/
public int[] getCounts(int index) {
if (index < 0 ||
index >= totalSize) {
throw new OutOfRangeException(index, 0, totalSize);
}
final int[] indices = new int[dimension];
int count = 0;
for (int i = 0; i < last; i++) {
int idx = 0;
final int offset = uniCounterOffset[i];
while (count <= index) {
count += offset;
++idx;
}
--idx;
count -= offset;
indices[i] = idx;
}
int idx = 1;
while (count < index) {
count += idx;
++idx;
}
--idx;
indices[last] = idx;
return indices;
}
```
| public int[] getCounts(int index) {
if (index < 0 ||
index >= totalSize) {
throw new OutOfRangeException(index, 0, totalSize);
}
final int[] indices = new int[dimension];
int count = 0;
for (int i = 0; i < last; i++) {
int idx = 0;
final int offset = uniCounterOffset[i];
while (count <= index) {
count += offset;
++idx;
}
--idx;
count -= offset;
indices[i] = idx;
}
int idx = 1;
while (count < index) {
count += idx;
++idx;
}
--idx;
indices[last] = idx;
return indices;
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Convert to multidimensional counter.
*
* @param index Index in unidimensional counter.
* @return the multidimensional counts.
* @throws OutOfRangeException if {@code index} is not between
* {@code 0} and the value returned by {@link #getSize()} (excluded).
*/
public int[] getCounts(int index) {
if (index < 0 ||
index >= totalSize) {
throw new OutOfRangeException(index, 0, totalSize);
}
final int[] indices = new int[dimension];
int count = 0;
for (int i = 0; i < last; i++) {
int idx = 0;
final int offset = uniCounterOffset[i];
while (count <= index) {
count += offset;
++idx;
}
--idx;
count -= offset;
indices[i] = idx;
}
int idx = 1;
while (count < index) {
count += idx;
++idx;
}
--idx;
indices[last] = idx;
return indices;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
126 | 6ae23291227098db690cc8132d097dab07c6a291d000aaaef87801f322b72f98 | void tryMinimizeExits(Node n, int exitType, String labelName) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Attempts to minimize the number of explicit exit points in a control
* structure to take advantage of the implied exit at the end of the
* structure. This is accomplished by removing redundant statements, and
* moving statements following a qualifying IF node into that node.
* For example:
*
* function () {
* if (x) return;
* else blah();
* foo();
* }
*
* becomes:
*
* function () {
* if (x) ;
* else {
* blah();
* foo();
* }
*
* @param n The execution node of a parent to inspect.
* @param exitType The type of exit to look for.
* @param labelName If parent is a label the name of the label to look for,
* null otherwise.
* @nullable labelName non-null only for breaks within labels.
*/
void tryMinimizeExits(Node n, int exitType, String labelName) {
// Just an 'exit'.
if (matchingExitNode(n, exitType, labelName)) {
NodeUtil.removeChild(n.getParent(), n);
compiler.reportCodeChange();
return;
}
// Just an 'if'.
if (n.isIf()) {
Node ifBlock = n.getFirstChild().getNext();
tryMinimizeExits(ifBlock, exitType, labelName);
Node elseBlock = ifBlock.getNext();
if (elseBlock != null) {
tryMinimizeExits(elseBlock, exitType, labelName);
}
return;
}
// Just a 'try/catch/finally'.
if (n.isTry()) {
Node tryBlock = n.getFirstChild();
tryMinimizeExits(tryBlock, exitType, labelName);
Node allCatchNodes = NodeUtil.getCatchBlock(n);
if (NodeUtil.hasCatchHandler(allCatchNodes)) {
Preconditions.checkState(allCatchNodes.hasOneChild());
Node catchNode = allCatchNodes.getFirstChild();
Node catchCodeBlock = catchNode.getLastChild();
tryMinimizeExits(catchCodeBlock, exitType, labelName);
}
/* Don't try to minimize the exits of finally blocks, as this
* can cause problems if it changes the completion type of the finally
* block. See ECMA 262 Sections 8.9 & 12.14
*/
if (NodeUtil.hasFinally(n)) {
Node finallyBlock = n.getLastChild();
tryMinimizeExits(finallyBlock, exitType, labelName);
}
}
// Just a 'label'.
if (n.isLabel()) {
Node labelBlock = n.getLastChild();
tryMinimizeExits(labelBlock, exitType, labelName);
}
// TODO(johnlenz): The last case of SWITCH statement?
// The rest assumes a block with at least one child, bail on anything else.
if (!n.isBlock() || n.getLastChild() == null) {
return;
}
// Multiple if-exits can be converted in a single pass.
// Convert "if (blah) break; if (blah2) break; other_stmt;" to
// become "if (blah); else { if (blah2); else { other_stmt; } }"
// which will get converted to "if (!blah && !blah2) { other_stmt; }".
for (Node c : n.children()) {
// An 'if' block to process below.
if (c.isIf()) {
Node ifTree = c;
Node trueBlock, falseBlock;
// First, the true condition block.
trueBlock = ifTree.getFirstChild().getNext();
falseBlock = trueBlock.getNext();
tryMinimizeIfBlockExits(trueBlock, falseBlock,
ifTree, exitType, labelName);
// Now the else block.
// The if blocks may have changed, get them again.
trueBlock = ifTree.getFirstChild().getNext();
falseBlock = trueBlock.getNext();
if (falseBlock != null) {
tryMinimizeIfBlockExits(falseBlock, trueBlock,
ifTree, exitType, labelName);
}
}
if (c == n.getLastChild()) {
break;
}
}
// Now try to minimize the exits of the last child, if it is removed
// look at what has become the last child.
for (Node c = n.getLastChild(); c != null; c = n.getLastChild()) {
tryMinimizeExits(c, exitType, labelName);
// If the node is still the last child, we are done.
if (c == n.getLastChild()) {
break;
}
}
}
```
| void tryMinimizeExits(Node n, int exitType, String labelName) {
// Just an 'exit'.
if (matchingExitNode(n, exitType, labelName)) {
NodeUtil.removeChild(n.getParent(), n);
compiler.reportCodeChange();
return;
}
// Just an 'if'.
if (n.isIf()) {
Node ifBlock = n.getFirstChild().getNext();
tryMinimizeExits(ifBlock, exitType, labelName);
Node elseBlock = ifBlock.getNext();
if (elseBlock != null) {
tryMinimizeExits(elseBlock, exitType, labelName);
}
return;
}
// Just a 'try/catch/finally'.
if (n.isTry()) {
Node tryBlock = n.getFirstChild();
tryMinimizeExits(tryBlock, exitType, labelName);
Node allCatchNodes = NodeUtil.getCatchBlock(n);
if (NodeUtil.hasCatchHandler(allCatchNodes)) {
Preconditions.checkState(allCatchNodes.hasOneChild());
Node catchNode = allCatchNodes.getFirstChild();
Node catchCodeBlock = catchNode.getLastChild();
tryMinimizeExits(catchCodeBlock, exitType, labelName);
}
/* Don't try to minimize the exits of finally blocks, as this
* can cause problems if it changes the completion type of the finally
* block. See ECMA 262 Sections 8.9 & 12.14
*/
if (NodeUtil.hasFinally(n)) {
Node finallyBlock = n.getLastChild();
tryMinimizeExits(finallyBlock, exitType, labelName);
}
}
// Just a 'label'.
if (n.isLabel()) {
Node labelBlock = n.getLastChild();
tryMinimizeExits(labelBlock, exitType, labelName);
}
// TODO(johnlenz): The last case of SWITCH statement?
// The rest assumes a block with at least one child, bail on anything else.
if (!n.isBlock() || n.getLastChild() == null) {
return;
}
// Multiple if-exits can be converted in a single pass.
// Convert "if (blah) break; if (blah2) break; other_stmt;" to
// become "if (blah); else { if (blah2); else { other_stmt; } }"
// which will get converted to "if (!blah && !blah2) { other_stmt; }".
for (Node c : n.children()) {
// An 'if' block to process below.
if (c.isIf()) {
Node ifTree = c;
Node trueBlock, falseBlock;
// First, the true condition block.
trueBlock = ifTree.getFirstChild().getNext();
falseBlock = trueBlock.getNext();
tryMinimizeIfBlockExits(trueBlock, falseBlock,
ifTree, exitType, labelName);
// Now the else block.
// The if blocks may have changed, get them again.
trueBlock = ifTree.getFirstChild().getNext();
falseBlock = trueBlock.getNext();
if (falseBlock != null) {
tryMinimizeIfBlockExits(falseBlock, trueBlock,
ifTree, exitType, labelName);
}
}
if (c == n.getLastChild()) {
break;
}
}
// Now try to minimize the exits of the last child, if it is removed
// look at what has become the last child.
for (Node c = n.getLastChild(); c != null; c = n.getLastChild()) {
tryMinimizeExits(c, exitType, labelName);
// If the node is still the last child, we are done.
if (c == n.getLastChild()) {
break;
}
}
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Attempts to minimize the number of explicit exit points in a control
* structure to take advantage of the implied exit at the end of the
* structure. This is accomplished by removing redundant statements, and
* moving statements following a qualifying IF node into that node.
* For example:
*
* function () {
* if (x) return;
* else blah();
* foo();
* }
*
* becomes:
*
* function () {
* if (x) ;
* else {
* blah();
* foo();
* }
*
* @param n The execution node of a parent to inspect.
* @param exitType The type of exit to look for.
* @param labelName If parent is a label the name of the label to look for,
* null otherwise.
* @nullable labelName non-null only for breaks within labels.
*/
void tryMinimizeExits(Node n, int exitType, String labelName) {
// Just an 'exit'.
if (matchingExitNode(n, exitType, labelName)) {
NodeUtil.removeChild(n.getParent(), n);
compiler.reportCodeChange();
return;
}
// Just an 'if'.
if (n.isIf()) {
Node ifBlock = n.getFirstChild().getNext();
tryMinimizeExits(ifBlock, exitType, labelName);
Node elseBlock = ifBlock.getNext();
if (elseBlock != null) {
tryMinimizeExits(elseBlock, exitType, labelName);
}
return;
}
// Just a 'try/catch/finally'.
if (n.isTry()) {
Node tryBlock = n.getFirstChild();
tryMinimizeExits(tryBlock, exitType, labelName);
Node allCatchNodes = NodeUtil.getCatchBlock(n);
if (NodeUtil.hasCatchHandler(allCatchNodes)) {
Preconditions.checkState(allCatchNodes.hasOneChild());
Node catchNode = allCatchNodes.getFirstChild();
Node catchCodeBlock = catchNode.getLastChild();
tryMinimizeExits(catchCodeBlock, exitType, labelName);
}
/* Don't try to minimize the exits of finally blocks, as this
* can cause problems if it changes the completion type of the finally
* block. See ECMA 262 Sections 8.9 & 12.14
*/
if (NodeUtil.hasFinally(n)) {
Node finallyBlock = n.getLastChild();
tryMinimizeExits(finallyBlock, exitType, labelName);
}
}
// Just a 'label'.
if (n.isLabel()) {
Node labelBlock = n.getLastChild();
tryMinimizeExits(labelBlock, exitType, labelName);
}
// TODO(johnlenz): The last case of SWITCH statement?
// The rest assumes a block with at least one child, bail on anything else.
if (!n.isBlock() || n.getLastChild() == null) {
return;
}
// Multiple if-exits can be converted in a single pass.
// Convert "if (blah) break; if (blah2) break; other_stmt;" to
// become "if (blah); else { if (blah2); else { other_stmt; } }"
// which will get converted to "if (!blah && !blah2) { other_stmt; }".
for (Node c : n.children()) {
// An 'if' block to process below.
if (c.isIf()) {
Node ifTree = c;
Node trueBlock, falseBlock;
// First, the true condition block.
trueBlock = ifTree.getFirstChild().getNext();
falseBlock = trueBlock.getNext();
tryMinimizeIfBlockExits(trueBlock, falseBlock,
ifTree, exitType, labelName);
// Now the else block.
// The if blocks may have changed, get them again.
trueBlock = ifTree.getFirstChild().getNext();
falseBlock = trueBlock.getNext();
if (falseBlock != null) {
tryMinimizeIfBlockExits(falseBlock, trueBlock,
ifTree, exitType, labelName);
}
}
if (c == n.getLastChild()) {
break;
}
}
// Now try to minimize the exits of the last child, if it is removed
// look at what has become the last child.
for (Node c = n.getLastChild(); c != null; c = n.getLastChild()) {
tryMinimizeExits(c, exitType, labelName);
// If the node is still the last child, we are done.
if (c == n.getLastChild()) {
break;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
15 | 6b23d6564a26ea0cd07049c0f803868b709059eefe539495772244975f78e090 | private char getMappingCode(final String str, final int index) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Used internally by the Soundex algorithm.
*
* Consonants from the same code group separated by W or H are treated as one.
*
* @param str
* the cleaned working string to encode (in upper case).
* @param index
* the character position to encode
* @return Mapping code for a particular character
* @throws IllegalArgumentException
* if the character is not mapped
*/
private char getMappingCode(final String str, final int index) {
// map() throws IllegalArgumentException
final char mappedChar = this.map(str.charAt(index));
// HW rule check
if (index > 1 && mappedChar != '0') {
for (int i=index-1 ; i>=0 ; i--) {
final char prevChar = str.charAt(i);
if (this.map(prevChar)==mappedChar) {
return 0;
}
if ('H'!=prevChar && 'W'!=prevChar) {
break;
}
}
}
return mappedChar;
}
```
| private char getMappingCode(final String str, final int index) {
// map() throws IllegalArgumentException
final char mappedChar = this.map(str.charAt(index));
// HW rule check
if (index > 1 && mappedChar != '0') {
for (int i=index-1 ; i>=0 ; i--) {
final char prevChar = str.charAt(i);
if (this.map(prevChar)==mappedChar) {
return 0;
}
if ('H'!=prevChar && 'W'!=prevChar) {
break;
}
}
}
return mappedChar;
} | false | Codec | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Used internally by the Soundex algorithm.
*
* Consonants from the same code group separated by W or H are treated as one.
*
* @param str
* the cleaned working string to encode (in upper case).
* @param index
* the character position to encode
* @return Mapping code for a particular character
* @throws IllegalArgumentException
* if the character is not mapped
*/
private char getMappingCode(final String str, final int index) {
// map() throws IllegalArgumentException
final char mappedChar = this.map(str.charAt(index));
// HW rule check
if (index > 1 && mappedChar != '0') {
for (int i=index-1 ; i>=0 ; i--) {
final char prevChar = str.charAt(i);
if (this.map(prevChar)==mappedChar) {
return 0;
}
if ('H'!=prevChar && 'W'!=prevChar) {
break;
}
}
}
return mappedChar;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
27 | 6b2552b696ee61f64e73787f6944787cc9e7660b763377587fe4eb12ac4a71c1 | public static Number createNumber(String str) throws NumberFormatException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Turns a string value into a java.lang.Number.</p>
*
* <p>First, the value is examined for a type qualifier on the end
* (<code>'f','F','d','D','l','L'</code>). If it is found, it starts
* trying to create successively larger types from the type specified
* until one is found that can represent the value.</p>
*
* <p>If a type specifier is not found, it will check for a decimal point
* and then try successively larger types from <code>Integer</code> to
* <code>BigInteger</code> and from <code>Float</code> to
* <code>BigDecimal</code>.</p>
*
* <p>If the string starts with <code>0x</code> or <code>-0x</code>, it
* will be interpreted as a hexadecimal integer. Values with leading
* <code>0</code>'s will not be interpreted as octal.</p>
*
* <p>Returns <code>null</code> if the string is <code>null</code>.</p>
*
* <p>This method does not trim the input string, i.e., strings with leading
* or trailing spaces will generate NumberFormatExceptions.</p>
*
* @param str String containing a number, may be null
* @return Number created from the string
* @throws NumberFormatException if the value cannot be converted
*/
// plus minus everything. Prolly more. A lot are not separable.
// 45 45.5 45E7 4.5E7 Hex Oct Binary xxxF xxxD xxxf xxxd
// Possible inputs:
// new BigInteger(String,int radix)
// new BigInteger(String)
// new BigDecimal(String)
// Short.valueOf(String)
// Short.valueOf(String,int)
// Short.decode(String)
// new Short(String)
// Long.valueOf(String)
// Long.valueOf(String,int)
// Long.getLong(String,Integer)
// Long.getLong(String,int)
// Long.getLong(String)
// new Long(String)
// new Byte(String)
// new Double(String)
// new Integer(String)
// Integer.getInteger(String,Integer val)
// Integer.getInteger(String,int val)
// Integer.getInteger(String)
// Integer.decode(String)
// Integer.valueOf(String)
// Integer.valueOf(String,int radix)
// new Float(String)
// Float.valueOf(String)
// Double.valueOf(String)
// Byte.valueOf(String)
// Byte.valueOf(String,int radix)
// Byte.decode(String)
// useful methods:
// BigDecimal, BigInteger and Byte
// must handle Long, Float, Integer, Float, Short,
//-----------------------------------------------------------------------
public static Number createNumber(String str) throws NumberFormatException {
if (str == null) {
return null;
}
if (StringUtils.isBlank(str)) {
throw new NumberFormatException("A blank string is not a valid number");
}
if (str.startsWith("--")) {
// this is protection for poorness in java.lang.BigDecimal.
// it accepts this as a legal value, but it does not appear
// to be in specification of class. OS X Java parses it to
// a wrong value.
return null;
}
if (str.startsWith("0x") || str.startsWith("-0x")) {
return createInteger(str);
}
char lastChar = str.charAt(str.length() - 1);
String mant;
String dec;
String exp;
int decPos = str.indexOf('.');
int expPos = str.indexOf('e') + str.indexOf('E') + 1;
if (decPos > -1) {
if (expPos > -1) {
if (expPos < decPos) {
throw new NumberFormatException(str + " is not a valid number.");
}
dec = str.substring(decPos + 1, expPos);
} else {
dec = str.substring(decPos + 1);
}
mant = str.substring(0, decPos);
} else {
if (expPos > -1) {
mant = str.substring(0, expPos);
} else {
mant = str;
}
dec = null;
}
if (!Character.isDigit(lastChar) && lastChar != '.') {
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length() - 1);
} else {
exp = null;
}
//Requesting a specific type..
String numeric = str.substring(0, str.length() - 1);
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
switch (lastChar) {
case 'l' :
case 'L' :
if (dec == null
&& exp == null
&& (numeric.charAt(0) == '-' && isDigits(numeric.substring(1)) || isDigits(numeric))) {
try {
return createLong(numeric);
} catch (NumberFormatException nfe) {
//Too big for a long
}
return createBigInteger(numeric);
}
throw new NumberFormatException(str + " is not a valid number.");
case 'f' :
case 'F' :
try {
Float f = NumberUtils.createFloat(numeric);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
//If it's too big for a float or the float value = 0 and the string
//has non-zeros in it, then float does not have the precision we want
return f;
}
} catch (NumberFormatException nfe) {
// ignore the bad number
}
//$FALL-THROUGH$
case 'd' :
case 'D' :
try {
Double d = NumberUtils.createDouble(numeric);
if (!(d.isInfinite() || (d.floatValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) {
// ignore the bad number
}
try {
return createBigDecimal(numeric);
} catch (NumberFormatException e) {
// ignore the bad number
}
//$FALL-THROUGH$
default :
throw new NumberFormatException(str + " is not a valid number.");
}
} else {
//User doesn't have a preference on the return type, so let's start
//small and go from there...
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length());
} else {
exp = null;
}
if (dec == null && exp == null) {
//Must be an int,long,bigint
try {
return createInteger(str);
} catch (NumberFormatException nfe) {
// ignore the bad number
}
try {
return createLong(str);
} catch (NumberFormatException nfe) {
// ignore the bad number
}
return createBigInteger(str);
} else {
//Must be a float,double,BigDec
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
try {
Float f = createFloat(str);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
return f;
}
} catch (NumberFormatException nfe) {
// ignore the bad number
}
try {
Double d = createDouble(str);
if (!(d.isInfinite() || (d.doubleValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) {
// ignore the bad number
}
return createBigDecimal(str);
}
}
}
```
| public static Number createNumber(String str) throws NumberFormatException {
if (str == null) {
return null;
}
if (StringUtils.isBlank(str)) {
throw new NumberFormatException("A blank string is not a valid number");
}
if (str.startsWith("--")) {
// this is protection for poorness in java.lang.BigDecimal.
// it accepts this as a legal value, but it does not appear
// to be in specification of class. OS X Java parses it to
// a wrong value.
return null;
}
if (str.startsWith("0x") || str.startsWith("-0x")) {
return createInteger(str);
}
char lastChar = str.charAt(str.length() - 1);
String mant;
String dec;
String exp;
int decPos = str.indexOf('.');
int expPos = str.indexOf('e') + str.indexOf('E') + 1;
if (decPos > -1) {
if (expPos > -1) {
if (expPos < decPos) {
throw new NumberFormatException(str + " is not a valid number.");
}
dec = str.substring(decPos + 1, expPos);
} else {
dec = str.substring(decPos + 1);
}
mant = str.substring(0, decPos);
} else {
if (expPos > -1) {
mant = str.substring(0, expPos);
} else {
mant = str;
}
dec = null;
}
if (!Character.isDigit(lastChar) && lastChar != '.') {
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length() - 1);
} else {
exp = null;
}
//Requesting a specific type..
String numeric = str.substring(0, str.length() - 1);
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
switch (lastChar) {
case 'l' :
case 'L' :
if (dec == null
&& exp == null
&& (numeric.charAt(0) == '-' && isDigits(numeric.substring(1)) || isDigits(numeric))) {
try {
return createLong(numeric);
} catch (NumberFormatException nfe) {
//Too big for a long
}
return createBigInteger(numeric);
}
throw new NumberFormatException(str + " is not a valid number.");
case 'f' :
case 'F' :
try {
Float f = NumberUtils.createFloat(numeric);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
//If it's too big for a float or the float value = 0 and the string
//has non-zeros in it, then float does not have the precision we want
return f;
}
} catch (NumberFormatException nfe) {
// ignore the bad number
}
//$FALL-THROUGH$
case 'd' :
case 'D' :
try {
Double d = NumberUtils.createDouble(numeric);
if (!(d.isInfinite() || (d.floatValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) {
// ignore the bad number
}
try {
return createBigDecimal(numeric);
} catch (NumberFormatException e) {
// ignore the bad number
}
//$FALL-THROUGH$
default :
throw new NumberFormatException(str + " is not a valid number.");
}
} else {
//User doesn't have a preference on the return type, so let's start
//small and go from there...
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length());
} else {
exp = null;
}
if (dec == null && exp == null) {
//Must be an int,long,bigint
try {
return createInteger(str);
} catch (NumberFormatException nfe) {
// ignore the bad number
}
try {
return createLong(str);
} catch (NumberFormatException nfe) {
// ignore the bad number
}
return createBigInteger(str);
} else {
//Must be a float,double,BigDec
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
try {
Float f = createFloat(str);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
return f;
}
} catch (NumberFormatException nfe) {
// ignore the bad number
}
try {
Double d = createDouble(str);
if (!(d.isInfinite() || (d.doubleValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) {
// ignore the bad number
}
return createBigDecimal(str);
}
}
} | true | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Turns a string value into a java.lang.Number.</p>
*
* <p>First, the value is examined for a type qualifier on the end
* (<code>'f','F','d','D','l','L'</code>). If it is found, it starts
* trying to create successively larger types from the type specified
* until one is found that can represent the value.</p>
*
* <p>If a type specifier is not found, it will check for a decimal point
* and then try successively larger types from <code>Integer</code> to
* <code>BigInteger</code> and from <code>Float</code> to
* <code>BigDecimal</code>.</p>
*
* <p>If the string starts with <code>0x</code> or <code>-0x</code>, it
* will be interpreted as a hexadecimal integer. Values with leading
* <code>0</code>'s will not be interpreted as octal.</p>
*
* <p>Returns <code>null</code> if the string is <code>null</code>.</p>
*
* <p>This method does not trim the input string, i.e., strings with leading
* or trailing spaces will generate NumberFormatExceptions.</p>
*
* @param str String containing a number, may be null
* @return Number created from the string
* @throws NumberFormatException if the value cannot be converted
*/
// plus minus everything. Prolly more. A lot are not separable.
// 45 45.5 45E7 4.5E7 Hex Oct Binary xxxF xxxD xxxf xxxd
// Possible inputs:
// new BigInteger(String,int radix)
// new BigInteger(String)
// new BigDecimal(String)
// Short.valueOf(String)
// Short.valueOf(String,int)
// Short.decode(String)
// new Short(String)
// Long.valueOf(String)
// Long.valueOf(String,int)
// Long.getLong(String,Integer)
// Long.getLong(String,int)
// Long.getLong(String)
// new Long(String)
// new Byte(String)
// new Double(String)
// new Integer(String)
// Integer.getInteger(String,Integer val)
// Integer.getInteger(String,int val)
// Integer.getInteger(String)
// Integer.decode(String)
// Integer.valueOf(String)
// Integer.valueOf(String,int radix)
// new Float(String)
// Float.valueOf(String)
// Double.valueOf(String)
// Byte.valueOf(String)
// Byte.valueOf(String,int radix)
// Byte.decode(String)
// useful methods:
// BigDecimal, BigInteger and Byte
// must handle Long, Float, Integer, Float, Short,
//-----------------------------------------------------------------------
public static Number createNumber(String str) throws NumberFormatException {
if (str == null) {
return null;
}
if (StringUtils.isBlank(str)) {
throw new NumberFormatException("A blank string is not a valid number");
}
if (str.startsWith("--")) {
// this is protection for poorness in java.lang.BigDecimal.
// it accepts this as a legal value, but it does not appear
// to be in specification of class. OS X Java parses it to
// a wrong value.
return null;
}
if (str.startsWith("0x") || str.startsWith("-0x")) {
return createInteger(str);
}
char lastChar = str.charAt(str.length() - 1);
String mant;
String dec;
String exp;
int decPos = str.indexOf('.');
int expPos = str.indexOf('e') + str.indexOf('E') + 1;
if (decPos > -1) {
if (expPos > -1) {
if (expPos < decPos) {
throw new NumberFormatException(str + " is not a valid number.");
}
dec = str.substring(decPos + 1, expPos);
} else {
dec = str.substring(decPos + 1);
}
mant = str.substring(0, decPos);
} else {
if (expPos > -1) {
mant = str.substring(0, expPos);
} else {
mant = str;
}
dec = null;
}
if (!Character.isDigit(lastChar) && lastChar != '.') {
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length() - 1);
} else {
exp = null;
}
//Requesting a specific type..
String numeric = str.substring(0, str.length() - 1);
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
switch (lastChar) {
case 'l' :
case 'L' :
if (dec == null
&& exp == null
&& (numeric.charAt(0) == '-' && isDigits(numeric.substring(1)) || isDigits(numeric))) {
try {
return createLong(numeric);
} catch (NumberFormatException nfe) {
//Too big for a long
}
return createBigInteger(numeric);
}
throw new NumberFormatException(str + " is not a valid number.");
case 'f' :
case 'F' :
try {
Float f = NumberUtils.createFloat(numeric);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
//If it's too big for a float or the float value = 0 and the string
//has non-zeros in it, then float does not have the precision we want
return f;
}
} catch (NumberFormatException nfe) {
// ignore the bad number
}
//$FALL-THROUGH$
case 'd' :
case 'D' :
try {
Double d = NumberUtils.createDouble(numeric);
if (!(d.isInfinite() || (d.floatValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) {
// ignore the bad number
}
try {
return createBigDecimal(numeric);
} catch (NumberFormatException e) {
// ignore the bad number
}
//$FALL-THROUGH$
default :
throw new NumberFormatException(str + " is not a valid number.");
}
} else {
//User doesn't have a preference on the return type, so let's start
//small and go from there...
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length());
} else {
exp = null;
}
if (dec == null && exp == null) {
//Must be an int,long,bigint
try {
return createInteger(str);
} catch (NumberFormatException nfe) {
// ignore the bad number
}
try {
return createLong(str);
} catch (NumberFormatException nfe) {
// ignore the bad number
}
return createBigInteger(str);
} else {
//Must be a float,double,BigDec
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
try {
Float f = createFloat(str);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
return f;
}
} catch (NumberFormatException nfe) {
// ignore the bad number
}
try {
Double d = createDouble(str);
if (!(d.isInfinite() || (d.doubleValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) {
// ignore the bad number
}
return createBigDecimal(str);
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
37 | 6b44f9acdcd3a5f2616c28b10863c8e17cc1934b56bf00f6613d6a9da08b633f | @Override
protected JavaType _narrow(Class<?> subclass)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
protected JavaType _narrow(Class<?> subclass)
{
if (_class == subclass) {
return this;
}
// Should we check that there is a sub-class relationship?
// 15-Jan-2016, tatu: Almost yes, but there are some complications with
// placeholder values, so no.
/*
if (!_class.isAssignableFrom(subclass)) {
throw new IllegalArgumentException("Class "+subclass.getName()+" not sub-type of "
+_class.getName());
}
*/
// 15-Jan-2015, tatu: Not correct; should really re-resolve...
return new SimpleType(subclass, _bindings, this, _superInterfaces,
_valueHandler, _typeHandler, _asStatic);
}
```
| @Override
protected JavaType _narrow(Class<?> subclass)
{
if (_class == subclass) {
return this;
}
// Should we check that there is a sub-class relationship?
// 15-Jan-2016, tatu: Almost yes, but there are some complications with
// placeholder values, so no.
/*
if (!_class.isAssignableFrom(subclass)) {
throw new IllegalArgumentException("Class "+subclass.getName()+" not sub-type of "
+_class.getName());
}
*/
// 15-Jan-2015, tatu: Not correct; should really re-resolve...
return new SimpleType(subclass, _bindings, this, _superInterfaces,
_valueHandler, _typeHandler, _asStatic);
} | false | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
protected JavaType _narrow(Class<?> subclass)
{
if (_class == subclass) {
return this;
}
// Should we check that there is a sub-class relationship?
// 15-Jan-2016, tatu: Almost yes, but there are some complications with
// placeholder values, so no.
/*
if (!_class.isAssignableFrom(subclass)) {
throw new IllegalArgumentException("Class "+subclass.getName()+" not sub-type of "
+_class.getName());
}
*/
// 15-Jan-2015, tatu: Not correct; should really re-resolve...
return new SimpleType(subclass, _bindings, this, _superInterfaces,
_valueHandler, _typeHandler, _asStatic);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
72 | 6b90ad9ab29c040eba522ca543473b581d2798e2a6802858fd9903c868363504 | public double solve(final UnivariateRealFunction f,
final double min, final double max, final double initial)
throws MaxIterationsExceededException, FunctionEvaluationException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Find a zero in the given interval with an initial guess.
* <p>Throws <code>IllegalArgumentException</code> if the values of the
* function at the three points have the same sign (note that it is
* allowed to have endpoints with the same sign if the initial point has
* opposite sign function-wise).</p>
*
* @param f function to solve.
* @param min the lower bound for the interval.
* @param max the upper bound for the interval.
* @param initial the start value to use (must be set to min if no
* initial point is known).
* @return the value where the function is zero
* @throws MaxIterationsExceededException the maximum iteration count
* is exceeded
* @throws FunctionEvaluationException if an error occurs evaluating
* the function
* @throws IllegalArgumentException if initial is not between min and max
* (even if it <em>is</em> a root)
*/
public double solve(final UnivariateRealFunction f,
final double min, final double max, final double initial)
throws MaxIterationsExceededException, FunctionEvaluationException {
clearResult();
verifySequence(min, initial, max);
// return the initial guess if it is good enough
double yInitial = f.value(initial);
if (Math.abs(yInitial) <= functionValueAccuracy) {
setResult(initial, 0);
return result;
}
// return the first endpoint if it is good enough
double yMin = f.value(min);
if (Math.abs(yMin) <= functionValueAccuracy) {
setResult(yMin, 0);
return result;
}
// reduce interval if min and initial bracket the root
if (yInitial * yMin < 0) {
return solve(f, min, yMin, initial, yInitial, min, yMin);
}
// return the second endpoint if it is good enough
double yMax = f.value(max);
if (Math.abs(yMax) <= functionValueAccuracy) {
setResult(yMax, 0);
return result;
}
// reduce interval if initial and max bracket the root
if (yInitial * yMax < 0) {
return solve(f, initial, yInitial, max, yMax, initial, yInitial);
}
if (yMin * yMax > 0) {
throw MathRuntimeException.createIllegalArgumentException(
NON_BRACKETING_MESSAGE, min, max, yMin, yMax);
}
// full Brent algorithm starting with provided initial guess
return solve(f, min, yMin, max, yMax, initial, yInitial);
}
```
| public double solve(final UnivariateRealFunction f,
final double min, final double max, final double initial)
throws MaxIterationsExceededException, FunctionEvaluationException {
clearResult();
verifySequence(min, initial, max);
// return the initial guess if it is good enough
double yInitial = f.value(initial);
if (Math.abs(yInitial) <= functionValueAccuracy) {
setResult(initial, 0);
return result;
}
// return the first endpoint if it is good enough
double yMin = f.value(min);
if (Math.abs(yMin) <= functionValueAccuracy) {
setResult(yMin, 0);
return result;
}
// reduce interval if min and initial bracket the root
if (yInitial * yMin < 0) {
return solve(f, min, yMin, initial, yInitial, min, yMin);
}
// return the second endpoint if it is good enough
double yMax = f.value(max);
if (Math.abs(yMax) <= functionValueAccuracy) {
setResult(yMax, 0);
return result;
}
// reduce interval if initial and max bracket the root
if (yInitial * yMax < 0) {
return solve(f, initial, yInitial, max, yMax, initial, yInitial);
}
if (yMin * yMax > 0) {
throw MathRuntimeException.createIllegalArgumentException(
NON_BRACKETING_MESSAGE, min, max, yMin, yMax);
}
// full Brent algorithm starting with provided initial guess
return solve(f, min, yMin, max, yMax, initial, yInitial);
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Find a zero in the given interval with an initial guess.
* <p>Throws <code>IllegalArgumentException</code> if the values of the
* function at the three points have the same sign (note that it is
* allowed to have endpoints with the same sign if the initial point has
* opposite sign function-wise).</p>
*
* @param f function to solve.
* @param min the lower bound for the interval.
* @param max the upper bound for the interval.
* @param initial the start value to use (must be set to min if no
* initial point is known).
* @return the value where the function is zero
* @throws MaxIterationsExceededException the maximum iteration count
* is exceeded
* @throws FunctionEvaluationException if an error occurs evaluating
* the function
* @throws IllegalArgumentException if initial is not between min and max
* (even if it <em>is</em> a root)
*/
public double solve(final UnivariateRealFunction f,
final double min, final double max, final double initial)
throws MaxIterationsExceededException, FunctionEvaluationException {
clearResult();
verifySequence(min, initial, max);
// return the initial guess if it is good enough
double yInitial = f.value(initial);
if (Math.abs(yInitial) <= functionValueAccuracy) {
setResult(initial, 0);
return result;
}
// return the first endpoint if it is good enough
double yMin = f.value(min);
if (Math.abs(yMin) <= functionValueAccuracy) {
setResult(yMin, 0);
return result;
}
// reduce interval if min and initial bracket the root
if (yInitial * yMin < 0) {
return solve(f, min, yMin, initial, yInitial, min, yMin);
}
// return the second endpoint if it is good enough
double yMax = f.value(max);
if (Math.abs(yMax) <= functionValueAccuracy) {
setResult(yMax, 0);
return result;
}
// reduce interval if initial and max bracket the root
if (yInitial * yMax < 0) {
return solve(f, initial, yInitial, max, yMax, initial, yInitial);
}
if (yMin * yMax > 0) {
throw MathRuntimeException.createIllegalArgumentException(
NON_BRACKETING_MESSAGE, min, max, yMin, yMax);
}
// full Brent algorithm starting with provided initial guess
return solve(f, min, yMin, max, yMax, initial, yInitial);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
73 | 6b90ad9ab29c040eba522ca543473b581d2798e2a6802858fd9903c868363504 | public double solve(final UnivariateRealFunction f,
final double min, final double max, final double initial)
throws MaxIterationsExceededException, FunctionEvaluationException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Find a zero in the given interval with an initial guess.
* <p>Throws <code>IllegalArgumentException</code> if the values of the
* function at the three points have the same sign (note that it is
* allowed to have endpoints with the same sign if the initial point has
* opposite sign function-wise).</p>
*
* @param f function to solve.
* @param min the lower bound for the interval.
* @param max the upper bound for the interval.
* @param initial the start value to use (must be set to min if no
* initial point is known).
* @return the value where the function is zero
* @throws MaxIterationsExceededException the maximum iteration count
* is exceeded
* @throws FunctionEvaluationException if an error occurs evaluating
* the function
* @throws IllegalArgumentException if initial is not between min and max
* (even if it <em>is</em> a root)
*/
public double solve(final UnivariateRealFunction f,
final double min, final double max, final double initial)
throws MaxIterationsExceededException, FunctionEvaluationException {
clearResult();
verifySequence(min, initial, max);
// return the initial guess if it is good enough
double yInitial = f.value(initial);
if (Math.abs(yInitial) <= functionValueAccuracy) {
setResult(initial, 0);
return result;
}
// return the first endpoint if it is good enough
double yMin = f.value(min);
if (Math.abs(yMin) <= functionValueAccuracy) {
setResult(yMin, 0);
return result;
}
// reduce interval if min and initial bracket the root
if (yInitial * yMin < 0) {
return solve(f, min, yMin, initial, yInitial, min, yMin);
}
// return the second endpoint if it is good enough
double yMax = f.value(max);
if (Math.abs(yMax) <= functionValueAccuracy) {
setResult(yMax, 0);
return result;
}
// reduce interval if initial and max bracket the root
if (yInitial * yMax < 0) {
return solve(f, initial, yInitial, max, yMax, initial, yInitial);
}
if (yMin * yMax > 0) {
throw MathRuntimeException.createIllegalArgumentException(
NON_BRACKETING_MESSAGE, min, max, yMin, yMax);
}
// full Brent algorithm starting with provided initial guess
return solve(f, min, yMin, max, yMax, initial, yInitial);
}
```
| public double solve(final UnivariateRealFunction f,
final double min, final double max, final double initial)
throws MaxIterationsExceededException, FunctionEvaluationException {
clearResult();
verifySequence(min, initial, max);
// return the initial guess if it is good enough
double yInitial = f.value(initial);
if (Math.abs(yInitial) <= functionValueAccuracy) {
setResult(initial, 0);
return result;
}
// return the first endpoint if it is good enough
double yMin = f.value(min);
if (Math.abs(yMin) <= functionValueAccuracy) {
setResult(yMin, 0);
return result;
}
// reduce interval if min and initial bracket the root
if (yInitial * yMin < 0) {
return solve(f, min, yMin, initial, yInitial, min, yMin);
}
// return the second endpoint if it is good enough
double yMax = f.value(max);
if (Math.abs(yMax) <= functionValueAccuracy) {
setResult(yMax, 0);
return result;
}
// reduce interval if initial and max bracket the root
if (yInitial * yMax < 0) {
return solve(f, initial, yInitial, max, yMax, initial, yInitial);
}
if (yMin * yMax > 0) {
throw MathRuntimeException.createIllegalArgumentException(
NON_BRACKETING_MESSAGE, min, max, yMin, yMax);
}
// full Brent algorithm starting with provided initial guess
return solve(f, min, yMin, max, yMax, initial, yInitial);
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Find a zero in the given interval with an initial guess.
* <p>Throws <code>IllegalArgumentException</code> if the values of the
* function at the three points have the same sign (note that it is
* allowed to have endpoints with the same sign if the initial point has
* opposite sign function-wise).</p>
*
* @param f function to solve.
* @param min the lower bound for the interval.
* @param max the upper bound for the interval.
* @param initial the start value to use (must be set to min if no
* initial point is known).
* @return the value where the function is zero
* @throws MaxIterationsExceededException the maximum iteration count
* is exceeded
* @throws FunctionEvaluationException if an error occurs evaluating
* the function
* @throws IllegalArgumentException if initial is not between min and max
* (even if it <em>is</em> a root)
*/
public double solve(final UnivariateRealFunction f,
final double min, final double max, final double initial)
throws MaxIterationsExceededException, FunctionEvaluationException {
clearResult();
verifySequence(min, initial, max);
// return the initial guess if it is good enough
double yInitial = f.value(initial);
if (Math.abs(yInitial) <= functionValueAccuracy) {
setResult(initial, 0);
return result;
}
// return the first endpoint if it is good enough
double yMin = f.value(min);
if (Math.abs(yMin) <= functionValueAccuracy) {
setResult(yMin, 0);
return result;
}
// reduce interval if min and initial bracket the root
if (yInitial * yMin < 0) {
return solve(f, min, yMin, initial, yInitial, min, yMin);
}
// return the second endpoint if it is good enough
double yMax = f.value(max);
if (Math.abs(yMax) <= functionValueAccuracy) {
setResult(yMax, 0);
return result;
}
// reduce interval if initial and max bracket the root
if (yInitial * yMax < 0) {
return solve(f, initial, yInitial, max, yMax, initial, yInitial);
}
if (yMin * yMax > 0) {
throw MathRuntimeException.createIllegalArgumentException(
NON_BRACKETING_MESSAGE, min, max, yMin, yMax);
}
// full Brent algorithm starting with provided initial guess
return solve(f, min, yMin, max, yMax, initial, yInitial);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
82 | 6bc2cc3306522bc74172970424760ab0f952bcafe270251324bbeff17e2dd4e8 | protected void addBeanProps(DeserializationContext ctxt,
BeanDescription beanDesc, BeanDeserializerBuilder builder)
throws JsonMappingException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Method called to figure out settable properties for the
* bean deserializer to use.
*<p>
* Note: designed to be overridable, and effort is made to keep interface
* similar between versions.
*/
protected void addBeanProps(DeserializationContext ctxt,
BeanDescription beanDesc, BeanDeserializerBuilder builder)
throws JsonMappingException
{
final boolean isConcrete = !beanDesc.getType().isAbstract();
final SettableBeanProperty[] creatorProps = isConcrete
? builder.getValueInstantiator().getFromObjectArguments(ctxt.getConfig())
: null;
final boolean hasCreatorProps = (creatorProps != null);
// 01-May-2016, tatu: Which base type to use here gets tricky, since
// it may often make most sense to use general type for overrides,
// but what we have here may be more specific impl type. But for now
// just use it as is.
JsonIgnoreProperties.Value ignorals = ctxt.getConfig()
.getDefaultPropertyIgnorals(beanDesc.getBeanClass(),
beanDesc.getClassInfo());
Set<String> ignored;
if (ignorals != null) {
boolean ignoreAny = ignorals.getIgnoreUnknown();
builder.setIgnoreUnknownProperties(ignoreAny);
// Or explicit/implicit definitions?
ignored = ignorals.findIgnoredForDeserialization();
for (String propName : ignored) {
builder.addIgnorable(propName);
}
} else {
ignored = Collections.emptySet();
}
// Also, do we have a fallback "any" setter?
AnnotatedMethod anySetterMethod = beanDesc.findAnySetter();
AnnotatedMember anySetterField = null;
if (anySetterMethod != null) {
builder.setAnySetter(constructAnySetter(ctxt, beanDesc, anySetterMethod));
}
else {
anySetterField = beanDesc.findAnySetterField();
if(anySetterField != null) {
builder.setAnySetter(constructAnySetter(ctxt, beanDesc, anySetterField));
}
}
// NOTE: we do NOT add @JsonIgnore'd properties into blocked ones if there's any-setter
// Implicit ones via @JsonIgnore and equivalent?
if (anySetterMethod == null && anySetterField == null) {
Collection<String> ignored2 = beanDesc.getIgnoredPropertyNames();
if (ignored2 != null) {
for (String propName : ignored2) {
// allow ignoral of similarly named JSON property, but do not force;
// latter means NOT adding this to 'ignored':
builder.addIgnorable(propName);
}
}
}
final boolean useGettersAsSetters = ctxt.isEnabled(MapperFeature.USE_GETTERS_AS_SETTERS)
&& ctxt.isEnabled(MapperFeature.AUTO_DETECT_GETTERS);
// Ok: let's then filter out property definitions
List<BeanPropertyDefinition> propDefs = filterBeanProps(ctxt,
beanDesc, builder, beanDesc.findProperties(), ignored);
// After which we can let custom code change the set
if (_factoryConfig.hasDeserializerModifiers()) {
for (BeanDeserializerModifier mod : _factoryConfig.deserializerModifiers()) {
propDefs = mod.updateProperties(ctxt.getConfig(), beanDesc, propDefs);
}
}
// At which point we still have all kinds of properties; not all with mutators:
for (BeanPropertyDefinition propDef : propDefs) {
SettableBeanProperty prop = null;
/* 18-Oct-2013, tatu: Although constructor parameters have highest precedence,
* we need to do linkage (as per [databind#318]), and so need to start with
* other types, and only then create constructor parameter, if any.
*/
if (propDef.hasSetter()) {
JavaType propertyType = propDef.getSetter().getParameterType(0);
prop = constructSettableProperty(ctxt, beanDesc, propDef, propertyType);
} else if (propDef.hasField()) {
JavaType propertyType = propDef.getField().getType();
prop = constructSettableProperty(ctxt, beanDesc, propDef, propertyType);
} else if (useGettersAsSetters && propDef.hasGetter()) {
/* May also need to consider getters
* for Map/Collection properties; but with lowest precedence
*/
AnnotatedMethod getter = propDef.getGetter();
// should only consider Collections and Maps, for now?
Class<?> rawPropertyType = getter.getRawType();
if (Collection.class.isAssignableFrom(rawPropertyType)
|| Map.class.isAssignableFrom(rawPropertyType)) {
prop = constructSetterlessProperty(ctxt, beanDesc, propDef);
}
}
// 25-Sep-2014, tatu: No point in finding constructor parameters for abstract types
// (since they are never used anyway)
if (hasCreatorProps && propDef.hasConstructorParameter()) {
/* If property is passed via constructor parameter, we must
* handle things in special way. Not sure what is the most optimal way...
* for now, let's just call a (new) method in builder, which does nothing.
*/
// but let's call a method just to allow custom builders to be aware...
final String name = propDef.getName();
CreatorProperty cprop = null;
if (creatorProps != null) {
for (SettableBeanProperty cp : creatorProps) {
if (name.equals(cp.getName()) && (cp instanceof CreatorProperty)) {
cprop = (CreatorProperty) cp;
break;
}
}
}
if (cprop == null) {
List<String> n = new ArrayList<>();
for (SettableBeanProperty cp : creatorProps) {
n.add(cp.getName());
}
ctxt.reportBadPropertyDefinition(beanDesc, propDef,
"Could not find creator property with name '%s' (known Creator properties: %s)",
name, n);
continue;
}
if (prop != null) {
cprop.setFallbackSetter(prop);
}
prop = cprop;
builder.addCreatorProperty(cprop);
continue;
}
if (prop != null) {
Class<?>[] views = propDef.findViews();
if (views == null) {
// one more twist: if default inclusion disabled, need to force empty set of views
if (!ctxt.isEnabled(MapperFeature.DEFAULT_VIEW_INCLUSION)) {
views = NO_VIEWS;
}
}
// one more thing before adding to builder: copy any metadata
prop.setViews(views);
builder.addProperty(prop);
}
}
}
```
| protected void addBeanProps(DeserializationContext ctxt,
BeanDescription beanDesc, BeanDeserializerBuilder builder)
throws JsonMappingException
{
final boolean isConcrete = !beanDesc.getType().isAbstract();
final SettableBeanProperty[] creatorProps = isConcrete
? builder.getValueInstantiator().getFromObjectArguments(ctxt.getConfig())
: null;
final boolean hasCreatorProps = (creatorProps != null);
// 01-May-2016, tatu: Which base type to use here gets tricky, since
// it may often make most sense to use general type for overrides,
// but what we have here may be more specific impl type. But for now
// just use it as is.
JsonIgnoreProperties.Value ignorals = ctxt.getConfig()
.getDefaultPropertyIgnorals(beanDesc.getBeanClass(),
beanDesc.getClassInfo());
Set<String> ignored;
if (ignorals != null) {
boolean ignoreAny = ignorals.getIgnoreUnknown();
builder.setIgnoreUnknownProperties(ignoreAny);
// Or explicit/implicit definitions?
ignored = ignorals.findIgnoredForDeserialization();
for (String propName : ignored) {
builder.addIgnorable(propName);
}
} else {
ignored = Collections.emptySet();
}
// Also, do we have a fallback "any" setter?
AnnotatedMethod anySetterMethod = beanDesc.findAnySetter();
AnnotatedMember anySetterField = null;
if (anySetterMethod != null) {
builder.setAnySetter(constructAnySetter(ctxt, beanDesc, anySetterMethod));
}
else {
anySetterField = beanDesc.findAnySetterField();
if(anySetterField != null) {
builder.setAnySetter(constructAnySetter(ctxt, beanDesc, anySetterField));
}
}
// NOTE: we do NOT add @JsonIgnore'd properties into blocked ones if there's any-setter
// Implicit ones via @JsonIgnore and equivalent?
if (anySetterMethod == null && anySetterField == null) {
Collection<String> ignored2 = beanDesc.getIgnoredPropertyNames();
if (ignored2 != null) {
for (String propName : ignored2) {
// allow ignoral of similarly named JSON property, but do not force;
// latter means NOT adding this to 'ignored':
builder.addIgnorable(propName);
}
}
}
final boolean useGettersAsSetters = ctxt.isEnabled(MapperFeature.USE_GETTERS_AS_SETTERS)
&& ctxt.isEnabled(MapperFeature.AUTO_DETECT_GETTERS);
// Ok: let's then filter out property definitions
List<BeanPropertyDefinition> propDefs = filterBeanProps(ctxt,
beanDesc, builder, beanDesc.findProperties(), ignored);
// After which we can let custom code change the set
if (_factoryConfig.hasDeserializerModifiers()) {
for (BeanDeserializerModifier mod : _factoryConfig.deserializerModifiers()) {
propDefs = mod.updateProperties(ctxt.getConfig(), beanDesc, propDefs);
}
}
// At which point we still have all kinds of properties; not all with mutators:
for (BeanPropertyDefinition propDef : propDefs) {
SettableBeanProperty prop = null;
/* 18-Oct-2013, tatu: Although constructor parameters have highest precedence,
* we need to do linkage (as per [databind#318]), and so need to start with
* other types, and only then create constructor parameter, if any.
*/
if (propDef.hasSetter()) {
JavaType propertyType = propDef.getSetter().getParameterType(0);
prop = constructSettableProperty(ctxt, beanDesc, propDef, propertyType);
} else if (propDef.hasField()) {
JavaType propertyType = propDef.getField().getType();
prop = constructSettableProperty(ctxt, beanDesc, propDef, propertyType);
} else if (useGettersAsSetters && propDef.hasGetter()) {
/* May also need to consider getters
* for Map/Collection properties; but with lowest precedence
*/
AnnotatedMethod getter = propDef.getGetter();
// should only consider Collections and Maps, for now?
Class<?> rawPropertyType = getter.getRawType();
if (Collection.class.isAssignableFrom(rawPropertyType)
|| Map.class.isAssignableFrom(rawPropertyType)) {
prop = constructSetterlessProperty(ctxt, beanDesc, propDef);
}
}
// 25-Sep-2014, tatu: No point in finding constructor parameters for abstract types
// (since they are never used anyway)
if (hasCreatorProps && propDef.hasConstructorParameter()) {
/* If property is passed via constructor parameter, we must
* handle things in special way. Not sure what is the most optimal way...
* for now, let's just call a (new) method in builder, which does nothing.
*/
// but let's call a method just to allow custom builders to be aware...
final String name = propDef.getName();
CreatorProperty cprop = null;
if (creatorProps != null) {
for (SettableBeanProperty cp : creatorProps) {
if (name.equals(cp.getName()) && (cp instanceof CreatorProperty)) {
cprop = (CreatorProperty) cp;
break;
}
}
}
if (cprop == null) {
List<String> n = new ArrayList<>();
for (SettableBeanProperty cp : creatorProps) {
n.add(cp.getName());
}
ctxt.reportBadPropertyDefinition(beanDesc, propDef,
"Could not find creator property with name '%s' (known Creator properties: %s)",
name, n);
continue;
}
if (prop != null) {
cprop.setFallbackSetter(prop);
}
prop = cprop;
builder.addCreatorProperty(cprop);
continue;
}
if (prop != null) {
Class<?>[] views = propDef.findViews();
if (views == null) {
// one more twist: if default inclusion disabled, need to force empty set of views
if (!ctxt.isEnabled(MapperFeature.DEFAULT_VIEW_INCLUSION)) {
views = NO_VIEWS;
}
}
// one more thing before adding to builder: copy any metadata
prop.setViews(views);
builder.addProperty(prop);
}
}
} | false | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Method called to figure out settable properties for the
* bean deserializer to use.
*<p>
* Note: designed to be overridable, and effort is made to keep interface
* similar between versions.
*/
protected void addBeanProps(DeserializationContext ctxt,
BeanDescription beanDesc, BeanDeserializerBuilder builder)
throws JsonMappingException
{
final boolean isConcrete = !beanDesc.getType().isAbstract();
final SettableBeanProperty[] creatorProps = isConcrete
? builder.getValueInstantiator().getFromObjectArguments(ctxt.getConfig())
: null;
final boolean hasCreatorProps = (creatorProps != null);
// 01-May-2016, tatu: Which base type to use here gets tricky, since
// it may often make most sense to use general type for overrides,
// but what we have here may be more specific impl type. But for now
// just use it as is.
JsonIgnoreProperties.Value ignorals = ctxt.getConfig()
.getDefaultPropertyIgnorals(beanDesc.getBeanClass(),
beanDesc.getClassInfo());
Set<String> ignored;
if (ignorals != null) {
boolean ignoreAny = ignorals.getIgnoreUnknown();
builder.setIgnoreUnknownProperties(ignoreAny);
// Or explicit/implicit definitions?
ignored = ignorals.findIgnoredForDeserialization();
for (String propName : ignored) {
builder.addIgnorable(propName);
}
} else {
ignored = Collections.emptySet();
}
// Also, do we have a fallback "any" setter?
AnnotatedMethod anySetterMethod = beanDesc.findAnySetter();
AnnotatedMember anySetterField = null;
if (anySetterMethod != null) {
builder.setAnySetter(constructAnySetter(ctxt, beanDesc, anySetterMethod));
}
else {
anySetterField = beanDesc.findAnySetterField();
if(anySetterField != null) {
builder.setAnySetter(constructAnySetter(ctxt, beanDesc, anySetterField));
}
}
// NOTE: we do NOT add @JsonIgnore'd properties into blocked ones if there's any-setter
// Implicit ones via @JsonIgnore and equivalent?
if (anySetterMethod == null && anySetterField == null) {
Collection<String> ignored2 = beanDesc.getIgnoredPropertyNames();
if (ignored2 != null) {
for (String propName : ignored2) {
// allow ignoral of similarly named JSON property, but do not force;
// latter means NOT adding this to 'ignored':
builder.addIgnorable(propName);
}
}
}
final boolean useGettersAsSetters = ctxt.isEnabled(MapperFeature.USE_GETTERS_AS_SETTERS)
&& ctxt.isEnabled(MapperFeature.AUTO_DETECT_GETTERS);
// Ok: let's then filter out property definitions
List<BeanPropertyDefinition> propDefs = filterBeanProps(ctxt,
beanDesc, builder, beanDesc.findProperties(), ignored);
// After which we can let custom code change the set
if (_factoryConfig.hasDeserializerModifiers()) {
for (BeanDeserializerModifier mod : _factoryConfig.deserializerModifiers()) {
propDefs = mod.updateProperties(ctxt.getConfig(), beanDesc, propDefs);
}
}
// At which point we still have all kinds of properties; not all with mutators:
for (BeanPropertyDefinition propDef : propDefs) {
SettableBeanProperty prop = null;
/* 18-Oct-2013, tatu: Although constructor parameters have highest precedence,
* we need to do linkage (as per [databind#318]), and so need to start with
* other types, and only then create constructor parameter, if any.
*/
if (propDef.hasSetter()) {
JavaType propertyType = propDef.getSetter().getParameterType(0);
prop = constructSettableProperty(ctxt, beanDesc, propDef, propertyType);
} else if (propDef.hasField()) {
JavaType propertyType = propDef.getField().getType();
prop = constructSettableProperty(ctxt, beanDesc, propDef, propertyType);
} else if (useGettersAsSetters && propDef.hasGetter()) {
/* May also need to consider getters
* for Map/Collection properties; but with lowest precedence
*/
AnnotatedMethod getter = propDef.getGetter();
// should only consider Collections and Maps, for now?
Class<?> rawPropertyType = getter.getRawType();
if (Collection.class.isAssignableFrom(rawPropertyType)
|| Map.class.isAssignableFrom(rawPropertyType)) {
prop = constructSetterlessProperty(ctxt, beanDesc, propDef);
}
}
// 25-Sep-2014, tatu: No point in finding constructor parameters for abstract types
// (since they are never used anyway)
if (hasCreatorProps && propDef.hasConstructorParameter()) {
/* If property is passed via constructor parameter, we must
* handle things in special way. Not sure what is the most optimal way...
* for now, let's just call a (new) method in builder, which does nothing.
*/
// but let's call a method just to allow custom builders to be aware...
final String name = propDef.getName();
CreatorProperty cprop = null;
if (creatorProps != null) {
for (SettableBeanProperty cp : creatorProps) {
if (name.equals(cp.getName()) && (cp instanceof CreatorProperty)) {
cprop = (CreatorProperty) cp;
break;
}
}
}
if (cprop == null) {
List<String> n = new ArrayList<>();
for (SettableBeanProperty cp : creatorProps) {
n.add(cp.getName());
}
ctxt.reportBadPropertyDefinition(beanDesc, propDef,
"Could not find creator property with name '%s' (known Creator properties: %s)",
name, n);
continue;
}
if (prop != null) {
cprop.setFallbackSetter(prop);
}
prop = cprop;
builder.addCreatorProperty(cprop);
continue;
}
if (prop != null) {
Class<?>[] views = propDef.findViews();
if (views == null) {
// one more twist: if default inclusion disabled, need to force empty set of views
if (!ctxt.isEnabled(MapperFeature.DEFAULT_VIEW_INCLUSION)) {
views = NO_VIEWS;
}
}
// one more thing before adding to builder: copy any metadata
prop.setViews(views);
builder.addProperty(prop);
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
46 | 6cc8d8445771766c4898071f83e3ead4cbea514bbcd2de41314931f9abcc4bc5 | private static ZipLong unixTimeToZipLong(long l) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private static ZipLong unixTimeToZipLong(long l) {
final long TWO_TO_32 = 0x100000000L;
if (l >= TWO_TO_32) {
throw new IllegalArgumentException("X5455 timestamps must fit in a signed 32 bit integer: " + l);
}
return new ZipLong(l);
}
```
| private static ZipLong unixTimeToZipLong(long l) {
final long TWO_TO_32 = 0x100000000L;
if (l >= TWO_TO_32) {
throw new IllegalArgumentException("X5455 timestamps must fit in a signed 32 bit integer: " + l);
}
return new ZipLong(l);
} | true | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private static ZipLong unixTimeToZipLong(long l) {
final long TWO_TO_32 = 0x100000000L;
if (l >= TWO_TO_32) {
throw new IllegalArgumentException("X5455 timestamps must fit in a signed 32 bit integer: " + l);
}
return new ZipLong(l);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
82 | 6ce1be0fdceeecca216148dbdb23fd0291e20e4ba8f1aadbe972c170259a6805 | static Document parseInputStream(InputStream input, String charsetName, String baseUri, Parser parser) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
static Document parseInputStream(InputStream input, String charsetName, String baseUri, Parser parser) throws IOException {
if (input == null) // empty body
return new Document(baseUri);
input = ConstrainableInputStream.wrap(input, bufferSize, 0);
Document doc = null;
boolean fullyRead = false;
// read the start of the stream and look for a BOM or meta charset
input.mark(bufferSize);
ByteBuffer firstBytes = readToByteBuffer(input, firstReadBufferSize - 1); // -1 because we read one more to see if completed. First read is < buffer size, so can't be invalid.
fullyRead = input.read() == -1;
input.reset();
// look for BOM - overrides any other header or input
BomCharset bomCharset = detectCharsetFromBom(firstBytes);
if (bomCharset != null)
charsetName = bomCharset.charset;
if (charsetName == null) { // determine from meta. safe first parse as UTF-8
String docData = Charset.forName(defaultCharset).decode(firstBytes).toString();
doc = parser.parseInput(docData, baseUri);
// look for <meta http-equiv="Content-Type" content="text/html;charset=gb2312"> or HTML5 <meta charset="gb2312">
Elements metaElements = doc.select("meta[http-equiv=content-type], meta[charset]");
String foundCharset = null; // if not found, will keep utf-8 as best attempt
for (Element meta : metaElements) {
if (meta.hasAttr("http-equiv"))
foundCharset = getCharsetFromContentType(meta.attr("content"));
if (foundCharset == null && meta.hasAttr("charset"))
foundCharset = meta.attr("charset");
if (foundCharset != null)
break;
}
// look for <?xml encoding='ISO-8859-1'?>
if (foundCharset == null && doc.childNodeSize() > 0) {
Node first = doc.childNode(0);
XmlDeclaration decl = null;
if (first instanceof XmlDeclaration)
decl = (XmlDeclaration) first;
else if (first instanceof Comment) {
Comment comment = (Comment) first;
if (comment.isXmlDeclaration())
decl = comment.asXmlDeclaration();
}
if (decl != null) {
if (decl.name().equalsIgnoreCase("xml"))
foundCharset = decl.attr("encoding");
}
}
foundCharset = validateCharset(foundCharset);
if (foundCharset != null && !foundCharset.equalsIgnoreCase(defaultCharset)) { // need to re-decode. (case insensitive check here to match how validate works)
foundCharset = foundCharset.trim().replaceAll("[\"']", "");
charsetName = foundCharset;
doc = null;
} else if (!fullyRead) {
doc = null;
}
} else { // specified by content type header (or by user on file load)
Validate.notEmpty(charsetName, "Must set charset arg to character set of file to parse. Set to null to attempt to detect from HTML");
}
if (doc == null) {
if (charsetName == null)
charsetName = defaultCharset;
BufferedReader reader = new BufferedReader(new InputStreamReader(input, charsetName), bufferSize);
if (bomCharset != null && bomCharset.offset) // creating the buffered reader ignores the input pos, so must skip here
reader.skip(1);
try {
doc = parser.parseInput(reader, baseUri);
} catch (UncheckedIOException e) {
// io exception when parsing (not seen before because reading the stream as we go)
throw e.ioException();
}
Charset charset = Charset.forName(charsetName);
doc.outputSettings().charset(charset);
if (!charset.canEncode()) {
// some charsets can read but not encode; switch to an encodable charset and update the meta el
doc.charset(Charset.forName(defaultCharset));
}
}
input.close();
return doc;
}
```
| static Document parseInputStream(InputStream input, String charsetName, String baseUri, Parser parser) throws IOException {
if (input == null) // empty body
return new Document(baseUri);
input = ConstrainableInputStream.wrap(input, bufferSize, 0);
Document doc = null;
boolean fullyRead = false;
// read the start of the stream and look for a BOM or meta charset
input.mark(bufferSize);
ByteBuffer firstBytes = readToByteBuffer(input, firstReadBufferSize - 1); // -1 because we read one more to see if completed. First read is < buffer size, so can't be invalid.
fullyRead = input.read() == -1;
input.reset();
// look for BOM - overrides any other header or input
BomCharset bomCharset = detectCharsetFromBom(firstBytes);
if (bomCharset != null)
charsetName = bomCharset.charset;
if (charsetName == null) { // determine from meta. safe first parse as UTF-8
String docData = Charset.forName(defaultCharset).decode(firstBytes).toString();
doc = parser.parseInput(docData, baseUri);
// look for <meta http-equiv="Content-Type" content="text/html;charset=gb2312"> or HTML5 <meta charset="gb2312">
Elements metaElements = doc.select("meta[http-equiv=content-type], meta[charset]");
String foundCharset = null; // if not found, will keep utf-8 as best attempt
for (Element meta : metaElements) {
if (meta.hasAttr("http-equiv"))
foundCharset = getCharsetFromContentType(meta.attr("content"));
if (foundCharset == null && meta.hasAttr("charset"))
foundCharset = meta.attr("charset");
if (foundCharset != null)
break;
}
// look for <?xml encoding='ISO-8859-1'?>
if (foundCharset == null && doc.childNodeSize() > 0) {
Node first = doc.childNode(0);
XmlDeclaration decl = null;
if (first instanceof XmlDeclaration)
decl = (XmlDeclaration) first;
else if (first instanceof Comment) {
Comment comment = (Comment) first;
if (comment.isXmlDeclaration())
decl = comment.asXmlDeclaration();
}
if (decl != null) {
if (decl.name().equalsIgnoreCase("xml"))
foundCharset = decl.attr("encoding");
}
}
foundCharset = validateCharset(foundCharset);
if (foundCharset != null && !foundCharset.equalsIgnoreCase(defaultCharset)) { // need to re-decode. (case insensitive check here to match how validate works)
foundCharset = foundCharset.trim().replaceAll("[\"']", "");
charsetName = foundCharset;
doc = null;
} else if (!fullyRead) {
doc = null;
}
} else { // specified by content type header (or by user on file load)
Validate.notEmpty(charsetName, "Must set charset arg to character set of file to parse. Set to null to attempt to detect from HTML");
}
if (doc == null) {
if (charsetName == null)
charsetName = defaultCharset;
BufferedReader reader = new BufferedReader(new InputStreamReader(input, charsetName), bufferSize);
if (bomCharset != null && bomCharset.offset) // creating the buffered reader ignores the input pos, so must skip here
reader.skip(1);
try {
doc = parser.parseInput(reader, baseUri);
} catch (UncheckedIOException e) {
// io exception when parsing (not seen before because reading the stream as we go)
throw e.ioException();
}
Charset charset = Charset.forName(charsetName);
doc.outputSettings().charset(charset);
if (!charset.canEncode()) {
// some charsets can read but not encode; switch to an encodable charset and update the meta el
doc.charset(Charset.forName(defaultCharset));
}
}
input.close();
return doc;
} | false | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
static Document parseInputStream(InputStream input, String charsetName, String baseUri, Parser parser) throws IOException {
if (input == null) // empty body
return new Document(baseUri);
input = ConstrainableInputStream.wrap(input, bufferSize, 0);
Document doc = null;
boolean fullyRead = false;
// read the start of the stream and look for a BOM or meta charset
input.mark(bufferSize);
ByteBuffer firstBytes = readToByteBuffer(input, firstReadBufferSize - 1); // -1 because we read one more to see if completed. First read is < buffer size, so can't be invalid.
fullyRead = input.read() == -1;
input.reset();
// look for BOM - overrides any other header or input
BomCharset bomCharset = detectCharsetFromBom(firstBytes);
if (bomCharset != null)
charsetName = bomCharset.charset;
if (charsetName == null) { // determine from meta. safe first parse as UTF-8
String docData = Charset.forName(defaultCharset).decode(firstBytes).toString();
doc = parser.parseInput(docData, baseUri);
// look for <meta http-equiv="Content-Type" content="text/html;charset=gb2312"> or HTML5 <meta charset="gb2312">
Elements metaElements = doc.select("meta[http-equiv=content-type], meta[charset]");
String foundCharset = null; // if not found, will keep utf-8 as best attempt
for (Element meta : metaElements) {
if (meta.hasAttr("http-equiv"))
foundCharset = getCharsetFromContentType(meta.attr("content"));
if (foundCharset == null && meta.hasAttr("charset"))
foundCharset = meta.attr("charset");
if (foundCharset != null)
break;
}
// look for <?xml encoding='ISO-8859-1'?>
if (foundCharset == null && doc.childNodeSize() > 0) {
Node first = doc.childNode(0);
XmlDeclaration decl = null;
if (first instanceof XmlDeclaration)
decl = (XmlDeclaration) first;
else if (first instanceof Comment) {
Comment comment = (Comment) first;
if (comment.isXmlDeclaration())
decl = comment.asXmlDeclaration();
}
if (decl != null) {
if (decl.name().equalsIgnoreCase("xml"))
foundCharset = decl.attr("encoding");
}
}
foundCharset = validateCharset(foundCharset);
if (foundCharset != null && !foundCharset.equalsIgnoreCase(defaultCharset)) { // need to re-decode. (case insensitive check here to match how validate works)
foundCharset = foundCharset.trim().replaceAll("[\"']", "");
charsetName = foundCharset;
doc = null;
} else if (!fullyRead) {
doc = null;
}
} else { // specified by content type header (or by user on file load)
Validate.notEmpty(charsetName, "Must set charset arg to character set of file to parse. Set to null to attempt to detect from HTML");
}
if (doc == null) {
if (charsetName == null)
charsetName = defaultCharset;
BufferedReader reader = new BufferedReader(new InputStreamReader(input, charsetName), bufferSize);
if (bomCharset != null && bomCharset.offset) // creating the buffered reader ignores the input pos, so must skip here
reader.skip(1);
try {
doc = parser.parseInput(reader, baseUri);
} catch (UncheckedIOException e) {
// io exception when parsing (not seen before because reading the stream as we go)
throw e.ioException();
}
Charset charset = Charset.forName(charsetName);
doc.outputSettings().charset(charset);
if (!charset.canEncode()) {
// some charsets can read but not encode; switch to an encodable charset and update the meta el
doc.charset(Charset.forName(defaultCharset));
}
}
input.close();
return doc;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
107 | 6d42dc40c15309ba1aca80441f5d88550844dbc8f59c918b7b4d322a7e8e0859 | protected final JsonDeserializer<Object> _findDeserializer(DeserializationContext ctxt,
String typeId) throws IOException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/*
/**********************************************************
/* Helper methods for sub-classes
/**********************************************************
*/
protected final JsonDeserializer<Object> _findDeserializer(DeserializationContext ctxt,
String typeId) throws IOException
{
JsonDeserializer<Object> deser = _deserializers.get(typeId);
if (deser == null) {
/* As per [databind#305], need to provide contextual info. But for
* backwards compatibility, let's start by only supporting this
* for base class, not via interface. Later on we can add this
* to the interface, assuming deprecation at base class helps.
*/
JavaType type = _idResolver.typeFromId(ctxt, typeId);
if (type == null) {
// use the default impl if no type id available:
deser = _findDefaultImplDeserializer(ctxt);
if (deser == null) {
// 10-May-2016, tatu: We may get some help...
JavaType actual = _handleUnknownTypeId(ctxt, typeId);
if (actual == null) { // what should this be taken to mean?
// 17-Jan-2019, tatu: As per [databind#2221], better NOT return `null` but...
return null;
}
// ... would this actually work?
deser = ctxt.findContextualValueDeserializer(actual, _property);
}
} else {
/* 16-Dec-2010, tatu: Since nominal type we get here has no (generic) type parameters,
* we actually now need to explicitly narrow from base type (which may have parameterization)
* using raw type.
*
* One complication, though; cannot change 'type class' (simple type to container); otherwise
* we may try to narrow a SimpleType (Object.class) into MapType (Map.class), losing actual
* type in process (getting SimpleType of Map.class which will not work as expected)
*/
if ((_baseType != null)
&& _baseType.getClass() == type.getClass()) {
/* 09-Aug-2015, tatu: Not sure if the second part of the check makes sense;
* but it appears to check that JavaType impl class is the same which is
* important for some reason?
* Disabling the check will break 2 Enum-related tests.
*/
// 19-Jun-2016, tatu: As per [databind#1270] we may actually get full
// generic type with custom type resolvers. If so, should try to retain them.
// Whether this is sufficient to avoid problems remains to be seen, but for
// now it should improve things.
if (!type.hasGenericTypes()) {
type = ctxt.getTypeFactory().constructSpecializedType(_baseType, type.getRawClass());
}
}
deser = ctxt.findContextualValueDeserializer(type, _property);
}
_deserializers.put(typeId, deser);
}
return deser;
}
```
| protected final JsonDeserializer<Object> _findDeserializer(DeserializationContext ctxt,
String typeId) throws IOException
{
JsonDeserializer<Object> deser = _deserializers.get(typeId);
if (deser == null) {
/* As per [databind#305], need to provide contextual info. But for
* backwards compatibility, let's start by only supporting this
* for base class, not via interface. Later on we can add this
* to the interface, assuming deprecation at base class helps.
*/
JavaType type = _idResolver.typeFromId(ctxt, typeId);
if (type == null) {
// use the default impl if no type id available:
deser = _findDefaultImplDeserializer(ctxt);
if (deser == null) {
// 10-May-2016, tatu: We may get some help...
JavaType actual = _handleUnknownTypeId(ctxt, typeId);
if (actual == null) { // what should this be taken to mean?
// 17-Jan-2019, tatu: As per [databind#2221], better NOT return `null` but...
return null;
}
// ... would this actually work?
deser = ctxt.findContextualValueDeserializer(actual, _property);
}
} else {
/* 16-Dec-2010, tatu: Since nominal type we get here has no (generic) type parameters,
* we actually now need to explicitly narrow from base type (which may have parameterization)
* using raw type.
*
* One complication, though; cannot change 'type class' (simple type to container); otherwise
* we may try to narrow a SimpleType (Object.class) into MapType (Map.class), losing actual
* type in process (getting SimpleType of Map.class which will not work as expected)
*/
if ((_baseType != null)
&& _baseType.getClass() == type.getClass()) {
/* 09-Aug-2015, tatu: Not sure if the second part of the check makes sense;
* but it appears to check that JavaType impl class is the same which is
* important for some reason?
* Disabling the check will break 2 Enum-related tests.
*/
// 19-Jun-2016, tatu: As per [databind#1270] we may actually get full
// generic type with custom type resolvers. If so, should try to retain them.
// Whether this is sufficient to avoid problems remains to be seen, but for
// now it should improve things.
if (!type.hasGenericTypes()) {
type = ctxt.getTypeFactory().constructSpecializedType(_baseType, type.getRawClass());
}
}
deser = ctxt.findContextualValueDeserializer(type, _property);
}
_deserializers.put(typeId, deser);
}
return deser;
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/*
/**********************************************************
/* Helper methods for sub-classes
/**********************************************************
*/
protected final JsonDeserializer<Object> _findDeserializer(DeserializationContext ctxt,
String typeId) throws IOException
{
JsonDeserializer<Object> deser = _deserializers.get(typeId);
if (deser == null) {
/* As per [databind#305], need to provide contextual info. But for
* backwards compatibility, let's start by only supporting this
* for base class, not via interface. Later on we can add this
* to the interface, assuming deprecation at base class helps.
*/
JavaType type = _idResolver.typeFromId(ctxt, typeId);
if (type == null) {
// use the default impl if no type id available:
deser = _findDefaultImplDeserializer(ctxt);
if (deser == null) {
// 10-May-2016, tatu: We may get some help...
JavaType actual = _handleUnknownTypeId(ctxt, typeId);
if (actual == null) { // what should this be taken to mean?
// 17-Jan-2019, tatu: As per [databind#2221], better NOT return `null` but...
return null;
}
// ... would this actually work?
deser = ctxt.findContextualValueDeserializer(actual, _property);
}
} else {
/* 16-Dec-2010, tatu: Since nominal type we get here has no (generic) type parameters,
* we actually now need to explicitly narrow from base type (which may have parameterization)
* using raw type.
*
* One complication, though; cannot change 'type class' (simple type to container); otherwise
* we may try to narrow a SimpleType (Object.class) into MapType (Map.class), losing actual
* type in process (getting SimpleType of Map.class which will not work as expected)
*/
if ((_baseType != null)
&& _baseType.getClass() == type.getClass()) {
/* 09-Aug-2015, tatu: Not sure if the second part of the check makes sense;
* but it appears to check that JavaType impl class is the same which is
* important for some reason?
* Disabling the check will break 2 Enum-related tests.
*/
// 19-Jun-2016, tatu: As per [databind#1270] we may actually get full
// generic type with custom type resolvers. If so, should try to retain them.
// Whether this is sufficient to avoid problems remains to be seen, but for
// now it should improve things.
if (!type.hasGenericTypes()) {
type = ctxt.getTypeFactory().constructSpecializedType(_baseType, type.getRawClass());
}
}
deser = ctxt.findContextualValueDeserializer(type, _property);
}
_deserializers.put(typeId, deser);
}
return deser;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
97 | 6d43292cf0dfb19d09b02bf6566a1e3b2c56fbc58c56cd4eaa567581a47abd5e | public double solve(double min, double max) throws MaxIterationsExceededException,
FunctionEvaluationException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Find a zero in the given interval.
* <p>
* Requires that the values of the function at the endpoints have opposite
* signs. An <code>IllegalArgumentException</code> is thrown if this is not
* the case.</p>
*
* @param min the lower bound for the interval.
* @param max the upper bound for the interval.
* @return the value where the function is zero
* @throws MaxIterationsExceededException if the maximum iteration count is exceeded
* @throws FunctionEvaluationException if an error occurs evaluating the
* function
* @throws IllegalArgumentException if min is not less than max or the
* signs of the values of the function at the endpoints are not opposites
*/
public double solve(double min, double max) throws MaxIterationsExceededException,
FunctionEvaluationException {
clearResult();
verifyInterval(min, max);
double ret = Double.NaN;
double yMin = f.value(min);
double yMax = f.value(max);
// Verify bracketing
double sign = yMin * yMax;
if (sign >= 0) {
// check if either value is close to a zero
// neither value is close to zero and min and max do not bracket root.
throw new IllegalArgumentException
("Function values at endpoints do not have different signs." +
" Endpoints: [" + min + "," + max + "]" +
" Values: [" + yMin + "," + yMax + "]");
} else {
// solve using only the first endpoint as initial guess
ret = solve(min, yMin, max, yMax, min, yMin);
// either min or max is a root
}
return ret;
}
```
| public double solve(double min, double max) throws MaxIterationsExceededException,
FunctionEvaluationException {
clearResult();
verifyInterval(min, max);
double ret = Double.NaN;
double yMin = f.value(min);
double yMax = f.value(max);
// Verify bracketing
double sign = yMin * yMax;
if (sign >= 0) {
// check if either value is close to a zero
// neither value is close to zero and min and max do not bracket root.
throw new IllegalArgumentException
("Function values at endpoints do not have different signs." +
" Endpoints: [" + min + "," + max + "]" +
" Values: [" + yMin + "," + yMax + "]");
} else {
// solve using only the first endpoint as initial guess
ret = solve(min, yMin, max, yMax, min, yMin);
// either min or max is a root
}
return ret;
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Find a zero in the given interval.
* <p>
* Requires that the values of the function at the endpoints have opposite
* signs. An <code>IllegalArgumentException</code> is thrown if this is not
* the case.</p>
*
* @param min the lower bound for the interval.
* @param max the upper bound for the interval.
* @return the value where the function is zero
* @throws MaxIterationsExceededException if the maximum iteration count is exceeded
* @throws FunctionEvaluationException if an error occurs evaluating the
* function
* @throws IllegalArgumentException if min is not less than max or the
* signs of the values of the function at the endpoints are not opposites
*/
public double solve(double min, double max) throws MaxIterationsExceededException,
FunctionEvaluationException {
clearResult();
verifyInterval(min, max);
double ret = Double.NaN;
double yMin = f.value(min);
double yMax = f.value(max);
// Verify bracketing
double sign = yMin * yMax;
if (sign >= 0) {
// check if either value is close to a zero
// neither value is close to zero and min and max do not bracket root.
throw new IllegalArgumentException
("Function values at endpoints do not have different signs." +
" Endpoints: [" + min + "," + max + "]" +
" Values: [" + yMin + "," + yMax + "]");
} else {
// solve using only the first endpoint as initial guess
ret = solve(min, yMin, max, yMax, min, yMin);
// either min or max is a root
}
return ret;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
27 | 6d447eda0b62adbaf1a706acc032f45f5a934da5cb1f07b5f0c82988d3cfa453 | @SuppressWarnings("resource")
protected Object deserializeUsingPropertyBasedWithExternalTypeId(JsonParser p, DeserializationContext ctxt)
throws IOException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@SuppressWarnings("resource")
protected Object deserializeUsingPropertyBasedWithExternalTypeId(JsonParser p, DeserializationContext ctxt)
throws IOException
{
final ExternalTypeHandler ext = _externalTypeIdHandler.start();
final PropertyBasedCreator creator = _propertyBasedCreator;
PropertyValueBuffer buffer = creator.startBuilding(p, ctxt, _objectIdReader);
TokenBuffer tokens = new TokenBuffer(p);
tokens.writeStartObject();
JsonToken t = p.getCurrentToken();
for (; t == JsonToken.FIELD_NAME; t = p.nextToken()) {
String propName = p.getCurrentName();
p.nextToken(); // to point to value
// creator property?
SettableBeanProperty creatorProp = creator.findCreatorProperty(propName);
if (creatorProp != null) {
// first: let's check to see if this might be part of value with external type id:
// 11-Sep-2015, tatu: Important; do NOT pass buffer as last arg, but null,
// since it is not the bean
if (ext.handlePropertyValue(p, ctxt, propName, buffer)) {
;
} else {
// Last creator property to set?
if (buffer.assignParameter(creatorProp, _deserializeWithErrorWrapping(p, ctxt, creatorProp))) {
t = p.nextToken(); // to move to following FIELD_NAME/END_OBJECT
Object bean;
try {
bean = creator.build(ctxt, buffer);
} catch (Exception e) {
wrapAndThrow(e, _beanType.getRawClass(), propName, ctxt);
continue; // never gets here
}
// if so, need to copy all remaining tokens into buffer
while (t == JsonToken.FIELD_NAME) {
p.nextToken(); // to skip name
tokens.copyCurrentStructure(p);
t = p.nextToken();
}
if (bean.getClass() != _beanType.getRawClass()) {
// !!! 08-Jul-2011, tatu: Could theoretically support; but for now
// it's too complicated, so bail out
throw ctxt.mappingException("Can not create polymorphic instances with unwrapped values");
}
return ext.complete(p, ctxt, bean);
}
}
continue;
}
// Object Id property?
if (buffer.readIdProperty(propName)) {
continue;
}
// regular property? needs buffering
SettableBeanProperty prop = _beanProperties.find(propName);
if (prop != null) {
buffer.bufferProperty(prop, prop.deserialize(p, ctxt));
continue;
}
// external type id (or property that depends on it)?
if (ext.handlePropertyValue(p, ctxt, propName, null)) {
continue;
}
/* As per [JACKSON-313], things marked as ignorable should not be
* passed to any setter
*/
if (_ignorableProps != null && _ignorableProps.contains(propName)) {
handleIgnoredProperty(p, ctxt, handledType(), propName);
continue;
}
// "any property"?
if (_anySetter != null) {
buffer.bufferAnyProperty(_anySetter, propName, _anySetter.deserialize(p, ctxt));
}
}
// We hit END_OBJECT; resolve the pieces:
try {
return ext.complete(p, ctxt, buffer, creator);
} catch (Exception e) {
wrapInstantiationProblem(e, ctxt);
return null; // never gets here
}
}
```
| @SuppressWarnings("resource")
protected Object deserializeUsingPropertyBasedWithExternalTypeId(JsonParser p, DeserializationContext ctxt)
throws IOException
{
final ExternalTypeHandler ext = _externalTypeIdHandler.start();
final PropertyBasedCreator creator = _propertyBasedCreator;
PropertyValueBuffer buffer = creator.startBuilding(p, ctxt, _objectIdReader);
TokenBuffer tokens = new TokenBuffer(p);
tokens.writeStartObject();
JsonToken t = p.getCurrentToken();
for (; t == JsonToken.FIELD_NAME; t = p.nextToken()) {
String propName = p.getCurrentName();
p.nextToken(); // to point to value
// creator property?
SettableBeanProperty creatorProp = creator.findCreatorProperty(propName);
if (creatorProp != null) {
// first: let's check to see if this might be part of value with external type id:
// 11-Sep-2015, tatu: Important; do NOT pass buffer as last arg, but null,
// since it is not the bean
if (ext.handlePropertyValue(p, ctxt, propName, buffer)) {
;
} else {
// Last creator property to set?
if (buffer.assignParameter(creatorProp, _deserializeWithErrorWrapping(p, ctxt, creatorProp))) {
t = p.nextToken(); // to move to following FIELD_NAME/END_OBJECT
Object bean;
try {
bean = creator.build(ctxt, buffer);
} catch (Exception e) {
wrapAndThrow(e, _beanType.getRawClass(), propName, ctxt);
continue; // never gets here
}
// if so, need to copy all remaining tokens into buffer
while (t == JsonToken.FIELD_NAME) {
p.nextToken(); // to skip name
tokens.copyCurrentStructure(p);
t = p.nextToken();
}
if (bean.getClass() != _beanType.getRawClass()) {
// !!! 08-Jul-2011, tatu: Could theoretically support; but for now
// it's too complicated, so bail out
throw ctxt.mappingException("Can not create polymorphic instances with unwrapped values");
}
return ext.complete(p, ctxt, bean);
}
}
continue;
}
// Object Id property?
if (buffer.readIdProperty(propName)) {
continue;
}
// regular property? needs buffering
SettableBeanProperty prop = _beanProperties.find(propName);
if (prop != null) {
buffer.bufferProperty(prop, prop.deserialize(p, ctxt));
continue;
}
// external type id (or property that depends on it)?
if (ext.handlePropertyValue(p, ctxt, propName, null)) {
continue;
}
/* As per [JACKSON-313], things marked as ignorable should not be
* passed to any setter
*/
if (_ignorableProps != null && _ignorableProps.contains(propName)) {
handleIgnoredProperty(p, ctxt, handledType(), propName);
continue;
}
// "any property"?
if (_anySetter != null) {
buffer.bufferAnyProperty(_anySetter, propName, _anySetter.deserialize(p, ctxt));
}
}
// We hit END_OBJECT; resolve the pieces:
try {
return ext.complete(p, ctxt, buffer, creator);
} catch (Exception e) {
wrapInstantiationProblem(e, ctxt);
return null; // never gets here
}
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@SuppressWarnings("resource")
protected Object deserializeUsingPropertyBasedWithExternalTypeId(JsonParser p, DeserializationContext ctxt)
throws IOException
{
final ExternalTypeHandler ext = _externalTypeIdHandler.start();
final PropertyBasedCreator creator = _propertyBasedCreator;
PropertyValueBuffer buffer = creator.startBuilding(p, ctxt, _objectIdReader);
TokenBuffer tokens = new TokenBuffer(p);
tokens.writeStartObject();
JsonToken t = p.getCurrentToken();
for (; t == JsonToken.FIELD_NAME; t = p.nextToken()) {
String propName = p.getCurrentName();
p.nextToken(); // to point to value
// creator property?
SettableBeanProperty creatorProp = creator.findCreatorProperty(propName);
if (creatorProp != null) {
// first: let's check to see if this might be part of value with external type id:
// 11-Sep-2015, tatu: Important; do NOT pass buffer as last arg, but null,
// since it is not the bean
if (ext.handlePropertyValue(p, ctxt, propName, buffer)) {
;
} else {
// Last creator property to set?
if (buffer.assignParameter(creatorProp, _deserializeWithErrorWrapping(p, ctxt, creatorProp))) {
t = p.nextToken(); // to move to following FIELD_NAME/END_OBJECT
Object bean;
try {
bean = creator.build(ctxt, buffer);
} catch (Exception e) {
wrapAndThrow(e, _beanType.getRawClass(), propName, ctxt);
continue; // never gets here
}
// if so, need to copy all remaining tokens into buffer
while (t == JsonToken.FIELD_NAME) {
p.nextToken(); // to skip name
tokens.copyCurrentStructure(p);
t = p.nextToken();
}
if (bean.getClass() != _beanType.getRawClass()) {
// !!! 08-Jul-2011, tatu: Could theoretically support; but for now
// it's too complicated, so bail out
throw ctxt.mappingException("Can not create polymorphic instances with unwrapped values");
}
return ext.complete(p, ctxt, bean);
}
}
continue;
}
// Object Id property?
if (buffer.readIdProperty(propName)) {
continue;
}
// regular property? needs buffering
SettableBeanProperty prop = _beanProperties.find(propName);
if (prop != null) {
buffer.bufferProperty(prop, prop.deserialize(p, ctxt));
continue;
}
// external type id (or property that depends on it)?
if (ext.handlePropertyValue(p, ctxt, propName, null)) {
continue;
}
/* As per [JACKSON-313], things marked as ignorable should not be
* passed to any setter
*/
if (_ignorableProps != null && _ignorableProps.contains(propName)) {
handleIgnoredProperty(p, ctxt, handledType(), propName);
continue;
}
// "any property"?
if (_anySetter != null) {
buffer.bufferAnyProperty(_anySetter, propName, _anySetter.deserialize(p, ctxt));
}
}
// We hit END_OBJECT; resolve the pieces:
try {
return ext.complete(p, ctxt, buffer, creator);
} catch (Exception e) {
wrapInstantiationProblem(e, ctxt);
return null; // never gets here
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
39 | 6d4b9cb5e08ec167f4185e158bff0272451468773a08a2a6113777b7badc75b1 | @Override
String toStringHelper(boolean forAnnotations) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
String toStringHelper(boolean forAnnotations) {
if (hasReferenceName()) {
return getReferenceName();
} else if (prettyPrint) {
// Don't pretty print recursively.
prettyPrint = false;
// Use a tree set so that the properties are sorted.
Set<String> propertyNames = Sets.newTreeSet();
for (ObjectType current = this;
current != null && !current.isNativeObjectType() &&
propertyNames.size() <= MAX_PRETTY_PRINTED_PROPERTIES;
current = current.getImplicitPrototype()) {
propertyNames.addAll(current.getOwnPropertyNames());
}
StringBuilder sb = new StringBuilder();
sb.append("{");
int i = 0;
for (String property : propertyNames) {
if (i > 0) {
sb.append(", ");
}
sb.append(property);
sb.append(": ");
sb.append(getPropertyType(property).toStringHelper(forAnnotations));
++i;
if (!forAnnotations && i == MAX_PRETTY_PRINTED_PROPERTIES) {
sb.append(", ...");
break;
}
}
sb.append("}");
prettyPrint = true;
return sb.toString();
} else {
return forAnnotations ? "?" : "{...}";
}
}
```
| @Override
String toStringHelper(boolean forAnnotations) {
if (hasReferenceName()) {
return getReferenceName();
} else if (prettyPrint) {
// Don't pretty print recursively.
prettyPrint = false;
// Use a tree set so that the properties are sorted.
Set<String> propertyNames = Sets.newTreeSet();
for (ObjectType current = this;
current != null && !current.isNativeObjectType() &&
propertyNames.size() <= MAX_PRETTY_PRINTED_PROPERTIES;
current = current.getImplicitPrototype()) {
propertyNames.addAll(current.getOwnPropertyNames());
}
StringBuilder sb = new StringBuilder();
sb.append("{");
int i = 0;
for (String property : propertyNames) {
if (i > 0) {
sb.append(", ");
}
sb.append(property);
sb.append(": ");
sb.append(getPropertyType(property).toStringHelper(forAnnotations));
++i;
if (!forAnnotations && i == MAX_PRETTY_PRINTED_PROPERTIES) {
sb.append(", ...");
break;
}
}
sb.append("}");
prettyPrint = true;
return sb.toString();
} else {
return forAnnotations ? "?" : "{...}";
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
String toStringHelper(boolean forAnnotations) {
if (hasReferenceName()) {
return getReferenceName();
} else if (prettyPrint) {
// Don't pretty print recursively.
prettyPrint = false;
// Use a tree set so that the properties are sorted.
Set<String> propertyNames = Sets.newTreeSet();
for (ObjectType current = this;
current != null && !current.isNativeObjectType() &&
propertyNames.size() <= MAX_PRETTY_PRINTED_PROPERTIES;
current = current.getImplicitPrototype()) {
propertyNames.addAll(current.getOwnPropertyNames());
}
StringBuilder sb = new StringBuilder();
sb.append("{");
int i = 0;
for (String property : propertyNames) {
if (i > 0) {
sb.append(", ");
}
sb.append(property);
sb.append(": ");
sb.append(getPropertyType(property).toStringHelper(forAnnotations));
++i;
if (!forAnnotations && i == MAX_PRETTY_PRINTED_PROPERTIES) {
sb.append(", ...");
break;
}
}
sb.append("}");
prettyPrint = true;
return sb.toString();
} else {
return forAnnotations ? "?" : "{...}";
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
11 | 6d9263f8f6b9ee2d7992938d39b557e3b236296b5600d3268f45b92a9ff351d2 | @Override
public Number read(JsonReader in) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public Number read(JsonReader in) throws IOException {
JsonToken jsonToken = in.peek();
switch (jsonToken) {
case NULL:
in.nextNull();
return null;
case NUMBER:
case STRING:
return new LazilyParsedNumber(in.nextString());
default:
throw new JsonSyntaxException("Expecting number, got: " + jsonToken);
}
}
```
| @Override
public Number read(JsonReader in) throws IOException {
JsonToken jsonToken = in.peek();
switch (jsonToken) {
case NULL:
in.nextNull();
return null;
case NUMBER:
case STRING:
return new LazilyParsedNumber(in.nextString());
default:
throw new JsonSyntaxException("Expecting number, got: " + jsonToken);
}
} | false | Gson | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public Number read(JsonReader in) throws IOException {
JsonToken jsonToken = in.peek();
switch (jsonToken) {
case NULL:
in.nextNull();
return null;
case NUMBER:
case STRING:
return new LazilyParsedNumber(in.nextString());
default:
throw new JsonSyntaxException("Expecting number, got: " + jsonToken);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
6 | 6dc619741ab79c0db0ab0ff6c644f59e1227e9a6721ad0965be06171be9eeff9 | public boolean equals(Object obj) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Tests the list for equality with another object (typically also a list).
*
* @param obj the other object (<code>null</code> permitted).
*
* @return A boolean.
*/
public boolean equals(Object obj) {
if (obj == this) {
return true;
}
if (!(obj instanceof ShapeList)) {
return false;
}
return super.equals(obj);
}
```
| public boolean equals(Object obj) {
if (obj == this) {
return true;
}
if (!(obj instanceof ShapeList)) {
return false;
}
return super.equals(obj);
} | true | Chart | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Tests the list for equality with another object (typically also a list).
*
* @param obj the other object (<code>null</code> permitted).
*
* @return A boolean.
*/
public boolean equals(Object obj) {
if (obj == this) {
return true;
}
if (!(obj instanceof ShapeList)) {
return false;
}
return super.equals(obj);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
70 | 6ddd5903ae17fc4e8359b2c18b9dd27e08b42955402a21591b47632eda2f7e65 | private void declareArguments(Node functionNode) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Declares all of a function's arguments.
*/
private void declareArguments(Node functionNode) {
Node astParameters = functionNode.getFirstChild().getNext();
Node body = astParameters.getNext();
FunctionType functionType = (FunctionType) functionNode.getJSType();
if (functionType != null) {
Node jsDocParameters = functionType.getParametersNode();
if (jsDocParameters != null) {
Node jsDocParameter = jsDocParameters.getFirstChild();
for (Node astParameter : astParameters.children()) {
if (jsDocParameter != null) {
defineSlot(astParameter, functionNode,
jsDocParameter.getJSType(), false);
jsDocParameter = jsDocParameter.getNext();
} else {
defineSlot(astParameter, functionNode, null, true);
}
}
}
}
} // end declareArguments
```
| private void declareArguments(Node functionNode) {
Node astParameters = functionNode.getFirstChild().getNext();
Node body = astParameters.getNext();
FunctionType functionType = (FunctionType) functionNode.getJSType();
if (functionType != null) {
Node jsDocParameters = functionType.getParametersNode();
if (jsDocParameters != null) {
Node jsDocParameter = jsDocParameters.getFirstChild();
for (Node astParameter : astParameters.children()) {
if (jsDocParameter != null) {
defineSlot(astParameter, functionNode,
jsDocParameter.getJSType(), false);
jsDocParameter = jsDocParameter.getNext();
} else {
defineSlot(astParameter, functionNode, null, true);
}
}
}
}
} // end declareArguments | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Declares all of a function's arguments.
*/
private void declareArguments(Node functionNode) {
Node astParameters = functionNode.getFirstChild().getNext();
Node body = astParameters.getNext();
FunctionType functionType = (FunctionType) functionNode.getJSType();
if (functionType != null) {
Node jsDocParameters = functionType.getParametersNode();
if (jsDocParameters != null) {
Node jsDocParameter = jsDocParameters.getFirstChild();
for (Node astParameter : astParameters.children()) {
if (jsDocParameter != null) {
defineSlot(astParameter, functionNode,
jsDocParameter.getJSType(), false);
jsDocParameter = jsDocParameter.getNext();
} else {
defineSlot(astParameter, functionNode, null, true);
}
}
}
}
} // end declareArguments
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
102 | 6de8330b8e0f402253f8a18caa6d4792d59bf882d4a7770bb9103c4c06ec28fa | @Override
public void process(Node externs, Node root) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public void process(Node externs, Node root) {
NodeTraversal.traverse(compiler, root, this);
if (MAKE_LOCAL_NAMES_UNIQUE) {
MakeDeclaredNamesUnique renamer = new MakeDeclaredNamesUnique();
NodeTraversal t = new NodeTraversal(compiler, renamer);
t.traverseRoots(externs, root);
}
removeDuplicateDeclarations(root);
new PropogateConstantAnnotations(compiler, assertOnChange)
.process(externs, root);
}
```
| @Override
public void process(Node externs, Node root) {
NodeTraversal.traverse(compiler, root, this);
if (MAKE_LOCAL_NAMES_UNIQUE) {
MakeDeclaredNamesUnique renamer = new MakeDeclaredNamesUnique();
NodeTraversal t = new NodeTraversal(compiler, renamer);
t.traverseRoots(externs, root);
}
removeDuplicateDeclarations(root);
new PropogateConstantAnnotations(compiler, assertOnChange)
.process(externs, root);
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public void process(Node externs, Node root) {
NodeTraversal.traverse(compiler, root, this);
if (MAKE_LOCAL_NAMES_UNIQUE) {
MakeDeclaredNamesUnique renamer = new MakeDeclaredNamesUnique();
NodeTraversal t = new NodeTraversal(compiler, renamer);
t.traverseRoots(externs, root);
}
removeDuplicateDeclarations(root);
new PropogateConstantAnnotations(compiler, assertOnChange)
.process(externs, root);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
16 | 6df395e90350dedfee4dd9a93af1e0b6760c1f42875fef1705e064dd5de832b4 | public ArchiveInputStream createArchiveInputStream(final InputStream in)
throws ArchiveException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Create an archive input stream from an input stream, autodetecting
* the archive type from the first few bytes of the stream. The InputStream
* must support marks, like BufferedInputStream.
*
* @param in the input stream
* @return the archive input stream
* @throws ArchiveException if the archiver name is not known
* @throws IllegalArgumentException if the stream is null or does not support mark
*/
public ArchiveInputStream createArchiveInputStream(final InputStream in)
throws ArchiveException {
if (in == null) {
throw new IllegalArgumentException("Stream must not be null.");
}
if (!in.markSupported()) {
throw new IllegalArgumentException("Mark is not supported.");
}
final byte[] signature = new byte[12];
in.mark(signature.length);
try {
int signatureLength = in.read(signature);
in.reset();
if (ZipArchiveInputStream.matches(signature, signatureLength)) {
return new ZipArchiveInputStream(in);
} else if (JarArchiveInputStream.matches(signature, signatureLength)) {
return new JarArchiveInputStream(in);
} else if (ArArchiveInputStream.matches(signature, signatureLength)) {
return new ArArchiveInputStream(in);
} else if (CpioArchiveInputStream.matches(signature, signatureLength)) {
return new CpioArchiveInputStream(in);
}
// Dump needs a bigger buffer to check the signature;
final byte[] dumpsig = new byte[32];
in.mark(dumpsig.length);
signatureLength = in.read(dumpsig);
in.reset();
if (DumpArchiveInputStream.matches(dumpsig, signatureLength)) {
return new DumpArchiveInputStream(in);
}
// Tar needs an even bigger buffer to check the signature; read the first block
final byte[] tarheader = new byte[512];
in.mark(tarheader.length);
signatureLength = in.read(tarheader);
in.reset();
if (TarArchiveInputStream.matches(tarheader, signatureLength)) {
return new TarArchiveInputStream(in);
}
// COMPRESS-117 - improve auto-recognition
if (signatureLength >= 512) {
try {
TarArchiveInputStream tais = new TarArchiveInputStream(new ByteArrayInputStream(tarheader));
// COMPRESS-191 - verify the header checksum
if (tais.getNextTarEntry().isCheckSumOK()) {
return new TarArchiveInputStream(in);
}
} catch (Exception e) { // NOPMD
// can generate IllegalArgumentException as well
// as IOException
// autodetection, simply not a TAR
// ignored
}
}
} catch (IOException e) {
throw new ArchiveException("Could not use reset and mark operations.", e);
}
throw new ArchiveException("No Archiver found for the stream signature");
}
```
| public ArchiveInputStream createArchiveInputStream(final InputStream in)
throws ArchiveException {
if (in == null) {
throw new IllegalArgumentException("Stream must not be null.");
}
if (!in.markSupported()) {
throw new IllegalArgumentException("Mark is not supported.");
}
final byte[] signature = new byte[12];
in.mark(signature.length);
try {
int signatureLength = in.read(signature);
in.reset();
if (ZipArchiveInputStream.matches(signature, signatureLength)) {
return new ZipArchiveInputStream(in);
} else if (JarArchiveInputStream.matches(signature, signatureLength)) {
return new JarArchiveInputStream(in);
} else if (ArArchiveInputStream.matches(signature, signatureLength)) {
return new ArArchiveInputStream(in);
} else if (CpioArchiveInputStream.matches(signature, signatureLength)) {
return new CpioArchiveInputStream(in);
}
// Dump needs a bigger buffer to check the signature;
final byte[] dumpsig = new byte[32];
in.mark(dumpsig.length);
signatureLength = in.read(dumpsig);
in.reset();
if (DumpArchiveInputStream.matches(dumpsig, signatureLength)) {
return new DumpArchiveInputStream(in);
}
// Tar needs an even bigger buffer to check the signature; read the first block
final byte[] tarheader = new byte[512];
in.mark(tarheader.length);
signatureLength = in.read(tarheader);
in.reset();
if (TarArchiveInputStream.matches(tarheader, signatureLength)) {
return new TarArchiveInputStream(in);
}
// COMPRESS-117 - improve auto-recognition
if (signatureLength >= 512) {
try {
TarArchiveInputStream tais = new TarArchiveInputStream(new ByteArrayInputStream(tarheader));
// COMPRESS-191 - verify the header checksum
if (tais.getNextTarEntry().isCheckSumOK()) {
return new TarArchiveInputStream(in);
}
} catch (Exception e) { // NOPMD
// can generate IllegalArgumentException as well
// as IOException
// autodetection, simply not a TAR
// ignored
}
}
} catch (IOException e) {
throw new ArchiveException("Could not use reset and mark operations.", e);
}
throw new ArchiveException("No Archiver found for the stream signature");
} | false | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Create an archive input stream from an input stream, autodetecting
* the archive type from the first few bytes of the stream. The InputStream
* must support marks, like BufferedInputStream.
*
* @param in the input stream
* @return the archive input stream
* @throws ArchiveException if the archiver name is not known
* @throws IllegalArgumentException if the stream is null or does not support mark
*/
public ArchiveInputStream createArchiveInputStream(final InputStream in)
throws ArchiveException {
if (in == null) {
throw new IllegalArgumentException("Stream must not be null.");
}
if (!in.markSupported()) {
throw new IllegalArgumentException("Mark is not supported.");
}
final byte[] signature = new byte[12];
in.mark(signature.length);
try {
int signatureLength = in.read(signature);
in.reset();
if (ZipArchiveInputStream.matches(signature, signatureLength)) {
return new ZipArchiveInputStream(in);
} else if (JarArchiveInputStream.matches(signature, signatureLength)) {
return new JarArchiveInputStream(in);
} else if (ArArchiveInputStream.matches(signature, signatureLength)) {
return new ArArchiveInputStream(in);
} else if (CpioArchiveInputStream.matches(signature, signatureLength)) {
return new CpioArchiveInputStream(in);
}
// Dump needs a bigger buffer to check the signature;
final byte[] dumpsig = new byte[32];
in.mark(dumpsig.length);
signatureLength = in.read(dumpsig);
in.reset();
if (DumpArchiveInputStream.matches(dumpsig, signatureLength)) {
return new DumpArchiveInputStream(in);
}
// Tar needs an even bigger buffer to check the signature; read the first block
final byte[] tarheader = new byte[512];
in.mark(tarheader.length);
signatureLength = in.read(tarheader);
in.reset();
if (TarArchiveInputStream.matches(tarheader, signatureLength)) {
return new TarArchiveInputStream(in);
}
// COMPRESS-117 - improve auto-recognition
if (signatureLength >= 512) {
try {
TarArchiveInputStream tais = new TarArchiveInputStream(new ByteArrayInputStream(tarheader));
// COMPRESS-191 - verify the header checksum
if (tais.getNextTarEntry().isCheckSumOK()) {
return new TarArchiveInputStream(in);
}
} catch (Exception e) { // NOPMD
// can generate IllegalArgumentException as well
// as IOException
// autodetection, simply not a TAR
// ignored
}
}
} catch (IOException e) {
throw new ArchiveException("Could not use reset and mark operations.", e);
}
throw new ArchiveException("No Archiver found for the stream signature");
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
38 | 6e0aad84e8b4a093328a4bc6df19dd565b2d7e48c8ad3f63b1c5bd090805e4c9 | public StringBuffer format(Calendar calendar, StringBuffer buf) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Formats a <code>Calendar</code> object into the
* supplied <code>StringBuffer</code>.</p>
*
* @param calendar the calendar to format
* @param buf the buffer to format into
* @return the specified string buffer
*/
public StringBuffer format(Calendar calendar, StringBuffer buf) {
if (mTimeZoneForced) {
calendar.getTime(); /// LANG-538
calendar = (Calendar) calendar.clone();
calendar.setTimeZone(mTimeZone);
}
return applyRules(calendar, buf);
}
```
| public StringBuffer format(Calendar calendar, StringBuffer buf) {
if (mTimeZoneForced) {
calendar.getTime(); /// LANG-538
calendar = (Calendar) calendar.clone();
calendar.setTimeZone(mTimeZone);
}
return applyRules(calendar, buf);
} | false | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Formats a <code>Calendar</code> object into the
* supplied <code>StringBuffer</code>.</p>
*
* @param calendar the calendar to format
* @param buf the buffer to format into
* @return the specified string buffer
*/
public StringBuffer format(Calendar calendar, StringBuffer buf) {
if (mTimeZoneForced) {
calendar.getTime(); /// LANG-538
calendar = (Calendar) calendar.clone();
calendar.setTimeZone(mTimeZone);
}
return applyRules(calendar, buf);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
45 | 6e2a1aea1d777f18b1703820fe1092857e2b74d6d4efedbf5747162cba720153 | @Override
public JsonSerializer<?> createContextual(SerializerProvider serializers,
BeanProperty property) throws JsonMappingException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public JsonSerializer<?> createContextual(SerializerProvider serializers,
BeanProperty property) throws JsonMappingException
{
if (property != null) {
JsonFormat.Value format = serializers.getAnnotationIntrospector().findFormat((Annotated)property.getMember());
if (format != null) {
// Simple case first: serialize as numeric timestamp?
JsonFormat.Shape shape = format.getShape();
if (shape.isNumeric()) {
return withFormat(Boolean.TRUE, null);
}
if ((shape == JsonFormat.Shape.STRING) || format.hasPattern()
|| format.hasLocale() || format.hasTimeZone()) {
TimeZone tz = format.getTimeZone();
final String pattern = format.hasPattern()
? format.getPattern()
: StdDateFormat.DATE_FORMAT_STR_ISO8601;
final Locale loc = format.hasLocale()
? format.getLocale()
: serializers.getLocale();
SimpleDateFormat df = new SimpleDateFormat(pattern, loc);
if (tz == null) {
tz = serializers.getTimeZone();
}
df.setTimeZone(tz);
return withFormat(Boolean.FALSE, df);
}
}
}
return this;
}
```
| @Override
public JsonSerializer<?> createContextual(SerializerProvider serializers,
BeanProperty property) throws JsonMappingException
{
if (property != null) {
JsonFormat.Value format = serializers.getAnnotationIntrospector().findFormat((Annotated)property.getMember());
if (format != null) {
// Simple case first: serialize as numeric timestamp?
JsonFormat.Shape shape = format.getShape();
if (shape.isNumeric()) {
return withFormat(Boolean.TRUE, null);
}
if ((shape == JsonFormat.Shape.STRING) || format.hasPattern()
|| format.hasLocale() || format.hasTimeZone()) {
TimeZone tz = format.getTimeZone();
final String pattern = format.hasPattern()
? format.getPattern()
: StdDateFormat.DATE_FORMAT_STR_ISO8601;
final Locale loc = format.hasLocale()
? format.getLocale()
: serializers.getLocale();
SimpleDateFormat df = new SimpleDateFormat(pattern, loc);
if (tz == null) {
tz = serializers.getTimeZone();
}
df.setTimeZone(tz);
return withFormat(Boolean.FALSE, df);
}
}
}
return this;
} | false | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public JsonSerializer<?> createContextual(SerializerProvider serializers,
BeanProperty property) throws JsonMappingException
{
if (property != null) {
JsonFormat.Value format = serializers.getAnnotationIntrospector().findFormat((Annotated)property.getMember());
if (format != null) {
// Simple case first: serialize as numeric timestamp?
JsonFormat.Shape shape = format.getShape();
if (shape.isNumeric()) {
return withFormat(Boolean.TRUE, null);
}
if ((shape == JsonFormat.Shape.STRING) || format.hasPattern()
|| format.hasLocale() || format.hasTimeZone()) {
TimeZone tz = format.getTimeZone();
final String pattern = format.hasPattern()
? format.getPattern()
: StdDateFormat.DATE_FORMAT_STR_ISO8601;
final Locale loc = format.hasLocale()
? format.getLocale()
: serializers.getLocale();
SimpleDateFormat df = new SimpleDateFormat(pattern, loc);
if (tz == null) {
tz = serializers.getTimeZone();
}
df.setTimeZone(tz);
return withFormat(Boolean.FALSE, df);
}
}
}
return this;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
87 | 6e53116b5b0191e7ca49481008c21400a795c9ddc8c2df72e64736c71c7fce2a | private boolean isFoldableExpressBlock(Node n) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* @return Whether the node is a block with a single statement that is
* an expression.
*/
private boolean isFoldableExpressBlock(Node n) {
if (n.getType() == Token.BLOCK) {
if (n.hasOneChild()) {
Node maybeExpr = n.getFirstChild();
// IE has a bug where event handlers behave differently when
// their return value is used vs. when their return value is in
// an EXPR_RESULT. It's pretty freaking weird. See:
// http://code.google.com/p/closure-compiler/issues/detail?id=291
// We try to detect this case, and not fold EXPR_RESULTs
// into other expressions.
// We only have to worry about methods with an implicit 'this'
// param, or this doesn't happen.
return NodeUtil.isExpressionNode(maybeExpr);
}
}
return false;
}
```
| private boolean isFoldableExpressBlock(Node n) {
if (n.getType() == Token.BLOCK) {
if (n.hasOneChild()) {
Node maybeExpr = n.getFirstChild();
// IE has a bug where event handlers behave differently when
// their return value is used vs. when their return value is in
// an EXPR_RESULT. It's pretty freaking weird. See:
// http://code.google.com/p/closure-compiler/issues/detail?id=291
// We try to detect this case, and not fold EXPR_RESULTs
// into other expressions.
// We only have to worry about methods with an implicit 'this'
// param, or this doesn't happen.
return NodeUtil.isExpressionNode(maybeExpr);
}
}
return false;
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* @return Whether the node is a block with a single statement that is
* an expression.
*/
private boolean isFoldableExpressBlock(Node n) {
if (n.getType() == Token.BLOCK) {
if (n.hasOneChild()) {
Node maybeExpr = n.getFirstChild();
// IE has a bug where event handlers behave differently when
// their return value is used vs. when their return value is in
// an EXPR_RESULT. It's pretty freaking weird. See:
// http://code.google.com/p/closure-compiler/issues/detail?id=291
// We try to detect this case, and not fold EXPR_RESULTs
// into other expressions.
// We only have to worry about methods with an implicit 'this'
// param, or this doesn't happen.
return NodeUtil.isExpressionNode(maybeExpr);
}
}
return false;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
46 | 6e5393357bd3924b9bab1c8035fe1ab26bf891ddc993b5623536a53ebbd07f8b | @Override
public StringBuilder getGenericSignature(StringBuilder sb)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public StringBuilder getGenericSignature(StringBuilder sb)
{
_classSignature(_class, sb, false);
sb.append('<');
sb = _referencedType.getGenericSignature(sb);
sb.append(';');
return sb;
}
```
| @Override
public StringBuilder getGenericSignature(StringBuilder sb)
{
_classSignature(_class, sb, false);
sb.append('<');
sb = _referencedType.getGenericSignature(sb);
sb.append(';');
return sb;
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public StringBuilder getGenericSignature(StringBuilder sb)
{
_classSignature(_class, sb, false);
sb.append('<');
sb = _referencedType.getGenericSignature(sb);
sb.append(';');
return sb;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
38 | 6e8a85a9b4d5805db842753f826dc5713629be502dbea36ee4bf410d59660c63 | @Override
public boolean isDirectory() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Return whether or not this entry represents a directory.
*
* @return True if this entry is a directory.
*/
@Override
public boolean isDirectory() {
if (file != null) {
return file.isDirectory();
}
if (linkFlag == LF_DIR) {
return true;
}
if (getName().endsWith("/")) {
return true;
}
return false;
}
```
| @Override
public boolean isDirectory() {
if (file != null) {
return file.isDirectory();
}
if (linkFlag == LF_DIR) {
return true;
}
if (getName().endsWith("/")) {
return true;
}
return false;
} | true | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Return whether or not this entry represents a directory.
*
* @return True if this entry is a directory.
*/
@Override
public boolean isDirectory() {
if (file != null) {
return file.isDirectory();
}
if (linkFlag == LF_DIR) {
return true;
}
if (getName().endsWith("/")) {
return true;
}
return false;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
132 | 6e97cc02f573a42dc706a8dae57a0d65e6982dbe288cc81d4fb378ddb295bf76 | private Node tryMinimizeIf(Node n) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Try turning IF nodes into smaller HOOKs
*
* Returns the replacement for n or the original if no replacement was
* necessary.
*/
private Node tryMinimizeIf(Node n) {
Node parent = n.getParent();
Node cond = n.getFirstChild();
/* If the condition is a literal, we'll let other
* optimizations try to remove useless code.
*/
if (NodeUtil.isLiteralValue(cond, true)) {
return n;
}
Node thenBranch = cond.getNext();
Node elseBranch = thenBranch.getNext();
if (elseBranch == null) {
if (isFoldableExpressBlock(thenBranch)) {
Node expr = getBlockExpression(thenBranch);
if (!late && isPropertyAssignmentInExpression(expr)) {
// Keep opportunities for CollapseProperties such as
// a.longIdentifier || a.longIdentifier = ... -> var a = ...;
// until CollapseProperties has been run.
return n;
}
if (cond.isNot()) {
// if(!x)bar(); -> x||bar();
if (isLowerPrecedenceInExpression(cond, OR_PRECEDENCE) &&
isLowerPrecedenceInExpression(expr.getFirstChild(),
OR_PRECEDENCE)) {
// It's not okay to add two sets of parentheses.
return n;
}
Node or = IR.or(
cond.removeFirstChild(),
expr.removeFirstChild()).srcref(n);
Node newExpr = NodeUtil.newExpr(or);
parent.replaceChild(n, newExpr);
reportCodeChange();
return newExpr;
}
// if(x)foo(); -> x&&foo();
if (isLowerPrecedenceInExpression(cond, AND_PRECEDENCE) &&
isLowerPrecedenceInExpression(expr.getFirstChild(),
AND_PRECEDENCE)) {
// One additional set of parentheses is worth the change even if
// there is no immediate code size win. However, two extra pair of
// {}, we would have to think twice. (unless we know for sure the
// we can further optimize its parent.
return n;
}
n.removeChild(cond);
Node and = IR.and(cond, expr.removeFirstChild()).srcref(n);
Node newExpr = NodeUtil.newExpr(and);
parent.replaceChild(n, newExpr);
reportCodeChange();
return newExpr;
} else {
// Try to combine two IF-ELSE
if (NodeUtil.isStatementBlock(thenBranch) &&
thenBranch.hasOneChild()) {
Node innerIf = thenBranch.getFirstChild();
if (innerIf.isIf()) {
Node innerCond = innerIf.getFirstChild();
Node innerThenBranch = innerCond.getNext();
Node innerElseBranch = innerThenBranch.getNext();
if (innerElseBranch == null &&
!(isLowerPrecedenceInExpression(cond, AND_PRECEDENCE) &&
isLowerPrecedenceInExpression(innerCond, AND_PRECEDENCE))) {
n.detachChildren();
n.addChildToBack(
IR.and(
cond,
innerCond.detachFromParent())
.srcref(cond));
n.addChildrenToBack(innerThenBranch.detachFromParent());
reportCodeChange();
// Not worth trying to fold the current IF-ELSE into && because
// the inner IF-ELSE wasn't able to be folded into && anyways.
return n;
}
}
}
}
return n;
}
/* TODO(dcc) This modifies the siblings of n, which is undesirable for a
* peephole optimization. This should probably get moved to another pass.
*/
tryRemoveRepeatedStatements(n);
// if(!x)foo();else bar(); -> if(x)bar();else foo();
// An additional set of curly braces isn't worth it.
if (cond.isNot() && !consumesDanglingElse(elseBranch)) {
n.replaceChild(cond, cond.removeFirstChild());
n.removeChild(thenBranch);
n.addChildToBack(thenBranch);
reportCodeChange();
return n;
}
// if(x)return 1;else return 2; -> return x?1:2;
if (isReturnExpressBlock(thenBranch) && isReturnExpressBlock(elseBranch)) {
Node thenExpr = getBlockReturnExpression(thenBranch);
Node elseExpr = getBlockReturnExpression(elseBranch);
n.removeChild(cond);
thenExpr.detachFromParent();
elseExpr.detachFromParent();
// note - we ignore any cases with "return;", technically this
// can be converted to "return undefined;" or some variant, but
// that does not help code size.
Node returnNode = IR.returnNode(
IR.hook(cond, thenExpr, elseExpr)
.srcref(n));
parent.replaceChild(n, returnNode);
reportCodeChange();
return returnNode;
}
boolean thenBranchIsExpressionBlock = isFoldableExpressBlock(thenBranch);
boolean elseBranchIsExpressionBlock = isFoldableExpressBlock(elseBranch);
if (thenBranchIsExpressionBlock && elseBranchIsExpressionBlock) {
Node thenOp = getBlockExpression(thenBranch).getFirstChild();
Node elseOp = getBlockExpression(elseBranch).getFirstChild();
if (thenOp.getType() == elseOp.getType()) {
// if(x)a=1;else a=2; -> a=x?1:2;
if (NodeUtil.isAssignmentOp(thenOp)) {
Node lhs = thenOp.getFirstChild();
if (areNodesEqualForInlining(lhs, elseOp.getFirstChild()) &&
// if LHS has side effects, don't proceed [since the optimization
// evaluates LHS before cond]
// NOTE - there are some circumstances where we can
// proceed even if there are side effects...
!mayEffectMutableState(lhs) &&
(!mayHaveSideEffects(cond) ||
(thenOp.isAssign() && thenOp.getFirstChild().isName()))) {
n.removeChild(cond);
Node assignName = thenOp.removeFirstChild();
Node thenExpr = thenOp.removeFirstChild();
Node elseExpr = elseOp.getLastChild();
elseOp.removeChild(elseExpr);
Node hookNode = IR.hook(cond, thenExpr, elseExpr).srcref(n);
Node assign = new Node(thenOp.getType(), assignName, hookNode)
.srcref(thenOp);
Node expr = NodeUtil.newExpr(assign);
parent.replaceChild(n, expr);
reportCodeChange();
return expr;
}
}
}
// if(x)foo();else bar(); -> x?foo():bar()
n.removeChild(cond);
thenOp.detachFromParent();
elseOp.detachFromParent();
Node expr = IR.exprResult(
IR.hook(cond, thenOp, elseOp).srcref(n));
parent.replaceChild(n, expr);
reportCodeChange();
return expr;
}
boolean thenBranchIsVar = isVarBlock(thenBranch);
boolean elseBranchIsVar = isVarBlock(elseBranch);
// if(x)var y=1;else y=2 -> var y=x?1:2
if (thenBranchIsVar && elseBranchIsExpressionBlock &&
getBlockExpression(elseBranch).getFirstChild().isAssign()) {
Node var = getBlockVar(thenBranch);
Node elseAssign = getBlockExpression(elseBranch).getFirstChild();
Node name1 = var.getFirstChild();
Node maybeName2 = elseAssign.getFirstChild();
if (name1.hasChildren()
&& maybeName2.isName()
&& name1.getString().equals(maybeName2.getString())) {
Node thenExpr = name1.removeChildren();
Node elseExpr = elseAssign.getLastChild().detachFromParent();
cond.detachFromParent();
Node hookNode = IR.hook(cond, thenExpr, elseExpr)
.srcref(n);
var.detachFromParent();
name1.addChildrenToBack(hookNode);
parent.replaceChild(n, var);
reportCodeChange();
return var;
}
// if(x)y=1;else var y=2 -> var y=x?1:2
} else if (elseBranchIsVar && thenBranchIsExpressionBlock &&
getBlockExpression(thenBranch).getFirstChild().isAssign()) {
Node var = getBlockVar(elseBranch);
Node thenAssign = getBlockExpression(thenBranch).getFirstChild();
Node maybeName1 = thenAssign.getFirstChild();
Node name2 = var.getFirstChild();
if (name2.hasChildren()
&& maybeName1.isName()
&& maybeName1.getString().equals(name2.getString())) {
Node thenExpr = thenAssign.getLastChild().detachFromParent();
Node elseExpr = name2.removeChildren();
cond.detachFromParent();
Node hookNode = IR.hook(cond, thenExpr, elseExpr)
.srcref(n);
var.detachFromParent();
name2.addChildrenToBack(hookNode);
parent.replaceChild(n, var);
reportCodeChange();
return var;
}
}
return n;
}
```
| private Node tryMinimizeIf(Node n) {
Node parent = n.getParent();
Node cond = n.getFirstChild();
/* If the condition is a literal, we'll let other
* optimizations try to remove useless code.
*/
if (NodeUtil.isLiteralValue(cond, true)) {
return n;
}
Node thenBranch = cond.getNext();
Node elseBranch = thenBranch.getNext();
if (elseBranch == null) {
if (isFoldableExpressBlock(thenBranch)) {
Node expr = getBlockExpression(thenBranch);
if (!late && isPropertyAssignmentInExpression(expr)) {
// Keep opportunities for CollapseProperties such as
// a.longIdentifier || a.longIdentifier = ... -> var a = ...;
// until CollapseProperties has been run.
return n;
}
if (cond.isNot()) {
// if(!x)bar(); -> x||bar();
if (isLowerPrecedenceInExpression(cond, OR_PRECEDENCE) &&
isLowerPrecedenceInExpression(expr.getFirstChild(),
OR_PRECEDENCE)) {
// It's not okay to add two sets of parentheses.
return n;
}
Node or = IR.or(
cond.removeFirstChild(),
expr.removeFirstChild()).srcref(n);
Node newExpr = NodeUtil.newExpr(or);
parent.replaceChild(n, newExpr);
reportCodeChange();
return newExpr;
}
// if(x)foo(); -> x&&foo();
if (isLowerPrecedenceInExpression(cond, AND_PRECEDENCE) &&
isLowerPrecedenceInExpression(expr.getFirstChild(),
AND_PRECEDENCE)) {
// One additional set of parentheses is worth the change even if
// there is no immediate code size win. However, two extra pair of
// {}, we would have to think twice. (unless we know for sure the
// we can further optimize its parent.
return n;
}
n.removeChild(cond);
Node and = IR.and(cond, expr.removeFirstChild()).srcref(n);
Node newExpr = NodeUtil.newExpr(and);
parent.replaceChild(n, newExpr);
reportCodeChange();
return newExpr;
} else {
// Try to combine two IF-ELSE
if (NodeUtil.isStatementBlock(thenBranch) &&
thenBranch.hasOneChild()) {
Node innerIf = thenBranch.getFirstChild();
if (innerIf.isIf()) {
Node innerCond = innerIf.getFirstChild();
Node innerThenBranch = innerCond.getNext();
Node innerElseBranch = innerThenBranch.getNext();
if (innerElseBranch == null &&
!(isLowerPrecedenceInExpression(cond, AND_PRECEDENCE) &&
isLowerPrecedenceInExpression(innerCond, AND_PRECEDENCE))) {
n.detachChildren();
n.addChildToBack(
IR.and(
cond,
innerCond.detachFromParent())
.srcref(cond));
n.addChildrenToBack(innerThenBranch.detachFromParent());
reportCodeChange();
// Not worth trying to fold the current IF-ELSE into && because
// the inner IF-ELSE wasn't able to be folded into && anyways.
return n;
}
}
}
}
return n;
}
/* TODO(dcc) This modifies the siblings of n, which is undesirable for a
* peephole optimization. This should probably get moved to another pass.
*/
tryRemoveRepeatedStatements(n);
// if(!x)foo();else bar(); -> if(x)bar();else foo();
// An additional set of curly braces isn't worth it.
if (cond.isNot() && !consumesDanglingElse(elseBranch)) {
n.replaceChild(cond, cond.removeFirstChild());
n.removeChild(thenBranch);
n.addChildToBack(thenBranch);
reportCodeChange();
return n;
}
// if(x)return 1;else return 2; -> return x?1:2;
if (isReturnExpressBlock(thenBranch) && isReturnExpressBlock(elseBranch)) {
Node thenExpr = getBlockReturnExpression(thenBranch);
Node elseExpr = getBlockReturnExpression(elseBranch);
n.removeChild(cond);
thenExpr.detachFromParent();
elseExpr.detachFromParent();
// note - we ignore any cases with "return;", technically this
// can be converted to "return undefined;" or some variant, but
// that does not help code size.
Node returnNode = IR.returnNode(
IR.hook(cond, thenExpr, elseExpr)
.srcref(n));
parent.replaceChild(n, returnNode);
reportCodeChange();
return returnNode;
}
boolean thenBranchIsExpressionBlock = isFoldableExpressBlock(thenBranch);
boolean elseBranchIsExpressionBlock = isFoldableExpressBlock(elseBranch);
if (thenBranchIsExpressionBlock && elseBranchIsExpressionBlock) {
Node thenOp = getBlockExpression(thenBranch).getFirstChild();
Node elseOp = getBlockExpression(elseBranch).getFirstChild();
if (thenOp.getType() == elseOp.getType()) {
// if(x)a=1;else a=2; -> a=x?1:2;
if (NodeUtil.isAssignmentOp(thenOp)) {
Node lhs = thenOp.getFirstChild();
if (areNodesEqualForInlining(lhs, elseOp.getFirstChild()) &&
// if LHS has side effects, don't proceed [since the optimization
// evaluates LHS before cond]
// NOTE - there are some circumstances where we can
// proceed even if there are side effects...
!mayEffectMutableState(lhs) &&
(!mayHaveSideEffects(cond) ||
(thenOp.isAssign() && thenOp.getFirstChild().isName()))) {
n.removeChild(cond);
Node assignName = thenOp.removeFirstChild();
Node thenExpr = thenOp.removeFirstChild();
Node elseExpr = elseOp.getLastChild();
elseOp.removeChild(elseExpr);
Node hookNode = IR.hook(cond, thenExpr, elseExpr).srcref(n);
Node assign = new Node(thenOp.getType(), assignName, hookNode)
.srcref(thenOp);
Node expr = NodeUtil.newExpr(assign);
parent.replaceChild(n, expr);
reportCodeChange();
return expr;
}
}
}
// if(x)foo();else bar(); -> x?foo():bar()
n.removeChild(cond);
thenOp.detachFromParent();
elseOp.detachFromParent();
Node expr = IR.exprResult(
IR.hook(cond, thenOp, elseOp).srcref(n));
parent.replaceChild(n, expr);
reportCodeChange();
return expr;
}
boolean thenBranchIsVar = isVarBlock(thenBranch);
boolean elseBranchIsVar = isVarBlock(elseBranch);
// if(x)var y=1;else y=2 -> var y=x?1:2
if (thenBranchIsVar && elseBranchIsExpressionBlock &&
getBlockExpression(elseBranch).getFirstChild().isAssign()) {
Node var = getBlockVar(thenBranch);
Node elseAssign = getBlockExpression(elseBranch).getFirstChild();
Node name1 = var.getFirstChild();
Node maybeName2 = elseAssign.getFirstChild();
if (name1.hasChildren()
&& maybeName2.isName()
&& name1.getString().equals(maybeName2.getString())) {
Node thenExpr = name1.removeChildren();
Node elseExpr = elseAssign.getLastChild().detachFromParent();
cond.detachFromParent();
Node hookNode = IR.hook(cond, thenExpr, elseExpr)
.srcref(n);
var.detachFromParent();
name1.addChildrenToBack(hookNode);
parent.replaceChild(n, var);
reportCodeChange();
return var;
}
// if(x)y=1;else var y=2 -> var y=x?1:2
} else if (elseBranchIsVar && thenBranchIsExpressionBlock &&
getBlockExpression(thenBranch).getFirstChild().isAssign()) {
Node var = getBlockVar(elseBranch);
Node thenAssign = getBlockExpression(thenBranch).getFirstChild();
Node maybeName1 = thenAssign.getFirstChild();
Node name2 = var.getFirstChild();
if (name2.hasChildren()
&& maybeName1.isName()
&& maybeName1.getString().equals(name2.getString())) {
Node thenExpr = thenAssign.getLastChild().detachFromParent();
Node elseExpr = name2.removeChildren();
cond.detachFromParent();
Node hookNode = IR.hook(cond, thenExpr, elseExpr)
.srcref(n);
var.detachFromParent();
name2.addChildrenToBack(hookNode);
parent.replaceChild(n, var);
reportCodeChange();
return var;
}
}
return n;
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Try turning IF nodes into smaller HOOKs
*
* Returns the replacement for n or the original if no replacement was
* necessary.
*/
private Node tryMinimizeIf(Node n) {
Node parent = n.getParent();
Node cond = n.getFirstChild();
/* If the condition is a literal, we'll let other
* optimizations try to remove useless code.
*/
if (NodeUtil.isLiteralValue(cond, true)) {
return n;
}
Node thenBranch = cond.getNext();
Node elseBranch = thenBranch.getNext();
if (elseBranch == null) {
if (isFoldableExpressBlock(thenBranch)) {
Node expr = getBlockExpression(thenBranch);
if (!late && isPropertyAssignmentInExpression(expr)) {
// Keep opportunities for CollapseProperties such as
// a.longIdentifier || a.longIdentifier = ... -> var a = ...;
// until CollapseProperties has been run.
return n;
}
if (cond.isNot()) {
// if(!x)bar(); -> x||bar();
if (isLowerPrecedenceInExpression(cond, OR_PRECEDENCE) &&
isLowerPrecedenceInExpression(expr.getFirstChild(),
OR_PRECEDENCE)) {
// It's not okay to add two sets of parentheses.
return n;
}
Node or = IR.or(
cond.removeFirstChild(),
expr.removeFirstChild()).srcref(n);
Node newExpr = NodeUtil.newExpr(or);
parent.replaceChild(n, newExpr);
reportCodeChange();
return newExpr;
}
// if(x)foo(); -> x&&foo();
if (isLowerPrecedenceInExpression(cond, AND_PRECEDENCE) &&
isLowerPrecedenceInExpression(expr.getFirstChild(),
AND_PRECEDENCE)) {
// One additional set of parentheses is worth the change even if
// there is no immediate code size win. However, two extra pair of
// {}, we would have to think twice. (unless we know for sure the
// we can further optimize its parent.
return n;
}
n.removeChild(cond);
Node and = IR.and(cond, expr.removeFirstChild()).srcref(n);
Node newExpr = NodeUtil.newExpr(and);
parent.replaceChild(n, newExpr);
reportCodeChange();
return newExpr;
} else {
// Try to combine two IF-ELSE
if (NodeUtil.isStatementBlock(thenBranch) &&
thenBranch.hasOneChild()) {
Node innerIf = thenBranch.getFirstChild();
if (innerIf.isIf()) {
Node innerCond = innerIf.getFirstChild();
Node innerThenBranch = innerCond.getNext();
Node innerElseBranch = innerThenBranch.getNext();
if (innerElseBranch == null &&
!(isLowerPrecedenceInExpression(cond, AND_PRECEDENCE) &&
isLowerPrecedenceInExpression(innerCond, AND_PRECEDENCE))) {
n.detachChildren();
n.addChildToBack(
IR.and(
cond,
innerCond.detachFromParent())
.srcref(cond));
n.addChildrenToBack(innerThenBranch.detachFromParent());
reportCodeChange();
// Not worth trying to fold the current IF-ELSE into && because
// the inner IF-ELSE wasn't able to be folded into && anyways.
return n;
}
}
}
}
return n;
}
/* TODO(dcc) This modifies the siblings of n, which is undesirable for a
* peephole optimization. This should probably get moved to another pass.
*/
tryRemoveRepeatedStatements(n);
// if(!x)foo();else bar(); -> if(x)bar();else foo();
// An additional set of curly braces isn't worth it.
if (cond.isNot() && !consumesDanglingElse(elseBranch)) {
n.replaceChild(cond, cond.removeFirstChild());
n.removeChild(thenBranch);
n.addChildToBack(thenBranch);
reportCodeChange();
return n;
}
// if(x)return 1;else return 2; -> return x?1:2;
if (isReturnExpressBlock(thenBranch) && isReturnExpressBlock(elseBranch)) {
Node thenExpr = getBlockReturnExpression(thenBranch);
Node elseExpr = getBlockReturnExpression(elseBranch);
n.removeChild(cond);
thenExpr.detachFromParent();
elseExpr.detachFromParent();
// note - we ignore any cases with "return;", technically this
// can be converted to "return undefined;" or some variant, but
// that does not help code size.
Node returnNode = IR.returnNode(
IR.hook(cond, thenExpr, elseExpr)
.srcref(n));
parent.replaceChild(n, returnNode);
reportCodeChange();
return returnNode;
}
boolean thenBranchIsExpressionBlock = isFoldableExpressBlock(thenBranch);
boolean elseBranchIsExpressionBlock = isFoldableExpressBlock(elseBranch);
if (thenBranchIsExpressionBlock && elseBranchIsExpressionBlock) {
Node thenOp = getBlockExpression(thenBranch).getFirstChild();
Node elseOp = getBlockExpression(elseBranch).getFirstChild();
if (thenOp.getType() == elseOp.getType()) {
// if(x)a=1;else a=2; -> a=x?1:2;
if (NodeUtil.isAssignmentOp(thenOp)) {
Node lhs = thenOp.getFirstChild();
if (areNodesEqualForInlining(lhs, elseOp.getFirstChild()) &&
// if LHS has side effects, don't proceed [since the optimization
// evaluates LHS before cond]
// NOTE - there are some circumstances where we can
// proceed even if there are side effects...
!mayEffectMutableState(lhs) &&
(!mayHaveSideEffects(cond) ||
(thenOp.isAssign() && thenOp.getFirstChild().isName()))) {
n.removeChild(cond);
Node assignName = thenOp.removeFirstChild();
Node thenExpr = thenOp.removeFirstChild();
Node elseExpr = elseOp.getLastChild();
elseOp.removeChild(elseExpr);
Node hookNode = IR.hook(cond, thenExpr, elseExpr).srcref(n);
Node assign = new Node(thenOp.getType(), assignName, hookNode)
.srcref(thenOp);
Node expr = NodeUtil.newExpr(assign);
parent.replaceChild(n, expr);
reportCodeChange();
return expr;
}
}
}
// if(x)foo();else bar(); -> x?foo():bar()
n.removeChild(cond);
thenOp.detachFromParent();
elseOp.detachFromParent();
Node expr = IR.exprResult(
IR.hook(cond, thenOp, elseOp).srcref(n));
parent.replaceChild(n, expr);
reportCodeChange();
return expr;
}
boolean thenBranchIsVar = isVarBlock(thenBranch);
boolean elseBranchIsVar = isVarBlock(elseBranch);
// if(x)var y=1;else y=2 -> var y=x?1:2
if (thenBranchIsVar && elseBranchIsExpressionBlock &&
getBlockExpression(elseBranch).getFirstChild().isAssign()) {
Node var = getBlockVar(thenBranch);
Node elseAssign = getBlockExpression(elseBranch).getFirstChild();
Node name1 = var.getFirstChild();
Node maybeName2 = elseAssign.getFirstChild();
if (name1.hasChildren()
&& maybeName2.isName()
&& name1.getString().equals(maybeName2.getString())) {
Node thenExpr = name1.removeChildren();
Node elseExpr = elseAssign.getLastChild().detachFromParent();
cond.detachFromParent();
Node hookNode = IR.hook(cond, thenExpr, elseExpr)
.srcref(n);
var.detachFromParent();
name1.addChildrenToBack(hookNode);
parent.replaceChild(n, var);
reportCodeChange();
return var;
}
// if(x)y=1;else var y=2 -> var y=x?1:2
} else if (elseBranchIsVar && thenBranchIsExpressionBlock &&
getBlockExpression(thenBranch).getFirstChild().isAssign()) {
Node var = getBlockVar(elseBranch);
Node thenAssign = getBlockExpression(thenBranch).getFirstChild();
Node maybeName1 = thenAssign.getFirstChild();
Node name2 = var.getFirstChild();
if (name2.hasChildren()
&& maybeName1.isName()
&& maybeName1.getString().equals(name2.getString())) {
Node thenExpr = thenAssign.getLastChild().detachFromParent();
Node elseExpr = name2.removeChildren();
cond.detachFromParent();
Node hookNode = IR.hook(cond, thenExpr, elseExpr)
.srcref(n);
var.detachFromParent();
name2.addChildrenToBack(hookNode);
parent.replaceChild(n, var);
reportCodeChange();
return var;
}
}
return n;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
57 | 6ee8e5176a7f4ba4400432f42f8c5b72923ee2c353d0adbb0521f2d5d082959a | public <T> MappingIterator<T> readValues(byte[] src, int offset, int length)
throws IOException, JsonProcessingException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Overloaded version of {@link #readValue(InputStream)}.
*/
public <T> MappingIterator<T> readValues(byte[] src, int offset, int length)
throws IOException, JsonProcessingException
{
if (_dataFormatReaders != null) {
return _detectBindAndReadValues(_dataFormatReaders.findFormat(src, offset, length), false);
}
return _bindAndReadValues(_considerFilter(_parserFactory.createParser(src),
true));
}
```
| public <T> MappingIterator<T> readValues(byte[] src, int offset, int length)
throws IOException, JsonProcessingException
{
if (_dataFormatReaders != null) {
return _detectBindAndReadValues(_dataFormatReaders.findFormat(src, offset, length), false);
}
return _bindAndReadValues(_considerFilter(_parserFactory.createParser(src),
true));
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Overloaded version of {@link #readValue(InputStream)}.
*/
public <T> MappingIterator<T> readValues(byte[] src, int offset, int length)
throws IOException, JsonProcessingException
{
if (_dataFormatReaders != null) {
return _detectBindAndReadValues(_dataFormatReaders.findFormat(src, offset, length), false);
}
return _bindAndReadValues(_considerFilter(_parserFactory.createParser(src),
true));
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
6 | 6ef4cd1388b7b592abb1c48ac14948d4e5f4b9f96741184282b9c5588471b7c7 | public final void translate(CharSequence input, Writer out) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Translate an input onto a Writer. This is intentionally final as its algorithm is
* tightly coupled with the abstract method of this class.
*
* @param input CharSequence that is being translated
* @param out Writer to translate the text to
* @throws IOException if and only if the Writer produces an IOException
*/
public final void translate(CharSequence input, Writer out) throws IOException {
if (out == null) {
throw new IllegalArgumentException("The Writer must not be null");
}
if (input == null) {
return;
}
int pos = 0;
int len = input.length();
while (pos < len) {
int consumed = translate(input, pos, out);
if (consumed == 0) {
char[] c = Character.toChars(Character.codePointAt(input, pos));
out.write(c);
pos+= c.length;
continue;
}
// // contract with translators is that they have to understand codepoints
// // and they just took care of a surrogate pair
for (int pt = 0; pt < consumed; pt++) {
pos += Character.charCount(Character.codePointAt(input, pos));
}
}
}
```
| public final void translate(CharSequence input, Writer out) throws IOException {
if (out == null) {
throw new IllegalArgumentException("The Writer must not be null");
}
if (input == null) {
return;
}
int pos = 0;
int len = input.length();
while (pos < len) {
int consumed = translate(input, pos, out);
if (consumed == 0) {
char[] c = Character.toChars(Character.codePointAt(input, pos));
out.write(c);
pos+= c.length;
continue;
}
// // contract with translators is that they have to understand codepoints
// // and they just took care of a surrogate pair
for (int pt = 0; pt < consumed; pt++) {
pos += Character.charCount(Character.codePointAt(input, pos));
}
}
} | true | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Translate an input onto a Writer. This is intentionally final as its algorithm is
* tightly coupled with the abstract method of this class.
*
* @param input CharSequence that is being translated
* @param out Writer to translate the text to
* @throws IOException if and only if the Writer produces an IOException
*/
public final void translate(CharSequence input, Writer out) throws IOException {
if (out == null) {
throw new IllegalArgumentException("The Writer must not be null");
}
if (input == null) {
return;
}
int pos = 0;
int len = input.length();
while (pos < len) {
int consumed = translate(input, pos, out);
if (consumed == 0) {
char[] c = Character.toChars(Character.codePointAt(input, pos));
out.write(c);
pos+= c.length;
continue;
}
// // contract with translators is that they have to understand codepoints
// // and they just took care of a surrogate pair
for (int pt = 0; pt < consumed; pt++) {
pos += Character.charCount(Character.codePointAt(input, pos));
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
17 | 6ef4cd1388b7b592abb1c48ac14948d4e5f4b9f96741184282b9c5588471b7c7 | public final void translate(CharSequence input, Writer out) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Translate an input onto a Writer. This is intentionally final as its algorithm is
* tightly coupled with the abstract method of this class.
*
* @param input CharSequence that is being translated
* @param out Writer to translate the text to
* @throws IOException if and only if the Writer produces an IOException
*/
public final void translate(CharSequence input, Writer out) throws IOException {
if (out == null) {
throw new IllegalArgumentException("The Writer must not be null");
}
if (input == null) {
return;
}
int pos = 0;
int len = input.length();
while (pos < len) {
int consumed = translate(input, pos, out);
if (consumed == 0) {
char[] c = Character.toChars(Character.codePointAt(input, pos));
out.write(c);
pos+= c.length;
continue;
}
// // contract with translators is that they have to understand codepoints
// // and they just took care of a surrogate pair
for (int pt = 0; pt < consumed; pt++) {
pos += Character.charCount(Character.codePointAt(input, pos));
}
}
}
```
| public final void translate(CharSequence input, Writer out) throws IOException {
if (out == null) {
throw new IllegalArgumentException("The Writer must not be null");
}
if (input == null) {
return;
}
int pos = 0;
int len = input.length();
while (pos < len) {
int consumed = translate(input, pos, out);
if (consumed == 0) {
char[] c = Character.toChars(Character.codePointAt(input, pos));
out.write(c);
pos+= c.length;
continue;
}
// // contract with translators is that they have to understand codepoints
// // and they just took care of a surrogate pair
for (int pt = 0; pt < consumed; pt++) {
pos += Character.charCount(Character.codePointAt(input, pos));
}
}
} | false | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Translate an input onto a Writer. This is intentionally final as its algorithm is
* tightly coupled with the abstract method of this class.
*
* @param input CharSequence that is being translated
* @param out Writer to translate the text to
* @throws IOException if and only if the Writer produces an IOException
*/
public final void translate(CharSequence input, Writer out) throws IOException {
if (out == null) {
throw new IllegalArgumentException("The Writer must not be null");
}
if (input == null) {
return;
}
int pos = 0;
int len = input.length();
while (pos < len) {
int consumed = translate(input, pos, out);
if (consumed == 0) {
char[] c = Character.toChars(Character.codePointAt(input, pos));
out.write(c);
pos+= c.length;
continue;
}
// // contract with translators is that they have to understand codepoints
// // and they just took care of a surrogate pair
for (int pt = 0; pt < consumed; pt++) {
pos += Character.charCount(Character.codePointAt(input, pos));
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
94 | 6f357fbe6f2168d337a1563a9687d1e1221d02a5660cf5a118ded561db5a63cc | static boolean isValidDefineValue(Node val, Set<String> defines) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Determines whether the given value may be assigned to a define.
*
* @param val The value being assigned.
* @param defines The list of names of existing defines.
*/
static boolean isValidDefineValue(Node val, Set<String> defines) {
switch (val.getType()) {
case Token.STRING:
case Token.NUMBER:
case Token.TRUE:
case Token.FALSE:
return true;
// Binary operators are only valid if both children are valid.
case Token.BITAND:
case Token.BITNOT:
case Token.BITOR:
case Token.BITXOR:
// Uniary operators are valid if the child is valid.
case Token.NOT:
case Token.NEG:
return isValidDefineValue(val.getFirstChild(), defines);
// Names are valid if and only if they are defines themselves.
case Token.NAME:
case Token.GETPROP:
if (val.isQualifiedName()) {
return defines.contains(val.getQualifiedName());
}
}
return false;
}
```
| static boolean isValidDefineValue(Node val, Set<String> defines) {
switch (val.getType()) {
case Token.STRING:
case Token.NUMBER:
case Token.TRUE:
case Token.FALSE:
return true;
// Binary operators are only valid if both children are valid.
case Token.BITAND:
case Token.BITNOT:
case Token.BITOR:
case Token.BITXOR:
// Uniary operators are valid if the child is valid.
case Token.NOT:
case Token.NEG:
return isValidDefineValue(val.getFirstChild(), defines);
// Names are valid if and only if they are defines themselves.
case Token.NAME:
case Token.GETPROP:
if (val.isQualifiedName()) {
return defines.contains(val.getQualifiedName());
}
}
return false;
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Determines whether the given value may be assigned to a define.
*
* @param val The value being assigned.
* @param defines The list of names of existing defines.
*/
static boolean isValidDefineValue(Node val, Set<String> defines) {
switch (val.getType()) {
case Token.STRING:
case Token.NUMBER:
case Token.TRUE:
case Token.FALSE:
return true;
// Binary operators are only valid if both children are valid.
case Token.BITAND:
case Token.BITNOT:
case Token.BITOR:
case Token.BITXOR:
// Uniary operators are valid if the child is valid.
case Token.NOT:
case Token.NEG:
return isValidDefineValue(val.getFirstChild(), defines);
// Names are valid if and only if they are defines themselves.
case Token.NAME:
case Token.GETPROP:
if (val.isQualifiedName()) {
return defines.contains(val.getQualifiedName());
}
}
return false;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
49 | 6f422ca3471edccca6884dfc717f498e5af342d375f47316c90cf6809ff6d338 | public Object generateId(Object forPojo) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public Object generateId(Object forPojo) {
// 04-Jun-2016, tatu: As per [databind#1255], need to consider possibility of
// id being generated for "alwaysAsId", but not being written as POJO; regardless,
// need to use existing id if there is one:
if (id == null) {
id = generator.generateId(forPojo);
}
return id;
}
```
| public Object generateId(Object forPojo) {
// 04-Jun-2016, tatu: As per [databind#1255], need to consider possibility of
// id being generated for "alwaysAsId", but not being written as POJO; regardless,
// need to use existing id if there is one:
if (id == null) {
id = generator.generateId(forPojo);
}
return id;
} | false | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public Object generateId(Object forPojo) {
// 04-Jun-2016, tatu: As per [databind#1255], need to consider possibility of
// id being generated for "alwaysAsId", but not being written as POJO; regardless,
// need to use existing id if there is one:
if (id == null) {
id = generator.generateId(forPojo);
}
return id;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
152 | 6f636e042bc162224e945bac42f13a1888a80421eab118d6566a17cacebb60bc | @Override
JSType resolveInternal(ErrorReporter t, StaticScope<JSType> scope) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
JSType resolveInternal(ErrorReporter t, StaticScope<JSType> scope) {
setResolvedTypeInternal(this);
call = (ArrowType) safeResolve(call, t, scope);
prototype = (FunctionPrototypeType) safeResolve(prototype, t, scope);
// Warning about typeOfThis if it doesn't resolve to an ObjectType
// is handled further upstream.
// TODO(nicksantos): Handle this correctly if we have a UnionType.
typeOfThis = (ObjectType) safeResolve(typeOfThis, t, scope);
boolean changed = false;
ImmutableList.Builder<ObjectType> resolvedInterfaces =
ImmutableList.builder();
for (ObjectType iface : implementedInterfaces) {
ObjectType resolvedIface = (ObjectType) iface.resolve(t, scope);
resolvedInterfaces.add(resolvedIface);
changed |= (resolvedIface != iface);
}
if (changed) {
implementedInterfaces = resolvedInterfaces.build();
}
if (subTypes != null) {
for (int i = 0; i < subTypes.size(); i++) {
subTypes.set(i, (FunctionType) subTypes.get(i).resolve(t, scope));
}
}
return super.resolveInternal(t, scope);
}
```
| @Override
JSType resolveInternal(ErrorReporter t, StaticScope<JSType> scope) {
setResolvedTypeInternal(this);
call = (ArrowType) safeResolve(call, t, scope);
prototype = (FunctionPrototypeType) safeResolve(prototype, t, scope);
// Warning about typeOfThis if it doesn't resolve to an ObjectType
// is handled further upstream.
// TODO(nicksantos): Handle this correctly if we have a UnionType.
typeOfThis = (ObjectType) safeResolve(typeOfThis, t, scope);
boolean changed = false;
ImmutableList.Builder<ObjectType> resolvedInterfaces =
ImmutableList.builder();
for (ObjectType iface : implementedInterfaces) {
ObjectType resolvedIface = (ObjectType) iface.resolve(t, scope);
resolvedInterfaces.add(resolvedIface);
changed |= (resolvedIface != iface);
}
if (changed) {
implementedInterfaces = resolvedInterfaces.build();
}
if (subTypes != null) {
for (int i = 0; i < subTypes.size(); i++) {
subTypes.set(i, (FunctionType) subTypes.get(i).resolve(t, scope));
}
}
return super.resolveInternal(t, scope);
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
JSType resolveInternal(ErrorReporter t, StaticScope<JSType> scope) {
setResolvedTypeInternal(this);
call = (ArrowType) safeResolve(call, t, scope);
prototype = (FunctionPrototypeType) safeResolve(prototype, t, scope);
// Warning about typeOfThis if it doesn't resolve to an ObjectType
// is handled further upstream.
// TODO(nicksantos): Handle this correctly if we have a UnionType.
typeOfThis = (ObjectType) safeResolve(typeOfThis, t, scope);
boolean changed = false;
ImmutableList.Builder<ObjectType> resolvedInterfaces =
ImmutableList.builder();
for (ObjectType iface : implementedInterfaces) {
ObjectType resolvedIface = (ObjectType) iface.resolve(t, scope);
resolvedInterfaces.add(resolvedIface);
changed |= (resolvedIface != iface);
}
if (changed) {
implementedInterfaces = resolvedInterfaces.build();
}
if (subTypes != null) {
for (int i = 0; i < subTypes.size(); i++) {
subTypes.set(i, (FunctionType) subTypes.get(i).resolve(t, scope));
}
}
return super.resolveInternal(t, scope);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
46 | 6f63d7773ef58f469f3500eff8b1d39282d69d07eeb1392ce12781187abc0235 | private static ZipLong unixTimeToZipLong(long l) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private static ZipLong unixTimeToZipLong(long l) {
if (l < Integer.MIN_VALUE || l > Integer.MAX_VALUE) {
throw new IllegalArgumentException("X5455 timestamps must fit in a signed 32 bit integer: " + l);
}
return new ZipLong(l);
}
```
| private static ZipLong unixTimeToZipLong(long l) {
if (l < Integer.MIN_VALUE || l > Integer.MAX_VALUE) {
throw new IllegalArgumentException("X5455 timestamps must fit in a signed 32 bit integer: " + l);
}
return new ZipLong(l);
} | false | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private static ZipLong unixTimeToZipLong(long l) {
if (l < Integer.MIN_VALUE || l > Integer.MAX_VALUE) {
throw new IllegalArgumentException("X5455 timestamps must fit in a signed 32 bit integer: " + l);
}
return new ZipLong(l);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
91 | 6fb97b94504135466070e4095a989c1f81cfe25e03160517412456e6ee600942 | public boolean shouldTraverse(NodeTraversal t, Node n, Node parent) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Since this pass reports errors only when a global {@code this} keyword
* is encountered, there is no reason to traverse non global contexts.
*/
public boolean shouldTraverse(NodeTraversal t, Node n, Node parent) {
if (n.getType() == Token.FUNCTION) {
// Don't traverse functions that are constructors or have the @this
// or @override annotation.
JSDocInfo jsDoc = getFunctionJsDocInfo(n);
if (jsDoc != null &&
(jsDoc.isConstructor() ||
jsDoc.isInterface() ||
jsDoc.hasThisType() ||
jsDoc.isOverride())) {
return false;
}
// Don't traverse functions unless they would normally
// be able to have a @this annotation associated with them. e.g.,
// var a = function() { }; // or
// function a() {} // or
// a.x = function() {}; // or
// var a = {x: function() {}};
int pType = parent.getType();
if (!(pType == Token.BLOCK ||
pType == Token.SCRIPT ||
pType == Token.NAME ||
pType == Token.ASSIGN ||
// object literal keys
pType == Token.STRING ||
pType == Token.NUMBER)) {
return false;
}
// Don't traverse functions that are getting lent to a prototype.
Node gramps = parent.getParent();
if (NodeUtil.isObjectLitKey(parent, gramps)) {
JSDocInfo maybeLends = gramps.getJSDocInfo();
if (maybeLends != null &&
maybeLends.getLendsName() != null &&
maybeLends.getLendsName().endsWith(".prototype")) {
return false;
}
}
}
if (parent != null && parent.getType() == Token.ASSIGN) {
Node lhs = parent.getFirstChild();
Node rhs = lhs.getNext();
if (n == lhs) {
// Always traverse the left side of the assignment. To handle
// nested assignments properly (e.g., (a = this).property = c;),
// assignLhsChild should not be overridden.
if (assignLhsChild == null) {
assignLhsChild = lhs;
}
} else {
// Only traverse the right side if it's not an assignment to a prototype
// property or subproperty.
if (NodeUtil.isGet(lhs)) {
if (lhs.getType() == Token.GETPROP &&
lhs.getLastChild().getString().equals("prototype")) {
return false;
}
Node llhs = lhs.getFirstChild();
if (llhs.getType() == Token.GETPROP &&
llhs.getLastChild().getString().equals("prototype")) {
return false;
}
}
}
}
return true;
}
```
| public boolean shouldTraverse(NodeTraversal t, Node n, Node parent) {
if (n.getType() == Token.FUNCTION) {
// Don't traverse functions that are constructors or have the @this
// or @override annotation.
JSDocInfo jsDoc = getFunctionJsDocInfo(n);
if (jsDoc != null &&
(jsDoc.isConstructor() ||
jsDoc.isInterface() ||
jsDoc.hasThisType() ||
jsDoc.isOverride())) {
return false;
}
// Don't traverse functions unless they would normally
// be able to have a @this annotation associated with them. e.g.,
// var a = function() { }; // or
// function a() {} // or
// a.x = function() {}; // or
// var a = {x: function() {}};
int pType = parent.getType();
if (!(pType == Token.BLOCK ||
pType == Token.SCRIPT ||
pType == Token.NAME ||
pType == Token.ASSIGN ||
// object literal keys
pType == Token.STRING ||
pType == Token.NUMBER)) {
return false;
}
// Don't traverse functions that are getting lent to a prototype.
Node gramps = parent.getParent();
if (NodeUtil.isObjectLitKey(parent, gramps)) {
JSDocInfo maybeLends = gramps.getJSDocInfo();
if (maybeLends != null &&
maybeLends.getLendsName() != null &&
maybeLends.getLendsName().endsWith(".prototype")) {
return false;
}
}
}
if (parent != null && parent.getType() == Token.ASSIGN) {
Node lhs = parent.getFirstChild();
Node rhs = lhs.getNext();
if (n == lhs) {
// Always traverse the left side of the assignment. To handle
// nested assignments properly (e.g., (a = this).property = c;),
// assignLhsChild should not be overridden.
if (assignLhsChild == null) {
assignLhsChild = lhs;
}
} else {
// Only traverse the right side if it's not an assignment to a prototype
// property or subproperty.
if (NodeUtil.isGet(lhs)) {
if (lhs.getType() == Token.GETPROP &&
lhs.getLastChild().getString().equals("prototype")) {
return false;
}
Node llhs = lhs.getFirstChild();
if (llhs.getType() == Token.GETPROP &&
llhs.getLastChild().getString().equals("prototype")) {
return false;
}
}
}
}
return true;
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Since this pass reports errors only when a global {@code this} keyword
* is encountered, there is no reason to traverse non global contexts.
*/
public boolean shouldTraverse(NodeTraversal t, Node n, Node parent) {
if (n.getType() == Token.FUNCTION) {
// Don't traverse functions that are constructors or have the @this
// or @override annotation.
JSDocInfo jsDoc = getFunctionJsDocInfo(n);
if (jsDoc != null &&
(jsDoc.isConstructor() ||
jsDoc.isInterface() ||
jsDoc.hasThisType() ||
jsDoc.isOverride())) {
return false;
}
// Don't traverse functions unless they would normally
// be able to have a @this annotation associated with them. e.g.,
// var a = function() { }; // or
// function a() {} // or
// a.x = function() {}; // or
// var a = {x: function() {}};
int pType = parent.getType();
if (!(pType == Token.BLOCK ||
pType == Token.SCRIPT ||
pType == Token.NAME ||
pType == Token.ASSIGN ||
// object literal keys
pType == Token.STRING ||
pType == Token.NUMBER)) {
return false;
}
// Don't traverse functions that are getting lent to a prototype.
Node gramps = parent.getParent();
if (NodeUtil.isObjectLitKey(parent, gramps)) {
JSDocInfo maybeLends = gramps.getJSDocInfo();
if (maybeLends != null &&
maybeLends.getLendsName() != null &&
maybeLends.getLendsName().endsWith(".prototype")) {
return false;
}
}
}
if (parent != null && parent.getType() == Token.ASSIGN) {
Node lhs = parent.getFirstChild();
Node rhs = lhs.getNext();
if (n == lhs) {
// Always traverse the left side of the assignment. To handle
// nested assignments properly (e.g., (a = this).property = c;),
// assignLhsChild should not be overridden.
if (assignLhsChild == null) {
assignLhsChild = lhs;
}
} else {
// Only traverse the right side if it's not an assignment to a prototype
// property or subproperty.
if (NodeUtil.isGet(lhs)) {
if (lhs.getType() == Token.GETPROP &&
lhs.getLastChild().getString().equals("prototype")) {
return false;
}
Node llhs = lhs.getFirstChild();
if (llhs.getType() == Token.GETPROP &&
llhs.getLastChild().getString().equals("prototype")) {
return false;
}
}
}
}
return true;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
37 | 708f2cc60be9e96d5179da234f438f86863905e1fd717a8ab502a95b9f57852d | public String html() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Retrieves the element's inner HTML. E.g. on a {@code <div>} with one empty {@code <p>}, would return
* {@code <p></p>}. (Whereas {@link #outerHtml()} would return {@code <div><p></p></div>}.)
*
* @return String of HTML.
* @see #outerHtml()
*/
public String html() {
StringBuilder accum = new StringBuilder();
html(accum);
return accum.toString().trim();
}
```
| public String html() {
StringBuilder accum = new StringBuilder();
html(accum);
return accum.toString().trim();
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Retrieves the element's inner HTML. E.g. on a {@code <div>} with one empty {@code <p>}, would return
* {@code <p></p>}. (Whereas {@link #outerHtml()} would return {@code <div><p></p></div>}.)
*
* @return String of HTML.
* @see #outerHtml()
*/
public String html() {
StringBuilder accum = new StringBuilder();
html(accum);
return accum.toString().trim();
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
62 | 7090d9e84bf1f08a3df09abc9f64e04b303db5ba45a4157b76a2494f020191bc | private String format(JSError error, boolean warning) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private String format(JSError error, boolean warning) {
// extract source excerpt
SourceExcerptProvider source = getSource();
String sourceExcerpt = source == null ? null :
excerpt.get(
source, error.sourceName, error.lineNumber, excerptFormatter);
// formatting the message
StringBuilder b = new StringBuilder();
if (error.sourceName != null) {
b.append(error.sourceName);
if (error.lineNumber > 0) {
b.append(':');
b.append(error.lineNumber);
}
b.append(": ");
}
b.append(getLevelName(warning ? CheckLevel.WARNING : CheckLevel.ERROR));
b.append(" - ");
b.append(error.description);
b.append('\n');
if (sourceExcerpt != null) {
b.append(sourceExcerpt);
b.append('\n');
int charno = error.getCharno();
// padding equal to the excerpt and arrow at the end
// charno == sourceExpert.length() means something is missing
// at the end of the line
if (excerpt.equals(LINE)
&& 0 <= charno && charno < sourceExcerpt.length()) {
for (int i = 0; i < charno; i++) {
char c = sourceExcerpt.charAt(i);
if (Character.isWhitespace(c)) {
b.append(c);
} else {
b.append(' ');
}
}
b.append("^\n");
}
}
return b.toString();
}
```
| private String format(JSError error, boolean warning) {
// extract source excerpt
SourceExcerptProvider source = getSource();
String sourceExcerpt = source == null ? null :
excerpt.get(
source, error.sourceName, error.lineNumber, excerptFormatter);
// formatting the message
StringBuilder b = new StringBuilder();
if (error.sourceName != null) {
b.append(error.sourceName);
if (error.lineNumber > 0) {
b.append(':');
b.append(error.lineNumber);
}
b.append(": ");
}
b.append(getLevelName(warning ? CheckLevel.WARNING : CheckLevel.ERROR));
b.append(" - ");
b.append(error.description);
b.append('\n');
if (sourceExcerpt != null) {
b.append(sourceExcerpt);
b.append('\n');
int charno = error.getCharno();
// padding equal to the excerpt and arrow at the end
// charno == sourceExpert.length() means something is missing
// at the end of the line
if (excerpt.equals(LINE)
&& 0 <= charno && charno < sourceExcerpt.length()) {
for (int i = 0; i < charno; i++) {
char c = sourceExcerpt.charAt(i);
if (Character.isWhitespace(c)) {
b.append(c);
} else {
b.append(' ');
}
}
b.append("^\n");
}
}
return b.toString();
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private String format(JSError error, boolean warning) {
// extract source excerpt
SourceExcerptProvider source = getSource();
String sourceExcerpt = source == null ? null :
excerpt.get(
source, error.sourceName, error.lineNumber, excerptFormatter);
// formatting the message
StringBuilder b = new StringBuilder();
if (error.sourceName != null) {
b.append(error.sourceName);
if (error.lineNumber > 0) {
b.append(':');
b.append(error.lineNumber);
}
b.append(": ");
}
b.append(getLevelName(warning ? CheckLevel.WARNING : CheckLevel.ERROR));
b.append(" - ");
b.append(error.description);
b.append('\n');
if (sourceExcerpt != null) {
b.append(sourceExcerpt);
b.append('\n');
int charno = error.getCharno();
// padding equal to the excerpt and arrow at the end
// charno == sourceExpert.length() means something is missing
// at the end of the line
if (excerpt.equals(LINE)
&& 0 <= charno && charno < sourceExcerpt.length()) {
for (int i = 0; i < charno; i++) {
char c = sourceExcerpt.charAt(i);
if (Character.isWhitespace(c)) {
b.append(c);
} else {
b.append(' ');
}
}
b.append("^\n");
}
}
return b.toString();
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
10 | 70d1c1e0cd19ce484b92dee1b43a9efab2e5bee2fc34326486598fa5cee3dee1 | public CSVPrinter(final Appendable out, final CSVFormat format) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Creates a printer that will print values to the given stream following the CSVFormat.
* <p>
* Currently, only a pure encapsulation format or a pure escaping format is supported. Hybrid formats (encapsulation
* and escaping with a different character) are not supported.
* </p>
*
* @param out
* stream to which to print. Must not be null.
* @param format
* the CSV format. Must not be null.
* @throws IOException
* thrown if the optional header cannot be printed.
* @throws IllegalArgumentException
* thrown if the parameters of the format are inconsistent or if either out or format are null.
*/
public CSVPrinter(final Appendable out, final CSVFormat format) throws IOException {
Assertions.notNull(out, "out");
Assertions.notNull(format, "format");
this.out = out;
this.format = format;
this.format.validate();
// TODO: Is it a good idea to do this here instead of on the first call to a print method?
// It seems a pain to have to track whether the header has already been printed or not.
if (format.getHeader() != null) {
this.printRecord((Object[]) format.getHeader());
}
}
```
| public CSVPrinter(final Appendable out, final CSVFormat format) throws IOException {
Assertions.notNull(out, "out");
Assertions.notNull(format, "format");
this.out = out;
this.format = format;
this.format.validate();
// TODO: Is it a good idea to do this here instead of on the first call to a print method?
// It seems a pain to have to track whether the header has already been printed or not.
if (format.getHeader() != null) {
this.printRecord((Object[]) format.getHeader());
}
} | false | Csv | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Creates a printer that will print values to the given stream following the CSVFormat.
* <p>
* Currently, only a pure encapsulation format or a pure escaping format is supported. Hybrid formats (encapsulation
* and escaping with a different character) are not supported.
* </p>
*
* @param out
* stream to which to print. Must not be null.
* @param format
* the CSV format. Must not be null.
* @throws IOException
* thrown if the optional header cannot be printed.
* @throws IllegalArgumentException
* thrown if the parameters of the format are inconsistent or if either out or format are null.
*/
public CSVPrinter(final Appendable out, final CSVFormat format) throws IOException {
Assertions.notNull(out, "out");
Assertions.notNull(format, "format");
this.out = out;
this.format = format;
this.format.validate();
// TODO: Is it a good idea to do this here instead of on the first call to a print method?
// It seems a pain to have to track whether the header has already been printed or not.
if (format.getHeader() != null) {
this.printRecord((Object[]) format.getHeader());
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
6 | 71644af752960bb260b357a3aa9136fb9c3ff5d677ad50d9f1d4a9c6426f4df8 | protected Date parseAsISO8601(String dateStr, ParsePosition pos)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
protected Date parseAsISO8601(String dateStr, ParsePosition pos)
{
/* 21-May-2009, tatu: DateFormat has very strict handling of
* timezone modifiers for ISO-8601. So we need to do some scrubbing.
*/
/* First: do we have "zulu" format ('Z' == "GMT")? If yes, that's
* quite simple because we already set date format timezone to be
* GMT, and hence can just strip out 'Z' altogether
*/
int len = dateStr.length();
char c = dateStr.charAt(len-1);
DateFormat df;
// [JACKSON-200]: need to support "plain" date...
if (len <= 10 && Character.isDigit(c)) {
df = _formatPlain;
if (df == null) {
df = _formatPlain = _cloneFormat(DATE_FORMAT_PLAIN, DATE_FORMAT_STR_PLAIN, _timezone, _locale);
}
} else if (c == 'Z') {
df = _formatISO8601_z;
if (df == null) {
df = _formatISO8601_z = _cloneFormat(DATE_FORMAT_ISO8601_Z, DATE_FORMAT_STR_ISO8601_Z, _timezone, _locale);
}
// [JACKSON-334]: may be missing milliseconds... if so, add
if (dateStr.charAt(len-4) == ':') {
StringBuilder sb = new StringBuilder(dateStr);
sb.insert(len-1, ".000");
dateStr = sb.toString();
}
} else {
// Let's see if we have timezone indicator or not...
if (hasTimeZone(dateStr)) {
c = dateStr.charAt(len-3);
if (c == ':') { // remove optional colon
// remove colon
StringBuilder sb = new StringBuilder(dateStr);
sb.delete(len-3, len-2);
dateStr = sb.toString();
} else if (c == '+' || c == '-') { // missing minutes
// let's just append '00'
dateStr += "00";
}
// Milliseconds partial or missing; and even seconds are optional
len = dateStr.length();
// remove 'T', '+'/'-' and 4-digit timezone-offset
c = dateStr.charAt(len-9);
if (Character.isDigit(c)) {
StringBuilder sb = new StringBuilder(dateStr);
sb.insert(len-5, ".000");
dateStr = sb.toString();
}
df = _formatISO8601;
if (_formatISO8601 == null) {
df = _formatISO8601 = _cloneFormat(DATE_FORMAT_ISO8601, DATE_FORMAT_STR_ISO8601, _timezone, _locale);
}
} else {
// If not, plain date. Easiest to just patch 'Z' in the end?
StringBuilder sb = new StringBuilder(dateStr);
// And possible also millisecond part if missing
int timeLen = len - dateStr.lastIndexOf('T') - 1;
if (timeLen <= 8) {
sb.append(".000");
}
sb.append('Z');
dateStr = sb.toString();
df = _formatISO8601_z;
if (df == null) {
df = _formatISO8601_z = _cloneFormat(DATE_FORMAT_ISO8601_Z, DATE_FORMAT_STR_ISO8601_Z,
_timezone, _locale);
}
}
}
return df.parse(dateStr, pos);
}
```
| protected Date parseAsISO8601(String dateStr, ParsePosition pos)
{
/* 21-May-2009, tatu: DateFormat has very strict handling of
* timezone modifiers for ISO-8601. So we need to do some scrubbing.
*/
/* First: do we have "zulu" format ('Z' == "GMT")? If yes, that's
* quite simple because we already set date format timezone to be
* GMT, and hence can just strip out 'Z' altogether
*/
int len = dateStr.length();
char c = dateStr.charAt(len-1);
DateFormat df;
// [JACKSON-200]: need to support "plain" date...
if (len <= 10 && Character.isDigit(c)) {
df = _formatPlain;
if (df == null) {
df = _formatPlain = _cloneFormat(DATE_FORMAT_PLAIN, DATE_FORMAT_STR_PLAIN, _timezone, _locale);
}
} else if (c == 'Z') {
df = _formatISO8601_z;
if (df == null) {
df = _formatISO8601_z = _cloneFormat(DATE_FORMAT_ISO8601_Z, DATE_FORMAT_STR_ISO8601_Z, _timezone, _locale);
}
// [JACKSON-334]: may be missing milliseconds... if so, add
if (dateStr.charAt(len-4) == ':') {
StringBuilder sb = new StringBuilder(dateStr);
sb.insert(len-1, ".000");
dateStr = sb.toString();
}
} else {
// Let's see if we have timezone indicator or not...
if (hasTimeZone(dateStr)) {
c = dateStr.charAt(len-3);
if (c == ':') { // remove optional colon
// remove colon
StringBuilder sb = new StringBuilder(dateStr);
sb.delete(len-3, len-2);
dateStr = sb.toString();
} else if (c == '+' || c == '-') { // missing minutes
// let's just append '00'
dateStr += "00";
}
// Milliseconds partial or missing; and even seconds are optional
len = dateStr.length();
// remove 'T', '+'/'-' and 4-digit timezone-offset
c = dateStr.charAt(len-9);
if (Character.isDigit(c)) {
StringBuilder sb = new StringBuilder(dateStr);
sb.insert(len-5, ".000");
dateStr = sb.toString();
}
df = _formatISO8601;
if (_formatISO8601 == null) {
df = _formatISO8601 = _cloneFormat(DATE_FORMAT_ISO8601, DATE_FORMAT_STR_ISO8601, _timezone, _locale);
}
} else {
// If not, plain date. Easiest to just patch 'Z' in the end?
StringBuilder sb = new StringBuilder(dateStr);
// And possible also millisecond part if missing
int timeLen = len - dateStr.lastIndexOf('T') - 1;
if (timeLen <= 8) {
sb.append(".000");
}
sb.append('Z');
dateStr = sb.toString();
df = _formatISO8601_z;
if (df == null) {
df = _formatISO8601_z = _cloneFormat(DATE_FORMAT_ISO8601_Z, DATE_FORMAT_STR_ISO8601_Z,
_timezone, _locale);
}
}
}
return df.parse(dateStr, pos);
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
protected Date parseAsISO8601(String dateStr, ParsePosition pos)
{
/* 21-May-2009, tatu: DateFormat has very strict handling of
* timezone modifiers for ISO-8601. So we need to do some scrubbing.
*/
/* First: do we have "zulu" format ('Z' == "GMT")? If yes, that's
* quite simple because we already set date format timezone to be
* GMT, and hence can just strip out 'Z' altogether
*/
int len = dateStr.length();
char c = dateStr.charAt(len-1);
DateFormat df;
// [JACKSON-200]: need to support "plain" date...
if (len <= 10 && Character.isDigit(c)) {
df = _formatPlain;
if (df == null) {
df = _formatPlain = _cloneFormat(DATE_FORMAT_PLAIN, DATE_FORMAT_STR_PLAIN, _timezone, _locale);
}
} else if (c == 'Z') {
df = _formatISO8601_z;
if (df == null) {
df = _formatISO8601_z = _cloneFormat(DATE_FORMAT_ISO8601_Z, DATE_FORMAT_STR_ISO8601_Z, _timezone, _locale);
}
// [JACKSON-334]: may be missing milliseconds... if so, add
if (dateStr.charAt(len-4) == ':') {
StringBuilder sb = new StringBuilder(dateStr);
sb.insert(len-1, ".000");
dateStr = sb.toString();
}
} else {
// Let's see if we have timezone indicator or not...
if (hasTimeZone(dateStr)) {
c = dateStr.charAt(len-3);
if (c == ':') { // remove optional colon
// remove colon
StringBuilder sb = new StringBuilder(dateStr);
sb.delete(len-3, len-2);
dateStr = sb.toString();
} else if (c == '+' || c == '-') { // missing minutes
// let's just append '00'
dateStr += "00";
}
// Milliseconds partial or missing; and even seconds are optional
len = dateStr.length();
// remove 'T', '+'/'-' and 4-digit timezone-offset
c = dateStr.charAt(len-9);
if (Character.isDigit(c)) {
StringBuilder sb = new StringBuilder(dateStr);
sb.insert(len-5, ".000");
dateStr = sb.toString();
}
df = _formatISO8601;
if (_formatISO8601 == null) {
df = _formatISO8601 = _cloneFormat(DATE_FORMAT_ISO8601, DATE_FORMAT_STR_ISO8601, _timezone, _locale);
}
} else {
// If not, plain date. Easiest to just patch 'Z' in the end?
StringBuilder sb = new StringBuilder(dateStr);
// And possible also millisecond part if missing
int timeLen = len - dateStr.lastIndexOf('T') - 1;
if (timeLen <= 8) {
sb.append(".000");
}
sb.append('Z');
dateStr = sb.toString();
df = _formatISO8601_z;
if (df == null) {
df = _formatISO8601_z = _cloneFormat(DATE_FORMAT_ISO8601_Z, DATE_FORMAT_STR_ISO8601_Z,
_timezone, _locale);
}
}
}
return df.parse(dateStr, pos);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |