bug_id
stringlengths 1
3
| task_id
stringlengths 64
64
| function_signature
stringlengths 15
364
| prompt_chat
stringlengths 471
20.2k
| code
stringlengths 44
19.8k
| defective
bool 2
classes | project
stringclasses 17
values | prompt_complete
stringlengths 3.07k
22.8k
|
|---|---|---|---|---|---|---|---|
6 | 8e3f89612c9ae4adbe70d9167b602427eb7b8a4a1374c82d41f1263dd0b0806e | private final static int _parseIndex(String str) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/*
/**********************************************************
/* Internal methods
/**********************************************************
*/
private final static int _parseIndex(String str) {
final int len = str.length();
// [core#133]: beware of super long indexes; assume we never
// have arrays over 2 billion entries so ints are fine.
if (len == 0 || len > 10) {
return -1;
}
// [core#176]: no leading zeroes allowed
char c = str.charAt(0);
if (c <= '0') {
return (len == 1 && c == '0') ? 0 : -1;
}
if (c > '9') {
return -1;
}
for (int i = 1; i < len; ++i) {
c = str.charAt(i);
if (c > '9' || c < '0') {
return -1;
}
}
if (len == 10) {
long l = NumberInput.parseLong(str);
if (l > Integer.MAX_VALUE) {
return -1;
}
}
return NumberInput.parseInt(str);
}
```
| private final static int _parseIndex(String str) {
final int len = str.length();
// [core#133]: beware of super long indexes; assume we never
// have arrays over 2 billion entries so ints are fine.
if (len == 0 || len > 10) {
return -1;
}
// [core#176]: no leading zeroes allowed
char c = str.charAt(0);
if (c <= '0') {
return (len == 1 && c == '0') ? 0 : -1;
}
if (c > '9') {
return -1;
}
for (int i = 1; i < len; ++i) {
c = str.charAt(i);
if (c > '9' || c < '0') {
return -1;
}
}
if (len == 10) {
long l = NumberInput.parseLong(str);
if (l > Integer.MAX_VALUE) {
return -1;
}
}
return NumberInput.parseInt(str);
} | false | JacksonCore | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/*
/**********************************************************
/* Internal methods
/**********************************************************
*/
private final static int _parseIndex(String str) {
final int len = str.length();
// [core#133]: beware of super long indexes; assume we never
// have arrays over 2 billion entries so ints are fine.
if (len == 0 || len > 10) {
return -1;
}
// [core#176]: no leading zeroes allowed
char c = str.charAt(0);
if (c <= '0') {
return (len == 1 && c == '0') ? 0 : -1;
}
if (c > '9') {
return -1;
}
for (int i = 1; i < len; ++i) {
c = str.charAt(i);
if (c > '9' || c < '0') {
return -1;
}
}
if (len == 10) {
long l = NumberInput.parseLong(str);
if (l > Integer.MAX_VALUE) {
return -1;
}
}
return NumberInput.parseInt(str);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
23 | 8e5eff2a96bb525576567b8e7ea9f4574eebc54fac09b38b2304a286cad1940e | @Override
InputStream decode(final InputStream in, final Coder coder,
byte[] password) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
InputStream decode(final InputStream in, final Coder coder,
byte[] password) throws IOException {
byte propsByte = coder.properties[0];
long dictSize = coder.properties[1];
for (int i = 1; i < 4; i++) {
dictSize |= (coder.properties[i + 1] << (8 * i));
}
if (dictSize > LZMAInputStream.DICT_SIZE_MAX) {
throw new IOException("Dictionary larger than 4GiB maximum size");
}
return new LZMAInputStream(in, -1, propsByte, (int) dictSize);
}
```
| @Override
InputStream decode(final InputStream in, final Coder coder,
byte[] password) throws IOException {
byte propsByte = coder.properties[0];
long dictSize = coder.properties[1];
for (int i = 1; i < 4; i++) {
dictSize |= (coder.properties[i + 1] << (8 * i));
}
if (dictSize > LZMAInputStream.DICT_SIZE_MAX) {
throw new IOException("Dictionary larger than 4GiB maximum size");
}
return new LZMAInputStream(in, -1, propsByte, (int) dictSize);
} | true | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
InputStream decode(final InputStream in, final Coder coder,
byte[] password) throws IOException {
byte propsByte = coder.properties[0];
long dictSize = coder.properties[1];
for (int i = 1; i < 4; i++) {
dictSize |= (coder.properties[i + 1] << (8 * i));
}
if (dictSize > LZMAInputStream.DICT_SIZE_MAX) {
throw new IOException("Dictionary larger than 4GiB maximum size");
}
return new LZMAInputStream(in, -1, propsByte, (int) dictSize);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
11 | 8e67509f4a536177874861af4accb413a8777db6fca87046a8bea90b55a95b43 | private Map<String, Integer> initializeHeader() throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Initializes the name to index mapping if the format defines a header.
*
* @return null if the format has no header.
* @throws IOException if there is a problem reading the header or skipping the first record
*/
private Map<String, Integer> initializeHeader() throws IOException {
Map<String, Integer> hdrMap = null;
final String[] formatHeader = this.format.getHeader();
if (formatHeader != null) {
hdrMap = new LinkedHashMap<String, Integer>();
String[] headerRecord = null;
if (formatHeader.length == 0) {
// read the header from the first line of the file
final CSVRecord nextRecord = this.nextRecord();
if (nextRecord != null) {
headerRecord = nextRecord.values();
}
} else {
if (this.format.getSkipHeaderRecord()) {
this.nextRecord();
}
headerRecord = formatHeader;
}
// build the name to index mappings
if (headerRecord != null) {
for (int i = 0; i < headerRecord.length; i++) {
final String header = headerRecord[i];
final boolean containsHeader = hdrMap.containsKey(header);
final boolean emptyHeader = header.trim().isEmpty();
if (containsHeader && (!emptyHeader || (emptyHeader && !this.format.getIgnoreEmptyHeaders()))) {
throw new IllegalArgumentException("The header contains a duplicate name: \"" + header +
"\" in " + Arrays.toString(headerRecord));
}
hdrMap.put(header, Integer.valueOf(i));
}
}
}
return hdrMap;
}
```
| private Map<String, Integer> initializeHeader() throws IOException {
Map<String, Integer> hdrMap = null;
final String[] formatHeader = this.format.getHeader();
if (formatHeader != null) {
hdrMap = new LinkedHashMap<String, Integer>();
String[] headerRecord = null;
if (formatHeader.length == 0) {
// read the header from the first line of the file
final CSVRecord nextRecord = this.nextRecord();
if (nextRecord != null) {
headerRecord = nextRecord.values();
}
} else {
if (this.format.getSkipHeaderRecord()) {
this.nextRecord();
}
headerRecord = formatHeader;
}
// build the name to index mappings
if (headerRecord != null) {
for (int i = 0; i < headerRecord.length; i++) {
final String header = headerRecord[i];
final boolean containsHeader = hdrMap.containsKey(header);
final boolean emptyHeader = header.trim().isEmpty();
if (containsHeader && (!emptyHeader || (emptyHeader && !this.format.getIgnoreEmptyHeaders()))) {
throw new IllegalArgumentException("The header contains a duplicate name: \"" + header +
"\" in " + Arrays.toString(headerRecord));
}
hdrMap.put(header, Integer.valueOf(i));
}
}
}
return hdrMap;
} | true | Csv | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Initializes the name to index mapping if the format defines a header.
*
* @return null if the format has no header.
* @throws IOException if there is a problem reading the header or skipping the first record
*/
private Map<String, Integer> initializeHeader() throws IOException {
Map<String, Integer> hdrMap = null;
final String[] formatHeader = this.format.getHeader();
if (formatHeader != null) {
hdrMap = new LinkedHashMap<String, Integer>();
String[] headerRecord = null;
if (formatHeader.length == 0) {
// read the header from the first line of the file
final CSVRecord nextRecord = this.nextRecord();
if (nextRecord != null) {
headerRecord = nextRecord.values();
}
} else {
if (this.format.getSkipHeaderRecord()) {
this.nextRecord();
}
headerRecord = formatHeader;
}
// build the name to index mappings
if (headerRecord != null) {
for (int i = 0; i < headerRecord.length; i++) {
final String header = headerRecord[i];
final boolean containsHeader = hdrMap.containsKey(header);
final boolean emptyHeader = header.trim().isEmpty();
if (containsHeader && (!emptyHeader || (emptyHeader && !this.format.getIgnoreEmptyHeaders()))) {
throw new IllegalArgumentException("The header contains a duplicate name: \"" + header +
"\" in " + Arrays.toString(headerRecord));
}
hdrMap.put(header, Integer.valueOf(i));
}
}
}
return hdrMap;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
19 | 8ebca4d006154c4dead1591756371cd94fcc734cf12e49c9d386c7d25588ff07 | public int getOffsetFromLocal(long instantLocal) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Gets the millisecond offset to subtract from local time to get UTC time.
* This offset can be used to undo adding the offset obtained by getOffset.
*
* <pre>
* millisLocal == millisUTC + getOffset(millisUTC)
* millisUTC == millisLocal - getOffsetFromLocal(millisLocal)
* </pre>
*
* NOTE: After calculating millisLocal, some error may be introduced. At
* offset transitions (due to DST or other historical changes), ranges of
* local times may map to different UTC times.
* <p>
* This method will return an offset suitable for calculating an instant
* after any DST gap. For example, consider a zone with a cutover
* from 01:00 to 01:59:<br />
* Input: 00:00 Output: 00:00<br />
* Input: 00:30 Output: 00:30<br />
* Input: 01:00 Output: 02:00<br />
* Input: 01:30 Output: 02:30<br />
* Input: 02:00 Output: 02:00<br />
* Input: 02:30 Output: 02:30<br />
* <p>
* During a DST overlap (where the local time is ambiguous) this method will return
* the earlier instant. The combination of these two rules is to always favour
* daylight (summer) time over standard (winter) time.
* <p>
* NOTE: Prior to v2.0, the DST overlap behaviour was not defined and varied by hemisphere.
* Prior to v1.5, the DST gap behaviour was also not defined.
*
* @param instantLocal the millisecond instant, relative to this time zone, to get the offset for
* @return the millisecond offset to subtract from local time to get UTC time
*/
public int getOffsetFromLocal(long instantLocal) {
// get the offset at instantLocal (first estimate)
final int offsetLocal = getOffset(instantLocal);
// adjust instantLocal using the estimate and recalc the offset
final long instantAdjusted = instantLocal - offsetLocal;
final int offsetAdjusted = getOffset(instantAdjusted);
// if the offsets differ, we must be near a DST boundary
if (offsetLocal != offsetAdjusted) {
// we need to ensure that time is always after the DST gap
// this happens naturally for positive offsets, but not for negative
if ((offsetLocal - offsetAdjusted) < 0) {
// if we just return offsetAdjusted then the time is pushed
// back before the transition, whereas it should be
// on or after the transition
long nextLocal = nextTransition(instantAdjusted);
long nextAdjusted = nextTransition(instantLocal - offsetAdjusted);
if (nextLocal != nextAdjusted) {
return offsetLocal;
}
}
} else if (offsetLocal >= 0) {
long prev = previousTransition(instantAdjusted);
if (prev < instantAdjusted) {
int offsetPrev = getOffset(prev);
int diff = offsetPrev - offsetLocal;
if (instantAdjusted - prev <= diff) {
return offsetPrev;
}
}
}
return offsetAdjusted;
}
```
| public int getOffsetFromLocal(long instantLocal) {
// get the offset at instantLocal (first estimate)
final int offsetLocal = getOffset(instantLocal);
// adjust instantLocal using the estimate and recalc the offset
final long instantAdjusted = instantLocal - offsetLocal;
final int offsetAdjusted = getOffset(instantAdjusted);
// if the offsets differ, we must be near a DST boundary
if (offsetLocal != offsetAdjusted) {
// we need to ensure that time is always after the DST gap
// this happens naturally for positive offsets, but not for negative
if ((offsetLocal - offsetAdjusted) < 0) {
// if we just return offsetAdjusted then the time is pushed
// back before the transition, whereas it should be
// on or after the transition
long nextLocal = nextTransition(instantAdjusted);
long nextAdjusted = nextTransition(instantLocal - offsetAdjusted);
if (nextLocal != nextAdjusted) {
return offsetLocal;
}
}
} else if (offsetLocal >= 0) {
long prev = previousTransition(instantAdjusted);
if (prev < instantAdjusted) {
int offsetPrev = getOffset(prev);
int diff = offsetPrev - offsetLocal;
if (instantAdjusted - prev <= diff) {
return offsetPrev;
}
}
}
return offsetAdjusted;
} | false | Time | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Gets the millisecond offset to subtract from local time to get UTC time.
* This offset can be used to undo adding the offset obtained by getOffset.
*
* <pre>
* millisLocal == millisUTC + getOffset(millisUTC)
* millisUTC == millisLocal - getOffsetFromLocal(millisLocal)
* </pre>
*
* NOTE: After calculating millisLocal, some error may be introduced. At
* offset transitions (due to DST or other historical changes), ranges of
* local times may map to different UTC times.
* <p>
* This method will return an offset suitable for calculating an instant
* after any DST gap. For example, consider a zone with a cutover
* from 01:00 to 01:59:<br />
* Input: 00:00 Output: 00:00<br />
* Input: 00:30 Output: 00:30<br />
* Input: 01:00 Output: 02:00<br />
* Input: 01:30 Output: 02:30<br />
* Input: 02:00 Output: 02:00<br />
* Input: 02:30 Output: 02:30<br />
* <p>
* During a DST overlap (where the local time is ambiguous) this method will return
* the earlier instant. The combination of these two rules is to always favour
* daylight (summer) time over standard (winter) time.
* <p>
* NOTE: Prior to v2.0, the DST overlap behaviour was not defined and varied by hemisphere.
* Prior to v1.5, the DST gap behaviour was also not defined.
*
* @param instantLocal the millisecond instant, relative to this time zone, to get the offset for
* @return the millisecond offset to subtract from local time to get UTC time
*/
public int getOffsetFromLocal(long instantLocal) {
// get the offset at instantLocal (first estimate)
final int offsetLocal = getOffset(instantLocal);
// adjust instantLocal using the estimate and recalc the offset
final long instantAdjusted = instantLocal - offsetLocal;
final int offsetAdjusted = getOffset(instantAdjusted);
// if the offsets differ, we must be near a DST boundary
if (offsetLocal != offsetAdjusted) {
// we need to ensure that time is always after the DST gap
// this happens naturally for positive offsets, but not for negative
if ((offsetLocal - offsetAdjusted) < 0) {
// if we just return offsetAdjusted then the time is pushed
// back before the transition, whereas it should be
// on or after the transition
long nextLocal = nextTransition(instantAdjusted);
long nextAdjusted = nextTransition(instantLocal - offsetAdjusted);
if (nextLocal != nextAdjusted) {
return offsetLocal;
}
}
} else if (offsetLocal >= 0) {
long prev = previousTransition(instantAdjusted);
if (prev < instantAdjusted) {
int offsetPrev = getOffset(prev);
int diff = offsetPrev - offsetLocal;
if (instantAdjusted - prev <= diff) {
return offsetPrev;
}
}
}
return offsetAdjusted;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
79 | 8ed6c408273ef3b08ad62d262bfc584aa3ac3037f7b7f2c8b0a0f406850b849f | public static double distance(int[] p1, int[] p2) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Calculates the L<sub>2</sub> (Euclidean) distance between two points.
*
* @param p1 the first point
* @param p2 the second point
* @return the L<sub>2</sub> distance between the two points
*/
public static double distance(int[] p1, int[] p2) {
int sum = 0;
for (int i = 0; i < p1.length; i++) {
final int dp = p1[i] - p2[i];
sum += dp * dp;
}
return Math.sqrt(sum);
}
```
| public static double distance(int[] p1, int[] p2) {
int sum = 0;
for (int i = 0; i < p1.length; i++) {
final int dp = p1[i] - p2[i];
sum += dp * dp;
}
return Math.sqrt(sum);
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Calculates the L<sub>2</sub> (Euclidean) distance between two points.
*
* @param p1 the first point
* @param p2 the second point
* @return the L<sub>2</sub> distance between the two points
*/
public static double distance(int[] p1, int[] p2) {
int sum = 0;
for (int i = 0; i < p1.length; i++) {
final int dp = p1[i] - p2[i];
sum += dp * dp;
}
return Math.sqrt(sum);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
42 | 8f0efa4e8278de26ca5155cf9d638439f8cb3bafd333462b397f2bef3dc4ab6d | @Override
Node processForInLoop(ForInLoop loopNode) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
Node processForInLoop(ForInLoop loopNode) {
if (loopNode.isForEach()) {
errorReporter.error(
"unsupported language extension: for each",
sourceName,
loopNode.getLineno(), "", 0);
// Return the bare minimum to put the AST in a valid state.
return newNode(Token.EXPR_RESULT, Node.newNumber(0));
}
return newNode(
Token.FOR,
transform(loopNode.getIterator()),
transform(loopNode.getIteratedObject()),
transformBlock(loopNode.getBody()));
}
```
| @Override
Node processForInLoop(ForInLoop loopNode) {
if (loopNode.isForEach()) {
errorReporter.error(
"unsupported language extension: for each",
sourceName,
loopNode.getLineno(), "", 0);
// Return the bare minimum to put the AST in a valid state.
return newNode(Token.EXPR_RESULT, Node.newNumber(0));
}
return newNode(
Token.FOR,
transform(loopNode.getIterator()),
transform(loopNode.getIteratedObject()),
transformBlock(loopNode.getBody()));
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
Node processForInLoop(ForInLoop loopNode) {
if (loopNode.isForEach()) {
errorReporter.error(
"unsupported language extension: for each",
sourceName,
loopNode.getLineno(), "", 0);
// Return the bare minimum to put the AST in a valid state.
return newNode(Token.EXPR_RESULT, Node.newNumber(0));
}
return newNode(
Token.FOR,
transform(loopNode.getIterator()),
transform(loopNode.getIteratedObject()),
transformBlock(loopNode.getBody()));
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
12 | 8f1dfa9e7c0d4d4025731d9b4698ceebb12d4588bd89ec9941f01276bb1a9c8e | public TarArchiveEntry getNextTarEntry() throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Get the next entry in this tar archive. This will skip
* over any remaining data in the current entry, if there
* is one, and place the input stream at the header of the
* next entry, and read the header and instantiate a new
* TarEntry from the header bytes and return that entry.
* If there are no more entries in the archive, null will
* be returned to indicate that the end of the archive has
* been reached.
*
* @return The next TarEntry in the archive, or null.
* @throws IOException on error
*/
public TarArchiveEntry getNextTarEntry() throws IOException {
if (hasHitEOF) {
return null;
}
if (currEntry != null) {
long numToSkip = entrySize - entryOffset;
while (numToSkip > 0) {
long skipped = skip(numToSkip);
if (skipped <= 0) {
throw new RuntimeException("failed to skip current tar entry");
}
numToSkip -= skipped;
}
readBuf = null;
}
byte[] headerBuf = getRecord();
if (hasHitEOF) {
currEntry = null;
return null;
}
try {
currEntry = new TarArchiveEntry(headerBuf);
} catch (IllegalArgumentException e) {
IOException ioe = new IOException("Error detected parsing the header");
ioe.initCause(e);
throw ioe;
}
entryOffset = 0;
entrySize = currEntry.getSize();
if (currEntry.isGNULongNameEntry()) {
// read in the name
StringBuffer longName = new StringBuffer();
byte[] buf = new byte[SMALL_BUFFER_SIZE];
int length = 0;
while ((length = read(buf)) >= 0) {
longName.append(new String(buf, 0, length));
}
getNextEntry();
if (currEntry == null) {
// Bugzilla: 40334
// Malformed tar file - long entry name not followed by entry
return null;
}
// remove trailing null terminator
if (longName.length() > 0
&& longName.charAt(longName.length() - 1) == 0) {
longName.deleteCharAt(longName.length() - 1);
}
currEntry.setName(longName.toString());
}
if (currEntry.isPaxHeader()){ // Process Pax headers
paxHeaders();
}
if (currEntry.isGNUSparse()){ // Process sparse files
readGNUSparse();
}
// If the size of the next element in the archive has changed
// due to a new size being reported in the posix header
// information, we update entrySize here so that it contains
// the correct value.
entrySize = currEntry.getSize();
return currEntry;
}
```
| public TarArchiveEntry getNextTarEntry() throws IOException {
if (hasHitEOF) {
return null;
}
if (currEntry != null) {
long numToSkip = entrySize - entryOffset;
while (numToSkip > 0) {
long skipped = skip(numToSkip);
if (skipped <= 0) {
throw new RuntimeException("failed to skip current tar entry");
}
numToSkip -= skipped;
}
readBuf = null;
}
byte[] headerBuf = getRecord();
if (hasHitEOF) {
currEntry = null;
return null;
}
try {
currEntry = new TarArchiveEntry(headerBuf);
} catch (IllegalArgumentException e) {
IOException ioe = new IOException("Error detected parsing the header");
ioe.initCause(e);
throw ioe;
}
entryOffset = 0;
entrySize = currEntry.getSize();
if (currEntry.isGNULongNameEntry()) {
// read in the name
StringBuffer longName = new StringBuffer();
byte[] buf = new byte[SMALL_BUFFER_SIZE];
int length = 0;
while ((length = read(buf)) >= 0) {
longName.append(new String(buf, 0, length));
}
getNextEntry();
if (currEntry == null) {
// Bugzilla: 40334
// Malformed tar file - long entry name not followed by entry
return null;
}
// remove trailing null terminator
if (longName.length() > 0
&& longName.charAt(longName.length() - 1) == 0) {
longName.deleteCharAt(longName.length() - 1);
}
currEntry.setName(longName.toString());
}
if (currEntry.isPaxHeader()){ // Process Pax headers
paxHeaders();
}
if (currEntry.isGNUSparse()){ // Process sparse files
readGNUSparse();
}
// If the size of the next element in the archive has changed
// due to a new size being reported in the posix header
// information, we update entrySize here so that it contains
// the correct value.
entrySize = currEntry.getSize();
return currEntry;
} | false | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Get the next entry in this tar archive. This will skip
* over any remaining data in the current entry, if there
* is one, and place the input stream at the header of the
* next entry, and read the header and instantiate a new
* TarEntry from the header bytes and return that entry.
* If there are no more entries in the archive, null will
* be returned to indicate that the end of the archive has
* been reached.
*
* @return The next TarEntry in the archive, or null.
* @throws IOException on error
*/
public TarArchiveEntry getNextTarEntry() throws IOException {
if (hasHitEOF) {
return null;
}
if (currEntry != null) {
long numToSkip = entrySize - entryOffset;
while (numToSkip > 0) {
long skipped = skip(numToSkip);
if (skipped <= 0) {
throw new RuntimeException("failed to skip current tar entry");
}
numToSkip -= skipped;
}
readBuf = null;
}
byte[] headerBuf = getRecord();
if (hasHitEOF) {
currEntry = null;
return null;
}
try {
currEntry = new TarArchiveEntry(headerBuf);
} catch (IllegalArgumentException e) {
IOException ioe = new IOException("Error detected parsing the header");
ioe.initCause(e);
throw ioe;
}
entryOffset = 0;
entrySize = currEntry.getSize();
if (currEntry.isGNULongNameEntry()) {
// read in the name
StringBuffer longName = new StringBuffer();
byte[] buf = new byte[SMALL_BUFFER_SIZE];
int length = 0;
while ((length = read(buf)) >= 0) {
longName.append(new String(buf, 0, length));
}
getNextEntry();
if (currEntry == null) {
// Bugzilla: 40334
// Malformed tar file - long entry name not followed by entry
return null;
}
// remove trailing null terminator
if (longName.length() > 0
&& longName.charAt(longName.length() - 1) == 0) {
longName.deleteCharAt(longName.length() - 1);
}
currEntry.setName(longName.toString());
}
if (currEntry.isPaxHeader()){ // Process Pax headers
paxHeaders();
}
if (currEntry.isGNUSparse()){ // Process sparse files
readGNUSparse();
}
// If the size of the next element in the archive has changed
// due to a new size being reported in the posix header
// information, we update entrySize here so that it contains
// the correct value.
entrySize = currEntry.getSize();
return currEntry;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
13 | 8f22f48a1036a82db6305de71182334f1fb25475e6a4744488c2c2d34b2ece25 | protected void setName(String name) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Set the name of the entry.
* @param name the name to use
*/
protected void setName(String name) {
if (name != null && getPlatform() == PLATFORM_FAT
&& name.indexOf("/") == -1) {
name = name.replace('\\', '/');
}
this.name = name;
}
```
| protected void setName(String name) {
if (name != null && getPlatform() == PLATFORM_FAT
&& name.indexOf("/") == -1) {
name = name.replace('\\', '/');
}
this.name = name;
} | false | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Set the name of the entry.
* @param name the name to use
*/
protected void setName(String name) {
if (name != null && getPlatform() == PLATFORM_FAT
&& name.indexOf("/") == -1) {
name = name.replace('\\', '/');
}
this.name = name;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
83 | 8f2636a5d20d2f666cc6888549800b673e2209b6e840ec9300b8d40d88d278c3 | @Override
public int parseArguments(Parameters params) throws CmdLineException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public int parseArguments(Parameters params) throws CmdLineException {
String param = null;
try {
param = params.getParameter(0);
} catch (CmdLineException e) {}
if (param == null) {
setter.addValue(true);
return 0;
} else {
String lowerParam = param.toLowerCase();
if (TRUES.contains(lowerParam)) {
setter.addValue(true);
} else if (FALSES.contains(lowerParam)) {
setter.addValue(false);
} else {
setter.addValue(true);
return 0;
}
return 1;
}
}
```
| @Override
public int parseArguments(Parameters params) throws CmdLineException {
String param = null;
try {
param = params.getParameter(0);
} catch (CmdLineException e) {}
if (param == null) {
setter.addValue(true);
return 0;
} else {
String lowerParam = param.toLowerCase();
if (TRUES.contains(lowerParam)) {
setter.addValue(true);
} else if (FALSES.contains(lowerParam)) {
setter.addValue(false);
} else {
setter.addValue(true);
return 0;
}
return 1;
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public int parseArguments(Parameters params) throws CmdLineException {
String param = null;
try {
param = params.getParameter(0);
} catch (CmdLineException e) {}
if (param == null) {
setter.addValue(true);
return 0;
} else {
String lowerParam = param.toLowerCase();
if (TRUES.contains(lowerParam)) {
setter.addValue(true);
} else if (FALSES.contains(lowerParam)) {
setter.addValue(false);
} else {
setter.addValue(true);
return 0;
}
return 1;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
88 | 8f6dc98fc2fcc4f2f45e3ee27925517f7ccea1084148725dee894987eb5c8262 | public String getValue() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
Get the attribute value.
@return the attribute value
*/
public String getValue() {
return Attributes.checkNotNull(val);
}
```
| public String getValue() {
return Attributes.checkNotNull(val);
} | false | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
Get the attribute value.
@return the attribute value
*/
public String getValue() {
return Attributes.checkNotNull(val);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
41 | 8ff4eff1b50b2a65bdbb7682b4e95b5606fe27127ad3d80a545134b67fd19a04 | public double evaluate(final double[] values, final double[] weights,
final double mean, final int begin, final int length) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns the weighted variance of the entries in the specified portion of
* the input array, using the precomputed weighted mean value. Returns
* <code>Double.NaN</code> if the designated subarray is empty.
* <p>
* Uses the formula <pre>
* Σ(weights[i]*(values[i] - mean)<sup>2</sup>)/(Σ(weights[i]) - 1)
* </pre></p>
* <p>
* The formula used assumes that the supplied mean value is the weighted arithmetic
* mean of the sample data, not a known population parameter. This method
* is supplied only to save computation when the mean has already been
* computed.</p>
* <p>
* This formula will not return the same result as the unweighted variance when all
* weights are equal, unless all weights are equal to 1. The formula assumes that
* weights are to be treated as "expansion values," as will be the case if for example
* the weights represent frequency counts. To normalize weights so that the denominator
* in the variance computation equals the length of the input vector minus one, use <pre>
* <code>evaluate(values, MathArrays.normalizeArray(weights, values.length), mean); </code>
* </pre>
* <p>
* Returns 0 for a single-value (i.e. length = 1) sample.</p>
* <p>
* Throws <code>IllegalArgumentException</code> if any of the following are true:
* <ul><li>the values array is null</li>
* <li>the weights array is null</li>
* <li>the weights array does not have the same length as the values array</li>
* <li>the weights array contains one or more infinite values</li>
* <li>the weights array contains one or more NaN values</li>
* <li>the weights array contains negative values</li>
* <li>the start and length arguments do not determine a valid array</li>
* </ul></p>
* <p>
* Does not change the internal state of the statistic.</p>
*
* @param values the input array
* @param weights the weights array
* @param mean the precomputed weighted mean value
* @param begin index of the first array element to include
* @param length the number of elements to include
* @return the variance of the values or Double.NaN if length = 0
* @throws IllegalArgumentException if the parameters are not valid
* @since 2.1
*/
public double evaluate(final double[] values, final double[] weights,
final double mean, final int begin, final int length) {
double var = Double.NaN;
if (test(values, weights, begin, length)) {
if (length == 1) {
var = 0.0;
} else if (length > 1) {
double accum = 0.0;
double dev = 0.0;
double accum2 = 0.0;
for (int i = begin; i < begin + length; i++) {
dev = values[i] - mean;
accum += weights[i] * (dev * dev);
accum2 += weights[i] * dev;
}
double sumWts = 0;
for (int i = begin; i < begin + length; i++) {
sumWts += weights[i];
}
if (isBiasCorrected) {
var = (accum - (accum2 * accum2 / sumWts)) / (sumWts - 1.0);
} else {
var = (accum - (accum2 * accum2 / sumWts)) / sumWts;
}
}
}
return var;
}
```
| public double evaluate(final double[] values, final double[] weights,
final double mean, final int begin, final int length) {
double var = Double.NaN;
if (test(values, weights, begin, length)) {
if (length == 1) {
var = 0.0;
} else if (length > 1) {
double accum = 0.0;
double dev = 0.0;
double accum2 = 0.0;
for (int i = begin; i < begin + length; i++) {
dev = values[i] - mean;
accum += weights[i] * (dev * dev);
accum2 += weights[i] * dev;
}
double sumWts = 0;
for (int i = begin; i < begin + length; i++) {
sumWts += weights[i];
}
if (isBiasCorrected) {
var = (accum - (accum2 * accum2 / sumWts)) / (sumWts - 1.0);
} else {
var = (accum - (accum2 * accum2 / sumWts)) / sumWts;
}
}
}
return var;
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns the weighted variance of the entries in the specified portion of
* the input array, using the precomputed weighted mean value. Returns
* <code>Double.NaN</code> if the designated subarray is empty.
* <p>
* Uses the formula <pre>
* Σ(weights[i]*(values[i] - mean)<sup>2</sup>)/(Σ(weights[i]) - 1)
* </pre></p>
* <p>
* The formula used assumes that the supplied mean value is the weighted arithmetic
* mean of the sample data, not a known population parameter. This method
* is supplied only to save computation when the mean has already been
* computed.</p>
* <p>
* This formula will not return the same result as the unweighted variance when all
* weights are equal, unless all weights are equal to 1. The formula assumes that
* weights are to be treated as "expansion values," as will be the case if for example
* the weights represent frequency counts. To normalize weights so that the denominator
* in the variance computation equals the length of the input vector minus one, use <pre>
* <code>evaluate(values, MathArrays.normalizeArray(weights, values.length), mean); </code>
* </pre>
* <p>
* Returns 0 for a single-value (i.e. length = 1) sample.</p>
* <p>
* Throws <code>IllegalArgumentException</code> if any of the following are true:
* <ul><li>the values array is null</li>
* <li>the weights array is null</li>
* <li>the weights array does not have the same length as the values array</li>
* <li>the weights array contains one or more infinite values</li>
* <li>the weights array contains one or more NaN values</li>
* <li>the weights array contains negative values</li>
* <li>the start and length arguments do not determine a valid array</li>
* </ul></p>
* <p>
* Does not change the internal state of the statistic.</p>
*
* @param values the input array
* @param weights the weights array
* @param mean the precomputed weighted mean value
* @param begin index of the first array element to include
* @param length the number of elements to include
* @return the variance of the values or Double.NaN if length = 0
* @throws IllegalArgumentException if the parameters are not valid
* @since 2.1
*/
public double evaluate(final double[] values, final double[] weights,
final double mean, final int begin, final int length) {
double var = Double.NaN;
if (test(values, weights, begin, length)) {
if (length == 1) {
var = 0.0;
} else if (length > 1) {
double accum = 0.0;
double dev = 0.0;
double accum2 = 0.0;
for (int i = begin; i < begin + length; i++) {
dev = values[i] - mean;
accum += weights[i] * (dev * dev);
accum2 += weights[i] * dev;
}
double sumWts = 0;
for (int i = begin; i < begin + length; i++) {
sumWts += weights[i];
}
if (isBiasCorrected) {
var = (accum - (accum2 * accum2 / sumWts)) / (sumWts - 1.0);
} else {
var = (accum - (accum2 * accum2 / sumWts)) / sumWts;
}
}
}
return var;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
88 | 9063d9cfdc23f6fa66928860c2d6cce6eff29ff71404afd17e16f3a1f8a6474c | private VariableLiveness isVariableReadBeforeKill(
Node n, String variable) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Give an expression and a variable. It returns READ, if the first
* reference of that variable is a read. It returns KILL, if the first
* reference of that variable is an assignment. It returns MAY_LIVE otherwise.
*/
private VariableLiveness isVariableReadBeforeKill(
Node n, String variable) {
if (NodeUtil.isName(n) && variable.equals(n.getString())) {
if (NodeUtil.isLhs(n, n.getParent())) {
// The expression to which the assignment is made is evaluated before
// the RHS is evaluated (normal left to right evaluation) but the KILL
// occurs after the RHS is evaluated.
return VariableLiveness.KILL;
} else {
return VariableLiveness.READ;
}
}
// Expressions are evaluated left-right, depth first.
for (Node child = n.getFirstChild();
child != null; child = child.getNext()) {
if (!ControlFlowGraph.isEnteringNewCfgNode(child)) { // Not a FUNCTION
VariableLiveness state = isVariableReadBeforeKill(child, variable);
if (state != VariableLiveness.MAYBE_LIVE) {
return state;
}
}
}
return VariableLiveness.MAYBE_LIVE;
}
```
| private VariableLiveness isVariableReadBeforeKill(
Node n, String variable) {
if (NodeUtil.isName(n) && variable.equals(n.getString())) {
if (NodeUtil.isLhs(n, n.getParent())) {
// The expression to which the assignment is made is evaluated before
// the RHS is evaluated (normal left to right evaluation) but the KILL
// occurs after the RHS is evaluated.
return VariableLiveness.KILL;
} else {
return VariableLiveness.READ;
}
}
// Expressions are evaluated left-right, depth first.
for (Node child = n.getFirstChild();
child != null; child = child.getNext()) {
if (!ControlFlowGraph.isEnteringNewCfgNode(child)) { // Not a FUNCTION
VariableLiveness state = isVariableReadBeforeKill(child, variable);
if (state != VariableLiveness.MAYBE_LIVE) {
return state;
}
}
}
return VariableLiveness.MAYBE_LIVE;
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Give an expression and a variable. It returns READ, if the first
* reference of that variable is a read. It returns KILL, if the first
* reference of that variable is an assignment. It returns MAY_LIVE otherwise.
*/
private VariableLiveness isVariableReadBeforeKill(
Node n, String variable) {
if (NodeUtil.isName(n) && variable.equals(n.getString())) {
if (NodeUtil.isLhs(n, n.getParent())) {
// The expression to which the assignment is made is evaluated before
// the RHS is evaluated (normal left to right evaluation) but the KILL
// occurs after the RHS is evaluated.
return VariableLiveness.KILL;
} else {
return VariableLiveness.READ;
}
}
// Expressions are evaluated left-right, depth first.
for (Node child = n.getFirstChild();
child != null; child = child.getNext()) {
if (!ControlFlowGraph.isEnteringNewCfgNode(child)) { // Not a FUNCTION
VariableLiveness state = isVariableReadBeforeKill(child, variable);
if (state != VariableLiveness.MAYBE_LIVE) {
return state;
}
}
}
return VariableLiveness.MAYBE_LIVE;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
77 | 906981ab7faff43f580921a7ec47f90b01ae74e382674abd0ea18d078682a75b | static String strEscape(String s, char quote,
String doublequoteEscape,
String singlequoteEscape,
String backslashEscape,
CharsetEncoder outputCharsetEncoder) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/** Helper to escape javascript string as well as regular expression */
static String strEscape(String s, char quote,
String doublequoteEscape,
String singlequoteEscape,
String backslashEscape,
CharsetEncoder outputCharsetEncoder) {
StringBuilder sb = new StringBuilder(s.length() + 2);
sb.append(quote);
for (int i = 0; i < s.length(); i++) {
char c = s.charAt(i);
switch (c) {
case '\n': sb.append("\\n"); break;
case '\r': sb.append("\\r"); break;
case '\t': sb.append("\\t"); break;
case '\\': sb.append(backslashEscape); break;
case '\"': sb.append(doublequoteEscape); break;
case '\'': sb.append(singlequoteEscape); break;
case '>': // Break --> into --\> or ]]> into ]]\>
if (i >= 2 &&
((s.charAt(i - 1) == '-' && s.charAt(i - 2) == '-') ||
(s.charAt(i - 1) == ']' && s.charAt(i - 2) == ']'))) {
sb.append("\\>");
} else {
sb.append(c);
}
break;
case '<':
// Break </script into <\/script
final String END_SCRIPT = "/script";
// Break <!-- into <\!--
final String START_COMMENT = "!--";
if (s.regionMatches(true, i + 1, END_SCRIPT, 0,
END_SCRIPT.length())) {
sb.append("<\\");
} else if (s.regionMatches(false, i + 1, START_COMMENT, 0,
START_COMMENT.length())) {
sb.append("<\\");
} else {
sb.append(c);
}
break;
default:
// If we're given an outputCharsetEncoder, then check if the
// character can be represented in this character set.
if (outputCharsetEncoder != null) {
if (outputCharsetEncoder.canEncode(c)) {
sb.append(c);
} else {
// Unicode-escape the character.
appendHexJavaScriptRepresentation(sb, c);
}
} else {
// No charsetEncoder provided - pass straight latin characters
// through, and escape the rest. Doing the explicit character
// check is measurably faster than using the CharsetEncoder.
if (c > 0x1f && c <= 0x7f) {
sb.append(c);
} else {
// Other characters can be misinterpreted by some js parsers,
// or perhaps mangled by proxies along the way,
// so we play it safe and unicode escape them.
appendHexJavaScriptRepresentation(sb, c);
}
}
}
}
sb.append(quote);
return sb.toString();
}
```
| static String strEscape(String s, char quote,
String doublequoteEscape,
String singlequoteEscape,
String backslashEscape,
CharsetEncoder outputCharsetEncoder) {
StringBuilder sb = new StringBuilder(s.length() + 2);
sb.append(quote);
for (int i = 0; i < s.length(); i++) {
char c = s.charAt(i);
switch (c) {
case '\n': sb.append("\\n"); break;
case '\r': sb.append("\\r"); break;
case '\t': sb.append("\\t"); break;
case '\\': sb.append(backslashEscape); break;
case '\"': sb.append(doublequoteEscape); break;
case '\'': sb.append(singlequoteEscape); break;
case '>': // Break --> into --\> or ]]> into ]]\>
if (i >= 2 &&
((s.charAt(i - 1) == '-' && s.charAt(i - 2) == '-') ||
(s.charAt(i - 1) == ']' && s.charAt(i - 2) == ']'))) {
sb.append("\\>");
} else {
sb.append(c);
}
break;
case '<':
// Break </script into <\/script
final String END_SCRIPT = "/script";
// Break <!-- into <\!--
final String START_COMMENT = "!--";
if (s.regionMatches(true, i + 1, END_SCRIPT, 0,
END_SCRIPT.length())) {
sb.append("<\\");
} else if (s.regionMatches(false, i + 1, START_COMMENT, 0,
START_COMMENT.length())) {
sb.append("<\\");
} else {
sb.append(c);
}
break;
default:
// If we're given an outputCharsetEncoder, then check if the
// character can be represented in this character set.
if (outputCharsetEncoder != null) {
if (outputCharsetEncoder.canEncode(c)) {
sb.append(c);
} else {
// Unicode-escape the character.
appendHexJavaScriptRepresentation(sb, c);
}
} else {
// No charsetEncoder provided - pass straight latin characters
// through, and escape the rest. Doing the explicit character
// check is measurably faster than using the CharsetEncoder.
if (c > 0x1f && c <= 0x7f) {
sb.append(c);
} else {
// Other characters can be misinterpreted by some js parsers,
// or perhaps mangled by proxies along the way,
// so we play it safe and unicode escape them.
appendHexJavaScriptRepresentation(sb, c);
}
}
}
}
sb.append(quote);
return sb.toString();
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/** Helper to escape javascript string as well as regular expression */
static String strEscape(String s, char quote,
String doublequoteEscape,
String singlequoteEscape,
String backslashEscape,
CharsetEncoder outputCharsetEncoder) {
StringBuilder sb = new StringBuilder(s.length() + 2);
sb.append(quote);
for (int i = 0; i < s.length(); i++) {
char c = s.charAt(i);
switch (c) {
case '\n': sb.append("\\n"); break;
case '\r': sb.append("\\r"); break;
case '\t': sb.append("\\t"); break;
case '\\': sb.append(backslashEscape); break;
case '\"': sb.append(doublequoteEscape); break;
case '\'': sb.append(singlequoteEscape); break;
case '>': // Break --> into --\> or ]]> into ]]\>
if (i >= 2 &&
((s.charAt(i - 1) == '-' && s.charAt(i - 2) == '-') ||
(s.charAt(i - 1) == ']' && s.charAt(i - 2) == ']'))) {
sb.append("\\>");
} else {
sb.append(c);
}
break;
case '<':
// Break </script into <\/script
final String END_SCRIPT = "/script";
// Break <!-- into <\!--
final String START_COMMENT = "!--";
if (s.regionMatches(true, i + 1, END_SCRIPT, 0,
END_SCRIPT.length())) {
sb.append("<\\");
} else if (s.regionMatches(false, i + 1, START_COMMENT, 0,
START_COMMENT.length())) {
sb.append("<\\");
} else {
sb.append(c);
}
break;
default:
// If we're given an outputCharsetEncoder, then check if the
// character can be represented in this character set.
if (outputCharsetEncoder != null) {
if (outputCharsetEncoder.canEncode(c)) {
sb.append(c);
} else {
// Unicode-escape the character.
appendHexJavaScriptRepresentation(sb, c);
}
} else {
// No charsetEncoder provided - pass straight latin characters
// through, and escape the rest. Doing the explicit character
// check is measurably faster than using the CharsetEncoder.
if (c > 0x1f && c <= 0x7f) {
sb.append(c);
} else {
// Other characters can be misinterpreted by some js parsers,
// or perhaps mangled by proxies along the way,
// so we play it safe and unicode escape them.
appendHexJavaScriptRepresentation(sb, c);
}
}
}
}
sb.append(quote);
return sb.toString();
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
33 | 90b980002376199d8f541dcdc2e83b02663b4b246343d562e999bcbf5dbfd5d0 | @Override
public void matchConstraint(ObjectType constraintObj) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public void matchConstraint(ObjectType constraintObj) {
// We only want to match contraints on anonymous types.
if (hasReferenceName()) {
return;
}
// Handle the case where the constraint object is a record type.
//
// param constraintObj {{prop: (number|undefined)}}
// function f(constraintObj) {}
// f({});
//
// We want to modify the object literal to match the constraint, by
// taking any each property on the record and trying to match
// properties on this object.
if (constraintObj.isRecordType()) {
for (String prop : constraintObj.getOwnPropertyNames()) {
JSType propType = constraintObj.getPropertyType(prop);
if (!isPropertyTypeDeclared(prop)) {
JSType typeToInfer = propType;
if (!hasProperty(prop)) {
typeToInfer = getNativeType(JSTypeNative.VOID_TYPE)
.getLeastSupertype(propType);
}
defineInferredProperty(prop, typeToInfer, null);
}
}
}
}
```
| @Override
public void matchConstraint(ObjectType constraintObj) {
// We only want to match contraints on anonymous types.
if (hasReferenceName()) {
return;
}
// Handle the case where the constraint object is a record type.
//
// param constraintObj {{prop: (number|undefined)}}
// function f(constraintObj) {}
// f({});
//
// We want to modify the object literal to match the constraint, by
// taking any each property on the record and trying to match
// properties on this object.
if (constraintObj.isRecordType()) {
for (String prop : constraintObj.getOwnPropertyNames()) {
JSType propType = constraintObj.getPropertyType(prop);
if (!isPropertyTypeDeclared(prop)) {
JSType typeToInfer = propType;
if (!hasProperty(prop)) {
typeToInfer = getNativeType(JSTypeNative.VOID_TYPE)
.getLeastSupertype(propType);
}
defineInferredProperty(prop, typeToInfer, null);
}
}
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public void matchConstraint(ObjectType constraintObj) {
// We only want to match contraints on anonymous types.
if (hasReferenceName()) {
return;
}
// Handle the case where the constraint object is a record type.
//
// param constraintObj {{prop: (number|undefined)}}
// function f(constraintObj) {}
// f({});
//
// We want to modify the object literal to match the constraint, by
// taking any each property on the record and trying to match
// properties on this object.
if (constraintObj.isRecordType()) {
for (String prop : constraintObj.getOwnPropertyNames()) {
JSType propType = constraintObj.getPropertyType(prop);
if (!isPropertyTypeDeclared(prop)) {
JSType typeToInfer = propType;
if (!hasProperty(prop)) {
typeToInfer = getNativeType(JSTypeNative.VOID_TYPE)
.getLeastSupertype(propType);
}
defineInferredProperty(prop, typeToInfer, null);
}
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
18 | 90cf9397b9bcb3d1f8e8c57f7f26920313ec5c4b6ce675518686d3775daab615 | public static boolean equals(final CharSequence cs1, final CharSequence cs2) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>
* Compares two CharSequences, returning <code>true</code> if they represent equal sequences of characters.
* </p>
*
* <p>
* <code>null</code>s are handled without exceptions. Two <code>null</code> references are considered to be equal.
* The comparison is case sensitive.
* </p>
*
* <pre>
* StringUtils.equals(null, null) = true
* StringUtils.equals(null, "abc") = false
* StringUtils.equals("abc", null) = false
* StringUtils.equals("abc", "abc") = true
* StringUtils.equals("abc", "ABC") = false
* </pre>
*
* <p>
* Copied from Apache Commons Lang r1583482 on April 10, 2014 (day of 3.3.2 release).
* </p>
*
* @see Object#equals(Object)
* @param cs1
* the first CharSequence, may be <code>null</code>
* @param cs2
* the second CharSequence, may be <code>null</code>
* @return <code>true</code> if the CharSequences are equal (case-sensitive), or both <code>null</code>
* @since 1.10
*/
public static boolean equals(final CharSequence cs1, final CharSequence cs2) {
if (cs1 == cs2) {
return true;
}
if (cs1 == null || cs2 == null) {
return false;
}
if (cs1 instanceof String && cs2 instanceof String) {
return cs1.equals(cs2);
}
return CharSequenceUtils.regionMatches(cs1, false, 0, cs2, 0, Math.max(cs1.length(), cs2.length()));
}
```
| public static boolean equals(final CharSequence cs1, final CharSequence cs2) {
if (cs1 == cs2) {
return true;
}
if (cs1 == null || cs2 == null) {
return false;
}
if (cs1 instanceof String && cs2 instanceof String) {
return cs1.equals(cs2);
}
return CharSequenceUtils.regionMatches(cs1, false, 0, cs2, 0, Math.max(cs1.length(), cs2.length()));
} | true | Codec | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>
* Compares two CharSequences, returning <code>true</code> if they represent equal sequences of characters.
* </p>
*
* <p>
* <code>null</code>s are handled without exceptions. Two <code>null</code> references are considered to be equal.
* The comparison is case sensitive.
* </p>
*
* <pre>
* StringUtils.equals(null, null) = true
* StringUtils.equals(null, "abc") = false
* StringUtils.equals("abc", null) = false
* StringUtils.equals("abc", "abc") = true
* StringUtils.equals("abc", "ABC") = false
* </pre>
*
* <p>
* Copied from Apache Commons Lang r1583482 on April 10, 2014 (day of 3.3.2 release).
* </p>
*
* @see Object#equals(Object)
* @param cs1
* the first CharSequence, may be <code>null</code>
* @param cs2
* the second CharSequence, may be <code>null</code>
* @return <code>true</code> if the CharSequences are equal (case-sensitive), or both <code>null</code>
* @since 1.10
*/
public static boolean equals(final CharSequence cs1, final CharSequence cs2) {
if (cs1 == cs2) {
return true;
}
if (cs1 == null || cs2 == null) {
return false;
}
if (cs1 instanceof String && cs2 instanceof String) {
return cs1.equals(cs2);
}
return CharSequenceUtils.regionMatches(cs1, false, 0, cs2, 0, Math.max(cs1.length(), cs2.length()));
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
72 | 911b8486291c54bb351747611e8fd351c9ccd444100fcb060b1000d5153b9f0d | private static String cacheString(final char[] charBuf, final String[] stringCache, final int start, final int count) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Caches short strings, as a flywheel pattern, to reduce GC load. Just for this doc, to prevent leaks.
* <p />
* Simplistic, and on hash collisions just falls back to creating a new string, vs a full HashMap with Entry list.
* That saves both having to create objects as hash keys, and running through the entry list, at the expense of
* some more duplicates.
*/
private static String cacheString(final char[] charBuf, final String[] stringCache, final int start, final int count) {
// limit (no cache):
if (count > maxStringCacheLen)
return new String(charBuf, start, count);
if (count < 1)
return "";
// calculate hash:
int hash = 0;
int offset = start;
for (int i = 0; i < count; i++) {
hash = 31 * hash + charBuf[offset++];
}
// get from cache
final int index = hash & stringCache.length - 1;
String cached = stringCache[index];
if (cached == null) { // miss, add
cached = new String(charBuf, start, count);
stringCache[index] = cached;
} else { // hashcode hit, check equality
if (rangeEquals(charBuf, start, count, cached)) { // hit
return cached;
} else { // hashcode conflict
cached = new String(charBuf, start, count);
stringCache[index] = cached; // update the cache, as recently used strings are more likely to show up again
}
}
return cached;
}
```
| private static String cacheString(final char[] charBuf, final String[] stringCache, final int start, final int count) {
// limit (no cache):
if (count > maxStringCacheLen)
return new String(charBuf, start, count);
if (count < 1)
return "";
// calculate hash:
int hash = 0;
int offset = start;
for (int i = 0; i < count; i++) {
hash = 31 * hash + charBuf[offset++];
}
// get from cache
final int index = hash & stringCache.length - 1;
String cached = stringCache[index];
if (cached == null) { // miss, add
cached = new String(charBuf, start, count);
stringCache[index] = cached;
} else { // hashcode hit, check equality
if (rangeEquals(charBuf, start, count, cached)) { // hit
return cached;
} else { // hashcode conflict
cached = new String(charBuf, start, count);
stringCache[index] = cached; // update the cache, as recently used strings are more likely to show up again
}
}
return cached;
} | false | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Caches short strings, as a flywheel pattern, to reduce GC load. Just for this doc, to prevent leaks.
* <p />
* Simplistic, and on hash collisions just falls back to creating a new string, vs a full HashMap with Entry list.
* That saves both having to create objects as hash keys, and running through the entry list, at the expense of
* some more duplicates.
*/
private static String cacheString(final char[] charBuf, final String[] stringCache, final int start, final int count) {
// limit (no cache):
if (count > maxStringCacheLen)
return new String(charBuf, start, count);
if (count < 1)
return "";
// calculate hash:
int hash = 0;
int offset = start;
for (int i = 0; i < count; i++) {
hash = 31 * hash + charBuf[offset++];
}
// get from cache
final int index = hash & stringCache.length - 1;
String cached = stringCache[index];
if (cached == null) { // miss, add
cached = new String(charBuf, start, count);
stringCache[index] = cached;
} else { // hashcode hit, check equality
if (rangeEquals(charBuf, start, count, cached)) { // hit
return cached;
} else { // hashcode conflict
cached = new String(charBuf, start, count);
stringCache[index] = cached; // update the cache, as recently used strings are more likely to show up again
}
}
return cached;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
5 | 913a7ac096f54ace0aed90473a26f4280bb1dbe9c759fea4553633cb40ae7cfc | public XYDataItem addOrUpdate(Number x, Number y) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Adds or updates an item in the series and sends a
* {@link SeriesChangeEvent} to all registered listeners.
*
* @param x the x-value (<code>null</code> not permitted).
* @param y the y-value (<code>null</code> permitted).
*
* @return A copy of the overwritten data item, or <code>null</code> if no
* item was overwritten.
*/
public XYDataItem addOrUpdate(Number x, Number y) {
if (x == null) {
throw new IllegalArgumentException("Null 'x' argument.");
}
// if we get to here, we know that duplicate X values are not permitted
XYDataItem overwritten = null;
int index = indexOf(x);
if (index >= 0 && !this.allowDuplicateXValues) {
XYDataItem existing = (XYDataItem) this.data.get(index);
try {
overwritten = (XYDataItem) existing.clone();
}
catch (CloneNotSupportedException e) {
throw new SeriesException("Couldn't clone XYDataItem!");
}
existing.setY(y);
}
else {
// if the series is sorted, the negative index is a result from
// Collections.binarySearch() and tells us where to insert the
// new item...otherwise it will be just -1 and we should just
// append the value to the list...
if (this.autoSort) {
this.data.add(-index - 1, new XYDataItem(x, y));
}
else {
this.data.add(new XYDataItem(x, y));
}
// check if this addition will exceed the maximum item count...
if (getItemCount() > this.maximumItemCount) {
this.data.remove(0);
}
}
fireSeriesChanged();
return overwritten;
}
```
| public XYDataItem addOrUpdate(Number x, Number y) {
if (x == null) {
throw new IllegalArgumentException("Null 'x' argument.");
}
// if we get to here, we know that duplicate X values are not permitted
XYDataItem overwritten = null;
int index = indexOf(x);
if (index >= 0 && !this.allowDuplicateXValues) {
XYDataItem existing = (XYDataItem) this.data.get(index);
try {
overwritten = (XYDataItem) existing.clone();
}
catch (CloneNotSupportedException e) {
throw new SeriesException("Couldn't clone XYDataItem!");
}
existing.setY(y);
}
else {
// if the series is sorted, the negative index is a result from
// Collections.binarySearch() and tells us where to insert the
// new item...otherwise it will be just -1 and we should just
// append the value to the list...
if (this.autoSort) {
this.data.add(-index - 1, new XYDataItem(x, y));
}
else {
this.data.add(new XYDataItem(x, y));
}
// check if this addition will exceed the maximum item count...
if (getItemCount() > this.maximumItemCount) {
this.data.remove(0);
}
}
fireSeriesChanged();
return overwritten;
} | true | Chart | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Adds or updates an item in the series and sends a
* {@link SeriesChangeEvent} to all registered listeners.
*
* @param x the x-value (<code>null</code> not permitted).
* @param y the y-value (<code>null</code> permitted).
*
* @return A copy of the overwritten data item, or <code>null</code> if no
* item was overwritten.
*/
public XYDataItem addOrUpdate(Number x, Number y) {
if (x == null) {
throw new IllegalArgumentException("Null 'x' argument.");
}
// if we get to here, we know that duplicate X values are not permitted
XYDataItem overwritten = null;
int index = indexOf(x);
if (index >= 0 && !this.allowDuplicateXValues) {
XYDataItem existing = (XYDataItem) this.data.get(index);
try {
overwritten = (XYDataItem) existing.clone();
}
catch (CloneNotSupportedException e) {
throw new SeriesException("Couldn't clone XYDataItem!");
}
existing.setY(y);
}
else {
// if the series is sorted, the negative index is a result from
// Collections.binarySearch() and tells us where to insert the
// new item...otherwise it will be just -1 and we should just
// append the value to the list...
if (this.autoSort) {
this.data.add(-index - 1, new XYDataItem(x, y));
}
else {
this.data.add(new XYDataItem(x, y));
}
// check if this addition will exceed the maximum item count...
if (getItemCount() > this.maximumItemCount) {
this.data.remove(0);
}
}
fireSeriesChanged();
return overwritten;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
26 | 9186ad9bf517c3a3d79abee6e2900b51e4ed2500bf79d3a853e17ebd806b755e | @Override
public void feedInput(byte[] buf, int start, int end) throws IOException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public void feedInput(byte[] buf, int start, int end) throws IOException
{
// Must not have remaining input
if (_inputPtr < _inputEnd) {
_reportError("Still have %d undecoded bytes, should not call 'feedInput'", _inputEnd - _inputPtr);
}
if (end < start) {
_reportError("Input end (%d) may not be before start (%d)", end, start);
}
// and shouldn't have been marked as end-of-input
if (_endOfInput) {
_reportError("Already closed, can not feed more input");
}
// Time to update pointers first
_currInputProcessed += _origBufferLen;
// Also need to adjust row start, to work as if it extended into the past wrt new buffer
_currInputRowStart = start - (_inputEnd - _currInputRowStart);
// And then update buffer settings
_currBufferStart = start;
_inputBuffer = buf;
_inputPtr = start;
_inputEnd = end;
_origBufferLen = end - start;
}
```
| @Override
public void feedInput(byte[] buf, int start, int end) throws IOException
{
// Must not have remaining input
if (_inputPtr < _inputEnd) {
_reportError("Still have %d undecoded bytes, should not call 'feedInput'", _inputEnd - _inputPtr);
}
if (end < start) {
_reportError("Input end (%d) may not be before start (%d)", end, start);
}
// and shouldn't have been marked as end-of-input
if (_endOfInput) {
_reportError("Already closed, can not feed more input");
}
// Time to update pointers first
_currInputProcessed += _origBufferLen;
// Also need to adjust row start, to work as if it extended into the past wrt new buffer
_currInputRowStart = start - (_inputEnd - _currInputRowStart);
// And then update buffer settings
_currBufferStart = start;
_inputBuffer = buf;
_inputPtr = start;
_inputEnd = end;
_origBufferLen = end - start;
} | false | JacksonCore | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public void feedInput(byte[] buf, int start, int end) throws IOException
{
// Must not have remaining input
if (_inputPtr < _inputEnd) {
_reportError("Still have %d undecoded bytes, should not call 'feedInput'", _inputEnd - _inputPtr);
}
if (end < start) {
_reportError("Input end (%d) may not be before start (%d)", end, start);
}
// and shouldn't have been marked as end-of-input
if (_endOfInput) {
_reportError("Already closed, can not feed more input");
}
// Time to update pointers first
_currInputProcessed += _origBufferLen;
// Also need to adjust row start, to work as if it extended into the past wrt new buffer
_currInputRowStart = start - (_inputEnd - _currInputRowStart);
// And then update buffer settings
_currBufferStart = start;
_inputBuffer = buf;
_inputPtr = start;
_inputEnd = end;
_origBufferLen = end - start;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
34 | 929621d934e4081594fadef7f539706d0ddbbeb1f60bd362a5f82c37c8d4e3e5 | public void captureArgumentsFrom(Invocation i) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public void captureArgumentsFrom(Invocation i) {
int k = 0;
for (Matcher m : matchers) {
if (m instanceof CapturesArguments) {
((CapturesArguments) m).captureFrom(i.getArguments()[k]);
}
k++;
}
}
```
| public void captureArgumentsFrom(Invocation i) {
int k = 0;
for (Matcher m : matchers) {
if (m instanceof CapturesArguments) {
((CapturesArguments) m).captureFrom(i.getArguments()[k]);
}
k++;
}
} | true | Mockito | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public void captureArgumentsFrom(Invocation i) {
int k = 0;
for (Matcher m : matchers) {
if (m instanceof CapturesArguments) {
((CapturesArguments) m).captureFrom(i.getArguments()[k]);
}
k++;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
41 | 92b3c0ed8c0870c892514256ef3f38e9415d31248a1858aa3564081822b013dd | @Override
public boolean equals(Object o) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public boolean equals(Object o) {
if (this == o) return true;
if (o == null || getClass() != o.getClass()) return false;
if (!super.equals(o)) return false;
Element element = (Element) o;
return this == o;
}
```
| @Override
public boolean equals(Object o) {
if (this == o) return true;
if (o == null || getClass() != o.getClass()) return false;
if (!super.equals(o)) return false;
Element element = (Element) o;
return this == o;
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public boolean equals(Object o) {
if (this == o) return true;
if (o == null || getClass() != o.getClass()) return false;
if (!super.equals(o)) return false;
Element element = (Element) o;
return this == o;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
61 | 939316c49759d6833cc13661bf7fe4b603cc51edc19c70dfdee077c9bbaea8b4 | public int indexOf(String str, int startIndex) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Searches the string builder to find the first reference to the specified
* string starting searching from the given index.
* <p>
* Note that a null input string will return -1, whereas the JDK throws an exception.
*
* @param str the string to find, null returns -1
* @param startIndex the index to start at, invalid index rounded to edge
* @return the first index of the string, or -1 if not found
*/
public int indexOf(String str, int startIndex) {
startIndex = (startIndex < 0 ? 0 : startIndex);
if (str == null || startIndex >= size) {
return -1;
}
int strLen = str.length();
if (strLen == 1) {
return indexOf(str.charAt(0), startIndex);
}
if (strLen == 0) {
return startIndex;
}
if (strLen > size) {
return -1;
}
char[] thisBuf = buffer;
int len = thisBuf.length - strLen;
outer:
for (int i = startIndex; i < len; i++) {
for (int j = 0; j < strLen; j++) {
if (str.charAt(j) != thisBuf[i + j]) {
continue outer;
}
}
return i;
}
return -1;
}
```
| public int indexOf(String str, int startIndex) {
startIndex = (startIndex < 0 ? 0 : startIndex);
if (str == null || startIndex >= size) {
return -1;
}
int strLen = str.length();
if (strLen == 1) {
return indexOf(str.charAt(0), startIndex);
}
if (strLen == 0) {
return startIndex;
}
if (strLen > size) {
return -1;
}
char[] thisBuf = buffer;
int len = thisBuf.length - strLen;
outer:
for (int i = startIndex; i < len; i++) {
for (int j = 0; j < strLen; j++) {
if (str.charAt(j) != thisBuf[i + j]) {
continue outer;
}
}
return i;
}
return -1;
} | true | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Searches the string builder to find the first reference to the specified
* string starting searching from the given index.
* <p>
* Note that a null input string will return -1, whereas the JDK throws an exception.
*
* @param str the string to find, null returns -1
* @param startIndex the index to start at, invalid index rounded to edge
* @return the first index of the string, or -1 if not found
*/
public int indexOf(String str, int startIndex) {
startIndex = (startIndex < 0 ? 0 : startIndex);
if (str == null || startIndex >= size) {
return -1;
}
int strLen = str.length();
if (strLen == 1) {
return indexOf(str.charAt(0), startIndex);
}
if (strLen == 0) {
return startIndex;
}
if (strLen > size) {
return -1;
}
char[] thisBuf = buffer;
int len = thisBuf.length - strLen;
outer:
for (int i = startIndex; i < len; i++) {
for (int j = 0; j < strLen; j++) {
if (str.charAt(j) != thisBuf[i + j]) {
continue outer;
}
}
return i;
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
8 | 93fc0621e462501139cf21fb13fc5511be6870fafea89828a5f39fd119134f49 | private boolean compute(Object left, Object right) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private boolean compute(Object left, Object right) {
left = reduce(left);
right = reduce(right);
if (left instanceof InitialContext) {
((InitialContext) left).reset();
}
if (right instanceof InitialContext) {
((InitialContext) right).reset();
}
if (left instanceof Iterator && right instanceof Iterator) {
return findMatch((Iterator) left, (Iterator) right);
}
if (left instanceof Iterator) {
return containsMatch((Iterator) left, right);
}
if (right instanceof Iterator) {
return containsMatch((Iterator) right, left);
}
double ld = InfoSetUtil.doubleValue(left);
double rd = InfoSetUtil.doubleValue(right);
return evaluateCompare(ld == rd ? 0 : ld < rd ? -1 : 1);
}
```
| private boolean compute(Object left, Object right) {
left = reduce(left);
right = reduce(right);
if (left instanceof InitialContext) {
((InitialContext) left).reset();
}
if (right instanceof InitialContext) {
((InitialContext) right).reset();
}
if (left instanceof Iterator && right instanceof Iterator) {
return findMatch((Iterator) left, (Iterator) right);
}
if (left instanceof Iterator) {
return containsMatch((Iterator) left, right);
}
if (right instanceof Iterator) {
return containsMatch((Iterator) right, left);
}
double ld = InfoSetUtil.doubleValue(left);
double rd = InfoSetUtil.doubleValue(right);
return evaluateCompare(ld == rd ? 0 : ld < rd ? -1 : 1);
} | true | JxPath | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private boolean compute(Object left, Object right) {
left = reduce(left);
right = reduce(right);
if (left instanceof InitialContext) {
((InitialContext) left).reset();
}
if (right instanceof InitialContext) {
((InitialContext) right).reset();
}
if (left instanceof Iterator && right instanceof Iterator) {
return findMatch((Iterator) left, (Iterator) right);
}
if (left instanceof Iterator) {
return containsMatch((Iterator) left, right);
}
if (right instanceof Iterator) {
return containsMatch((Iterator) right, left);
}
double ld = InfoSetUtil.doubleValue(left);
double rd = InfoSetUtil.doubleValue(right);
return evaluateCompare(ld == rd ? 0 : ld < rd ? -1 : 1);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
16 | 941bc0dee0ebd741a74e4539f220688c805a260c89ffb558014de521d8bd11ec | public ArchiveInputStream createArchiveInputStream(final InputStream in)
throws ArchiveException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Create an archive input stream from an input stream, autodetecting
* the archive type from the first few bytes of the stream. The InputStream
* must support marks, like BufferedInputStream.
*
* @param in the input stream
* @return the archive input stream
* @throws ArchiveException if the archiver name is not known
* @throws IllegalArgumentException if the stream is null or does not support mark
*/
public ArchiveInputStream createArchiveInputStream(final InputStream in)
throws ArchiveException {
if (in == null) {
throw new IllegalArgumentException("Stream must not be null.");
}
if (!in.markSupported()) {
throw new IllegalArgumentException("Mark is not supported.");
}
final byte[] signature = new byte[12];
in.mark(signature.length);
try {
int signatureLength = in.read(signature);
in.reset();
if (ZipArchiveInputStream.matches(signature, signatureLength)) {
return new ZipArchiveInputStream(in);
} else if (JarArchiveInputStream.matches(signature, signatureLength)) {
return new JarArchiveInputStream(in);
} else if (ArArchiveInputStream.matches(signature, signatureLength)) {
return new ArArchiveInputStream(in);
} else if (CpioArchiveInputStream.matches(signature, signatureLength)) {
return new CpioArchiveInputStream(in);
}
// Dump needs a bigger buffer to check the signature;
final byte[] dumpsig = new byte[32];
in.mark(dumpsig.length);
signatureLength = in.read(dumpsig);
in.reset();
if (DumpArchiveInputStream.matches(dumpsig, signatureLength)) {
return new DumpArchiveInputStream(in);
}
// Tar needs an even bigger buffer to check the signature; read the first block
final byte[] tarheader = new byte[512];
in.mark(tarheader.length);
signatureLength = in.read(tarheader);
in.reset();
if (TarArchiveInputStream.matches(tarheader, signatureLength)) {
return new TarArchiveInputStream(in);
}
// COMPRESS-117 - improve auto-recognition
if (signatureLength >= 512) {
try {
TarArchiveInputStream tais = new TarArchiveInputStream(new ByteArrayInputStream(tarheader));
// COMPRESS-191 - verify the header checksum
tais.getNextEntry();
return new TarArchiveInputStream(in);
} catch (Exception e) { // NOPMD
// can generate IllegalArgumentException as well
// as IOException
// autodetection, simply not a TAR
// ignored
}
}
} catch (IOException e) {
throw new ArchiveException("Could not use reset and mark operations.", e);
}
throw new ArchiveException("No Archiver found for the stream signature");
}
```
| public ArchiveInputStream createArchiveInputStream(final InputStream in)
throws ArchiveException {
if (in == null) {
throw new IllegalArgumentException("Stream must not be null.");
}
if (!in.markSupported()) {
throw new IllegalArgumentException("Mark is not supported.");
}
final byte[] signature = new byte[12];
in.mark(signature.length);
try {
int signatureLength = in.read(signature);
in.reset();
if (ZipArchiveInputStream.matches(signature, signatureLength)) {
return new ZipArchiveInputStream(in);
} else if (JarArchiveInputStream.matches(signature, signatureLength)) {
return new JarArchiveInputStream(in);
} else if (ArArchiveInputStream.matches(signature, signatureLength)) {
return new ArArchiveInputStream(in);
} else if (CpioArchiveInputStream.matches(signature, signatureLength)) {
return new CpioArchiveInputStream(in);
}
// Dump needs a bigger buffer to check the signature;
final byte[] dumpsig = new byte[32];
in.mark(dumpsig.length);
signatureLength = in.read(dumpsig);
in.reset();
if (DumpArchiveInputStream.matches(dumpsig, signatureLength)) {
return new DumpArchiveInputStream(in);
}
// Tar needs an even bigger buffer to check the signature; read the first block
final byte[] tarheader = new byte[512];
in.mark(tarheader.length);
signatureLength = in.read(tarheader);
in.reset();
if (TarArchiveInputStream.matches(tarheader, signatureLength)) {
return new TarArchiveInputStream(in);
}
// COMPRESS-117 - improve auto-recognition
if (signatureLength >= 512) {
try {
TarArchiveInputStream tais = new TarArchiveInputStream(new ByteArrayInputStream(tarheader));
// COMPRESS-191 - verify the header checksum
tais.getNextEntry();
return new TarArchiveInputStream(in);
} catch (Exception e) { // NOPMD
// can generate IllegalArgumentException as well
// as IOException
// autodetection, simply not a TAR
// ignored
}
}
} catch (IOException e) {
throw new ArchiveException("Could not use reset and mark operations.", e);
}
throw new ArchiveException("No Archiver found for the stream signature");
} | true | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Create an archive input stream from an input stream, autodetecting
* the archive type from the first few bytes of the stream. The InputStream
* must support marks, like BufferedInputStream.
*
* @param in the input stream
* @return the archive input stream
* @throws ArchiveException if the archiver name is not known
* @throws IllegalArgumentException if the stream is null or does not support mark
*/
public ArchiveInputStream createArchiveInputStream(final InputStream in)
throws ArchiveException {
if (in == null) {
throw new IllegalArgumentException("Stream must not be null.");
}
if (!in.markSupported()) {
throw new IllegalArgumentException("Mark is not supported.");
}
final byte[] signature = new byte[12];
in.mark(signature.length);
try {
int signatureLength = in.read(signature);
in.reset();
if (ZipArchiveInputStream.matches(signature, signatureLength)) {
return new ZipArchiveInputStream(in);
} else if (JarArchiveInputStream.matches(signature, signatureLength)) {
return new JarArchiveInputStream(in);
} else if (ArArchiveInputStream.matches(signature, signatureLength)) {
return new ArArchiveInputStream(in);
} else if (CpioArchiveInputStream.matches(signature, signatureLength)) {
return new CpioArchiveInputStream(in);
}
// Dump needs a bigger buffer to check the signature;
final byte[] dumpsig = new byte[32];
in.mark(dumpsig.length);
signatureLength = in.read(dumpsig);
in.reset();
if (DumpArchiveInputStream.matches(dumpsig, signatureLength)) {
return new DumpArchiveInputStream(in);
}
// Tar needs an even bigger buffer to check the signature; read the first block
final byte[] tarheader = new byte[512];
in.mark(tarheader.length);
signatureLength = in.read(tarheader);
in.reset();
if (TarArchiveInputStream.matches(tarheader, signatureLength)) {
return new TarArchiveInputStream(in);
}
// COMPRESS-117 - improve auto-recognition
if (signatureLength >= 512) {
try {
TarArchiveInputStream tais = new TarArchiveInputStream(new ByteArrayInputStream(tarheader));
// COMPRESS-191 - verify the header checksum
tais.getNextEntry();
return new TarArchiveInputStream(in);
} catch (Exception e) { // NOPMD
// can generate IllegalArgumentException as well
// as IOException
// autodetection, simply not a TAR
// ignored
}
}
} catch (IOException e) {
throw new ArchiveException("Could not use reset and mark operations.", e);
}
throw new ArchiveException("No Archiver found for the stream signature");
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
19 | 94bb8ec294988761106a394d6c82fbac767ead8066553d920c32ef5c8f19b02f | public int getOffsetFromLocal(long instantLocal) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Gets the millisecond offset to subtract from local time to get UTC time.
* This offset can be used to undo adding the offset obtained by getOffset.
*
* <pre>
* millisLocal == millisUTC + getOffset(millisUTC)
* millisUTC == millisLocal - getOffsetFromLocal(millisLocal)
* </pre>
*
* NOTE: After calculating millisLocal, some error may be introduced. At
* offset transitions (due to DST or other historical changes), ranges of
* local times may map to different UTC times.
* <p>
* This method will return an offset suitable for calculating an instant
* after any DST gap. For example, consider a zone with a cutover
* from 01:00 to 01:59:<br />
* Input: 00:00 Output: 00:00<br />
* Input: 00:30 Output: 00:30<br />
* Input: 01:00 Output: 02:00<br />
* Input: 01:30 Output: 02:30<br />
* Input: 02:00 Output: 02:00<br />
* Input: 02:30 Output: 02:30<br />
* <p>
* During a DST overlap (where the local time is ambiguous) this method will return
* the earlier instant. The combination of these two rules is to always favour
* daylight (summer) time over standard (winter) time.
* <p>
* NOTE: Prior to v2.0, the DST overlap behaviour was not defined and varied by hemisphere.
* Prior to v1.5, the DST gap behaviour was also not defined.
*
* @param instantLocal the millisecond instant, relative to this time zone, to get the offset for
* @return the millisecond offset to subtract from local time to get UTC time
*/
public int getOffsetFromLocal(long instantLocal) {
// get the offset at instantLocal (first estimate)
final int offsetLocal = getOffset(instantLocal);
// adjust instantLocal using the estimate and recalc the offset
final long instantAdjusted = instantLocal - offsetLocal;
final int offsetAdjusted = getOffset(instantAdjusted);
// if the offsets differ, we must be near a DST boundary
if (offsetLocal != offsetAdjusted) {
// we need to ensure that time is always after the DST gap
// this happens naturally for positive offsets, but not for negative
if ((offsetLocal - offsetAdjusted) < 0) {
// if we just return offsetAdjusted then the time is pushed
// back before the transition, whereas it should be
// on or after the transition
long nextLocal = nextTransition(instantAdjusted);
long nextAdjusted = nextTransition(instantLocal - offsetAdjusted);
if (nextLocal != nextAdjusted) {
return offsetLocal;
}
}
} else if (offsetLocal > 0) {
long prev = previousTransition(instantAdjusted);
if (prev < instantAdjusted) {
int offsetPrev = getOffset(prev);
int diff = offsetPrev - offsetLocal;
if (instantAdjusted - prev <= diff) {
return offsetPrev;
}
}
}
return offsetAdjusted;
}
```
| public int getOffsetFromLocal(long instantLocal) {
// get the offset at instantLocal (first estimate)
final int offsetLocal = getOffset(instantLocal);
// adjust instantLocal using the estimate and recalc the offset
final long instantAdjusted = instantLocal - offsetLocal;
final int offsetAdjusted = getOffset(instantAdjusted);
// if the offsets differ, we must be near a DST boundary
if (offsetLocal != offsetAdjusted) {
// we need to ensure that time is always after the DST gap
// this happens naturally for positive offsets, but not for negative
if ((offsetLocal - offsetAdjusted) < 0) {
// if we just return offsetAdjusted then the time is pushed
// back before the transition, whereas it should be
// on or after the transition
long nextLocal = nextTransition(instantAdjusted);
long nextAdjusted = nextTransition(instantLocal - offsetAdjusted);
if (nextLocal != nextAdjusted) {
return offsetLocal;
}
}
} else if (offsetLocal > 0) {
long prev = previousTransition(instantAdjusted);
if (prev < instantAdjusted) {
int offsetPrev = getOffset(prev);
int diff = offsetPrev - offsetLocal;
if (instantAdjusted - prev <= diff) {
return offsetPrev;
}
}
}
return offsetAdjusted;
} | true | Time | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Gets the millisecond offset to subtract from local time to get UTC time.
* This offset can be used to undo adding the offset obtained by getOffset.
*
* <pre>
* millisLocal == millisUTC + getOffset(millisUTC)
* millisUTC == millisLocal - getOffsetFromLocal(millisLocal)
* </pre>
*
* NOTE: After calculating millisLocal, some error may be introduced. At
* offset transitions (due to DST or other historical changes), ranges of
* local times may map to different UTC times.
* <p>
* This method will return an offset suitable for calculating an instant
* after any DST gap. For example, consider a zone with a cutover
* from 01:00 to 01:59:<br />
* Input: 00:00 Output: 00:00<br />
* Input: 00:30 Output: 00:30<br />
* Input: 01:00 Output: 02:00<br />
* Input: 01:30 Output: 02:30<br />
* Input: 02:00 Output: 02:00<br />
* Input: 02:30 Output: 02:30<br />
* <p>
* During a DST overlap (where the local time is ambiguous) this method will return
* the earlier instant. The combination of these two rules is to always favour
* daylight (summer) time over standard (winter) time.
* <p>
* NOTE: Prior to v2.0, the DST overlap behaviour was not defined and varied by hemisphere.
* Prior to v1.5, the DST gap behaviour was also not defined.
*
* @param instantLocal the millisecond instant, relative to this time zone, to get the offset for
* @return the millisecond offset to subtract from local time to get UTC time
*/
public int getOffsetFromLocal(long instantLocal) {
// get the offset at instantLocal (first estimate)
final int offsetLocal = getOffset(instantLocal);
// adjust instantLocal using the estimate and recalc the offset
final long instantAdjusted = instantLocal - offsetLocal;
final int offsetAdjusted = getOffset(instantAdjusted);
// if the offsets differ, we must be near a DST boundary
if (offsetLocal != offsetAdjusted) {
// we need to ensure that time is always after the DST gap
// this happens naturally for positive offsets, but not for negative
if ((offsetLocal - offsetAdjusted) < 0) {
// if we just return offsetAdjusted then the time is pushed
// back before the transition, whereas it should be
// on or after the transition
long nextLocal = nextTransition(instantAdjusted);
long nextAdjusted = nextTransition(instantLocal - offsetAdjusted);
if (nextLocal != nextAdjusted) {
return offsetLocal;
}
}
} else if (offsetLocal > 0) {
long prev = previousTransition(instantAdjusted);
if (prev < instantAdjusted) {
int offsetPrev = getOffset(prev);
int diff = offsetPrev - offsetLocal;
if (instantAdjusted - prev <= diff) {
return offsetPrev;
}
}
}
return offsetAdjusted;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
25 | 94bb8ec294988761106a394d6c82fbac767ead8066553d920c32ef5c8f19b02f | public int getOffsetFromLocal(long instantLocal) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Gets the millisecond offset to subtract from local time to get UTC time.
* This offset can be used to undo adding the offset obtained by getOffset.
*
* <pre>
* millisLocal == millisUTC + getOffset(millisUTC)
* millisUTC == millisLocal - getOffsetFromLocal(millisLocal)
* </pre>
*
* NOTE: After calculating millisLocal, some error may be introduced. At
* offset transitions (due to DST or other historical changes), ranges of
* local times may map to different UTC times.
* <p>
* This method will return an offset suitable for calculating an instant
* after any DST gap. For example, consider a zone with a cutover
* from 01:00 to 01:59:<br />
* Input: 00:00 Output: 00:00<br />
* Input: 00:30 Output: 00:30<br />
* Input: 01:00 Output: 02:00<br />
* Input: 01:30 Output: 02:30<br />
* Input: 02:00 Output: 02:00<br />
* Input: 02:30 Output: 02:30<br />
* <p>
* During a DST overlap (where the local time is ambiguous) this method will return
* the earlier instant. The combination of these two rules is to always favour
* daylight (summer) time over standard (winter) time.
* <p>
* NOTE: Prior to v2.0, the DST overlap behaviour was not defined and varied by hemisphere.
* Prior to v1.5, the DST gap behaviour was also not defined.
*
* @param instantLocal the millisecond instant, relative to this time zone, to get the offset for
* @return the millisecond offset to subtract from local time to get UTC time
*/
public int getOffsetFromLocal(long instantLocal) {
// get the offset at instantLocal (first estimate)
final int offsetLocal = getOffset(instantLocal);
// adjust instantLocal using the estimate and recalc the offset
final long instantAdjusted = instantLocal - offsetLocal;
final int offsetAdjusted = getOffset(instantAdjusted);
// if the offsets differ, we must be near a DST boundary
if (offsetLocal != offsetAdjusted) {
// we need to ensure that time is always after the DST gap
// this happens naturally for positive offsets, but not for negative
if ((offsetLocal - offsetAdjusted) < 0) {
// if we just return offsetAdjusted then the time is pushed
// back before the transition, whereas it should be
// on or after the transition
long nextLocal = nextTransition(instantAdjusted);
long nextAdjusted = nextTransition(instantLocal - offsetAdjusted);
if (nextLocal != nextAdjusted) {
return offsetLocal;
}
}
} else if (offsetLocal > 0) {
long prev = previousTransition(instantAdjusted);
if (prev < instantAdjusted) {
int offsetPrev = getOffset(prev);
int diff = offsetPrev - offsetLocal;
if (instantAdjusted - prev <= diff) {
return offsetPrev;
}
}
}
return offsetAdjusted;
}
```
| public int getOffsetFromLocal(long instantLocal) {
// get the offset at instantLocal (first estimate)
final int offsetLocal = getOffset(instantLocal);
// adjust instantLocal using the estimate and recalc the offset
final long instantAdjusted = instantLocal - offsetLocal;
final int offsetAdjusted = getOffset(instantAdjusted);
// if the offsets differ, we must be near a DST boundary
if (offsetLocal != offsetAdjusted) {
// we need to ensure that time is always after the DST gap
// this happens naturally for positive offsets, but not for negative
if ((offsetLocal - offsetAdjusted) < 0) {
// if we just return offsetAdjusted then the time is pushed
// back before the transition, whereas it should be
// on or after the transition
long nextLocal = nextTransition(instantAdjusted);
long nextAdjusted = nextTransition(instantLocal - offsetAdjusted);
if (nextLocal != nextAdjusted) {
return offsetLocal;
}
}
} else if (offsetLocal > 0) {
long prev = previousTransition(instantAdjusted);
if (prev < instantAdjusted) {
int offsetPrev = getOffset(prev);
int diff = offsetPrev - offsetLocal;
if (instantAdjusted - prev <= diff) {
return offsetPrev;
}
}
}
return offsetAdjusted;
} | false | Time | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Gets the millisecond offset to subtract from local time to get UTC time.
* This offset can be used to undo adding the offset obtained by getOffset.
*
* <pre>
* millisLocal == millisUTC + getOffset(millisUTC)
* millisUTC == millisLocal - getOffsetFromLocal(millisLocal)
* </pre>
*
* NOTE: After calculating millisLocal, some error may be introduced. At
* offset transitions (due to DST or other historical changes), ranges of
* local times may map to different UTC times.
* <p>
* This method will return an offset suitable for calculating an instant
* after any DST gap. For example, consider a zone with a cutover
* from 01:00 to 01:59:<br />
* Input: 00:00 Output: 00:00<br />
* Input: 00:30 Output: 00:30<br />
* Input: 01:00 Output: 02:00<br />
* Input: 01:30 Output: 02:30<br />
* Input: 02:00 Output: 02:00<br />
* Input: 02:30 Output: 02:30<br />
* <p>
* During a DST overlap (where the local time is ambiguous) this method will return
* the earlier instant. The combination of these two rules is to always favour
* daylight (summer) time over standard (winter) time.
* <p>
* NOTE: Prior to v2.0, the DST overlap behaviour was not defined and varied by hemisphere.
* Prior to v1.5, the DST gap behaviour was also not defined.
*
* @param instantLocal the millisecond instant, relative to this time zone, to get the offset for
* @return the millisecond offset to subtract from local time to get UTC time
*/
public int getOffsetFromLocal(long instantLocal) {
// get the offset at instantLocal (first estimate)
final int offsetLocal = getOffset(instantLocal);
// adjust instantLocal using the estimate and recalc the offset
final long instantAdjusted = instantLocal - offsetLocal;
final int offsetAdjusted = getOffset(instantAdjusted);
// if the offsets differ, we must be near a DST boundary
if (offsetLocal != offsetAdjusted) {
// we need to ensure that time is always after the DST gap
// this happens naturally for positive offsets, but not for negative
if ((offsetLocal - offsetAdjusted) < 0) {
// if we just return offsetAdjusted then the time is pushed
// back before the transition, whereas it should be
// on or after the transition
long nextLocal = nextTransition(instantAdjusted);
long nextAdjusted = nextTransition(instantLocal - offsetAdjusted);
if (nextLocal != nextAdjusted) {
return offsetLocal;
}
}
} else if (offsetLocal > 0) {
long prev = previousTransition(instantAdjusted);
if (prev < instantAdjusted) {
int offsetPrev = getOffset(prev);
int diff = offsetPrev - offsetLocal;
if (instantAdjusted - prev <= diff) {
return offsetPrev;
}
}
}
return offsetAdjusted;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
97 | 9528c8c6779fe439ef84eb733efb6d22e2d9f8686128203c4c4933d222f4b060 | private Node tryFoldShift(Node n, Node left, Node right) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Try to fold shift operations
*/
private Node tryFoldShift(Node n, Node left, Node right) {
if (left.getType() == Token.NUMBER &&
right.getType() == Token.NUMBER) {
double result;
double lval = left.getDouble();
double rval = right.getDouble();
// check ranges. We do not do anything that would clip the double to
// a 32-bit range, since the user likely does not intend that.
if (!(lval >= Integer.MIN_VALUE && lval <= Integer.MAX_VALUE)) {
error(BITWISE_OPERAND_OUT_OF_RANGE, left);
return n;
}
// only the lower 5 bits are used when shifting, so don't do anything
// if the shift amount is outside [0,32)
if (!(rval >= 0 && rval < 32)) {
error(SHIFT_AMOUNT_OUT_OF_BOUNDS, right);
return n;
}
// Convert the numbers to ints
int lvalInt = (int) lval;
if (lvalInt != lval) {
error(FRACTIONAL_BITWISE_OPERAND, left);
return n;
}
int rvalInt = (int) rval;
if (rvalInt != rval) {
error(FRACTIONAL_BITWISE_OPERAND, right);
return n;
}
switch (n.getType()) {
case Token.LSH:
result = lvalInt << rvalInt;
break;
case Token.RSH:
result = lvalInt >> rvalInt;
break;
case Token.URSH:
// JavaScript handles zero shifts on signed numbers differently than
// Java as an Java int can not represent the unsigned 32-bit number
// where JavaScript can so use a long here.
long lvalLong = lvalInt & 0xffffffffL;
result = lvalLong >>> rvalInt;
break;
default:
throw new AssertionError("Unknown shift operator: " +
Node.tokenToName(n.getType()));
}
Node newNumber = Node.newNumber(result);
n.getParent().replaceChild(n, newNumber);
reportCodeChange();
return newNumber;
}
return n;
}
```
| private Node tryFoldShift(Node n, Node left, Node right) {
if (left.getType() == Token.NUMBER &&
right.getType() == Token.NUMBER) {
double result;
double lval = left.getDouble();
double rval = right.getDouble();
// check ranges. We do not do anything that would clip the double to
// a 32-bit range, since the user likely does not intend that.
if (!(lval >= Integer.MIN_VALUE && lval <= Integer.MAX_VALUE)) {
error(BITWISE_OPERAND_OUT_OF_RANGE, left);
return n;
}
// only the lower 5 bits are used when shifting, so don't do anything
// if the shift amount is outside [0,32)
if (!(rval >= 0 && rval < 32)) {
error(SHIFT_AMOUNT_OUT_OF_BOUNDS, right);
return n;
}
// Convert the numbers to ints
int lvalInt = (int) lval;
if (lvalInt != lval) {
error(FRACTIONAL_BITWISE_OPERAND, left);
return n;
}
int rvalInt = (int) rval;
if (rvalInt != rval) {
error(FRACTIONAL_BITWISE_OPERAND, right);
return n;
}
switch (n.getType()) {
case Token.LSH:
result = lvalInt << rvalInt;
break;
case Token.RSH:
result = lvalInt >> rvalInt;
break;
case Token.URSH:
// JavaScript handles zero shifts on signed numbers differently than
// Java as an Java int can not represent the unsigned 32-bit number
// where JavaScript can so use a long here.
long lvalLong = lvalInt & 0xffffffffL;
result = lvalLong >>> rvalInt;
break;
default:
throw new AssertionError("Unknown shift operator: " +
Node.tokenToName(n.getType()));
}
Node newNumber = Node.newNumber(result);
n.getParent().replaceChild(n, newNumber);
reportCodeChange();
return newNumber;
}
return n;
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Try to fold shift operations
*/
private Node tryFoldShift(Node n, Node left, Node right) {
if (left.getType() == Token.NUMBER &&
right.getType() == Token.NUMBER) {
double result;
double lval = left.getDouble();
double rval = right.getDouble();
// check ranges. We do not do anything that would clip the double to
// a 32-bit range, since the user likely does not intend that.
if (!(lval >= Integer.MIN_VALUE && lval <= Integer.MAX_VALUE)) {
error(BITWISE_OPERAND_OUT_OF_RANGE, left);
return n;
}
// only the lower 5 bits are used when shifting, so don't do anything
// if the shift amount is outside [0,32)
if (!(rval >= 0 && rval < 32)) {
error(SHIFT_AMOUNT_OUT_OF_BOUNDS, right);
return n;
}
// Convert the numbers to ints
int lvalInt = (int) lval;
if (lvalInt != lval) {
error(FRACTIONAL_BITWISE_OPERAND, left);
return n;
}
int rvalInt = (int) rval;
if (rvalInt != rval) {
error(FRACTIONAL_BITWISE_OPERAND, right);
return n;
}
switch (n.getType()) {
case Token.LSH:
result = lvalInt << rvalInt;
break;
case Token.RSH:
result = lvalInt >> rvalInt;
break;
case Token.URSH:
// JavaScript handles zero shifts on signed numbers differently than
// Java as an Java int can not represent the unsigned 32-bit number
// where JavaScript can so use a long here.
long lvalLong = lvalInt & 0xffffffffL;
result = lvalLong >>> rvalInt;
break;
default:
throw new AssertionError("Unknown shift operator: " +
Node.tokenToName(n.getType()));
}
Node newNumber = Node.newNumber(result);
n.getParent().replaceChild(n, newNumber);
reportCodeChange();
return newNumber;
}
return n;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
13 | 9621e9bf3e23d0cdc29ceea7626c90fc231a68ab91405783c894730b4c919d5e | private int peekNumber() throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private int peekNumber() throws IOException {
// Like nextNonWhitespace, this uses locals 'p' and 'l' to save inner-loop field access.
char[] buffer = this.buffer;
int p = pos;
int l = limit;
long value = 0; // Negative to accommodate Long.MIN_VALUE more easily.
boolean negative = false;
boolean fitsInLong = true;
int last = NUMBER_CHAR_NONE;
int i = 0;
charactersOfNumber:
for (; true; i++) {
if (p + i == l) {
if (i == buffer.length) {
// Though this looks like a well-formed number, it's too long to continue reading. Give up
// and let the application handle this as an unquoted literal.
return PEEKED_NONE;
}
if (!fillBuffer(i + 1)) {
break;
}
p = pos;
l = limit;
}
char c = buffer[p + i];
switch (c) {
case '-':
if (last == NUMBER_CHAR_NONE) {
negative = true;
last = NUMBER_CHAR_SIGN;
continue;
} else if (last == NUMBER_CHAR_EXP_E) {
last = NUMBER_CHAR_EXP_SIGN;
continue;
}
return PEEKED_NONE;
case '+':
if (last == NUMBER_CHAR_EXP_E) {
last = NUMBER_CHAR_EXP_SIGN;
continue;
}
return PEEKED_NONE;
case 'e':
case 'E':
if (last == NUMBER_CHAR_DIGIT || last == NUMBER_CHAR_FRACTION_DIGIT) {
last = NUMBER_CHAR_EXP_E;
continue;
}
return PEEKED_NONE;
case '.':
if (last == NUMBER_CHAR_DIGIT) {
last = NUMBER_CHAR_DECIMAL;
continue;
}
return PEEKED_NONE;
default:
if (c < '0' || c > '9') {
if (!isLiteral(c)) {
break charactersOfNumber;
}
return PEEKED_NONE;
}
if (last == NUMBER_CHAR_SIGN || last == NUMBER_CHAR_NONE) {
value = -(c - '0');
last = NUMBER_CHAR_DIGIT;
} else if (last == NUMBER_CHAR_DIGIT) {
if (value == 0) {
return PEEKED_NONE; // Leading '0' prefix is not allowed (since it could be octal).
}
long newValue = value * 10 - (c - '0');
fitsInLong &= value > MIN_INCOMPLETE_INTEGER
|| (value == MIN_INCOMPLETE_INTEGER && newValue < value);
value = newValue;
} else if (last == NUMBER_CHAR_DECIMAL) {
last = NUMBER_CHAR_FRACTION_DIGIT;
} else if (last == NUMBER_CHAR_EXP_E || last == NUMBER_CHAR_EXP_SIGN) {
last = NUMBER_CHAR_EXP_DIGIT;
}
}
}
// We've read a complete number. Decide if it's a PEEKED_LONG or a PEEKED_NUMBER.
if (last == NUMBER_CHAR_DIGIT && fitsInLong && (value != Long.MIN_VALUE || negative) && (value!=0 || false==negative)) {
peekedLong = negative ? value : -value;
pos += i;
return peeked = PEEKED_LONG;
} else if (last == NUMBER_CHAR_DIGIT || last == NUMBER_CHAR_FRACTION_DIGIT
|| last == NUMBER_CHAR_EXP_DIGIT) {
peekedNumberLength = i;
return peeked = PEEKED_NUMBER;
} else {
return PEEKED_NONE;
}
}
```
| private int peekNumber() throws IOException {
// Like nextNonWhitespace, this uses locals 'p' and 'l' to save inner-loop field access.
char[] buffer = this.buffer;
int p = pos;
int l = limit;
long value = 0; // Negative to accommodate Long.MIN_VALUE more easily.
boolean negative = false;
boolean fitsInLong = true;
int last = NUMBER_CHAR_NONE;
int i = 0;
charactersOfNumber:
for (; true; i++) {
if (p + i == l) {
if (i == buffer.length) {
// Though this looks like a well-formed number, it's too long to continue reading. Give up
// and let the application handle this as an unquoted literal.
return PEEKED_NONE;
}
if (!fillBuffer(i + 1)) {
break;
}
p = pos;
l = limit;
}
char c = buffer[p + i];
switch (c) {
case '-':
if (last == NUMBER_CHAR_NONE) {
negative = true;
last = NUMBER_CHAR_SIGN;
continue;
} else if (last == NUMBER_CHAR_EXP_E) {
last = NUMBER_CHAR_EXP_SIGN;
continue;
}
return PEEKED_NONE;
case '+':
if (last == NUMBER_CHAR_EXP_E) {
last = NUMBER_CHAR_EXP_SIGN;
continue;
}
return PEEKED_NONE;
case 'e':
case 'E':
if (last == NUMBER_CHAR_DIGIT || last == NUMBER_CHAR_FRACTION_DIGIT) {
last = NUMBER_CHAR_EXP_E;
continue;
}
return PEEKED_NONE;
case '.':
if (last == NUMBER_CHAR_DIGIT) {
last = NUMBER_CHAR_DECIMAL;
continue;
}
return PEEKED_NONE;
default:
if (c < '0' || c > '9') {
if (!isLiteral(c)) {
break charactersOfNumber;
}
return PEEKED_NONE;
}
if (last == NUMBER_CHAR_SIGN || last == NUMBER_CHAR_NONE) {
value = -(c - '0');
last = NUMBER_CHAR_DIGIT;
} else if (last == NUMBER_CHAR_DIGIT) {
if (value == 0) {
return PEEKED_NONE; // Leading '0' prefix is not allowed (since it could be octal).
}
long newValue = value * 10 - (c - '0');
fitsInLong &= value > MIN_INCOMPLETE_INTEGER
|| (value == MIN_INCOMPLETE_INTEGER && newValue < value);
value = newValue;
} else if (last == NUMBER_CHAR_DECIMAL) {
last = NUMBER_CHAR_FRACTION_DIGIT;
} else if (last == NUMBER_CHAR_EXP_E || last == NUMBER_CHAR_EXP_SIGN) {
last = NUMBER_CHAR_EXP_DIGIT;
}
}
}
// We've read a complete number. Decide if it's a PEEKED_LONG or a PEEKED_NUMBER.
if (last == NUMBER_CHAR_DIGIT && fitsInLong && (value != Long.MIN_VALUE || negative) && (value!=0 || false==negative)) {
peekedLong = negative ? value : -value;
pos += i;
return peeked = PEEKED_LONG;
} else if (last == NUMBER_CHAR_DIGIT || last == NUMBER_CHAR_FRACTION_DIGIT
|| last == NUMBER_CHAR_EXP_DIGIT) {
peekedNumberLength = i;
return peeked = PEEKED_NUMBER;
} else {
return PEEKED_NONE;
}
} | false | Gson | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private int peekNumber() throws IOException {
// Like nextNonWhitespace, this uses locals 'p' and 'l' to save inner-loop field access.
char[] buffer = this.buffer;
int p = pos;
int l = limit;
long value = 0; // Negative to accommodate Long.MIN_VALUE more easily.
boolean negative = false;
boolean fitsInLong = true;
int last = NUMBER_CHAR_NONE;
int i = 0;
charactersOfNumber:
for (; true; i++) {
if (p + i == l) {
if (i == buffer.length) {
// Though this looks like a well-formed number, it's too long to continue reading. Give up
// and let the application handle this as an unquoted literal.
return PEEKED_NONE;
}
if (!fillBuffer(i + 1)) {
break;
}
p = pos;
l = limit;
}
char c = buffer[p + i];
switch (c) {
case '-':
if (last == NUMBER_CHAR_NONE) {
negative = true;
last = NUMBER_CHAR_SIGN;
continue;
} else if (last == NUMBER_CHAR_EXP_E) {
last = NUMBER_CHAR_EXP_SIGN;
continue;
}
return PEEKED_NONE;
case '+':
if (last == NUMBER_CHAR_EXP_E) {
last = NUMBER_CHAR_EXP_SIGN;
continue;
}
return PEEKED_NONE;
case 'e':
case 'E':
if (last == NUMBER_CHAR_DIGIT || last == NUMBER_CHAR_FRACTION_DIGIT) {
last = NUMBER_CHAR_EXP_E;
continue;
}
return PEEKED_NONE;
case '.':
if (last == NUMBER_CHAR_DIGIT) {
last = NUMBER_CHAR_DECIMAL;
continue;
}
return PEEKED_NONE;
default:
if (c < '0' || c > '9') {
if (!isLiteral(c)) {
break charactersOfNumber;
}
return PEEKED_NONE;
}
if (last == NUMBER_CHAR_SIGN || last == NUMBER_CHAR_NONE) {
value = -(c - '0');
last = NUMBER_CHAR_DIGIT;
} else if (last == NUMBER_CHAR_DIGIT) {
if (value == 0) {
return PEEKED_NONE; // Leading '0' prefix is not allowed (since it could be octal).
}
long newValue = value * 10 - (c - '0');
fitsInLong &= value > MIN_INCOMPLETE_INTEGER
|| (value == MIN_INCOMPLETE_INTEGER && newValue < value);
value = newValue;
} else if (last == NUMBER_CHAR_DECIMAL) {
last = NUMBER_CHAR_FRACTION_DIGIT;
} else if (last == NUMBER_CHAR_EXP_E || last == NUMBER_CHAR_EXP_SIGN) {
last = NUMBER_CHAR_EXP_DIGIT;
}
}
}
// We've read a complete number. Decide if it's a PEEKED_LONG or a PEEKED_NUMBER.
if (last == NUMBER_CHAR_DIGIT && fitsInLong && (value != Long.MIN_VALUE || negative) && (value!=0 || false==negative)) {
peekedLong = negative ? value : -value;
pos += i;
return peeked = PEEKED_LONG;
} else if (last == NUMBER_CHAR_DIGIT || last == NUMBER_CHAR_FRACTION_DIGIT
|| last == NUMBER_CHAR_EXP_DIGIT) {
peekedNumberLength = i;
return peeked = PEEKED_NUMBER;
} else {
return PEEKED_NONE;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
9 | 96406756201f4c1c4247a0d73b25acfc868f37509322949e41d68a0f79e9a5db | public TimeSeries createCopy(RegularTimePeriod start, RegularTimePeriod end)
throws CloneNotSupportedException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Creates a new timeseries by copying a subset of the data in this time
* series.
*
* @param start the first time period to copy (<code>null</code> not
* permitted).
* @param end the last time period to copy (<code>null</code> not
* permitted).
*
* @return A time series containing a copy of this time series from start
* until end.
*
* @throws CloneNotSupportedException if there is a cloning problem.
*/
public TimeSeries createCopy(RegularTimePeriod start, RegularTimePeriod end)
throws CloneNotSupportedException {
if (start == null) {
throw new IllegalArgumentException("Null 'start' argument.");
}
if (end == null) {
throw new IllegalArgumentException("Null 'end' argument.");
}
if (start.compareTo(end) > 0) {
throw new IllegalArgumentException(
"Requires start on or before end.");
}
boolean emptyRange = false;
int startIndex = getIndex(start);
if (startIndex < 0) {
startIndex = -(startIndex + 1);
if (startIndex == this.data.size()) {
emptyRange = true; // start is after last data item
}
}
int endIndex = getIndex(end);
if (endIndex < 0) { // end period is not in original series
endIndex = -(endIndex + 1); // this is first item AFTER end period
endIndex = endIndex - 1; // so this is last item BEFORE end
}
if ((endIndex < 0) || (endIndex < startIndex)) {
emptyRange = true;
}
if (emptyRange) {
TimeSeries copy = (TimeSeries) super.clone();
copy.data = new java.util.ArrayList();
return copy;
}
else {
return createCopy(startIndex, endIndex);
}
}
```
| public TimeSeries createCopy(RegularTimePeriod start, RegularTimePeriod end)
throws CloneNotSupportedException {
if (start == null) {
throw new IllegalArgumentException("Null 'start' argument.");
}
if (end == null) {
throw new IllegalArgumentException("Null 'end' argument.");
}
if (start.compareTo(end) > 0) {
throw new IllegalArgumentException(
"Requires start on or before end.");
}
boolean emptyRange = false;
int startIndex = getIndex(start);
if (startIndex < 0) {
startIndex = -(startIndex + 1);
if (startIndex == this.data.size()) {
emptyRange = true; // start is after last data item
}
}
int endIndex = getIndex(end);
if (endIndex < 0) { // end period is not in original series
endIndex = -(endIndex + 1); // this is first item AFTER end period
endIndex = endIndex - 1; // so this is last item BEFORE end
}
if ((endIndex < 0) || (endIndex < startIndex)) {
emptyRange = true;
}
if (emptyRange) {
TimeSeries copy = (TimeSeries) super.clone();
copy.data = new java.util.ArrayList();
return copy;
}
else {
return createCopy(startIndex, endIndex);
}
} | false | Chart | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Creates a new timeseries by copying a subset of the data in this time
* series.
*
* @param start the first time period to copy (<code>null</code> not
* permitted).
* @param end the last time period to copy (<code>null</code> not
* permitted).
*
* @return A time series containing a copy of this time series from start
* until end.
*
* @throws CloneNotSupportedException if there is a cloning problem.
*/
public TimeSeries createCopy(RegularTimePeriod start, RegularTimePeriod end)
throws CloneNotSupportedException {
if (start == null) {
throw new IllegalArgumentException("Null 'start' argument.");
}
if (end == null) {
throw new IllegalArgumentException("Null 'end' argument.");
}
if (start.compareTo(end) > 0) {
throw new IllegalArgumentException(
"Requires start on or before end.");
}
boolean emptyRange = false;
int startIndex = getIndex(start);
if (startIndex < 0) {
startIndex = -(startIndex + 1);
if (startIndex == this.data.size()) {
emptyRange = true; // start is after last data item
}
}
int endIndex = getIndex(end);
if (endIndex < 0) { // end period is not in original series
endIndex = -(endIndex + 1); // this is first item AFTER end period
endIndex = endIndex - 1; // so this is last item BEFORE end
}
if ((endIndex < 0) || (endIndex < startIndex)) {
emptyRange = true;
}
if (emptyRange) {
TimeSeries copy = (TimeSeries) super.clone();
copy.data = new java.util.ArrayList();
return copy;
}
else {
return createCopy(startIndex, endIndex);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
107 | 96b833cdadea17125d95c84aad869578945d7985710771289a5aff35936c891f | @Override
protected CompilerOptions createOptions() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
protected CompilerOptions createOptions() {
CompilerOptions options = new CompilerOptions();
if (flags.processJqueryPrimitives) {
options.setCodingConvention(new JqueryCodingConvention());
} else {
options.setCodingConvention(new ClosureCodingConvention());
}
options.setExtraAnnotationNames(flags.extraAnnotationName);
CompilationLevel level = flags.compilationLevel;
level.setOptionsForCompilationLevel(options);
if (flags.debug) {
level.setDebugOptionsForCompilationLevel(options);
}
if (flags.useTypesForOptimization) {
level.setTypeBasedOptimizationOptions(options);
}
if (flags.generateExports) {
options.setGenerateExports(flags.generateExports);
}
WarningLevel wLevel = flags.warningLevel;
wLevel.setOptionsForWarningLevel(options);
for (FormattingOption formattingOption : flags.formatting) {
formattingOption.applyToOptions(options);
}
options.closurePass = flags.processClosurePrimitives;
options.jqueryPass = CompilationLevel.ADVANCED_OPTIMIZATIONS == level &&
flags.processJqueryPrimitives;
options.angularPass = flags.angularPass;
if (!flags.translationsFile.isEmpty()) {
try {
options.messageBundle = new XtbMessageBundle(
new FileInputStream(flags.translationsFile),
flags.translationsProject);
} catch (IOException e) {
throw new RuntimeException("Reading XTB file", e);
}
} else if (CompilationLevel.ADVANCED_OPTIMIZATIONS == level) {
// In SIMPLE or WHITESPACE mode, if the user hasn't specified a
// translations file, they might reasonably try to write their own
// implementation of goog.getMsg that makes the substitution at
// run-time.
//
// In ADVANCED mode, goog.getMsg is going to be renamed anyway,
// so we might as well inline it. But shut off the i18n warnings,
// because the user didn't really ask for i18n.
options.messageBundle = new EmptyMessageBundle();
options.setWarningLevel(JsMessageVisitor.MSG_CONVENTIONS, CheckLevel.OFF);
}
return options;
}
```
| @Override
protected CompilerOptions createOptions() {
CompilerOptions options = new CompilerOptions();
if (flags.processJqueryPrimitives) {
options.setCodingConvention(new JqueryCodingConvention());
} else {
options.setCodingConvention(new ClosureCodingConvention());
}
options.setExtraAnnotationNames(flags.extraAnnotationName);
CompilationLevel level = flags.compilationLevel;
level.setOptionsForCompilationLevel(options);
if (flags.debug) {
level.setDebugOptionsForCompilationLevel(options);
}
if (flags.useTypesForOptimization) {
level.setTypeBasedOptimizationOptions(options);
}
if (flags.generateExports) {
options.setGenerateExports(flags.generateExports);
}
WarningLevel wLevel = flags.warningLevel;
wLevel.setOptionsForWarningLevel(options);
for (FormattingOption formattingOption : flags.formatting) {
formattingOption.applyToOptions(options);
}
options.closurePass = flags.processClosurePrimitives;
options.jqueryPass = CompilationLevel.ADVANCED_OPTIMIZATIONS == level &&
flags.processJqueryPrimitives;
options.angularPass = flags.angularPass;
if (!flags.translationsFile.isEmpty()) {
try {
options.messageBundle = new XtbMessageBundle(
new FileInputStream(flags.translationsFile),
flags.translationsProject);
} catch (IOException e) {
throw new RuntimeException("Reading XTB file", e);
}
} else if (CompilationLevel.ADVANCED_OPTIMIZATIONS == level) {
// In SIMPLE or WHITESPACE mode, if the user hasn't specified a
// translations file, they might reasonably try to write their own
// implementation of goog.getMsg that makes the substitution at
// run-time.
//
// In ADVANCED mode, goog.getMsg is going to be renamed anyway,
// so we might as well inline it. But shut off the i18n warnings,
// because the user didn't really ask for i18n.
options.messageBundle = new EmptyMessageBundle();
options.setWarningLevel(JsMessageVisitor.MSG_CONVENTIONS, CheckLevel.OFF);
}
return options;
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
protected CompilerOptions createOptions() {
CompilerOptions options = new CompilerOptions();
if (flags.processJqueryPrimitives) {
options.setCodingConvention(new JqueryCodingConvention());
} else {
options.setCodingConvention(new ClosureCodingConvention());
}
options.setExtraAnnotationNames(flags.extraAnnotationName);
CompilationLevel level = flags.compilationLevel;
level.setOptionsForCompilationLevel(options);
if (flags.debug) {
level.setDebugOptionsForCompilationLevel(options);
}
if (flags.useTypesForOptimization) {
level.setTypeBasedOptimizationOptions(options);
}
if (flags.generateExports) {
options.setGenerateExports(flags.generateExports);
}
WarningLevel wLevel = flags.warningLevel;
wLevel.setOptionsForWarningLevel(options);
for (FormattingOption formattingOption : flags.formatting) {
formattingOption.applyToOptions(options);
}
options.closurePass = flags.processClosurePrimitives;
options.jqueryPass = CompilationLevel.ADVANCED_OPTIMIZATIONS == level &&
flags.processJqueryPrimitives;
options.angularPass = flags.angularPass;
if (!flags.translationsFile.isEmpty()) {
try {
options.messageBundle = new XtbMessageBundle(
new FileInputStream(flags.translationsFile),
flags.translationsProject);
} catch (IOException e) {
throw new RuntimeException("Reading XTB file", e);
}
} else if (CompilationLevel.ADVANCED_OPTIMIZATIONS == level) {
// In SIMPLE or WHITESPACE mode, if the user hasn't specified a
// translations file, they might reasonably try to write their own
// implementation of goog.getMsg that makes the substitution at
// run-time.
//
// In ADVANCED mode, goog.getMsg is going to be renamed anyway,
// so we might as well inline it. But shut off the i18n warnings,
// because the user didn't really ask for i18n.
options.messageBundle = new EmptyMessageBundle();
options.setWarningLevel(JsMessageVisitor.MSG_CONVENTIONS, CheckLevel.OFF);
}
return options;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
3 | 96c1fccf7f115b9cdece3e63c3796d50e6f91bd5fec90dd7ff7f93800e186e28 | public static double linearCombination(final double[] a, final double[] b)
throws DimensionMismatchException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Compute a linear combination accurately.
* This method computes the sum of the products
* <code>a<sub>i</sub> b<sub>i</sub></code> to high accuracy.
* It does so by using specific multiplication and addition algorithms to
* preserve accuracy and reduce cancellation effects.
* <br/>
* It is based on the 2005 paper
* <a href="http://citeseerx.ist.psu.edu/viewdoc/summary?doi=10.1.1.2.1547">
* Accurate Sum and Dot Product</a> by Takeshi Ogita, Siegfried M. Rump,
* and Shin'ichi Oishi published in SIAM J. Sci. Comput.
*
* @param a Factors.
* @param b Factors.
* @return <code>Σ<sub>i</sub> a<sub>i</sub> b<sub>i</sub></code>.
* @throws DimensionMismatchException if arrays dimensions don't match
*/
public static double linearCombination(final double[] a, final double[] b)
throws DimensionMismatchException {
final int len = a.length;
if (len != b.length) {
throw new DimensionMismatchException(len, b.length);
}
if (len == 1) {
// Revert to scalar multiplication.
return a[0] * b[0];
}
final double[] prodHigh = new double[len];
double prodLowSum = 0;
for (int i = 0; i < len; i++) {
final double ai = a[i];
final double ca = SPLIT_FACTOR * ai;
final double aHigh = ca - (ca - ai);
final double aLow = ai - aHigh;
final double bi = b[i];
final double cb = SPLIT_FACTOR * bi;
final double bHigh = cb - (cb - bi);
final double bLow = bi - bHigh;
prodHigh[i] = ai * bi;
final double prodLow = aLow * bLow - (((prodHigh[i] -
aHigh * bHigh) -
aLow * bHigh) -
aHigh * bLow);
prodLowSum += prodLow;
}
final double prodHighCur = prodHigh[0];
double prodHighNext = prodHigh[1];
double sHighPrev = prodHighCur + prodHighNext;
double sPrime = sHighPrev - prodHighNext;
double sLowSum = (prodHighNext - (sHighPrev - sPrime)) + (prodHighCur - sPrime);
final int lenMinusOne = len - 1;
for (int i = 1; i < lenMinusOne; i++) {
prodHighNext = prodHigh[i + 1];
final double sHighCur = sHighPrev + prodHighNext;
sPrime = sHighCur - prodHighNext;
sLowSum += (prodHighNext - (sHighCur - sPrime)) + (sHighPrev - sPrime);
sHighPrev = sHighCur;
}
double result = sHighPrev + (prodLowSum + sLowSum);
if (Double.isNaN(result)) {
// either we have split infinite numbers or some coefficients were NaNs,
// just rely on the naive implementation and let IEEE754 handle this
result = 0;
for (int i = 0; i < len; ++i) {
result += a[i] * b[i];
}
}
return result;
}
```
| public static double linearCombination(final double[] a, final double[] b)
throws DimensionMismatchException {
final int len = a.length;
if (len != b.length) {
throw new DimensionMismatchException(len, b.length);
}
if (len == 1) {
// Revert to scalar multiplication.
return a[0] * b[0];
}
final double[] prodHigh = new double[len];
double prodLowSum = 0;
for (int i = 0; i < len; i++) {
final double ai = a[i];
final double ca = SPLIT_FACTOR * ai;
final double aHigh = ca - (ca - ai);
final double aLow = ai - aHigh;
final double bi = b[i];
final double cb = SPLIT_FACTOR * bi;
final double bHigh = cb - (cb - bi);
final double bLow = bi - bHigh;
prodHigh[i] = ai * bi;
final double prodLow = aLow * bLow - (((prodHigh[i] -
aHigh * bHigh) -
aLow * bHigh) -
aHigh * bLow);
prodLowSum += prodLow;
}
final double prodHighCur = prodHigh[0];
double prodHighNext = prodHigh[1];
double sHighPrev = prodHighCur + prodHighNext;
double sPrime = sHighPrev - prodHighNext;
double sLowSum = (prodHighNext - (sHighPrev - sPrime)) + (prodHighCur - sPrime);
final int lenMinusOne = len - 1;
for (int i = 1; i < lenMinusOne; i++) {
prodHighNext = prodHigh[i + 1];
final double sHighCur = sHighPrev + prodHighNext;
sPrime = sHighCur - prodHighNext;
sLowSum += (prodHighNext - (sHighCur - sPrime)) + (sHighPrev - sPrime);
sHighPrev = sHighCur;
}
double result = sHighPrev + (prodLowSum + sLowSum);
if (Double.isNaN(result)) {
// either we have split infinite numbers or some coefficients were NaNs,
// just rely on the naive implementation and let IEEE754 handle this
result = 0;
for (int i = 0; i < len; ++i) {
result += a[i] * b[i];
}
}
return result;
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Compute a linear combination accurately.
* This method computes the sum of the products
* <code>a<sub>i</sub> b<sub>i</sub></code> to high accuracy.
* It does so by using specific multiplication and addition algorithms to
* preserve accuracy and reduce cancellation effects.
* <br/>
* It is based on the 2005 paper
* <a href="http://citeseerx.ist.psu.edu/viewdoc/summary?doi=10.1.1.2.1547">
* Accurate Sum and Dot Product</a> by Takeshi Ogita, Siegfried M. Rump,
* and Shin'ichi Oishi published in SIAM J. Sci. Comput.
*
* @param a Factors.
* @param b Factors.
* @return <code>Σ<sub>i</sub> a<sub>i</sub> b<sub>i</sub></code>.
* @throws DimensionMismatchException if arrays dimensions don't match
*/
public static double linearCombination(final double[] a, final double[] b)
throws DimensionMismatchException {
final int len = a.length;
if (len != b.length) {
throw new DimensionMismatchException(len, b.length);
}
if (len == 1) {
// Revert to scalar multiplication.
return a[0] * b[0];
}
final double[] prodHigh = new double[len];
double prodLowSum = 0;
for (int i = 0; i < len; i++) {
final double ai = a[i];
final double ca = SPLIT_FACTOR * ai;
final double aHigh = ca - (ca - ai);
final double aLow = ai - aHigh;
final double bi = b[i];
final double cb = SPLIT_FACTOR * bi;
final double bHigh = cb - (cb - bi);
final double bLow = bi - bHigh;
prodHigh[i] = ai * bi;
final double prodLow = aLow * bLow - (((prodHigh[i] -
aHigh * bHigh) -
aLow * bHigh) -
aHigh * bLow);
prodLowSum += prodLow;
}
final double prodHighCur = prodHigh[0];
double prodHighNext = prodHigh[1];
double sHighPrev = prodHighCur + prodHighNext;
double sPrime = sHighPrev - prodHighNext;
double sLowSum = (prodHighNext - (sHighPrev - sPrime)) + (prodHighCur - sPrime);
final int lenMinusOne = len - 1;
for (int i = 1; i < lenMinusOne; i++) {
prodHighNext = prodHigh[i + 1];
final double sHighCur = sHighPrev + prodHighNext;
sPrime = sHighCur - prodHighNext;
sLowSum += (prodHighNext - (sHighCur - sPrime)) + (sHighPrev - sPrime);
sHighPrev = sHighCur;
}
double result = sHighPrev + (prodLowSum + sLowSum);
if (Double.isNaN(result)) {
// either we have split infinite numbers or some coefficients were NaNs,
// just rely on the naive implementation and let IEEE754 handle this
result = 0;
for (int i = 0; i < len; ++i) {
result += a[i] * b[i];
}
}
return result;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
43 | 96c8c7431c150687aef5a2ffa431c42c4e76a323be712295e93187bf8949fc23 | private StringBuffer appendQuotedString(String pattern, ParsePosition pos,
StringBuffer appendTo, boolean escapingOn) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Consume a quoted string, adding it to <code>appendTo</code> if
* specified.
*
* @param pattern pattern to parse
* @param pos current parse position
* @param appendTo optional StringBuffer to append
* @param escapingOn whether to process escaped quotes
* @return <code>appendTo</code>
*/
private StringBuffer appendQuotedString(String pattern, ParsePosition pos,
StringBuffer appendTo, boolean escapingOn) {
int start = pos.getIndex();
char[] c = pattern.toCharArray();
if (escapingOn && c[start] == QUOTE) {
return appendTo == null ? null : appendTo.append(QUOTE);
}
int lastHold = start;
for (int i = pos.getIndex(); i < pattern.length(); i++) {
if (escapingOn && pattern.substring(i).startsWith(ESCAPED_QUOTE)) {
appendTo.append(c, lastHold, pos.getIndex() - lastHold).append(
QUOTE);
pos.setIndex(i + ESCAPED_QUOTE.length());
lastHold = pos.getIndex();
continue;
}
switch (c[pos.getIndex()]) {
case QUOTE:
next(pos);
return appendTo == null ? null : appendTo.append(c, lastHold,
pos.getIndex() - lastHold);
default:
next(pos);
}
}
throw new IllegalArgumentException(
"Unterminated quoted string at position " + start);
}
```
| private StringBuffer appendQuotedString(String pattern, ParsePosition pos,
StringBuffer appendTo, boolean escapingOn) {
int start = pos.getIndex();
char[] c = pattern.toCharArray();
if (escapingOn && c[start] == QUOTE) {
return appendTo == null ? null : appendTo.append(QUOTE);
}
int lastHold = start;
for (int i = pos.getIndex(); i < pattern.length(); i++) {
if (escapingOn && pattern.substring(i).startsWith(ESCAPED_QUOTE)) {
appendTo.append(c, lastHold, pos.getIndex() - lastHold).append(
QUOTE);
pos.setIndex(i + ESCAPED_QUOTE.length());
lastHold = pos.getIndex();
continue;
}
switch (c[pos.getIndex()]) {
case QUOTE:
next(pos);
return appendTo == null ? null : appendTo.append(c, lastHold,
pos.getIndex() - lastHold);
default:
next(pos);
}
}
throw new IllegalArgumentException(
"Unterminated quoted string at position " + start);
} | true | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Consume a quoted string, adding it to <code>appendTo</code> if
* specified.
*
* @param pattern pattern to parse
* @param pos current parse position
* @param appendTo optional StringBuffer to append
* @param escapingOn whether to process escaped quotes
* @return <code>appendTo</code>
*/
private StringBuffer appendQuotedString(String pattern, ParsePosition pos,
StringBuffer appendTo, boolean escapingOn) {
int start = pos.getIndex();
char[] c = pattern.toCharArray();
if (escapingOn && c[start] == QUOTE) {
return appendTo == null ? null : appendTo.append(QUOTE);
}
int lastHold = start;
for (int i = pos.getIndex(); i < pattern.length(); i++) {
if (escapingOn && pattern.substring(i).startsWith(ESCAPED_QUOTE)) {
appendTo.append(c, lastHold, pos.getIndex() - lastHold).append(
QUOTE);
pos.setIndex(i + ESCAPED_QUOTE.length());
lastHold = pos.getIndex();
continue;
}
switch (c[pos.getIndex()]) {
case QUOTE:
next(pos);
return appendTo == null ? null : appendTo.append(c, lastHold,
pos.getIndex() - lastHold);
default:
next(pos);
}
}
throw new IllegalArgumentException(
"Unterminated quoted string at position " + start);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
38 | 96d43867e2229ae8175bf166c62534952096caee3c73b2ac2187150ad8d7aaa0 | private boolean toStringEquals(Matcher m, Object arg) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private boolean toStringEquals(Matcher m, Object arg) {
return StringDescription.toString(m).equals(arg.toString());
}
```
| private boolean toStringEquals(Matcher m, Object arg) {
return StringDescription.toString(m).equals(arg.toString());
} | true | Mockito | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private boolean toStringEquals(Matcher m, Object arg) {
return StringDescription.toString(m).equals(arg.toString());
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
101 | 97073c84cb700703c106d01844b2f771b4e340689155f05118e440a23d928051 | public Complex parse(String source, ParsePosition pos) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Parses a string to produce a {@link Complex} object.
*
* @param source the string to parse
* @param pos input/ouput parsing parameter.
* @return the parsed {@link Complex} object.
*/
public Complex parse(String source, ParsePosition pos) {
int initialIndex = pos.getIndex();
// parse whitespace
parseAndIgnoreWhitespace(source, pos);
// parse real
Number re = parseNumber(source, getRealFormat(), pos);
if (re == null) {
// invalid real number
// set index back to initial, error index should already be set
// character examined.
pos.setIndex(initialIndex);
return null;
}
// parse sign
int startIndex = pos.getIndex();
char c = parseNextCharacter(source, pos);
int sign = 0;
switch (c) {
case 0 :
// no sign
// return real only complex number
return new Complex(re.doubleValue(), 0.0);
case '-' :
sign = -1;
break;
case '+' :
sign = 1;
break;
default :
// invalid sign
// set index back to initial, error index should be the last
// character examined.
pos.setIndex(initialIndex);
pos.setErrorIndex(startIndex);
return null;
}
// parse whitespace
parseAndIgnoreWhitespace(source, pos);
// parse imaginary
Number im = parseNumber(source, getRealFormat(), pos);
if (im == null) {
// invalid imaginary number
// set index back to initial, error index should already be set
// character examined.
pos.setIndex(initialIndex);
return null;
}
// parse imaginary character
int n = getImaginaryCharacter().length();
startIndex = pos.getIndex();
int endIndex = startIndex + n;
if (
source.substring(startIndex, endIndex).compareTo(
getImaginaryCharacter()) != 0) {
// set index back to initial, error index should be the start index
// character examined.
pos.setIndex(initialIndex);
pos.setErrorIndex(startIndex);
return null;
}
pos.setIndex(endIndex);
return new Complex(re.doubleValue(), im.doubleValue() * sign);
}
```
| public Complex parse(String source, ParsePosition pos) {
int initialIndex = pos.getIndex();
// parse whitespace
parseAndIgnoreWhitespace(source, pos);
// parse real
Number re = parseNumber(source, getRealFormat(), pos);
if (re == null) {
// invalid real number
// set index back to initial, error index should already be set
// character examined.
pos.setIndex(initialIndex);
return null;
}
// parse sign
int startIndex = pos.getIndex();
char c = parseNextCharacter(source, pos);
int sign = 0;
switch (c) {
case 0 :
// no sign
// return real only complex number
return new Complex(re.doubleValue(), 0.0);
case '-' :
sign = -1;
break;
case '+' :
sign = 1;
break;
default :
// invalid sign
// set index back to initial, error index should be the last
// character examined.
pos.setIndex(initialIndex);
pos.setErrorIndex(startIndex);
return null;
}
// parse whitespace
parseAndIgnoreWhitespace(source, pos);
// parse imaginary
Number im = parseNumber(source, getRealFormat(), pos);
if (im == null) {
// invalid imaginary number
// set index back to initial, error index should already be set
// character examined.
pos.setIndex(initialIndex);
return null;
}
// parse imaginary character
int n = getImaginaryCharacter().length();
startIndex = pos.getIndex();
int endIndex = startIndex + n;
if (
source.substring(startIndex, endIndex).compareTo(
getImaginaryCharacter()) != 0) {
// set index back to initial, error index should be the start index
// character examined.
pos.setIndex(initialIndex);
pos.setErrorIndex(startIndex);
return null;
}
pos.setIndex(endIndex);
return new Complex(re.doubleValue(), im.doubleValue() * sign);
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Parses a string to produce a {@link Complex} object.
*
* @param source the string to parse
* @param pos input/ouput parsing parameter.
* @return the parsed {@link Complex} object.
*/
public Complex parse(String source, ParsePosition pos) {
int initialIndex = pos.getIndex();
// parse whitespace
parseAndIgnoreWhitespace(source, pos);
// parse real
Number re = parseNumber(source, getRealFormat(), pos);
if (re == null) {
// invalid real number
// set index back to initial, error index should already be set
// character examined.
pos.setIndex(initialIndex);
return null;
}
// parse sign
int startIndex = pos.getIndex();
char c = parseNextCharacter(source, pos);
int sign = 0;
switch (c) {
case 0 :
// no sign
// return real only complex number
return new Complex(re.doubleValue(), 0.0);
case '-' :
sign = -1;
break;
case '+' :
sign = 1;
break;
default :
// invalid sign
// set index back to initial, error index should be the last
// character examined.
pos.setIndex(initialIndex);
pos.setErrorIndex(startIndex);
return null;
}
// parse whitespace
parseAndIgnoreWhitespace(source, pos);
// parse imaginary
Number im = parseNumber(source, getRealFormat(), pos);
if (im == null) {
// invalid imaginary number
// set index back to initial, error index should already be set
// character examined.
pos.setIndex(initialIndex);
return null;
}
// parse imaginary character
int n = getImaginaryCharacter().length();
startIndex = pos.getIndex();
int endIndex = startIndex + n;
if (
source.substring(startIndex, endIndex).compareTo(
getImaginaryCharacter()) != 0) {
// set index back to initial, error index should be the start index
// character examined.
pos.setIndex(initialIndex);
pos.setErrorIndex(startIndex);
return null;
}
pos.setIndex(endIndex);
return new Complex(re.doubleValue(), im.doubleValue() * sign);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
58 | 971c7a223b903d8c371b229da9b08db7524247c827669367355465f8565c2023 | public static Number createNumber(String str) throws NumberFormatException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Turns a string value into a java.lang.Number.</p>
*
* <p>First, the value is examined for a type qualifier on the end
* (<code>'f','F','d','D','l','L'</code>). If it is found, it starts
* trying to create successively larger types from the type specified
* until one is found that can represent the value.</p>
*
* <p>If a type specifier is not found, it will check for a decimal point
* and then try successively larger types from <code>Integer</code> to
* <code>BigInteger</code> and from <code>Float</code> to
* <code>BigDecimal</code>.</p>
*
* <p>If the string starts with <code>0x</code> or <code>-0x</code>, it
* will be interpreted as a hexadecimal integer. Values with leading
* <code>0</code>'s will not be interpreted as octal.</p>
*
* <p>Returns <code>null</code> if the string is <code>null</code>.</p>
*
* <p>This method does not trim the input string, i.e., strings with leading
* or trailing spaces will generate NumberFormatExceptions.</p>
*
* @param str String containing a number, may be null
* @return Number created from the string
* @throws NumberFormatException if the value cannot be converted
*/
// plus minus everything. Prolly more. A lot are not separable.
// 45 45.5 45E7 4.5E7 Hex Oct Binary xxxF xxxD xxxf xxxd
// Possible inputs:
// new BigInteger(String,int radix)
// new BigInteger(String)
// new BigDecimal(String)
// Short.valueOf(String)
// Short.valueOf(String,int)
// Short.decode(String)
// new Short(String)
// Long.valueOf(String)
// Long.valueOf(String,int)
// Long.getLong(String,Integer)
// Long.getLong(String,int)
// Long.getLong(String)
// new Long(String)
// new Byte(String)
// new Double(String)
// new Integer(String)
// Integer.getInteger(String,Integer val)
// Integer.getInteger(String,int val)
// Integer.getInteger(String)
// Integer.decode(String)
// Integer.valueOf(String)
// Integer.valueOf(String,int radix)
// new Float(String)
// Float.valueOf(String)
// Double.valueOf(String)
// Byte.valueOf(String)
// Byte.valueOf(String,int radix)
// Byte.decode(String)
// useful methods:
// BigDecimal, BigInteger and Byte
// must handle Long, Float, Integer, Float, Short,
//-----------------------------------------------------------------------
public static Number createNumber(String str) throws NumberFormatException {
if (str == null) {
return null;
}
if (StringUtils.isBlank(str)) {
throw new NumberFormatException("A blank string is not a valid number");
}
if (str.startsWith("--")) {
// this is protection for poorness in java.lang.BigDecimal.
// it accepts this as a legal value, but it does not appear
// to be in specification of class. OS X Java parses it to
// a wrong value.
return null;
}
if (str.startsWith("0x") || str.startsWith("-0x")) {
return createInteger(str);
}
char lastChar = str.charAt(str.length() - 1);
String mant;
String dec;
String exp;
int decPos = str.indexOf('.');
int expPos = str.indexOf('e') + str.indexOf('E') + 1;
if (decPos > -1) {
if (expPos > -1) {
if (expPos < decPos) {
throw new NumberFormatException(str + " is not a valid number.");
}
dec = str.substring(decPos + 1, expPos);
} else {
dec = str.substring(decPos + 1);
}
mant = str.substring(0, decPos);
} else {
if (expPos > -1) {
mant = str.substring(0, expPos);
} else {
mant = str;
}
dec = null;
}
if (!Character.isDigit(lastChar)) {
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length() - 1);
} else {
exp = null;
}
//Requesting a specific type..
String numeric = str.substring(0, str.length() - 1);
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
switch (lastChar) {
case 'l' :
case 'L' :
if (dec == null
&& exp == null
&& (numeric.charAt(0) == '-' && isDigits(numeric.substring(1)) || isDigits(numeric))) {
try {
return createLong(numeric);
} catch (NumberFormatException nfe) {
//Too big for a long
}
return createBigInteger(numeric);
}
throw new NumberFormatException(str + " is not a valid number.");
case 'f' :
case 'F' :
try {
Float f = NumberUtils.createFloat(numeric);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
//If it's too big for a float or the float value = 0 and the string
//has non-zeros in it, then float does not have the precision we want
return f;
}
} catch (NumberFormatException nfe) {
// ignore the bad number
}
//Fall through
case 'd' :
case 'D' :
try {
Double d = NumberUtils.createDouble(numeric);
if (!(d.isInfinite() || (d.floatValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) {
// ignore the bad number
}
try {
return createBigDecimal(numeric);
} catch (NumberFormatException e) {
// ignore the bad number
}
//Fall through
default :
throw new NumberFormatException(str + " is not a valid number.");
}
} else {
//User doesn't have a preference on the return type, so let's start
//small and go from there...
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length());
} else {
exp = null;
}
if (dec == null && exp == null) {
//Must be an int,long,bigint
try {
return createInteger(str);
} catch (NumberFormatException nfe) {
// ignore the bad number
}
try {
return createLong(str);
} catch (NumberFormatException nfe) {
// ignore the bad number
}
return createBigInteger(str);
} else {
//Must be a float,double,BigDec
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
try {
Float f = createFloat(str);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
return f;
}
} catch (NumberFormatException nfe) {
// ignore the bad number
}
try {
Double d = createDouble(str);
if (!(d.isInfinite() || (d.doubleValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) {
// ignore the bad number
}
return createBigDecimal(str);
}
}
}
```
| public static Number createNumber(String str) throws NumberFormatException {
if (str == null) {
return null;
}
if (StringUtils.isBlank(str)) {
throw new NumberFormatException("A blank string is not a valid number");
}
if (str.startsWith("--")) {
// this is protection for poorness in java.lang.BigDecimal.
// it accepts this as a legal value, but it does not appear
// to be in specification of class. OS X Java parses it to
// a wrong value.
return null;
}
if (str.startsWith("0x") || str.startsWith("-0x")) {
return createInteger(str);
}
char lastChar = str.charAt(str.length() - 1);
String mant;
String dec;
String exp;
int decPos = str.indexOf('.');
int expPos = str.indexOf('e') + str.indexOf('E') + 1;
if (decPos > -1) {
if (expPos > -1) {
if (expPos < decPos) {
throw new NumberFormatException(str + " is not a valid number.");
}
dec = str.substring(decPos + 1, expPos);
} else {
dec = str.substring(decPos + 1);
}
mant = str.substring(0, decPos);
} else {
if (expPos > -1) {
mant = str.substring(0, expPos);
} else {
mant = str;
}
dec = null;
}
if (!Character.isDigit(lastChar)) {
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length() - 1);
} else {
exp = null;
}
//Requesting a specific type..
String numeric = str.substring(0, str.length() - 1);
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
switch (lastChar) {
case 'l' :
case 'L' :
if (dec == null
&& exp == null
&& (numeric.charAt(0) == '-' && isDigits(numeric.substring(1)) || isDigits(numeric))) {
try {
return createLong(numeric);
} catch (NumberFormatException nfe) {
//Too big for a long
}
return createBigInteger(numeric);
}
throw new NumberFormatException(str + " is not a valid number.");
case 'f' :
case 'F' :
try {
Float f = NumberUtils.createFloat(numeric);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
//If it's too big for a float or the float value = 0 and the string
//has non-zeros in it, then float does not have the precision we want
return f;
}
} catch (NumberFormatException nfe) {
// ignore the bad number
}
//Fall through
case 'd' :
case 'D' :
try {
Double d = NumberUtils.createDouble(numeric);
if (!(d.isInfinite() || (d.floatValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) {
// ignore the bad number
}
try {
return createBigDecimal(numeric);
} catch (NumberFormatException e) {
// ignore the bad number
}
//Fall through
default :
throw new NumberFormatException(str + " is not a valid number.");
}
} else {
//User doesn't have a preference on the return type, so let's start
//small and go from there...
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length());
} else {
exp = null;
}
if (dec == null && exp == null) {
//Must be an int,long,bigint
try {
return createInteger(str);
} catch (NumberFormatException nfe) {
// ignore the bad number
}
try {
return createLong(str);
} catch (NumberFormatException nfe) {
// ignore the bad number
}
return createBigInteger(str);
} else {
//Must be a float,double,BigDec
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
try {
Float f = createFloat(str);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
return f;
}
} catch (NumberFormatException nfe) {
// ignore the bad number
}
try {
Double d = createDouble(str);
if (!(d.isInfinite() || (d.doubleValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) {
// ignore the bad number
}
return createBigDecimal(str);
}
}
} | false | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Turns a string value into a java.lang.Number.</p>
*
* <p>First, the value is examined for a type qualifier on the end
* (<code>'f','F','d','D','l','L'</code>). If it is found, it starts
* trying to create successively larger types from the type specified
* until one is found that can represent the value.</p>
*
* <p>If a type specifier is not found, it will check for a decimal point
* and then try successively larger types from <code>Integer</code> to
* <code>BigInteger</code> and from <code>Float</code> to
* <code>BigDecimal</code>.</p>
*
* <p>If the string starts with <code>0x</code> or <code>-0x</code>, it
* will be interpreted as a hexadecimal integer. Values with leading
* <code>0</code>'s will not be interpreted as octal.</p>
*
* <p>Returns <code>null</code> if the string is <code>null</code>.</p>
*
* <p>This method does not trim the input string, i.e., strings with leading
* or trailing spaces will generate NumberFormatExceptions.</p>
*
* @param str String containing a number, may be null
* @return Number created from the string
* @throws NumberFormatException if the value cannot be converted
*/
// plus minus everything. Prolly more. A lot are not separable.
// 45 45.5 45E7 4.5E7 Hex Oct Binary xxxF xxxD xxxf xxxd
// Possible inputs:
// new BigInteger(String,int radix)
// new BigInteger(String)
// new BigDecimal(String)
// Short.valueOf(String)
// Short.valueOf(String,int)
// Short.decode(String)
// new Short(String)
// Long.valueOf(String)
// Long.valueOf(String,int)
// Long.getLong(String,Integer)
// Long.getLong(String,int)
// Long.getLong(String)
// new Long(String)
// new Byte(String)
// new Double(String)
// new Integer(String)
// Integer.getInteger(String,Integer val)
// Integer.getInteger(String,int val)
// Integer.getInteger(String)
// Integer.decode(String)
// Integer.valueOf(String)
// Integer.valueOf(String,int radix)
// new Float(String)
// Float.valueOf(String)
// Double.valueOf(String)
// Byte.valueOf(String)
// Byte.valueOf(String,int radix)
// Byte.decode(String)
// useful methods:
// BigDecimal, BigInteger and Byte
// must handle Long, Float, Integer, Float, Short,
//-----------------------------------------------------------------------
public static Number createNumber(String str) throws NumberFormatException {
if (str == null) {
return null;
}
if (StringUtils.isBlank(str)) {
throw new NumberFormatException("A blank string is not a valid number");
}
if (str.startsWith("--")) {
// this is protection for poorness in java.lang.BigDecimal.
// it accepts this as a legal value, but it does not appear
// to be in specification of class. OS X Java parses it to
// a wrong value.
return null;
}
if (str.startsWith("0x") || str.startsWith("-0x")) {
return createInteger(str);
}
char lastChar = str.charAt(str.length() - 1);
String mant;
String dec;
String exp;
int decPos = str.indexOf('.');
int expPos = str.indexOf('e') + str.indexOf('E') + 1;
if (decPos > -1) {
if (expPos > -1) {
if (expPos < decPos) {
throw new NumberFormatException(str + " is not a valid number.");
}
dec = str.substring(decPos + 1, expPos);
} else {
dec = str.substring(decPos + 1);
}
mant = str.substring(0, decPos);
} else {
if (expPos > -1) {
mant = str.substring(0, expPos);
} else {
mant = str;
}
dec = null;
}
if (!Character.isDigit(lastChar)) {
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length() - 1);
} else {
exp = null;
}
//Requesting a specific type..
String numeric = str.substring(0, str.length() - 1);
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
switch (lastChar) {
case 'l' :
case 'L' :
if (dec == null
&& exp == null
&& (numeric.charAt(0) == '-' && isDigits(numeric.substring(1)) || isDigits(numeric))) {
try {
return createLong(numeric);
} catch (NumberFormatException nfe) {
//Too big for a long
}
return createBigInteger(numeric);
}
throw new NumberFormatException(str + " is not a valid number.");
case 'f' :
case 'F' :
try {
Float f = NumberUtils.createFloat(numeric);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
//If it's too big for a float or the float value = 0 and the string
//has non-zeros in it, then float does not have the precision we want
return f;
}
} catch (NumberFormatException nfe) {
// ignore the bad number
}
//Fall through
case 'd' :
case 'D' :
try {
Double d = NumberUtils.createDouble(numeric);
if (!(d.isInfinite() || (d.floatValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) {
// ignore the bad number
}
try {
return createBigDecimal(numeric);
} catch (NumberFormatException e) {
// ignore the bad number
}
//Fall through
default :
throw new NumberFormatException(str + " is not a valid number.");
}
} else {
//User doesn't have a preference on the return type, so let's start
//small and go from there...
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length());
} else {
exp = null;
}
if (dec == null && exp == null) {
//Must be an int,long,bigint
try {
return createInteger(str);
} catch (NumberFormatException nfe) {
// ignore the bad number
}
try {
return createLong(str);
} catch (NumberFormatException nfe) {
// ignore the bad number
}
return createBigInteger(str);
} else {
//Must be a float,double,BigDec
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
try {
Float f = createFloat(str);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
return f;
}
} catch (NumberFormatException nfe) {
// ignore the bad number
}
try {
Double d = createDouble(str);
if (!(d.isInfinite() || (d.doubleValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) {
// ignore the bad number
}
return createBigDecimal(str);
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
14 | 973607328730b9f183120ad03f3a91758e64627bd7cdf4398cb1f4db88499dd1 | public int[] add(ReadablePartial partial, int fieldIndex, int[] values, int valueToAdd) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
//-----------------------------------------------------------------------
public int[] add(ReadablePartial partial, int fieldIndex, int[] values, int valueToAdd) {
// overridden as superclass algorithm can't handle
// 2004-02-29 + 48 months -> 2008-02-29 type dates
if (valueToAdd == 0) {
return values;
}
if (partial.size() > 0 && partial.getFieldType(0).equals(DateTimeFieldType.monthOfYear()) && fieldIndex == 0) {
// month is largest field and being added to, such as month-day
int curMonth0 = partial.getValue(0) - 1;
int newMonth = ((curMonth0 + (valueToAdd % 12) + 12) % 12) + 1;
return set(partial, 0, values, newMonth);
}
if (DateTimeUtils.isContiguous(partial)) {
long instant = 0L;
for (int i = 0, isize = partial.size(); i < isize; i++) {
instant = partial.getFieldType(i).getField(iChronology).set(instant, values[i]);
}
instant = add(instant, valueToAdd);
return iChronology.get(partial, instant);
} else {
return super.add(partial, fieldIndex, values, valueToAdd);
}
}
```
| public int[] add(ReadablePartial partial, int fieldIndex, int[] values, int valueToAdd) {
// overridden as superclass algorithm can't handle
// 2004-02-29 + 48 months -> 2008-02-29 type dates
if (valueToAdd == 0) {
return values;
}
if (partial.size() > 0 && partial.getFieldType(0).equals(DateTimeFieldType.monthOfYear()) && fieldIndex == 0) {
// month is largest field and being added to, such as month-day
int curMonth0 = partial.getValue(0) - 1;
int newMonth = ((curMonth0 + (valueToAdd % 12) + 12) % 12) + 1;
return set(partial, 0, values, newMonth);
}
if (DateTimeUtils.isContiguous(partial)) {
long instant = 0L;
for (int i = 0, isize = partial.size(); i < isize; i++) {
instant = partial.getFieldType(i).getField(iChronology).set(instant, values[i]);
}
instant = add(instant, valueToAdd);
return iChronology.get(partial, instant);
} else {
return super.add(partial, fieldIndex, values, valueToAdd);
}
} | false | Time | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
//-----------------------------------------------------------------------
public int[] add(ReadablePartial partial, int fieldIndex, int[] values, int valueToAdd) {
// overridden as superclass algorithm can't handle
// 2004-02-29 + 48 months -> 2008-02-29 type dates
if (valueToAdd == 0) {
return values;
}
if (partial.size() > 0 && partial.getFieldType(0).equals(DateTimeFieldType.monthOfYear()) && fieldIndex == 0) {
// month is largest field and being added to, such as month-day
int curMonth0 = partial.getValue(0) - 1;
int newMonth = ((curMonth0 + (valueToAdd % 12) + 12) % 12) + 1;
return set(partial, 0, values, newMonth);
}
if (DateTimeUtils.isContiguous(partial)) {
long instant = 0L;
for (int i = 0, isize = partial.size(); i < isize; i++) {
instant = partial.getFieldType(i).getField(iChronology).set(instant, values[i]);
}
instant = add(instant, valueToAdd);
return iChronology.get(partial, instant);
} else {
return super.add(partial, fieldIndex, values, valueToAdd);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
35 | 978d92e9794742e218560a15471354483844d127feca02fce4c13e01d9566a56 | private void inferPropertyTypesToMatchConstraint(
JSType type, JSType constraint) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Suppose X is an object with inferred properties.
* Suppose also that X is used in a way where it would only type-check
* correctly if some of those properties are widened.
* Then we should be polite and automatically widen X's properties for him.
*
* For a concrete example, consider:
* param x {{prop: (number|undefined)}}
* function f(x) {}
* f({});
*
* If we give the anonymous object an inferred property of (number|undefined),
* then this code will type-check appropriately.
*/
private void inferPropertyTypesToMatchConstraint(
JSType type, JSType constraint) {
if (type == null || constraint == null) {
return;
}
ObjectType constraintObj =
ObjectType.cast(constraint.restrictByNotNullOrUndefined());
if (constraintObj != null) {
type.matchConstraint(constraintObj);
}
}
```
| private void inferPropertyTypesToMatchConstraint(
JSType type, JSType constraint) {
if (type == null || constraint == null) {
return;
}
ObjectType constraintObj =
ObjectType.cast(constraint.restrictByNotNullOrUndefined());
if (constraintObj != null) {
type.matchConstraint(constraintObj);
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Suppose X is an object with inferred properties.
* Suppose also that X is used in a way where it would only type-check
* correctly if some of those properties are widened.
* Then we should be polite and automatically widen X's properties for him.
*
* For a concrete example, consider:
* param x {{prop: (number|undefined)}}
* function f(x) {}
* f({});
*
* If we give the anonymous object an inferred property of (number|undefined),
* then this code will type-check appropriately.
*/
private void inferPropertyTypesToMatchConstraint(
JSType type, JSType constraint) {
if (type == null || constraint == null) {
return;
}
ObjectType constraintObj =
ObjectType.cast(constraint.restrictByNotNullOrUndefined());
if (constraintObj != null) {
type.matchConstraint(constraintObj);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
18 | 97d3eb7868f1eceadf1b6901e842dbc5444200e1e5b1cf878e5be5d249dfd3fb | void writePaxHeaders(String entryName,
Map<String, String> headers) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Writes a PAX extended header with the given map as contents.
* @since 1.4
*/
void writePaxHeaders(String entryName,
Map<String, String> headers) throws IOException {
String name = "./PaxHeaders.X/" + stripTo7Bits(entryName);
while (name.endsWith("/")) {
// TarEntry's constructor would think this is a directory
// and not allow any data to be written
name = name.substring(0, name.length() - 1);
}
if (name.length() >= TarConstants.NAMELEN) {
name = name.substring(0, TarConstants.NAMELEN - 1);
}
TarArchiveEntry pex = new TarArchiveEntry(name,
TarConstants.LF_PAX_EXTENDED_HEADER_LC);
StringWriter w = new StringWriter();
for (Map.Entry<String, String> h : headers.entrySet()) {
String key = h.getKey();
String value = h.getValue();
int len = key.length() + value.length()
+ 3 /* blank, equals and newline */
+ 2 /* guess 9 < actual length < 100 */;
String line = len + " " + key + "=" + value + "\n";
int actualLength = line.getBytes(CharsetNames.UTF_8).length;
while (len != actualLength) {
// Adjust for cases where length < 10 or > 100
// or where UTF-8 encoding isn't a single octet
// per character.
// Must be in loop as size may go from 99 to 100 in
// first pass so we'd need a second.
len = actualLength;
line = len + " " + key + "=" + value + "\n";
actualLength = line.getBytes(CharsetNames.UTF_8).length;
}
w.write(line);
}
byte[] data = w.toString().getBytes(CharsetNames.UTF_8);
pex.setSize(data.length);
putArchiveEntry(pex);
write(data);
closeArchiveEntry();
}
```
| void writePaxHeaders(String entryName,
Map<String, String> headers) throws IOException {
String name = "./PaxHeaders.X/" + stripTo7Bits(entryName);
while (name.endsWith("/")) {
// TarEntry's constructor would think this is a directory
// and not allow any data to be written
name = name.substring(0, name.length() - 1);
}
if (name.length() >= TarConstants.NAMELEN) {
name = name.substring(0, TarConstants.NAMELEN - 1);
}
TarArchiveEntry pex = new TarArchiveEntry(name,
TarConstants.LF_PAX_EXTENDED_HEADER_LC);
StringWriter w = new StringWriter();
for (Map.Entry<String, String> h : headers.entrySet()) {
String key = h.getKey();
String value = h.getValue();
int len = key.length() + value.length()
+ 3 /* blank, equals and newline */
+ 2 /* guess 9 < actual length < 100 */;
String line = len + " " + key + "=" + value + "\n";
int actualLength = line.getBytes(CharsetNames.UTF_8).length;
while (len != actualLength) {
// Adjust for cases where length < 10 or > 100
// or where UTF-8 encoding isn't a single octet
// per character.
// Must be in loop as size may go from 99 to 100 in
// first pass so we'd need a second.
len = actualLength;
line = len + " " + key + "=" + value + "\n";
actualLength = line.getBytes(CharsetNames.UTF_8).length;
}
w.write(line);
}
byte[] data = w.toString().getBytes(CharsetNames.UTF_8);
pex.setSize(data.length);
putArchiveEntry(pex);
write(data);
closeArchiveEntry();
} | false | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Writes a PAX extended header with the given map as contents.
* @since 1.4
*/
void writePaxHeaders(String entryName,
Map<String, String> headers) throws IOException {
String name = "./PaxHeaders.X/" + stripTo7Bits(entryName);
while (name.endsWith("/")) {
// TarEntry's constructor would think this is a directory
// and not allow any data to be written
name = name.substring(0, name.length() - 1);
}
if (name.length() >= TarConstants.NAMELEN) {
name = name.substring(0, TarConstants.NAMELEN - 1);
}
TarArchiveEntry pex = new TarArchiveEntry(name,
TarConstants.LF_PAX_EXTENDED_HEADER_LC);
StringWriter w = new StringWriter();
for (Map.Entry<String, String> h : headers.entrySet()) {
String key = h.getKey();
String value = h.getValue();
int len = key.length() + value.length()
+ 3 /* blank, equals and newline */
+ 2 /* guess 9 < actual length < 100 */;
String line = len + " " + key + "=" + value + "\n";
int actualLength = line.getBytes(CharsetNames.UTF_8).length;
while (len != actualLength) {
// Adjust for cases where length < 10 or > 100
// or where UTF-8 encoding isn't a single octet
// per character.
// Must be in loop as size may go from 99 to 100 in
// first pass so we'd need a second.
len = actualLength;
line = len + " " + key + "=" + value + "\n";
actualLength = line.getBytes(CharsetNames.UTF_8).length;
}
w.write(line);
}
byte[] data = w.toString().getBytes(CharsetNames.UTF_8);
pex.setSize(data.length);
putArchiveEntry(pex);
write(data);
closeArchiveEntry();
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
90 | 97fde32fda1ed713279040beac1794ddd94ba56a5a3f70bea1efb022753021a2 | private static boolean looksLikeUtf8(byte[] input) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private static boolean looksLikeUtf8(byte[] input) {
int i = 0;
// BOM:
if (input.length >= 3 && (input[0] & 0xFF) == 0xEF
&& (input[1] & 0xFF) == 0xBB & (input[2] & 0xFF) == 0xBF) {
i = 3;
}
int end;
for (int j = input.length; i < j; ++i) {
int o = input[i];
if ((o & 0x80) == 0) {
continue; // ASCII
}
// UTF-8 leading:
if ((o & 0xE0) == 0xC0) {
end = i + 1;
} else if ((o & 0xF0) == 0xE0) {
end = i + 2;
} else if ((o & 0xF8) == 0xF0) {
end = i + 3;
} else {
return false;
}
while (i < end) {
i++;
o = input[i];
if ((o & 0xC0) != 0x80) {
return false;
}
}
}
return true;
}
```
| private static boolean looksLikeUtf8(byte[] input) {
int i = 0;
// BOM:
if (input.length >= 3 && (input[0] & 0xFF) == 0xEF
&& (input[1] & 0xFF) == 0xBB & (input[2] & 0xFF) == 0xBF) {
i = 3;
}
int end;
for (int j = input.length; i < j; ++i) {
int o = input[i];
if ((o & 0x80) == 0) {
continue; // ASCII
}
// UTF-8 leading:
if ((o & 0xE0) == 0xC0) {
end = i + 1;
} else if ((o & 0xF0) == 0xE0) {
end = i + 2;
} else if ((o & 0xF8) == 0xF0) {
end = i + 3;
} else {
return false;
}
while (i < end) {
i++;
o = input[i];
if ((o & 0xC0) != 0x80) {
return false;
}
}
}
return true;
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private static boolean looksLikeUtf8(byte[] input) {
int i = 0;
// BOM:
if (input.length >= 3 && (input[0] & 0xFF) == 0xEF
&& (input[1] & 0xFF) == 0xBB & (input[2] & 0xFF) == 0xBF) {
i = 3;
}
int end;
for (int j = input.length; i < j; ++i) {
int o = input[i];
if ((o & 0x80) == 0) {
continue; // ASCII
}
// UTF-8 leading:
if ((o & 0xE0) == 0xC0) {
end = i + 1;
} else if ((o & 0xF0) == 0xE0) {
end = i + 2;
} else if ((o & 0xF8) == 0xF0) {
end = i + 3;
} else {
return false;
}
while (i < end) {
i++;
o = input[i];
if ((o & 0xC0) != 0x80) {
return false;
}
}
}
return true;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
5 | 988639410b622d034430ff2bc76586822980747dc082a434314c48b71f6f5612 | public int read(byte[] buffer, int start, int length) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public int read(byte[] buffer, int start, int length) throws IOException {
if (closed) {
throw new IOException("The stream is closed");
}
if (inf.finished() || current == null) {
return -1;
}
// avoid int overflow, check null buffer
if (start <= buffer.length && length >= 0 && start >= 0
&& buffer.length - start >= length) {
if (current.getMethod() == ZipArchiveOutputStream.STORED) {
int csize = (int) current.getSize();
if (readBytesOfEntry >= csize) {
return -1;
}
if (offsetInBuffer >= lengthOfLastRead) {
offsetInBuffer = 0;
if ((lengthOfLastRead = in.read(buf)) == -1) {
return -1;
}
count(lengthOfLastRead);
bytesReadFromStream += lengthOfLastRead;
}
int toRead = length > lengthOfLastRead
? lengthOfLastRead - offsetInBuffer
: length;
if ((csize - readBytesOfEntry) < toRead) {
toRead = csize - readBytesOfEntry;
}
System.arraycopy(buf, offsetInBuffer, buffer, start, toRead);
offsetInBuffer += toRead;
readBytesOfEntry += toRead;
crc.update(buffer, start, toRead);
return toRead;
}
if (inf.needsInput()) {
fill();
if (lengthOfLastRead > 0) {
bytesReadFromStream += lengthOfLastRead;
}
}
int read = 0;
try {
read = inf.inflate(buffer, start, length);
} catch (DataFormatException e) {
throw new ZipException(e.getMessage());
}
if (read == 0 && inf.finished()) {
return -1;
}
crc.update(buffer, start, read);
return read;
}
throw new ArrayIndexOutOfBoundsException();
}
```
| public int read(byte[] buffer, int start, int length) throws IOException {
if (closed) {
throw new IOException("The stream is closed");
}
if (inf.finished() || current == null) {
return -1;
}
// avoid int overflow, check null buffer
if (start <= buffer.length && length >= 0 && start >= 0
&& buffer.length - start >= length) {
if (current.getMethod() == ZipArchiveOutputStream.STORED) {
int csize = (int) current.getSize();
if (readBytesOfEntry >= csize) {
return -1;
}
if (offsetInBuffer >= lengthOfLastRead) {
offsetInBuffer = 0;
if ((lengthOfLastRead = in.read(buf)) == -1) {
return -1;
}
count(lengthOfLastRead);
bytesReadFromStream += lengthOfLastRead;
}
int toRead = length > lengthOfLastRead
? lengthOfLastRead - offsetInBuffer
: length;
if ((csize - readBytesOfEntry) < toRead) {
toRead = csize - readBytesOfEntry;
}
System.arraycopy(buf, offsetInBuffer, buffer, start, toRead);
offsetInBuffer += toRead;
readBytesOfEntry += toRead;
crc.update(buffer, start, toRead);
return toRead;
}
if (inf.needsInput()) {
fill();
if (lengthOfLastRead > 0) {
bytesReadFromStream += lengthOfLastRead;
}
}
int read = 0;
try {
read = inf.inflate(buffer, start, length);
} catch (DataFormatException e) {
throw new ZipException(e.getMessage());
}
if (read == 0 && inf.finished()) {
return -1;
}
crc.update(buffer, start, read);
return read;
}
throw new ArrayIndexOutOfBoundsException();
} | true | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public int read(byte[] buffer, int start, int length) throws IOException {
if (closed) {
throw new IOException("The stream is closed");
}
if (inf.finished() || current == null) {
return -1;
}
// avoid int overflow, check null buffer
if (start <= buffer.length && length >= 0 && start >= 0
&& buffer.length - start >= length) {
if (current.getMethod() == ZipArchiveOutputStream.STORED) {
int csize = (int) current.getSize();
if (readBytesOfEntry >= csize) {
return -1;
}
if (offsetInBuffer >= lengthOfLastRead) {
offsetInBuffer = 0;
if ((lengthOfLastRead = in.read(buf)) == -1) {
return -1;
}
count(lengthOfLastRead);
bytesReadFromStream += lengthOfLastRead;
}
int toRead = length > lengthOfLastRead
? lengthOfLastRead - offsetInBuffer
: length;
if ((csize - readBytesOfEntry) < toRead) {
toRead = csize - readBytesOfEntry;
}
System.arraycopy(buf, offsetInBuffer, buffer, start, toRead);
offsetInBuffer += toRead;
readBytesOfEntry += toRead;
crc.update(buffer, start, toRead);
return toRead;
}
if (inf.needsInput()) {
fill();
if (lengthOfLastRead > 0) {
bytesReadFromStream += lengthOfLastRead;
}
}
int read = 0;
try {
read = inf.inflate(buffer, start, length);
} catch (DataFormatException e) {
throw new ZipException(e.getMessage());
}
if (read == 0 && inf.finished()) {
return -1;
}
crc.update(buffer, start, read);
return read;
}
throw new ArrayIndexOutOfBoundsException();
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
88 | 988b70b58a365f2db768c2062b8c48b7e9e92d598bf48f026288f24a0345835c | private VariableLiveness isVariableReadBeforeKill(
Node n, String variable) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Give an expression and a variable. It returns READ, if the first
* reference of that variable is a read. It returns KILL, if the first
* reference of that variable is an assignment. It returns MAY_LIVE otherwise.
*/
private VariableLiveness isVariableReadBeforeKill(
Node n, String variable) {
if (NodeUtil.isName(n) && variable.equals(n.getString())) {
if (NodeUtil.isLhs(n, n.getParent())) {
Preconditions.checkState(n.getParent().getType() == Token.ASSIGN);
// The expression to which the assignment is made is evaluated before
// the RHS is evaluated (normal left to right evaluation) but the KILL
// occurs after the RHS is evaluated.
Node rhs = n.getNext();
VariableLiveness state = isVariableReadBeforeKill(rhs, variable);
if (state == VariableLiveness.READ) {
return state;
}
return VariableLiveness.KILL;
} else {
return VariableLiveness.READ;
}
}
// Expressions are evaluated left-right, depth first.
for (Node child = n.getFirstChild();
child != null; child = child.getNext()) {
if (!ControlFlowGraph.isEnteringNewCfgNode(child)) { // Not a FUNCTION
VariableLiveness state = isVariableReadBeforeKill(child, variable);
if (state != VariableLiveness.MAYBE_LIVE) {
return state;
}
}
}
return VariableLiveness.MAYBE_LIVE;
}
```
| private VariableLiveness isVariableReadBeforeKill(
Node n, String variable) {
if (NodeUtil.isName(n) && variable.equals(n.getString())) {
if (NodeUtil.isLhs(n, n.getParent())) {
Preconditions.checkState(n.getParent().getType() == Token.ASSIGN);
// The expression to which the assignment is made is evaluated before
// the RHS is evaluated (normal left to right evaluation) but the KILL
// occurs after the RHS is evaluated.
Node rhs = n.getNext();
VariableLiveness state = isVariableReadBeforeKill(rhs, variable);
if (state == VariableLiveness.READ) {
return state;
}
return VariableLiveness.KILL;
} else {
return VariableLiveness.READ;
}
}
// Expressions are evaluated left-right, depth first.
for (Node child = n.getFirstChild();
child != null; child = child.getNext()) {
if (!ControlFlowGraph.isEnteringNewCfgNode(child)) { // Not a FUNCTION
VariableLiveness state = isVariableReadBeforeKill(child, variable);
if (state != VariableLiveness.MAYBE_LIVE) {
return state;
}
}
}
return VariableLiveness.MAYBE_LIVE;
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Give an expression and a variable. It returns READ, if the first
* reference of that variable is a read. It returns KILL, if the first
* reference of that variable is an assignment. It returns MAY_LIVE otherwise.
*/
private VariableLiveness isVariableReadBeforeKill(
Node n, String variable) {
if (NodeUtil.isName(n) && variable.equals(n.getString())) {
if (NodeUtil.isLhs(n, n.getParent())) {
Preconditions.checkState(n.getParent().getType() == Token.ASSIGN);
// The expression to which the assignment is made is evaluated before
// the RHS is evaluated (normal left to right evaluation) but the KILL
// occurs after the RHS is evaluated.
Node rhs = n.getNext();
VariableLiveness state = isVariableReadBeforeKill(rhs, variable);
if (state == VariableLiveness.READ) {
return state;
}
return VariableLiveness.KILL;
} else {
return VariableLiveness.READ;
}
}
// Expressions are evaluated left-right, depth first.
for (Node child = n.getFirstChild();
child != null; child = child.getNext()) {
if (!ControlFlowGraph.isEnteringNewCfgNode(child)) { // Not a FUNCTION
VariableLiveness state = isVariableReadBeforeKill(child, variable);
if (state != VariableLiveness.MAYBE_LIVE) {
return state;
}
}
}
return VariableLiveness.MAYBE_LIVE;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
34 | 98a901dbfb88a95e46e72c9a205e534c56bf0b874656474cf0c5d1e7337d9645 | @Override
public void acceptJsonFormatVisitor(JsonFormatVisitorWrapper visitor, JavaType typeHint) throws JsonMappingException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public void acceptJsonFormatVisitor(JsonFormatVisitorWrapper visitor, JavaType typeHint) throws JsonMappingException
{
if (_isInt) {
visitIntFormat(visitor, typeHint, JsonParser.NumberType.BIG_INTEGER);
} else {
Class<?> h = handledType();
if (h == BigDecimal.class) {
visitFloatFormat(visitor, typeHint, JsonParser.NumberType.BIG_INTEGER);
} else {
// otherwise bit unclear what to call... but let's try:
/*JsonNumberFormatVisitor v2 =*/ visitor.expectNumberFormat(typeHint);
}
}
}
```
| @Override
public void acceptJsonFormatVisitor(JsonFormatVisitorWrapper visitor, JavaType typeHint) throws JsonMappingException
{
if (_isInt) {
visitIntFormat(visitor, typeHint, JsonParser.NumberType.BIG_INTEGER);
} else {
Class<?> h = handledType();
if (h == BigDecimal.class) {
visitFloatFormat(visitor, typeHint, JsonParser.NumberType.BIG_INTEGER);
} else {
// otherwise bit unclear what to call... but let's try:
/*JsonNumberFormatVisitor v2 =*/ visitor.expectNumberFormat(typeHint);
}
}
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public void acceptJsonFormatVisitor(JsonFormatVisitorWrapper visitor, JavaType typeHint) throws JsonMappingException
{
if (_isInt) {
visitIntFormat(visitor, typeHint, JsonParser.NumberType.BIG_INTEGER);
} else {
Class<?> h = handledType();
if (h == BigDecimal.class) {
visitFloatFormat(visitor, typeHint, JsonParser.NumberType.BIG_INTEGER);
} else {
// otherwise bit unclear what to call... but let's try:
/*JsonNumberFormatVisitor v2 =*/ visitor.expectNumberFormat(typeHint);
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
1 | 98b4b3262430120675fa68af6ab7ceebe5b58a58a6bdac2cb5ecf13814ad3c8b | public void serializeAsColumn(Object bean, JsonGenerator jgen, SerializerProvider prov)
throws Exception
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Alternative to {@link #serializeAsField} that is used when a POJO
* is serialized as JSON Array; the difference is that no field names
* are written.
*
* @since 2.1
*/
public void serializeAsColumn(Object bean, JsonGenerator jgen, SerializerProvider prov)
throws Exception
{
Object value = get(bean);
if (value == null) { // nulls need specialized handling
if (_nullSerializer != null) {
_nullSerializer.serialize(null, jgen, prov);
} else { // can NOT suppress entries in tabular output
jgen.writeNull();
}
return;
}
// otherwise find serializer to use
JsonSerializer<Object> ser = _serializer;
if (ser == null) {
Class<?> cls = value.getClass();
PropertySerializerMap map = _dynamicSerializers;
ser = map.serializerFor(cls);
if (ser == null) {
ser = _findAndAddDynamic(map, cls, prov);
}
}
// and then see if we must suppress certain values (default, empty)
if (_suppressableValue != null) {
if (MARKER_FOR_EMPTY == _suppressableValue) {
if (ser.isEmpty(value)) { // can NOT suppress entries in tabular output
serializeAsPlaceholder(bean, jgen, prov);
return;
}
} else if (_suppressableValue.equals(value)) { // can NOT suppress entries in tabular output
serializeAsPlaceholder(bean, jgen, prov);
return;
}
}
// For non-nulls: simple check for direct cycles
if (value == bean) {
_handleSelfReference(bean, ser);
}
if (_typeSerializer == null) {
ser.serialize(value, jgen, prov);
} else {
ser.serializeWithType(value, jgen, prov, _typeSerializer);
}
}
```
| public void serializeAsColumn(Object bean, JsonGenerator jgen, SerializerProvider prov)
throws Exception
{
Object value = get(bean);
if (value == null) { // nulls need specialized handling
if (_nullSerializer != null) {
_nullSerializer.serialize(null, jgen, prov);
} else { // can NOT suppress entries in tabular output
jgen.writeNull();
}
return;
}
// otherwise find serializer to use
JsonSerializer<Object> ser = _serializer;
if (ser == null) {
Class<?> cls = value.getClass();
PropertySerializerMap map = _dynamicSerializers;
ser = map.serializerFor(cls);
if (ser == null) {
ser = _findAndAddDynamic(map, cls, prov);
}
}
// and then see if we must suppress certain values (default, empty)
if (_suppressableValue != null) {
if (MARKER_FOR_EMPTY == _suppressableValue) {
if (ser.isEmpty(value)) { // can NOT suppress entries in tabular output
serializeAsPlaceholder(bean, jgen, prov);
return;
}
} else if (_suppressableValue.equals(value)) { // can NOT suppress entries in tabular output
serializeAsPlaceholder(bean, jgen, prov);
return;
}
}
// For non-nulls: simple check for direct cycles
if (value == bean) {
_handleSelfReference(bean, ser);
}
if (_typeSerializer == null) {
ser.serialize(value, jgen, prov);
} else {
ser.serializeWithType(value, jgen, prov, _typeSerializer);
}
} | false | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Alternative to {@link #serializeAsField} that is used when a POJO
* is serialized as JSON Array; the difference is that no field names
* are written.
*
* @since 2.1
*/
public void serializeAsColumn(Object bean, JsonGenerator jgen, SerializerProvider prov)
throws Exception
{
Object value = get(bean);
if (value == null) { // nulls need specialized handling
if (_nullSerializer != null) {
_nullSerializer.serialize(null, jgen, prov);
} else { // can NOT suppress entries in tabular output
jgen.writeNull();
}
return;
}
// otherwise find serializer to use
JsonSerializer<Object> ser = _serializer;
if (ser == null) {
Class<?> cls = value.getClass();
PropertySerializerMap map = _dynamicSerializers;
ser = map.serializerFor(cls);
if (ser == null) {
ser = _findAndAddDynamic(map, cls, prov);
}
}
// and then see if we must suppress certain values (default, empty)
if (_suppressableValue != null) {
if (MARKER_FOR_EMPTY == _suppressableValue) {
if (ser.isEmpty(value)) { // can NOT suppress entries in tabular output
serializeAsPlaceholder(bean, jgen, prov);
return;
}
} else if (_suppressableValue.equals(value)) { // can NOT suppress entries in tabular output
serializeAsPlaceholder(bean, jgen, prov);
return;
}
}
// For non-nulls: simple check for direct cycles
if (value == bean) {
_handleSelfReference(bean, ser);
}
if (_typeSerializer == null) {
ser.serialize(value, jgen, prov);
} else {
ser.serializeWithType(value, jgen, prov, _typeSerializer);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
26 | 995c7866bed13d35c3ef41a9a0a83f7233f962837c274f5e560fa5a563038d73 | public String format(Date date) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Formats a <code>Date</code> object.</p>
*
* @param date the date to format
* @return the formatted string
*/
public String format(Date date) {
Calendar c = new GregorianCalendar(mTimeZone, mLocale);
c.setTime(date);
return applyRules(c, new StringBuffer(mMaxLengthEstimate)).toString();
}
```
| public String format(Date date) {
Calendar c = new GregorianCalendar(mTimeZone, mLocale);
c.setTime(date);
return applyRules(c, new StringBuffer(mMaxLengthEstimate)).toString();
} | false | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Formats a <code>Date</code> object.</p>
*
* @param date the date to format
* @return the formatted string
*/
public String format(Date date) {
Calendar c = new GregorianCalendar(mTimeZone, mLocale);
c.setTime(date);
return applyRules(c, new StringBuffer(mMaxLengthEstimate)).toString();
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
124 | 9966337b25cf46db62d8d28220be5adc4fa6de7ba0c4364e3028a8c353c7a53e | private boolean isSafeReplacement(Node node, Node replacement) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Checks name referenced in node to determine if it might have
* changed.
* @return Whether the replacement can be made.
*/
private boolean isSafeReplacement(Node node, Node replacement) {
// No checks are needed for simple names.
if (node.isName()) {
return true;
}
Preconditions.checkArgument(node.isGetProp());
node = node.getFirstChild();
if (node.isName()
&& isNameAssignedTo(node.getString(), replacement)) {
return false;
}
return true;
}
```
| private boolean isSafeReplacement(Node node, Node replacement) {
// No checks are needed for simple names.
if (node.isName()) {
return true;
}
Preconditions.checkArgument(node.isGetProp());
node = node.getFirstChild();
if (node.isName()
&& isNameAssignedTo(node.getString(), replacement)) {
return false;
}
return true;
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Checks name referenced in node to determine if it might have
* changed.
* @return Whether the replacement can be made.
*/
private boolean isSafeReplacement(Node node, Node replacement) {
// No checks are needed for simple names.
if (node.isName()) {
return true;
}
Preconditions.checkArgument(node.isGetProp());
node = node.getFirstChild();
if (node.isName()
&& isNameAssignedTo(node.getString(), replacement)) {
return false;
}
return true;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
83 | 9a51dbb937e2a59ef8aee47c3236ab6c36a8be4e6a1e16524aaebc53e97e1689 | @SuppressWarnings("unchecked")
@Override
public T deserialize(JsonParser p, DeserializationContext ctxt) throws IOException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/*
/**********************************************************
/* Deserializer implementations
/**********************************************************
*/
@SuppressWarnings("unchecked")
@Override
public T deserialize(JsonParser p, DeserializationContext ctxt) throws IOException
{
// 22-Sep-2012, tatu: For 2.1, use this new method, may force coercion:
String text = p.getValueAsString();
if (text != null) { // has String representation
if (text.length() == 0 || (text = text.trim()).length() == 0) {
// 04-Feb-2013, tatu: Usually should become null; but not always
return _deserializeFromEmptyString();
}
Exception cause = null;
try {
// 19-May-2017, tatu: Used to require non-null result (assuming `null`
// indicated error; but that seems wrong. Should be able to return
// `null` as value.
if (_deserialize(text, ctxt) != null) {
return _deserialize(text, ctxt);
}
} catch (IllegalArgumentException iae) {
cause = iae;
} catch (MalformedURLException me) {
cause = me;
}
String msg = "not a valid textual representation";
if (cause != null) {
String m2 = cause.getMessage();
if (m2 != null) {
msg = msg + ", problem: "+m2;
}
}
// 05-May-2016, tatu: Unlike most usage, this seems legit, so...
JsonMappingException e = ctxt.weirdStringException(text, _valueClass, msg);
if (cause != null) {
e.initCause(cause);
}
throw e;
// nothing to do here, yet? We'll fail anyway
}
JsonToken t = p.getCurrentToken();
// [databind#381]
if (t == JsonToken.START_ARRAY) {
return _deserializeFromArray(p, ctxt);
}
if (t == JsonToken.VALUE_EMBEDDED_OBJECT) {
// Trivial cases; null to null, instance of type itself returned as is
Object ob = p.getEmbeddedObject();
if (ob == null) {
return null;
}
if (_valueClass.isAssignableFrom(ob.getClass())) {
return (T) ob;
}
return _deserializeEmbedded(ob, ctxt);
}
return (T) ctxt.handleUnexpectedToken(_valueClass, p);
}
```
| @SuppressWarnings("unchecked")
@Override
public T deserialize(JsonParser p, DeserializationContext ctxt) throws IOException
{
// 22-Sep-2012, tatu: For 2.1, use this new method, may force coercion:
String text = p.getValueAsString();
if (text != null) { // has String representation
if (text.length() == 0 || (text = text.trim()).length() == 0) {
// 04-Feb-2013, tatu: Usually should become null; but not always
return _deserializeFromEmptyString();
}
Exception cause = null;
try {
// 19-May-2017, tatu: Used to require non-null result (assuming `null`
// indicated error; but that seems wrong. Should be able to return
// `null` as value.
if (_deserialize(text, ctxt) != null) {
return _deserialize(text, ctxt);
}
} catch (IllegalArgumentException iae) {
cause = iae;
} catch (MalformedURLException me) {
cause = me;
}
String msg = "not a valid textual representation";
if (cause != null) {
String m2 = cause.getMessage();
if (m2 != null) {
msg = msg + ", problem: "+m2;
}
}
// 05-May-2016, tatu: Unlike most usage, this seems legit, so...
JsonMappingException e = ctxt.weirdStringException(text, _valueClass, msg);
if (cause != null) {
e.initCause(cause);
}
throw e;
// nothing to do here, yet? We'll fail anyway
}
JsonToken t = p.getCurrentToken();
// [databind#381]
if (t == JsonToken.START_ARRAY) {
return _deserializeFromArray(p, ctxt);
}
if (t == JsonToken.VALUE_EMBEDDED_OBJECT) {
// Trivial cases; null to null, instance of type itself returned as is
Object ob = p.getEmbeddedObject();
if (ob == null) {
return null;
}
if (_valueClass.isAssignableFrom(ob.getClass())) {
return (T) ob;
}
return _deserializeEmbedded(ob, ctxt);
}
return (T) ctxt.handleUnexpectedToken(_valueClass, p);
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/*
/**********************************************************
/* Deserializer implementations
/**********************************************************
*/
@SuppressWarnings("unchecked")
@Override
public T deserialize(JsonParser p, DeserializationContext ctxt) throws IOException
{
// 22-Sep-2012, tatu: For 2.1, use this new method, may force coercion:
String text = p.getValueAsString();
if (text != null) { // has String representation
if (text.length() == 0 || (text = text.trim()).length() == 0) {
// 04-Feb-2013, tatu: Usually should become null; but not always
return _deserializeFromEmptyString();
}
Exception cause = null;
try {
// 19-May-2017, tatu: Used to require non-null result (assuming `null`
// indicated error; but that seems wrong. Should be able to return
// `null` as value.
if (_deserialize(text, ctxt) != null) {
return _deserialize(text, ctxt);
}
} catch (IllegalArgumentException iae) {
cause = iae;
} catch (MalformedURLException me) {
cause = me;
}
String msg = "not a valid textual representation";
if (cause != null) {
String m2 = cause.getMessage();
if (m2 != null) {
msg = msg + ", problem: "+m2;
}
}
// 05-May-2016, tatu: Unlike most usage, this seems legit, so...
JsonMappingException e = ctxt.weirdStringException(text, _valueClass, msg);
if (cause != null) {
e.initCause(cause);
}
throw e;
// nothing to do here, yet? We'll fail anyway
}
JsonToken t = p.getCurrentToken();
// [databind#381]
if (t == JsonToken.START_ARRAY) {
return _deserializeFromArray(p, ctxt);
}
if (t == JsonToken.VALUE_EMBEDDED_OBJECT) {
// Trivial cases; null to null, instance of type itself returned as is
Object ob = p.getEmbeddedObject();
if (ob == null) {
return null;
}
if (_valueClass.isAssignableFrom(ob.getClass())) {
return (T) ob;
}
return _deserializeEmbedded(ob, ctxt);
}
return (T) ctxt.handleUnexpectedToken(_valueClass, p);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
36 | 9aac5cd68a0809e2d40dc646789da0ac1a58ac0b1d15175b0184d3aaacccd868 | private boolean canInline(
Reference declaration,
Reference initialization,
Reference reference) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* @return true if the provided reference and declaration can be safely
* inlined according to our criteria
*/
private boolean canInline(
Reference declaration,
Reference initialization,
Reference reference) {
if (!isValidDeclaration(declaration)
|| !isValidInitialization(initialization)
|| !isValidReference(reference)) {
return false;
}
// If the value is read more than once, skip it.
// VAR declarations and EXPR_RESULT don't need the value, but other
// ASSIGN expressions parents do.
if (declaration != initialization &&
!initialization.getGrandparent().isExprResult()) {
return false;
}
// Be very conservative and do no cross control structures or
// scope boundaries
if (declaration.getBasicBlock() != initialization.getBasicBlock()
|| declaration.getBasicBlock() != reference.getBasicBlock()) {
return false;
}
// Do not inline into a call node. This would change
// the context in which it was being called. For example,
// var a = b.c;
// a();
// should not be inlined, because it calls a in the context of b
// rather than the context of the window.
// var a = b.c;
// f(a)
// is ok.
Node value = initialization.getAssignedValue();
Preconditions.checkState(value != null);
if (value.isGetProp()
&& reference.getParent().isCall()
&& reference.getParent().getFirstChild() == reference.getNode()) {
return false;
}
if (value.isFunction()) {
Node callNode = reference.getParent();
if (reference.getParent().isCall()) {
CodingConvention convention = compiler.getCodingConvention();
// Bug 2388531: Don't inline subclass definitions into class defining
// calls as this confused class removing logic.
SubclassRelationship relationship =
convention.getClassesDefinedByCall(callNode);
if (relationship != null) {
return false;
}
// issue 668: Don't inline singleton getter methods
// calls as this confused class removing logic.
}
}
return canMoveAggressively(value) ||
canMoveModerately(initialization, reference);
}
```
| private boolean canInline(
Reference declaration,
Reference initialization,
Reference reference) {
if (!isValidDeclaration(declaration)
|| !isValidInitialization(initialization)
|| !isValidReference(reference)) {
return false;
}
// If the value is read more than once, skip it.
// VAR declarations and EXPR_RESULT don't need the value, but other
// ASSIGN expressions parents do.
if (declaration != initialization &&
!initialization.getGrandparent().isExprResult()) {
return false;
}
// Be very conservative and do no cross control structures or
// scope boundaries
if (declaration.getBasicBlock() != initialization.getBasicBlock()
|| declaration.getBasicBlock() != reference.getBasicBlock()) {
return false;
}
// Do not inline into a call node. This would change
// the context in which it was being called. For example,
// var a = b.c;
// a();
// should not be inlined, because it calls a in the context of b
// rather than the context of the window.
// var a = b.c;
// f(a)
// is ok.
Node value = initialization.getAssignedValue();
Preconditions.checkState(value != null);
if (value.isGetProp()
&& reference.getParent().isCall()
&& reference.getParent().getFirstChild() == reference.getNode()) {
return false;
}
if (value.isFunction()) {
Node callNode = reference.getParent();
if (reference.getParent().isCall()) {
CodingConvention convention = compiler.getCodingConvention();
// Bug 2388531: Don't inline subclass definitions into class defining
// calls as this confused class removing logic.
SubclassRelationship relationship =
convention.getClassesDefinedByCall(callNode);
if (relationship != null) {
return false;
}
// issue 668: Don't inline singleton getter methods
// calls as this confused class removing logic.
}
}
return canMoveAggressively(value) ||
canMoveModerately(initialization, reference);
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* @return true if the provided reference and declaration can be safely
* inlined according to our criteria
*/
private boolean canInline(
Reference declaration,
Reference initialization,
Reference reference) {
if (!isValidDeclaration(declaration)
|| !isValidInitialization(initialization)
|| !isValidReference(reference)) {
return false;
}
// If the value is read more than once, skip it.
// VAR declarations and EXPR_RESULT don't need the value, but other
// ASSIGN expressions parents do.
if (declaration != initialization &&
!initialization.getGrandparent().isExprResult()) {
return false;
}
// Be very conservative and do no cross control structures or
// scope boundaries
if (declaration.getBasicBlock() != initialization.getBasicBlock()
|| declaration.getBasicBlock() != reference.getBasicBlock()) {
return false;
}
// Do not inline into a call node. This would change
// the context in which it was being called. For example,
// var a = b.c;
// a();
// should not be inlined, because it calls a in the context of b
// rather than the context of the window.
// var a = b.c;
// f(a)
// is ok.
Node value = initialization.getAssignedValue();
Preconditions.checkState(value != null);
if (value.isGetProp()
&& reference.getParent().isCall()
&& reference.getParent().getFirstChild() == reference.getNode()) {
return false;
}
if (value.isFunction()) {
Node callNode = reference.getParent();
if (reference.getParent().isCall()) {
CodingConvention convention = compiler.getCodingConvention();
// Bug 2388531: Don't inline subclass definitions into class defining
// calls as this confused class removing logic.
SubclassRelationship relationship =
convention.getClassesDefinedByCall(callNode);
if (relationship != null) {
return false;
}
// issue 668: Don't inline singleton getter methods
// calls as this confused class removing logic.
}
}
return canMoveAggressively(value) ||
canMoveModerately(initialization, reference);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
75 | 9ab23e6359c272e376e6d2d2bdccb164746480e0dd87547ccbe979936c51aab0 | final void html(final Appendable accum, final Document.OutputSettings out) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
final void html(final Appendable accum, final Document.OutputSettings out) throws IOException {
final int sz = size;
for (int i = 0; i < sz; i++) {
// inlined from Attribute.html()
final String key = keys[i];
final String val = vals[i];
accum.append(' ').append(key);
// collapse checked=null, checked="", checked=checked; write out others
if (!(out.syntax() == Document.OutputSettings.Syntax.html
&& (val == null || val.equals(key) && Attribute.isBooleanAttribute(key)))) {
accum.append("=\"");
Entities.escape(accum, val == null ? EmptyString : val, out, true, false, false);
accum.append('"');
}
}
}
```
| final void html(final Appendable accum, final Document.OutputSettings out) throws IOException {
final int sz = size;
for (int i = 0; i < sz; i++) {
// inlined from Attribute.html()
final String key = keys[i];
final String val = vals[i];
accum.append(' ').append(key);
// collapse checked=null, checked="", checked=checked; write out others
if (!(out.syntax() == Document.OutputSettings.Syntax.html
&& (val == null || val.equals(key) && Attribute.isBooleanAttribute(key)))) {
accum.append("=\"");
Entities.escape(accum, val == null ? EmptyString : val, out, true, false, false);
accum.append('"');
}
}
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
final void html(final Appendable accum, final Document.OutputSettings out) throws IOException {
final int sz = size;
for (int i = 0; i < sz; i++) {
// inlined from Attribute.html()
final String key = keys[i];
final String val = vals[i];
accum.append(' ').append(key);
// collapse checked=null, checked="", checked=checked; write out others
if (!(out.syntax() == Document.OutputSettings.Syntax.html
&& (val == null || val.equals(key) && Attribute.isBooleanAttribute(key)))) {
accum.append("=\"");
Entities.escape(accum, val == null ? EmptyString : val, out, true, false, false);
accum.append('"');
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
78 | 9ab29ce73651ccd13990e28d82c5108259db40acd299380e1e3833f7bee9a8ad | private Node performArithmeticOp(int opType, Node left, Node right) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Try to fold arithmetic binary operators
*/
private Node performArithmeticOp(int opType, Node left, Node right) {
// Unlike other operations, ADD operands are not always converted
// to Number.
if (opType == Token.ADD
&& (NodeUtil.mayBeString(left, false)
|| NodeUtil.mayBeString(right, false))) {
return null;
}
double result;
// TODO(johnlenz): Handle NaN with unknown value. BIT ops convert NaN
// to zero so this is a little akward here.
Double lValObj = NodeUtil.getNumberValue(left);
if (lValObj == null) {
return null;
}
Double rValObj = NodeUtil.getNumberValue(right);
if (rValObj == null) {
return null;
}
double lval = lValObj;
double rval = rValObj;
switch (opType) {
case Token.BITAND:
result = ScriptRuntime.toInt32(lval) & ScriptRuntime.toInt32(rval);
break;
case Token.BITOR:
result = ScriptRuntime.toInt32(lval) | ScriptRuntime.toInt32(rval);
break;
case Token.BITXOR:
result = ScriptRuntime.toInt32(lval) ^ ScriptRuntime.toInt32(rval);
break;
case Token.ADD:
result = lval + rval;
break;
case Token.SUB:
result = lval - rval;
break;
case Token.MUL:
result = lval * rval;
break;
case Token.MOD:
if (rval == 0) {
return null;
}
result = lval % rval;
break;
case Token.DIV:
if (rval == 0) {
return null;
}
result = lval / rval;
break;
default:
throw new Error("Unexpected arithmetic operator");
}
// TODO(johnlenz): consider removing the result length check.
// length of the left and right value plus 1 byte for the operator.
if (String.valueOf(result).length() <=
String.valueOf(lval).length() + String.valueOf(rval).length() + 1 &&
// Do not try to fold arithmetic for numbers > 2^53. After that
// point, fixed-point math starts to break down and become inaccurate.
Math.abs(result) <= MAX_FOLD_NUMBER) {
Node newNumber = Node.newNumber(result);
return newNumber;
} else if (Double.isNaN(result)) {
return Node.newString(Token.NAME, "NaN");
} else if (result == Double.POSITIVE_INFINITY) {
return Node.newString(Token.NAME, "Infinity");
} else if (result == Double.NEGATIVE_INFINITY) {
return new Node(Token.NEG, Node.newString(Token.NAME, "Infinity"));
}
return null;
}
```
| private Node performArithmeticOp(int opType, Node left, Node right) {
// Unlike other operations, ADD operands are not always converted
// to Number.
if (opType == Token.ADD
&& (NodeUtil.mayBeString(left, false)
|| NodeUtil.mayBeString(right, false))) {
return null;
}
double result;
// TODO(johnlenz): Handle NaN with unknown value. BIT ops convert NaN
// to zero so this is a little akward here.
Double lValObj = NodeUtil.getNumberValue(left);
if (lValObj == null) {
return null;
}
Double rValObj = NodeUtil.getNumberValue(right);
if (rValObj == null) {
return null;
}
double lval = lValObj;
double rval = rValObj;
switch (opType) {
case Token.BITAND:
result = ScriptRuntime.toInt32(lval) & ScriptRuntime.toInt32(rval);
break;
case Token.BITOR:
result = ScriptRuntime.toInt32(lval) | ScriptRuntime.toInt32(rval);
break;
case Token.BITXOR:
result = ScriptRuntime.toInt32(lval) ^ ScriptRuntime.toInt32(rval);
break;
case Token.ADD:
result = lval + rval;
break;
case Token.SUB:
result = lval - rval;
break;
case Token.MUL:
result = lval * rval;
break;
case Token.MOD:
if (rval == 0) {
return null;
}
result = lval % rval;
break;
case Token.DIV:
if (rval == 0) {
return null;
}
result = lval / rval;
break;
default:
throw new Error("Unexpected arithmetic operator");
}
// TODO(johnlenz): consider removing the result length check.
// length of the left and right value plus 1 byte for the operator.
if (String.valueOf(result).length() <=
String.valueOf(lval).length() + String.valueOf(rval).length() + 1 &&
// Do not try to fold arithmetic for numbers > 2^53. After that
// point, fixed-point math starts to break down and become inaccurate.
Math.abs(result) <= MAX_FOLD_NUMBER) {
Node newNumber = Node.newNumber(result);
return newNumber;
} else if (Double.isNaN(result)) {
return Node.newString(Token.NAME, "NaN");
} else if (result == Double.POSITIVE_INFINITY) {
return Node.newString(Token.NAME, "Infinity");
} else if (result == Double.NEGATIVE_INFINITY) {
return new Node(Token.NEG, Node.newString(Token.NAME, "Infinity"));
}
return null;
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Try to fold arithmetic binary operators
*/
private Node performArithmeticOp(int opType, Node left, Node right) {
// Unlike other operations, ADD operands are not always converted
// to Number.
if (opType == Token.ADD
&& (NodeUtil.mayBeString(left, false)
|| NodeUtil.mayBeString(right, false))) {
return null;
}
double result;
// TODO(johnlenz): Handle NaN with unknown value. BIT ops convert NaN
// to zero so this is a little akward here.
Double lValObj = NodeUtil.getNumberValue(left);
if (lValObj == null) {
return null;
}
Double rValObj = NodeUtil.getNumberValue(right);
if (rValObj == null) {
return null;
}
double lval = lValObj;
double rval = rValObj;
switch (opType) {
case Token.BITAND:
result = ScriptRuntime.toInt32(lval) & ScriptRuntime.toInt32(rval);
break;
case Token.BITOR:
result = ScriptRuntime.toInt32(lval) | ScriptRuntime.toInt32(rval);
break;
case Token.BITXOR:
result = ScriptRuntime.toInt32(lval) ^ ScriptRuntime.toInt32(rval);
break;
case Token.ADD:
result = lval + rval;
break;
case Token.SUB:
result = lval - rval;
break;
case Token.MUL:
result = lval * rval;
break;
case Token.MOD:
if (rval == 0) {
return null;
}
result = lval % rval;
break;
case Token.DIV:
if (rval == 0) {
return null;
}
result = lval / rval;
break;
default:
throw new Error("Unexpected arithmetic operator");
}
// TODO(johnlenz): consider removing the result length check.
// length of the left and right value plus 1 byte for the operator.
if (String.valueOf(result).length() <=
String.valueOf(lval).length() + String.valueOf(rval).length() + 1 &&
// Do not try to fold arithmetic for numbers > 2^53. After that
// point, fixed-point math starts to break down and become inaccurate.
Math.abs(result) <= MAX_FOLD_NUMBER) {
Node newNumber = Node.newNumber(result);
return newNumber;
} else if (Double.isNaN(result)) {
return Node.newString(Token.NAME, "NaN");
} else if (result == Double.POSITIVE_INFINITY) {
return Node.newString(Token.NAME, "Infinity");
} else if (result == Double.NEGATIVE_INFINITY) {
return new Node(Token.NEG, Node.newString(Token.NAME, "Infinity"));
}
return null;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
166 | 9ae0b361517ddf282b1eecaedcea4d6aaf54b54a312a50cc395d0d9636ff526e | @Override
public void matchConstraint(JSType constraint) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public void matchConstraint(JSType constraint) {
// We only want to match constraints on anonymous types.
if (hasReferenceName()) {
return;
}
// Handle the case where the constraint object is a record type.
//
// param constraint {{prop: (number|undefined)}}
// function f(constraint) {}
// f({});
//
// We want to modify the object literal to match the constraint, by
// taking any each property on the record and trying to match
// properties on this object.
if (constraint.isRecordType()) {
matchRecordTypeConstraint(constraint.toObjectType());
} else if (constraint.isUnionType()) {
for (JSType alt : constraint.toMaybeUnionType().getAlternates()) {
if (alt.isRecordType()) {
matchRecordTypeConstraint(alt.toObjectType());
}
}
}
}
```
| @Override
public void matchConstraint(JSType constraint) {
// We only want to match constraints on anonymous types.
if (hasReferenceName()) {
return;
}
// Handle the case where the constraint object is a record type.
//
// param constraint {{prop: (number|undefined)}}
// function f(constraint) {}
// f({});
//
// We want to modify the object literal to match the constraint, by
// taking any each property on the record and trying to match
// properties on this object.
if (constraint.isRecordType()) {
matchRecordTypeConstraint(constraint.toObjectType());
} else if (constraint.isUnionType()) {
for (JSType alt : constraint.toMaybeUnionType().getAlternates()) {
if (alt.isRecordType()) {
matchRecordTypeConstraint(alt.toObjectType());
}
}
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public void matchConstraint(JSType constraint) {
// We only want to match constraints on anonymous types.
if (hasReferenceName()) {
return;
}
// Handle the case where the constraint object is a record type.
//
// param constraint {{prop: (number|undefined)}}
// function f(constraint) {}
// f({});
//
// We want to modify the object literal to match the constraint, by
// taking any each property on the record and trying to match
// properties on this object.
if (constraint.isRecordType()) {
matchRecordTypeConstraint(constraint.toObjectType());
} else if (constraint.isUnionType()) {
for (JSType alt : constraint.toMaybeUnionType().getAlternates()) {
if (alt.isRecordType()) {
matchRecordTypeConstraint(alt.toObjectType());
}
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
51 | 9ae1cc5c35de75e83c99c41b42eeafad6d7a97720c1336e784eb8483f1f3324e | protected final double doSolve() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/** {@inheritDoc} */
protected final double doSolve() {
// Get initial solution
double x0 = getMin();
double x1 = getMax();
double f0 = computeObjectiveValue(x0);
double f1 = computeObjectiveValue(x1);
// If one of the bounds is the exact root, return it. Since these are
// not under-approximations or over-approximations, we can return them
// regardless of the allowed solutions.
if (f0 == 0.0) {
return x0;
}
if (f1 == 0.0) {
return x1;
}
// Verify bracketing of initial solution.
verifyBracketing(x0, x1);
// Get accuracies.
final double ftol = getFunctionValueAccuracy();
final double atol = getAbsoluteAccuracy();
final double rtol = getRelativeAccuracy();
// Keep track of inverted intervals, meaning that the left bound is
// larger than the right bound.
boolean inverted = false;
// Keep finding better approximations.
while (true) {
// Calculate the next approximation.
final double x = x1 - ((f1 * (x1 - x0)) / (f1 - f0));
final double fx = computeObjectiveValue(x);
// If the new approximation is the exact root, return it. Since
// this is not an under-approximation or an over-approximation,
// we can return it regardless of the allowed solutions.
if (fx == 0.0) {
return x;
}
// Update the bounds with the new approximation.
if (f1 * fx < 0) {
// The value of x1 has switched to the other bound, thus inverting
// the interval.
x0 = x1;
f0 = f1;
inverted = !inverted;
} else {
switch (method) {
case ILLINOIS:
f0 *= 0.5;
break;
case PEGASUS:
f0 *= f1 / (f1 + fx);
break;
// Update formula cannot make any progress: Update the
// search interval.
default:
// Should never happen.
}
}
// Update from [x0, x1] to [x0, x].
x1 = x;
f1 = fx;
// If the function value of the last approximation is too small,
// given the function value accuracy, then we can't get closer to
// the root than we already are.
if (FastMath.abs(f1) <= ftol) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
if (inverted) {
return x1;
}
break;
case RIGHT_SIDE:
if (!inverted) {
return x1;
}
break;
case BELOW_SIDE:
if (f1 <= 0) {
return x1;
}
break;
case ABOVE_SIDE:
if (f1 >= 0) {
return x1;
}
break;
default:
throw new MathInternalError();
}
}
// If the current interval is within the given accuracies, we
// are satisfied with the current approximation.
if (FastMath.abs(x1 - x0) < FastMath.max(rtol * FastMath.abs(x1),
atol)) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
return inverted ? x1 : x0;
case RIGHT_SIDE:
return inverted ? x0 : x1;
case BELOW_SIDE:
return (f1 <= 0) ? x1 : x0;
case ABOVE_SIDE:
return (f1 >= 0) ? x1 : x0;
default:
throw new MathInternalError();
}
}
}
}
```
| protected final double doSolve() {
// Get initial solution
double x0 = getMin();
double x1 = getMax();
double f0 = computeObjectiveValue(x0);
double f1 = computeObjectiveValue(x1);
// If one of the bounds is the exact root, return it. Since these are
// not under-approximations or over-approximations, we can return them
// regardless of the allowed solutions.
if (f0 == 0.0) {
return x0;
}
if (f1 == 0.0) {
return x1;
}
// Verify bracketing of initial solution.
verifyBracketing(x0, x1);
// Get accuracies.
final double ftol = getFunctionValueAccuracy();
final double atol = getAbsoluteAccuracy();
final double rtol = getRelativeAccuracy();
// Keep track of inverted intervals, meaning that the left bound is
// larger than the right bound.
boolean inverted = false;
// Keep finding better approximations.
while (true) {
// Calculate the next approximation.
final double x = x1 - ((f1 * (x1 - x0)) / (f1 - f0));
final double fx = computeObjectiveValue(x);
// If the new approximation is the exact root, return it. Since
// this is not an under-approximation or an over-approximation,
// we can return it regardless of the allowed solutions.
if (fx == 0.0) {
return x;
}
// Update the bounds with the new approximation.
if (f1 * fx < 0) {
// The value of x1 has switched to the other bound, thus inverting
// the interval.
x0 = x1;
f0 = f1;
inverted = !inverted;
} else {
switch (method) {
case ILLINOIS:
f0 *= 0.5;
break;
case PEGASUS:
f0 *= f1 / (f1 + fx);
break;
// Update formula cannot make any progress: Update the
// search interval.
default:
// Should never happen.
}
}
// Update from [x0, x1] to [x0, x].
x1 = x;
f1 = fx;
// If the function value of the last approximation is too small,
// given the function value accuracy, then we can't get closer to
// the root than we already are.
if (FastMath.abs(f1) <= ftol) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
if (inverted) {
return x1;
}
break;
case RIGHT_SIDE:
if (!inverted) {
return x1;
}
break;
case BELOW_SIDE:
if (f1 <= 0) {
return x1;
}
break;
case ABOVE_SIDE:
if (f1 >= 0) {
return x1;
}
break;
default:
throw new MathInternalError();
}
}
// If the current interval is within the given accuracies, we
// are satisfied with the current approximation.
if (FastMath.abs(x1 - x0) < FastMath.max(rtol * FastMath.abs(x1),
atol)) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
return inverted ? x1 : x0;
case RIGHT_SIDE:
return inverted ? x0 : x1;
case BELOW_SIDE:
return (f1 <= 0) ? x1 : x0;
case ABOVE_SIDE:
return (f1 >= 0) ? x1 : x0;
default:
throw new MathInternalError();
}
}
}
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/** {@inheritDoc} */
protected final double doSolve() {
// Get initial solution
double x0 = getMin();
double x1 = getMax();
double f0 = computeObjectiveValue(x0);
double f1 = computeObjectiveValue(x1);
// If one of the bounds is the exact root, return it. Since these are
// not under-approximations or over-approximations, we can return them
// regardless of the allowed solutions.
if (f0 == 0.0) {
return x0;
}
if (f1 == 0.0) {
return x1;
}
// Verify bracketing of initial solution.
verifyBracketing(x0, x1);
// Get accuracies.
final double ftol = getFunctionValueAccuracy();
final double atol = getAbsoluteAccuracy();
final double rtol = getRelativeAccuracy();
// Keep track of inverted intervals, meaning that the left bound is
// larger than the right bound.
boolean inverted = false;
// Keep finding better approximations.
while (true) {
// Calculate the next approximation.
final double x = x1 - ((f1 * (x1 - x0)) / (f1 - f0));
final double fx = computeObjectiveValue(x);
// If the new approximation is the exact root, return it. Since
// this is not an under-approximation or an over-approximation,
// we can return it regardless of the allowed solutions.
if (fx == 0.0) {
return x;
}
// Update the bounds with the new approximation.
if (f1 * fx < 0) {
// The value of x1 has switched to the other bound, thus inverting
// the interval.
x0 = x1;
f0 = f1;
inverted = !inverted;
} else {
switch (method) {
case ILLINOIS:
f0 *= 0.5;
break;
case PEGASUS:
f0 *= f1 / (f1 + fx);
break;
// Update formula cannot make any progress: Update the
// search interval.
default:
// Should never happen.
}
}
// Update from [x0, x1] to [x0, x].
x1 = x;
f1 = fx;
// If the function value of the last approximation is too small,
// given the function value accuracy, then we can't get closer to
// the root than we already are.
if (FastMath.abs(f1) <= ftol) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
if (inverted) {
return x1;
}
break;
case RIGHT_SIDE:
if (!inverted) {
return x1;
}
break;
case BELOW_SIDE:
if (f1 <= 0) {
return x1;
}
break;
case ABOVE_SIDE:
if (f1 >= 0) {
return x1;
}
break;
default:
throw new MathInternalError();
}
}
// If the current interval is within the given accuracies, we
// are satisfied with the current approximation.
if (FastMath.abs(x1 - x0) < FastMath.max(rtol * FastMath.abs(x1),
atol)) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
return inverted ? x1 : x0;
case RIGHT_SIDE:
return inverted ? x0 : x1;
case BELOW_SIDE:
return (f1 <= 0) ? x1 : x0;
case ABOVE_SIDE:
return (f1 >= 0) ? x1 : x0;
default:
throw new MathInternalError();
}
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
19 | 9b4ea2dc5cb4f4a1c544f9b511b889aae1e33e64d42c8dc9ba4931b8a09ee9a2 | private JavaType _mapType(Class<?> rawClass)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private JavaType _mapType(Class<?> rawClass)
{
// 28-May-2015, tatu: Properties are special, as per [databind#810]
if (rawClass == Properties.class) {
return MapType.construct(rawClass, CORE_TYPE_STRING, CORE_TYPE_STRING);
}
JavaType[] typeParams = findTypeParameters(rawClass, Map.class);
// ok to have no types ("raw")
if (typeParams == null) {
return MapType.construct(rawClass, _unknownType(), _unknownType());
}
// but exactly 2 types if any found
if (typeParams.length != 2) {
throw new IllegalArgumentException("Strange Map type "+rawClass.getName()+": can not determine type parameters");
}
return MapType.construct(rawClass, typeParams[0], typeParams[1]);
}
```
| private JavaType _mapType(Class<?> rawClass)
{
// 28-May-2015, tatu: Properties are special, as per [databind#810]
if (rawClass == Properties.class) {
return MapType.construct(rawClass, CORE_TYPE_STRING, CORE_TYPE_STRING);
}
JavaType[] typeParams = findTypeParameters(rawClass, Map.class);
// ok to have no types ("raw")
if (typeParams == null) {
return MapType.construct(rawClass, _unknownType(), _unknownType());
}
// but exactly 2 types if any found
if (typeParams.length != 2) {
throw new IllegalArgumentException("Strange Map type "+rawClass.getName()+": can not determine type parameters");
}
return MapType.construct(rawClass, typeParams[0], typeParams[1]);
} | false | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private JavaType _mapType(Class<?> rawClass)
{
// 28-May-2015, tatu: Properties are special, as per [databind#810]
if (rawClass == Properties.class) {
return MapType.construct(rawClass, CORE_TYPE_STRING, CORE_TYPE_STRING);
}
JavaType[] typeParams = findTypeParameters(rawClass, Map.class);
// ok to have no types ("raw")
if (typeParams == null) {
return MapType.construct(rawClass, _unknownType(), _unknownType());
}
// but exactly 2 types if any found
if (typeParams.length != 2) {
throw new IllegalArgumentException("Strange Map type "+rawClass.getName()+": can not determine type parameters");
}
return MapType.construct(rawClass, typeParams[0], typeParams[1]);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
23 | 9b619a8d6a2213732832fb48233828f926bc5db24c53f5e5fbd17e1340878cae | @Override
public DefaultPrettyPrinter createInstance() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/*
/**********************************************************
/* Instantiatable impl
/**********************************************************
*/
@Override
public DefaultPrettyPrinter createInstance() {
if (getClass() != DefaultPrettyPrinter.class) { // since 2.10
throw new IllegalStateException("Failed `createInstance()`: "+getClass().getName()
+" does not override method; it has to");
}
return new DefaultPrettyPrinter(this);
}
```
| @Override
public DefaultPrettyPrinter createInstance() {
if (getClass() != DefaultPrettyPrinter.class) { // since 2.10
throw new IllegalStateException("Failed `createInstance()`: "+getClass().getName()
+" does not override method; it has to");
}
return new DefaultPrettyPrinter(this);
} | false | JacksonCore | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/*
/**********************************************************
/* Instantiatable impl
/**********************************************************
*/
@Override
public DefaultPrettyPrinter createInstance() {
if (getClass() != DefaultPrettyPrinter.class) { // since 2.10
throw new IllegalStateException("Failed `createInstance()`: "+getClass().getName()
+" does not override method; it has to");
}
return new DefaultPrettyPrinter(this);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
116 | 9b651e5c37b2b645bbce0ed6616ea8744350011234a4fa086eedc8a1e70abcd6 | private CanInlineResult canInlineReferenceDirectly(
Node callNode, Node fnNode) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Determines whether a function can be inlined at a particular call site.
* There are several criteria that the function and reference must hold in
* order for the functions to be inlined:
* 1) If a call's arguments have side effects,
* the corresponding argument in the function must only be referenced once.
* For instance, this will not be inlined:
* <pre>
* function foo(a) { return a + a }
* x = foo(i++);
* </pre>
*/
private CanInlineResult canInlineReferenceDirectly(
Node callNode, Node fnNode) {
if (!isDirectCallNodeReplacementPossible(fnNode)) {
return CanInlineResult.NO;
}
Node block = fnNode.getLastChild();
boolean hasSideEffects = false; // empty function case
if (block.hasChildren()) {
Preconditions.checkState(block.hasOneChild());
Node stmt = block.getFirstChild();
if (stmt.isReturn()) {
hasSideEffects = NodeUtil.mayHaveSideEffects(
stmt.getFirstChild(), compiler);
}
}
// CALL NODE: [ NAME, ARG1, ARG2, ... ]
Node cArg = callNode.getFirstChild().getNext();
// Functions called via 'call' and 'apply' have a this-object as
// the first parameter, but this is not part of the called function's
// parameter list.
if (!callNode.getFirstChild().isName()) {
if (NodeUtil.isFunctionObjectCall(callNode)) {
// TODO(johnlenz): Support replace this with a value.
if (cArg == null || !cArg.isThis()) {
return CanInlineResult.NO;
}
cArg = cArg.getNext();
} else {
// ".apply" call should be filtered before this.
Preconditions.checkState(!NodeUtil.isFunctionObjectApply(callNode));
}
}
// FUNCTION NODE -> LP NODE: [ ARG1, ARG2, ... ]
Node fnParam = NodeUtil.getFunctionParameters(fnNode).getFirstChild();
while (cArg != null || fnParam != null) {
// For each named parameter check if a mutable argument use more than one.
if (fnParam != null) {
if (cArg != null) {
if (hasSideEffects && NodeUtil.canBeSideEffected(cArg)) {
return CanInlineResult.NO;
}
// Check for arguments that are evaluated more than once.
// Note: Unlike block inlining, there it is not possible that a
// parameter reference will be in a loop.
if (NodeUtil.mayEffectMutableState(cArg, compiler)
&& NodeUtil.getNameReferenceCount(
block, fnParam.getString()) > 1) {
return CanInlineResult.NO;
}
}
// Move to the next name.
fnParam = fnParam.getNext();
}
// For every call argument check for side-effects, even if there
// isn't a named parameter to match.
if (cArg != null) {
if (NodeUtil.mayHaveSideEffects(cArg, compiler)) {
return CanInlineResult.NO;
}
cArg = cArg.getNext();
}
}
return CanInlineResult.YES;
}
```
| private CanInlineResult canInlineReferenceDirectly(
Node callNode, Node fnNode) {
if (!isDirectCallNodeReplacementPossible(fnNode)) {
return CanInlineResult.NO;
}
Node block = fnNode.getLastChild();
boolean hasSideEffects = false; // empty function case
if (block.hasChildren()) {
Preconditions.checkState(block.hasOneChild());
Node stmt = block.getFirstChild();
if (stmt.isReturn()) {
hasSideEffects = NodeUtil.mayHaveSideEffects(
stmt.getFirstChild(), compiler);
}
}
// CALL NODE: [ NAME, ARG1, ARG2, ... ]
Node cArg = callNode.getFirstChild().getNext();
// Functions called via 'call' and 'apply' have a this-object as
// the first parameter, but this is not part of the called function's
// parameter list.
if (!callNode.getFirstChild().isName()) {
if (NodeUtil.isFunctionObjectCall(callNode)) {
// TODO(johnlenz): Support replace this with a value.
if (cArg == null || !cArg.isThis()) {
return CanInlineResult.NO;
}
cArg = cArg.getNext();
} else {
// ".apply" call should be filtered before this.
Preconditions.checkState(!NodeUtil.isFunctionObjectApply(callNode));
}
}
// FUNCTION NODE -> LP NODE: [ ARG1, ARG2, ... ]
Node fnParam = NodeUtil.getFunctionParameters(fnNode).getFirstChild();
while (cArg != null || fnParam != null) {
// For each named parameter check if a mutable argument use more than one.
if (fnParam != null) {
if (cArg != null) {
if (hasSideEffects && NodeUtil.canBeSideEffected(cArg)) {
return CanInlineResult.NO;
}
// Check for arguments that are evaluated more than once.
// Note: Unlike block inlining, there it is not possible that a
// parameter reference will be in a loop.
if (NodeUtil.mayEffectMutableState(cArg, compiler)
&& NodeUtil.getNameReferenceCount(
block, fnParam.getString()) > 1) {
return CanInlineResult.NO;
}
}
// Move to the next name.
fnParam = fnParam.getNext();
}
// For every call argument check for side-effects, even if there
// isn't a named parameter to match.
if (cArg != null) {
if (NodeUtil.mayHaveSideEffects(cArg, compiler)) {
return CanInlineResult.NO;
}
cArg = cArg.getNext();
}
}
return CanInlineResult.YES;
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Determines whether a function can be inlined at a particular call site.
* There are several criteria that the function and reference must hold in
* order for the functions to be inlined:
* 1) If a call's arguments have side effects,
* the corresponding argument in the function must only be referenced once.
* For instance, this will not be inlined:
* <pre>
* function foo(a) { return a + a }
* x = foo(i++);
* </pre>
*/
private CanInlineResult canInlineReferenceDirectly(
Node callNode, Node fnNode) {
if (!isDirectCallNodeReplacementPossible(fnNode)) {
return CanInlineResult.NO;
}
Node block = fnNode.getLastChild();
boolean hasSideEffects = false; // empty function case
if (block.hasChildren()) {
Preconditions.checkState(block.hasOneChild());
Node stmt = block.getFirstChild();
if (stmt.isReturn()) {
hasSideEffects = NodeUtil.mayHaveSideEffects(
stmt.getFirstChild(), compiler);
}
}
// CALL NODE: [ NAME, ARG1, ARG2, ... ]
Node cArg = callNode.getFirstChild().getNext();
// Functions called via 'call' and 'apply' have a this-object as
// the first parameter, but this is not part of the called function's
// parameter list.
if (!callNode.getFirstChild().isName()) {
if (NodeUtil.isFunctionObjectCall(callNode)) {
// TODO(johnlenz): Support replace this with a value.
if (cArg == null || !cArg.isThis()) {
return CanInlineResult.NO;
}
cArg = cArg.getNext();
} else {
// ".apply" call should be filtered before this.
Preconditions.checkState(!NodeUtil.isFunctionObjectApply(callNode));
}
}
// FUNCTION NODE -> LP NODE: [ ARG1, ARG2, ... ]
Node fnParam = NodeUtil.getFunctionParameters(fnNode).getFirstChild();
while (cArg != null || fnParam != null) {
// For each named parameter check if a mutable argument use more than one.
if (fnParam != null) {
if (cArg != null) {
if (hasSideEffects && NodeUtil.canBeSideEffected(cArg)) {
return CanInlineResult.NO;
}
// Check for arguments that are evaluated more than once.
// Note: Unlike block inlining, there it is not possible that a
// parameter reference will be in a loop.
if (NodeUtil.mayEffectMutableState(cArg, compiler)
&& NodeUtil.getNameReferenceCount(
block, fnParam.getString()) > 1) {
return CanInlineResult.NO;
}
}
// Move to the next name.
fnParam = fnParam.getNext();
}
// For every call argument check for side-effects, even if there
// isn't a named parameter to match.
if (cArg != null) {
if (NodeUtil.mayHaveSideEffects(cArg, compiler)) {
return CanInlineResult.NO;
}
cArg = cArg.getNext();
}
}
return CanInlineResult.YES;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
53 | 9bdaca10fba857055ccde4e1ed4e771b0bd868f098727430cf9dccfb773ed2e0 | private static void modify(Calendar val, int field, boolean round) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Internal calculation method.</p>
*
* @param val the calendar
* @param field the field constant
* @param round true to round, false to truncate
* @throws ArithmeticException if the year is over 280 million
*/
//-----------------------------------------------------------------------
private static void modify(Calendar val, int field, boolean round) {
if (val.get(Calendar.YEAR) > 280000000) {
throw new ArithmeticException("Calendar value too large for accurate calculations");
}
if (field == Calendar.MILLISECOND) {
return;
}
// ----------------- Fix for LANG-59 ---------------------- START ---------------
// see http://issues.apache.org/jira/browse/LANG-59
//
// Manually truncate milliseconds, seconds and minutes, rather than using
// Calendar methods.
Date date = val.getTime();
long time = date.getTime();
boolean done = false;
// truncate milliseconds
int millisecs = val.get(Calendar.MILLISECOND);
if (!round || millisecs < 500) {
time = time - millisecs;
if (field == Calendar.SECOND) {
done = true;
}
}
// truncate seconds
int seconds = val.get(Calendar.SECOND);
if (!done && (!round || seconds < 30)) {
time = time - (seconds * 1000L);
if (field == Calendar.MINUTE) {
done = true;
}
}
// truncate minutes
int minutes = val.get(Calendar.MINUTE);
if (!done && (!round || minutes < 30)) {
time = time - (minutes * 60000L);
}
// reset time
if (date.getTime() != time) {
date.setTime(time);
val.setTime(date);
}
// ----------------- Fix for LANG-59 ----------------------- END ----------------
boolean roundUp = false;
for (int i = 0; i < fields.length; i++) {
for (int j = 0; j < fields[i].length; j++) {
if (fields[i][j] == field) {
//This is our field... we stop looping
if (round && roundUp) {
if (field == DateUtils.SEMI_MONTH) {
//This is a special case that's hard to generalize
//If the date is 1, we round up to 16, otherwise
// we subtract 15 days and add 1 month
if (val.get(Calendar.DATE) == 1) {
val.add(Calendar.DATE, 15);
} else {
val.add(Calendar.DATE, -15);
val.add(Calendar.MONTH, 1);
}
} else {
//We need at add one to this field since the
// last number causes us to round up
val.add(fields[i][0], 1);
}
}
return;
}
}
//We have various fields that are not easy roundings
int offset = 0;
boolean offsetSet = false;
//These are special types of fields that require different rounding rules
switch (field) {
case DateUtils.SEMI_MONTH:
if (fields[i][0] == Calendar.DATE) {
//If we're going to drop the DATE field's value,
// we want to do this our own way.
//We need to subtrace 1 since the date has a minimum of 1
offset = val.get(Calendar.DATE) - 1;
//If we're above 15 days adjustment, that means we're in the
// bottom half of the month and should stay accordingly.
if (offset >= 15) {
offset -= 15;
}
//Record whether we're in the top or bottom half of that range
roundUp = offset > 7;
offsetSet = true;
}
break;
case Calendar.AM_PM:
if (fields[i][0] == Calendar.HOUR_OF_DAY) {
//If we're going to drop the HOUR field's value,
// we want to do this our own way.
offset = val.get(Calendar.HOUR_OF_DAY);
if (offset >= 12) {
offset -= 12;
}
roundUp = offset > 6;
offsetSet = true;
}
break;
}
if (!offsetSet) {
int min = val.getActualMinimum(fields[i][0]);
int max = val.getActualMaximum(fields[i][0]);
//Calculate the offset from the minimum allowed value
offset = val.get(fields[i][0]) - min;
//Set roundUp if this is more than half way between the minimum and maximum
roundUp = offset > ((max - min) / 2);
}
//We need to remove this field
if (offset != 0) {
val.set(fields[i][0], val.get(fields[i][0]) - offset);
}
}
throw new IllegalArgumentException("The field " + field + " is not supported");
}
```
| private static void modify(Calendar val, int field, boolean round) {
if (val.get(Calendar.YEAR) > 280000000) {
throw new ArithmeticException("Calendar value too large for accurate calculations");
}
if (field == Calendar.MILLISECOND) {
return;
}
// ----------------- Fix for LANG-59 ---------------------- START ---------------
// see http://issues.apache.org/jira/browse/LANG-59
//
// Manually truncate milliseconds, seconds and minutes, rather than using
// Calendar methods.
Date date = val.getTime();
long time = date.getTime();
boolean done = false;
// truncate milliseconds
int millisecs = val.get(Calendar.MILLISECOND);
if (!round || millisecs < 500) {
time = time - millisecs;
if (field == Calendar.SECOND) {
done = true;
}
}
// truncate seconds
int seconds = val.get(Calendar.SECOND);
if (!done && (!round || seconds < 30)) {
time = time - (seconds * 1000L);
if (field == Calendar.MINUTE) {
done = true;
}
}
// truncate minutes
int minutes = val.get(Calendar.MINUTE);
if (!done && (!round || minutes < 30)) {
time = time - (minutes * 60000L);
}
// reset time
if (date.getTime() != time) {
date.setTime(time);
val.setTime(date);
}
// ----------------- Fix for LANG-59 ----------------------- END ----------------
boolean roundUp = false;
for (int i = 0; i < fields.length; i++) {
for (int j = 0; j < fields[i].length; j++) {
if (fields[i][j] == field) {
//This is our field... we stop looping
if (round && roundUp) {
if (field == DateUtils.SEMI_MONTH) {
//This is a special case that's hard to generalize
//If the date is 1, we round up to 16, otherwise
// we subtract 15 days and add 1 month
if (val.get(Calendar.DATE) == 1) {
val.add(Calendar.DATE, 15);
} else {
val.add(Calendar.DATE, -15);
val.add(Calendar.MONTH, 1);
}
} else {
//We need at add one to this field since the
// last number causes us to round up
val.add(fields[i][0], 1);
}
}
return;
}
}
//We have various fields that are not easy roundings
int offset = 0;
boolean offsetSet = false;
//These are special types of fields that require different rounding rules
switch (field) {
case DateUtils.SEMI_MONTH:
if (fields[i][0] == Calendar.DATE) {
//If we're going to drop the DATE field's value,
// we want to do this our own way.
//We need to subtrace 1 since the date has a minimum of 1
offset = val.get(Calendar.DATE) - 1;
//If we're above 15 days adjustment, that means we're in the
// bottom half of the month and should stay accordingly.
if (offset >= 15) {
offset -= 15;
}
//Record whether we're in the top or bottom half of that range
roundUp = offset > 7;
offsetSet = true;
}
break;
case Calendar.AM_PM:
if (fields[i][0] == Calendar.HOUR_OF_DAY) {
//If we're going to drop the HOUR field's value,
// we want to do this our own way.
offset = val.get(Calendar.HOUR_OF_DAY);
if (offset >= 12) {
offset -= 12;
}
roundUp = offset > 6;
offsetSet = true;
}
break;
}
if (!offsetSet) {
int min = val.getActualMinimum(fields[i][0]);
int max = val.getActualMaximum(fields[i][0]);
//Calculate the offset from the minimum allowed value
offset = val.get(fields[i][0]) - min;
//Set roundUp if this is more than half way between the minimum and maximum
roundUp = offset > ((max - min) / 2);
}
//We need to remove this field
if (offset != 0) {
val.set(fields[i][0], val.get(fields[i][0]) - offset);
}
}
throw new IllegalArgumentException("The field " + field + " is not supported");
} | true | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Internal calculation method.</p>
*
* @param val the calendar
* @param field the field constant
* @param round true to round, false to truncate
* @throws ArithmeticException if the year is over 280 million
*/
//-----------------------------------------------------------------------
private static void modify(Calendar val, int field, boolean round) {
if (val.get(Calendar.YEAR) > 280000000) {
throw new ArithmeticException("Calendar value too large for accurate calculations");
}
if (field == Calendar.MILLISECOND) {
return;
}
// ----------------- Fix for LANG-59 ---------------------- START ---------------
// see http://issues.apache.org/jira/browse/LANG-59
//
// Manually truncate milliseconds, seconds and minutes, rather than using
// Calendar methods.
Date date = val.getTime();
long time = date.getTime();
boolean done = false;
// truncate milliseconds
int millisecs = val.get(Calendar.MILLISECOND);
if (!round || millisecs < 500) {
time = time - millisecs;
if (field == Calendar.SECOND) {
done = true;
}
}
// truncate seconds
int seconds = val.get(Calendar.SECOND);
if (!done && (!round || seconds < 30)) {
time = time - (seconds * 1000L);
if (field == Calendar.MINUTE) {
done = true;
}
}
// truncate minutes
int minutes = val.get(Calendar.MINUTE);
if (!done && (!round || minutes < 30)) {
time = time - (minutes * 60000L);
}
// reset time
if (date.getTime() != time) {
date.setTime(time);
val.setTime(date);
}
// ----------------- Fix for LANG-59 ----------------------- END ----------------
boolean roundUp = false;
for (int i = 0; i < fields.length; i++) {
for (int j = 0; j < fields[i].length; j++) {
if (fields[i][j] == field) {
//This is our field... we stop looping
if (round && roundUp) {
if (field == DateUtils.SEMI_MONTH) {
//This is a special case that's hard to generalize
//If the date is 1, we round up to 16, otherwise
// we subtract 15 days and add 1 month
if (val.get(Calendar.DATE) == 1) {
val.add(Calendar.DATE, 15);
} else {
val.add(Calendar.DATE, -15);
val.add(Calendar.MONTH, 1);
}
} else {
//We need at add one to this field since the
// last number causes us to round up
val.add(fields[i][0], 1);
}
}
return;
}
}
//We have various fields that are not easy roundings
int offset = 0;
boolean offsetSet = false;
//These are special types of fields that require different rounding rules
switch (field) {
case DateUtils.SEMI_MONTH:
if (fields[i][0] == Calendar.DATE) {
//If we're going to drop the DATE field's value,
// we want to do this our own way.
//We need to subtrace 1 since the date has a minimum of 1
offset = val.get(Calendar.DATE) - 1;
//If we're above 15 days adjustment, that means we're in the
// bottom half of the month and should stay accordingly.
if (offset >= 15) {
offset -= 15;
}
//Record whether we're in the top or bottom half of that range
roundUp = offset > 7;
offsetSet = true;
}
break;
case Calendar.AM_PM:
if (fields[i][0] == Calendar.HOUR_OF_DAY) {
//If we're going to drop the HOUR field's value,
// we want to do this our own way.
offset = val.get(Calendar.HOUR_OF_DAY);
if (offset >= 12) {
offset -= 12;
}
roundUp = offset > 6;
offsetSet = true;
}
break;
}
if (!offsetSet) {
int min = val.getActualMinimum(fields[i][0]);
int max = val.getActualMaximum(fields[i][0]);
//Calculate the offset from the minimum allowed value
offset = val.get(fields[i][0]) - min;
//Set roundUp if this is more than half way between the minimum and maximum
roundUp = offset > ((max - min) / 2);
}
//We need to remove this field
if (offset != 0) {
val.set(fields[i][0], val.get(fields[i][0]) - offset);
}
}
throw new IllegalArgumentException("The field " + field + " is not supported");
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
84 | 9c7cb7c758f1e0d9f943d0d91fbf044e85da378fe4a43e04ebb56e9e6399ac9f | @Override
protected void iterateSimplex(final Comparator<RealPointValuePair> comparator)
throws FunctionEvaluationException, OptimizationException, IllegalArgumentException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/** {@inheritDoc} */
@Override
protected void iterateSimplex(final Comparator<RealPointValuePair> comparator)
throws FunctionEvaluationException, OptimizationException, IllegalArgumentException {
final RealConvergenceChecker checker = getConvergenceChecker();
while (true) {
incrementIterationsCounter();
// save the original vertex
final RealPointValuePair[] original = simplex;
final RealPointValuePair best = original[0];
// perform a reflection step
final RealPointValuePair reflected = evaluateNewSimplex(original, 1.0, comparator);
if (comparator.compare(reflected, best) < 0) {
// compute the expanded simplex
final RealPointValuePair[] reflectedSimplex = simplex;
final RealPointValuePair expanded = evaluateNewSimplex(original, khi, comparator);
if (comparator.compare(reflected, expanded) <= 0) {
// accept the reflected simplex
simplex = reflectedSimplex;
}
return;
}
// compute the contracted simplex
final RealPointValuePair contracted = evaluateNewSimplex(original, gamma, comparator);
if (comparator.compare(contracted, best) < 0) {
// accept the contracted simplex
return;
}
// check convergence
final int iter = getIterations();
boolean converged = true;
for (int i = 0; i < simplex.length; ++i) {
converged &= checker.converged(iter, original[i], simplex[i]);
}
if (converged) {
return;
}
}
}
```
| @Override
protected void iterateSimplex(final Comparator<RealPointValuePair> comparator)
throws FunctionEvaluationException, OptimizationException, IllegalArgumentException {
final RealConvergenceChecker checker = getConvergenceChecker();
while (true) {
incrementIterationsCounter();
// save the original vertex
final RealPointValuePair[] original = simplex;
final RealPointValuePair best = original[0];
// perform a reflection step
final RealPointValuePair reflected = evaluateNewSimplex(original, 1.0, comparator);
if (comparator.compare(reflected, best) < 0) {
// compute the expanded simplex
final RealPointValuePair[] reflectedSimplex = simplex;
final RealPointValuePair expanded = evaluateNewSimplex(original, khi, comparator);
if (comparator.compare(reflected, expanded) <= 0) {
// accept the reflected simplex
simplex = reflectedSimplex;
}
return;
}
// compute the contracted simplex
final RealPointValuePair contracted = evaluateNewSimplex(original, gamma, comparator);
if (comparator.compare(contracted, best) < 0) {
// accept the contracted simplex
return;
}
// check convergence
final int iter = getIterations();
boolean converged = true;
for (int i = 0; i < simplex.length; ++i) {
converged &= checker.converged(iter, original[i], simplex[i]);
}
if (converged) {
return;
}
}
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/** {@inheritDoc} */
@Override
protected void iterateSimplex(final Comparator<RealPointValuePair> comparator)
throws FunctionEvaluationException, OptimizationException, IllegalArgumentException {
final RealConvergenceChecker checker = getConvergenceChecker();
while (true) {
incrementIterationsCounter();
// save the original vertex
final RealPointValuePair[] original = simplex;
final RealPointValuePair best = original[0];
// perform a reflection step
final RealPointValuePair reflected = evaluateNewSimplex(original, 1.0, comparator);
if (comparator.compare(reflected, best) < 0) {
// compute the expanded simplex
final RealPointValuePair[] reflectedSimplex = simplex;
final RealPointValuePair expanded = evaluateNewSimplex(original, khi, comparator);
if (comparator.compare(reflected, expanded) <= 0) {
// accept the reflected simplex
simplex = reflectedSimplex;
}
return;
}
// compute the contracted simplex
final RealPointValuePair contracted = evaluateNewSimplex(original, gamma, comparator);
if (comparator.compare(contracted, best) < 0) {
// accept the contracted simplex
return;
}
// check convergence
final int iter = getIterations();
boolean converged = true;
for (int i = 0; i < simplex.length; ++i) {
converged &= checker.converged(iter, original[i], simplex[i]);
}
if (converged) {
return;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
38 | 9cb9aed87ef47608a02ad29b6e3bb16a7ae44b49f59a73afdd0ddd5b4b02d50d | void addNumber(double x) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
void addNumber(double x) {
// This is not pretty printing. This is to prevent misparsing of x- -4 as
// x--4 (which is a syntax error).
char prev = getLastChar();
boolean negativeZero = isNegativeZero(x);
if ((x < 0 || negativeZero) && prev == '-') {
add(" ");
}
if ((long) x == x && !negativeZero) {
long value = (long) x;
long mantissa = value;
int exp = 0;
if (Math.abs(x) >= 100) {
while (mantissa / 10 * Math.pow(10, exp + 1) == value) {
mantissa /= 10;
exp++;
}
}
if (exp > 2) {
add(Long.toString(mantissa) + "E" + Integer.toString(exp));
} else {
add(Long.toString(value));
}
} else {
add(String.valueOf(x));
}
}
```
| void addNumber(double x) {
// This is not pretty printing. This is to prevent misparsing of x- -4 as
// x--4 (which is a syntax error).
char prev = getLastChar();
boolean negativeZero = isNegativeZero(x);
if ((x < 0 || negativeZero) && prev == '-') {
add(" ");
}
if ((long) x == x && !negativeZero) {
long value = (long) x;
long mantissa = value;
int exp = 0;
if (Math.abs(x) >= 100) {
while (mantissa / 10 * Math.pow(10, exp + 1) == value) {
mantissa /= 10;
exp++;
}
}
if (exp > 2) {
add(Long.toString(mantissa) + "E" + Integer.toString(exp));
} else {
add(Long.toString(value));
}
} else {
add(String.valueOf(x));
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
void addNumber(double x) {
// This is not pretty printing. This is to prevent misparsing of x- -4 as
// x--4 (which is a syntax error).
char prev = getLastChar();
boolean negativeZero = isNegativeZero(x);
if ((x < 0 || negativeZero) && prev == '-') {
add(" ");
}
if ((long) x == x && !negativeZero) {
long value = (long) x;
long mantissa = value;
int exp = 0;
if (Math.abs(x) >= 100) {
while (mantissa / 10 * Math.pow(10, exp + 1) == value) {
mantissa /= 10;
exp++;
}
}
if (exp > 2) {
add(Long.toString(mantissa) + "E" + Integer.toString(exp));
} else {
add(Long.toString(value));
}
} else {
add(String.valueOf(x));
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
5 | 9d105d5cebd223938d764e284a38ea7a6087eab7bbbf5b428a5ff8f59dbd2c75 | private int compareNodePointers(
NodePointer p1,
int depth1,
NodePointer p2,
int depth2)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private int compareNodePointers(
NodePointer p1,
int depth1,
NodePointer p2,
int depth2)
{
if (depth1 < depth2) {
int r = compareNodePointers(p1, depth1, p2.parent, depth2 - 1);
return r == 0 ? -1 : r;
}
if (depth1 > depth2) {
int r = compareNodePointers(p1.parent, depth1 - 1, p2, depth2);
return r == 0 ? 1 : r;
}
if (p1 == null && p2 == null) {
return 0;
}
if (p1 != null && p1.equals(p2)) {
return 0;
}
if (depth1 == 1) {
throw new JXPathException(
"Cannot compare pointers that do not belong to the same tree: '"
+ p1 + "' and '" + p2 + "'");
}
int r = compareNodePointers(p1.parent, depth1 - 1, p2.parent, depth2 - 1);
if (r != 0) {
return r;
}
return p1.parent.compareChildNodePointers(p1, p2);
}
```
| private int compareNodePointers(
NodePointer p1,
int depth1,
NodePointer p2,
int depth2)
{
if (depth1 < depth2) {
int r = compareNodePointers(p1, depth1, p2.parent, depth2 - 1);
return r == 0 ? -1 : r;
}
if (depth1 > depth2) {
int r = compareNodePointers(p1.parent, depth1 - 1, p2, depth2);
return r == 0 ? 1 : r;
}
if (p1 == null && p2 == null) {
return 0;
}
if (p1 != null && p1.equals(p2)) {
return 0;
}
if (depth1 == 1) {
throw new JXPathException(
"Cannot compare pointers that do not belong to the same tree: '"
+ p1 + "' and '" + p2 + "'");
}
int r = compareNodePointers(p1.parent, depth1 - 1, p2.parent, depth2 - 1);
if (r != 0) {
return r;
}
return p1.parent.compareChildNodePointers(p1, p2);
} | true | JxPath | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private int compareNodePointers(
NodePointer p1,
int depth1,
NodePointer p2,
int depth2)
{
if (depth1 < depth2) {
int r = compareNodePointers(p1, depth1, p2.parent, depth2 - 1);
return r == 0 ? -1 : r;
}
if (depth1 > depth2) {
int r = compareNodePointers(p1.parent, depth1 - 1, p2, depth2);
return r == 0 ? 1 : r;
}
if (p1 == null && p2 == null) {
return 0;
}
if (p1 != null && p1.equals(p2)) {
return 0;
}
if (depth1 == 1) {
throw new JXPathException(
"Cannot compare pointers that do not belong to the same tree: '"
+ p1 + "' and '" + p2 + "'");
}
int r = compareNodePointers(p1.parent, depth1 - 1, p2.parent, depth2 - 1);
if (r != 0) {
return r;
}
return p1.parent.compareChildNodePointers(p1, p2);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
53 | 9d7333b6850af56c98d12d76483fd3bf8e3cd10c3a13fa7c43982270a55ca76a | private void replaceAssignmentExpression(Var v, Reference ref,
Map<String, String> varmap) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Replaces an assignment like x = {...} with t1=a,t2=b,t3=c,true.
* Note that the resulting expression will always evaluate to
* true, as would the x = {...} expression.
*/
private void replaceAssignmentExpression(Var v, Reference ref,
Map<String, String> varmap) {
// Compute all of the assignments necessary
List<Node> nodes = Lists.newArrayList();
Node val = ref.getAssignedValue();
blacklistVarReferencesInTree(val, v.scope);
Preconditions.checkState(val.getType() == Token.OBJECTLIT);
Set<String> all = Sets.newLinkedHashSet(varmap.keySet());
for (Node key = val.getFirstChild(); key != null;
key = key.getNext()) {
String var = key.getString();
Node value = key.removeFirstChild();
// TODO(user): Copy type information.
nodes.add(
new Node(Token.ASSIGN,
Node.newString(Token.NAME, varmap.get(var)), value));
all.remove(var);
}
// TODO(user): Better source information.
for (String var : all) {
nodes.add(
new Node(Token.ASSIGN,
Node.newString(Token.NAME, varmap.get(var)),
NodeUtil.newUndefinedNode(null)));
}
Node replacement;
if (nodes.isEmpty()) {
replacement = new Node(Token.TRUE);
} else {
// All assignments evaluate to true, so make sure that the
// expr statement evaluates to true in case it matters.
nodes.add(new Node(Token.TRUE));
// Join these using COMMA. A COMMA node must have 2 children, so we
// create a tree. In the tree the first child be the COMMA to match
// the parser, otherwise tree equality tests fail.
nodes = Lists.reverse(nodes);
replacement = new Node(Token.COMMA);
Node cur = replacement;
int i;
for (i = 0; i < nodes.size() - 2; i++) {
cur.addChildToFront(nodes.get(i));
Node t = new Node(Token.COMMA);
cur.addChildToFront(t);
cur = t;
}
cur.addChildToFront(nodes.get(i));
cur.addChildToFront(nodes.get(i + 1));
}
Node replace = ref.getParent();
replacement.copyInformationFromForTree(replace);
if (replace.getType() == Token.VAR) {
replace.getParent().replaceChild(
replace, NodeUtil.newExpr(replacement));
} else {
replace.getParent().replaceChild(replace, replacement);
}
}
```
| private void replaceAssignmentExpression(Var v, Reference ref,
Map<String, String> varmap) {
// Compute all of the assignments necessary
List<Node> nodes = Lists.newArrayList();
Node val = ref.getAssignedValue();
blacklistVarReferencesInTree(val, v.scope);
Preconditions.checkState(val.getType() == Token.OBJECTLIT);
Set<String> all = Sets.newLinkedHashSet(varmap.keySet());
for (Node key = val.getFirstChild(); key != null;
key = key.getNext()) {
String var = key.getString();
Node value = key.removeFirstChild();
// TODO(user): Copy type information.
nodes.add(
new Node(Token.ASSIGN,
Node.newString(Token.NAME, varmap.get(var)), value));
all.remove(var);
}
// TODO(user): Better source information.
for (String var : all) {
nodes.add(
new Node(Token.ASSIGN,
Node.newString(Token.NAME, varmap.get(var)),
NodeUtil.newUndefinedNode(null)));
}
Node replacement;
if (nodes.isEmpty()) {
replacement = new Node(Token.TRUE);
} else {
// All assignments evaluate to true, so make sure that the
// expr statement evaluates to true in case it matters.
nodes.add(new Node(Token.TRUE));
// Join these using COMMA. A COMMA node must have 2 children, so we
// create a tree. In the tree the first child be the COMMA to match
// the parser, otherwise tree equality tests fail.
nodes = Lists.reverse(nodes);
replacement = new Node(Token.COMMA);
Node cur = replacement;
int i;
for (i = 0; i < nodes.size() - 2; i++) {
cur.addChildToFront(nodes.get(i));
Node t = new Node(Token.COMMA);
cur.addChildToFront(t);
cur = t;
}
cur.addChildToFront(nodes.get(i));
cur.addChildToFront(nodes.get(i + 1));
}
Node replace = ref.getParent();
replacement.copyInformationFromForTree(replace);
if (replace.getType() == Token.VAR) {
replace.getParent().replaceChild(
replace, NodeUtil.newExpr(replacement));
} else {
replace.getParent().replaceChild(replace, replacement);
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Replaces an assignment like x = {...} with t1=a,t2=b,t3=c,true.
* Note that the resulting expression will always evaluate to
* true, as would the x = {...} expression.
*/
private void replaceAssignmentExpression(Var v, Reference ref,
Map<String, String> varmap) {
// Compute all of the assignments necessary
List<Node> nodes = Lists.newArrayList();
Node val = ref.getAssignedValue();
blacklistVarReferencesInTree(val, v.scope);
Preconditions.checkState(val.getType() == Token.OBJECTLIT);
Set<String> all = Sets.newLinkedHashSet(varmap.keySet());
for (Node key = val.getFirstChild(); key != null;
key = key.getNext()) {
String var = key.getString();
Node value = key.removeFirstChild();
// TODO(user): Copy type information.
nodes.add(
new Node(Token.ASSIGN,
Node.newString(Token.NAME, varmap.get(var)), value));
all.remove(var);
}
// TODO(user): Better source information.
for (String var : all) {
nodes.add(
new Node(Token.ASSIGN,
Node.newString(Token.NAME, varmap.get(var)),
NodeUtil.newUndefinedNode(null)));
}
Node replacement;
if (nodes.isEmpty()) {
replacement = new Node(Token.TRUE);
} else {
// All assignments evaluate to true, so make sure that the
// expr statement evaluates to true in case it matters.
nodes.add(new Node(Token.TRUE));
// Join these using COMMA. A COMMA node must have 2 children, so we
// create a tree. In the tree the first child be the COMMA to match
// the parser, otherwise tree equality tests fail.
nodes = Lists.reverse(nodes);
replacement = new Node(Token.COMMA);
Node cur = replacement;
int i;
for (i = 0; i < nodes.size() - 2; i++) {
cur.addChildToFront(nodes.get(i));
Node t = new Node(Token.COMMA);
cur.addChildToFront(t);
cur = t;
}
cur.addChildToFront(nodes.get(i));
cur.addChildToFront(nodes.get(i + 1));
}
Node replace = ref.getParent();
replacement.copyInformationFromForTree(replace);
if (replace.getType() == Token.VAR) {
replace.getParent().replaceChild(
replace, NodeUtil.newExpr(replacement));
} else {
replace.getParent().replaceChild(replace, replacement);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
57 | 9d8a5fac7b4fa660396c2a4cad9b75953f70d18b399a0404885d421e66b95e6b | public static boolean isAvailableLocale(Locale locale) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Checks if the locale specified is in the list of available locales.</p>
*
* @param locale the Locale object to check if it is available
* @return true if the locale is a known locale
*/
//-----------------------------------------------------------------------
public static boolean isAvailableLocale(Locale locale) {
return availableLocaleList().contains(locale);
}
```
| public static boolean isAvailableLocale(Locale locale) {
return availableLocaleList().contains(locale);
} | false | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Checks if the locale specified is in the list of available locales.</p>
*
* @param locale the Locale object to check if it is available
* @return true if the locale is a known locale
*/
//-----------------------------------------------------------------------
public static boolean isAvailableLocale(Locale locale) {
return availableLocaleList().contains(locale);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
129 | 9db800642235fa48ed1d81f09177bebe320d4971200547cd46ab732267953a82 | private void annotateCalls(Node n) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* There are two types of calls we are interested in calls without explicit
* "this" values (what we are call "free" calls) and direct call to eval.
*/
private void annotateCalls(Node n) {
Preconditions.checkState(n.isCall());
// Keep track of of the "this" context of a call. A call without an
// explicit "this" is a free call.
Node first = n.getFirstChild();
// ignore cast nodes.
while (first.isCast()) {
first = first.getFirstChild();
}
if (!NodeUtil.isGet(first)) {
n.putBooleanProp(Node.FREE_CALL, true);
}
// Keep track of the context in which eval is called. It is important
// to distinguish between "(0, eval)()" and "eval()".
if (first.isName() &&
"eval".equals(first.getString())) {
first.putBooleanProp(Node.DIRECT_EVAL, true);
}
}
```
| private void annotateCalls(Node n) {
Preconditions.checkState(n.isCall());
// Keep track of of the "this" context of a call. A call without an
// explicit "this" is a free call.
Node first = n.getFirstChild();
// ignore cast nodes.
while (first.isCast()) {
first = first.getFirstChild();
}
if (!NodeUtil.isGet(first)) {
n.putBooleanProp(Node.FREE_CALL, true);
}
// Keep track of the context in which eval is called. It is important
// to distinguish between "(0, eval)()" and "eval()".
if (first.isName() &&
"eval".equals(first.getString())) {
first.putBooleanProp(Node.DIRECT_EVAL, true);
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* There are two types of calls we are interested in calls without explicit
* "this" values (what we are call "free" calls) and direct call to eval.
*/
private void annotateCalls(Node n) {
Preconditions.checkState(n.isCall());
// Keep track of of the "this" context of a call. A call without an
// explicit "this" is a free call.
Node first = n.getFirstChild();
// ignore cast nodes.
while (first.isCast()) {
first = first.getFirstChild();
}
if (!NodeUtil.isGet(first)) {
n.putBooleanProp(Node.FREE_CALL, true);
}
// Keep track of the context in which eval is called. It is important
// to distinguish between "(0, eval)()" and "eval()".
if (first.isName() &&
"eval".equals(first.getString())) {
first.putBooleanProp(Node.DIRECT_EVAL, true);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
57 | 9dcac8cc787aa7245f48ef5f7e6f5abcbdc176a5126d13817d7fec4865b89838 | private static <T extends Clusterable<T>> List<Cluster<T>>
chooseInitialCenters(final Collection<T> points, final int k, final Random random) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Use K-means++ to choose the initial centers.
*
* @param <T> type of the points to cluster
* @param points the points to choose the initial centers from
* @param k the number of centers to choose
* @param random random generator to use
* @return the initial centers
*/
private static <T extends Clusterable<T>> List<Cluster<T>>
chooseInitialCenters(final Collection<T> points, final int k, final Random random) {
final List<T> pointSet = new ArrayList<T>(points);
final List<Cluster<T>> resultSet = new ArrayList<Cluster<T>>();
// Choose one center uniformly at random from among the data points.
final T firstPoint = pointSet.remove(random.nextInt(pointSet.size()));
resultSet.add(new Cluster<T>(firstPoint));
final double[] dx2 = new double[pointSet.size()];
while (resultSet.size() < k) {
// For each data point x, compute D(x), the distance between x and
// the nearest center that has already been chosen.
double sum = 0;
for (int i = 0; i < pointSet.size(); i++) {
final T p = pointSet.get(i);
final Cluster<T> nearest = getNearestCluster(resultSet, p);
final double d = p.distanceFrom(nearest.getCenter());
sum += d * d;
dx2[i] = sum;
}
// Add one new data point as a center. Each point x is chosen with
// probability proportional to D(x)2
final double r = random.nextDouble() * sum;
for (int i = 0 ; i < dx2.length; i++) {
if (dx2[i] >= r) {
final T p = pointSet.remove(i);
resultSet.add(new Cluster<T>(p));
break;
}
}
}
return resultSet;
}
```
| private static <T extends Clusterable<T>> List<Cluster<T>>
chooseInitialCenters(final Collection<T> points, final int k, final Random random) {
final List<T> pointSet = new ArrayList<T>(points);
final List<Cluster<T>> resultSet = new ArrayList<Cluster<T>>();
// Choose one center uniformly at random from among the data points.
final T firstPoint = pointSet.remove(random.nextInt(pointSet.size()));
resultSet.add(new Cluster<T>(firstPoint));
final double[] dx2 = new double[pointSet.size()];
while (resultSet.size() < k) {
// For each data point x, compute D(x), the distance between x and
// the nearest center that has already been chosen.
double sum = 0;
for (int i = 0; i < pointSet.size(); i++) {
final T p = pointSet.get(i);
final Cluster<T> nearest = getNearestCluster(resultSet, p);
final double d = p.distanceFrom(nearest.getCenter());
sum += d * d;
dx2[i] = sum;
}
// Add one new data point as a center. Each point x is chosen with
// probability proportional to D(x)2
final double r = random.nextDouble() * sum;
for (int i = 0 ; i < dx2.length; i++) {
if (dx2[i] >= r) {
final T p = pointSet.remove(i);
resultSet.add(new Cluster<T>(p));
break;
}
}
}
return resultSet;
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Use K-means++ to choose the initial centers.
*
* @param <T> type of the points to cluster
* @param points the points to choose the initial centers from
* @param k the number of centers to choose
* @param random random generator to use
* @return the initial centers
*/
private static <T extends Clusterable<T>> List<Cluster<T>>
chooseInitialCenters(final Collection<T> points, final int k, final Random random) {
final List<T> pointSet = new ArrayList<T>(points);
final List<Cluster<T>> resultSet = new ArrayList<Cluster<T>>();
// Choose one center uniformly at random from among the data points.
final T firstPoint = pointSet.remove(random.nextInt(pointSet.size()));
resultSet.add(new Cluster<T>(firstPoint));
final double[] dx2 = new double[pointSet.size()];
while (resultSet.size() < k) {
// For each data point x, compute D(x), the distance between x and
// the nearest center that has already been chosen.
double sum = 0;
for (int i = 0; i < pointSet.size(); i++) {
final T p = pointSet.get(i);
final Cluster<T> nearest = getNearestCluster(resultSet, p);
final double d = p.distanceFrom(nearest.getCenter());
sum += d * d;
dx2[i] = sum;
}
// Add one new data point as a center. Each point x is chosen with
// probability proportional to D(x)2
final double r = random.nextDouble() * sum;
for (int i = 0 ; i < dx2.length; i++) {
if (dx2[i] >= r) {
final T p = pointSet.remove(i);
resultSet.add(new Cluster<T>(p));
break;
}
}
}
return resultSet;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
12 | 9dde29e563c8485a70483755550bea638ab3c74cfd1a90e3187bf15c169e70df | public MultiplePiePlot(CategoryDataset dataset) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Creates a new plot.
*
* @param dataset the dataset (<code>null</code> permitted).
*/
public MultiplePiePlot(CategoryDataset dataset) {
super();
setDataset(dataset);
PiePlot piePlot = new PiePlot(null);
this.pieChart = new JFreeChart(piePlot);
this.pieChart.removeLegend();
this.dataExtractOrder = TableOrder.BY_COLUMN;
this.pieChart.setBackgroundPaint(null);
TextTitle seriesTitle = new TextTitle("Series Title",
new Font("SansSerif", Font.BOLD, 12));
seriesTitle.setPosition(RectangleEdge.BOTTOM);
this.pieChart.setTitle(seriesTitle);
this.aggregatedItemsKey = "Other";
this.aggregatedItemsPaint = Color.lightGray;
this.sectionPaints = new HashMap();
}
```
| public MultiplePiePlot(CategoryDataset dataset) {
super();
setDataset(dataset);
PiePlot piePlot = new PiePlot(null);
this.pieChart = new JFreeChart(piePlot);
this.pieChart.removeLegend();
this.dataExtractOrder = TableOrder.BY_COLUMN;
this.pieChart.setBackgroundPaint(null);
TextTitle seriesTitle = new TextTitle("Series Title",
new Font("SansSerif", Font.BOLD, 12));
seriesTitle.setPosition(RectangleEdge.BOTTOM);
this.pieChart.setTitle(seriesTitle);
this.aggregatedItemsKey = "Other";
this.aggregatedItemsPaint = Color.lightGray;
this.sectionPaints = new HashMap();
} | false | Chart | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Creates a new plot.
*
* @param dataset the dataset (<code>null</code> permitted).
*/
public MultiplePiePlot(CategoryDataset dataset) {
super();
setDataset(dataset);
PiePlot piePlot = new PiePlot(null);
this.pieChart = new JFreeChart(piePlot);
this.pieChart.removeLegend();
this.dataExtractOrder = TableOrder.BY_COLUMN;
this.pieChart.setBackgroundPaint(null);
TextTitle seriesTitle = new TextTitle("Series Title",
new Font("SansSerif", Font.BOLD, 12));
seriesTitle.setPosition(RectangleEdge.BOTTOM);
this.pieChart.setTitle(seriesTitle);
this.aggregatedItemsKey = "Other";
this.aggregatedItemsPaint = Color.lightGray;
this.sectionPaints = new HashMap();
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
28 | 9e47abecefdb60bd98f385f2f91b869e6d6b6b01f6aeff3c1ef4de0c899034bd | protected void processProperties(Properties properties)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Sets the values of Options using the values in <code>properties</code>.
*
* @param properties The value properties to be processed.
*/
protected void processProperties(Properties properties)
{
if (properties == null)
{
return;
}
for (Enumeration e = properties.propertyNames(); e.hasMoreElements();)
{
String option = e.nextElement().toString();
if (!cmd.hasOption(option))
{
Option opt = getOptions().getOption(option);
// get the value from the properties instance
String value = properties.getProperty(option);
if (opt.hasArg())
{
if (opt.getValues() == null || opt.getValues().length == 0)
{
try
{
opt.addValueForProcessing(value);
}
catch (RuntimeException exp)
{
// if we cannot add the value don't worry about it
}
}
}
else if (!("yes".equalsIgnoreCase(value)
|| "true".equalsIgnoreCase(value)
|| "1".equalsIgnoreCase(value)))
{
// if the value is not yes, true or 1 then don't add the
// option to the CommandLine
continue;
}
cmd.addOption(opt);
}
}
}
```
| protected void processProperties(Properties properties)
{
if (properties == null)
{
return;
}
for (Enumeration e = properties.propertyNames(); e.hasMoreElements();)
{
String option = e.nextElement().toString();
if (!cmd.hasOption(option))
{
Option opt = getOptions().getOption(option);
// get the value from the properties instance
String value = properties.getProperty(option);
if (opt.hasArg())
{
if (opt.getValues() == null || opt.getValues().length == 0)
{
try
{
opt.addValueForProcessing(value);
}
catch (RuntimeException exp)
{
// if we cannot add the value don't worry about it
}
}
}
else if (!("yes".equalsIgnoreCase(value)
|| "true".equalsIgnoreCase(value)
|| "1".equalsIgnoreCase(value)))
{
// if the value is not yes, true or 1 then don't add the
// option to the CommandLine
continue;
}
cmd.addOption(opt);
}
}
} | false | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Sets the values of Options using the values in <code>properties</code>.
*
* @param properties The value properties to be processed.
*/
protected void processProperties(Properties properties)
{
if (properties == null)
{
return;
}
for (Enumeration e = properties.propertyNames(); e.hasMoreElements();)
{
String option = e.nextElement().toString();
if (!cmd.hasOption(option))
{
Option opt = getOptions().getOption(option);
// get the value from the properties instance
String value = properties.getProperty(option);
if (opt.hasArg())
{
if (opt.getValues() == null || opt.getValues().length == 0)
{
try
{
opt.addValueForProcessing(value);
}
catch (RuntimeException exp)
{
// if we cannot add the value don't worry about it
}
}
}
else if (!("yes".equalsIgnoreCase(value)
|| "true".equalsIgnoreCase(value)
|| "1".equalsIgnoreCase(value)))
{
// if the value is not yes, true or 1 then don't add the
// option to the CommandLine
continue;
}
cmd.addOption(opt);
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
27 | 9e863567e3ad3ac3c493a22f1c28e4bf4055c4c6d31346d798242419c1e12975 | private static PeriodFormatter toFormatter(List<Object> elementPairs, boolean notPrinter, boolean notParser) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
//-----------------------------------------------------------------------
private static PeriodFormatter toFormatter(List<Object> elementPairs, boolean notPrinter, boolean notParser) {
if (notPrinter && notParser) {
throw new IllegalStateException("Builder has created neither a printer nor a parser");
}
int size = elementPairs.size();
if (size >= 2 && elementPairs.get(0) instanceof Separator) {
Separator sep = (Separator) elementPairs.get(0);
PeriodFormatter f = toFormatter(elementPairs.subList(2, size), notPrinter, notParser);
sep = sep.finish(f.getPrinter(), f.getParser());
return new PeriodFormatter(sep, sep);
}
Object[] comp = createComposite(elementPairs);
if (notPrinter) {
return new PeriodFormatter(null, (PeriodParser) comp[1]);
} else if (notParser) {
return new PeriodFormatter((PeriodPrinter) comp[0], null);
} else {
return new PeriodFormatter((PeriodPrinter) comp[0], (PeriodParser) comp[1]);
}
}
```
| private static PeriodFormatter toFormatter(List<Object> elementPairs, boolean notPrinter, boolean notParser) {
if (notPrinter && notParser) {
throw new IllegalStateException("Builder has created neither a printer nor a parser");
}
int size = elementPairs.size();
if (size >= 2 && elementPairs.get(0) instanceof Separator) {
Separator sep = (Separator) elementPairs.get(0);
PeriodFormatter f = toFormatter(elementPairs.subList(2, size), notPrinter, notParser);
sep = sep.finish(f.getPrinter(), f.getParser());
return new PeriodFormatter(sep, sep);
}
Object[] comp = createComposite(elementPairs);
if (notPrinter) {
return new PeriodFormatter(null, (PeriodParser) comp[1]);
} else if (notParser) {
return new PeriodFormatter((PeriodPrinter) comp[0], null);
} else {
return new PeriodFormatter((PeriodPrinter) comp[0], (PeriodParser) comp[1]);
}
} | true | Time | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
//-----------------------------------------------------------------------
private static PeriodFormatter toFormatter(List<Object> elementPairs, boolean notPrinter, boolean notParser) {
if (notPrinter && notParser) {
throw new IllegalStateException("Builder has created neither a printer nor a parser");
}
int size = elementPairs.size();
if (size >= 2 && elementPairs.get(0) instanceof Separator) {
Separator sep = (Separator) elementPairs.get(0);
PeriodFormatter f = toFormatter(elementPairs.subList(2, size), notPrinter, notParser);
sep = sep.finish(f.getPrinter(), f.getParser());
return new PeriodFormatter(sep, sep);
}
Object[] comp = createComposite(elementPairs);
if (notPrinter) {
return new PeriodFormatter(null, (PeriodParser) comp[1]);
} else if (notParser) {
return new PeriodFormatter((PeriodPrinter) comp[0], null);
} else {
return new PeriodFormatter((PeriodPrinter) comp[0], (PeriodParser) comp[1]);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
1 | 9eb91567d59c342f46c70a619b7322d8b1ad077e42dd90b7ab4ed81b971cf1d0 | @Override
public int read() throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public int read() throws IOException {
int current = super.read();
if (current == '\n') {
lineCounter++;
}
lastChar = current;
return lastChar;
}
```
| @Override
public int read() throws IOException {
int current = super.read();
if (current == '\n') {
lineCounter++;
}
lastChar = current;
return lastChar;
} | true | Csv | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public int read() throws IOException {
int current = super.read();
if (current == '\n') {
lineCounter++;
}
lastChar = current;
return lastChar;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
20 | 9ebfb8b3fab175d796f80b2e39efacd5cd8f24bcb6ff0ca2a7784c52f4ce02b4 | static Document parseByteData(ByteBuffer byteData, String charsetName, String baseUri, Parser parser) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
// switching the chartset midstream when a meta http-equiv tag defines the charset.
// reads bytes first into a buffer, then decodes with the appropriate charset. done this way to support
static Document parseByteData(ByteBuffer byteData, String charsetName, String baseUri, Parser parser) {
String docData;
Document doc = null;
if (charsetName == null) { // determine from meta. safe parse as UTF-8
// look for <meta http-equiv="Content-Type" content="text/html;charset=gb2312"> or HTML5 <meta charset="gb2312">
docData = Charset.forName(defaultCharset).decode(byteData).toString();
doc = parser.parseInput(docData, baseUri);
Element meta = doc.select("meta[http-equiv=content-type], meta[charset]").first();
if (meta != null) { // if not found, will keep utf-8 as best attempt
String foundCharset = meta.hasAttr("http-equiv") ? getCharsetFromContentType(meta.attr("content")) : meta.attr("charset");
if (foundCharset != null && foundCharset.length() != 0 && !foundCharset.equals(defaultCharset)) { // need to re-decode
charsetName = foundCharset;
byteData.rewind();
docData = Charset.forName(foundCharset).decode(byteData).toString();
doc = null;
}
}
} else { // specified by content type header (or by user on file load)
Validate.notEmpty(charsetName, "Must set charset arg to character set of file to parse. Set to null to attempt to detect from HTML");
docData = Charset.forName(charsetName).decode(byteData).toString();
}
if (doc == null) {
// there are times where there is a spurious byte-order-mark at the start of the text. Shouldn't be present
// in utf-8. If after decoding, there is a BOM, strip it; otherwise will cause the parser to go straight
// into head mode
doc = parser.parseInput(docData, baseUri);
doc.outputSettings().charset(charsetName);
}
return doc;
}
```
| static Document parseByteData(ByteBuffer byteData, String charsetName, String baseUri, Parser parser) {
String docData;
Document doc = null;
if (charsetName == null) { // determine from meta. safe parse as UTF-8
// look for <meta http-equiv="Content-Type" content="text/html;charset=gb2312"> or HTML5 <meta charset="gb2312">
docData = Charset.forName(defaultCharset).decode(byteData).toString();
doc = parser.parseInput(docData, baseUri);
Element meta = doc.select("meta[http-equiv=content-type], meta[charset]").first();
if (meta != null) { // if not found, will keep utf-8 as best attempt
String foundCharset = meta.hasAttr("http-equiv") ? getCharsetFromContentType(meta.attr("content")) : meta.attr("charset");
if (foundCharset != null && foundCharset.length() != 0 && !foundCharset.equals(defaultCharset)) { // need to re-decode
charsetName = foundCharset;
byteData.rewind();
docData = Charset.forName(foundCharset).decode(byteData).toString();
doc = null;
}
}
} else { // specified by content type header (or by user on file load)
Validate.notEmpty(charsetName, "Must set charset arg to character set of file to parse. Set to null to attempt to detect from HTML");
docData = Charset.forName(charsetName).decode(byteData).toString();
}
if (doc == null) {
// there are times where there is a spurious byte-order-mark at the start of the text. Shouldn't be present
// in utf-8. If after decoding, there is a BOM, strip it; otherwise will cause the parser to go straight
// into head mode
doc = parser.parseInput(docData, baseUri);
doc.outputSettings().charset(charsetName);
}
return doc;
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
// switching the chartset midstream when a meta http-equiv tag defines the charset.
// reads bytes first into a buffer, then decodes with the appropriate charset. done this way to support
static Document parseByteData(ByteBuffer byteData, String charsetName, String baseUri, Parser parser) {
String docData;
Document doc = null;
if (charsetName == null) { // determine from meta. safe parse as UTF-8
// look for <meta http-equiv="Content-Type" content="text/html;charset=gb2312"> or HTML5 <meta charset="gb2312">
docData = Charset.forName(defaultCharset).decode(byteData).toString();
doc = parser.parseInput(docData, baseUri);
Element meta = doc.select("meta[http-equiv=content-type], meta[charset]").first();
if (meta != null) { // if not found, will keep utf-8 as best attempt
String foundCharset = meta.hasAttr("http-equiv") ? getCharsetFromContentType(meta.attr("content")) : meta.attr("charset");
if (foundCharset != null && foundCharset.length() != 0 && !foundCharset.equals(defaultCharset)) { // need to re-decode
charsetName = foundCharset;
byteData.rewind();
docData = Charset.forName(foundCharset).decode(byteData).toString();
doc = null;
}
}
} else { // specified by content type header (or by user on file load)
Validate.notEmpty(charsetName, "Must set charset arg to character set of file to parse. Set to null to attempt to detect from HTML");
docData = Charset.forName(charsetName).decode(byteData).toString();
}
if (doc == null) {
// there are times where there is a spurious byte-order-mark at the start of the text. Shouldn't be present
// in utf-8. If after decoding, there is a BOM, strip it; otherwise will cause the parser to go straight
// into head mode
doc = parser.parseInput(docData, baseUri);
doc.outputSettings().charset(charsetName);
}
return doc;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
133 | 9ee7342ccd42821711f49fe5826ad5fe2bba178772f409eb4eabf80d9e2996b6 | private String getRemainingJSDocLine() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns the remainder of the line.
*/
private String getRemainingJSDocLine() {
String result = stream.getRemainingJSDocLine();
unreadToken = NO_UNREAD_TOKEN;
return result;
}
```
| private String getRemainingJSDocLine() {
String result = stream.getRemainingJSDocLine();
unreadToken = NO_UNREAD_TOKEN;
return result;
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns the remainder of the line.
*/
private String getRemainingJSDocLine() {
String result = stream.getRemainingJSDocLine();
unreadToken = NO_UNREAD_TOKEN;
return result;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
125 | 9f595d0f884657f96d15e67375da3aeb29a52cb2d5831163ffe43f6ab411a1bf | private void visitNew(NodeTraversal t, Node n) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Visits a NEW node.
*/
private void visitNew(NodeTraversal t, Node n) {
Node constructor = n.getFirstChild();
JSType type = getJSType(constructor).restrictByNotNullOrUndefined();
if (type.isConstructor() || type.isEmptyType() || type.isUnknownType()) {
FunctionType fnType = type.toMaybeFunctionType();
if (fnType != null && fnType.hasInstanceType()) {
visitParameterList(t, n, fnType);
ensureTyped(t, n, fnType.getInstanceType());
} else {
ensureTyped(t, n);
}
} else {
report(t, n, NOT_A_CONSTRUCTOR);
ensureTyped(t, n);
}
}
```
| private void visitNew(NodeTraversal t, Node n) {
Node constructor = n.getFirstChild();
JSType type = getJSType(constructor).restrictByNotNullOrUndefined();
if (type.isConstructor() || type.isEmptyType() || type.isUnknownType()) {
FunctionType fnType = type.toMaybeFunctionType();
if (fnType != null && fnType.hasInstanceType()) {
visitParameterList(t, n, fnType);
ensureTyped(t, n, fnType.getInstanceType());
} else {
ensureTyped(t, n);
}
} else {
report(t, n, NOT_A_CONSTRUCTOR);
ensureTyped(t, n);
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Visits a NEW node.
*/
private void visitNew(NodeTraversal t, Node n) {
Node constructor = n.getFirstChild();
JSType type = getJSType(constructor).restrictByNotNullOrUndefined();
if (type.isConstructor() || type.isEmptyType() || type.isUnknownType()) {
FunctionType fnType = type.toMaybeFunctionType();
if (fnType != null && fnType.hasInstanceType()) {
visitParameterList(t, n, fnType);
ensureTyped(t, n, fnType.getInstanceType());
} else {
ensureTyped(t, n);
}
} else {
report(t, n, NOT_A_CONSTRUCTOR);
ensureTyped(t, n);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
28 | 9f94b6fd0e5e0fd6de5ea9e19d25f3ccf092723a7b92338a39c189c0b313a275 | private Integer getPivotRow(SimplexTableau tableau, final int col) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns the row with the minimum ratio as given by the minimum ratio test (MRT).
* @param tableau simple tableau for the problem
* @param col the column to test the ratio of. See {@link #getPivotColumn(SimplexTableau)}
* @return row with the minimum ratio
*/
private Integer getPivotRow(SimplexTableau tableau, final int col) {
// create a list of all the rows that tie for the lowest score in the minimum ratio test
List<Integer> minRatioPositions = new ArrayList<Integer>();
double minRatio = Double.MAX_VALUE;
for (int i = tableau.getNumObjectiveFunctions(); i < tableau.getHeight(); i++) {
final double rhs = tableau.getEntry(i, tableau.getWidth() - 1);
final double entry = tableau.getEntry(i, col);
if (Precision.compareTo(entry, 0d, maxUlps) > 0) {
final double ratio = rhs / entry;
// check if the entry is strictly equal to the current min ratio
// do not use a ulp/epsilon check
final int cmp = Double.compare(ratio, minRatio);
if (cmp == 0) {
minRatioPositions.add(i);
} else if (cmp < 0) {
minRatio = ratio;
minRatioPositions = new ArrayList<Integer>();
minRatioPositions.add(i);
}
}
}
if (minRatioPositions.size() == 0) {
return null;
} else if (minRatioPositions.size() > 1) {
// there's a degeneracy as indicated by a tie in the minimum ratio test
// 1. check if there's an artificial variable that can be forced out of the basis
for (Integer row : minRatioPositions) {
for (int i = 0; i < tableau.getNumArtificialVariables(); i++) {
int column = i + tableau.getArtificialVariableOffset();
final double entry = tableau.getEntry(row, column);
if (Precision.equals(entry, 1d, maxUlps) && row.equals(tableau.getBasicRow(column))) {
return row;
}
}
}
// 2. apply Bland's rule to prevent cycling:
// take the row for which the corresponding basic variable has the smallest index
//
// see http://www.stanford.edu/class/msande310/blandrule.pdf
// see http://en.wikipedia.org/wiki/Bland%27s_rule (not equivalent to the above paper)
//
// Additional heuristic: if we did not get a solution after half of maxIterations
// revert to the simple case of just returning the top-most row
// This heuristic is based on empirical data gathered while investigating MATH-828.
Integer minRow = null;
int minIndex = tableau.getWidth();
for (Integer row : minRatioPositions) {
int i = tableau.getNumObjectiveFunctions();
for (; i < tableau.getWidth() - 1 && minRow != row; i++) {
if (row == tableau.getBasicRow(i)) {
if (i < minIndex) {
minIndex = i;
minRow = row;
}
}
}
}
return minRow;
}
return minRatioPositions.get(0);
}
```
| private Integer getPivotRow(SimplexTableau tableau, final int col) {
// create a list of all the rows that tie for the lowest score in the minimum ratio test
List<Integer> minRatioPositions = new ArrayList<Integer>();
double minRatio = Double.MAX_VALUE;
for (int i = tableau.getNumObjectiveFunctions(); i < tableau.getHeight(); i++) {
final double rhs = tableau.getEntry(i, tableau.getWidth() - 1);
final double entry = tableau.getEntry(i, col);
if (Precision.compareTo(entry, 0d, maxUlps) > 0) {
final double ratio = rhs / entry;
// check if the entry is strictly equal to the current min ratio
// do not use a ulp/epsilon check
final int cmp = Double.compare(ratio, minRatio);
if (cmp == 0) {
minRatioPositions.add(i);
} else if (cmp < 0) {
minRatio = ratio;
minRatioPositions = new ArrayList<Integer>();
minRatioPositions.add(i);
}
}
}
if (minRatioPositions.size() == 0) {
return null;
} else if (minRatioPositions.size() > 1) {
// there's a degeneracy as indicated by a tie in the minimum ratio test
// 1. check if there's an artificial variable that can be forced out of the basis
for (Integer row : minRatioPositions) {
for (int i = 0; i < tableau.getNumArtificialVariables(); i++) {
int column = i + tableau.getArtificialVariableOffset();
final double entry = tableau.getEntry(row, column);
if (Precision.equals(entry, 1d, maxUlps) && row.equals(tableau.getBasicRow(column))) {
return row;
}
}
}
// 2. apply Bland's rule to prevent cycling:
// take the row for which the corresponding basic variable has the smallest index
//
// see http://www.stanford.edu/class/msande310/blandrule.pdf
// see http://en.wikipedia.org/wiki/Bland%27s_rule (not equivalent to the above paper)
//
// Additional heuristic: if we did not get a solution after half of maxIterations
// revert to the simple case of just returning the top-most row
// This heuristic is based on empirical data gathered while investigating MATH-828.
Integer minRow = null;
int minIndex = tableau.getWidth();
for (Integer row : minRatioPositions) {
int i = tableau.getNumObjectiveFunctions();
for (; i < tableau.getWidth() - 1 && minRow != row; i++) {
if (row == tableau.getBasicRow(i)) {
if (i < minIndex) {
minIndex = i;
minRow = row;
}
}
}
}
return minRow;
}
return minRatioPositions.get(0);
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns the row with the minimum ratio as given by the minimum ratio test (MRT).
* @param tableau simple tableau for the problem
* @param col the column to test the ratio of. See {@link #getPivotColumn(SimplexTableau)}
* @return row with the minimum ratio
*/
private Integer getPivotRow(SimplexTableau tableau, final int col) {
// create a list of all the rows that tie for the lowest score in the minimum ratio test
List<Integer> minRatioPositions = new ArrayList<Integer>();
double minRatio = Double.MAX_VALUE;
for (int i = tableau.getNumObjectiveFunctions(); i < tableau.getHeight(); i++) {
final double rhs = tableau.getEntry(i, tableau.getWidth() - 1);
final double entry = tableau.getEntry(i, col);
if (Precision.compareTo(entry, 0d, maxUlps) > 0) {
final double ratio = rhs / entry;
// check if the entry is strictly equal to the current min ratio
// do not use a ulp/epsilon check
final int cmp = Double.compare(ratio, minRatio);
if (cmp == 0) {
minRatioPositions.add(i);
} else if (cmp < 0) {
minRatio = ratio;
minRatioPositions = new ArrayList<Integer>();
minRatioPositions.add(i);
}
}
}
if (minRatioPositions.size() == 0) {
return null;
} else if (minRatioPositions.size() > 1) {
// there's a degeneracy as indicated by a tie in the minimum ratio test
// 1. check if there's an artificial variable that can be forced out of the basis
for (Integer row : minRatioPositions) {
for (int i = 0; i < tableau.getNumArtificialVariables(); i++) {
int column = i + tableau.getArtificialVariableOffset();
final double entry = tableau.getEntry(row, column);
if (Precision.equals(entry, 1d, maxUlps) && row.equals(tableau.getBasicRow(column))) {
return row;
}
}
}
// 2. apply Bland's rule to prevent cycling:
// take the row for which the corresponding basic variable has the smallest index
//
// see http://www.stanford.edu/class/msande310/blandrule.pdf
// see http://en.wikipedia.org/wiki/Bland%27s_rule (not equivalent to the above paper)
//
// Additional heuristic: if we did not get a solution after half of maxIterations
// revert to the simple case of just returning the top-most row
// This heuristic is based on empirical data gathered while investigating MATH-828.
Integer minRow = null;
int minIndex = tableau.getWidth();
for (Integer row : minRatioPositions) {
int i = tableau.getNumObjectiveFunctions();
for (; i < tableau.getWidth() - 1 && minRow != row; i++) {
if (row == tableau.getBasicRow(i)) {
if (i < minIndex) {
minIndex = i;
minRow = row;
}
}
}
}
return minRow;
}
return minRatioPositions.get(0);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
29 | 9ff2158de5a7bc359ca543956beb5766e0840638d09c85add84305f668570135 | static float toJavaVersionInt(String version) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>
* Converts the given Java version string to an <code>int</code>.
* </p>
*
* <p>
* Example return values:
* </p>
* <ul>
* <li><code>120</code> for Java 1.2</li>
* <li><code>131</code> for Java 1.3.1</li>
* <li><code>160</code> for Java 1.6.0_20</li>
* </ul>
*
* <p>
* Patch releases are not reported.
* </p>
* <p>
* This method is package private instead of private to support unit test invocation.
* </p>
*
* @return the version, for example 131 for Java 1.3.1
*/
static float toJavaVersionInt(String version) {
return toVersionInt(toJavaVersionIntArray(version, JAVA_VERSION_TRIM_SIZE));
}
```
| static float toJavaVersionInt(String version) {
return toVersionInt(toJavaVersionIntArray(version, JAVA_VERSION_TRIM_SIZE));
} | true | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>
* Converts the given Java version string to an <code>int</code>.
* </p>
*
* <p>
* Example return values:
* </p>
* <ul>
* <li><code>120</code> for Java 1.2</li>
* <li><code>131</code> for Java 1.3.1</li>
* <li><code>160</code> for Java 1.6.0_20</li>
* </ul>
*
* <p>
* Patch releases are not reported.
* </p>
* <p>
* This method is package private instead of private to support unit test invocation.
* </p>
*
* @return the version, for example 131 for Java 1.3.1
*/
static float toJavaVersionInt(String version) {
return toVersionInt(toJavaVersionIntArray(version, JAVA_VERSION_TRIM_SIZE));
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
62 | 9ff6d27db31966e27134332db7b17db9f2a7b93e0dbb7202266af5bf45a18736 | @Override
public CollectionDeserializer createContextual(DeserializationContext ctxt,
BeanProperty property) throws JsonMappingException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Method called to finalize setup of this deserializer,
* when it is known for which property deserializer is needed
* for.
*/
/*
/**********************************************************
/* Validation, post-processing (ResolvableDeserializer)
/**********************************************************
*/
@Override
public CollectionDeserializer createContextual(DeserializationContext ctxt,
BeanProperty property) throws JsonMappingException
{
// May need to resolve types for delegate-based creators:
JsonDeserializer<Object> delegateDeser = null;
if (_valueInstantiator != null) {
if (_valueInstantiator.canCreateUsingDelegate()) {
JavaType delegateType = _valueInstantiator.getDelegateType(ctxt.getConfig());
if (delegateType == null) {
throw new IllegalArgumentException("Invalid delegate-creator definition for "+_collectionType
+": value instantiator ("+_valueInstantiator.getClass().getName()
+") returned true for 'canCreateUsingDelegate()', but null for 'getDelegateType()'");
}
delegateDeser = findDeserializer(ctxt, delegateType, property);
}
}
// [databind#1043]: allow per-property allow-wrapping of single overrides:
// 11-Dec-2015, tatu: Should we pass basic `Collection.class`, or more refined? Mostly
// comes down to "List vs Collection" I suppose... for now, pass Collection
Boolean unwrapSingle = findFormatFeature(ctxt, property, Collection.class,
JsonFormat.Feature.ACCEPT_SINGLE_VALUE_AS_ARRAY);
// also, often value deserializer is resolved here:
JsonDeserializer<?> valueDeser = _valueDeserializer;
// May have a content converter
valueDeser = findConvertingContentDeserializer(ctxt, property, valueDeser);
final JavaType vt = _collectionType.getContentType();
if (valueDeser == null) {
valueDeser = ctxt.findContextualValueDeserializer(vt, property);
} else { // if directly assigned, probably not yet contextual, so:
valueDeser = ctxt.handleSecondaryContextualization(valueDeser, property, vt);
}
// and finally, type deserializer needs context as well
TypeDeserializer valueTypeDeser = _valueTypeDeserializer;
if (valueTypeDeser != null) {
valueTypeDeser = valueTypeDeser.forProperty(property);
}
return withResolved(delegateDeser, valueDeser, valueTypeDeser, unwrapSingle);
}
```
| @Override
public CollectionDeserializer createContextual(DeserializationContext ctxt,
BeanProperty property) throws JsonMappingException
{
// May need to resolve types for delegate-based creators:
JsonDeserializer<Object> delegateDeser = null;
if (_valueInstantiator != null) {
if (_valueInstantiator.canCreateUsingDelegate()) {
JavaType delegateType = _valueInstantiator.getDelegateType(ctxt.getConfig());
if (delegateType == null) {
throw new IllegalArgumentException("Invalid delegate-creator definition for "+_collectionType
+": value instantiator ("+_valueInstantiator.getClass().getName()
+") returned true for 'canCreateUsingDelegate()', but null for 'getDelegateType()'");
}
delegateDeser = findDeserializer(ctxt, delegateType, property);
}
}
// [databind#1043]: allow per-property allow-wrapping of single overrides:
// 11-Dec-2015, tatu: Should we pass basic `Collection.class`, or more refined? Mostly
// comes down to "List vs Collection" I suppose... for now, pass Collection
Boolean unwrapSingle = findFormatFeature(ctxt, property, Collection.class,
JsonFormat.Feature.ACCEPT_SINGLE_VALUE_AS_ARRAY);
// also, often value deserializer is resolved here:
JsonDeserializer<?> valueDeser = _valueDeserializer;
// May have a content converter
valueDeser = findConvertingContentDeserializer(ctxt, property, valueDeser);
final JavaType vt = _collectionType.getContentType();
if (valueDeser == null) {
valueDeser = ctxt.findContextualValueDeserializer(vt, property);
} else { // if directly assigned, probably not yet contextual, so:
valueDeser = ctxt.handleSecondaryContextualization(valueDeser, property, vt);
}
// and finally, type deserializer needs context as well
TypeDeserializer valueTypeDeser = _valueTypeDeserializer;
if (valueTypeDeser != null) {
valueTypeDeser = valueTypeDeser.forProperty(property);
}
return withResolved(delegateDeser, valueDeser, valueTypeDeser, unwrapSingle);
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Method called to finalize setup of this deserializer,
* when it is known for which property deserializer is needed
* for.
*/
/*
/**********************************************************
/* Validation, post-processing (ResolvableDeserializer)
/**********************************************************
*/
@Override
public CollectionDeserializer createContextual(DeserializationContext ctxt,
BeanProperty property) throws JsonMappingException
{
// May need to resolve types for delegate-based creators:
JsonDeserializer<Object> delegateDeser = null;
if (_valueInstantiator != null) {
if (_valueInstantiator.canCreateUsingDelegate()) {
JavaType delegateType = _valueInstantiator.getDelegateType(ctxt.getConfig());
if (delegateType == null) {
throw new IllegalArgumentException("Invalid delegate-creator definition for "+_collectionType
+": value instantiator ("+_valueInstantiator.getClass().getName()
+") returned true for 'canCreateUsingDelegate()', but null for 'getDelegateType()'");
}
delegateDeser = findDeserializer(ctxt, delegateType, property);
}
}
// [databind#1043]: allow per-property allow-wrapping of single overrides:
// 11-Dec-2015, tatu: Should we pass basic `Collection.class`, or more refined? Mostly
// comes down to "List vs Collection" I suppose... for now, pass Collection
Boolean unwrapSingle = findFormatFeature(ctxt, property, Collection.class,
JsonFormat.Feature.ACCEPT_SINGLE_VALUE_AS_ARRAY);
// also, often value deserializer is resolved here:
JsonDeserializer<?> valueDeser = _valueDeserializer;
// May have a content converter
valueDeser = findConvertingContentDeserializer(ctxt, property, valueDeser);
final JavaType vt = _collectionType.getContentType();
if (valueDeser == null) {
valueDeser = ctxt.findContextualValueDeserializer(vt, property);
} else { // if directly assigned, probably not yet contextual, so:
valueDeser = ctxt.handleSecondaryContextualization(valueDeser, property, vt);
}
// and finally, type deserializer needs context as well
TypeDeserializer valueTypeDeser = _valueTypeDeserializer;
if (valueTypeDeser != null) {
valueTypeDeser = valueTypeDeser.forProperty(property);
}
return withResolved(delegateDeser, valueDeser, valueTypeDeser, unwrapSingle);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
16 | a0035c3b824f1623826c977ed8fdf325f61199e76511ed6e8b424af1b3c61544 | protected final boolean _add(Annotation ann) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/*
/**********************************************************
/* Helper methods
/**********************************************************
*/
protected final boolean _add(Annotation ann) {
if (_annotations == null) {
_annotations = new HashMap<Class<? extends Annotation>,Annotation>();
}
Annotation previous = _annotations.put(ann.annotationType(), ann);
return (previous == null) || !previous.equals(ann);
}
```
| protected final boolean _add(Annotation ann) {
if (_annotations == null) {
_annotations = new HashMap<Class<? extends Annotation>,Annotation>();
}
Annotation previous = _annotations.put(ann.annotationType(), ann);
return (previous == null) || !previous.equals(ann);
} | false | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/*
/**********************************************************
/* Helper methods
/**********************************************************
*/
protected final boolean _add(Annotation ann) {
if (_annotations == null) {
_annotations = new HashMap<Class<? extends Annotation>,Annotation>();
}
Annotation previous = _annotations.put(ann.annotationType(), ann);
return (previous == null) || !previous.equals(ann);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
6 | a073e136ee01da2c84b0ed067d44f6b31914a5a91cfcc1ac44eda31694277e20 | @SuppressWarnings("unchecked") // Casts guarded by conditionals.
static TypeAdapter<?> getTypeAdapter(ConstructorConstructor constructorConstructor, Gson gson,
TypeToken<?> fieldType, JsonAdapter annotation) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@SuppressWarnings("unchecked") // Casts guarded by conditionals.
static TypeAdapter<?> getTypeAdapter(ConstructorConstructor constructorConstructor, Gson gson,
TypeToken<?> fieldType, JsonAdapter annotation) {
Class<?> value = annotation.value();
TypeAdapter<?> typeAdapter;
if (TypeAdapter.class.isAssignableFrom(value)) {
Class<TypeAdapter<?>> typeAdapterClass = (Class<TypeAdapter<?>>) value;
typeAdapter = constructorConstructor.get(TypeToken.get(typeAdapterClass)).construct();
} else if (TypeAdapterFactory.class.isAssignableFrom(value)) {
Class<TypeAdapterFactory> typeAdapterFactory = (Class<TypeAdapterFactory>) value;
typeAdapter = constructorConstructor.get(TypeToken.get(typeAdapterFactory))
.construct()
.create(gson, fieldType);
} else {
throw new IllegalArgumentException(
"@JsonAdapter value must be TypeAdapter or TypeAdapterFactory reference.");
}
if (typeAdapter != null) {
typeAdapter = typeAdapter.nullSafe();
}
return typeAdapter;
}
```
| @SuppressWarnings("unchecked") // Casts guarded by conditionals.
static TypeAdapter<?> getTypeAdapter(ConstructorConstructor constructorConstructor, Gson gson,
TypeToken<?> fieldType, JsonAdapter annotation) {
Class<?> value = annotation.value();
TypeAdapter<?> typeAdapter;
if (TypeAdapter.class.isAssignableFrom(value)) {
Class<TypeAdapter<?>> typeAdapterClass = (Class<TypeAdapter<?>>) value;
typeAdapter = constructorConstructor.get(TypeToken.get(typeAdapterClass)).construct();
} else if (TypeAdapterFactory.class.isAssignableFrom(value)) {
Class<TypeAdapterFactory> typeAdapterFactory = (Class<TypeAdapterFactory>) value;
typeAdapter = constructorConstructor.get(TypeToken.get(typeAdapterFactory))
.construct()
.create(gson, fieldType);
} else {
throw new IllegalArgumentException(
"@JsonAdapter value must be TypeAdapter or TypeAdapterFactory reference.");
}
if (typeAdapter != null) {
typeAdapter = typeAdapter.nullSafe();
}
return typeAdapter;
} | false | Gson | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@SuppressWarnings("unchecked") // Casts guarded by conditionals.
static TypeAdapter<?> getTypeAdapter(ConstructorConstructor constructorConstructor, Gson gson,
TypeToken<?> fieldType, JsonAdapter annotation) {
Class<?> value = annotation.value();
TypeAdapter<?> typeAdapter;
if (TypeAdapter.class.isAssignableFrom(value)) {
Class<TypeAdapter<?>> typeAdapterClass = (Class<TypeAdapter<?>>) value;
typeAdapter = constructorConstructor.get(TypeToken.get(typeAdapterClass)).construct();
} else if (TypeAdapterFactory.class.isAssignableFrom(value)) {
Class<TypeAdapterFactory> typeAdapterFactory = (Class<TypeAdapterFactory>) value;
typeAdapter = constructorConstructor.get(TypeToken.get(typeAdapterFactory))
.construct()
.create(gson, fieldType);
} else {
throw new IllegalArgumentException(
"@JsonAdapter value must be TypeAdapter or TypeAdapterFactory reference.");
}
if (typeAdapter != null) {
typeAdapter = typeAdapter.nullSafe();
}
return typeAdapter;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
26 | a0a09364d1ed073077d49991d70ebc89f573398eaf2a0a6790251d7660a23fa9 | public Document clean(Document dirtyDocument) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
Creates a new, clean document, from the original dirty document, containing only elements allowed by the whitelist.
The original document is not modified. Only elements from the dirt document's <code>body</code> are used.
@param dirtyDocument Untrusted base document to clean.
@return cleaned document.
*/
public Document clean(Document dirtyDocument) {
Validate.notNull(dirtyDocument);
Document clean = Document.createShell(dirtyDocument.baseUri());
if (dirtyDocument.body() != null) // frameset documents won't have a body. the clean doc will have empty body.
copySafeNodes(dirtyDocument.body(), clean.body());
return clean;
}
```
| public Document clean(Document dirtyDocument) {
Validate.notNull(dirtyDocument);
Document clean = Document.createShell(dirtyDocument.baseUri());
if (dirtyDocument.body() != null) // frameset documents won't have a body. the clean doc will have empty body.
copySafeNodes(dirtyDocument.body(), clean.body());
return clean;
} | false | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
Creates a new, clean document, from the original dirty document, containing only elements allowed by the whitelist.
The original document is not modified. Only elements from the dirt document's <code>body</code> are used.
@param dirtyDocument Untrusted base document to clean.
@return cleaned document.
*/
public Document clean(Document dirtyDocument) {
Validate.notNull(dirtyDocument);
Document clean = Document.createShell(dirtyDocument.baseUri());
if (dirtyDocument.body() != null) // frameset documents won't have a body. the clean doc will have empty body.
copySafeNodes(dirtyDocument.body(), clean.body());
return clean;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
25 | a0bfe0d2793b49c736f23a0a05af2ad10900e0ca91d6ee85fb6ed450b13e1b1d | public int getOffsetFromLocal(long instantLocal) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Gets the millisecond offset to subtract from local time to get UTC time.
* This offset can be used to undo adding the offset obtained by getOffset.
*
* <pre>
* millisLocal == millisUTC + getOffset(millisUTC)
* millisUTC == millisLocal - getOffsetFromLocal(millisLocal)
* </pre>
*
* NOTE: After calculating millisLocal, some error may be introduced. At
* offset transitions (due to DST or other historical changes), ranges of
* local times may map to different UTC times.
* <p>
* This method will return an offset suitable for calculating an instant
* after any DST gap. For example, consider a zone with a cutover
* from 01:00 to 01:59:<br />
* Input: 00:00 Output: 00:00<br />
* Input: 00:30 Output: 00:30<br />
* Input: 01:00 Output: 02:00<br />
* Input: 01:30 Output: 02:30<br />
* Input: 02:00 Output: 02:00<br />
* Input: 02:30 Output: 02:30<br />
* <p>
* During a DST overlap (where the local time is ambiguous) this method will return
* the earlier instant. The combination of these two rules is to always favour
* daylight (summer) time over standard (winter) time.
* <p>
* NOTE: Prior to v2.0, the DST overlap behaviour was not defined and varied by hemisphere.
* Prior to v1.5, the DST gap behaviour was also not defined.
*
* @param instantLocal the millisecond instant, relative to this time zone, to get the offset for
* @return the millisecond offset to subtract from local time to get UTC time
*/
public int getOffsetFromLocal(long instantLocal) {
// get the offset at instantLocal (first estimate)
final int offsetLocal = getOffset(instantLocal);
// adjust instantLocal using the estimate and recalc the offset
final long instantAdjusted = instantLocal - offsetLocal;
final int offsetAdjusted = getOffset(instantAdjusted);
// if the offsets differ, we must be near a DST boundary
if (offsetLocal != offsetAdjusted) {
// we need to ensure that time is always after the DST gap
// this happens naturally for positive offsets, but not for negative
if ((offsetLocal - offsetAdjusted) < 0) {
// if we just return offsetAdjusted then the time is pushed
// back before the transition, whereas it should be
// on or after the transition
long nextLocal = nextTransition(instantAdjusted);
long nextAdjusted = nextTransition(instantLocal - offsetAdjusted);
if (nextLocal != nextAdjusted) {
return offsetLocal;
}
}
}
return offsetAdjusted;
}
```
| public int getOffsetFromLocal(long instantLocal) {
// get the offset at instantLocal (first estimate)
final int offsetLocal = getOffset(instantLocal);
// adjust instantLocal using the estimate and recalc the offset
final long instantAdjusted = instantLocal - offsetLocal;
final int offsetAdjusted = getOffset(instantAdjusted);
// if the offsets differ, we must be near a DST boundary
if (offsetLocal != offsetAdjusted) {
// we need to ensure that time is always after the DST gap
// this happens naturally for positive offsets, but not for negative
if ((offsetLocal - offsetAdjusted) < 0) {
// if we just return offsetAdjusted then the time is pushed
// back before the transition, whereas it should be
// on or after the transition
long nextLocal = nextTransition(instantAdjusted);
long nextAdjusted = nextTransition(instantLocal - offsetAdjusted);
if (nextLocal != nextAdjusted) {
return offsetLocal;
}
}
}
return offsetAdjusted;
} | true | Time | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Gets the millisecond offset to subtract from local time to get UTC time.
* This offset can be used to undo adding the offset obtained by getOffset.
*
* <pre>
* millisLocal == millisUTC + getOffset(millisUTC)
* millisUTC == millisLocal - getOffsetFromLocal(millisLocal)
* </pre>
*
* NOTE: After calculating millisLocal, some error may be introduced. At
* offset transitions (due to DST or other historical changes), ranges of
* local times may map to different UTC times.
* <p>
* This method will return an offset suitable for calculating an instant
* after any DST gap. For example, consider a zone with a cutover
* from 01:00 to 01:59:<br />
* Input: 00:00 Output: 00:00<br />
* Input: 00:30 Output: 00:30<br />
* Input: 01:00 Output: 02:00<br />
* Input: 01:30 Output: 02:30<br />
* Input: 02:00 Output: 02:00<br />
* Input: 02:30 Output: 02:30<br />
* <p>
* During a DST overlap (where the local time is ambiguous) this method will return
* the earlier instant. The combination of these two rules is to always favour
* daylight (summer) time over standard (winter) time.
* <p>
* NOTE: Prior to v2.0, the DST overlap behaviour was not defined and varied by hemisphere.
* Prior to v1.5, the DST gap behaviour was also not defined.
*
* @param instantLocal the millisecond instant, relative to this time zone, to get the offset for
* @return the millisecond offset to subtract from local time to get UTC time
*/
public int getOffsetFromLocal(long instantLocal) {
// get the offset at instantLocal (first estimate)
final int offsetLocal = getOffset(instantLocal);
// adjust instantLocal using the estimate and recalc the offset
final long instantAdjusted = instantLocal - offsetLocal;
final int offsetAdjusted = getOffset(instantAdjusted);
// if the offsets differ, we must be near a DST boundary
if (offsetLocal != offsetAdjusted) {
// we need to ensure that time is always after the DST gap
// this happens naturally for positive offsets, but not for negative
if ((offsetLocal - offsetAdjusted) < 0) {
// if we just return offsetAdjusted then the time is pushed
// back before the transition, whereas it should be
// on or after the transition
long nextLocal = nextTransition(instantAdjusted);
long nextAdjusted = nextTransition(instantLocal - offsetAdjusted);
if (nextLocal != nextAdjusted) {
return offsetLocal;
}
}
}
return offsetAdjusted;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
55 | a0e2a98b759b308313848788e2a61860e9bcd22e55a0594fd14a473cc506b9ec | public void stop() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Stop the stopwatch.</p>
*
* <p>This method ends a new timing session, allowing the time to be retrieved.</p>
*
* @throws IllegalStateException if the StopWatch is not running.
*/
public void stop() {
if(this.runningState != STATE_RUNNING && this.runningState != STATE_SUSPENDED) {
throw new IllegalStateException("Stopwatch is not running. ");
}
if(this.runningState == STATE_RUNNING) {
stopTime = System.currentTimeMillis();
}
this.runningState = STATE_STOPPED;
}
```
| public void stop() {
if(this.runningState != STATE_RUNNING && this.runningState != STATE_SUSPENDED) {
throw new IllegalStateException("Stopwatch is not running. ");
}
if(this.runningState == STATE_RUNNING) {
stopTime = System.currentTimeMillis();
}
this.runningState = STATE_STOPPED;
} | false | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Stop the stopwatch.</p>
*
* <p>This method ends a new timing session, allowing the time to be retrieved.</p>
*
* @throws IllegalStateException if the StopWatch is not running.
*/
public void stop() {
if(this.runningState != STATE_RUNNING && this.runningState != STATE_SUSPENDED) {
throw new IllegalStateException("Stopwatch is not running. ");
}
if(this.runningState == STATE_RUNNING) {
stopTime = System.currentTimeMillis();
}
this.runningState = STATE_STOPPED;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
17 | a11093ddbb37a1d137907c2b1f01a8505168f67d2a46398af368427087461e5c | protected void burstToken(String token, boolean stopAtNonOption)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Breaks <code>token</code> into its constituent parts
* using the following algorithm.
* <ul>
* <li>ignore the first character ("<b>-</b>")</li>
* <li>foreach remaining character check if an {@link Option}
* exists with that id.</li>
* <li>if an {@link Option} does exist then add that character
* prepended with "<b>-</b>" to the list of processed tokens.</li>
* <li>if the {@link Option} can have an argument value and there
* are remaining characters in the token then add the remaining
* characters as a token to the list of processed tokens.</li>
* <li>if an {@link Option} does <b>NOT</b> exist <b>AND</b>
* <code>stopAtNonOption</code> <b>IS</b> set then add the special token
* "<b>--</b>" followed by the remaining characters and also
* the remaining tokens directly to the processed tokens list.</li>
* <li>if an {@link Option} does <b>NOT</b> exist <b>AND</b>
* <code>stopAtNonOption</code> <b>IS NOT</b> set then add that
* character prepended with "<b>-</b>".</li>
* </ul>
* </p>
*
* @param token The current token to be <b>burst</b>
* @param stopAtNonOption Specifies whether to stop processing
* at the first non-Option encountered.
*/
protected void burstToken(String token, boolean stopAtNonOption)
{
for (int i = 1; i < token.length(); i++)
{
String ch = String.valueOf(token.charAt(i));
if (options.hasOption(ch))
{
tokens.add("-" + ch);
currentOption = options.getOption(ch);
if (currentOption.hasArg() && (token.length() != (i + 1)))
{
tokens.add(token.substring(i + 1));
break;
}
}
else if (stopAtNonOption)
{
process(token.substring(i));
}
else
{
tokens.add(token);
break;
}
}
}
```
| protected void burstToken(String token, boolean stopAtNonOption)
{
for (int i = 1; i < token.length(); i++)
{
String ch = String.valueOf(token.charAt(i));
if (options.hasOption(ch))
{
tokens.add("-" + ch);
currentOption = options.getOption(ch);
if (currentOption.hasArg() && (token.length() != (i + 1)))
{
tokens.add(token.substring(i + 1));
break;
}
}
else if (stopAtNonOption)
{
process(token.substring(i));
}
else
{
tokens.add(token);
break;
}
}
} | true | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Breaks <code>token</code> into its constituent parts
* using the following algorithm.
* <ul>
* <li>ignore the first character ("<b>-</b>")</li>
* <li>foreach remaining character check if an {@link Option}
* exists with that id.</li>
* <li>if an {@link Option} does exist then add that character
* prepended with "<b>-</b>" to the list of processed tokens.</li>
* <li>if the {@link Option} can have an argument value and there
* are remaining characters in the token then add the remaining
* characters as a token to the list of processed tokens.</li>
* <li>if an {@link Option} does <b>NOT</b> exist <b>AND</b>
* <code>stopAtNonOption</code> <b>IS</b> set then add the special token
* "<b>--</b>" followed by the remaining characters and also
* the remaining tokens directly to the processed tokens list.</li>
* <li>if an {@link Option} does <b>NOT</b> exist <b>AND</b>
* <code>stopAtNonOption</code> <b>IS NOT</b> set then add that
* character prepended with "<b>-</b>".</li>
* </ul>
* </p>
*
* @param token The current token to be <b>burst</b>
* @param stopAtNonOption Specifies whether to stop processing
* at the first non-Option encountered.
*/
protected void burstToken(String token, boolean stopAtNonOption)
{
for (int i = 1; i < token.length(); i++)
{
String ch = String.valueOf(token.charAt(i));
if (options.hasOption(ch))
{
tokens.add("-" + ch);
currentOption = options.getOption(ch);
if (currentOption.hasArg() && (token.length() != (i + 1)))
{
tokens.add(token.substring(i + 1));
break;
}
}
else if (stopAtNonOption)
{
process(token.substring(i));
}
else
{
tokens.add(token);
break;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
13 | a1a1ed83d4171f9182e3e779336c1552f27eeb6ad2374eabb061aacbaaca6fc5 | public Object handle(Invocation invocation) throws Throwable | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public Object handle(Invocation invocation) throws Throwable {
if (invocationContainerImpl.hasAnswersForStubbing()) {
// stubbing voids with stubVoid() or doAnswer() style
InvocationMatcher invocationMatcher = matchersBinder.bindMatchers(mockingProgress
.getArgumentMatcherStorage(), invocation);
invocationContainerImpl.setMethodForStubbing(invocationMatcher);
return null;
}
VerificationMode verificationMode = mockingProgress.pullVerificationMode();
InvocationMatcher invocationMatcher = matchersBinder.bindMatchers(mockingProgress.getArgumentMatcherStorage(),
invocation);
mockingProgress.validateState();
//if verificationMode is not null then someone is doing verify()
if (verificationMode != null) {
//We need to check if verification was started on the correct mock
// - see VerifyingWithAnExtraCallToADifferentMockTest (bug 138)
if (((MockAwareVerificationMode) verificationMode).getMock() == invocation.getMock()) {
VerificationDataImpl data = new VerificationDataImpl(invocationContainerImpl, invocationMatcher);
verificationMode.verify(data);
return null;
} else {
// this means there is an invocation on a different mock. Re-adding verification mode
// - see VerifyingWithAnExtraCallToADifferentMockTest (bug 138)
mockingProgress.verificationStarted(verificationMode);
}
}
invocationContainerImpl.setInvocationForPotentialStubbing(invocationMatcher);
OngoingStubbingImpl<T> ongoingStubbing = new OngoingStubbingImpl<T>(invocationContainerImpl);
mockingProgress.reportOngoingStubbing(ongoingStubbing);
StubbedInvocationMatcher stubbedInvocation = invocationContainerImpl.findAnswerFor(invocation);
if (stubbedInvocation != null) {
stubbedInvocation.captureArgumentsFrom(invocation);
return stubbedInvocation.answer(invocation);
} else {
Object ret = mockSettings.getDefaultAnswer().answer(invocation);
// redo setting invocation for potential stubbing in case of partial
// mocks / spies.
// Without it, the real method inside 'when' might have delegated
// to other self method and overwrite the intended stubbed method
// with a different one. The reset is required to avoid runtime exception that validates return type with stubbed method signature.
invocationContainerImpl.resetInvocationForPotentialStubbing(invocationMatcher);
return ret;
}
}
```
| public Object handle(Invocation invocation) throws Throwable {
if (invocationContainerImpl.hasAnswersForStubbing()) {
// stubbing voids with stubVoid() or doAnswer() style
InvocationMatcher invocationMatcher = matchersBinder.bindMatchers(mockingProgress
.getArgumentMatcherStorage(), invocation);
invocationContainerImpl.setMethodForStubbing(invocationMatcher);
return null;
}
VerificationMode verificationMode = mockingProgress.pullVerificationMode();
InvocationMatcher invocationMatcher = matchersBinder.bindMatchers(mockingProgress.getArgumentMatcherStorage(),
invocation);
mockingProgress.validateState();
//if verificationMode is not null then someone is doing verify()
if (verificationMode != null) {
//We need to check if verification was started on the correct mock
// - see VerifyingWithAnExtraCallToADifferentMockTest (bug 138)
if (((MockAwareVerificationMode) verificationMode).getMock() == invocation.getMock()) {
VerificationDataImpl data = new VerificationDataImpl(invocationContainerImpl, invocationMatcher);
verificationMode.verify(data);
return null;
} else {
// this means there is an invocation on a different mock. Re-adding verification mode
// - see VerifyingWithAnExtraCallToADifferentMockTest (bug 138)
mockingProgress.verificationStarted(verificationMode);
}
}
invocationContainerImpl.setInvocationForPotentialStubbing(invocationMatcher);
OngoingStubbingImpl<T> ongoingStubbing = new OngoingStubbingImpl<T>(invocationContainerImpl);
mockingProgress.reportOngoingStubbing(ongoingStubbing);
StubbedInvocationMatcher stubbedInvocation = invocationContainerImpl.findAnswerFor(invocation);
if (stubbedInvocation != null) {
stubbedInvocation.captureArgumentsFrom(invocation);
return stubbedInvocation.answer(invocation);
} else {
Object ret = mockSettings.getDefaultAnswer().answer(invocation);
// redo setting invocation for potential stubbing in case of partial
// mocks / spies.
// Without it, the real method inside 'when' might have delegated
// to other self method and overwrite the intended stubbed method
// with a different one. The reset is required to avoid runtime exception that validates return type with stubbed method signature.
invocationContainerImpl.resetInvocationForPotentialStubbing(invocationMatcher);
return ret;
}
} | false | Mockito | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public Object handle(Invocation invocation) throws Throwable {
if (invocationContainerImpl.hasAnswersForStubbing()) {
// stubbing voids with stubVoid() or doAnswer() style
InvocationMatcher invocationMatcher = matchersBinder.bindMatchers(mockingProgress
.getArgumentMatcherStorage(), invocation);
invocationContainerImpl.setMethodForStubbing(invocationMatcher);
return null;
}
VerificationMode verificationMode = mockingProgress.pullVerificationMode();
InvocationMatcher invocationMatcher = matchersBinder.bindMatchers(mockingProgress.getArgumentMatcherStorage(),
invocation);
mockingProgress.validateState();
//if verificationMode is not null then someone is doing verify()
if (verificationMode != null) {
//We need to check if verification was started on the correct mock
// - see VerifyingWithAnExtraCallToADifferentMockTest (bug 138)
if (((MockAwareVerificationMode) verificationMode).getMock() == invocation.getMock()) {
VerificationDataImpl data = new VerificationDataImpl(invocationContainerImpl, invocationMatcher);
verificationMode.verify(data);
return null;
} else {
// this means there is an invocation on a different mock. Re-adding verification mode
// - see VerifyingWithAnExtraCallToADifferentMockTest (bug 138)
mockingProgress.verificationStarted(verificationMode);
}
}
invocationContainerImpl.setInvocationForPotentialStubbing(invocationMatcher);
OngoingStubbingImpl<T> ongoingStubbing = new OngoingStubbingImpl<T>(invocationContainerImpl);
mockingProgress.reportOngoingStubbing(ongoingStubbing);
StubbedInvocationMatcher stubbedInvocation = invocationContainerImpl.findAnswerFor(invocation);
if (stubbedInvocation != null) {
stubbedInvocation.captureArgumentsFrom(invocation);
return stubbedInvocation.answer(invocation);
} else {
Object ret = mockSettings.getDefaultAnswer().answer(invocation);
// redo setting invocation for potential stubbing in case of partial
// mocks / spies.
// Without it, the real method inside 'when' might have delegated
// to other self method and overwrite the intended stubbed method
// with a different one. The reset is required to avoid runtime exception that validates return type with stubbed method signature.
invocationContainerImpl.resetInvocationForPotentialStubbing(invocationMatcher);
return ret;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
39 | a232b48bbb28dd7ef63ba021a1ae87145592b5a62375f18a61bbc6f24339f2ad | @Override
String toStringHelper(boolean forAnnotations) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
String toStringHelper(boolean forAnnotations) {
if (hasReferenceName()) {
return getReferenceName();
} else if (prettyPrint) {
// Don't pretty print recursively.
prettyPrint = false;
// Use a tree set so that the properties are sorted.
Set<String> propertyNames = Sets.newTreeSet();
for (ObjectType current = this;
current != null && !current.isNativeObjectType() &&
propertyNames.size() <= MAX_PRETTY_PRINTED_PROPERTIES;
current = current.getImplicitPrototype()) {
propertyNames.addAll(current.getOwnPropertyNames());
}
StringBuilder sb = new StringBuilder();
sb.append("{");
int i = 0;
for (String property : propertyNames) {
if (i > 0) {
sb.append(", ");
}
sb.append(property);
sb.append(": ");
sb.append(getPropertyType(property).toString());
++i;
if (i == MAX_PRETTY_PRINTED_PROPERTIES) {
sb.append(", ...");
break;
}
}
sb.append("}");
prettyPrint = true;
return sb.toString();
} else {
return "{...}";
}
}
```
| @Override
String toStringHelper(boolean forAnnotations) {
if (hasReferenceName()) {
return getReferenceName();
} else if (prettyPrint) {
// Don't pretty print recursively.
prettyPrint = false;
// Use a tree set so that the properties are sorted.
Set<String> propertyNames = Sets.newTreeSet();
for (ObjectType current = this;
current != null && !current.isNativeObjectType() &&
propertyNames.size() <= MAX_PRETTY_PRINTED_PROPERTIES;
current = current.getImplicitPrototype()) {
propertyNames.addAll(current.getOwnPropertyNames());
}
StringBuilder sb = new StringBuilder();
sb.append("{");
int i = 0;
for (String property : propertyNames) {
if (i > 0) {
sb.append(", ");
}
sb.append(property);
sb.append(": ");
sb.append(getPropertyType(property).toString());
++i;
if (i == MAX_PRETTY_PRINTED_PROPERTIES) {
sb.append(", ...");
break;
}
}
sb.append("}");
prettyPrint = true;
return sb.toString();
} else {
return "{...}";
}
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
String toStringHelper(boolean forAnnotations) {
if (hasReferenceName()) {
return getReferenceName();
} else if (prettyPrint) {
// Don't pretty print recursively.
prettyPrint = false;
// Use a tree set so that the properties are sorted.
Set<String> propertyNames = Sets.newTreeSet();
for (ObjectType current = this;
current != null && !current.isNativeObjectType() &&
propertyNames.size() <= MAX_PRETTY_PRINTED_PROPERTIES;
current = current.getImplicitPrototype()) {
propertyNames.addAll(current.getOwnPropertyNames());
}
StringBuilder sb = new StringBuilder();
sb.append("{");
int i = 0;
for (String property : propertyNames) {
if (i > 0) {
sb.append(", ");
}
sb.append(property);
sb.append(": ");
sb.append(getPropertyType(property).toString());
++i;
if (i == MAX_PRETTY_PRINTED_PROPERTIES) {
sb.append(", ...");
break;
}
}
sb.append("}");
prettyPrint = true;
return sb.toString();
} else {
return "{...}";
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
26 | a29b2be64e65167e11bbc0903effff02db14687b8e9ce95785e8a570fff13485 | public Document clean(Document dirtyDocument) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
Creates a new, clean document, from the original dirty document, containing only elements allowed by the whitelist.
The original document is not modified. Only elements from the dirt document's <code>body</code> are used.
@param dirtyDocument Untrusted base document to clean.
@return cleaned document.
*/
public Document clean(Document dirtyDocument) {
Validate.notNull(dirtyDocument);
Document clean = Document.createShell(dirtyDocument.baseUri());
copySafeNodes(dirtyDocument.body(), clean.body());
return clean;
}
```
| public Document clean(Document dirtyDocument) {
Validate.notNull(dirtyDocument);
Document clean = Document.createShell(dirtyDocument.baseUri());
copySafeNodes(dirtyDocument.body(), clean.body());
return clean;
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
Creates a new, clean document, from the original dirty document, containing only elements allowed by the whitelist.
The original document is not modified. Only elements from the dirt document's <code>body</code> are used.
@param dirtyDocument Untrusted base document to clean.
@return cleaned document.
*/
public Document clean(Document dirtyDocument) {
Validate.notNull(dirtyDocument);
Document clean = Document.createShell(dirtyDocument.baseUri());
copySafeNodes(dirtyDocument.body(), clean.body());
return clean;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
24 | a29e9541be712528078ed804821c2683d1b9ac092e58a5d3740c97cae550e60e | public Paint getPaint(double value) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns a paint for the specified value.
*
* @param value the value (must be within the range specified by the
* lower and upper bounds for the scale).
*
* @return A paint for the specified value.
*/
public Paint getPaint(double value) {
double v = Math.max(value, this.lowerBound);
v = Math.min(v, this.upperBound);
int g = (int) ((value - this.lowerBound) / (this.upperBound
- this.lowerBound) * 255.0);
return new Color(g, g, g);
}
```
| public Paint getPaint(double value) {
double v = Math.max(value, this.lowerBound);
v = Math.min(v, this.upperBound);
int g = (int) ((value - this.lowerBound) / (this.upperBound
- this.lowerBound) * 255.0);
return new Color(g, g, g);
} | true | Chart | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns a paint for the specified value.
*
* @param value the value (must be within the range specified by the
* lower and upper bounds for the scale).
*
* @return A paint for the specified value.
*/
public Paint getPaint(double value) {
double v = Math.max(value, this.lowerBound);
v = Math.min(v, this.upperBound);
int g = (int) ((value - this.lowerBound) / (this.upperBound
- this.lowerBound) * 255.0);
return new Color(g, g, g);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
17 | a3be5c9849735d2e5edcb8b2cf28c052fdf1919dca1bfb738e049ff02b1cb5f0 | protected void burstToken(String token, boolean stopAtNonOption)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Breaks <code>token</code> into its constituent parts
* using the following algorithm.
* <ul>
* <li>ignore the first character ("<b>-</b>")</li>
* <li>foreach remaining character check if an {@link Option}
* exists with that id.</li>
* <li>if an {@link Option} does exist then add that character
* prepended with "<b>-</b>" to the list of processed tokens.</li>
* <li>if the {@link Option} can have an argument value and there
* are remaining characters in the token then add the remaining
* characters as a token to the list of processed tokens.</li>
* <li>if an {@link Option} does <b>NOT</b> exist <b>AND</b>
* <code>stopAtNonOption</code> <b>IS</b> set then add the special token
* "<b>--</b>" followed by the remaining characters and also
* the remaining tokens directly to the processed tokens list.</li>
* <li>if an {@link Option} does <b>NOT</b> exist <b>AND</b>
* <code>stopAtNonOption</code> <b>IS NOT</b> set then add that
* character prepended with "<b>-</b>".</li>
* </ul>
* </p>
*
* @param token The current token to be <b>burst</b>
* @param stopAtNonOption Specifies whether to stop processing
* at the first non-Option encountered.
*/
protected void burstToken(String token, boolean stopAtNonOption)
{
for (int i = 1; i < token.length(); i++)
{
String ch = String.valueOf(token.charAt(i));
if (options.hasOption(ch))
{
tokens.add("-" + ch);
currentOption = options.getOption(ch);
if (currentOption.hasArg() && (token.length() != (i + 1)))
{
tokens.add(token.substring(i + 1));
break;
}
}
else if (stopAtNonOption)
{
process(token.substring(i));
break;
}
else
{
tokens.add(token);
break;
}
}
}
```
| protected void burstToken(String token, boolean stopAtNonOption)
{
for (int i = 1; i < token.length(); i++)
{
String ch = String.valueOf(token.charAt(i));
if (options.hasOption(ch))
{
tokens.add("-" + ch);
currentOption = options.getOption(ch);
if (currentOption.hasArg() && (token.length() != (i + 1)))
{
tokens.add(token.substring(i + 1));
break;
}
}
else if (stopAtNonOption)
{
process(token.substring(i));
break;
}
else
{
tokens.add(token);
break;
}
}
} | false | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Breaks <code>token</code> into its constituent parts
* using the following algorithm.
* <ul>
* <li>ignore the first character ("<b>-</b>")</li>
* <li>foreach remaining character check if an {@link Option}
* exists with that id.</li>
* <li>if an {@link Option} does exist then add that character
* prepended with "<b>-</b>" to the list of processed tokens.</li>
* <li>if the {@link Option} can have an argument value and there
* are remaining characters in the token then add the remaining
* characters as a token to the list of processed tokens.</li>
* <li>if an {@link Option} does <b>NOT</b> exist <b>AND</b>
* <code>stopAtNonOption</code> <b>IS</b> set then add the special token
* "<b>--</b>" followed by the remaining characters and also
* the remaining tokens directly to the processed tokens list.</li>
* <li>if an {@link Option} does <b>NOT</b> exist <b>AND</b>
* <code>stopAtNonOption</code> <b>IS NOT</b> set then add that
* character prepended with "<b>-</b>".</li>
* </ul>
* </p>
*
* @param token The current token to be <b>burst</b>
* @param stopAtNonOption Specifies whether to stop processing
* at the first non-Option encountered.
*/
protected void burstToken(String token, boolean stopAtNonOption)
{
for (int i = 1; i < token.length(); i++)
{
String ch = String.valueOf(token.charAt(i));
if (options.hasOption(ch))
{
tokens.add("-" + ch);
currentOption = options.getOption(ch);
if (currentOption.hasArg() && (token.length() != (i + 1)))
{
tokens.add(token.substring(i + 1));
break;
}
}
else if (stopAtNonOption)
{
process(token.substring(i));
break;
}
else
{
tokens.add(token);
break;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
17 | a3c119700f90ac83b9e1bf78789b688cd83e3ae39cc59f1360fe1bb75f04687d | @Override
public Date read(JsonReader in) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public Date read(JsonReader in) throws IOException {
if (in.peek() == JsonToken.NULL) {
in.nextNull();
return null;
}
Date date = deserializeToDate(in.nextString());
if (dateType == Date.class) {
return date;
} else if (dateType == Timestamp.class) {
return new Timestamp(date.getTime());
} else if (dateType == java.sql.Date.class) {
return new java.sql.Date(date.getTime());
} else {
// This must never happen: dateType is guarded in the primary constructor
throw new AssertionError();
}
}
```
| @Override
public Date read(JsonReader in) throws IOException {
if (in.peek() == JsonToken.NULL) {
in.nextNull();
return null;
}
Date date = deserializeToDate(in.nextString());
if (dateType == Date.class) {
return date;
} else if (dateType == Timestamp.class) {
return new Timestamp(date.getTime());
} else if (dateType == java.sql.Date.class) {
return new java.sql.Date(date.getTime());
} else {
// This must never happen: dateType is guarded in the primary constructor
throw new AssertionError();
}
} | false | Gson | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public Date read(JsonReader in) throws IOException {
if (in.peek() == JsonToken.NULL) {
in.nextNull();
return null;
}
Date date = deserializeToDate(in.nextString());
if (dateType == Date.class) {
return date;
} else if (dateType == Timestamp.class) {
return new Timestamp(date.getTime());
} else if (dateType == java.sql.Date.class) {
return new java.sql.Date(date.getTime());
} else {
// This must never happen: dateType is guarded in the primary constructor
throw new AssertionError();
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
32 | a3ca4fd6b9f200b9d27a71352ac1574050795d882ea5b8a369cbe019aa6c9f5a | @Override
public Element clone() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public Element clone() {
Element clone = (Element) super.clone();
clone.classNames();
return clone;
}
```
| @Override
public Element clone() {
Element clone = (Element) super.clone();
clone.classNames();
return clone;
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public Element clone() {
Element clone = (Element) super.clone();
clone.classNames();
return clone;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
35 | a3f1de471f378d3544d0a1d469f891a7fba164dec165a56dc57756bba85c9649 | @SuppressWarnings("resource")
private final Object _deserialize(JsonParser p, DeserializationContext ctxt) throws IOException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Method that handles type information wrapper, locates actual
* subtype deserializer to use, and calls it to do actual
* deserialization.
*/
/*
/***************************************************************
/* Internal methods
/***************************************************************
*/
@SuppressWarnings("resource")
private final Object _deserialize(JsonParser p, DeserializationContext ctxt) throws IOException
{
// 02-Aug-2013, tatu: May need to use native type ids
if (p.canReadTypeId()) {
Object typeId = p.getTypeId();
if (typeId != null) {
return _deserializeWithNativeTypeId(p, ctxt, typeId);
}
}
// first, sanity checks
JsonToken t = p.getCurrentToken();
if (t == JsonToken.START_OBJECT) {
// should always get field name, but just in case...
if (p.nextToken() != JsonToken.FIELD_NAME) {
throw ctxt.wrongTokenException(p, JsonToken.FIELD_NAME,
"need JSON String that contains type id (for subtype of "+baseTypeName()+")");
}
} else if (t != JsonToken.FIELD_NAME) {
throw ctxt.wrongTokenException(p, JsonToken.START_OBJECT,
"need JSON Object to contain As.WRAPPER_OBJECT type information for class "+baseTypeName());
}
final String typeId = p.getText();
JsonDeserializer<Object> deser = _findDeserializer(ctxt, typeId);
p.nextToken();
// Minor complication: we may need to merge type id in?
if (_typeIdVisible && p.getCurrentToken() == JsonToken.START_OBJECT) {
// but what if there's nowhere to add it in? Error? Or skip? For now, skip.
TokenBuffer tb = new TokenBuffer(null, false);
tb.writeStartObject(); // recreate START_OBJECT
tb.writeFieldName(_typePropertyName);
tb.writeString(typeId);
p = JsonParserSequence.createFlattened(tb.asParser(p), p);
p.nextToken();
}
Object value = deser.deserialize(p, ctxt);
// And then need the closing END_OBJECT
if (p.nextToken() != JsonToken.END_OBJECT) {
throw ctxt.wrongTokenException(p, JsonToken.END_OBJECT,
"expected closing END_OBJECT after type information and deserialized value");
}
return value;
}
```
| @SuppressWarnings("resource")
private final Object _deserialize(JsonParser p, DeserializationContext ctxt) throws IOException
{
// 02-Aug-2013, tatu: May need to use native type ids
if (p.canReadTypeId()) {
Object typeId = p.getTypeId();
if (typeId != null) {
return _deserializeWithNativeTypeId(p, ctxt, typeId);
}
}
// first, sanity checks
JsonToken t = p.getCurrentToken();
if (t == JsonToken.START_OBJECT) {
// should always get field name, but just in case...
if (p.nextToken() != JsonToken.FIELD_NAME) {
throw ctxt.wrongTokenException(p, JsonToken.FIELD_NAME,
"need JSON String that contains type id (for subtype of "+baseTypeName()+")");
}
} else if (t != JsonToken.FIELD_NAME) {
throw ctxt.wrongTokenException(p, JsonToken.START_OBJECT,
"need JSON Object to contain As.WRAPPER_OBJECT type information for class "+baseTypeName());
}
final String typeId = p.getText();
JsonDeserializer<Object> deser = _findDeserializer(ctxt, typeId);
p.nextToken();
// Minor complication: we may need to merge type id in?
if (_typeIdVisible && p.getCurrentToken() == JsonToken.START_OBJECT) {
// but what if there's nowhere to add it in? Error? Or skip? For now, skip.
TokenBuffer tb = new TokenBuffer(null, false);
tb.writeStartObject(); // recreate START_OBJECT
tb.writeFieldName(_typePropertyName);
tb.writeString(typeId);
p = JsonParserSequence.createFlattened(tb.asParser(p), p);
p.nextToken();
}
Object value = deser.deserialize(p, ctxt);
// And then need the closing END_OBJECT
if (p.nextToken() != JsonToken.END_OBJECT) {
throw ctxt.wrongTokenException(p, JsonToken.END_OBJECT,
"expected closing END_OBJECT after type information and deserialized value");
}
return value;
} | false | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Method that handles type information wrapper, locates actual
* subtype deserializer to use, and calls it to do actual
* deserialization.
*/
/*
/***************************************************************
/* Internal methods
/***************************************************************
*/
@SuppressWarnings("resource")
private final Object _deserialize(JsonParser p, DeserializationContext ctxt) throws IOException
{
// 02-Aug-2013, tatu: May need to use native type ids
if (p.canReadTypeId()) {
Object typeId = p.getTypeId();
if (typeId != null) {
return _deserializeWithNativeTypeId(p, ctxt, typeId);
}
}
// first, sanity checks
JsonToken t = p.getCurrentToken();
if (t == JsonToken.START_OBJECT) {
// should always get field name, but just in case...
if (p.nextToken() != JsonToken.FIELD_NAME) {
throw ctxt.wrongTokenException(p, JsonToken.FIELD_NAME,
"need JSON String that contains type id (for subtype of "+baseTypeName()+")");
}
} else if (t != JsonToken.FIELD_NAME) {
throw ctxt.wrongTokenException(p, JsonToken.START_OBJECT,
"need JSON Object to contain As.WRAPPER_OBJECT type information for class "+baseTypeName());
}
final String typeId = p.getText();
JsonDeserializer<Object> deser = _findDeserializer(ctxt, typeId);
p.nextToken();
// Minor complication: we may need to merge type id in?
if (_typeIdVisible && p.getCurrentToken() == JsonToken.START_OBJECT) {
// but what if there's nowhere to add it in? Error? Or skip? For now, skip.
TokenBuffer tb = new TokenBuffer(null, false);
tb.writeStartObject(); // recreate START_OBJECT
tb.writeFieldName(_typePropertyName);
tb.writeString(typeId);
p = JsonParserSequence.createFlattened(tb.asParser(p), p);
p.nextToken();
}
Object value = deser.deserialize(p, ctxt);
// And then need the closing END_OBJECT
if (p.nextToken() != JsonToken.END_OBJECT) {
throw ctxt.wrongTokenException(p, JsonToken.END_OBJECT,
"expected closing END_OBJECT after type information and deserialized value");
}
return value;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
31 | a3f6bb4d2c4c4d9ab77fa0e8aa5d54ccda70b410a5e3a91869ff13f4a76dcd9a | Node parseInputs() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Parses the externs and main inputs.
*
* @return A synthetic root node whose two children are the externs root
* and the main root
*/
//------------------------------------------------------------------------
// Parsing
//------------------------------------------------------------------------
Node parseInputs() {
boolean devMode = options.devMode != DevMode.OFF;
// If old roots exist (we are parsing a second time), detach each of the
// individual file parse trees.
if (externsRoot != null) {
externsRoot.detachChildren();
}
if (jsRoot != null) {
jsRoot.detachChildren();
}
// Parse main js sources.
jsRoot = IR.block();
jsRoot.setIsSyntheticBlock(true);
externsRoot = IR.block();
externsRoot.setIsSyntheticBlock(true);
externAndJsRoot = IR.block(externsRoot, jsRoot);
externAndJsRoot.setIsSyntheticBlock(true);
if (options.tracer.isOn()) {
tracker = new PerformanceTracker(jsRoot, options.tracer);
addChangeHandler(tracker.getCodeChangeHandler());
}
Tracer tracer = newTracer("parseInputs");
try {
// Parse externs sources.
for (CompilerInput input : externs) {
Node n = input.getAstRoot(this);
if (hasErrors()) {
return null;
}
externsRoot.addChildToBack(n);
}
// Modules inferred in ProcessCommonJS pass.
if (options.transformAMDToCJSModules || options.processCommonJSModules) {
processAMDAndCommonJSModules();
}
// Check if inputs need to be rebuilt from modules.
boolean staleInputs = false;
// Check if the sources need to be re-ordered.
if (options.dependencyOptions.needsManagement() &&
options.closurePass) {
for (CompilerInput input : inputs) {
// Forward-declare all the provided types, so that they
// are not flagged even if they are dropped from the process.
for (String provide : input.getProvides()) {
getTypeRegistry().forwardDeclareType(provide);
}
}
try {
inputs =
(moduleGraph == null ? new JSModuleGraph(modules) : moduleGraph)
.manageDependencies(options.dependencyOptions, inputs);
staleInputs = true;
} catch (CircularDependencyException e) {
report(JSError.make(
JSModule.CIRCULAR_DEPENDENCY_ERROR, e.getMessage()));
// If in IDE mode, we ignore the error and keep going.
if (hasErrors()) {
return null;
}
} catch (MissingProvideException e) {
report(JSError.make(
MISSING_ENTRY_ERROR, e.getMessage()));
// If in IDE mode, we ignore the error and keep going.
if (hasErrors()) {
return null;
}
}
}
for (CompilerInput input : inputs) {
Node n = input.getAstRoot(this);
// Inputs can have a null AST during initial parse.
if (n == null) {
continue;
}
if (n.getJSDocInfo() != null) {
JSDocInfo info = n.getJSDocInfo();
if (info.isExterns()) {
// If the input file is explicitly marked as an externs file, then
// assume the programmer made a mistake and throw it into
// the externs pile anyways.
externsRoot.addChildToBack(n);
input.setIsExtern(true);
input.getModule().remove(input);
externs.add(input);
staleInputs = true;
} else if (info.isNoCompile()) {
input.getModule().remove(input);
staleInputs = true;
}
}
}
if (staleInputs) {
fillEmptyModules(modules);
rebuildInputsFromModules();
}
// Build the AST.
for (CompilerInput input : inputs) {
Node n = input.getAstRoot(this);
if (n == null) {
continue;
}
if (devMode) {
runSanityCheck();
if (hasErrors()) {
return null;
}
}
if (options.sourceMapOutputPath != null ||
options.nameReferenceReportPath != null) {
// Annotate the nodes in the tree with information from the
// input file. This information is used to construct the SourceMap.
SourceInformationAnnotator sia =
new SourceInformationAnnotator(
input.getName(), options.devMode != DevMode.OFF);
NodeTraversal.traverse(this, n, sia);
}
jsRoot.addChildToBack(n);
}
if (hasErrors()) {
return null;
}
return externAndJsRoot;
} finally {
stopTracer(tracer, "parseInputs");
}
}
```
| Node parseInputs() {
boolean devMode = options.devMode != DevMode.OFF;
// If old roots exist (we are parsing a second time), detach each of the
// individual file parse trees.
if (externsRoot != null) {
externsRoot.detachChildren();
}
if (jsRoot != null) {
jsRoot.detachChildren();
}
// Parse main js sources.
jsRoot = IR.block();
jsRoot.setIsSyntheticBlock(true);
externsRoot = IR.block();
externsRoot.setIsSyntheticBlock(true);
externAndJsRoot = IR.block(externsRoot, jsRoot);
externAndJsRoot.setIsSyntheticBlock(true);
if (options.tracer.isOn()) {
tracker = new PerformanceTracker(jsRoot, options.tracer);
addChangeHandler(tracker.getCodeChangeHandler());
}
Tracer tracer = newTracer("parseInputs");
try {
// Parse externs sources.
for (CompilerInput input : externs) {
Node n = input.getAstRoot(this);
if (hasErrors()) {
return null;
}
externsRoot.addChildToBack(n);
}
// Modules inferred in ProcessCommonJS pass.
if (options.transformAMDToCJSModules || options.processCommonJSModules) {
processAMDAndCommonJSModules();
}
// Check if inputs need to be rebuilt from modules.
boolean staleInputs = false;
// Check if the sources need to be re-ordered.
if (options.dependencyOptions.needsManagement() &&
options.closurePass) {
for (CompilerInput input : inputs) {
// Forward-declare all the provided types, so that they
// are not flagged even if they are dropped from the process.
for (String provide : input.getProvides()) {
getTypeRegistry().forwardDeclareType(provide);
}
}
try {
inputs =
(moduleGraph == null ? new JSModuleGraph(modules) : moduleGraph)
.manageDependencies(options.dependencyOptions, inputs);
staleInputs = true;
} catch (CircularDependencyException e) {
report(JSError.make(
JSModule.CIRCULAR_DEPENDENCY_ERROR, e.getMessage()));
// If in IDE mode, we ignore the error and keep going.
if (hasErrors()) {
return null;
}
} catch (MissingProvideException e) {
report(JSError.make(
MISSING_ENTRY_ERROR, e.getMessage()));
// If in IDE mode, we ignore the error and keep going.
if (hasErrors()) {
return null;
}
}
}
for (CompilerInput input : inputs) {
Node n = input.getAstRoot(this);
// Inputs can have a null AST during initial parse.
if (n == null) {
continue;
}
if (n.getJSDocInfo() != null) {
JSDocInfo info = n.getJSDocInfo();
if (info.isExterns()) {
// If the input file is explicitly marked as an externs file, then
// assume the programmer made a mistake and throw it into
// the externs pile anyways.
externsRoot.addChildToBack(n);
input.setIsExtern(true);
input.getModule().remove(input);
externs.add(input);
staleInputs = true;
} else if (info.isNoCompile()) {
input.getModule().remove(input);
staleInputs = true;
}
}
}
if (staleInputs) {
fillEmptyModules(modules);
rebuildInputsFromModules();
}
// Build the AST.
for (CompilerInput input : inputs) {
Node n = input.getAstRoot(this);
if (n == null) {
continue;
}
if (devMode) {
runSanityCheck();
if (hasErrors()) {
return null;
}
}
if (options.sourceMapOutputPath != null ||
options.nameReferenceReportPath != null) {
// Annotate the nodes in the tree with information from the
// input file. This information is used to construct the SourceMap.
SourceInformationAnnotator sia =
new SourceInformationAnnotator(
input.getName(), options.devMode != DevMode.OFF);
NodeTraversal.traverse(this, n, sia);
}
jsRoot.addChildToBack(n);
}
if (hasErrors()) {
return null;
}
return externAndJsRoot;
} finally {
stopTracer(tracer, "parseInputs");
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Parses the externs and main inputs.
*
* @return A synthetic root node whose two children are the externs root
* and the main root
*/
//------------------------------------------------------------------------
// Parsing
//------------------------------------------------------------------------
Node parseInputs() {
boolean devMode = options.devMode != DevMode.OFF;
// If old roots exist (we are parsing a second time), detach each of the
// individual file parse trees.
if (externsRoot != null) {
externsRoot.detachChildren();
}
if (jsRoot != null) {
jsRoot.detachChildren();
}
// Parse main js sources.
jsRoot = IR.block();
jsRoot.setIsSyntheticBlock(true);
externsRoot = IR.block();
externsRoot.setIsSyntheticBlock(true);
externAndJsRoot = IR.block(externsRoot, jsRoot);
externAndJsRoot.setIsSyntheticBlock(true);
if (options.tracer.isOn()) {
tracker = new PerformanceTracker(jsRoot, options.tracer);
addChangeHandler(tracker.getCodeChangeHandler());
}
Tracer tracer = newTracer("parseInputs");
try {
// Parse externs sources.
for (CompilerInput input : externs) {
Node n = input.getAstRoot(this);
if (hasErrors()) {
return null;
}
externsRoot.addChildToBack(n);
}
// Modules inferred in ProcessCommonJS pass.
if (options.transformAMDToCJSModules || options.processCommonJSModules) {
processAMDAndCommonJSModules();
}
// Check if inputs need to be rebuilt from modules.
boolean staleInputs = false;
// Check if the sources need to be re-ordered.
if (options.dependencyOptions.needsManagement() &&
options.closurePass) {
for (CompilerInput input : inputs) {
// Forward-declare all the provided types, so that they
// are not flagged even if they are dropped from the process.
for (String provide : input.getProvides()) {
getTypeRegistry().forwardDeclareType(provide);
}
}
try {
inputs =
(moduleGraph == null ? new JSModuleGraph(modules) : moduleGraph)
.manageDependencies(options.dependencyOptions, inputs);
staleInputs = true;
} catch (CircularDependencyException e) {
report(JSError.make(
JSModule.CIRCULAR_DEPENDENCY_ERROR, e.getMessage()));
// If in IDE mode, we ignore the error and keep going.
if (hasErrors()) {
return null;
}
} catch (MissingProvideException e) {
report(JSError.make(
MISSING_ENTRY_ERROR, e.getMessage()));
// If in IDE mode, we ignore the error and keep going.
if (hasErrors()) {
return null;
}
}
}
for (CompilerInput input : inputs) {
Node n = input.getAstRoot(this);
// Inputs can have a null AST during initial parse.
if (n == null) {
continue;
}
if (n.getJSDocInfo() != null) {
JSDocInfo info = n.getJSDocInfo();
if (info.isExterns()) {
// If the input file is explicitly marked as an externs file, then
// assume the programmer made a mistake and throw it into
// the externs pile anyways.
externsRoot.addChildToBack(n);
input.setIsExtern(true);
input.getModule().remove(input);
externs.add(input);
staleInputs = true;
} else if (info.isNoCompile()) {
input.getModule().remove(input);
staleInputs = true;
}
}
}
if (staleInputs) {
fillEmptyModules(modules);
rebuildInputsFromModules();
}
// Build the AST.
for (CompilerInput input : inputs) {
Node n = input.getAstRoot(this);
if (n == null) {
continue;
}
if (devMode) {
runSanityCheck();
if (hasErrors()) {
return null;
}
}
if (options.sourceMapOutputPath != null ||
options.nameReferenceReportPath != null) {
// Annotate the nodes in the tree with information from the
// input file. This information is used to construct the SourceMap.
SourceInformationAnnotator sia =
new SourceInformationAnnotator(
input.getName(), options.devMode != DevMode.OFF);
NodeTraversal.traverse(this, n, sia);
}
jsRoot.addChildToBack(n);
}
if (hasErrors()) {
return null;
}
return externAndJsRoot;
} finally {
stopTracer(tracer, "parseInputs");
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
1 | a44e0a377a70afd434997a20bbe632c709e40789d21ec91e21f610ab091a9943 | public static Number createNumber(final String str) throws NumberFormatException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Turns a string value into a java.lang.Number.</p>
*
* <p>If the string starts with {@code 0x} or {@code -0x} (lower or upper case) or {@code #} or {@code -#}, it
* will be interpreted as a hexadecimal Integer - or Long, if the number of digits after the
* prefix is more than 8 - or BigInteger if there are more than 16 digits.
* </p>
* <p>Then, the value is examined for a type qualifier on the end, i.e. one of
* <code>'f','F','d','D','l','L'</code>. If it is found, it starts
* trying to create successively larger types from the type specified
* until one is found that can represent the value.</p>
*
* <p>If a type specifier is not found, it will check for a decimal point
* and then try successively larger types from <code>Integer</code> to
* <code>BigInteger</code> and from <code>Float</code> to
* <code>BigDecimal</code>.</p>
*
* <p>
* Integral values with a leading {@code 0} will be interpreted as octal; the returned number will
* be Integer, Long or BigDecimal as appropriate.
* </p>
*
* <p>Returns <code>null</code> if the string is <code>null</code>.</p>
*
* <p>This method does not trim the input string, i.e., strings with leading
* or trailing spaces will generate NumberFormatExceptions.</p>
*
* @param str String containing a number, may be null
* @return Number created from the string (or null if the input is null)
* @throws NumberFormatException if the value cannot be converted
*/
// plus minus everything. Prolly more. A lot are not separable.
// 45 45.5 45E7 4.5E7 Hex Oct Binary xxxF xxxD xxxf xxxd
// Possible inputs:
// new BigInteger(String,int radix)
// new BigInteger(String)
// new BigDecimal(String)
// Short.valueOf(String)
// Short.valueOf(String,int)
// Short.decode(String)
// Short.valueOf(String)
// Long.valueOf(String)
// Long.valueOf(String,int)
// Long.getLong(String,Integer)
// Long.getLong(String,int)
// Long.getLong(String)
// Long.valueOf(String)
// new Byte(String)
// Double.valueOf(String)
// Integer.valueOf(String)
// Integer.getInteger(String,Integer val)
// Integer.getInteger(String,int val)
// Integer.getInteger(String)
// Integer.decode(String)
// Integer.valueOf(String)
// Integer.valueOf(String,int radix)
// Float.valueOf(String)
// Float.valueOf(String)
// Double.valueOf(String)
// Byte.valueOf(String)
// Byte.valueOf(String,int radix)
// Byte.decode(String)
// useful methods:
// BigDecimal, BigInteger and Byte
// must handle Long, Float, Integer, Float, Short,
//-----------------------------------------------------------------------
public static Number createNumber(final String str) throws NumberFormatException {
if (str == null) {
return null;
}
if (StringUtils.isBlank(str)) {
throw new NumberFormatException("A blank string is not a valid number");
}
// Need to deal with all possible hex prefixes here
final String[] hex_prefixes = {"0x", "0X", "-0x", "-0X", "#", "-#"};
int pfxLen = 0;
for(final String pfx : hex_prefixes) {
if (str.startsWith(pfx)) {
pfxLen += pfx.length();
break;
}
}
if (pfxLen > 0) { // we have a hex number
char firstSigDigit = 0; // strip leading zeroes
for(int i = pfxLen; i < str.length(); i++) {
firstSigDigit = str.charAt(i);
if (firstSigDigit == '0') { // count leading zeroes
pfxLen++;
} else {
break;
}
}
final int hexDigits = str.length() - pfxLen;
if (hexDigits > 16 || (hexDigits == 16 && firstSigDigit > '7')) { // too many for Long
return createBigInteger(str);
}
if (hexDigits > 8 || (hexDigits == 8 && firstSigDigit > '7')) { // too many for an int
return createLong(str);
}
return createInteger(str);
}
final char lastChar = str.charAt(str.length() - 1);
String mant;
String dec;
String exp;
final int decPos = str.indexOf('.');
final int expPos = str.indexOf('e') + str.indexOf('E') + 1; // assumes both not present
// if both e and E are present, this is caught by the checks on expPos (which prevent IOOBE)
// and the parsing which will detect if e or E appear in a number due to using the wrong offset
int numDecimals = 0; // Check required precision (LANG-693)
if (decPos > -1) { // there is a decimal point
if (expPos > -1) { // there is an exponent
if (expPos < decPos || expPos > str.length()) { // prevents double exponent causing IOOBE
throw new NumberFormatException(str + " is not a valid number.");
}
dec = str.substring(decPos + 1, expPos);
} else {
dec = str.substring(decPos + 1);
}
mant = str.substring(0, decPos);
numDecimals = dec.length(); // gets number of digits past the decimal to ensure no loss of precision for floating point numbers.
} else {
if (expPos > -1) {
if (expPos > str.length()) { // prevents double exponent causing IOOBE
throw new NumberFormatException(str + " is not a valid number.");
}
mant = str.substring(0, expPos);
} else {
mant = str;
}
dec = null;
}
if (!Character.isDigit(lastChar) && lastChar != '.') {
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length() - 1);
} else {
exp = null;
}
//Requesting a specific type..
final String numeric = str.substring(0, str.length() - 1);
final boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
switch (lastChar) {
case 'l' :
case 'L' :
if (dec == null
&& exp == null
&& (numeric.charAt(0) == '-' && isDigits(numeric.substring(1)) || isDigits(numeric))) {
try {
return createLong(numeric);
} catch (final NumberFormatException nfe) { // NOPMD
// Too big for a long
}
return createBigInteger(numeric);
}
throw new NumberFormatException(str + " is not a valid number.");
case 'f' :
case 'F' :
try {
final Float f = NumberUtils.createFloat(numeric);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
//If it's too big for a float or the float value = 0 and the string
//has non-zeros in it, then float does not have the precision we want
return f;
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
case 'd' :
case 'D' :
try {
final Double d = NumberUtils.createDouble(numeric);
if (!(d.isInfinite() || (d.floatValue() == 0.0D && !allZeros))) {
return d;
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createBigDecimal(numeric);
} catch (final NumberFormatException e) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
default :
throw new NumberFormatException(str + " is not a valid number.");
}
}
//User doesn't have a preference on the return type, so let's start
//small and go from there...
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length());
} else {
exp = null;
}
if (dec == null && exp == null) { // no decimal point and no exponent
//Must be an Integer, Long, Biginteger
try {
return createInteger(str);
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createLong(str);
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigInteger(str);
}
//Must be a Float, Double, BigDecimal
final boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
try {
if(numDecimals <= 7){// If number has 7 or fewer digits past the decimal point then make it a float
final Float f = createFloat(str);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
return f;
}
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
if(numDecimals <= 16){// If number has between 8 and 16 digits past the decimal point then make it a double
final Double d = createDouble(str);
if (!(d.isInfinite() || (d.doubleValue() == 0.0D && !allZeros))) {
return d;
}
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigDecimal(str);
}
```
| public static Number createNumber(final String str) throws NumberFormatException {
if (str == null) {
return null;
}
if (StringUtils.isBlank(str)) {
throw new NumberFormatException("A blank string is not a valid number");
}
// Need to deal with all possible hex prefixes here
final String[] hex_prefixes = {"0x", "0X", "-0x", "-0X", "#", "-#"};
int pfxLen = 0;
for(final String pfx : hex_prefixes) {
if (str.startsWith(pfx)) {
pfxLen += pfx.length();
break;
}
}
if (pfxLen > 0) { // we have a hex number
char firstSigDigit = 0; // strip leading zeroes
for(int i = pfxLen; i < str.length(); i++) {
firstSigDigit = str.charAt(i);
if (firstSigDigit == '0') { // count leading zeroes
pfxLen++;
} else {
break;
}
}
final int hexDigits = str.length() - pfxLen;
if (hexDigits > 16 || (hexDigits == 16 && firstSigDigit > '7')) { // too many for Long
return createBigInteger(str);
}
if (hexDigits > 8 || (hexDigits == 8 && firstSigDigit > '7')) { // too many for an int
return createLong(str);
}
return createInteger(str);
}
final char lastChar = str.charAt(str.length() - 1);
String mant;
String dec;
String exp;
final int decPos = str.indexOf('.');
final int expPos = str.indexOf('e') + str.indexOf('E') + 1; // assumes both not present
// if both e and E are present, this is caught by the checks on expPos (which prevent IOOBE)
// and the parsing which will detect if e or E appear in a number due to using the wrong offset
int numDecimals = 0; // Check required precision (LANG-693)
if (decPos > -1) { // there is a decimal point
if (expPos > -1) { // there is an exponent
if (expPos < decPos || expPos > str.length()) { // prevents double exponent causing IOOBE
throw new NumberFormatException(str + " is not a valid number.");
}
dec = str.substring(decPos + 1, expPos);
} else {
dec = str.substring(decPos + 1);
}
mant = str.substring(0, decPos);
numDecimals = dec.length(); // gets number of digits past the decimal to ensure no loss of precision for floating point numbers.
} else {
if (expPos > -1) {
if (expPos > str.length()) { // prevents double exponent causing IOOBE
throw new NumberFormatException(str + " is not a valid number.");
}
mant = str.substring(0, expPos);
} else {
mant = str;
}
dec = null;
}
if (!Character.isDigit(lastChar) && lastChar != '.') {
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length() - 1);
} else {
exp = null;
}
//Requesting a specific type..
final String numeric = str.substring(0, str.length() - 1);
final boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
switch (lastChar) {
case 'l' :
case 'L' :
if (dec == null
&& exp == null
&& (numeric.charAt(0) == '-' && isDigits(numeric.substring(1)) || isDigits(numeric))) {
try {
return createLong(numeric);
} catch (final NumberFormatException nfe) { // NOPMD
// Too big for a long
}
return createBigInteger(numeric);
}
throw new NumberFormatException(str + " is not a valid number.");
case 'f' :
case 'F' :
try {
final Float f = NumberUtils.createFloat(numeric);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
//If it's too big for a float or the float value = 0 and the string
//has non-zeros in it, then float does not have the precision we want
return f;
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
case 'd' :
case 'D' :
try {
final Double d = NumberUtils.createDouble(numeric);
if (!(d.isInfinite() || (d.floatValue() == 0.0D && !allZeros))) {
return d;
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createBigDecimal(numeric);
} catch (final NumberFormatException e) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
default :
throw new NumberFormatException(str + " is not a valid number.");
}
}
//User doesn't have a preference on the return type, so let's start
//small and go from there...
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length());
} else {
exp = null;
}
if (dec == null && exp == null) { // no decimal point and no exponent
//Must be an Integer, Long, Biginteger
try {
return createInteger(str);
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createLong(str);
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigInteger(str);
}
//Must be a Float, Double, BigDecimal
final boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
try {
if(numDecimals <= 7){// If number has 7 or fewer digits past the decimal point then make it a float
final Float f = createFloat(str);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
return f;
}
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
if(numDecimals <= 16){// If number has between 8 and 16 digits past the decimal point then make it a double
final Double d = createDouble(str);
if (!(d.isInfinite() || (d.doubleValue() == 0.0D && !allZeros))) {
return d;
}
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigDecimal(str);
} | false | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Turns a string value into a java.lang.Number.</p>
*
* <p>If the string starts with {@code 0x} or {@code -0x} (lower or upper case) or {@code #} or {@code -#}, it
* will be interpreted as a hexadecimal Integer - or Long, if the number of digits after the
* prefix is more than 8 - or BigInteger if there are more than 16 digits.
* </p>
* <p>Then, the value is examined for a type qualifier on the end, i.e. one of
* <code>'f','F','d','D','l','L'</code>. If it is found, it starts
* trying to create successively larger types from the type specified
* until one is found that can represent the value.</p>
*
* <p>If a type specifier is not found, it will check for a decimal point
* and then try successively larger types from <code>Integer</code> to
* <code>BigInteger</code> and from <code>Float</code> to
* <code>BigDecimal</code>.</p>
*
* <p>
* Integral values with a leading {@code 0} will be interpreted as octal; the returned number will
* be Integer, Long or BigDecimal as appropriate.
* </p>
*
* <p>Returns <code>null</code> if the string is <code>null</code>.</p>
*
* <p>This method does not trim the input string, i.e., strings with leading
* or trailing spaces will generate NumberFormatExceptions.</p>
*
* @param str String containing a number, may be null
* @return Number created from the string (or null if the input is null)
* @throws NumberFormatException if the value cannot be converted
*/
// plus minus everything. Prolly more. A lot are not separable.
// 45 45.5 45E7 4.5E7 Hex Oct Binary xxxF xxxD xxxf xxxd
// Possible inputs:
// new BigInteger(String,int radix)
// new BigInteger(String)
// new BigDecimal(String)
// Short.valueOf(String)
// Short.valueOf(String,int)
// Short.decode(String)
// Short.valueOf(String)
// Long.valueOf(String)
// Long.valueOf(String,int)
// Long.getLong(String,Integer)
// Long.getLong(String,int)
// Long.getLong(String)
// Long.valueOf(String)
// new Byte(String)
// Double.valueOf(String)
// Integer.valueOf(String)
// Integer.getInteger(String,Integer val)
// Integer.getInteger(String,int val)
// Integer.getInteger(String)
// Integer.decode(String)
// Integer.valueOf(String)
// Integer.valueOf(String,int radix)
// Float.valueOf(String)
// Float.valueOf(String)
// Double.valueOf(String)
// Byte.valueOf(String)
// Byte.valueOf(String,int radix)
// Byte.decode(String)
// useful methods:
// BigDecimal, BigInteger and Byte
// must handle Long, Float, Integer, Float, Short,
//-----------------------------------------------------------------------
public static Number createNumber(final String str) throws NumberFormatException {
if (str == null) {
return null;
}
if (StringUtils.isBlank(str)) {
throw new NumberFormatException("A blank string is not a valid number");
}
// Need to deal with all possible hex prefixes here
final String[] hex_prefixes = {"0x", "0X", "-0x", "-0X", "#", "-#"};
int pfxLen = 0;
for(final String pfx : hex_prefixes) {
if (str.startsWith(pfx)) {
pfxLen += pfx.length();
break;
}
}
if (pfxLen > 0) { // we have a hex number
char firstSigDigit = 0; // strip leading zeroes
for(int i = pfxLen; i < str.length(); i++) {
firstSigDigit = str.charAt(i);
if (firstSigDigit == '0') { // count leading zeroes
pfxLen++;
} else {
break;
}
}
final int hexDigits = str.length() - pfxLen;
if (hexDigits > 16 || (hexDigits == 16 && firstSigDigit > '7')) { // too many for Long
return createBigInteger(str);
}
if (hexDigits > 8 || (hexDigits == 8 && firstSigDigit > '7')) { // too many for an int
return createLong(str);
}
return createInteger(str);
}
final char lastChar = str.charAt(str.length() - 1);
String mant;
String dec;
String exp;
final int decPos = str.indexOf('.');
final int expPos = str.indexOf('e') + str.indexOf('E') + 1; // assumes both not present
// if both e and E are present, this is caught by the checks on expPos (which prevent IOOBE)
// and the parsing which will detect if e or E appear in a number due to using the wrong offset
int numDecimals = 0; // Check required precision (LANG-693)
if (decPos > -1) { // there is a decimal point
if (expPos > -1) { // there is an exponent
if (expPos < decPos || expPos > str.length()) { // prevents double exponent causing IOOBE
throw new NumberFormatException(str + " is not a valid number.");
}
dec = str.substring(decPos + 1, expPos);
} else {
dec = str.substring(decPos + 1);
}
mant = str.substring(0, decPos);
numDecimals = dec.length(); // gets number of digits past the decimal to ensure no loss of precision for floating point numbers.
} else {
if (expPos > -1) {
if (expPos > str.length()) { // prevents double exponent causing IOOBE
throw new NumberFormatException(str + " is not a valid number.");
}
mant = str.substring(0, expPos);
} else {
mant = str;
}
dec = null;
}
if (!Character.isDigit(lastChar) && lastChar != '.') {
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length() - 1);
} else {
exp = null;
}
//Requesting a specific type..
final String numeric = str.substring(0, str.length() - 1);
final boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
switch (lastChar) {
case 'l' :
case 'L' :
if (dec == null
&& exp == null
&& (numeric.charAt(0) == '-' && isDigits(numeric.substring(1)) || isDigits(numeric))) {
try {
return createLong(numeric);
} catch (final NumberFormatException nfe) { // NOPMD
// Too big for a long
}
return createBigInteger(numeric);
}
throw new NumberFormatException(str + " is not a valid number.");
case 'f' :
case 'F' :
try {
final Float f = NumberUtils.createFloat(numeric);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
//If it's too big for a float or the float value = 0 and the string
//has non-zeros in it, then float does not have the precision we want
return f;
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
case 'd' :
case 'D' :
try {
final Double d = NumberUtils.createDouble(numeric);
if (!(d.isInfinite() || (d.floatValue() == 0.0D && !allZeros))) {
return d;
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createBigDecimal(numeric);
} catch (final NumberFormatException e) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
default :
throw new NumberFormatException(str + " is not a valid number.");
}
}
//User doesn't have a preference on the return type, so let's start
//small and go from there...
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length());
} else {
exp = null;
}
if (dec == null && exp == null) { // no decimal point and no exponent
//Must be an Integer, Long, Biginteger
try {
return createInteger(str);
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createLong(str);
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigInteger(str);
}
//Must be a Float, Double, BigDecimal
final boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
try {
if(numDecimals <= 7){// If number has 7 or fewer digits past the decimal point then make it a float
final Float f = createFloat(str);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
return f;
}
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
if(numDecimals <= 16){// If number has between 8 and 16 digits past the decimal point then make it a double
final Double d = createDouble(str);
if (!(d.isInfinite() || (d.doubleValue() == 0.0D && !allZeros))) {
return d;
}
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigDecimal(str);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
7 | a46267b6de4e330637e53b78b13690841364e27f4050d2f74a005dca59bf696e | public TokenBuffer deserialize(JsonParser jp, DeserializationContext ctxt) throws IOException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Helper method used by standard deserializer.
*
* @since 2.3
*/
public TokenBuffer deserialize(JsonParser jp, DeserializationContext ctxt) throws IOException
{
if (jp.getCurrentTokenId() != JsonToken.FIELD_NAME.id()) {
copyCurrentStructure(jp);
return this;
}
/* 28-Oct-2014, tatu: As per #592, need to support a special case of starting from
* FIELD_NAME, which is taken to mean that we are missing START_OBJECT, but need
* to assume one did exist.
*/
JsonToken t;
writeStartObject();
do {
copyCurrentStructure(jp);
} while ((t = jp.nextToken()) == JsonToken.FIELD_NAME);
if (t != JsonToken.END_OBJECT) {
throw ctxt.mappingException("Expected END_OBJECT after copying contents of a JsonParser into TokenBuffer, got "+t);
}
writeEndObject();
return this;
}
```
| public TokenBuffer deserialize(JsonParser jp, DeserializationContext ctxt) throws IOException
{
if (jp.getCurrentTokenId() != JsonToken.FIELD_NAME.id()) {
copyCurrentStructure(jp);
return this;
}
/* 28-Oct-2014, tatu: As per #592, need to support a special case of starting from
* FIELD_NAME, which is taken to mean that we are missing START_OBJECT, but need
* to assume one did exist.
*/
JsonToken t;
writeStartObject();
do {
copyCurrentStructure(jp);
} while ((t = jp.nextToken()) == JsonToken.FIELD_NAME);
if (t != JsonToken.END_OBJECT) {
throw ctxt.mappingException("Expected END_OBJECT after copying contents of a JsonParser into TokenBuffer, got "+t);
}
writeEndObject();
return this;
} | false | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Helper method used by standard deserializer.
*
* @since 2.3
*/
public TokenBuffer deserialize(JsonParser jp, DeserializationContext ctxt) throws IOException
{
if (jp.getCurrentTokenId() != JsonToken.FIELD_NAME.id()) {
copyCurrentStructure(jp);
return this;
}
/* 28-Oct-2014, tatu: As per #592, need to support a special case of starting from
* FIELD_NAME, which is taken to mean that we are missing START_OBJECT, but need
* to assume one did exist.
*/
JsonToken t;
writeStartObject();
do {
copyCurrentStructure(jp);
} while ((t = jp.nextToken()) == JsonToken.FIELD_NAME);
if (t != JsonToken.END_OBJECT) {
throw ctxt.mappingException("Expected END_OBJECT after copying contents of a JsonParser into TokenBuffer, got "+t);
}
writeEndObject();
return this;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
26 | a53cf87f85597cbc9ccb91c65eb5e5817b15d7f81f2365e6b99df56414d7162b | private Fraction(double value, double epsilon, int maxDenominator, int maxIterations)
throws FractionConversionException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Create a fraction given the double value and either the maximum error
* allowed or the maximum number of denominator digits.
* <p>
*
* NOTE: This constructor is called with EITHER
* - a valid epsilon value and the maxDenominator set to Integer.MAX_VALUE
* (that way the maxDenominator has no effect).
* OR
* - a valid maxDenominator value and the epsilon value set to zero
* (that way epsilon only has effect if there is an exact match before
* the maxDenominator value is reached).
* </p><p>
*
* It has been done this way so that the same code can be (re)used for both
* scenarios. However this could be confusing to users if it were part of
* the public API and this constructor should therefore remain PRIVATE.
* </p>
*
* See JIRA issue ticket MATH-181 for more details:
*
* https://issues.apache.org/jira/browse/MATH-181
*
* @param value the double value to convert to a fraction.
* @param epsilon maximum error allowed. The resulting fraction is within
* {@code epsilon} of {@code value}, in absolute terms.
* @param maxDenominator maximum denominator value allowed.
* @param maxIterations maximum number of convergents
* @throws FractionConversionException if the continued fraction failed to
* converge.
*/
private Fraction(double value, double epsilon, int maxDenominator, int maxIterations)
throws FractionConversionException
{
long overflow = Integer.MAX_VALUE;
double r0 = value;
long a0 = (long)FastMath.floor(r0);
if (FastMath.abs(a0) > overflow) {
throw new FractionConversionException(value, a0, 1l);
}
// check for (almost) integer arguments, which should not go
// to iterations.
if (FastMath.abs(a0 - value) < epsilon) {
this.numerator = (int) a0;
this.denominator = 1;
return;
}
long p0 = 1;
long q0 = 0;
long p1 = a0;
long q1 = 1;
long p2 = 0;
long q2 = 1;
int n = 0;
boolean stop = false;
do {
++n;
double r1 = 1.0 / (r0 - a0);
long a1 = (long)FastMath.floor(r1);
p2 = (a1 * p1) + p0;
q2 = (a1 * q1) + q0;
if ((FastMath.abs(p2) > overflow) || (FastMath.abs(q2) > overflow)) {
throw new FractionConversionException(value, p2, q2);
}
double convergent = (double)p2 / (double)q2;
if (n < maxIterations && FastMath.abs(convergent - value) > epsilon && q2 < maxDenominator) {
p0 = p1;
p1 = p2;
q0 = q1;
q1 = q2;
a0 = a1;
r0 = r1;
} else {
stop = true;
}
} while (!stop);
if (n >= maxIterations) {
throw new FractionConversionException(value, maxIterations);
}
if (q2 < maxDenominator) {
this.numerator = (int) p2;
this.denominator = (int) q2;
} else {
this.numerator = (int) p1;
this.denominator = (int) q1;
}
}
```
| private Fraction(double value, double epsilon, int maxDenominator, int maxIterations)
throws FractionConversionException
{
long overflow = Integer.MAX_VALUE;
double r0 = value;
long a0 = (long)FastMath.floor(r0);
if (FastMath.abs(a0) > overflow) {
throw new FractionConversionException(value, a0, 1l);
}
// check for (almost) integer arguments, which should not go
// to iterations.
if (FastMath.abs(a0 - value) < epsilon) {
this.numerator = (int) a0;
this.denominator = 1;
return;
}
long p0 = 1;
long q0 = 0;
long p1 = a0;
long q1 = 1;
long p2 = 0;
long q2 = 1;
int n = 0;
boolean stop = false;
do {
++n;
double r1 = 1.0 / (r0 - a0);
long a1 = (long)FastMath.floor(r1);
p2 = (a1 * p1) + p0;
q2 = (a1 * q1) + q0;
if ((FastMath.abs(p2) > overflow) || (FastMath.abs(q2) > overflow)) {
throw new FractionConversionException(value, p2, q2);
}
double convergent = (double)p2 / (double)q2;
if (n < maxIterations && FastMath.abs(convergent - value) > epsilon && q2 < maxDenominator) {
p0 = p1;
p1 = p2;
q0 = q1;
q1 = q2;
a0 = a1;
r0 = r1;
} else {
stop = true;
}
} while (!stop);
if (n >= maxIterations) {
throw new FractionConversionException(value, maxIterations);
}
if (q2 < maxDenominator) {
this.numerator = (int) p2;
this.denominator = (int) q2;
} else {
this.numerator = (int) p1;
this.denominator = (int) q1;
}
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Create a fraction given the double value and either the maximum error
* allowed or the maximum number of denominator digits.
* <p>
*
* NOTE: This constructor is called with EITHER
* - a valid epsilon value and the maxDenominator set to Integer.MAX_VALUE
* (that way the maxDenominator has no effect).
* OR
* - a valid maxDenominator value and the epsilon value set to zero
* (that way epsilon only has effect if there is an exact match before
* the maxDenominator value is reached).
* </p><p>
*
* It has been done this way so that the same code can be (re)used for both
* scenarios. However this could be confusing to users if it were part of
* the public API and this constructor should therefore remain PRIVATE.
* </p>
*
* See JIRA issue ticket MATH-181 for more details:
*
* https://issues.apache.org/jira/browse/MATH-181
*
* @param value the double value to convert to a fraction.
* @param epsilon maximum error allowed. The resulting fraction is within
* {@code epsilon} of {@code value}, in absolute terms.
* @param maxDenominator maximum denominator value allowed.
* @param maxIterations maximum number of convergents
* @throws FractionConversionException if the continued fraction failed to
* converge.
*/
private Fraction(double value, double epsilon, int maxDenominator, int maxIterations)
throws FractionConversionException
{
long overflow = Integer.MAX_VALUE;
double r0 = value;
long a0 = (long)FastMath.floor(r0);
if (FastMath.abs(a0) > overflow) {
throw new FractionConversionException(value, a0, 1l);
}
// check for (almost) integer arguments, which should not go
// to iterations.
if (FastMath.abs(a0 - value) < epsilon) {
this.numerator = (int) a0;
this.denominator = 1;
return;
}
long p0 = 1;
long q0 = 0;
long p1 = a0;
long q1 = 1;
long p2 = 0;
long q2 = 1;
int n = 0;
boolean stop = false;
do {
++n;
double r1 = 1.0 / (r0 - a0);
long a1 = (long)FastMath.floor(r1);
p2 = (a1 * p1) + p0;
q2 = (a1 * q1) + q0;
if ((FastMath.abs(p2) > overflow) || (FastMath.abs(q2) > overflow)) {
throw new FractionConversionException(value, p2, q2);
}
double convergent = (double)p2 / (double)q2;
if (n < maxIterations && FastMath.abs(convergent - value) > epsilon && q2 < maxDenominator) {
p0 = p1;
p1 = p2;
q0 = q1;
q1 = q2;
a0 = a1;
r0 = r1;
} else {
stop = true;
}
} while (!stop);
if (n >= maxIterations) {
throw new FractionConversionException(value, maxIterations);
}
if (q2 < maxDenominator) {
this.numerator = (int) p2;
this.denominator = (int) q2;
} else {
this.numerator = (int) p1;
this.denominator = (int) q1;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
5 | a54eb3183fd425a7c97863fd3fafadd73623691be5d63cc43cdbdb7a7e1696a5 | public static Locale toLocale(final String str) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Converts a String to a Locale.</p>
*
* <p>This method takes the string format of a locale and creates the
* locale object from it.</p>
*
* <pre>
* LocaleUtils.toLocale("en") = new Locale("en", "")
* LocaleUtils.toLocale("en_GB") = new Locale("en", "GB")
* LocaleUtils.toLocale("en_GB_xxx") = new Locale("en", "GB", "xxx") (#)
* </pre>
*
* <p>(#) The behaviour of the JDK variant constructor changed between JDK1.3 and JDK1.4.
* In JDK1.3, the constructor upper cases the variant, in JDK1.4, it doesn't.
* Thus, the result from getVariant() may vary depending on your JDK.</p>
*
* <p>This method validates the input strictly.
* The language code must be lowercase.
* The country code must be uppercase.
* The separator must be an underscore.
* The length must be correct.
* </p>
*
* @param str the locale String to convert, null returns null
* @return a Locale, null if null input
* @throws IllegalArgumentException if the string is an invalid format
*/
//-----------------------------------------------------------------------
public static Locale toLocale(final String str) {
if (str == null) {
return null;
}
final int len = str.length();
if (len < 2) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
final char ch0 = str.charAt(0);
final char ch1 = str.charAt(1);
if (!Character.isLowerCase(ch0) || !Character.isLowerCase(ch1)) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (len == 2) {
return new Locale(str);
}
if (len < 5) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (str.charAt(2) != '_') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
final char ch3 = str.charAt(3);
if (ch3 == '_') {
return new Locale(str.substring(0, 2), "", str.substring(4));
}
final char ch4 = str.charAt(4);
if (!Character.isUpperCase(ch3) || !Character.isUpperCase(ch4)) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (len == 5) {
return new Locale(str.substring(0, 2), str.substring(3, 5));
}
if (len < 7) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (str.charAt(5) != '_') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
return new Locale(str.substring(0, 2), str.substring(3, 5), str.substring(6));
}
```
| public static Locale toLocale(final String str) {
if (str == null) {
return null;
}
final int len = str.length();
if (len < 2) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
final char ch0 = str.charAt(0);
final char ch1 = str.charAt(1);
if (!Character.isLowerCase(ch0) || !Character.isLowerCase(ch1)) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (len == 2) {
return new Locale(str);
}
if (len < 5) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (str.charAt(2) != '_') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
final char ch3 = str.charAt(3);
if (ch3 == '_') {
return new Locale(str.substring(0, 2), "", str.substring(4));
}
final char ch4 = str.charAt(4);
if (!Character.isUpperCase(ch3) || !Character.isUpperCase(ch4)) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (len == 5) {
return new Locale(str.substring(0, 2), str.substring(3, 5));
}
if (len < 7) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (str.charAt(5) != '_') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
return new Locale(str.substring(0, 2), str.substring(3, 5), str.substring(6));
} | true | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Converts a String to a Locale.</p>
*
* <p>This method takes the string format of a locale and creates the
* locale object from it.</p>
*
* <pre>
* LocaleUtils.toLocale("en") = new Locale("en", "")
* LocaleUtils.toLocale("en_GB") = new Locale("en", "GB")
* LocaleUtils.toLocale("en_GB_xxx") = new Locale("en", "GB", "xxx") (#)
* </pre>
*
* <p>(#) The behaviour of the JDK variant constructor changed between JDK1.3 and JDK1.4.
* In JDK1.3, the constructor upper cases the variant, in JDK1.4, it doesn't.
* Thus, the result from getVariant() may vary depending on your JDK.</p>
*
* <p>This method validates the input strictly.
* The language code must be lowercase.
* The country code must be uppercase.
* The separator must be an underscore.
* The length must be correct.
* </p>
*
* @param str the locale String to convert, null returns null
* @return a Locale, null if null input
* @throws IllegalArgumentException if the string is an invalid format
*/
//-----------------------------------------------------------------------
public static Locale toLocale(final String str) {
if (str == null) {
return null;
}
final int len = str.length();
if (len < 2) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
final char ch0 = str.charAt(0);
final char ch1 = str.charAt(1);
if (!Character.isLowerCase(ch0) || !Character.isLowerCase(ch1)) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (len == 2) {
return new Locale(str);
}
if (len < 5) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (str.charAt(2) != '_') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
final char ch3 = str.charAt(3);
if (ch3 == '_') {
return new Locale(str.substring(0, 2), "", str.substring(4));
}
final char ch4 = str.charAt(4);
if (!Character.isUpperCase(ch3) || !Character.isUpperCase(ch4)) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (len == 5) {
return new Locale(str.substring(0, 2), str.substring(3, 5));
}
if (len < 7) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (str.charAt(5) != '_') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
return new Locale(str.substring(0, 2), str.substring(3, 5), str.substring(6));
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
21 | a57176a012d81fb2e3cfb7fffff9bab76581d1b711a39f2963a1f2466806a655 | @Override
public JsonToken nextToken() throws IOException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/*
/**********************************************************
/* Public API, traversal
/**********************************************************
*/
@Override
public JsonToken nextToken() throws IOException
{
// 23-May-2017, tatu: To be honest, code here is rather hairy and I don't like all
// conditionals; and it seems odd to return `null` but NOT considering input
// as closed... would love a rewrite to simplify/clear up logic here.
// Check for _allowMultipleMatches - false and at least there is one token - which is _currToken
// check for no buffered context _exposedContext - null
// If all the conditions matches then check for scalar / non-scalar property
if (!_allowMultipleMatches && (_currToken != null) && (_exposedContext == null)) {
//if not scalar and ended successfully, and !includePath, then return null
if (!_includePath) {
if (_currToken.isStructEnd()) {
if (_headContext.isStartHandled()) {
return (_currToken = null);
}
} else if (_currToken.isScalarValue()) {
//else if scalar, and scalar not present in obj/array and !includePath and INCLUDE_ALL matched once
// then return null
if (!_headContext.isStartHandled() && (_itemFilter == TokenFilter.INCLUDE_ALL)) {
return (_currToken = null);
}
}
}
}
// Anything buffered?
TokenFilterContext ctxt = _exposedContext;
if (ctxt != null) {
while (true) {
JsonToken t = ctxt.nextTokenToRead();
if (t != null) {
_currToken = t;
return t;
}
// all done with buffered stuff?
if (ctxt == _headContext) {
_exposedContext = null;
if (ctxt.inArray()) {
t = delegate.getCurrentToken();
// Is this guaranteed to work without further checks?
// if (t != JsonToken.START_ARRAY) {
_currToken = t;
return t;
}
// Almost! Most likely still have the current token;
// with the sole exception of
/*
t = delegate.getCurrentToken();
if (t != JsonToken.FIELD_NAME) {
_currToken = t;
return t;
}
*/
break;
}
// If not, traverse down the context chain
ctxt = _headContext.findChildOf(ctxt);
_exposedContext = ctxt;
if (ctxt == null) { // should never occur
throw _constructError("Unexpected problem: chain of filtered context broken");
}
}
}
// If not, need to read more. If we got any:
JsonToken t = delegate.nextToken();
if (t == null) {
// no strict need to close, since we have no state here
_currToken = t;
return t;
}
// otherwise... to include or not?
TokenFilter f;
switch (t.id()) {
case ID_START_ARRAY:
f = _itemFilter;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildArrayContext(f, true);
return (_currToken = t);
}
if (f == null) { // does this occur?
delegate.skipChildren();
break;
}
// Otherwise still iffy, need to check
f = _headContext.checkValue(f);
if (f == null) {
delegate.skipChildren();
break;
}
if (f != TokenFilter.INCLUDE_ALL) {
f = f.filterStartArray();
}
_itemFilter = f;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildArrayContext(f, true);
return (_currToken = t);
}
_headContext = _headContext.createChildArrayContext(f, false);
// Also: only need buffering if parent path to be included
if (_includePath) {
t = _nextTokenWithBuffering(_headContext);
if (t != null) {
_currToken = t;
return t;
}
}
break;
case ID_START_OBJECT:
f = _itemFilter;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildObjectContext(f, true);
return (_currToken = t);
}
if (f == null) { // does this occur?
delegate.skipChildren();
break;
}
// Otherwise still iffy, need to check
f = _headContext.checkValue(f);
if (f == null) {
delegate.skipChildren();
break;
}
if (f != TokenFilter.INCLUDE_ALL) {
f = f.filterStartObject();
}
_itemFilter = f;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildObjectContext(f, true);
return (_currToken = t);
}
_headContext = _headContext.createChildObjectContext(f, false);
// Also: only need buffering if parent path to be included
if (_includePath) {
t = _nextTokenWithBuffering(_headContext);
if (t != null) {
_currToken = t;
return t;
}
}
// note: inclusion of surrounding Object handled separately via
// FIELD_NAME
break;
case ID_END_ARRAY:
case ID_END_OBJECT:
{
boolean returnEnd = _headContext.isStartHandled();
f = _headContext.getFilter();
if ((f != null) && (f != TokenFilter.INCLUDE_ALL)) {
f.filterFinishArray();
}
_headContext = _headContext.getParent();
_itemFilter = _headContext.getFilter();
if (returnEnd) {
return (_currToken = t);
}
}
break;
case ID_FIELD_NAME:
{
final String name = delegate.getCurrentName();
// note: this will also set 'needToHandleName'
f = _headContext.setFieldName(name);
if (f == TokenFilter.INCLUDE_ALL) {
_itemFilter = f;
if (!_includePath) {
// Minor twist here: if parent NOT included, may need to induce output of
// surrounding START_OBJECT/END_OBJECT
if (_includeImmediateParent && !_headContext.isStartHandled()) {
t = _headContext.nextTokenToRead(); // returns START_OBJECT but also marks it handled
_exposedContext = _headContext;
}
}
return (_currToken = t);
}
if (f == null) {
delegate.nextToken();
delegate.skipChildren();
break;
}
f = f.includeProperty(name);
if (f == null) {
delegate.nextToken();
delegate.skipChildren();
break;
}
_itemFilter = f;
if (f == TokenFilter.INCLUDE_ALL) {
if (_includePath) {
return (_currToken = t);
}
}
if (_includePath) {
t = _nextTokenWithBuffering(_headContext);
if (t != null) {
_currToken = t;
return t;
}
}
break;
}
default: // scalar value
f = _itemFilter;
if (f == TokenFilter.INCLUDE_ALL) {
return (_currToken = t);
}
if (f != null) {
f = _headContext.checkValue(f);
if ((f == TokenFilter.INCLUDE_ALL)
|| ((f != null) && f.includeValue(delegate))) {
return (_currToken = t);
}
}
// Otherwise not included (leaves must be explicitly included)
break;
}
// We get here if token was not yet found; offlined handling
return _nextToken2();
}
```
| @Override
public JsonToken nextToken() throws IOException
{
// 23-May-2017, tatu: To be honest, code here is rather hairy and I don't like all
// conditionals; and it seems odd to return `null` but NOT considering input
// as closed... would love a rewrite to simplify/clear up logic here.
// Check for _allowMultipleMatches - false and at least there is one token - which is _currToken
// check for no buffered context _exposedContext - null
// If all the conditions matches then check for scalar / non-scalar property
if (!_allowMultipleMatches && (_currToken != null) && (_exposedContext == null)) {
//if not scalar and ended successfully, and !includePath, then return null
if (!_includePath) {
if (_currToken.isStructEnd()) {
if (_headContext.isStartHandled()) {
return (_currToken = null);
}
} else if (_currToken.isScalarValue()) {
//else if scalar, and scalar not present in obj/array and !includePath and INCLUDE_ALL matched once
// then return null
if (!_headContext.isStartHandled() && (_itemFilter == TokenFilter.INCLUDE_ALL)) {
return (_currToken = null);
}
}
}
}
// Anything buffered?
TokenFilterContext ctxt = _exposedContext;
if (ctxt != null) {
while (true) {
JsonToken t = ctxt.nextTokenToRead();
if (t != null) {
_currToken = t;
return t;
}
// all done with buffered stuff?
if (ctxt == _headContext) {
_exposedContext = null;
if (ctxt.inArray()) {
t = delegate.getCurrentToken();
// Is this guaranteed to work without further checks?
// if (t != JsonToken.START_ARRAY) {
_currToken = t;
return t;
}
// Almost! Most likely still have the current token;
// with the sole exception of
/*
t = delegate.getCurrentToken();
if (t != JsonToken.FIELD_NAME) {
_currToken = t;
return t;
}
*/
break;
}
// If not, traverse down the context chain
ctxt = _headContext.findChildOf(ctxt);
_exposedContext = ctxt;
if (ctxt == null) { // should never occur
throw _constructError("Unexpected problem: chain of filtered context broken");
}
}
}
// If not, need to read more. If we got any:
JsonToken t = delegate.nextToken();
if (t == null) {
// no strict need to close, since we have no state here
_currToken = t;
return t;
}
// otherwise... to include or not?
TokenFilter f;
switch (t.id()) {
case ID_START_ARRAY:
f = _itemFilter;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildArrayContext(f, true);
return (_currToken = t);
}
if (f == null) { // does this occur?
delegate.skipChildren();
break;
}
// Otherwise still iffy, need to check
f = _headContext.checkValue(f);
if (f == null) {
delegate.skipChildren();
break;
}
if (f != TokenFilter.INCLUDE_ALL) {
f = f.filterStartArray();
}
_itemFilter = f;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildArrayContext(f, true);
return (_currToken = t);
}
_headContext = _headContext.createChildArrayContext(f, false);
// Also: only need buffering if parent path to be included
if (_includePath) {
t = _nextTokenWithBuffering(_headContext);
if (t != null) {
_currToken = t;
return t;
}
}
break;
case ID_START_OBJECT:
f = _itemFilter;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildObjectContext(f, true);
return (_currToken = t);
}
if (f == null) { // does this occur?
delegate.skipChildren();
break;
}
// Otherwise still iffy, need to check
f = _headContext.checkValue(f);
if (f == null) {
delegate.skipChildren();
break;
}
if (f != TokenFilter.INCLUDE_ALL) {
f = f.filterStartObject();
}
_itemFilter = f;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildObjectContext(f, true);
return (_currToken = t);
}
_headContext = _headContext.createChildObjectContext(f, false);
// Also: only need buffering if parent path to be included
if (_includePath) {
t = _nextTokenWithBuffering(_headContext);
if (t != null) {
_currToken = t;
return t;
}
}
// note: inclusion of surrounding Object handled separately via
// FIELD_NAME
break;
case ID_END_ARRAY:
case ID_END_OBJECT:
{
boolean returnEnd = _headContext.isStartHandled();
f = _headContext.getFilter();
if ((f != null) && (f != TokenFilter.INCLUDE_ALL)) {
f.filterFinishArray();
}
_headContext = _headContext.getParent();
_itemFilter = _headContext.getFilter();
if (returnEnd) {
return (_currToken = t);
}
}
break;
case ID_FIELD_NAME:
{
final String name = delegate.getCurrentName();
// note: this will also set 'needToHandleName'
f = _headContext.setFieldName(name);
if (f == TokenFilter.INCLUDE_ALL) {
_itemFilter = f;
if (!_includePath) {
// Minor twist here: if parent NOT included, may need to induce output of
// surrounding START_OBJECT/END_OBJECT
if (_includeImmediateParent && !_headContext.isStartHandled()) {
t = _headContext.nextTokenToRead(); // returns START_OBJECT but also marks it handled
_exposedContext = _headContext;
}
}
return (_currToken = t);
}
if (f == null) {
delegate.nextToken();
delegate.skipChildren();
break;
}
f = f.includeProperty(name);
if (f == null) {
delegate.nextToken();
delegate.skipChildren();
break;
}
_itemFilter = f;
if (f == TokenFilter.INCLUDE_ALL) {
if (_includePath) {
return (_currToken = t);
}
}
if (_includePath) {
t = _nextTokenWithBuffering(_headContext);
if (t != null) {
_currToken = t;
return t;
}
}
break;
}
default: // scalar value
f = _itemFilter;
if (f == TokenFilter.INCLUDE_ALL) {
return (_currToken = t);
}
if (f != null) {
f = _headContext.checkValue(f);
if ((f == TokenFilter.INCLUDE_ALL)
|| ((f != null) && f.includeValue(delegate))) {
return (_currToken = t);
}
}
// Otherwise not included (leaves must be explicitly included)
break;
}
// We get here if token was not yet found; offlined handling
return _nextToken2();
} | false | JacksonCore | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/*
/**********************************************************
/* Public API, traversal
/**********************************************************
*/
@Override
public JsonToken nextToken() throws IOException
{
// 23-May-2017, tatu: To be honest, code here is rather hairy and I don't like all
// conditionals; and it seems odd to return `null` but NOT considering input
// as closed... would love a rewrite to simplify/clear up logic here.
// Check for _allowMultipleMatches - false and at least there is one token - which is _currToken
// check for no buffered context _exposedContext - null
// If all the conditions matches then check for scalar / non-scalar property
if (!_allowMultipleMatches && (_currToken != null) && (_exposedContext == null)) {
//if not scalar and ended successfully, and !includePath, then return null
if (!_includePath) {
if (_currToken.isStructEnd()) {
if (_headContext.isStartHandled()) {
return (_currToken = null);
}
} else if (_currToken.isScalarValue()) {
//else if scalar, and scalar not present in obj/array and !includePath and INCLUDE_ALL matched once
// then return null
if (!_headContext.isStartHandled() && (_itemFilter == TokenFilter.INCLUDE_ALL)) {
return (_currToken = null);
}
}
}
}
// Anything buffered?
TokenFilterContext ctxt = _exposedContext;
if (ctxt != null) {
while (true) {
JsonToken t = ctxt.nextTokenToRead();
if (t != null) {
_currToken = t;
return t;
}
// all done with buffered stuff?
if (ctxt == _headContext) {
_exposedContext = null;
if (ctxt.inArray()) {
t = delegate.getCurrentToken();
// Is this guaranteed to work without further checks?
// if (t != JsonToken.START_ARRAY) {
_currToken = t;
return t;
}
// Almost! Most likely still have the current token;
// with the sole exception of
/*
t = delegate.getCurrentToken();
if (t != JsonToken.FIELD_NAME) {
_currToken = t;
return t;
}
*/
break;
}
// If not, traverse down the context chain
ctxt = _headContext.findChildOf(ctxt);
_exposedContext = ctxt;
if (ctxt == null) { // should never occur
throw _constructError("Unexpected problem: chain of filtered context broken");
}
}
}
// If not, need to read more. If we got any:
JsonToken t = delegate.nextToken();
if (t == null) {
// no strict need to close, since we have no state here
_currToken = t;
return t;
}
// otherwise... to include or not?
TokenFilter f;
switch (t.id()) {
case ID_START_ARRAY:
f = _itemFilter;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildArrayContext(f, true);
return (_currToken = t);
}
if (f == null) { // does this occur?
delegate.skipChildren();
break;
}
// Otherwise still iffy, need to check
f = _headContext.checkValue(f);
if (f == null) {
delegate.skipChildren();
break;
}
if (f != TokenFilter.INCLUDE_ALL) {
f = f.filterStartArray();
}
_itemFilter = f;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildArrayContext(f, true);
return (_currToken = t);
}
_headContext = _headContext.createChildArrayContext(f, false);
// Also: only need buffering if parent path to be included
if (_includePath) {
t = _nextTokenWithBuffering(_headContext);
if (t != null) {
_currToken = t;
return t;
}
}
break;
case ID_START_OBJECT:
f = _itemFilter;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildObjectContext(f, true);
return (_currToken = t);
}
if (f == null) { // does this occur?
delegate.skipChildren();
break;
}
// Otherwise still iffy, need to check
f = _headContext.checkValue(f);
if (f == null) {
delegate.skipChildren();
break;
}
if (f != TokenFilter.INCLUDE_ALL) {
f = f.filterStartObject();
}
_itemFilter = f;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildObjectContext(f, true);
return (_currToken = t);
}
_headContext = _headContext.createChildObjectContext(f, false);
// Also: only need buffering if parent path to be included
if (_includePath) {
t = _nextTokenWithBuffering(_headContext);
if (t != null) {
_currToken = t;
return t;
}
}
// note: inclusion of surrounding Object handled separately via
// FIELD_NAME
break;
case ID_END_ARRAY:
case ID_END_OBJECT:
{
boolean returnEnd = _headContext.isStartHandled();
f = _headContext.getFilter();
if ((f != null) && (f != TokenFilter.INCLUDE_ALL)) {
f.filterFinishArray();
}
_headContext = _headContext.getParent();
_itemFilter = _headContext.getFilter();
if (returnEnd) {
return (_currToken = t);
}
}
break;
case ID_FIELD_NAME:
{
final String name = delegate.getCurrentName();
// note: this will also set 'needToHandleName'
f = _headContext.setFieldName(name);
if (f == TokenFilter.INCLUDE_ALL) {
_itemFilter = f;
if (!_includePath) {
// Minor twist here: if parent NOT included, may need to induce output of
// surrounding START_OBJECT/END_OBJECT
if (_includeImmediateParent && !_headContext.isStartHandled()) {
t = _headContext.nextTokenToRead(); // returns START_OBJECT but also marks it handled
_exposedContext = _headContext;
}
}
return (_currToken = t);
}
if (f == null) {
delegate.nextToken();
delegate.skipChildren();
break;
}
f = f.includeProperty(name);
if (f == null) {
delegate.nextToken();
delegate.skipChildren();
break;
}
_itemFilter = f;
if (f == TokenFilter.INCLUDE_ALL) {
if (_includePath) {
return (_currToken = t);
}
}
if (_includePath) {
t = _nextTokenWithBuffering(_headContext);
if (t != null) {
_currToken = t;
return t;
}
}
break;
}
default: // scalar value
f = _itemFilter;
if (f == TokenFilter.INCLUDE_ALL) {
return (_currToken = t);
}
if (f != null) {
f = _headContext.checkValue(f);
if ((f == TokenFilter.INCLUDE_ALL)
|| ((f != null) && f.includeValue(delegate))) {
return (_currToken = t);
}
}
// Otherwise not included (leaves must be explicitly included)
break;
}
// We get here if token was not yet found; offlined handling
return _nextToken2();
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
22 | a61bf5f8bbcc937a29282e668894596f68ad69cd4e5db008921413dc93e9c45b | public static boolean areEqual(Object o1, Object o2) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public static boolean areEqual(Object o1, Object o2) {
if (o1 == null || o2 == null) {
return o1 == null && o2 == null;
} else if (isArray(o1)) {
return isArray(o2) && areArraysEqual(o1, o2);
} else {
return o1.equals(o2);
}
}
```
| public static boolean areEqual(Object o1, Object o2) {
if (o1 == null || o2 == null) {
return o1 == null && o2 == null;
} else if (isArray(o1)) {
return isArray(o2) && areArraysEqual(o1, o2);
} else {
return o1.equals(o2);
}
} | true | Mockito | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public static boolean areEqual(Object o1, Object o2) {
if (o1 == null || o2 == null) {
return o1 == null && o2 == null;
} else if (isArray(o1)) {
return isArray(o2) && areArraysEqual(o1, o2);
} else {
return o1.equals(o2);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
69 | a65e774f703e89eff3a65b946634d03bbdaef94132c5985275da3fcc58bc998e | private void visitCall(NodeTraversal t, Node n) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Visits a CALL node.
*
* @param t The node traversal object that supplies context, such as the
* scope chain to use in name lookups as well as error reporting.
* @param n The node being visited.
*/
private void visitCall(NodeTraversal t, Node n) {
Node child = n.getFirstChild();
JSType childType = getJSType(child).restrictByNotNullOrUndefined();
if (!childType.canBeCalled()) {
report(t, n, NOT_CALLABLE, childType.toString());
ensureTyped(t, n);
return;
}
// A couple of types can be called as if they were functions.
// If it is a function type, then validate parameters.
if (childType instanceof FunctionType) {
FunctionType functionType = (FunctionType) childType;
boolean isExtern = false;
JSDocInfo functionJSDocInfo = functionType.getJSDocInfo();
if(functionJSDocInfo != null) {
String sourceName = functionJSDocInfo.getSourceName();
CompilerInput functionSource = compiler.getInput(sourceName);
isExtern = functionSource.isExtern();
}
// Non-native constructors should not be called directly
// unless they specify a return type and are defined
// in an extern.
if (functionType.isConstructor() &&
!functionType.isNativeObjectType() &&
(functionType.getReturnType().isUnknownType() ||
functionType.getReturnType().isVoidType() ||
!isExtern)) {
report(t, n, CONSTRUCTOR_NOT_CALLABLE, childType.toString());
}
// Functions with explcit 'this' types must be called in a GETPROP
// or GETELEM.
if (functionType.isOrdinaryFunction() &&
!functionType.getTypeOfThis().isUnknownType() &&
!functionType.getTypeOfThis().isNativeObjectType() &&
!(child.getType() == Token.GETELEM ||
child.getType() == Token.GETPROP)) {
report(t, n, EXPECTED_THIS_TYPE, functionType.toString());
}
visitParameterList(t, n, functionType);
ensureTyped(t, n, functionType.getReturnType());
} else {
ensureTyped(t, n);
}
// TODO: Add something to check for calls of RegExp objects, which is not
// supported by IE. Either say something about the return type or warn
// about the non-portability of the call or both.
}
```
| private void visitCall(NodeTraversal t, Node n) {
Node child = n.getFirstChild();
JSType childType = getJSType(child).restrictByNotNullOrUndefined();
if (!childType.canBeCalled()) {
report(t, n, NOT_CALLABLE, childType.toString());
ensureTyped(t, n);
return;
}
// A couple of types can be called as if they were functions.
// If it is a function type, then validate parameters.
if (childType instanceof FunctionType) {
FunctionType functionType = (FunctionType) childType;
boolean isExtern = false;
JSDocInfo functionJSDocInfo = functionType.getJSDocInfo();
if(functionJSDocInfo != null) {
String sourceName = functionJSDocInfo.getSourceName();
CompilerInput functionSource = compiler.getInput(sourceName);
isExtern = functionSource.isExtern();
}
// Non-native constructors should not be called directly
// unless they specify a return type and are defined
// in an extern.
if (functionType.isConstructor() &&
!functionType.isNativeObjectType() &&
(functionType.getReturnType().isUnknownType() ||
functionType.getReturnType().isVoidType() ||
!isExtern)) {
report(t, n, CONSTRUCTOR_NOT_CALLABLE, childType.toString());
}
// Functions with explcit 'this' types must be called in a GETPROP
// or GETELEM.
if (functionType.isOrdinaryFunction() &&
!functionType.getTypeOfThis().isUnknownType() &&
!functionType.getTypeOfThis().isNativeObjectType() &&
!(child.getType() == Token.GETELEM ||
child.getType() == Token.GETPROP)) {
report(t, n, EXPECTED_THIS_TYPE, functionType.toString());
}
visitParameterList(t, n, functionType);
ensureTyped(t, n, functionType.getReturnType());
} else {
ensureTyped(t, n);
}
// TODO: Add something to check for calls of RegExp objects, which is not
// supported by IE. Either say something about the return type or warn
// about the non-portability of the call or both.
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Visits a CALL node.
*
* @param t The node traversal object that supplies context, such as the
* scope chain to use in name lookups as well as error reporting.
* @param n The node being visited.
*/
private void visitCall(NodeTraversal t, Node n) {
Node child = n.getFirstChild();
JSType childType = getJSType(child).restrictByNotNullOrUndefined();
if (!childType.canBeCalled()) {
report(t, n, NOT_CALLABLE, childType.toString());
ensureTyped(t, n);
return;
}
// A couple of types can be called as if they were functions.
// If it is a function type, then validate parameters.
if (childType instanceof FunctionType) {
FunctionType functionType = (FunctionType) childType;
boolean isExtern = false;
JSDocInfo functionJSDocInfo = functionType.getJSDocInfo();
if(functionJSDocInfo != null) {
String sourceName = functionJSDocInfo.getSourceName();
CompilerInput functionSource = compiler.getInput(sourceName);
isExtern = functionSource.isExtern();
}
// Non-native constructors should not be called directly
// unless they specify a return type and are defined
// in an extern.
if (functionType.isConstructor() &&
!functionType.isNativeObjectType() &&
(functionType.getReturnType().isUnknownType() ||
functionType.getReturnType().isVoidType() ||
!isExtern)) {
report(t, n, CONSTRUCTOR_NOT_CALLABLE, childType.toString());
}
// Functions with explcit 'this' types must be called in a GETPROP
// or GETELEM.
if (functionType.isOrdinaryFunction() &&
!functionType.getTypeOfThis().isUnknownType() &&
!functionType.getTypeOfThis().isNativeObjectType() &&
!(child.getType() == Token.GETELEM ||
child.getType() == Token.GETPROP)) {
report(t, n, EXPECTED_THIS_TYPE, functionType.toString());
}
visitParameterList(t, n, functionType);
ensureTyped(t, n, functionType.getReturnType());
} else {
ensureTyped(t, n);
}
// TODO: Add something to check for calls of RegExp objects, which is not
// supported by IE. Either say something about the return type or warn
// about the non-portability of the call or both.
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
29 | a6d555b9202c8d42874855b5d1f2078431f352fe162da2b5582fc62143a6aa44 | public void describeTo(Description description) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public void describeTo(Description description) {
description.appendText("same(");
appendQuoting(description);
description.appendText(wanted.toString());
appendQuoting(description);
description.appendText(")");
}
```
| public void describeTo(Description description) {
description.appendText("same(");
appendQuoting(description);
description.appendText(wanted.toString());
appendQuoting(description);
description.appendText(")");
} | true | Mockito | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public void describeTo(Description description) {
description.appendText("same(");
appendQuoting(description);
description.appendText(wanted.toString());
appendQuoting(description);
description.appendText(")");
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
95 | a6e92f6eabba30410d426b1452885201d7b089db6288f07967274403539e14ab | void defineSlot(Node n, Node parent, JSType type, boolean inferred) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Defines a typed variable. The defining node will be annotated with the
* variable's type of {@link JSTypeNative#UNKNOWN_TYPE} if its type is
* inferred.
*
* Slots may be any variable or any qualified name in the global scope.
*
* @param n the defining NAME or GETPROP node.
* @param parent the {@code n}'s parent.
* @param type the variable's type. It may be {@code null} if
* {@code inferred} is {@code true}.
*/
void defineSlot(Node n, Node parent, JSType type, boolean inferred) {
Preconditions.checkArgument(inferred || type != null);
// Only allow declarations of NAMEs and qualfied names.
boolean shouldDeclareOnGlobalThis = false;
if (n.getType() == Token.NAME) {
Preconditions.checkArgument(
parent.getType() == Token.FUNCTION ||
parent.getType() == Token.VAR ||
parent.getType() == Token.LP ||
parent.getType() == Token.CATCH);
shouldDeclareOnGlobalThis = scope.isGlobal() &&
(parent.getType() == Token.VAR ||
parent.getType() == Token.FUNCTION);
} else {
Preconditions.checkArgument(
n.getType() == Token.GETPROP &&
(parent.getType() == Token.ASSIGN ||
parent.getType() == Token.EXPR_RESULT));
}
String variableName = n.getQualifiedName();
Preconditions.checkArgument(!variableName.isEmpty());
// If n is a property, then we should really declare it in the
// scope where the root object appears. This helps out people
// who declare "global" names in an anonymous namespace.
Scope scopeToDeclareIn = scope;
if (n.getType() == Token.GETPROP && !scope.isGlobal() &&
isQnameRootedInGlobalScope(n)) {
Scope globalScope = scope.getGlobalScope();
// don't try to declare in the global scope if there's
// already a symbol there with this name.
if (!globalScope.isDeclared(variableName, false)) {
scopeToDeclareIn = scope.getGlobalScope();
}
}
// declared in closest scope?
if (scopeToDeclareIn.isDeclared(variableName, false)) {
Var oldVar = scopeToDeclareIn.getVar(variableName);
validator.expectUndeclaredVariable(
sourceName, n, parent, oldVar, variableName, type);
} else {
if (!inferred) {
setDeferredType(n, type);
}
CompilerInput input = compiler.getInput(sourceName);
scopeToDeclareIn.declare(variableName, n, type, input, inferred);
if (shouldDeclareOnGlobalThis) {
ObjectType globalThis =
typeRegistry.getNativeObjectType(JSTypeNative.GLOBAL_THIS);
boolean isExtern = input.isExtern();
if (inferred) {
globalThis.defineInferredProperty(variableName,
type == null ?
getNativeType(JSTypeNative.NO_TYPE) :
type,
isExtern);
} else {
globalThis.defineDeclaredProperty(variableName, type, isExtern);
}
}
// If we're in the global scope, also declare var.prototype
// in the scope chain.
if (scopeToDeclareIn.isGlobal() && type instanceof FunctionType) {
FunctionType fnType = (FunctionType) type;
if (fnType.isConstructor() || fnType.isInterface()) {
FunctionType superClassCtor = fnType.getSuperClassConstructor();
scopeToDeclareIn.declare(variableName + ".prototype", n,
fnType.getPrototype(), compiler.getInput(sourceName),
/* declared iff there's an explicit supertype */
superClassCtor == null ||
superClassCtor.getInstanceType().equals(
getNativeType(OBJECT_TYPE)));
}
}
}
}
```
| void defineSlot(Node n, Node parent, JSType type, boolean inferred) {
Preconditions.checkArgument(inferred || type != null);
// Only allow declarations of NAMEs and qualfied names.
boolean shouldDeclareOnGlobalThis = false;
if (n.getType() == Token.NAME) {
Preconditions.checkArgument(
parent.getType() == Token.FUNCTION ||
parent.getType() == Token.VAR ||
parent.getType() == Token.LP ||
parent.getType() == Token.CATCH);
shouldDeclareOnGlobalThis = scope.isGlobal() &&
(parent.getType() == Token.VAR ||
parent.getType() == Token.FUNCTION);
} else {
Preconditions.checkArgument(
n.getType() == Token.GETPROP &&
(parent.getType() == Token.ASSIGN ||
parent.getType() == Token.EXPR_RESULT));
}
String variableName = n.getQualifiedName();
Preconditions.checkArgument(!variableName.isEmpty());
// If n is a property, then we should really declare it in the
// scope where the root object appears. This helps out people
// who declare "global" names in an anonymous namespace.
Scope scopeToDeclareIn = scope;
if (n.getType() == Token.GETPROP && !scope.isGlobal() &&
isQnameRootedInGlobalScope(n)) {
Scope globalScope = scope.getGlobalScope();
// don't try to declare in the global scope if there's
// already a symbol there with this name.
if (!globalScope.isDeclared(variableName, false)) {
scopeToDeclareIn = scope.getGlobalScope();
}
}
// declared in closest scope?
if (scopeToDeclareIn.isDeclared(variableName, false)) {
Var oldVar = scopeToDeclareIn.getVar(variableName);
validator.expectUndeclaredVariable(
sourceName, n, parent, oldVar, variableName, type);
} else {
if (!inferred) {
setDeferredType(n, type);
}
CompilerInput input = compiler.getInput(sourceName);
scopeToDeclareIn.declare(variableName, n, type, input, inferred);
if (shouldDeclareOnGlobalThis) {
ObjectType globalThis =
typeRegistry.getNativeObjectType(JSTypeNative.GLOBAL_THIS);
boolean isExtern = input.isExtern();
if (inferred) {
globalThis.defineInferredProperty(variableName,
type == null ?
getNativeType(JSTypeNative.NO_TYPE) :
type,
isExtern);
} else {
globalThis.defineDeclaredProperty(variableName, type, isExtern);
}
}
// If we're in the global scope, also declare var.prototype
// in the scope chain.
if (scopeToDeclareIn.isGlobal() && type instanceof FunctionType) {
FunctionType fnType = (FunctionType) type;
if (fnType.isConstructor() || fnType.isInterface()) {
FunctionType superClassCtor = fnType.getSuperClassConstructor();
scopeToDeclareIn.declare(variableName + ".prototype", n,
fnType.getPrototype(), compiler.getInput(sourceName),
/* declared iff there's an explicit supertype */
superClassCtor == null ||
superClassCtor.getInstanceType().equals(
getNativeType(OBJECT_TYPE)));
}
}
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Defines a typed variable. The defining node will be annotated with the
* variable's type of {@link JSTypeNative#UNKNOWN_TYPE} if its type is
* inferred.
*
* Slots may be any variable or any qualified name in the global scope.
*
* @param n the defining NAME or GETPROP node.
* @param parent the {@code n}'s parent.
* @param type the variable's type. It may be {@code null} if
* {@code inferred} is {@code true}.
*/
void defineSlot(Node n, Node parent, JSType type, boolean inferred) {
Preconditions.checkArgument(inferred || type != null);
// Only allow declarations of NAMEs and qualfied names.
boolean shouldDeclareOnGlobalThis = false;
if (n.getType() == Token.NAME) {
Preconditions.checkArgument(
parent.getType() == Token.FUNCTION ||
parent.getType() == Token.VAR ||
parent.getType() == Token.LP ||
parent.getType() == Token.CATCH);
shouldDeclareOnGlobalThis = scope.isGlobal() &&
(parent.getType() == Token.VAR ||
parent.getType() == Token.FUNCTION);
} else {
Preconditions.checkArgument(
n.getType() == Token.GETPROP &&
(parent.getType() == Token.ASSIGN ||
parent.getType() == Token.EXPR_RESULT));
}
String variableName = n.getQualifiedName();
Preconditions.checkArgument(!variableName.isEmpty());
// If n is a property, then we should really declare it in the
// scope where the root object appears. This helps out people
// who declare "global" names in an anonymous namespace.
Scope scopeToDeclareIn = scope;
if (n.getType() == Token.GETPROP && !scope.isGlobal() &&
isQnameRootedInGlobalScope(n)) {
Scope globalScope = scope.getGlobalScope();
// don't try to declare in the global scope if there's
// already a symbol there with this name.
if (!globalScope.isDeclared(variableName, false)) {
scopeToDeclareIn = scope.getGlobalScope();
}
}
// declared in closest scope?
if (scopeToDeclareIn.isDeclared(variableName, false)) {
Var oldVar = scopeToDeclareIn.getVar(variableName);
validator.expectUndeclaredVariable(
sourceName, n, parent, oldVar, variableName, type);
} else {
if (!inferred) {
setDeferredType(n, type);
}
CompilerInput input = compiler.getInput(sourceName);
scopeToDeclareIn.declare(variableName, n, type, input, inferred);
if (shouldDeclareOnGlobalThis) {
ObjectType globalThis =
typeRegistry.getNativeObjectType(JSTypeNative.GLOBAL_THIS);
boolean isExtern = input.isExtern();
if (inferred) {
globalThis.defineInferredProperty(variableName,
type == null ?
getNativeType(JSTypeNative.NO_TYPE) :
type,
isExtern);
} else {
globalThis.defineDeclaredProperty(variableName, type, isExtern);
}
}
// If we're in the global scope, also declare var.prototype
// in the scope chain.
if (scopeToDeclareIn.isGlobal() && type instanceof FunctionType) {
FunctionType fnType = (FunctionType) type;
if (fnType.isConstructor() || fnType.isInterface()) {
FunctionType superClassCtor = fnType.getSuperClassConstructor();
scopeToDeclareIn.declare(variableName + ".prototype", n,
fnType.getPrototype(), compiler.getInput(sourceName),
/* declared iff there's an explicit supertype */
superClassCtor == null ||
superClassCtor.getInstanceType().equals(
getNativeType(OBJECT_TYPE)));
}
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
24 | a7bc396ae39175a6581b77326e1868fb993a84a811e53d163d202d2501320c4c | public static boolean isNumber(String str) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Checks whether the String a valid Java number.</p>
*
* <p>Valid numbers include hexadecimal marked with the <code>0x</code>
* qualifier, scientific notation and numbers marked with a type
* qualifier (e.g. 123L).</p>
*
* <p><code>Null</code> and empty String will return
* <code>false</code>.</p>
*
* @param str the <code>String</code> to check
* @return <code>true</code> if the string is a correctly formatted number
*/
public static boolean isNumber(String str) {
if (StringUtils.isEmpty(str)) {
return false;
}
char[] chars = str.toCharArray();
int sz = chars.length;
boolean hasExp = false;
boolean hasDecPoint = false;
boolean allowSigns = false;
boolean foundDigit = false;
// deal with any possible sign up front
int start = (chars[0] == '-') ? 1 : 0;
if (sz > start + 1) {
if (chars[start] == '0' && chars[start + 1] == 'x') {
int i = start + 2;
if (i == sz) {
return false; // str == "0x"
}
// checking hex (it can't be anything else)
for (; i < chars.length; i++) {
if ((chars[i] < '0' || chars[i] > '9')
&& (chars[i] < 'a' || chars[i] > 'f')
&& (chars[i] < 'A' || chars[i] > 'F')) {
return false;
}
}
return true;
}
}
sz--; // don't want to loop to the last char, check it afterwords
// for type qualifiers
int i = start;
// loop to the next to last char or to the last char if we need another digit to
// make a valid number (e.g. chars[0..5] = "1234E")
while (i < sz || (i < sz + 1 && allowSigns && !foundDigit)) {
if (chars[i] >= '0' && chars[i] <= '9') {
foundDigit = true;
allowSigns = false;
} else if (chars[i] == '.') {
if (hasDecPoint || hasExp) {
// two decimal points or dec in exponent
return false;
}
hasDecPoint = true;
} else if (chars[i] == 'e' || chars[i] == 'E') {
// we've already taken care of hex.
if (hasExp) {
// two E's
return false;
}
if (!foundDigit) {
return false;
}
hasExp = true;
allowSigns = true;
} else if (chars[i] == '+' || chars[i] == '-') {
if (!allowSigns) {
return false;
}
allowSigns = false;
foundDigit = false; // we need a digit after the E
} else {
return false;
}
i++;
}
if (i < chars.length) {
if (chars[i] >= '0' && chars[i] <= '9') {
// no type qualifier, OK
return true;
}
if (chars[i] == 'e' || chars[i] == 'E') {
// can't have an E at the last byte
return false;
}
if (chars[i] == '.') {
if (hasDecPoint || hasExp) {
// two decimal points or dec in exponent
return false;
}
// single trailing decimal point after non-exponent is ok
return foundDigit;
}
if (!allowSigns
&& (chars[i] == 'd'
|| chars[i] == 'D'
|| chars[i] == 'f'
|| chars[i] == 'F')) {
return foundDigit;
}
if (chars[i] == 'l'
|| chars[i] == 'L') {
// not allowing L with an exponent or decimal point
return foundDigit && !hasExp;
}
// last character is illegal
return false;
}
// allowSigns is true iff the val ends in 'E'
// found digit it to make sure weird stuff like '.' and '1E-' doesn't pass
return !allowSigns && foundDigit;
}
```
| public static boolean isNumber(String str) {
if (StringUtils.isEmpty(str)) {
return false;
}
char[] chars = str.toCharArray();
int sz = chars.length;
boolean hasExp = false;
boolean hasDecPoint = false;
boolean allowSigns = false;
boolean foundDigit = false;
// deal with any possible sign up front
int start = (chars[0] == '-') ? 1 : 0;
if (sz > start + 1) {
if (chars[start] == '0' && chars[start + 1] == 'x') {
int i = start + 2;
if (i == sz) {
return false; // str == "0x"
}
// checking hex (it can't be anything else)
for (; i < chars.length; i++) {
if ((chars[i] < '0' || chars[i] > '9')
&& (chars[i] < 'a' || chars[i] > 'f')
&& (chars[i] < 'A' || chars[i] > 'F')) {
return false;
}
}
return true;
}
}
sz--; // don't want to loop to the last char, check it afterwords
// for type qualifiers
int i = start;
// loop to the next to last char or to the last char if we need another digit to
// make a valid number (e.g. chars[0..5] = "1234E")
while (i < sz || (i < sz + 1 && allowSigns && !foundDigit)) {
if (chars[i] >= '0' && chars[i] <= '9') {
foundDigit = true;
allowSigns = false;
} else if (chars[i] == '.') {
if (hasDecPoint || hasExp) {
// two decimal points or dec in exponent
return false;
}
hasDecPoint = true;
} else if (chars[i] == 'e' || chars[i] == 'E') {
// we've already taken care of hex.
if (hasExp) {
// two E's
return false;
}
if (!foundDigit) {
return false;
}
hasExp = true;
allowSigns = true;
} else if (chars[i] == '+' || chars[i] == '-') {
if (!allowSigns) {
return false;
}
allowSigns = false;
foundDigit = false; // we need a digit after the E
} else {
return false;
}
i++;
}
if (i < chars.length) {
if (chars[i] >= '0' && chars[i] <= '9') {
// no type qualifier, OK
return true;
}
if (chars[i] == 'e' || chars[i] == 'E') {
// can't have an E at the last byte
return false;
}
if (chars[i] == '.') {
if (hasDecPoint || hasExp) {
// two decimal points or dec in exponent
return false;
}
// single trailing decimal point after non-exponent is ok
return foundDigit;
}
if (!allowSigns
&& (chars[i] == 'd'
|| chars[i] == 'D'
|| chars[i] == 'f'
|| chars[i] == 'F')) {
return foundDigit;
}
if (chars[i] == 'l'
|| chars[i] == 'L') {
// not allowing L with an exponent or decimal point
return foundDigit && !hasExp;
}
// last character is illegal
return false;
}
// allowSigns is true iff the val ends in 'E'
// found digit it to make sure weird stuff like '.' and '1E-' doesn't pass
return !allowSigns && foundDigit;
} | true | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Checks whether the String a valid Java number.</p>
*
* <p>Valid numbers include hexadecimal marked with the <code>0x</code>
* qualifier, scientific notation and numbers marked with a type
* qualifier (e.g. 123L).</p>
*
* <p><code>Null</code> and empty String will return
* <code>false</code>.</p>
*
* @param str the <code>String</code> to check
* @return <code>true</code> if the string is a correctly formatted number
*/
public static boolean isNumber(String str) {
if (StringUtils.isEmpty(str)) {
return false;
}
char[] chars = str.toCharArray();
int sz = chars.length;
boolean hasExp = false;
boolean hasDecPoint = false;
boolean allowSigns = false;
boolean foundDigit = false;
// deal with any possible sign up front
int start = (chars[0] == '-') ? 1 : 0;
if (sz > start + 1) {
if (chars[start] == '0' && chars[start + 1] == 'x') {
int i = start + 2;
if (i == sz) {
return false; // str == "0x"
}
// checking hex (it can't be anything else)
for (; i < chars.length; i++) {
if ((chars[i] < '0' || chars[i] > '9')
&& (chars[i] < 'a' || chars[i] > 'f')
&& (chars[i] < 'A' || chars[i] > 'F')) {
return false;
}
}
return true;
}
}
sz--; // don't want to loop to the last char, check it afterwords
// for type qualifiers
int i = start;
// loop to the next to last char or to the last char if we need another digit to
// make a valid number (e.g. chars[0..5] = "1234E")
while (i < sz || (i < sz + 1 && allowSigns && !foundDigit)) {
if (chars[i] >= '0' && chars[i] <= '9') {
foundDigit = true;
allowSigns = false;
} else if (chars[i] == '.') {
if (hasDecPoint || hasExp) {
// two decimal points or dec in exponent
return false;
}
hasDecPoint = true;
} else if (chars[i] == 'e' || chars[i] == 'E') {
// we've already taken care of hex.
if (hasExp) {
// two E's
return false;
}
if (!foundDigit) {
return false;
}
hasExp = true;
allowSigns = true;
} else if (chars[i] == '+' || chars[i] == '-') {
if (!allowSigns) {
return false;
}
allowSigns = false;
foundDigit = false; // we need a digit after the E
} else {
return false;
}
i++;
}
if (i < chars.length) {
if (chars[i] >= '0' && chars[i] <= '9') {
// no type qualifier, OK
return true;
}
if (chars[i] == 'e' || chars[i] == 'E') {
// can't have an E at the last byte
return false;
}
if (chars[i] == '.') {
if (hasDecPoint || hasExp) {
// two decimal points or dec in exponent
return false;
}
// single trailing decimal point after non-exponent is ok
return foundDigit;
}
if (!allowSigns
&& (chars[i] == 'd'
|| chars[i] == 'D'
|| chars[i] == 'f'
|| chars[i] == 'F')) {
return foundDigit;
}
if (chars[i] == 'l'
|| chars[i] == 'L') {
// not allowing L with an exponent or decimal point
return foundDigit && !hasExp;
}
// last character is illegal
return false;
}
// allowSigns is true iff the val ends in 'E'
// found digit it to make sure weird stuff like '.' and '1E-' doesn't pass
return !allowSigns && foundDigit;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
21 | a7db0e4bcb50dc13cebdd9eddd908e676b81ff2cfe83423d5b0c4d1e45c2f49a | @Override
public void visit(NodeTraversal t, Node n, Node parent) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public void visit(NodeTraversal t, Node n, Node parent) {
// VOID nodes appear when there are extra semicolons at the BLOCK level.
// I've been unable to think of any cases where this indicates a bug,
// and apparently some people like keeping these semicolons around,
// so we'll allow it.
if (n.isEmpty() ||
n.isComma()) {
return;
}
if (parent == null) {
return;
}
// Do not try to remove a block or an expr result. We already handle
// these cases when we visit the child, and the peephole passes will
// fix up the tree in more clever ways when these are removed.
if (n.isExprResult() || n.isBlock()) {
return;
}
// This no-op statement was there so that JSDoc information could
// be attached to the name. This check should not complain about it.
if (n.isQualifiedName() && n.getJSDocInfo() != null) {
return;
}
boolean isResultUsed = NodeUtil.isExpressionResultUsed(n);
boolean isSimpleOp = NodeUtil.isSimpleOperatorType(n.getType());
if (!isResultUsed &&
(isSimpleOp || !NodeUtil.mayHaveSideEffects(n, t.getCompiler()))) {
String msg = "This code lacks side-effects. Is there a bug?";
if (n.isString()) {
msg = "Is there a missing '+' on the previous line?";
} else if (isSimpleOp) {
msg = "The result of the '" + Token.name(n.getType()).toLowerCase() +
"' operator is not being used.";
}
t.getCompiler().report(
t.makeError(n, level, USELESS_CODE_ERROR, msg));
// TODO(johnlenz): determine if it is necessary to
// try to protect side-effect free statements as well.
if (!NodeUtil.isStatement(n)) {
problemNodes.add(n);
}
}
}
```
| @Override
public void visit(NodeTraversal t, Node n, Node parent) {
// VOID nodes appear when there are extra semicolons at the BLOCK level.
// I've been unable to think of any cases where this indicates a bug,
// and apparently some people like keeping these semicolons around,
// so we'll allow it.
if (n.isEmpty() ||
n.isComma()) {
return;
}
if (parent == null) {
return;
}
// Do not try to remove a block or an expr result. We already handle
// these cases when we visit the child, and the peephole passes will
// fix up the tree in more clever ways when these are removed.
if (n.isExprResult() || n.isBlock()) {
return;
}
// This no-op statement was there so that JSDoc information could
// be attached to the name. This check should not complain about it.
if (n.isQualifiedName() && n.getJSDocInfo() != null) {
return;
}
boolean isResultUsed = NodeUtil.isExpressionResultUsed(n);
boolean isSimpleOp = NodeUtil.isSimpleOperatorType(n.getType());
if (!isResultUsed &&
(isSimpleOp || !NodeUtil.mayHaveSideEffects(n, t.getCompiler()))) {
String msg = "This code lacks side-effects. Is there a bug?";
if (n.isString()) {
msg = "Is there a missing '+' on the previous line?";
} else if (isSimpleOp) {
msg = "The result of the '" + Token.name(n.getType()).toLowerCase() +
"' operator is not being used.";
}
t.getCompiler().report(
t.makeError(n, level, USELESS_CODE_ERROR, msg));
// TODO(johnlenz): determine if it is necessary to
// try to protect side-effect free statements as well.
if (!NodeUtil.isStatement(n)) {
problemNodes.add(n);
}
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public void visit(NodeTraversal t, Node n, Node parent) {
// VOID nodes appear when there are extra semicolons at the BLOCK level.
// I've been unable to think of any cases where this indicates a bug,
// and apparently some people like keeping these semicolons around,
// so we'll allow it.
if (n.isEmpty() ||
n.isComma()) {
return;
}
if (parent == null) {
return;
}
// Do not try to remove a block or an expr result. We already handle
// these cases when we visit the child, and the peephole passes will
// fix up the tree in more clever ways when these are removed.
if (n.isExprResult() || n.isBlock()) {
return;
}
// This no-op statement was there so that JSDoc information could
// be attached to the name. This check should not complain about it.
if (n.isQualifiedName() && n.getJSDocInfo() != null) {
return;
}
boolean isResultUsed = NodeUtil.isExpressionResultUsed(n);
boolean isSimpleOp = NodeUtil.isSimpleOperatorType(n.getType());
if (!isResultUsed &&
(isSimpleOp || !NodeUtil.mayHaveSideEffects(n, t.getCompiler()))) {
String msg = "This code lacks side-effects. Is there a bug?";
if (n.isString()) {
msg = "Is there a missing '+' on the previous line?";
} else if (isSimpleOp) {
msg = "The result of the '" + Token.name(n.getType()).toLowerCase() +
"' operator is not being used.";
}
t.getCompiler().report(
t.makeError(n, level, USELESS_CODE_ERROR, msg));
// TODO(johnlenz): determine if it is necessary to
// try to protect side-effect free statements as well.
if (!NodeUtil.isStatement(n)) {
problemNodes.add(n);
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
22 | a7db0e4bcb50dc13cebdd9eddd908e676b81ff2cfe83423d5b0c4d1e45c2f49a | @Override
public void visit(NodeTraversal t, Node n, Node parent) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public void visit(NodeTraversal t, Node n, Node parent) {
// VOID nodes appear when there are extra semicolons at the BLOCK level.
// I've been unable to think of any cases where this indicates a bug,
// and apparently some people like keeping these semicolons around,
// so we'll allow it.
if (n.isEmpty() ||
n.isComma()) {
return;
}
if (parent == null) {
return;
}
// Do not try to remove a block or an expr result. We already handle
// these cases when we visit the child, and the peephole passes will
// fix up the tree in more clever ways when these are removed.
if (n.isExprResult() || n.isBlock()) {
return;
}
// This no-op statement was there so that JSDoc information could
// be attached to the name. This check should not complain about it.
if (n.isQualifiedName() && n.getJSDocInfo() != null) {
return;
}
boolean isResultUsed = NodeUtil.isExpressionResultUsed(n);
boolean isSimpleOp = NodeUtil.isSimpleOperatorType(n.getType());
if (!isResultUsed &&
(isSimpleOp || !NodeUtil.mayHaveSideEffects(n, t.getCompiler()))) {
String msg = "This code lacks side-effects. Is there a bug?";
if (n.isString()) {
msg = "Is there a missing '+' on the previous line?";
} else if (isSimpleOp) {
msg = "The result of the '" + Token.name(n.getType()).toLowerCase() +
"' operator is not being used.";
}
t.getCompiler().report(
t.makeError(n, level, USELESS_CODE_ERROR, msg));
// TODO(johnlenz): determine if it is necessary to
// try to protect side-effect free statements as well.
if (!NodeUtil.isStatement(n)) {
problemNodes.add(n);
}
}
}
```
| @Override
public void visit(NodeTraversal t, Node n, Node parent) {
// VOID nodes appear when there are extra semicolons at the BLOCK level.
// I've been unable to think of any cases where this indicates a bug,
// and apparently some people like keeping these semicolons around,
// so we'll allow it.
if (n.isEmpty() ||
n.isComma()) {
return;
}
if (parent == null) {
return;
}
// Do not try to remove a block or an expr result. We already handle
// these cases when we visit the child, and the peephole passes will
// fix up the tree in more clever ways when these are removed.
if (n.isExprResult() || n.isBlock()) {
return;
}
// This no-op statement was there so that JSDoc information could
// be attached to the name. This check should not complain about it.
if (n.isQualifiedName() && n.getJSDocInfo() != null) {
return;
}
boolean isResultUsed = NodeUtil.isExpressionResultUsed(n);
boolean isSimpleOp = NodeUtil.isSimpleOperatorType(n.getType());
if (!isResultUsed &&
(isSimpleOp || !NodeUtil.mayHaveSideEffects(n, t.getCompiler()))) {
String msg = "This code lacks side-effects. Is there a bug?";
if (n.isString()) {
msg = "Is there a missing '+' on the previous line?";
} else if (isSimpleOp) {
msg = "The result of the '" + Token.name(n.getType()).toLowerCase() +
"' operator is not being used.";
}
t.getCompiler().report(
t.makeError(n, level, USELESS_CODE_ERROR, msg));
// TODO(johnlenz): determine if it is necessary to
// try to protect side-effect free statements as well.
if (!NodeUtil.isStatement(n)) {
problemNodes.add(n);
}
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public void visit(NodeTraversal t, Node n, Node parent) {
// VOID nodes appear when there are extra semicolons at the BLOCK level.
// I've been unable to think of any cases where this indicates a bug,
// and apparently some people like keeping these semicolons around,
// so we'll allow it.
if (n.isEmpty() ||
n.isComma()) {
return;
}
if (parent == null) {
return;
}
// Do not try to remove a block or an expr result. We already handle
// these cases when we visit the child, and the peephole passes will
// fix up the tree in more clever ways when these are removed.
if (n.isExprResult() || n.isBlock()) {
return;
}
// This no-op statement was there so that JSDoc information could
// be attached to the name. This check should not complain about it.
if (n.isQualifiedName() && n.getJSDocInfo() != null) {
return;
}
boolean isResultUsed = NodeUtil.isExpressionResultUsed(n);
boolean isSimpleOp = NodeUtil.isSimpleOperatorType(n.getType());
if (!isResultUsed &&
(isSimpleOp || !NodeUtil.mayHaveSideEffects(n, t.getCompiler()))) {
String msg = "This code lacks side-effects. Is there a bug?";
if (n.isString()) {
msg = "Is there a missing '+' on the previous line?";
} else if (isSimpleOp) {
msg = "The result of the '" + Token.name(n.getType()).toLowerCase() +
"' operator is not being used.";
}
t.getCompiler().report(
t.makeError(n, level, USELESS_CODE_ERROR, msg));
// TODO(johnlenz): determine if it is necessary to
// try to protect side-effect free statements as well.
if (!NodeUtil.isStatement(n)) {
problemNodes.add(n);
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
16 | a8263f65a470f4d188d8719fa84a4a5c6cf12c1a6b13ed7deb32aa1ff2a7ba7b | private static Type resolve(Type context, Class<?> contextRawType, Type toResolve,
Collection<TypeVariable> visitedTypeVariables) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private static Type resolve(Type context, Class<?> contextRawType, Type toResolve,
Collection<TypeVariable> visitedTypeVariables) {
// this implementation is made a little more complicated in an attempt to avoid object-creation
while (true) {
if (toResolve instanceof TypeVariable) {
TypeVariable<?> typeVariable = (TypeVariable<?>) toResolve;
if (visitedTypeVariables.contains(typeVariable)) {
// cannot reduce due to infinite recursion
return toResolve;
} else {
visitedTypeVariables.add(typeVariable);
}
toResolve = resolveTypeVariable(context, contextRawType, typeVariable);
if (toResolve == typeVariable) {
return toResolve;
}
} else if (toResolve instanceof Class && ((Class<?>) toResolve).isArray()) {
Class<?> original = (Class<?>) toResolve;
Type componentType = original.getComponentType();
Type newComponentType = resolve(context, contextRawType, componentType, visitedTypeVariables);
return componentType == newComponentType
? original
: arrayOf(newComponentType);
} else if (toResolve instanceof GenericArrayType) {
GenericArrayType original = (GenericArrayType) toResolve;
Type componentType = original.getGenericComponentType();
Type newComponentType = resolve(context, contextRawType, componentType, visitedTypeVariables);
return componentType == newComponentType
? original
: arrayOf(newComponentType);
} else if (toResolve instanceof ParameterizedType) {
ParameterizedType original = (ParameterizedType) toResolve;
Type ownerType = original.getOwnerType();
Type newOwnerType = resolve(context, contextRawType, ownerType, visitedTypeVariables);
boolean changed = newOwnerType != ownerType;
Type[] args = original.getActualTypeArguments();
for (int t = 0, length = args.length; t < length; t++) {
Type resolvedTypeArgument = resolve(context, contextRawType, args[t], visitedTypeVariables);
if (resolvedTypeArgument != args[t]) {
if (!changed) {
args = args.clone();
changed = true;
}
args[t] = resolvedTypeArgument;
}
}
return changed
? newParameterizedTypeWithOwner(newOwnerType, original.getRawType(), args)
: original;
} else if (toResolve instanceof WildcardType) {
WildcardType original = (WildcardType) toResolve;
Type[] originalLowerBound = original.getLowerBounds();
Type[] originalUpperBound = original.getUpperBounds();
if (originalLowerBound.length == 1) {
Type lowerBound = resolve(context, contextRawType, originalLowerBound[0], visitedTypeVariables);
if (lowerBound != originalLowerBound[0]) {
return supertypeOf(lowerBound);
}
} else if (originalUpperBound.length == 1) {
Type upperBound = resolve(context, contextRawType, originalUpperBound[0], visitedTypeVariables);
if (upperBound != originalUpperBound[0]) {
return subtypeOf(upperBound);
}
}
return original;
} else {
return toResolve;
}
}
}
```
| private static Type resolve(Type context, Class<?> contextRawType, Type toResolve,
Collection<TypeVariable> visitedTypeVariables) {
// this implementation is made a little more complicated in an attempt to avoid object-creation
while (true) {
if (toResolve instanceof TypeVariable) {
TypeVariable<?> typeVariable = (TypeVariable<?>) toResolve;
if (visitedTypeVariables.contains(typeVariable)) {
// cannot reduce due to infinite recursion
return toResolve;
} else {
visitedTypeVariables.add(typeVariable);
}
toResolve = resolveTypeVariable(context, contextRawType, typeVariable);
if (toResolve == typeVariable) {
return toResolve;
}
} else if (toResolve instanceof Class && ((Class<?>) toResolve).isArray()) {
Class<?> original = (Class<?>) toResolve;
Type componentType = original.getComponentType();
Type newComponentType = resolve(context, contextRawType, componentType, visitedTypeVariables);
return componentType == newComponentType
? original
: arrayOf(newComponentType);
} else if (toResolve instanceof GenericArrayType) {
GenericArrayType original = (GenericArrayType) toResolve;
Type componentType = original.getGenericComponentType();
Type newComponentType = resolve(context, contextRawType, componentType, visitedTypeVariables);
return componentType == newComponentType
? original
: arrayOf(newComponentType);
} else if (toResolve instanceof ParameterizedType) {
ParameterizedType original = (ParameterizedType) toResolve;
Type ownerType = original.getOwnerType();
Type newOwnerType = resolve(context, contextRawType, ownerType, visitedTypeVariables);
boolean changed = newOwnerType != ownerType;
Type[] args = original.getActualTypeArguments();
for (int t = 0, length = args.length; t < length; t++) {
Type resolvedTypeArgument = resolve(context, contextRawType, args[t], visitedTypeVariables);
if (resolvedTypeArgument != args[t]) {
if (!changed) {
args = args.clone();
changed = true;
}
args[t] = resolvedTypeArgument;
}
}
return changed
? newParameterizedTypeWithOwner(newOwnerType, original.getRawType(), args)
: original;
} else if (toResolve instanceof WildcardType) {
WildcardType original = (WildcardType) toResolve;
Type[] originalLowerBound = original.getLowerBounds();
Type[] originalUpperBound = original.getUpperBounds();
if (originalLowerBound.length == 1) {
Type lowerBound = resolve(context, contextRawType, originalLowerBound[0], visitedTypeVariables);
if (lowerBound != originalLowerBound[0]) {
return supertypeOf(lowerBound);
}
} else if (originalUpperBound.length == 1) {
Type upperBound = resolve(context, contextRawType, originalUpperBound[0], visitedTypeVariables);
if (upperBound != originalUpperBound[0]) {
return subtypeOf(upperBound);
}
}
return original;
} else {
return toResolve;
}
}
} | false | Gson | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private static Type resolve(Type context, Class<?> contextRawType, Type toResolve,
Collection<TypeVariable> visitedTypeVariables) {
// this implementation is made a little more complicated in an attempt to avoid object-creation
while (true) {
if (toResolve instanceof TypeVariable) {
TypeVariable<?> typeVariable = (TypeVariable<?>) toResolve;
if (visitedTypeVariables.contains(typeVariable)) {
// cannot reduce due to infinite recursion
return toResolve;
} else {
visitedTypeVariables.add(typeVariable);
}
toResolve = resolveTypeVariable(context, contextRawType, typeVariable);
if (toResolve == typeVariable) {
return toResolve;
}
} else if (toResolve instanceof Class && ((Class<?>) toResolve).isArray()) {
Class<?> original = (Class<?>) toResolve;
Type componentType = original.getComponentType();
Type newComponentType = resolve(context, contextRawType, componentType, visitedTypeVariables);
return componentType == newComponentType
? original
: arrayOf(newComponentType);
} else if (toResolve instanceof GenericArrayType) {
GenericArrayType original = (GenericArrayType) toResolve;
Type componentType = original.getGenericComponentType();
Type newComponentType = resolve(context, contextRawType, componentType, visitedTypeVariables);
return componentType == newComponentType
? original
: arrayOf(newComponentType);
} else if (toResolve instanceof ParameterizedType) {
ParameterizedType original = (ParameterizedType) toResolve;
Type ownerType = original.getOwnerType();
Type newOwnerType = resolve(context, contextRawType, ownerType, visitedTypeVariables);
boolean changed = newOwnerType != ownerType;
Type[] args = original.getActualTypeArguments();
for (int t = 0, length = args.length; t < length; t++) {
Type resolvedTypeArgument = resolve(context, contextRawType, args[t], visitedTypeVariables);
if (resolvedTypeArgument != args[t]) {
if (!changed) {
args = args.clone();
changed = true;
}
args[t] = resolvedTypeArgument;
}
}
return changed
? newParameterizedTypeWithOwner(newOwnerType, original.getRawType(), args)
: original;
} else if (toResolve instanceof WildcardType) {
WildcardType original = (WildcardType) toResolve;
Type[] originalLowerBound = original.getLowerBounds();
Type[] originalUpperBound = original.getUpperBounds();
if (originalLowerBound.length == 1) {
Type lowerBound = resolve(context, contextRawType, originalLowerBound[0], visitedTypeVariables);
if (lowerBound != originalLowerBound[0]) {
return supertypeOf(lowerBound);
}
} else if (originalUpperBound.length == 1) {
Type upperBound = resolve(context, contextRawType, originalUpperBound[0], visitedTypeVariables);
if (upperBound != originalUpperBound[0]) {
return subtypeOf(upperBound);
}
}
return original;
} else {
return toResolve;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
86 | a893a93d4d936e1412bbc09bfd1f688fb3d04fbb2edc2d35ee6da33d36305752 | public XmlDeclaration asXmlDeclaration() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Attempt to cast this comment to an XML Declaration note.
* @return an XML declaration if it could be parsed as one, null otherwise.
*/
public XmlDeclaration asXmlDeclaration() {
String data = getData();
Document doc = Jsoup.parse("<" + data.substring(1, data.length() -1) + ">", baseUri(), Parser.xmlParser());
XmlDeclaration decl = null;
if (doc.childNodeSize() > 0) {
Element el = doc.child(0);
decl = new XmlDeclaration(NodeUtils.parser(doc).settings().normalizeTag(el.tagName()), data.startsWith("!"));
decl.attributes().addAll(el.attributes());
}
return decl;
}
```
| public XmlDeclaration asXmlDeclaration() {
String data = getData();
Document doc = Jsoup.parse("<" + data.substring(1, data.length() -1) + ">", baseUri(), Parser.xmlParser());
XmlDeclaration decl = null;
if (doc.childNodeSize() > 0) {
Element el = doc.child(0);
decl = new XmlDeclaration(NodeUtils.parser(doc).settings().normalizeTag(el.tagName()), data.startsWith("!"));
decl.attributes().addAll(el.attributes());
}
return decl;
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Attempt to cast this comment to an XML Declaration note.
* @return an XML declaration if it could be parsed as one, null otherwise.
*/
public XmlDeclaration asXmlDeclaration() {
String data = getData();
Document doc = Jsoup.parse("<" + data.substring(1, data.length() -1) + ">", baseUri(), Parser.xmlParser());
XmlDeclaration decl = null;
if (doc.childNodeSize() > 0) {
Element el = doc.child(0);
decl = new XmlDeclaration(NodeUtils.parser(doc).settings().normalizeTag(el.tagName()), data.startsWith("!"));
decl.attributes().addAll(el.attributes());
}
return decl;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |